Is this an open or a closed circuit?

Is This An Open Or A Closed Circuit?

Answers

Answer 1

Answer:

It is a closed circuit.

Answer 2
it is a closed circuit

Related Questions

2016 Physics A-CR
In which situations is elastic potential energy present? Check all that apply.
A bow is drawn back from its equilibrium position.
An arrow rests on a bow.
O A spring toy dart gun is unloaded.
A spring toy dart gun is loaded with a dart.
A bungee cord is connected to a tall tower.
A bungee cord is stretched with a person at the end.

Answers

Answer:

A bow is drawn back from its equilibrium position.

A spring toy dart gun is loaded with a dart.

A bungee cord is stretched with a person at the end.

Explanation:

All of these examples have to do with the elastic object being stretched but not in motion, therefore they have stored energy, or potential energy.

Answer:

A bow is drawn back from its equilibrium position.

A spring toy dart gun is loaded with a dart.

A bungee cord is connected to a tall tower.

A bungee cord is stretched with a person at the end.

Explanation:

Potential energy is defined as the energy a material posesses by it viture of position. elastic potential potential energy is a special case of potential  energy which is defined as the potential energy that is stored in material that are elastic. Elastic is connected with stretching and so looking at the options , option 2 and 4 are out of the lists

A vehicle moving with a uniform acceleration of 2 m/s2 has
a velocity of 4 m/s at a certain time. What will its velocity be
a 1s later,
b 5s later?​

Answers

Answer:

a) 6 m/s

b) 14 m/s

Explanation:

Acceleration is change in velocity over change in time.

a) a = Δv / Δt

2 m/s² = (v − 4 m/s) / 1 s

v = 6 m/s

b) a = Δv / Δt

2 m/s² = (v − 4 m/s) / 5 s

v = 14 m/s

During a baseball game, a batter hits a high
pop-up.
If the ball remains in the air for 6.37 s, how
high does it rise? The acceleration of gravity
is 9.8 m/s2.

Answers

Answer:

50.0 m

Explanation:

First of all, we can find the initial velocity of the ball, using the equation

v = u + at

where

v = 0 is the velocity of the ball at the highest position

u is the initial velocity

[tex]a=g=-9.8 m/s^2[/tex] is the acceleration of gravity

[tex]t=\frac{6.37}{2}=3.19 s[/tex] is the time the ball took to reach the maximum height (half of the time it remained in the air)

Solving for u,

[tex]u=v-at=0-(-9.8)(3.19)=31.3 m/s[/tex]

Now we can find the maximum height using the other SUVAT equation:

[tex]v^2-u^2 = 2ad[/tex]

where d is the maximum height. Solving for d,

[tex]d=\frac{v^2-u^2}{2a}=\frac{0^2-(31.3)^2}{2(-9.8)}=50.0 m[/tex]

Organized elements into four groups based on properties

Answers

Answer:

Lavoisier

Explanation:

Kim travelled at a speed if 18km/h for two hours. What was the distance covered?

Answers

Answer:

36 km

Explanation:

Answer:

36

Explanation:

Which word identifies a large natural or human-made lake used to supply water?
marsh
pond
reservoir
wetland

Answers

Answer:

reservoir.     C

Explanation:

Just took the test on edge 2020

A large natural or human-made lake used to supply water is a reservoir.

What is a reservoir?

A reservoir is a large area of land or even a container where things especially water is stored for future use.

A reservoir of water can be natural or man-made.

It is usually found underground or on the surface.

Therefore, a large natural or human-made lake used to supply water is a reservoir.

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All of the following would be useful in trying to obtain procedural information to replicate an experiment previously published except for a lab journal used in the original experiment. a published scientific journal. a dictionary. a peer-reviewed article

Answers

Answer:

I am pretty sure that the answer would be a peer reviewed article.

Explanation:

I saw this because, an encyclopedia, published scientific journal, and a lab journal used in the original experiment, are all reliable sources of information.

Answer:

A dictionary

Explanation:

did the quiz

what happens to your behind when you sit for too long?

Answers

Becomes numb. Or begins to hurt

Sitting for long hours without any interruption may cause painful neck, swayed back in the long run and sometimes disc damage.

Explanation:

Human bodies are designed to stand upright. Cardiovascular and bowel functions work effectively in that way.  Sitting too long may weaken and deplete large leg and gluteal muscles which are significant in walking and stabilizing the body.

It also causes stress and reduced social skills. It can also lead to serious health hazards such as cardiovascular complications, diabetes, imbalances in spinal structure. To avoid all these exercises, yoga, stretching regularly is mandatory.

3. If a car accelerates from rest at a constant 5.5 m/s, how long will it take for the car to reach a
velocity of 28 m/s?​

Answers

Answer: 2.54 s

Explanation:

If we are talking about a constant acceleration, we can use the following equation:

[tex]V_{f}=V_{o}+2at[/tex]

Where:

[tex]V_{f}=28 m/s[/tex] is the final velocity of the car

[tex]V_{o}=0t[/tex] is the finitial velocity of the car (it started from rest)

[tex]a=5.5 m/s^{2}[/tex] is the constant acceleration of the car

[tex]t[/tex] is the time it takes to reach [tex]V_{f}[/tex] with the given constant velocity

Hence:

[tex]V_{f}=2at[/tex]

Clearing [tex]t[/tex]:

[tex]t=\frac{V_{f}}{2a}[/tex]

[tex]t=\frac{28 m/s}{2a(5.5 m/s^{2})}[/tex]

Finally:

[tex]t=2.54 s[/tex]

Final answer:

It takes approximately 5.09 seconds for the car to accelerate from rest to a velocity of 28 m/s with a constant acceleration of 5.5 m/s².

Explanation:

To determine the time it takes for a car to reach a certain velocity with a given acceleration from rest, we use the kinematic equation:

final velocity (v) = initial velocity (u) + acceleration (a) × time (t)

Given that the car starts from rest, the initial velocity u is 0 m/s. We are told the car accelerates at a constant rate of 5.5 m/s2 and we want to find the time when the car reaches a velocity of 28 m/s. Plugging in the values we have:

28 m/s = 0 m/s + (5.5 m/s2) × t

Solving for t, we get:

t = 28 m/s / 5.5 m/s2

t = 5.09 seconds (approximately).

So, it takes approximately 5.09 seconds for the car to accelerate from rest to 28 m/s at a constant acceleration of 5.5 m/s2.

Which option determines gravitational pull?

A. Acceleration

B. The sun

C. Volume

D. Mass

Answers

The Answer is : mass
D

The correct option that determines gravitational pull is mass. Gravitational force is calculated using the masses of objects and the gravitational constant, with the formula F = mg close to the Earth's surface.

Gravitational pull and Influencing Factors

The option that determines gravitational pull is mass. According to Newton's Law of Gravity, anything that has mass attracts everything else that has mass. The gravitational force (F) between two objects can be determined by the equation F = G(M1M2)/r^2, where G is the gravitational constant, M1 and M2 are the masses of the objects, and r is the distance between the centers of the two objects. The force of gravity on an object near the Earth's surface is calculated as the mass of the object (m) multiplied by the acceleration due to gravity (g), which is F = mg.

Volume does not directly determine gravitational pull; rather, it is the total quantity of matter, or mass, within that volume that contributes to gravity. The acceleration due to gravity remains constant (g = 9.81 m/s^2 near the Earth's surface) regardless of the object's mass. While the force of gravity is relatively weak, it is sufficient to keep the planets in orbit around the sun, as demonstrated in Newton's Universal Law of Gravitation.

How does the energy of a system change during a phase change?

Answers

Answer:

They are changes in bonding energy between the molecules. If heat is coming into a substance during a phase change, then this energy is used to break the bonds between the molecules of the substance. ... At the moment of melting the average kinetic energy of the molecules does not change.

Explanation:

A bicycle traveled 150 meters west from point A to point B. Then it took the same route and came back to point A. It took a total of 2 minutes for the bicycle to return to point A. What is the average speed and average velocity of the bicycle?

Answers

Answer:

2.5 m/s

0 m/s

Explanation:

Average speed is distance over time.

Average velocity is displacement over time.

The bicycle travels 150 meters from A to B, then 150 meters from B to A.  So the distance is 300 meters and the displacement is 0 m.

s = 300 m / 120 s = 2.5 m/s

v = 0 m / 120 s = 0 m/s

How does increasing the speed of a motorbike change the amount of energy in its kinetic energy store?

Answers

Answer:

Kinetic energy is energy in motion so therefor if you increase the velocity or in your case speed the kinetic energy also has to increase

Explanation:

Answer:

If the speed of a motorbike increases, its kinetic energy will also increase.

Explanation:

Kinetic energy is the energy an object has due to its motion, and it is a function of the mass and velocity of the object:

[tex]E_{k}=\frac{m*v^{2}}{2}[/tex]

From the expression, it is easy do identify a quadratic relation between kinetic energy and velocity. Therefore, if the speed of a motorbike increases, its kinetic energy will also increase.

For example, if you increase the speed of a motorbike by 10 times, and since mass is a constant value, the kinetic energy will increase by 100 times.

ad for the distance from the sun tothe earth is 1.5 x 10"m. how long does it take for light from ths sun to reach the eath? give your answer n seconds

Answers

Answer:

About 8.3 minutes

Explanation:

Use the formula for velocity as the distance covered by the light divided the time it takes: [tex][tex]velocity=\frac{distance}{time}[/tex][/tex]

Use the information about the speed of light in vacuum: [tex]300000000 \frac{m}{s} = 3*10^{8} \frac{m}{s}[/tex]

and the information you are given regarding the distance between Sun and Earth: [tex]1.5 * 10^{11} m[/tex]

to solve the first velocity equation for the unknown time "t":

[tex]velocity=\frac{distance}{time} \\3*10^8\frac{m}{s} =\frac{1.5*10^11 m}{t} \\t=\frac{1.5*10^11 }{3*10^8} s= 500 s[/tex]

we can convert second into minutes by dividing by 60: 500 s = 500/60 minutes = 8.3333... minutes

you have a 200 kg bag being lifted with a block and tackle. If you pull with 100 newtons what is the MA of the system?

Answers

Answer:

The mechanical advantage of the system is equal to 19.62

Explanation:

The ratio of the force produced by a machine to the force applied to it is called mechanical advantage. In other words it is the ratio of output force to the input force.

In this problem mass=200kg

applied force=100N  

input force=100N

output force=[tex]mg=200 \times 9.8=196N.[/tex]

mechanical advantage [tex]MA= \frac{1960}{100}=19.6[/tex]

It gives an idea about the efficiency of a mechanical device. It is indeed a measure of force amplification. In block and tackle system an assembly of ropes and pulleys is used to lift loads. When the moving block is supported by a  greater  number of rope sections the force amplification will be more.

Answer:

19.6

Explanation:

MA=Ouput/Input

To get output value multiply; 200 (which is the mass) * 9.8 (which is gravity)

So, 200*9.8=1960N

Input is 100 because that is the force you are putting into the bag

Back to our formula MA=Output/Input, enter in our values...

MA=1960/100

Now divide 1960/100=19.6

MA=19.6

(no units; they cancel out).

Radium has a half-life of 1,660 years. Calculate the number of years until only 1/16th of a sample remains.

years

Answers

Radium has a half-life of 1,660 years.The number of years until only 1/16th of a sample remains is 6641 years.

Answer: 6641 years

Explanation:

Given that the half-life of Radium is 1660 years. The number of years to be calculated when the sample of radium could just be remained of 1/16th of its part, which can be calculated by the following means,

Half life,  [tex]T_{1 / 2}=1660 \text { years }[/tex]

[tex]\frac{N}{N_{0}}=\frac{1}{16}[/tex]

t is the taken time, then,

[tex]\frac{N}{N_{0}}=e^{-\lambda t}[/tex]

[tex]\frac{N}{N_{0}}=e^{\lambda t}[/tex]

Taking ln on both sides, we get,

[tex]\lambda t=\ln \left(\frac{N}{N_{0}}\right)[/tex]

[tex]t=\frac{1}{\lambda} \ln \left(\frac{N_{0}}{N}\right)[/tex]

[tex]=\frac{T_{1 / 2}}{0.693}\left(\ln \left(\frac{N_{0}}{N}\right)\right)[/tex]

By substituting the given values,

[tex]t = \frac{1660}{0.693}(\ln 16)[/tex]

Therefore, t = 6641 years

If the mass of a person is 600kg on Earth what is the persons mass on the moon

Answers

Answer:

The mass of the person would remain 600kg.

Explanation:

mass refers to the amount of matter in a particular object. therefore even though the moon has less gravitational force than the Earths, it still would have the same mass since the person is made up of the same amount of matter on Earth and in the moon.

when asked about weight, it would be 1000N. but in mass , same 600kg.

write a one or two summary paragraph discussing this experiment and the results use tye following questions 1 according to your data was your hypothisis correct be sure to refer your data when answering this question 2 summarize ang difficulties or probloms you had in performing the experiment thaf might have affected the results list at least two real world examples that apply the findings for this experiment​

Answers

Final answer:

The experiment confirmed the initial hypothesis, supported by specific data points. Some difficulties encountered during the process could have affected the results. The findings of the experiment align with two real-world examples.

Explanation:

In the experiment we conducted, we intended to test a specific hypothesis. After careful analysis of the obtained data, the results did indicate that our hypothesis was indeed correct. Observations and specific data points derived from the experiment including (insert statistical or observational evidence) clearly supports this conclusion.

The experiment was not without difficulties. Some of the issues encountered include (insert specific problems or difficulties), which might have affected some of our findings. Two real-world applications of our findings would be (insert example one) and (insert example two). These applications provide practical illustrations on why these findings contribute relevant information to our broader understanding the subject matter.

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Would earth orbiting the sun be known as

A. Newton’s First Law of Motion

B. Newton’s Second Law of Motion

C. Newton’s Third Law of Motion

Answers

C. Newton’s Third Law of Motion.

Because...
Newtons third law implies conversation of momentum it can also be seen as following from the second law: when one object pushes a second object at some point of contact using an applied force, there must be an equation of opposite force from the second object that cancels the applied force. Otherwise, there would be a nonzero net force on a massless point which, by the second law, would accelerate the point of contact by an infinite amount.

All three of Newton's laws of motion, as well as his law of universal gravity, are involved in the explanation of orbits.

If Joey ran 60 meters in 10 seconds, then his velocity is ________ m/s.

Answers

If joey ran 60 meters in 10 seconds, then his velocity is 6 m/s

Answer:

6

Explanation:

Which scientist first proposed physical laws to mathematically describe the effect of forces on the motions of bodies?

Answers

Answer:

Issac Newton!

Explanation:

Hope this helps.

Answer: Isaac Newton

Explanation:

Isaac NewtonThe three laws of motion were first compiled by Isaac Newton in his Philosophiæ Naturalis Principia Mathematica (Mathematical Principles of Natural Philosophy), first published in 1687. Newtonused them to explain and investigate the motion of many physical objects and systems.Feb 21, 2017

The time required for one cycle, a complete motion that returns to its starting point, is called the _____.

Answers

Answer:

period

Explanation:

Answer:

The time required for one cycle, a complete motion that returns to its starting point, is called the period .

Explanation:

Any motion that repeats at regular time intervals is called periodic motion. This kind a motion has some characteristics like the period. Other important characteristic is the frequency, which is the number of complete cycles in a given time, that is, the inverse of the period.

Which of the following is an example of the conclusion phase of the scientific method?

a scientists creates graphs and performs calculations
a scientist decides on a question to explore
a scientist collects data
a scientist examines the results and answers the lab question

Answers

Answer:

A scientist examines the results and answers the lab question.

Also in the conclusion write down what you learned from the experiment.

Answer:

the dude above me is right

Explanation:

he right

What chemical phenomenon accounts for the elasticity seen in solids?

covalent bonds
hydrogen bonds
ionic bonds
all of the above

Answers

Final answer:

The elasticity in solids is primarily due to covalent bonds. These bonds allow atoms to move slightly and then return to their original positions. Other types of bonds such as ionic and hydrogen can also contribute, but typically covalent bonds are the main factor.

Explanation:

The chemical phenomenon that accounts for the elasticity seen in solids is primarily due to covalent bonds.

These bonds hold the atoms together in the solid and allow them to move slightly and then return to their original positions. Other bonds like ionic and hydrogen bonds can also contribute to some extent, but typically, covalent bonds play the largest role. If a force is applied to a solid, it can stretch or deform, but it will return to its original shape when the force is removed because of the elasticity provided by these bonds.

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An engineer in a locomotive sees a car stuck
on the track at a railroad crossing in front of
the train. When the engineer first sees the
car, the locomotive is 270 m from the crossing
and its speed is 12 m/s.
If the engineer’s reaction time is 0.79 s,
what should be the magnitude of the minimum deceleration to avoid an accident?
Answer in units of m/s
2
.

Answers

Answer:

a=0.27637 m/s²

Explanation:

Hello,

You should remember that ;

Stopping distance=reaction distance + braking distance

First find the reaction distance which is that distance traveled from point of detecting danger to start of breaking process.

Formula: d=(s*r) where s is speed in m/s and r is reaction time in seconds

Given: s=12m/s  and r=0.79 s

d= 12*0.79=9.48 m

Remaining distance to cover and stop

Where distance from locomotive to railroad crossing is 260, then remaining distance will be;

270m-9.48m=260.52 m

To get magnitude of minimum deceleration to avoid an accident you apply the formula:

v²=u²-2as

where

v= final speed = 0 m/s

u=speed of locomotive = 12 m/s

a=acceleration in m/s²

s=remaining distance to cover

v²=u²-2as

0²=12²-2*a*260.52

0=144-521.04 a

144/521.04= 521.04/521.04a

a=0.27637 m/s²

Hope this Helps!

(please help ;-;) Which of the following statements about the water cycle is true?

Organisms in the biosphere do not influence the water cycle.

The water cycle only continues during daylight hours.

Plants play a vital role in the water cycle.

Precipitation that falls to the ground ends up only as groundwater.

Answers

Answer:

I guess that the answer is plants play a vital role In the water cycle.

Answer:

Plants play a vital role in the water cycle.

Explanation:

Vegetation plays an important role in the water cycle by preventing soil erosion and increasing groundwater levels. In areas with thick vegetation cover, the foliage cover breaks the force of precipitation falling on the ground, which may otherwise cause erosion.

A 4.5 kg bowling ball rolls down a 500m hill. How much potential energy does it lose?

Answers

Answer:

22050 J

Explanation:

Given Mass of the ball, m = 4.5 Kg

Height, h =500 m

Acceleration due to gravity, [tex]g= 9.8m/s^{2}[/tex]

To calculate the potential energy we use formula,

[tex]PE = mgh[/tex]

Substituting the given values, we get

PE = 4.5× 9.8×500

    =22050 J

Final answer:

The potential energy loss for a 4.5 kg bowling ball rolling down a 500m hill would be approximately 221325 Joules in an idealized scenario.

Explanation:

The potential energy loss of an object rolling down a hill can be calculated using the formula for gravitational potential energy, PE = mgh, where m is the mass of the object, g is the gravitational acceleration (9.81 m/s² on Earth), and h is the height of the hill. So, for a 4.5 kg bowling ball rolling down a 500m hill, the potential energy loss would be PE = (4.5 kg) * (9.81 m/s²) * (500 m), which equals 221325 Joules. However, it's important to note that this is an idealized calculation and in real scenarios some of this energy would be transferred into other forms such as kinetic energy as the ball speeds up, and thermal energy due to friction.

Relevant concepts: Potential Energy, Kinetic Energy, and Gravitational Potential Energy.

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What is the weight of a text book whose mass is 2.4 kg measured on the moon? The gravitational acceleration on the moon is approximately 1/6 that on the earth.

Answers

Answer:

2.4 kg

1 kg = 10N

2.4 kg = ?

2.4 kg = 24N

On the moon 1/6th

1/6 * 24 = 4N

therefore weight of the textbook on the moon would be 4N

define average velocity and instantaneous velocity when are they same ​

Answers

Answer:

Look to the explanation

Explanation:

Average velocity: is the average rate of change of displacement with

respect to time

Average velocity is a measure for distance traveled in a given time

We can calculate the average velocity by the rule [tex]v=\frac{s}{t}[/tex]

where s is the displacement and t is the time

Instantaneous velocity: is the velocity of an object in motion at a

specific point (x , t)

instantaneous velocity is the limit of velocity as the change in time

approaches zero

We can calculate the instantaneous velocity by the rule [tex]v=\frac{ds}{dt}[/tex]

Average velocity is equal to the instantaneous velocity when

acceleration is zero

Although the temperature gradient changes from region to region in the homosphere, there is one gradient that stays the same. it continues to decrease as you increase in altitude, no matter where you are in the homospere. what gradient?

Answers

Answer: the answer is air gradient

Explanation:

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