Isaiah would have to put 10 one-hundred gram weights to balance it out because there are 1000 grams in a kilogram.
Which conversions from scientific notation to standard notation are true? Check all that apply.
For this case we have the following expressions:
a) [tex]1.71 * 10 ^ 3[/tex], in this case we have a positive exponent, therefore we move the decimal point as many times to the right as indicated by the exponent, that is, 3 times. So, we have:
[tex]1.71 * 10 ^ 3 = 1,710[/tex]
b) [tex]8.05 * 10 ^ 5[/tex], in this case we have a positive exponent, therefore we move the decimal point as many times to the right as indicated by the exponent, that is, 5 times. So, we have:
[tex]8.05 * 10 ^ 5 = 805,000[/tex]
c)[tex]2.4 * 10 ^ 4[/tex], in this case we have a positive exponent, therefore we move the decimal point as many times to the right as indicated by the exponent, that is, 4 times. So, we have:
[tex]2.4 * 10 ^ 4 = 24,000[/tex]
d) [tex]8.25 * 10^{-3}[/tex], in this case we have a negative exponent, therefore we move the decimal point as many times to the left as indicated by the exponent, that is, 3 times. So, we have:
[tex]8.25 * 10^{-3} =0.00825[/tex]
e) [tex]7.09 * 10^{-6}[/tex], in this case we have a negative exponent, therefore we move the decimal point as many times to the left as indicated by the exponent, that is, 6 times. So, we have:
[tex]7.09 * 10^{-6} = 0.00000709[/tex]
f) [tex]3.99 * 10 ^ 5[/tex], in this case we have a positive exponent, therefore we move the decimal point as many times to the right as indicated by the exponent, that is, 5 times. So, we have:
[tex]3.99 * 10 ^ 5 = 399,000[/tex]
g) [tex]8 * 10 ^ 7[/tex], in this case we have a positive exponent, therefore we move the decimal point as many times to the right as indicated by the exponent, that is, 7 times. So, we have:
[tex]8 * 10 ^ 7 = 80,000,000[/tex]
h) [tex]1.03 * 10^{-4}[/tex], in this case we have a negative exponent, therefore we move the decimal point as many times to the left as indicated by the exponent, that is, 4 times. So, we have:
[tex]1.03 * 10^{-4}= 0.000103[/tex]
Answer:
The correct options are: b, e, g and h
You and your friend are having a race, but since you are faster than him, you decide to give him a head start. He starts 10m in front of the starting line while you start on the starting line. You run at 6 meters/second, while your friend runs at 5.5 meters/second. After how many seconds will you and your friend be same distance from the starting line? seconds months
Answer:
20 seconds
Step-by-step explanation:
Your friend starts 10 meters in front of the starting line.
You start from the starting line.
You run at 6 meters/ second.
Your friend runs at 5.5 meters/second.
You and your friend will be at the same distance from the starting line only when you are able to catch your friend.
The relative speed between you two is the difference in your speed and your friend's speed that is:
[tex]6-5.5=0.5m/s[/tex]
So to cover 10 meters of separation at the speed of 0.5 meter/second it will take:
[tex]t=\frac{10}{0.5}= \frac{100}{5}=20s[/tex]
So it will take 20 seconds for you and your friend to be at the same distance from the starting line.
Answer:
20 seconds is correct.
Step-by-step explanation:
If a movie starts at 7:10 and ended at 9:05 how long was it
1 hour 55 minutes
break the time down into hours and minutes
7 : 10 → 8 : 00 = 50 minutes
8 : 00 → 9 : 00 = 1 hour
9 : 00 → 9 : 05 = 5 minutes
adding 1 hour + 50 minutes + 5 minutes = 1 hour 55 minutes
The movie lasted for a total of 115 minutes, which is calculated by adding the one hour between 7:10 and 8:10 to the additional 55 minutes between 8:10 and 9:05.
To calculate the duration of a movie that starts at 7:10 and ends at 9:05, you would subtract the start time from the end time. Starting at 7:10 and going up to 8:10 is one hour. From 8:10 to 9:05 is an additional 55 minutes. Therefore, adding these two parts together, the movie lasted for 1 hour plus 55 minutes, which is a total of 115 minutes.
Step-by-step, the calculation is as follows:
Calculate elapsed time from 7:10 to 8:10 (1 hour).Add the additional minutes from 8:10 to 9:05 (55 minutes).Combine both to find the total duration (1 hour + 55 minutes = 115 minutes).
Janelle buys 4 cases of water. Each case of water contains 12 bottles. Janelle drinks 3 bottles of water. Veronica writes a numerical expression to represent the situation. Her expression (12 - 3) x 4 has a mistake.
519 divided by 6 and 915 divided by 7 and 439 divided by 7 and 812 divided by 9 which one does not have a two digit quotient.
519/6=86.5
915/7=130.7142
439/7=62.7142
812/9=90.2222
so i think its the 1st on but i may be wrong.
In the given sets of divisions, 812 divided by 9 is the one that does not yield a three-digit quotient when considering only whole numbers. All other division operations yield a three-digit quotient.
Explanation:Let's start by dividing each number step by step. When we divide 519 by 6, we get 86.5, and when we divide 915 by 7, we get 130.71428571428572. Next, when we divide 439 by 7, we get 62.714285714285715, and finally when we divide 812 by 9, we get 90.22222222222223.
In this case, a quotient is the result obtained from division. We're asked to identify the operation which does not yield a two-digit quotient. Here, all the separate division operations give us a quotient that is a numerical value with more than two digits. However, when you consider whole numbers only, 812 divided by 9 gives us a two-digit quotient (90), while all other division operation results are three-digit numbers.
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Lucia knows the fourth term in a sequence is 52 and the ninth term in the same sequence is 82. Complete the explanation of how she can find the common difference for the sequence. Then use the common difference to find the second term of the sequence
well, I really can't really understand the way you asked the question, But, If it helps I can give you the entire sequence all the way to 82.
The sequence is,
2, 12, 22, 32, 42, 52, 62, 72 , 82, ect...,
A football team won 9 out of 12 games what percentage of games has the football team won
Help me on this someone please
Last year there were 1,435 8th grade students enrolled at your sc hool. This year there are 1,220. What is the percent change in the number of 8th grade students?
1.2% of 8th grade students is the percentage change.
Using synthetic division what is the quotient of (2x^3-3x-10) divided by (x-2)
a person who is entitled to social security benefits but is not receiving them would take his or her case to...
A: administrative court
B: Civil court
C: criminal on the state
D: It depends on the state
Answer:
A: administrative court.Step-by-step explanation:
An administrative court is specialize in administrative laws, its concern is mainly about public powers. Basically, the role of these type of courts is to ensure that officials are doing their job according to the law. Some of the issues that matters to an administrative courts are: taxation, dispensation of monetary benefits, environmental licenses, building inspection, child custody, immigration decisions, and more.
So, in this case we are talking about social security, someone is not receiving the benefits from it, so this means that a public institution is not working well, that's an administrative court jurisdiction, because it's in the public sector.
helpppppppp? please thank you
The x values are the same for both green dots, so you are looking at a simplified version of the distance formula.
d = sqrt( (x2 - x1)^2 + (y2 - y1)^2 )
Since x1 = x2 = 5, the first set of brackets = (5 - 5) = 0
d = sqrt( y2 - y1)^2 )
d = y2 - y1
y2 = 5
y1 = - 1
d = 5 - - 1
d = 6 Answer
: student council is selling tickets to the fall ball dance. Tickets cost $6.00 per person , or $10 per couple. To cover the expenses required, they need to make at least $1,450. Let x represent the number of individual ticket sold, and y represent the number of couple tickets sold. Write a linear inequality to model the situation
To model the situation with a linear inequality, represent the number of individual tickets sold as x and the number of couple tickets as y. The inequality is 6x + 10y >= 1450, signifying that the revenue from individual and couple ticket sales needs to be at least $1,450.
Explanation:To write a linear inequality to model the student council ticket sales, let x represent the number of individual tickets sold, and y represent the number of couple tickets sold. The tickets cost $6.00 per individual and $10.00 per couple. The council needs to make at least $1,450 to cover the expenses of the fall ball dance.
To derive the inequality, we consider the revenue generated from selling individual tickets (x tickets × $6.00 per ticket) plus the revenue generated from selling couple tickets (y tickets × $10.00 per ticket) should be at least $1,450:
6x + 10y ≥ 1450
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solve the world problem. the formula d = rt gives the distance traveled in time t at rate r. if a bicyclist rides for 2.3 hours and travels 41 miles, what was her average speed.
A.9.43 miles per hour
B.38.7 miles per hour
C.5.6 miles per hour
D.17.83 miles per hour
What is the value of x in the equation 3(2x + 4) = –6? (4 points)
–3
1
12
19
3.
The steps below show the incomplete solution to find the value of x for the equation
5x –2x –3 = –2 + 15:
Step 1: 5x –2x –3 = –2 + 15
Step 2: 5x –2x –3 = 13
Step 3: 3x –3 = 13
Which of these is most likely the next step? (4 points)
3x = 16
3x = 10
3x = 39
3x = 3
Jackson bought 5 ounces of raisins for $,4. How many ounces of raisins can he buy with $1
Answer:
1.25 ounces
Step-by-step explanation:
Answer: The required number of ounces that he can buy with $1 is 1.25.
Step-by-step explanation: Given that Jackson bought 5 ounces of raisins for $4.
We are to find the number of ounces of raisins that he can buy with $1.
We will be using the UNITARY method to solve the problem.
We have
Number of ounces of raisins that can be bought with $4 = 5.
Therefore, the number of ounces of raisins that can be bought with $1 is given by
[tex]\dfrac{5}{4}=1.25.[/tex]
Thus, the required number of ounces that he can buy with $1 is 1.25.
A team of scientists estimate the current number of butterflies in a park to be 20 thousand. The butterfly population is expected to increase at a rate of 4% per year. Which equation models the number of butterflies, in thousands, in the park after n years? A. 0.04(20)n B. 20(1.04)n C. 1.04(20)n D. 20(0.04)n
Answer:
Option B is the correct answer.
Explanation:
Current number of butterflies in the park = 20 thousand.
Rate of increase of butterfly population = 4% = 0.04
The population of butterfly after 1 year = 20+0.04*20 = 20*1.04
The population of butterfly after 2 years = 20*1.04 + 20*1.04*0.04 = 20*1.04*1.04
The population of butterfly after 3 years = 20*1.04*1.04 + 20*1.04*1.04*0.04 = 20*1.04*1.04*1.04
So, population of butterfly after n years = 20*(1.04*1.04*1.04* .... n times)
[tex]= 20*1.04^n[/tex]
Option B is the correct answer.
Answer:
The answer is C
Step-by-step explanation:
Please Help!!!
Which statement represents the biconditional statement of the conditional statements?
If the measures of two angles have a sum of 180º, then the angles are supplements.
If two angles are supplements, then their measures have a sum of 180º.
A. The measures of two angles have a sum of 180º if and only if the angles are supplements.
B. The measures of two angles do not have a sum of 180º if and only if the angles are supplements.
C. The measures of two angles do not have a sum of 180º if and only if the angles are not supplements.
D. The measures of two angles have a sum of 180º if and only if the angles are not supplements.
A. The measures of two angles have a sum of 180º if and only if the angles are supplements.
the angles must be supplementary to equal 180
In triangle ABC, m∠BAC = 50°. If m∠ACB = 30°, then the triangle is triangle. If m∠ABC = 40°, then the triangle is triangle. If triangle ABC is isosceles, and AB = 6 and BC = 4, then AC =
The angles in the triangle ABC total 120 degrees, verifying it as a correct triangle. Given it is an isosceles triangle with AB and AC being the equal sides of length 6, and by applying the law of cosines, the length of side AC can be calculated.
Explanation:Given the angles of the triangle ABC as m
We can use the Law of Cosines to find the length of the side AC. The Law of Cosines states that c² = a² + b² - 2ab * cos(y). By substituting the given values into this formula, we find AC = sqrt[4² + 6² - 2*4*6*cos(50°)] which gives us the length of side AC.
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help please? .....................
[tex]2x^2+6x-10=x^2+6\qquad\text{subtract}\ x^2\ \text{and 6 from both sides}\\\\x^2+6x-16=0\\\\x^2+8x-2x-16=0\\\\x(x+8)-2(x+8)=0\\\\(x+8)(x-2)=0\iff x+8=0\ \vee\ x-2=0\\\\x+8=0\qquad\text{subtract 8 from both sides}\\\boxed{x=-8}\\\\x-2=0\qquad\text{add 2 to both sides}\\\boxed{x=2}\\\\Answer:\ \boxed{B.\ -8\ and\ C.\ 2}[/tex]
(9 – 23) + |47 – 16|
A.
15
B.
17
C.
19
D.
25
You answer is: 17
Or otherwise B. is your correct answer.
(9 - 23) = -(14)
| 47 - 16| = 31
31 + (-14) = 17
Answer:
B: 17
Step-by-step explanation:
|-67.05 – 42.98| – (29.80 + 45.83)
A.
30.04
B.
34.04
C.
34.40
D.
44.04
Answer:
its d 44.04
Step-by-step explanation:
Solve the equation. Check your answer.
-11=5+8x
x=?
Answer:
x=-2
Step-by-step explanation:
Consider equation -11=5+8x
Collecting the like terms
-8x=11+5, -8x=16
Dividing through by -8 ob both sides of the equation
(-8x)-/8=16/-8
x=-2
The question is in the attached. Thank yo
C Is your awnser! have a good day Pretty sure its C because theres only 1 line
A spider ate 2 5 % 25%25, percent more bugs this month than last month. The spider ate 8 88 bugs last month. How many bugs did the spider eat this month? Bugs
bugs eaten this month = bugs eaten last month plus 25% of last month
x = 88 + .25 x 88
x = 88 + 88(.25)
= 88 + 22
= 110
Answer: 110 bugs
If EF = 5w + 20, FG = 7w + 28, and EG = 72, find the value of w. Find EF and FG
Answer:
w = 2, EF = 30 , FG = 42
Explanation:
We have EF = 5w + 20 and FG = 7w + 28
Since these points E, F and G are col-linear points we have.
EG = EF + FG
And given that EG = 72
So, EF+EG = 72
5w + 20 + 7w + 28 = 72
12w + 48 = 72
12 w = 24
w = 2
So EF = 5w + 20 = 5x2 + 20 = 30
FG = 7w + 28 = 7x2 + 28 = 42
please try to answer quickly :) thanks
For the 1 and 2/5, go four little lines past the 1.
-1/2, go five little lines in between 0 and -1.
and for -2 1/10, go to -2 and then one little line towards the 3, so it is one little line to the left of -2.
Graph the function with the given description. A linear function h models a relationship in which the dependent variable increases 1 unit for every 5 units the independent variable decreases. The value of the function at 0 is 3.
The function is an illustration of a linear function.
See attachment for the graph of [tex]\mathbf{h(x) =-\frac{1}{5}x + 3}[/tex]
Let the independent variable be x
The highlights are given as:
The value of the function at 0 is 3. i.e. h(0) = 3When the independent variable decreases by 5 (i.e. -5), the independent variable increases by 1. So, the slope (m) is -1/5From the above highlights, we have:
[tex]\mathbf{m = -\frac{1}{5}}[/tex] --- the slope
[tex]\mathbf{b = 3}[/tex] --- the y-intercept
A linear equation is represented as:
[tex]\mathbf{h(x) =mx + b}[/tex]
So, we have:
[tex]\mathbf{h(x) =-\frac{1}{5}x + 3}[/tex]
See attachment for the graph of [tex]\mathbf{h(x) =-\frac{1}{5}x + 3}[/tex]
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As a farmer, one of your responsibilities is to plow the field to prepare it for planting. On day 1, you plowed of the field. On day 2, you plowed of the field. How much more of the field did you plow on day 1 than on day 2?
Answer:
1/2 more then day 2.
Step-by-step explanation:
The difference in the amount of field plowed on day 1 compared to day 2 is 1/4, assuming day 1 was ½ and day 2 was ¼ of the field.
Explanation:To calculate how much more of the field was plowed on day 1 than on day 2, we need to subtract the fractions that represent the part of the field plowed on each day. However, you did not specify the fractions, so I will assume you meant to say ½ of the field was plowed on day 1 and ¼ of the field on day 2. Thus, the difference can be calculated as follows:
Calculate the difference in fractions: ½ - ¼.Find a common denominator for the two fractions, which is 4 in this case.Convert both fractions to have the common denominator: ½ = 2/4 and ¼ remains the same.Subtract the numerators: 2 - 1 = 1.Write the result as a fraction with the common denominator: 1/4.Therefore, you plowed 1/4 more of the field on day 1 than you did on day 2.
Nick works two jobs to pay for college. He tutors for $15 per hour and also works as a bag boy for $8 per hour. Due to his class and study schedule, Nick is only able to work up to 20 hours per week but must earn at least $150 per week. If t represents the number of hours Nick tutors and b represents the number of hours he works as a bag boy, which system of inequalities represents this scenario?
A.) t + b greater than or equal to 20 15t + 8b = 150
B.) t + b less than or equal to 20 15t + 8b greater than or equal to 150
C.) t + b less than or equal to 20 15t + 8b less than or equal to 150
D.) None of the systems shown represent this scenario.
Answer:
Option B is the correct answer.
Step-by-step explanation:
Earning for tutoring per hour = 15$
Earning for bag boy per hour = 8$
We have Nick is only able to work up to 20 hours per week but must earn at least $150 per week and t represents the number of hours Nick tutors and b represents the number of hours he works as a bag boy.
Nick is only able to work up to 20 hours per week
t + b ≤ 20
But must earn at least $150 per week
15 t + 8 b ≥ 150
Option B is the correct answer.