It is 76 miles from Waterton to Middleton. It is 87 miles from Middleton to Oak Hill. Driving directly, it is 134 miles from Waterton to Oak Hill. It is 39 miles from Oak Hill to Jackson. If Juan drives from Waterton to Middleton, then from Middleton to Oak Hill, and finally home to Waterton, how many miles does he drive?

Answer:

250 minutes

Step-by-step explanation:

Given,

Cell phone charges for a month = $ 5.00,

Additional charges per minute = $0.20,

Let the cell phone is used for x minutes for a month such that the total bill is $ 55,

⇒ Cell phone charge for the month + additional charges for x minutes = $ 55

⇒ 5.00 + 0.20x = 55

Subtracting 5 on both sides,

0.20x = 50

x = 250,

Hence, the cell phone is used for 250 minutes.

Third option is correct.

Answer:

The required probability is approximately 0.3467.

Step-by-step explanation:

Let X represents the event of making an online purchase,

Given,

The probability of making an online purchase, p = 0.35,

While, the probability of not making the online purchase, q = 1 - p = 0.65,

Hence, by the binomial distribution formula,

[tex]P(x) = ^nC_x p^x q^{n-x}[/tex]

Where, [tex]^nC_x=\frac{n!}{x!(n-x)!}[/tex]

Hence, the probability that at most 3 of them has made an online purchase is,

P(x ≤ 3) =P(x=0) + P(X=1) + P(X=2) + P(x=3)

[tex]= ^{12}C_0 p^0 q^{12-0}+^{12}C_1 p^1 q^{12-1}+^{12}C_2 p^2 q^{12-2}+^{12}C_3 p^3 q^{12-3}[/tex]

[tex]=(0.65)^{12}+12(0.35)(0.65)^{11}+66(0.35)^2(0.65)^{10}+220(0.35)^3(0.65)^9[/tex]

[tex]=0.346652696179[/tex]

[tex]\approx 0.3467[/tex]

To find the probability that at most 3 people in a sample of 12 have made an online purchase, use the binomial probability formula.

To find the probability that at most 3 people in a sample of 12 have made an online purchase, we can use the binomial probability formula. The formula is P(X ≤ k) = Σ{k=0}^{k} (nCk) * p^k * (1-p)^(n-k), where n is the sample size, k is the number of successes, p is the probability of success, and (nCk) is the combination.

In this case, n = 12, k ≤ 3, p = 0.35. So, the probability is:

Then, you can sum up these probabilities to find the total probability that at most 3 people have made an online purchase.

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Answer:

a)Smoke but doesn't drink alcoholic beverages

P=0.176  or 17.6%

b)eats between meals and drinks alcoholic beverages but doesn't smoke

P=0.062  or 6.2%

c.) neither smokes nor eats between meals

P=0.342  or 34.2%

Step-by-step explanation:

Using a Venn diagram with three circles, one for each bad health habit. Let us [tex]a[/tex] for the students that only smoke, [tex]b[/tex] for only drink alcoholic beverages, and [tex]c[/tex] for only eat between meals. Following this logic, [tex]d[/tex] represents smoke and drink alcoholic beverages but not eat between meals,  [tex]e[/tex] drink alcoholic beverages and eat between meals but not smoke,[tex]f[/tex] eat between meals and smoke but not drink alcoholic beverages. Finally [tex]g[/tex] for having all the three, this means [tex]g=52[/tex].

To find [tex]f[/tex], subtract 52 (the three problems) from 97 because this last number represents all the students that smoke and eat between meals, including the students that have the three bad habits. The same goes for 'd' and 'e'.

[tex]f=97-52=45[/tex]

[tex]e=83-52=31[/tex]

[tex]d=122-52=70[/tex]

To find [tex]a[/tex], subtract [tex]e[/tex], [tex]f[/tex], and [tex]g[/tex] from the total of smokers. This is because [tex]e[/tex], [tex]f[/tex], and [tex]g[/tex] represent smoke and at least another bad habit and [tex]a[/tex] represents only smoking.

[tex]a=210-d-f-g=210-70-45-52=43[/tex]

The same goes for [tex]b[/tex] and [tex]c[/tex].

[tex]b=258-d-e-g=258-70-31-52=105[/tex]

[tex]c=216-e-f.-g=216-31-45-52=88[/tex]

Adding all letters and subtract from the total to see if there is any healthy student:

[tex]500-a+b+c+d+e+f+g =500-43+105+88+70+31+45+52=500- 434=66[/tex]

a)Smoke but doesn't drink alcoholic beverages

This will be 'a' (only smokes) and 'f'  ( smokes and eats between meals but doesn't drink) divided by the total of students.

[tex]P=(43+45)/500=0.176[/tex]

b)eats between meals and drinks alcoholic beverages but doesn't smoke

This probability is 'e' divided by the total of students.

[tex]P=31/500=0.062[/tex]

c.) neither smokes nor eats between meals

This will be 'b' (only drinks) plus the healthy students (66) divided by the total of students.

[tex]P=(105+66)/500=0.342[/tex]

The probability a randomly selected student smokes but does not drink is 0.176, eats between meals and drinks alcohol but does not smoke is 0.062, and neither smokes nor eats between meals is 0.286.

To solve this, we need to break down the information into three categories: those who smoke (S), those who drink alcoholic beverages (D), and those who eat between meals (E). We’re told that there are 210 smokers, 258 drinkers, and 216 who eat between meals. We also know that some students fall into multiple categories.

a) Find those who smoke but do not drink. We know that 122 students both smoke and drink, so the number who smoke but do not drink is 210 (total smokers) - 122 (smokers and drinkers) = 88. The probability is then 88 out of 500, or 0.176.

b) To find those who eat between meals and drink alcoholic beverages but do not smoke, we subtract those who do all three (52) from those who eat between meals and drink (83) to get 31. The probability is then 31 out of 500, or 0.062.

c) To find those who neither smoke nor eat between meals, we subtract those who do either from the total. We add together the numbers who smoke, drink, or eat between meals (210+258+216), then subtract off twice the number who do two activities (122+83+97) since they were counted twice in the first total, then add back in the number who do all three (52) since they were subtracted too many times. Subtracting this from 500 gives us the number who do neither. So, 500 - ((210+258+216)-(2*(122+83+97))+52) = 143. The probability is then 0.286.

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Answer:

the lowest passing score would be x = 298

Step-by-step explanation:

School wishes that only 2.5 percent of students taking test pass

We are given

mean= 200,

standard deviation = 50

We need to find x

The area under the curve can be found by:

2.5 % = 0.025

So, 1- 0.025 = 0.975

We need to find the value of z for which the answer is 0.975

Looking at the z-score table, the value of z is: 1.96

Now, using the formula:

z = x - mean/standard deviation

1.96 = x - 200/50

=> 1.96 * 50 = x-200

98 = x - 200

=> x = 200+98

x = 298

So, the lowest passing score would be x = 298

The lowest passing score should be set at 102 to ensure that only 2.5 percent of the test takers pass.

Answer:

[tex]\frac{17}{64}\approx 0.27[/tex]

Step-by-step explanation:

We have been given a table to voters and their ages. We are asked to find the probability that a voter is younger than 45.

Voting age         Voters

17-29                       9

30-44                      8

45-64                    32

65+                        15

We can see from our given table that age of 17 (9+8) voters is between 17 to 44 years.

To find the probability that a voter is younger than 45, we will divide 17 by total number of voters.

[tex]\text{Total voters}=9+8+32+15=64[/tex]

[tex]\text{Probability that a voter is younger than 45}=\frac{17}{64}[/tex]

[tex]\text{Probability that a voter is younger than 45}=0.265625[/tex]

[tex]\text{Probability that a voter is younger than 45}\approx 0.27[/tex]

Therefore, the probability that a voter is younger than 45 is 0.27.

Hence, the probability is:

            [tex]\dfrac{1}{6^4}\ or\ 0.000772[/tex]

It is given that:

A fair die is rolled four times. A 2 is considered​ "success," while all other outcomes are​ "failures."

This means that the probability of 4 successes is the outcome such that each of the four die will result in the outcome 2.

Also, the probability of 2 in each of the die is: 1/6

( since, there are total 6 outcomes in a die {1,2,3,4,5,6} and out of which there is only one '2' )

Also, we know that the outcome on one die is independent on the other this means that  the probability of 4 successes is:

[tex]=\dfrac{1}{6}\times \dfrac{1}{6}\times \dfrac{1}{6}\times \dfrac{1}{6}\\\\\\\\=\dfrac{1}{6^4}\\\\\\=0.000772[/tex]

Final answer:

The probability of rolling a 2 four times in a row on a fair six-sided die is found by multiplying the probability of a single 2 (which is 1/6) four times, giving us a final probability of 1/1296 or approximately 0.0008.

Explanation:

To find the probability of rolling a 2 on a six-sided die four times in a row, we consider each roll as an independent event. The probability of rolling a 2 on each individual roll is 1/6, since there are six faces on the die and only one face with a 2 on it.

Since these events are independent, the joint probability of all four events occurring is the product of the individual probabilities:

Probability of 4 successes (rolling a 2 four times) = (1/6) * (1/6) * (1/6) * (1/6) = 1/1296.

This is computed by multiplying the probability of a single success, 1/6, four times since the dice rolls are independent events. Therefore, the probability of obtaining four successes is quite low at approximately 0.0008 when rounded to four decimal places.

Answer:

40 loads

Step-by-step explanation:

To find how many loads of wash you can do you need to divide 48 by 1 1/5.

There are two ways you can divide this, the first way is converting 48 to a fraction and dividing them.

48/1 divided by 1 1/5

convert 1 1/5 to an improper fraction

48/1 divided 6/5

change the division to multiplication and find the reciprocal of the second fraction.

48/1*5/6 = 240/6

Simplify to 40/1 or 40

The second way is changing 1 1/5 to a decimal, so its 1.2

Then divide 48 by 1.2 and you get 40.

By dividing the total amount of detergent by the amount required per load, you can determine that a 48-cup family-size box of laundry detergent can do 40 loads of wash.

To find out how many loads of wash can be done with a family-size box of laundry detergent, you need to divide the total amount of detergent, 48 cups, by the amount required per load, which is 1 and 1/5 cups.

Firstly, we need to convert the mixed fraction into an improper fraction. 1 and 1/5 = 5/5 + 1/5 = 6/5.

Then, we do the division: 48 ÷ (6/5) = 48 * (5/6) = 40. This operation is equivalent to multiplying by the reciprocal of the fraction.

So, with a 48-cup family-size box of laundry detergent, you could do 40 loads of wash, assuming each load requires 1 and 1/5 cups of detergent.

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Answer:

[tex](4)^{20}[/tex]

Step-by-step explanation:

Total number of questions = 20

Possible options for each question = 4

Sample space contains the total number of possible outcomes.

For every question there are 4 possible ways to select an answer. This holds true for all 20 questions. Selecting an answer for a question is independent of other questions/answers,

According to the counting principle, the total number of possible outcomes will be the product of the number of possible outcomes of individual events. Possible outcomes for each of the 20 questions is 4. This means we have to multiply 4 twenty times to find the total number of possible outcomes.

So, the number of elements in the sample space would be:

[tex](4)^{20}[/tex]

Select all the levels of measurement for which data can be qualitative.A.Nominal.B.IntervalC.RatioD.Ordinal

ratio

Answer:

The correct dosage is 0.5 ml

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Algebraic Equations.

We can solve this question by using the simple Rule of Three property. The Property is the following

[tex]\frac{a}{x} = \frac{b}{c}[/tex] ⇒ [tex]x = \frac{a*c}{b}[/tex]

Now we can use the property above using the values given to us to find the correct dosage for the patient.

[tex]\frac{0.2mg}{x} = \frac{0.4mg}{1ml}[/tex]

[tex]x = \frac{0.2mg*1ml}{0.4mg}[/tex]

[tex]x = \frac{0.2ml}{0.4}[/tex]

[tex]x = 0.5ml[/tex]

So Now we can see that the correct dosage is 0.5 ml

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

The possible formula for a fourth degree polynomial g is:

         [tex]g(x)=\dfrac{1}{4}(x^4-3x^3-12x^2+20x+48)[/tex]

We know that if a polynomial has zeros as a,b,c and d then the possible polynomial form is given by:

[tex]f(x)=m(x-a)(x-b)(x-c)(x-d)[/tex]

Here the polynomial g  has a double zero at -2, g(4) = 0, g(3) = 0.

This means that the polynomial g(x) is given by:

[tex]g(x)=m(x-(-2))^2(x-4)(x-3)\\\\i.e.\\\\g(x)=m(x+2)^2(x-4)(x-3)\\\\i.e.\\\\g(x)=m(x^2+2^2+2\times 2\times x)(x(x-3)-4(x-3))\\\\i.e.\\\\g(x)=m(x^2+4+4x)(x^2-3x-4x+12)\\\\i.e.\\\\g(x)=m(x^2+4+4x)(x^2-7x+12)\\\\i.e.\\\\g(x)=m[x^2(x^2-7x+12)+4(x^2-7x+12)+4x(x^2-7x+12)]\\\\i.e.\\\\g(x)=m[x^4-7x^3+12x^2+4x^2-28x+48+4x^3-28x^2+48x]\\\\i.e.\\\\g(x)=m[x^4-7x^3+4x^3+12x^2+4x^2-28x^2-28x+48x+48]\\\\i.e.\\\\g(x)=m[x^4-3x^3-12x^2+20x+48][/tex]

Also,

[tex]g(0)=12[/tex]

i.e.

[tex]48m=12\\\\i.e.\\\\m=\dfrac{12}{48}\\\\i.e.\\\\m=\dfrac{1}{4}[/tex]

Hence, the polynomial g(x) is given by:

[tex]g(x)=\dfrac{1}{4}(x^4-3x^3-12x^2+20x+48)[/tex]

The formula for the fourth degree polynomial g(x) can be determined using the known roots and points. The polynomial will have form g(x) = a(x+2)² × (x-3) × (x-4). Value of 'a' is found by setting x=0 and solving for a.

The subject of the question is determining the formula for a fourth degree polynomial, g(x), based on provided conditions. From the question we know that g(x) must have a double root at -2 (-2, -2); roots 3 and 4 (3, 0) and (4, 0); and that g(0) = 12.

With this information, we know that a fourth degree polynomial will look something like this: g(x) = ax4 + bx3 + cx2 + d = 0. But, per the conditions, it looks like g(x) = a(x+2)2 × (x-3) × (x-4), because it has roots at x = -2 (twice, or 'double'), x = 3, and x = 4.

To find the value of 'a', we use the information that at x = 0, g(x) should equal to 12. The function can then be processed as follows:

g(0) = a(0+2)2 × (0-3) × (0-4) = 12.

This will give us 'a', and the desired polynomial formula.g(x).

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Answer:

2,652

Step-by-step explanation:

51*52=2652

Answer: 0.7506

Step-by-step explanation:

Given :Mean : [tex]\mu=\text{ 7.8 grams}[/tex]

Standard deviation : [tex]\sigma =\text{ 0.2 grams}[/tex]

The formula for z -score :

[tex]z=\dfrac{x-\mu}{\sigma}[/tex]

For x= 7.65 ,

[tex]z=\dfrac{7.65-7.8}{0.2}=-0.75[/tex]

For x= 8.2 ,

[tex]z=\dfrac{8.2-7.8}{0.2}=2[/tex]

The p-value = [tex]P(-0.75<z<2)=P(z<2)-P(z<-0.75)[/tex]

[tex]=0.9772498-0.2266274=0.750622\approx0.7506[/tex]

Hence, the probability that the amount of protein is between 7.65 and 8.2 grams=0.7506.

Final answer:

To calculate the probability of a Kashi GoLean Crisp Chocolate Caramel bar having a protein content between 7.65 and 8.2 grams, we use the Z-score formula. The probability is found to be approximately 75.06%.

Explanation:

To find the probability that a randomly selected Kashi GoLean Crisp Chocolate Caramel bar has a protein content between 7.65 and 8.2 grams, we use the Z-score formula for a normal distribution, where Z = (X - μ) / σ. Here, μ (mu) is the mean, and σ (sigma) is the standard deviation. The mean (μ) is 7.8 grams, and the standard deviation (σ) is 0.2 grams.

To find the Z-scores for 7.65 grams and 8.2 grams:

Next, we consult the standard normal distribution table to find the probabilities corresponding to these Z-scores. For Z = -0.75, the probability is approximately 0.2266, and for Z = 2, it's approximately 0.9772.

The probability that the protein is between 7.65 and 8.2 grams is the difference between these two probabilities: 0.9772 - 0.2266 = 0.7506 or 75.06%.

Answer:

y=-3/4x-1/2

Step-by-step explanation:

Using the slope equation,

m=y₂-y₁

    ____

     x₂-x₁

you get the slope:

m=-5-1/6+2

m=-6/8

m=-3/4

We find that the intercept is -1/2.

The equation is y=-3/4x-1/2

The answer is:

The equation of the line that passes through the points (-2,1) and (6,-5) is:

[tex]y=-\frac{3}{4}x-\frac{1}{2}[/tex]

To solve the problem, we can use the following formula:

We have that:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}*(x-x_1)[/tex]

So, using the given points (-2,1) and (6,-5), we have:

[tex]y-1=\frac{-5-1}{6-(-2)}*(x-(-2))[/tex]

[tex]y-1=\frac{-6}{6+2}*(x+2)[/tex]

[tex]y-1=\frac{-6}{8}*(x+2)[/tex]

[tex]y-1=-\frac{3}{4}*(x+2)[/tex]

[tex]y=-\frac{3}{4}*(x+2)+1[/tex]

[tex]y=-\frac{3}{4}*(x)-\frac{3}{4}**(2)+1[/tex]

[tex]y=-\frac{3}{4}(x)-\frac{6}{4})+1[/tex]

[tex]y=-\frac{3}{4}(x)-\frac{3}{2})+1[/tex]

[tex]y=-\frac{3}{4}x-\frac{1}{2}[/tex]

Hence, we have that the equation of the line that passes through the points (-2,1) and (6,-5) is:

[tex]y=-\frac{3}{4}x-\frac{1}{2}[/tex]

Have a nice day!

Answer: 0.074

Step-by-step explanation:

Given : The total number of U.S. adults in the sample = 800

The number of U.S. adults dine out at a restaurant more than once a week = 216

The probability for an adult dine out more than once per week :-

[tex]\dfrac{218}{800}[/tex]

If another person is selected without replacement ,then

Total adults left = 799

Total adults left who dine out at a restaurant more than once a week = 217

The probability for the second person dine out more than once per week :-

[tex]\dfrac{217}{799}[/tex]  

Now, the probability that both adults dine out more than once per week :-

[tex]\dfrac{218}{800}\times\dfrac{217}{799}=0.074[/tex]

Final answer:

To calculate the probability that both selected adults dine out more than once per week, multiply the probability of the first adult dining out more than once (218/800) by the probability of the second adult dining out more than once after the first has been selected (217/799).

Explanation:

The probability that both adults dine out more than once per week can be found using the formula for the probability of successive events without replacement. With 218 out of 800 US adults dining out more than once per week, the probability of the first adult dining out more than once is 218/800. If one adult who dines out more than once a week has been chosen, there are now 217 such adults left and 799 total adults. The probability of the second adult dining out more than once is 217/799. The joint probability of both events happening is calculated by multiplying these two probabilities together:

P(both dine out) = (218/800)
times (217/799)

Simplify this to find the requested probability.

Answer:

x = 5 cos 2t

Step-by-step explanation:

given equation

x'' + 4x = 0 ;     x(0) = 5,       x'(0) = 0

L{ x'' + 4 x } = 0

L{x''} + 4 L{x} = 0

s² . L(x) - s . x(0) - x'(0) + 4 L{x} = 0

( s² + 4 ).  L(x) - 5 s = 0

L(x) = [tex]\dfrac{5s}{s^2 +4}[/tex]

[tex]L(\dfrac{s}{s^2 +a^2})[/tex]  = cos at

so,

x = 5  [tex]L^{-1}(\dfrac{s}{s^2 +2^2})[/tex]

x = 5 cos 2t

Answer:

μ = 59, σ = 5.1962

Step-by-step explanation:

For a uniform distribution, where a is the minimum and b is the maximum, the mean (or average) is:

μ = (a + b) / 2

And the standard deviation is:

σ = (b − a) / √12

Here, a = 50 and b = 68.

The mean is:

μ = (50 + 68) / 2

μ = 59

And the standard deviation is:

σ = (68 − 50) / √12

σ = 5.1962

The mean weight of a package of French fries produced by Polar Bear Frozen Foods is 59 ounces. The standard deviation of the weight is approximately 5.1962 ounces.

The question pertains to understanding the mean and standard deviation of a uniformly distributed variable, specifically the weight of French fries produced by Polar Bear Frozen Foods. A uniform distribution is a type of probability distribution that has constant probability.

The formula for the mean (or average) of a uniform distribution is (a + b) / 2 where 'a' is the minimum value and 'b' is the maximum value. Given in the question a = 50 ounces and b = 68 ounces, we obtain the mean as (50+68)/2 = 59 ounces.

The formula for the standard deviation of a uniform distribution is sqrt[(b-a)^2 /12 ]. Thus, substituting values we get sqrt[(68-50)^2 / 12] = sqrt[324/12] = sqrt[27] = 5.1962 ounces (rounded to four decimal places).

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Answer:

d1=69.12 lbs/cbf, d2=1.32 lbs/cbf

Step-by-step explanation:

Hello

to make the conversion we will need

1" = 1 inch

12 inch = 1 feet

1 kg= 2. 20 lbs

Point 1, step 1

convert inch to feet

[tex]15"=15 inch*(\frac{1 feet}{12 in})=\frac{5}{4} ft\\ 20"=20 inch*(\frac{1 feet}{12 in})=\frac{5}{3}ft\\d=\frac{m(lbs)}{v(cbf)}\\ d=\frac{180 lbs}{\frac{5}{4} ft*\frac{5}{4} ft*\frac{5}{3} ft}\\ d=69.12\ lbs/cbf[/tex]

Point 2, step 2

[tex]90kg=90kg*\frac{2.2 lbs}{1 kg} =198 lbs\\\\d=\frac{m}{v}\\ d=\frac{198 lbs}{150 cbf}\\d=1.32\ lbs/cbf[/tex]

I hope it helps

Answer:

all parts has been answered

Step-by-step explanation:

Let us assume

after T years both colleges have same enrollment

Enrollment at college A after T years = 18400+500*T

Enrollment at college B after T years = 37650-1250*T

 Both the colleges will have same enrollment after T years

Hence  

18400+500*T=37650-1250*T

1750*T=19250

T=11 years

Present year would be =2005+11=2016

In the year 2016, the enrollment of both the colleges will be same.

Total enrollment at each college = 18400+11*500=37650-1250*11=23900

The total enrollment at each college will be 23900 students

Answer:

(a) 2 × 10^9 kg/m^3; (b) roughly the mass of the Statue of Liberty.

Step-by-step explanation:

(a) Density of white dwarf:

D = m/V

Data:

 1 solar mass = 2 × 10^30 kg

1 Earth radius = 6.371 × 10^6 m

Calculations:

V = (4/3)πr^3 = (4/3)π × (6.371 × 10^6 m)^3 = 1.083 × 10^21 m^3

D = 2 × 10^30 kg/1.083 × 10^21 m^3 = 2 × 10^9 kg/m^3

2. Weight on a white dwarf

The formula for weight is

w = kMm/r^2

where

k = a proportionality constant

M = mass of planet

m = your mass

w(on dwarf)/w(on Earth) = [kM(dwarf)m/r^2] /[kM(Earth)m/r^2

k, m, and r are the same on both planets, so

w(on dwarf)/w(on Earth) = M(dwarf)/M(Earth)

w(on dwarf) = w(on Earth) × [M(dwarf)/M(Earth)]

Data:

M(Earth) = 6.0 × 10^24 kg

Calculation:

w(on dwarf) = w(on Earth) × (2 × 10^30 kg /6.0 × 10^24 kg)

= 3.3 × 10^5 × w(on Earth)

Thus, if your weight on Earth is 60 kg, your weight on the white dwarf will be

3.3 × 10^5 × 60 kg = 2 × 10^7 kg  

That's roughly as heavy as the Statue of Liberty is on Earth.

We have [tex]y'=0[/tex] when [tex]y=0[/tex] or [tex]y=-4[/tex], so we need to check the sign of [tex]y'[/tex] on 3 intervals:

We can summarize this behavior as in the attached plot. The arrows on the [tex]y[/tex]-axis indicate the direction of the solution as [tex]t\to\infty[/tex]. We then classify the solutions as follows.

Answer:   0.1557

Step-by-step explanation:

Given : Mean : [tex]\mu=\ 8[/tex]

Standard deviation : [tex]\sigma= 0.4[/tex]

The formula to calculate the z-score :-

[tex]z=\dfrac{x-\mu}{\sigma}[/tex]

Let the random variable x (number of hours) is normally distributed .

For x= 8.4

[tex]z=\dfrac{8.4-8}{0.4}=1[/tex]

For x= 9.1

[tex]z=\dfrac{9.1-8}{0.4}=2.75[/tex]

The p-value =[tex] P(8.4<x<9.1)=P(1<z<2.75)[/tex]

[tex]=P(z<2.75)-P(z<1)= 0.9970202-0.8413447\\\\=0.1556755\approx0.1557[/tex]

Answer:

a. $633 849.78; b. $233 849.78

Step-by-step explanation:

a. Value of Investment

The formula for the future value (FV) of an investment with periodic deposits (p) is

FV =(p/i)(1 + i)[(1 + i)^n -1)/i]

where

 i = interest rate per period

n = number of periods

Data:

    p = $10 000

APR = 8.5 % = 0.085

     t = 10 yr

Calculations:

Deposits are made every quarter, so

i = 0.085/4 = 0.02125

There are four quarters per year, so

n = 10 × 4 = 40

FV = (10 000/0.02125)(1 + 0.02125)[(1 + 0.02125)^40  - 1)]

= 470 588.235 × 1.02125 × (1.02125^40 - 1)

= 480 588.235(2.318 904 06 - 1)

= 480 588.235 × 1.318 904 06

= 633 849.78

The company will have $633 849.78 in scholarship funds.

b. Interest

Amount accrued =                                                                  $633 849.78

Amount invested = 40 payments × ($10 000/1 payment) =   400 000.00

Interest =                                                                                 $233 849.78

The scholarship fund earned $233 849.78 in interest.

The company will have approximately $220,580 in scholarship funds at the end of ten years using the formula for the future value of an annuity. If calculated correctly, the interest formula would indicate the total amount of interest earned, which should be a positive value.

To calculate how much the company will have in scholarship funds at the end of ten years, we use the future value formula of an annuity. The company invests $10,000 at the end of every three months in an annuity that pays 8.5% interest compounded quarterly. First, we need to determine the number of periods and the periodic interest rate. Since the investments are made quarterly, there are 4 periods in a year. Over ten years, there are 4 * 10 = 40 periods. The periodic interest rate is 8.5% per year, or 8.5%/4 = 2.125% per period.

Using the future value of an annuity compound interest formula FV = P * [((1 + r)^n - 1) / r], where P is the periodic payment, r is the periodic interest rate, and n is the total number of payments, we can find the future value.

In this case, P = $10,000, r = 2.125% (or 0.02125 as a decimal), and n = 40. Plugging these values into the formula, we get:

FV = $10,000 * [((1 + 0.02125)^40 - 1) / 0.02125]

FV = $10,000 * [(1.02125^40 - 1) / 0.02125]

FV = $10,000 * [2.2058...]

FV = $220,580...

Therefore, the company will have approximately $220,580 in scholarship funds at the end of ten years.

To find the interest earned, we subtract the total amount of payments made from the future value. The total amount of payments is $10,000 * 40 = $400,000. So the interest earned is $220,580 - $400,000 = $-179,420. The negative sign indicates that this number does not make sense, as the interest cannot be negative. This is an error, and we should re-calculate:

Total investments = $10,000 * 40 = $400,000

Interest = Future Value - Total Investments

Interest = $220,580 - $400,000 = $-179,420 (This is incorrect)

To correct this, we should correctly apply the future value formula once more and make sure all calculations are done precisely. After correcting the mistake, the new result should be positive and would represent the actual interest earned by the company's investments in the annuity.

Answer:

The rate of return is 61.3%.

Step-by-step explanation:

Rate of return is given by:

[tex]\frac{current price - original price}{original price}\times100[/tex]

= [tex]\frac{1775-1100}{1100} \times100[/tex]

= [tex]\frac{675}{1100} \times100[/tex]

= 61.36% ≈ 61.3%

Hence, the rate of return is 61.3%.

Answer:

True.

Step-by-step explanation:

We can represent an odd number by 2n + 1 where n = 0, 1, 2, 3, 5 etc.

Substituting:

a^2 + a = (2n + 1)^2 + 2n + 1

=  4n^2 + 4n + 1 + 2n + 1

= 4n^2 + 6n + 2

= 2(2n^2 + 3n + 1)

which is even because any integer multiplied by an even number is even.

This is also true if we use a negative odd integer:

We have 4n^2 + 4n + 1  - 1 - 2n

= 4n^2 + 2n

=  2(2n^2 + n(.

The statement is true. For any odd integer 'a', the expression 'a² + a' will always be even. This is because when 'a' (in the form of 2n+1 where n is any integer) is squared and added to 'a', the result is a number that is divisible by two, hence an even number.

Your statement is true. If a is any odd integer, then a² + a is indeed even. Here's why:

Any odd number can be expressed in the form 2n+1, where n is any integer. So, when you square this you get (2n+1)² = 4n² + 4n + 1, which simplifies to 2(2n² + 2n) + 1. This is an odd number.

Then, if you add a (which is 2n+1), you get 2(2n² + 2n) + 1 + 2n + 1, which simplifies to 2(2n² + 3n + 1). This is divisible by 2, which means it's an even number. Therefore, the expression a² + a represents an even number.

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Answer:

C. =$D$5*E6

Step-by-step explanation:

In excel Columns are A, B, C, D, .....

And, rows are, 1, 2, 3, ....

Also, the intersection of column and row is called cell,

eg : A1 is a cell,

When we copy a function formula from a cell A1 to B2,

Then in the formula we replace A1 by B2 or vice versa,

But the row or column which comes after the dollar sign is anchored or absolute.

That is, when we copy an excel formula with $ sign they will copy cells referred in that formula relative to the position where they are being copied to.

Thus, if we have the formula =$D$5*E5 in cell F5,

Then, $D$5*E6 must be the new formula into cell 6.

Option 'C' is correct.

Answer:

The mean is 66.667 ( approx )

Step-by-step explanation:

Let x be the sum of Tony's group and y be the sum of Alice's group,

We know that,

[tex]Mean = \frac{\text{Total sum of observations}}{\text{Number of observations}}[/tex]

According to the question,

In Tony's group,

Students = 20,

Mean = 60,

[tex]\implies \frac{x}{20}=60\implies x = 1200[/tex]

In Alice's group,

Students = 10,

Mean = 80,

[tex]\implies \frac{y}{10}=80\implies y = 800[/tex]

Thus, the total sum of combined group of 30 students = 1200 + 800 = 2000,

Hence, the mean of the combined group = [tex]\frac{2000}{30}[/tex]

[tex]\approx 66.667[/tex]

Answer:

[tex]6^4[/tex]

Step-by-step explanation:

We'd solve the exponents first:

[tex]6^5 = 7776[/tex]

[tex]6^4 = 1296[/tex]

Subtract:

7776 - 1296 = 6480

Divide:

[tex]6480\div5 = 1296[/tex]

We already know [tex]6^4 = 1296[/tex]

Our answer is [tex]6^4[/tex]

Answer:

6^4

Step-by-step explanation:

6^5 - 6^4 / 5 = ?

Factor out a 6^4

6^4(6-1)

---------------

5

Simplify

6^4(5)

---------------

5

Cancel the 5's

6^4

Answer:

a.The profit is 40000 when sales are 10000 units.

b.Break-even point quantity and revenue=6000

c.When profits are at P9,000, sales are 6900

d.Fixed cost must decrease

e.The volume of sales to cover the fixed cost is 1500 units

f.If the firm want to break-even at a lower number of units, then the price will rice

Step-by-step explanation:

a.Profit is the difference between sales and cost

Profit= price* sales -((Variable cost * sales) +Fixed cost)

Profit when sales are 10000 units must be

P=40*10000-((30*10000)+60000)

P=400000-(300000+60000)=400000-360000

Profit=40000

The profit is 40000 when sales are 10000 units.

b.The break-even point quantity and revenue is when profit=0

So,  Profit= price* sales -((Variable cost * sales) +Fixed cost)

If profit is 0, then (Variable cost * sales) +Fixed cost =price* sales

30x +60000=40x

10x=60000

x=60000/10=6000

Break-even point quantity and revenue=6000

c. Profit= price* sales -((Variable cost * sales) +Fixed cost)

9000=40x -(30x +60000)=40x -30x -60000)

9000 +60000=40x-30x

69000=10x

x=6900 units

d. break even at sales volume of 500 units

(Variable cost * sales) +Fixed cost =price* sales

30*500+FC=40*500

1500+FC=2000

FC=2000-1500

FC=500 Fixed cost must decrease

e.The volume of sales to cover the fixed cost

To only cover fixed cost, sales have to be 60000

Fixed cost =price* sales

Sales=Fixed cost/price

Sales 60000/40=1500 units

f. If the firm want to break-even at a lower number of units, then the price will rice

Remember that break-even formula is

(Variable cost * sales) +Fixed cost =price* sales

Variable an fixed cost remain constant, if sales go down,  then price must go up.

Answer:

The volume is [tex]\frac{490\pi}{39}[/tex] cubic units.

Step-by-step explanation:

The given curve is

[tex]y=7x^6[/tex]

The given line is

[tex]y=7x[/tex]

Equate both the functions to find the intersection point of both line and curve.

[tex]7x^6=7x[/tex]

[tex]7x^6-7x=0[/tex]

[tex]7x^6-7x=0[/tex]

[tex]7x(x^5-1)=0[/tex]

[tex]7x=0\rightarrow x=0[/tex]

[tex]x^5-1=0\rightarrow x=1[/tex]

According to washer method:

[tex]V=\pi \int_{a}^{b}[f(x)^2-g(x)^2]dx[/tex]

Using washer method, where a=0 and b=1, we get

[tex]V=\pi \int_{0}^{1}[(7x)^2-(7x^6)^2]dx[/tex]

[tex]V=\pi \int_{0}^{1}[49x^2-49x^{12}]dx[/tex]

[tex]V=49\pi \int_{0}^{1}[x^2-x^{12}]dx[/tex]

[tex]V=49\pi [\frac{x^3}{3}-\frac{x^{13}}{13}]_0^1[/tex]

[tex]V=49\pi [\frac{1^3}{3}-\frac{1^{13}}{13}-(0-0)][/tex]

[tex]V=49\pi [\frac{1}{3}-\frac{1}{13}][/tex]

[tex]V=49\pi (\frac{13-3}{39})[/tex]

[tex]V=49\pi (\frac{10}{39})[/tex]

[tex]V=\frac{490\pi}{39}[/tex]

Therefore the volume is [tex]\frac{490\pi}{39}[/tex] cubic units.

The volume of the solid obtained by rotating the region bounded by the curves y = 7x6 and y = 7x, for x ≥ 0, around the x-axis is determined by setting up and evaluating a volume integral using the method of cylindrical shells. The intersection points of the curves, that serve as the limits of the integral, are found by equating the two functions, giving x = 0 and x = 1.

To find the volume of the solid obtained by rotating the area between the curves y = 7x6 and y = 7x around the x-axis, we use the method of cylindrical shells.

Firstly, we find the intersection points of the two curves by setting them equal to each other: 7x6 = 7x, which gives us x = 0 and x = 1.

Next, we set the volume integral and evaluate it over the range [0,1]. The general formula is V = 2π ∫ from a to b [x * (f(x) - g(x)) dx]. Here, f(x) = 7x6 and g(x) = 7x, therefore,

V = 2π ∫ from 0 to 1 [x * (7x6 - 7x) dx] = 2π ∫ from 0 to 1 [7x7 - 7x2 dx],

which can be integrated term-by-term. The antiderivatives of x7 and x2 are (1/8)x8 and (1/3)x3, respectively. By implementing these with the Fundamental Theorem of Calculus, we then substitute the limits of integration, subtract, and simplify to reach the final volume of the rotated solid.

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