Given:
Time: 3.5 hrs
Velocity: 120 miles/hr
Now Distance= Speed × Time
Now Velocity and speed have the same magnitude. Velocity being a vector quantity has a definite direction. Whereas speed is a scalar quantity,it indicates only the magnitude an doesn't define any direction.
Hence Distance = Velocity x time
Distance = 3.5 × 120 = 420 miles
While Bob is demonstrating the gravitational force on falling objects to his class, he drops an 1.0 lb bag of feathers from the top of the science building. Determine the distance the bag has traveled after falling for 1.5 seconds assuming it has reach free fall and given the gravitational acceleration of 9.8 m/sec2.
A) 7.4 m
B) 11 m
C) 15 m
D) 22 m
The answer here is A) 7.4 m.
As per the question Bob drops the bag full with feathers from the top of the building.
The mass of the bag(m)= 1.0 lb
Let the air resistance is neglected.As the bag is under free fall ,hence the only force that acts on the bag is the force of gravity which is in vertical downward direction.
Here the acceleration produced on bag due to the free fall will be nothing else except the acceleration due to gravity i.e g =9.8 m/s^2
Here we are asked to calculate the distance travelled by the bag at the instant 1.5 s
Hence time t= 1.5 s
From equation of kinematics we know that -
S=ut + 0.5at^2 [ here S is the distance travelled]
For motion under free fall initial velocity (u)=0.
Hence S= 0×1.5+{0.5×(-9.8)×(1.5)^2}
⇒ -S =0-11.025 m
⇒ S= 11.025 m
=11 m
Here the negative sign is taken only due to the vertical downward motion of the body .we may take is positive depending on our frame of reference .
Hence the correct option is B.
If a weight lifter holds a 200 kg barbell in place over his head, he _______
A:does no work because the force he applies does not cause the barbell to move.
B: does work because the barbell is heavy to hold.
We have that from the Question, it can be said that
does no work because the force he applies does not cause the barbell to move. Option AFrom the Question we are told
If a weight lifter holds a 200 kg barbell in place over his head, he _______
A:does no work because the force he applies does not cause the barbell to move.
B: does work because the barbell is heavy to hold.
Generally the equation for work is mathematically given as
w=f*d
Therefore
For an instance where distance traveled is zero and force exerted is a 1000N the work done will still be zero because
1000*0 =0
Therefore
does no work because the force he applies does not cause the barbell to move.
Option A
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the orbit of mars is never far from the ecliptic. why?
So because trajectories including both universes are more or less inclined, Mars' orbit is not far from this same ecliptic.
The above ecliptic plane, which also spans from either the sun to the earth, is entirely fictitious. Whenever we place together with all planetary or asteroids on this ecliptic plane, those who don't precisely fit throughout this imaginary straight border, nevertheless Mars would be just 2 degrees away from that as well, because it is very centered and yet never pulls us objectively speaking.
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A worker pushes a large rock to the north while another worker helps by pushing it to the east. If they both exert equal force, in what direction does the rock move?
Question 2 options:
northeast
east
north
southwest
let the magnitude of force applied by each worker be "F"
consider east-west direction along X-axis and north-south direction along Y-axis
In unit vector form, force vector by worker pushing in east direction is given as
[tex]\underset{A}{\rightarrow}[/tex] = F [tex]\hat{i}[/tex] + 0 [tex]\hat{j}[/tex]
In unit vector form, force vector by worker pushing in north direction is given as
[tex]\underset{B}{\rightarrow}[/tex] = 0 [tex]\hat{i}[/tex] + F [tex]\hat{j}[/tex]
resultant force is given as the vector sum of two vector forces as
[tex]\underset{R}{\rightarrow}[/tex] = [tex]\underset{A}{\rightarrow}[/tex] + [tex]\underset{B}{\rightarrow}[/tex]
[tex]\underset{R}{\rightarrow}[/tex] = (F [tex]\hat{i}[/tex] + 0 [tex]\hat{j}[/tex] ) + (0 [tex]\hat{i}[/tex] + F [tex]\hat{j}[/tex] )
[tex]\underset{R}{\rightarrow}[/tex] = F [tex]\hat{i}[/tex] + F [tex]\hat{j}[/tex]
direction of the force is hence given as
θ = tan⁻¹(F/F)
θ = tan⁻¹(1)
θ = 45 degree north of east
hence the direction is north-east
A ball is dropped off the balcony of a hotel room and it takes 2.8s to fall to the ground . how high above the ground is the ball
The height of the ball above the ground is 38.45 m
First we will calculate the velocity of the ball when it touch the ground by using first equation of motion
v=u+gt
v=0+9.81×2.8
v=27.468 m/s
now the height of the ground can be calculated by the formula
v=√2gh
27.468=√2×9.81×h
h=38.45 m
What is the eccentricity of a planet's orbit if the focal distance is 8 and the major axis is 32?
Focal distance of an ellipse is given by the formula
[tex]f = ae[/tex]
here a = length of semi major axis
e = eccentricity of the path
now here we know that
length of major axis for the path of planet is given as 32 units
so here we can say
[tex]2a = 32 units[/tex]
[tex]a = 16 units[/tex]
so length of semi major axis is 16 units
focal distance for the planet path is given as 8 units
now from the above formula we can write
[tex]f = a*e[/tex]
[tex]8 = 16*e[/tex]
[tex]e = \frac{8}{16}[/tex]
[tex]e = \frac{1}{2} = 0.5[/tex]
so eccentricity for the path of planet will be 0.5
A block is at rest on the incline shown in the gure. The coefficients of static and kinetic friction are 0.6 and 0.51, respec- tively The acceleration of gravity is 9.8 m/s 29° What is the frictional force acting on the 46 kg mass?
Normal reaction force on the block while it is at rest on the inclined plane is given as
[tex]F_n = mgcos\theta[/tex]
here we know that
m = 46 kg
[tex]\theta = 29^o[/tex]
now we will have
[tex]F_n = 46*9.8*cos29 = 394.3 N[/tex]
now the limiting friction or maximum value of static friction on the block will be given as
[tex]F_s = \mu_s * F_n[/tex]
[tex]F_s = 0.6 * 394.3 = 236.56 N[/tex]
Above value is the maximum value of force at which block will not slide
Now the weight of the block which is parallel to inclined plane is given as
[tex]F_{||} = mg sin\theta[/tex]
here we know that
[tex]F_{||} = 46*9.8 sin29 = 218.55 N[/tex]
Now since the weight of the block here is less than the value of limiting friction force and also the block is at rest then the frictional force on the block is static friction and it will just counter balance the weight of the block along the inclined plane.
So here friction force on the given block will be same as its component on weight which is 218.55 N
The frictional force acting on the 46 kg mass is approximately 202.70 N.
Explanation:
The frictional force acting on the 46 kg mass can be found using the formula ƒk = µkN, where µk is the coefficient of kinetic friction and N is the normal force. The normal force can be found using N = mg cos(theta), where m is the mass of the block and g is the acceleration due to gravity. Plugging in the values, we get N = (46 kg)(9.8 m/s^2) cos(29°) = 397.67 N.
Now, we can calculate the frictional force using ƒk = µkN = (0.51)(397.67 N) = 202.70 N.
Therefore, the frictional force acting on the 46 kg mass is approximately 202.70 N.
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Arrange the steps in order to explain how a tornado forms.
An extreme difference in wind speed at two elevations causes wind shear.
The column of air stretches to form a tornado.
The difference in wind speed causes a column of air to rotate horizontally.
A strong updraft connects the rotating air with the clouds above.
Answer
The steps in order to explain how a tornado forms are;
1. An extreme difference in wind speed at two elevations causes the wind shear
2. The difference in wind speed causes a column of air to rotate horizontally
3. A strong updraft connects the rotating air with clouds above
4. The column of air stretches to form a tornado
Explanation
The typical steps of tornado formation follow the below steps;
• Occurrence of a large thunderstorm which happens in the cumulonimbus clouds
• There is a change in wind direction and speed at higher attitudes that makes the air to swirl horizontally
• Air rising from the ground pushes up on the swirling air and tips over it
• The swirling air funnel starts to suck up more warm air from the ground
• The funnel enlarges and stretches towards the ground
• The funnel touches the ground level to form a tornado
The formation of a tornado involves wind shear caused by extreme differences in wind speed at various elevations, leading to horizontal air rotation that becomes vertical when connected to an updraft from the clouds. Tornadoes result from severe thunderstorms and can produce destructive winds up to 500 km/h.
Explanation:To understand how tornadoes form, it is essential to arrange the steps of their formation in the correct sequence:
An extreme difference in wind speed at two elevations causes wind shear.The difference in wind speed causes a column of air to rotate horizontally.A strong updraft connects the rotating air with the clouds above.The column of air stretches to form a tornado.Tornadoes are associated with severe thunderstorms, particularly supercells, that involve a horizontally rotating column of air. The horizontal rotation shifts to a vertical axis due to the contrasting wind speeds, such as the strong cold winds from the jet stream and warmer winds rising from the Gulf of Mexico. A tornado is a violent rotating column of air that extends from a thunderstorm down to the ground and can reach wind speeds as high as 500 km/h (approximately 300 miles/h), particularly at the bottom where the funnel is narrowest.
Storm reports reveal that atmospheric pressure plays a crucial role in weather determination, and significant pressure differences can lead to strong winds capable of producing tornadoes. The understanding of rotational motion and angular momentum are integral to comprehending why tornadoes spin and increase in velocity; as their radius decreases, similar to an ice skater pulling in her limbs to spin faster.
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A 4-kg ball is 2 cm away from one 1-kg ball and 6 cm away from another 1-kg ball. Use the relationships among the balls to describe two factors that affect gravity. Also explain why the balls do not move toward each other unless acted upon by another force.
Force of gravitation between two balls is given by the formula
[tex]F = \frac{Gm_1 m_2}{r^2}[/tex]
here we know that
[tex]m_1[/tex] = mass of ball 1
[tex]m_2[/tex] = mass of ball 2
[tex]r[/tex] = distance between two balls
So here the two factors that will affect the force of gravitation is
1. Distance between two balls
2. mass of two balls
Here balls do not move due to gravitation attraction force because here the force of gravitation is very small as it is compared with other forces like frictional force between balls and ground.
So this weak gravitational force is balanced by frictional force on balls
SO all balls remains at rest
Gravitational force is directly affected by the masses of the objects involved and the distance between them. Despite this, objects do not simply move towards each other due to gravity because other forces such as friction and air resistance often counteract this attraction.
Explanation:The question essentially asks about two factors that affect gravity and why the balls do not move towards each other unless acted upon by an external force. Here's what we know from Newton's Law of Universal Gravitation: the gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. In simple terms, this means that the larger the masses of the objects, and the closer they are to each other, the stronger the gravitational pull between them.
Now, onto the second part of your question. In a perfect vacuum where no other forces exist, the balls would indeed move towards each other. However, in the real world, there are other forces at play, such as friction and air resistance, that counteract the gravitational pull. Therefore, unless these balls are acted upon by a stronger force (like a push or a pull), they will not move towards each other.
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What is another name for the dependent variable in an experiment? A. A manipulated variable B. A responding variable C. A controlled variable D. An independent variable
The dependent variable in an experiment is also called the responding variable, as it responds to changes in the independent variable.
In the context of an experiment, the dependent variable is also known as the responding variable. This is because it is the variable that responds to the changes made to the independent variable, which is referred to as the manipulated variable due to it being purposefully altered by the researcher. Other variables in the experiment, known as control variables, are kept constant so they do not affect the outcome of the dependent variable.
A metal ball of mass 2 kg is supported by a massless inextensible string, 12 cm long. A horizontal force displaces the ball by 30oto the vertical so that the string remains taut. Find:a) the horizontal force.b) the tension in the thread.
As it is given that 2 kg mass is suspended by 12 cm long thread and then a horizontal force is applied on it so that it remains in equilibrium at 30 degree angle
So here we can use force balance in X and Y directions
now for X direction or horizontal direction we can use
[tex]F = Tsin30[/tex]
for vertical direction similarly we can say
[tex]mg = T cos30[/tex]
so here we first divide the two equations
[tex]\frac{F}{mg} = \frac{sin 30}{cos 30}[/tex]
[tex]\frac{F}{mg} = tan 30[/tex]
[tex]F = mg tan30[/tex]
now plug in all values in the above equation
[tex]F = 2 * 9.8 * tan30[/tex]
[tex]F = 11.3 N[/tex]
Part b)
now in order to find the tension in the thread we can use any above equation
[tex]F = T sin30[/tex]
[tex]11.3 = T sin30[/tex]
[tex]T = \frac{11.3}{sin30}[/tex]
[tex]T = 22.6 N[/tex]
so tension in the thread will be 22.6 N
Final answer:
To find the horizontal force and tension in a string supporting a displaced metal ball, one must use equilibrium principles along with trigonometric relations from Newton's second law, focusing on the components of tension.
Explanation:
The question involves finding a) the horizontal force and b) the tension in the thread that supports a metal ball displaced by 30 degrees to the vertical. This situation can be analyzed using principles of equilibrium and Newton's second law. When the ball is displaced, it creates an angle with the vertical, leading to a horizontal component of the tension acting as the horizontal force, and a vertical component of the tension balancing the weight of the ball.
To calculate these forces, we can use trigonometric relations and Newton's second law. The tension in the string can be resolved into two components: the horizontal component (Thorizontal) and the vertical component (Tvertical). The vertical component balances the weight of the ball (mg), and the horizontal component is the force needed to keep the ball in equilibrium.
For a ball of mass 2 kg displaced at a 30-degree angle, assuming g = 9.8 m/s2, the calculations would involve using the equations Tvertical = mg and Thorizontal = Tvertical * tan(θ) where θ is the angle of displacement. However, specific calculations are not provided here without the complete equations and values.
If total (PE + KE) is conserved:
Yes, According to law of conservation of energy the total energy of any system remains conserved (same).
Example.
If a body is placed at some height it possesses some potential energy.
As P.E =mgh
When this body is starting moving downwards its height becomes decreases so P.E decreases but at the same time it is moving I.e having some velocity. K.E =1/2(m)(v^2).
Hence here P.E decreases but K.E increases at the same time. So total energy is conserved.
Final answer:
The conservation of mechanical energy principle states that in a system where only conservative forces act, the total mechanical energy (KE + PE) remains constant, represented by the equation KEi + PEi = KEf + PEf.
Explanation:
When discussing the scenario where the total mechanical energy, which is the sum of kinetic energy (KE) and potential energy (PE), remains constant, we are addressing a concept from Physics known as the conservation of mechanical energy principle.
This principle states that, in the absence of non-conservative forces like friction, the total mechanical energy of a system (KE + PE) does not change. The equation representing this principle is often displayed as KEi + PEi = KEf + PEf, where the subscripts i and f represent the initial and final states respectively.
This is a direct consequence of the work-energy theorem for conservative forces. It's important to note that this conservation applies only when all acting forces are conservative. Energy within such a system transfers between kinetic and various forms of potential energy, but the total amount of mechanical energy remains unchanged.
Why do you have to stand during an lab experiment?
answer: you stand in a lab experiment because if you sit during the lab, you have much reach of the materials on the table. and also, you might have a risk on some chemical spill on your clothes. the chemical might be flammable and it might set your clothes on fire.
so that's why you have to stand during lab experiments.
hope this helps! ❤ from peachimin
Standing during a lab experiment is important for safety and accuracy. It allows better control over equipment and materials and minimizes the risk of hazards.
Explanation:When conducting a lab experiment, it is important to stand to ensure safety and accuracy of the experiment. Standing allows you to have better control and stability over the equipment and materials you are working with. Additionally, it helps minimize the risk of accidental spills, breakage, or other hazards.
For example, if you are working with chemicals or glassware, standing can prevent the equipment from tipping over and causing injury. It also allows you to observe the reaction or process more closely, making it easier to record accurate data and observations.
Overall, standing during a lab experiment promotes safety, precision, and optimal results.
a friend says that earths continents are too large and massive to move. Explain to your friend why continents move.
Get to me as soon as you can!!!
Continents move slowly over time Today, we know that the continents rest on massive slabs of rock called tectonic plates. The plates are always moving and interacting in a process called plate tectonics. The continents are still moving today. :P
Continents move due to plate tectonics, which explains how the Earth's lithosphere is divided into plates that interact and move. Plate boundaries are the regions where plates meet and their movement is responsible for the movement of continents.
Explanation:The movement of continents is known as plate tectonics. The theory of plate tectonics explains how the Earth's lithosphere (the rigid outer layer of the Earth) is divided into several large and small plates that move and interact with each other. These plates can contain entire continents, and their movement is driven by convection currents in the Earth's mantle. When two continental masses are moving towards each other, they collide and can create mountain ranges, such as the Alps formed by the African and Eurasian plates.
Plate tectonics is the scientific explanation for why continents move. It involves the movement and interaction of several large and small plates that make up the Earth's lithosphere. By understanding plate tectonics, scientists have been able to explain the movement of continents as well as other geological phenomena such as earthquakes and volcanic activity.
Plate boundaries are the regions where two plates meet. There are three types of plate boundaries: divergent boundaries (where plates move apart), convergent boundaries (where plates collide), and transform boundaries (where plates slide past each other). The movement of these plates at the boundaries is responsible for the movement of continents over long periods of time.
If there is a loss of 4.36 × 10-5 g of mass in a nuclear reaction, how much energy would be released? Recall that c = 3 × 108 m/s.
A.
1.45 × 10-13 kJ
B.
3.92 × 106 kJ
C.
3.92 × 109 kJ
D.
3.92 × 1012 kJ
As E= mc²
E = (4.36 × 10^ -5) ×( 3 × 108 m/s.)²
E= 3.924×10^12J
E= (3.924×10^12)KJ/ 1000
E =3.92 × 109 kJ
Answer:
Released energy, [tex]E=3.92\times 10^6\ kJ[/tex]
Explanation:
It is given that,
Loss in mass in a nuclear reaction, [tex]m=4.36\times 10^{-5}\ g=4.36\times 10^{-8}\ g[/tex]
The relation between the mass and energy is given by Einstein mass energy equivalence equation :
[tex]E=mc^2[/tex]
c is the speed of light
So, [tex]E=4.36\times 10^{-8}\times (3\times 10^8)^2[/tex]
[tex]E=3.92\times 10^9\ J[/tex]
[tex]E=3.92\times 10^6\ kJ[/tex]
The energy released in a nuclear reaction is [tex]3.92\times 10^6\ kJ[/tex]. Hence, the correct option is (B)
Which of the following statements is true?
The more massive an object, the faster its acceleration of gravity.
Heavier objects will free-fall more quickly than lighter objects.
Objects in free-fall do not experience air resistance.
Mass and weight are the same.
Answer:
Objects in free-fall do not experience air resistance.
Explanation:
This comes from the definition of free-fall: an object in free fall is an object which is falling and the only force acting on it is gravity. Therefore, air resistance is not present for an object in free-fall. As a result, the acceleration of any object in free-fall is always equal to g (gravitational acceleration), and so all the objects fall with the same velocity and same time, regardless of their mass.
If the object is massive then the acceleration of gravity is faster, such objects will free fall more quickly than lighter objects. The objects in free fall do not experience air resistance are all true statements because the force of gravity which depends upon weight.
It is directly proportional to the weight. Yet the mass and weight are not same because mass is only value in kilograms but the weight is the value in which mass and gravitational acceleration are included. However, its unit is kilograms - 2 which is equal to Newton law of formula which is also unit of force.
A salesman travels to 2 customers. The first is a journey of 100 miles and takes 2 hours. He then goes to the second which is 80 miles in 1 hour. What is his average speed in mph?
60 mph
hope this helps
the equation is total distance/total time
180/3
60
HELP PLEASE
Can someone please explain to me why the answer would be 2.45m/s?
Solution with explanation is given below in attachment.
The following quantities describe location or its change:position, distance, and a displacement. Which are vectors?
As per the question there are three physical quantities named as position,distance and displacement.
Before coming into a conclusion first we have to understand a vector and a scalar.
A scalar quantity is a quantity which has only magnitude for it's complete specifications.
A vector is a quantity which has magnitude as well as direction and at the same time it is in accordance with the paraellogram law of vector addition.
Out of the three options displacement and position are vector quantities.It is because it is the minimum distance between two points .It has magnitude as well as direction.
Distance can not be considered as a vector quantity as it has only magnitude.There is no specific directions of distance travelled.
Position vector is a vector which provides location of an object in a plane or space.It is nothing else except the point which has x,y,z coordinates with origin is taken as the reference point.
Hence position and displacement are vectors
Answer:
position and displacement
Explanation:
Can anyone fill in the blanks for the potential and kentic energy? Also, is this showing energy transformation? Thank you so much!
Potential Kinetic Kinetic Potential Potential
what is the effective resistance of this dc circuit
You've managed somehow to post the mirror image of the circuit diagram, including the numbers and values of the resistors. I'm curious to know how you did that.
The three resistors at the left end of the diagram are 3Ω , 2Ω , and 1Ω all in series. They behave like a single resistor of (3+2+1) = 6Ω .
That 6Ω resistor is in parallel with the 2Ω drawn vertically in the middle of the diagram. That combination acts like a single resistor of 1.5Ω in that position.
Finally, we have that 1.5Ω resistor in series with 1Ω and 4Ω . That series combination behaves like a single resistor of 6.5Ω across the battery V.
Felipe drives his car at a velocity of 28 m/s. He applies the break, which slows the vehicle down at a rate of 6.4 m/s ^2 and causes it to slow to a stop. How long does it take for the car to stop?
If the acceleration applied is constant, then it is the same as the average acceleration throughout the duration of the stop.
[tex]a=\dfrac{\Delta v}{\Delta t}\implies-6.4\,\dfrac{\mathrm m}{\mathrm s^2}=\dfrac{0-28\,\frac{\mathrm m}{\mathrm s}}{\Delta t}\implies\Delta t=4.4\,\mathrm s[/tex]
(25 Points!!)
Sending information to the hippocampus allows your brain to
A) Get did of the old information it no longer needs.
B) Make more connections to create more memory
C) Send messages to the neurons when the brain is full.
D) Try something new and relieve any stress you may have.
Since the hippocampus' involvement with the brain is to do with memories, I would go with B.) The Hippocampus acts as a "memory index" of sorts, and if you send information to it, it would make connections to, in a sense, help remember it.
Answer:
it is b
Explanation:
A solid is 5 cm tall, 3 cm wide and 2 cm thick. It has a mass of 129 g. What is the density
If you drop a ball off a cliff oh, it starts out at 0m/s. After 1s, it will be traveling at about 10m/s. if air resistance is moved, what will happen in 2 s?
A.the ball will accelerate to 10m/s
B.the ball will still be moving at 10m/s
C.the ball will accelerate 20m/s
A rope attached to a sledge makes an angle of 40° with the ground. Calculate the tension in the rope required to produce a horizontal component 100N? What will be the vertical component of this force? 5 force act as shown by low. Calculate their resultant in magnitude and direction.
let the tension force in the rope attached to the sledge be "T"
θ = angle of rope with the horizontal = 40 deg
X = horizontal component of tension force "T" = 100 N
horizontal component of tension force "T" is given as
X = T Cosθ
100 = T Cos40
T = 130.54 N
Y = vertical component of the tension force = ?
vertical component of the tension force is given as
Y = T Sinθ
inserting the values
Y = (130.54) Sin40
Y = 83.91 N
Which phrases describe all the outer planets’ motion? Check all that apply.
no rotation
fast rotation
slow revolution
opposite revolution
north to south rotation
Answer: slow revolution and fast rotation
Solar system has 8 planets. 4 inner rocky planets - Mercury, Venus, Earth and Mars and 4 outer gaseous planets - Jupiter, Saturn, Uranus and Neptune. The outer planets have few common features.
They are gaseous. There period of revolution is larger than the inner planets which means that they have slow revolution about the Sun. One day on the outer planets is smaller than the inner planets which means they have fast rotation.
For example, Jupiter has revolves around sun in 11.86 Earth years and rotates about axis in 9.8 Earth hours. Uranus revolves around sun in 84 Earth years and rotates on its axis 17.9 Earth hours.
fast rotation
slow revolution
why is it possible to remove a paper without moving the object on it.(apply newton's law)
This is possible due to inertia of motion. which is nothing but newton's first law.
according to this law , an object tries to retain its state of motion or rest unless acted upon by an external force.
consider an object placed on a paper, initially both the object and paper are at rest. to pull the paper , we apply force on the paper and paper gains velocity. but the object keeps its motion of rest and hence the paper can be removed without moving the object.
IN WHAT WAY HAS TECHNOLOGY USED ABOARD THE INTERNATIONAL SPACE STATION BENEFITTED HUMANS BACK ON EARTH?
Answer
The ways are;
• By commercializing low earth orbit
• By supporting water purification efforts worldwide
• By bringing space station ultrasound equipment on earth
• By improving eye surgery with space hardware
Explanation
There is a revolutionary commercial pathways that is currently opening access to space.For example, NASA is purchasing commercial cargo resupply to space station which enable U.S business to develop a competition in selling services to others while freeing NASA resources for deep space exploration. Using technology developed in space, the Water Security Corporation has deployed systems using NASA water-processing technology to ensure drinkable water availability for human survival. Medical care in remote regions is now facilitated by use of small ultrasound units, tele-medicine and remote guided methods similar to those used in space. The Eye Tracking Device experiment has enable researchers to have an insight into corrective laser surgeries.
Answer:c
Explanation:
Rain falling vertically will make vertical streaks on a car's side window. However,if the car is moving, the streaks are slanted. If the streaks feom na vertically falling rain make 45 degree angle streaks, how fast is the car moving compared with the apeed of the falling rain?
When car is at rest the steaks makes makes vertical lines
which means the rain is falling in vertically downward direction
Now when car is moving with some speed v
Now the steaks makes and an angle 45 degree
So here we can say that relative velocity of rain with car is 45 degree
Now this is the resultant speed of rain in car frame
[tex]V_{rc} = V_r - V_c[/tex]
now if relative velocity makes 45 degree angle so this vector must have same components in vertical and horizontal direction
Since we know that relative velocity is resultant of rain velocity and car velocity so we can say here its two components are rain velocity and car velocity
So these two components must be of same magnitude
as it makes 45 degree
because when two vector are of same magnitude then the resultant vector always makes 45 degree with them if these two vectors are perpendicular to each other
car is moving at same speed as the speed of rain
Final answer:
When the rain makes a 45-degree angle streak on a moving car's window, the speed of the car is equal to the speed of the falling rain.
Explanation:
The student's question involves understanding relative velocities and their relationship to observed angles. Specifically, if rain makes 45-degree streaks on a moving vehicle's window, we want to know how fast the car is moving compared with the speed of the falling rain.
To solve this problem, we make use of trigonometry, particularly the tangent function which relates opposite and adjacent sides in a right-angled triangle. If the streaks are at a 45-degree angle, the vertical and horizontal speeds (i.e., speed of the rain and speed of the car) are equal. Therefore, in this scenario, the car is moving at the same speed as the rain is falling. Using the formula tan(θ) = vhorizontal / vvertical, where θ is the angle of the rain relative to the vertical, we find that at 45 degrees, tan(45) = 1 which implies the car's speed (vhorizontal) is equal to the rain's speed (vvertical).