Using the law of conservation of momentum, it is determined that after her collision with Jack, Jill will move in a direction that is south of east.
Explanation:This problem involves the principle of conservation of momentum. In this case, we have a two-body collision, where Mass1 (Jack, with mass 52kg and initial velocity 8m/s due east) collides with Mass2 (Jill, with mass 49.0kg and initially at rest). After the collision, Jack is traveling at a direction 34.0° north of east (let's call this direction east') with a speed of 5m/s. The initial momentum (Mass1 + Mass2) should be equal to the final momentum if we ignore the friction.
Before the collision, the total momentum was Momentum1 initial = Mass1 x Velocity1 initial = 52kg x 8m/s = 416 kg m/s, all in an eastward direction. Momentum2 initial = 0, as Jill was at rest.
After the collision, the final momentum of Jack becomes Momentum1 final = Mass1 x Velocity1 final = 52kg x 5m/s = 260 kg m/s, directed 34° north of east.
According to the law of conservation of momentum, the total initial momentum must equal the total final momentum. Hence, the final momentum of Jill will be Momentum2 final = Momentum1 initial - Momentum1 final = 156 kg m/s. This quantity only gives us the magnitude of the momentum, but we can calculate the direction based on Jack’s final direction. Given that momentum is a vector quantity, the principle of vector composition lets us infer that Jill’s final direction must be south of east to balance the north-of-east component of Jack's final momentum.
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How much energy is required to move a 1350 kg object from the earth's surface to an altitude twice the earth's radius?
Final answer:
The calculation of energy required to move an object to an altitude twice the Earth's radius involves understanding and applying principles of gravitational potential energy and the universal law of gravitation.
Explanation:
The question involves calculating the energy required to move a 1350 kg object from the Earth's surface to an altitude twice the Earth's radius. To solve this, we use the formula for gravitational potential energy (GPE), which is GPE = mgh at close distances to Earth's surface, and the universal law of gravitation for larger distances.
However, at distances far from the surface, the formula shifts to GPE = -G * (m1*m2)/r, where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between their centers. Since the altitude is twice the Earth's radius, the effective distance r would be 3 times the Earth's radius. This question requires integration of both concepts and understanding of physics to solve comprehensively.
A particle moves at a speed such that its kinetic energy just equals its mass energy. what is the speed of the particle?
a. 3 x 108 m/s;
b. 2.6 x 108 m/s;
c. 2.82 x 108 m/s;
d. 2.3 x 108 m/s
A 3.7-kg block on a horizontal frictionless surface is attached to an ideal spring whose force constant (spring constant) is 450 n/m. the block is pulled from its equilibrium position at x = 0.000 m to a position x = +0.080 m and is released from rest. the block then executes simple harmonic motion along the horizontal x-axis. the maximum elastic potential energy of the system is closest to
In the simple harmonic motion of a block attached to a spring, the maximum elasticity potential energy (U) occurs when displacement from equilibrium is the greatest. Given the provided spring constant (k) and displacement (x), the energy can be calculated using the formula U = (1/2)kx². The maximum elastic potential energy in this scenario is close to 1.44 joules.
Explanation:In physics, the problem you're dealing with relates to simple harmonic motion associated with a block attached to a spring on a frictionless surface. When the object is displaced from equilibrium and let go, it performs simple harmonic motion. During this motion, there is a constant interconversion between the kinetic and potential energy within the system.
The 'spring constant' (k) of an ideal spring is given as 450 n/m and the displacement from the equilibrium position (x) is 0.080 m. The maximum elastic potential energy is at extremes of the motion, when the displacement is the greatest (+/- x). It is given by the formula: U = (1/2)kx², where U is the elastic potential energy.
Substituting the given spring constant and displacement values into the formula: U = (1/2) * 450 * (0.080)² = 1.44 joules. Hence, the maximum elastic potential energy of the system is closest to 1.44 joules.
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Based on their locations on the periodic table, which best compares the properties of the metalloids arsenic (As) and antimony (Sb)?
) a charge of 6.15 mc is placed at each corner of a square 0.100 m on a side. determine the magnitude and direction of the force on each charg
The magnitude and direction of the force between each pair of charges can be determined using Coulomb's Law.
Explanation:The magnitude of the force between two charges can be determined using Coulomb's Law. In this case, we have four charges placed at the corners of a square. Since the charges are the same (6.15 mc), the force between each pair of charges will have the same magnitude. Let's label the charges as q1, q2, q3, and q4. The force between q1 and q2 is given by:
F12 = (k * q1 * q2) / r^2
where k is the Coulomb's constant (8.988 × 10^9 N m^2/C^2) and r is the distance between the charges (0.100 m). The direction of the force will be repulsive, since the charges have the same sign.
Using this formula, we can calculate the magnitude and direction of the force for all pairs of charges.
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An automobile engine slows down from 4500 rpm to 1600 rpm in 6.0 s. (a) calculate its angular acceleration, assumed constant. 3036.87 incorrect: your answer is incorrect. rad/s2 (b) calculate the total number of revolutions the engine makes in this time. 8700 incorrect: your answer is incorrect. rev
The angular acceleration of the automobile is 50.62 rad/s².
The total number of revolutions within the given time is 290 revolutions.
Angular acceleration of automobile
The angular acceleration of the automobile is calculated as follows;
[tex]\alpha = \frac{\omega _f - \omega _i}{t} \\\\[/tex]
ωf = 1600 rpm = 167.57 rad/s
ωi = 4500 rpm = 471.3 rad/s
[tex]\alpha = \frac{167.57 - 471.3}{6} \\\\\alpha = -50.62 \ rad/s^2[/tex]
Total number of revolutions in 6 sN = (4500 rpm - 1600 rpm)
N = 2,900 rpm
N = 2,900 x (6/60)
N = 290 rev
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Which equations can be used to calculate the electric potential energy stored in a capacitor? Check all that apply. U = QV U = CV U = U = CV2 U = U = QV2
U=1/2QV
U=1/2CV^2
U=Q^2/2C
An element which has strong intermolecular forces is most likely to have
a. a boiling point below room temperature
b. a melting point below room temperature
c. a boiling point very close to its melting point
d. a very high melting point
According to the forces of attraction, an element which has strong inter molecular forces is most likely to have a very high melting point.
What are forces of attraction?
Forces of attraction is a force by which atoms in a molecule combine. it is basically an attractive force in nature. It can act between an ion and an atom as well.It varies for different states of matter that is solids, liquids and gases.
The forces of attraction are maximum in solids as the molecules present in solid are tightly held while it is minimum in gases as the molecules are far apart . The forces of attraction in liquids is intermediate of solids and gases.
The physical properties such as melting point, boiling point, density are all dependent on forces of attraction which exists in the substances.
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A solid object heated to 120°C is placed inside a container of water at 33°C. What is the BEST explanation of the resulting change in temperature?
A) The temperature of both the water and solid will decrease.
B) The temperature of the solid will decrease and the water will decrease.
C) The temperature of the water will increase; the temperature of the solid will decrease.
D) The temperature of the water will remain constant; the temperature of the solid will decrease.
Answer:
its c
Explanation:
i took it
The part of the flower responsible for producing pollen (sperm) is the _______. A. stigma B. anther C. style D. filament
A 1200-kg ore cart is rolling at 10.8 m/s across a flat friction-free surface. a crane suddenly drops of ore vertically into the cart. how fast does the cart move just after being loaded with the ore?
A block of mass 2.5 kg is attached to a spring with spring constant 150 n/m and slides on a rough, horizontal surface (coefficient of kinetic friction 0.25). the spring is initially extended by a distance of 45 cm from its equilibrium position and released from rest. (a) what is the speed of the block when it is at the equilibrium position of the spring? (b) where does the block stop?
A 2.90 kg mass is pushed against a horizontal spring of force constant 23.0 n/cm on a frictionless air table. the spring is attached to the tabletop, and the mass is not attached to the spring in any way. when the spring has been compressed enough to store 15.0 j of potential energy in it, the mass is suddenly released from rest. part a find the greatest speed the mass reaches. vmax = 3.22 m/s submitmy answersgive up correct part b when does this occur? if not friction acts on it forever. if there is right at the beginning when it is just released. submitmy answersgive up
A 3.00 kg mud ball has a perfectly inelastic collision with a second mud ball that is initially at rest. the composite system moves with a speed equal to one- third the original speed of the 3.00 kg mud ball. what is the mass of the second mud ball?
Burning magnesium gives us magnesium oxide. This is a example of
If vx = 7.90 units and vy = -6.50 units, determine (a)the magnitude and (b)direction of v
Which graphic design tools help you draw circles and rectangles?
Answer: geometric shape tools
Explanation: plato/edmentum answer.
hope this helps! :)
if a vector a - b = 2c, a + b = 4c and c = 3i + 4j,find a and b
What type of motor operates at a constant steady-state speed regardless of the load?
For a temperature increase of δt1, a certain amount of an ideal gas requires 30 j when heated at constant volume and 50 j when heated at constant pressure. how much work is done by the gas in the second situation?
Work done by the ideal gas in the second situation is 20 Joule.
We know that amount of energy given to a ideal gas is distributed in it to increase its internal energy and to work done by increasing it volume.
Mathematically:
energy given to a ideal gas (dQ) = Increase in internal energy (dU) + work done (dW).
Now in this question: a certain amount of an ideal gas requires 30 j when heated at constant volume. So, this energy is used to increase internal energy (as no volume change occurs).
So, dQ₁ = dU = 30 Joule.
When heated at constant pressure, the certain amount of an ideal gas requires 50 J. So, this energy is used to increase internal energy and work done.
So, dQ₂ = dU + dW
⇒ dW = dQ₂ - dU = 50 Joule - 30 joule = 20 Joule.
Hence, work is done by an amount 20 joule by the ideal gas in the second situation.
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Two cars of the same mass have different velocities. Which car has more momentum
__________ helps us adapt to our environment. It also generally __________ with age. A. Plasticity . . . decreases B. Development . . . increases C. Plasticity . . . increases D. Development . . . decreases
Answer: A, Plasticity ... decreases
Explanation:
what causes the end of a star?
A 120-meter-long ski ift carries skiers from a station at the foot of a slope to a second station 40 m above. what is the IMA (ideal machincal advantage) of the lift?
Recall that the blocks can only move along the x axis. the x components of their velocities at a certain moment are v1x and v2x. find the x component of the velocity of the center of mass (vcm)x at that moment. keep in mind that, in general: vx=dx/dt. express your answer in terms of m1, m2, v1x, and v2x.
The x component of the center of mass velocity is calculated as the momentum-weighted average of the individual blocks' velocities, using the formula (m1*v1x + m2*v2x) / (m1 + m2).
Explanation:To find the x component of the velocity of the center of mass (vcm)x, we use the formula for the center of mass velocity in one dimension, which is given by:
(vcm)x = (m1*v1x + m2*v2x) / (m1 + m2)
This equation reveals that the center of mass velocity is the momentum-weighted average of the velocities of the individual blocks. Since momentum is mass times velocity, the product m1*v1x is the momentum of block 1 in the x direction, and m2*v2x is the momentum of block 2 in the x direction. The sum of these momenta gives the total momentum in the x direction. By dividing this sum by the total mass (m1 + m2), we obtain the velocity of the center of mass in the x direction.
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If the initial velocity of the system were not zero, how would this affect your results?
Which statements accurately describe elements? Check all that apply.
Elements are made up of two or more types of atoms.
Elements are made up of only one type of atom.
Each element has a unique chemical symbol.
Elements can be identified by their atomic number.
One element cannot be combined with another element.
Answer: The correct statements are:
- Elements are made up of only one type of atom.
- Each element has a unique chemical symbol.
- Elements can be identified by their atomic number.
Explanation: and just for a little bit more information about elements.
An element is a pure substance that is made from a single type of atom. Elements are the building blocks for all the rest of the matter in the world. Examples of elements include iron, oxygen, hydrogen, gold, and helium. An important number in an element is the atomic number.
To recharge a 12 v battery, a battery charger must move 3.3 × 105 c of charge from the negative terminal to the positive terminal. how much work is done by the battery charger? answer in units of j
Work done is calculated by change * potential
difference
in equation it means: W = Q * V
since the 2 terminals have now dq charge and (V) potential difference
small work done (dW) = V dq
total work done W = V Q = 12 * 3.3*10^5 = 3.96 *10^6 Joules which is
approximately 4 mega joules
To calculate the work done by the battery charger, multiply the charge moved (3.3 × [tex]10^5[/tex] C) by the voltage (12 V). The result is 3.96 × [tex]10^6[/tex] J.
To find out how much work is done by the battery charger, we use the relationship between electrical potential difference (voltage), charge, and work. The work done, W, when moving a charge, Q, through a potential difference, V, is given by the equation:
W = Q × VHere, the battery charger must move 3.3 × [tex]10^5[/tex] C of charge (Q) through a potential difference of 12 V (V). Substituting these values into the equation gives:
W = 3.3 × [tex]10^5[/tex] C × 12 VW = 3.96 × [tex]10^6[/tex] JTherefore, the work done by the battery charger is 3.96 × [tex]10^6[/tex] J.
A car has a kinetic energy of 1.9 × 10^3 joules. If the velocity of the car is decreased by half, what is its kinetic energy?
Which has a higher acceleration: a 10 kg object acted upon with a net force of 20 N or an 18 kg object acted on by a net force of 30 N
Answer:
the 10-kg object has higher acceleration
Explanation: