Jean gets an allowance of $15 each month plus an extra $2 for each chore she completes around the house. How much allowance will she earn if she does x chores in a month?

a. 15x + 2 dollars
b. 2x dollars
c. 2x + 15 dollars
d. 17x + 15 dollars

Answers

Answer 1
The answer is 2x + 15 dollars.

Related Questions

Q2 Q13.) Use the given conditions to write an equation for the line in​ point-slope form and​ slope-intercept form.

Answers

let
A (-5,-4) and B (5,10)

Part 1) write an equation for the line in​ point-slope form

we know that
the equation of a line in​ point-slope form is
y-y1=m*(x-x1)

step 1
find the slope m
m=(y2-y1)/(x2-x1)------> m=(10+4)/(5+5)----> m=14/10---> 7/5

strep 2
with m=7/5 and the point B (5,10)
find the equation of a line
y-y1=m*(x-x1)-----> y-10=(7/5)*(x-5)

the answer Part 1) is
y-10=(7/5)*(x-5)

Part 2) write an equation for the line in​ slope-intercept form

we know that
the equation of a line  in​ slope-intercept form is
y=mx+b

step 1
find the slope m
m=(y2-y1)/(x2-x1)------> m=(10+4)/(5+5)----> m=14/10---> 7/5

step 2
with m=7/5 and the point B (5,10)
find b
y=mx+b
10=(7/5)*5+b-----> 10=7+b-------> b=3

the equation of the line is
y=(7/5)x+3

the answer Part 2) is
y=(7/5)x+3

A school typically sells 500 yearbooks each year for 50 dollars each. The economic calls does a project and discovers that they can sell 100 more yearbooks for every $5 decrease in price. The revenue for yearbook sales is equal to the number of yearbooks sold times the price of the yearbook. Let x represent the number of $5 decrease in price. If the expression that represents the revenue is written in the form R(x)=(500+ax)(50-bx). Find the value of a and b

Answers

Final answer:

For the expression R(x)=(500+ax)(50-bx), a represents the increase in yearbooks sold for each $5 decrease in price and b represents the corresponding decrease in price per yearbook. The correct values for a and b are 100 and 5 respectively, resulting in the revenue expression R(x) = (500 + 100x)(50 - 5x).

Explanation:

The student's question revolves around the concept of revenue generation based on the number of items sold and the selling price per item.

When examining revenue, we understand it as the product of price per unit times the number of units sold. In the given example, a school is selling yearbooks with a base scenario of 500 yearbooks at $50 each. We are given that for every $5 decrease in price, the school can sell an additional 100 yearbooks. This can be formulated as:

R(x) = (500 + ax)(50 - bx)

Here x represents the number of $5 decreases from the original price. With each decrease, the number of books sold increases by 100, and the price decreases by $5.

Therefore, variable a must represent the increase in quantity sold for each $5 price decrease (a = 100), and variable b must represent the decrease in price per yearbook for each price decrease (b = 5).

Therefore, the values of a and b are 100 and 5, respectively.

The expression for the revenue becomes:

R(x) = (500 + 100x)(50 - 5x)

Write 2018 to the power of 2019 + 2018 as the sum of two perfect squares

Answers

[tex] 2018^{2019} + 2018=2018( 2018^{2018} +1)=( 13^{2}+ 43^{2})(( 2018^{1009})^{2} + 1^{2}) [/tex]
According to Brahmagupta-Fibonnaci identity 
[tex]( a^{2} + b^{2}) (c^{2}+ d^{2}) = (ac+bd)^{2} + (ad-bc )^{2} [/tex]
Then, we can write that
[tex](13^{2}+ 43^{2})(( 2018^{1009})^{2} + 1^{2})[/tex]
[tex][(13*2008^{1009}+43)^{2} +(13-2008^{1009}*43)^{2}] [/tex] 
Q.E.D

Answer: I, III, and IV only

Step-by-step explanation:

One method of slowing the growth of an insect population without using pesticides is to introduce into the population a number of sterile males that mate with fertile females but produce no offspring. let p represent the number of female insects in a population and s the number of sterile males introduced each generation. let r be the per capita rate of production of females by females, provided their chosen mate is not sterile. then the female population is related to time t by t = p + s p[(r − 1)p − s] dp. suppose an insect population with 10,000 females grows at a rate of r = 1.2 and 400 sterile males are added. evaluate the integral to give an equation relating the female population to time. (note that the resulting equation can't be solved explicitly for p. remember to use absolute values where appropriate.)

Answers

The relation between population and time is:
[tex]t = \int { \frac{P+S}{P[(r - 1)P - S]} } \, dP [/tex]

Since r = 1.2 and S = 400, we get:
[tex]t = \int { \frac{P+400}{P[(1.2 - 1)P - 400]} } \, dP [/tex]

= [tex] \int { \frac{P+400}{P(0.2P - 400)} } \, dP [/tex]

This is a rational function that we can write as:
[tex]\frac{P+400}{P(0.2P - 400)} = \frac{A}{P} + \frac{B}{(0.2P - 400)} [/tex]

In order to evaluate A and B, let's calculate the LCD:
[tex]\frac{P+400}{P(0.2P - 400)} = \frac{A(0.2P - 400)}{P(0.2P - 400)} + \frac{BP}{P(0.2P - 400)} [/tex]

which brings to:
P + 400 = 0.2AP - 400A + BP
             = P(0.2A + B) - 400A

Since, the left side must be equal to the right side, we get the following system of equations:
[tex] \left \{ {{0.2A + B = 1} \atop {-400A = 400}} \right. [/tex]

Which gives:
[tex] \left \{ {{B=1.2} \atop {A=-1}} \right. [/tex]

Therefore, our integral can be written as:
[tex]t = \int { \frac{P+400}{P(0.2P - 400)} } \, dP = \int {( \frac{-1}{P} + \frac{1.2}{0.2P-400} )} \, dP [/tex]
= [tex]- \int { \frac{1}{P} \, dP + 1.2\int { \frac{1}{0.2P-400} } \, dP[/tex]
= [tex]- \int { \frac{1}{P} \, dP + 6\int { \frac{0.2}{0.2P-400} } \, dP[/tex]
= - ln |P| + 6 ln |0.2P - 400| + C

We now have to evaluate the constant C. In order to do so, we consider that at t = 0 P = 10000:
0 = - ln |10000| + 6 ln |0.2(10000) - 400| + C
C = ln |10000| - 6 ln |1600|
C = ln (10⁴) - 6 ln (2⁶·5²)
C = 4 ln (10) - 36 ln (2) - 12 ln (5)

Therefore, the equation relating female population with time is:
t =  - ln |P| + 6 ln |0.2P - 400| + 4 ln (10) - 36 ln (2) - 12 ln (5)

The equation relating females population with time is [tex]\boxed{t =  - \ln \left| P \right| + 6\ln \left| {0.2P - 400} \right| - 12\ln \left( 5 \right) + 4\ln \left( {10} \right) - 36\ln \left( 2 \right)}.[/tex]

Further explanation:

Explanation:

The female population is related to time and it is given as follows,

[tex]t = \int {\dfrac{{p + s}}{{p\left[ {\left( {r - 1} \right)p - s} \right]}}dp}[/tex]

The sterile males are 400 and the growth rate is 1.2.

[tex]\begin{aligned}t&= \int {\frac{{p + 400}}{{p\left[ {\left( {1.2 - 1} \right)p - 400} \right]}}dp}\\&= \int {\frac{{p + 400}}{{p\left[ {0.2p - 400} \right]}}dp}\\\end{aligned}[/tex]

The expression [tex]\dfrac{{p + 400}}{{p\left[ {0.2p - 400} \right]}}[/tex] can also be expressed as follows,

[tex]\dfrac{{p + 400}}{{p\left[ {0.2p - 400} \right]}} = \dfrac{A}{p} + \dfrac{B}{{\left( {0.2p - 400} \right)}}[/tex]

Find the least common denominator.

[tex]\dfrac{{p + 400}}{{p\left( {0.2p - 400} \right)}} = \dfrac{{A\left( {0.2p - 400} \right)}}{{p\left( {0.2p - 400} \right)}} + \dfrac{{Bp}}{{p\left( {0.2p - 400} \right)}}[/tex]

[tex]\begin{aligned}p + 400 &= 0.2Ap - 400A + Bp\\p + 400 &= p\left( {0.2A + B} \right) - 400A\\\end{aligned}[/tex]

Equate left and right side of the expression to obtain the value of A and B.

[tex]\begin{aligned}0.2A + B &= 1\\- 400A &= 400\\\end{aligned}[/tex]

The value of A can be obtained as follows,

[tex]\begin{aligned}A&= \dfrac{{400}}{{ - 400}}\\A& =- 1\\\end{aligned}[/tex]

The value of B is 1.2.

Integral can be expressed as follows,

[tex]\begin{aligned}t &= \int {\frac{{p + 400}}{{p\left( {0.2p - 400} \right)}}dp}  \\ &= \int {\left( {\frac{{ - 1}}{p} + \frac{{1.2}}{{\left( {0.2p - 400} \right)}}} \right)dp} \\&= - \int {\frac{1}{p}dp}  + 6 \times \int {\frac{{0.2}}{{0.2p - 400}}dp}\\&= - \ln \left| p \right| + 6\ln \left| {0.2p - 400} \right| + C\\\end{aligned}[/tex]

At initial time the population is 10000.

[tex]\begin{aligned}- \ln \left| {10000} \right| + 6\ln \left| {0.2 \times 10000 - 400} \right| + C &= 0\\\ln \left| {10000} \right| - 6\ln \left| {1600} \right| &= C\\4\ln 10 - 36\ln \left( 2 \right) - 12\ln \left( 5 \right) &= C\\\end{aligned}[/tex]

Substitute [tex]4\ln 10 - 36\ln \left( 2 \right) - 12\ln \left( 5 \right)[/tex] for [tex]C.[/tex]

[tex]t =  - \ln \left| p \right| + 6\ln \left| {0.2p - 400} \right| + 4\ln 10 - 36\ln \left( 2 \right) - 12\ln \left( 5 \right)[/tex]

The equation relating females population with time is [tex]\boxed{t = - \ln \left| P \right| + 6\ln \left| {0.2P - 400} \right| - 12\ln \left( 5 \right) + 4\ln \left( {10} \right) - 36\ln \left( 2 \right)}.[/tex]

Learn more:

Learn more about inverse of the functionhttps://brainly.com/question/1632445. Learn more about equation of circle brainly.com/question/1506955. Learn more about range and domain of the function https://brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Exponential function

Keywords: exponential growth, growth rate model, pesticides, slowing, insect population, sterile males, mate, fertile, females, explicitly, female grows, integral, female insects, male insects, capita rate, chosen mate, generation.

What is the solution of square root of-4x=100? x = –2500 x = –50 x = –2.5 no solution

Answers

√(-4x) = 100
-4x = 100² = 10,000
x = 10,000/-4 = -2500

The solution is ...
  x = -2500

Any and all answers get a 5 star rating
First answer gets a thanks
Most reliable answer gets brainliest

The following data shows the weight, in pounds, of 6 boxes:

5, 3, 3, 4, 5, 4

What is the value of the mean absolute deviation of the weight of the boxes, and what does it represent about the weight of a box?

Answers

0.7 pound; the weight of 50% of the boxes is greater than 0.7 pound.

Hope this Helps!!

Write the equation of a circle with center upper c left-parenthesis 4 comma negative 5 right-parenthesis that passes through upper p left-parenthesis 1 comma negative 2 right-parenthesis number .

Answers

The square of the distance between C(4, -5) and P(1, -2) is given by the Pythagorean theorem as
  (4-1)² +(-5-(-2))² = 18
This is the square of the radius of the circle, so we can use it for r² in the formula
  (x -h)² +(y -k)² = r² . . . . . . . circle of radius r and center (h, k)

Your circle has equation ...
  (x -4)² +(y +5)² = 18

Hey can you please help me posted picture of question

Answers

Look at how the diagram branches off. It starts branching off with 2, then depending what you pick for bread, it goes to meats, which it branches off to 2 and then it goes to cheeses, which it then branches off to 2. 

So, 2, 2, 2 = B
answer is B.
 See attached picture:

Use any method to solve the equation. If necessary, round to the nearest hundredth.

x^2 + x − 30 = 0

A. –5, 6

B. 10, –12

C. 5, –6

D. 5. 5, –5.5


Answers

Here, in order to find the solutions to the quadratic equation - x² + x - 30 = 0, we will use factorization method.

In the method, we will split 30, in such factors, which when added or subtracted gives us 1,  and when multiplied gives us -30.

So, we will use, -5 and 6. When they are added they will give us 1 and when multiplied they will give us -30 as answer.

Now, the equation will be written as -

x² - 5x + 6x - 30 = 0

Taking common, we get

x(x - 5) +6(x-5) = 0

(x-5)(x+6) = 0

So, x - 5 = 0 and x +6 = 0, we will get, x = 5 and x = - 6

Thus, the correct option is C). x = 5 and -6

Find the equation for the plane through the points upper p 0 left parenthesis negative 2 comma negative 5 comma negative 4 right parenthesis​, upper q 0 left parenthesis 5 comma 1 comma negative 4 right parenthesis​, and upper r 0 left parenthesis negative 1 comma 2 comma 5 right parenthesis.

Answers

We can suppose the equation of the plane is in the form ...
  ax +by +cz = 1
By using the given point coordinates for x, y, and z, we end up with three equations in 3 unknowns. These can be described by the augmented matrix ...
[tex] \left[\begin{array}{ccc|c}-2&-5&-4&1\\5&1&-4&1\\-1&2&5&1 \end{array}\right] [/tex]
Putting this in reduced row-echelon form, we find
  a = 54/35
  b = -63/35
  c = 43/35

The equation of the plane through [tex]P_{0}(-2,-5,-4), Q_{0}(5,1,4), R_{0}(-1,2,5)[/tex] is ...
  54x -63y +43z = 35

How do you solve 6<_2g?

Answers

Divide both sides by 2 to isolate variable g. 

You're left with 6 / 2 < g which equals 3 < g

a student uses a solution that contains 16 grams of water to conduct an evaporation experiment

Answers

What’s the full questions yeah he uses 16 grams then what

the correct option is:

b.

Step 1:0.035 xx16=0.56

Step 2: 16-0.56=15.44

Step 3: 0.0425 xx15.44=0.6562

Step 4: 15.44-0.6562=14.7838

Let's break down the calculations:

Step 1: Calculate the amount of water lost at the end of the first hour.

[tex]\[ \text{Amount lost} = 0.035 \times 16 = 0.56 \][/tex]

Step 2: Subtract the amount lost from the initial amount to find the remaining water at the end of the first hour.

[tex]\[ \text{Remaining water} = 16 - 0.56 = 15.44 \][/tex]

Step 3: Calculate the amount of water lost at the end of the second hour.

[tex]\[ \text{Amount lost} = 0.0425 \times 15.44 = 0.6562 \][/tex]

Step 4: Subtract the amount lost from the remaining water at the end of the first hour to find the remaining water at the end of the second hour.

[tex]\[ \text{Remaining water} = 15.44 - 0.6562 = 14.7838 \][/tex]

So, the correct option is:

b.

Step 1:0.035 xx16=0.56

Step 2: 16-0.56=15.44

Step 3: 0.0425 xx15.44=0.6562

Step 4: 15.44-0.6562=14.7838

The complete Question is given below:

A student uses a solution that contains 16 grams of water to conduct an evaporation experiment.

At the end of one hour, the amount of water in the solution has decreased by 3.5% .

At the end of two hours, the amount of water in the solution has decreased by another 4.25% .

Which calculations can be used to determine the amount of water, in grams, remaining in the solution at the end of the second hour?

a.

Step 1:0.035 xx16=0.56

Step 2: 16-0.56=15.44

Step 3: 0.0425 xx15.44=0.6562

Step 4:16-0.6562=15.3438

b.

Step 1:0.035 xx16=0.56

Step 2: 16-0.56=15.44

Step 3: 0.0425 xx15.44=0.6562

Step 4: 15.44-0.6562=14.7838

c.

Step 1:0.35 xx16=5.6

Step 2: 16-5.6=10.4

Step 3: 0.425 xx10.4=4.42

Step 4:16-4.42=11.58

d.

Step 1: 0.35 xx16=5.6

Step 2: 16-5.6=10.4

Step 3: 0.425 xx10.4=4.42

Step 4:10.4-4.42=5.98

A 16 ounce package of cereal cost $4.00? what is the unit cost

Answers

Here, we need to find unit cost. Unit cost can be defined as a cost per unit of a product.

We are given that 16 ounce will cost $ 4.00.

That means -

Cost of 16 ounce of cereal package = $ 4.00

Cost of 1 ounce of cereal package -

(We will divide both sides by 16)

Cost of 16 ounce of cereal package ÷ 16 = $ 4.00 ÷ 16

Cost of 1 ounce of cereal package = $ 0.25.

Thus, the cost of 1 ounce of cereal package = $ 0.25.

Answer: 1 oz. Over 0.25 is your answer.

Step-by-step explanation:

Brian wants to fence in his triangular plot of farm land that measures 1.1 by 1.5 by 2.2 miles. Determine the angles at which the fences of the three sides will meet.

Rounding each angle to the nearest degree: m<A=___degrees

Answers

If you're going to get help, you may as well get help from an appropriate calculator. Many graphing calculators will solve triangles, as will stand-alone apps for phone or tablet.

The angle measures are ...
  ∠A = 115°
  ∠B = 27°
  ∠C = 38°


_____
You can use the Law of Cosines to solve for angle A, then the Law of Sines for the others.
  A = arccos((1.5²+1.1²-2.2²)/(2*1.1*1.5)) = arccos(-1.38/3.3) ≈ 115°
  C = arcsin(1.5/2.2*sin(115°)) ≈ 38°
  B = 180° -115° -38° = 27°

The angles for Brian's triangular plot of farmland are approximately 27° for ∠A, 38° for ∠B, and 115° for ∠C.

To determine the angles of a triangular plot of land with sides measuring 1.1 miles, 1.5 miles, and 2.2 miles, we can use the Law of Cosines. The Law of Cosines states:

⇒ c² = a² + b² - 2ab × cos(C)

Let's label the sides as follows:

⇒ a = 1.1 miles

⇒ b = 1.5 miles

⇒ c = 2.2 miles

First, we calculate ∠C (opposite side c):

⇒ cos(C) = (a² + b² - c²) ÷ (2ab)

⇒ cos(C) = (1.1² + 1.5² - 2.2²) ÷ (2 × 1.1 × 1.5)

= (1.21 + 2.25 - 4.84) ÷ (3.3)

= (-1.38) ÷ (3.3)

= -0.4182

Then, we find ∠C by taking the inverse cosine (cos-1):

⇒ ∠C ≈ 115°

Next, we calculate ∠A (opposite side a) using the same method:

⇒ cos(A) = (b² + c² - a²) ÷ (2bc)

⇒ cos(A) = (1.52 + 2.22 - 1.12) ÷ (2 × 1.5 × 2.2)

= (2.25 + 4.84 - 1.21) ÷ (6.6)

= (5.88) ÷ (6.6)

= 0.8909

Then, we find angle A:

⇒ ∠A ≈ 27°

Finally, we calculate angle B (opposite side b) using:

⇒ ∠B = 180° - ∠A - ∠C

= 180° - 27° - 115°

= 38°

The angles at which the fences of the three sides will meet are approximately 27° for ∠A, 38° for ∠B, and 115° for ∠C, when rounded to the nearest degree.

Complete question:

Brian wants to fence in his triangular plot of farm land that measures 1.1 × 1.5 × 2.2 miles.

Determine the angles at which the fences of the three sides will meet.

Rounding each angle to the nearest degree:

Density is mass divided by volume. Find the mass of a gold bar if the density is 19.32 g/cm3 and the volume is 50 cm3.

Answers

density = mass / volume
mass = density * volume
mass = 19.32 * 50
mass = 966 grams


Answer:

d

Step-by-step explanation:

denisity * volume = mass

the area of a circle is about 254 cm what is the radius

Answers

To find the radius of a circle with an area of 254 cm², you can use the formula for the area of a circle by solving for the radius. We get the radius as 8.99 cm.

The radius of a circle can be found by using the formula for the area of a circle:

Given Area = 254 cm²Formula: A = πr²Solve for r: r = √(A ÷ π)Substitute in Area: r = √(254 cm² ÷ 3.14159)Calculate the radius: r ≈ √(80.865) ≈ 8.99 cm

Please help me with this

Answers

The correct answers are the second option (Option B) and the last option (Option E).

 The explanation is shown below:
 1. By definition, a geometric sequence is a sequence of numbers each number, after the first one, is the result of multiply the previous number by a common ratio.
 2. The Option B has the following common ratio:
 (2/3) / (4/9)=1.5
 1/(2/3)=1.5
 r=1.5
 3. The Option E has the following common ratio:
 -15/3=-5
 75/-15=-5
 r=-5

HELP ASAP PLEASE
Name the quadrant in which the point (x, y) lies.

x > 0 and y < 0


III

II

IV

I

Answers

x > 0 refers to the right half of the coordinate plane.
y < 0 refers to the bottom half of the coordinate plane.

Both these conditions are met in the lower right quadrant of the coordinate plane. Quadrants are numbered counterclockwise from upper right, so the lower right quadrant is number IV.

The name of the quadrant in which (x >0, y < 0) lies is
  IV

Answer: quadrant 4

Step-by-step explanation:

the floor sheerly bedroom is a square with a perimeter of 60 ft what is the area of the floor of sherry bedroom

Answers

225[tex] ft^{2} [/tex]

Q # 4 Solve the graph please <6. , <1. , <2. ,<4

Answers

The interior angel of 7 will be angel 4
∠7 + ∠4 = 180°

write percent as a fraction or in simplest form of 37.5​%

Answers

37.5% is equivalent to a fractional form. You get this by putting 37.5 over 100 since per cent means per one-hundred. This gives us
                                             37.5% = 37.5/100 = 375/1000 = 3/8
The simplest form is 3/8, therefore the answer to your question is 3/8.
The answer is 3/8 because 3 ÷ 8 = 0.375

0.375 = 37.5%

Answer = 3/8

~Hope this helped~

You plant a tree that is 36 inches tall. After one year, the tree is 43 inches tall. Which expression describes the percent of increase in the tree's height?


Answers





36 - 100%43 - x  %
we multiply by cross ->  36 * x = 100 / 43 
we should remove '100%' from new value, because we find only increase.. no new value in percent.
x + 100 = (43 * 100)/36 
x =  4300/36 - 100x = 119+ 16/36 -100x = 19 +4/9



the answer is 

19.44% increase
HOW TO FIND THE GROWTH PERCENTAGE:


Percent Problem: 
You need to calculate percent increase from 36 to 43. 

First Step: Find the difference between two numbers, in this case, it's 10 - 2 = 8. 

Second Step: Take the difference, 7, and divide by the original number: 7/36 = 0.194444. 

Last, convert the decimal to a percent.

FINAL ANSWER: 19.44%


hey can some one help me with this

Answers

Hello!

First you have to find the surface area of what he is painting

Finding the areas of all the rectangles he is painting

14 * 8 = 112
14 * 8 = 112
12 * 8 = 96
12 * 8 = 96
12 * 14 = 168

Add all these up

112 + 112 + 96 + 96 + 168 = 584

Divide this by the amount of area a pint of paint covers

584 / 90 = 6.4888...

He needs 7 pints of paint because he needs more than 6

Multiply this by the cost of 1 pint of pint

7 * 7.98 = 55.86

The answer is $55.86

Hope this helps!
The area of a rectangular surface is given by the product of its length and width. The total area Jake wants to paint is that of the four side walls and the ceiling. That is ...
  A = (8 ft)(14 ft) +(8 ft)(12 ft) +(8 ft)(14 ft) +(8 ft)(12 ft) +(14 ft)(12 ft)
  A = (8 ft)*2*(14 ft +12 ft) +(14 ft)(12 ft) . . . . rearranging to simplify a bit
  A = 2*(8 ft)(26 ft) +(14 ft)(12 ft)
  A = 416 ft² +168 ft²
  A = 584 ft²

6 pints of paint will cover 6*(90 ft²) = 540 ft², not quite enough. The next higher multiple of 90 ft² is 7*(90 ft²) = 630 ft², more than adequate.

Jake will need to purchase 7 pints of paint.


The cost of Jake's purchase will be 7*$7.98 = $55.86.

Write the standard form of the number shown. three hundred eighty-nine billion, nine hundred thirty-six million, two hundred six thousand, seven hundred sixty-seven

Answers

ok really answer is this 389,936,206,767 ur welcome plz give me brainiest u can even put in the answer and it will right ur welcome.

The standard form of the given number is 3.89936206767 × 10¹¹

From the question, the given number is

three hundred eighty-nine billion, nine hundred thirty-six million, two hundred six thousand, seven hundred sixty-seven.

First, we will write the number in figures before writing it in standard form.

The number, three hundred eighty-nine billion, nine hundred thirty-six million, two hundred six thousand, seven hundred sixty-seven, written in figure is

389,936,206,767.

Now, to write in standard form,

A number is said to be in standard form, if it is written in form A × 10ⁿ.  Where A is a number bigger than or equal to 1 and less than 10 ( That is, A ≥ 1 and A < 10)

and n is any positive or negative whole number

∴ The number, 389,936,206,767, written in standard form is 3.89936206767 × 10¹¹

Hence, the standard form of the given number is 3.89936206767 × 10¹¹

Learn more here: https://brainly.com/question/1565680

Four pencils are held together with a band.
the figure on the right shows the bottom end of the pencils and the band.
each of the pencils has a diameter of 10mm
find the length of the band in this position.
give your answer in terms of pi.

Answers

Answer: (40+10π) mm.


Step-by-step explanation: Given diameter of the circle = 10mm.

Radius of the circle = 10/2 = 5 mm.

From the figure, we can see that each or the four corners makes a quarter of the circle.

And four corners would make the complete circle with radius 5mm.

Therefore, circumference of the four quarters of a circle = 2 π r

= 2 π  (5) = 10 π.

Now, we can see that each side 10 mm of band also there.

So, the length of straight band on all four sides = 4 × 10 = 40 mm.

Total length of the band = (40+10π) mm


The length of the band is the number of units it covers

The actual length of the band is: [tex]\mathbf{40 + 10\pi}[/tex]

The diameter of 1 pencil is given as:

[tex]\mathbf{d = 10}[/tex]

The circumference of 1 pencil is:

[tex]\mathbf{C = \pi d}[/tex]

So, we have:

[tex]\mathbf{C = 10\pi }[/tex]

Multiply by 4, to calculate the circumference of all pencils

[tex]\mathbf{4C =4 \times 10\pi }[/tex]

[tex]\mathbf{4C =40\pi }[/tex]

The rubber band covers a quarter of the 4 pencils.

So, we divide by 4

[tex]\mathbf{C = 10\pi }[/tex]

The length of the band on one pencil is:

[tex]\mathbf{L = 10}[/tex]

Multiply by 4, for the 4 pencils

[tex]\mathbf{L = 40}[/tex]

So, the actual length of the band is:

[tex]\mathbf{Length = 40 + 10\pi}[/tex]

Read more about lengths at:

https://brainly.com/question/12524954?

In a right rectangles pyramid with base edges a= 18 cm and b= 10 cm the slant height toward a is k= 13 cm while the slant height towards b is l= 15 cm. What is the surface area of the pyramid

Answers

To find the surface area of the pyramid, you will need to find the areas of all 5 faces.

rectangular base:
A = lw
    18 x 10
A = 180 square cm

side a triangular lateral faces:
A = 1/2bh
      1/2 x 18 x 13
A = 117 square cm x 2= 234 square cm

side b triangular lateral faces:
A = 1/2bh
      1/2 x 10 x 15
A = 75 square cm x 2= 150 square cm

Add all the bold areas together:
150 + 234 +180 = 564

The surface area is 564 square cm.

Jane multiplied 825 x 22 and got 3,300. Flynn multiplied the same numbers and got 18,150. Which student is correct? What mistake did the other student make?

Answers

Flynn was right Jane was wrong because she didn't multiple right

# 11 Q . please solve the diagrama

Answers

The area = π r² = π * 18² = 324 π in²

The first choice is the correct
The answer to your question would be 324 π in² and it would be the first option.
The area of a circle is = π r²
Substitute the given,which will give you this : π * 18² = 324 π in²

Q9 Q13.) Find the products AB and BA to determine whether B is the multiplicative inverse of A.

Answers

Hello there!

See pictures below for the answer!


P.S. I think I answered this question already. I still have it on Microsoft Word :)

As always, it is my pleasure to help students like you!

Find the total cost of a $619.50 refrigerator if the sales tax rate on the purchase is 2.8?

Answers

the answer would be 602.63
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