John goel is to have more then -7 dollors in hisaccount by the end of this mounth. the varible d is the nuber of dollor in johns bank account at the end of the mounth. Whrite an lineqwalatiy in terms of d that is true only if john meets hif monthy goal

Answer:

0.18401015

Step-by-step explanation:

You should use an online calculator

Answer:

a) no

Step-by-step explanation:

-The diagrams can be said to be mathematically similar if the dimensions of their corresponding sides enlarge or reduce by the same factor.

-We therefore determine the enlargement factor for both the radius and height as below:

-Let k be the scale factor

[tex]k_r=\frac{R}{r}\\\\=\frac{3.64}{2.6}\\\\=1.4\\\\k_h=\frac{H}{h}\\\\=\frac{10.192}{8.32}\\\\=1.225\\\\k_r\neq k_h[/tex]

Hence, the cylinders are not mathematically similar since the enlargment factors for the radius and height are not equal.

Answer:

Surface Area and Volume Unit Test

1. 14

2. hexagon

3. 224 m2

4. 896 pi in.2

5. 405 in.2

6. 49,009 m2

7. 4,910.4 yd3

8. 3.6 in

9. 4,608 cm3

10. 1,296 cm3

11. 1,442.0 yd3

12. 2,158 m2

13. no

14. 7 : 10

15. 100 m2

16. one-point perspective

17. 18.3 cm

Answer:

a. (√3)/2

b. 60 degrees.

Step-by-step explanation:

Please kindly check the attached files for explanation.

The sine of the angle is √3 / 2, and the measure of the angle is 60°.

Finding the Angle Between a Cable and the Ground

To determine the sine of the angle ( heta) between the cable and the ground, we need to use the horizontal and vertical forces exerted by the cable. We have a horizontal pull of 800 Newtons and a vertical pull of 800√3 Newtons.

First, we calculate the sine of the angle using the formula:

Sine ( heta) = Opposite / Hypotenuse

Here,
Opposite = Vertical Pull = 800√3 N
Hypotenuse = Resultant Force = √[(Horizontal Pull)^2 + (Vertical Pull)^2] = √[(800)^2 + (800√3)^2] = 1600 N

Thus,

Sine ( heta) = 800√3 / 1600 = √3 / 2

We know that the angle  heta with a sine value of √3 / 2 is 60 degrees (or  heta = 60°).

In conclusion, sine of the angle is √3 / 2, and the measure of the angle is 60°.

Answer: the minimum score required for a letter of recognition is 27.8

Step-by-step explanation:

Suppose ACT Mathematics scores are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = ACT Mathematics scores.

µ = mean score

σ = standard deviation

From the information given,

µ = 21.3

σ = 5.3

The probability of students whose scores are in the top 11 % would be be (1 - 11/100) = (1 - 0.11) = 0.89

Looking at the normal distribution table, the z score corresponding to the probability value is .23

Therefore,

1.23 = (x - 21.3)/5.3

Cross multiplying by 8.6, it becomes

1.23 × 5.3 = x - 21.3

6.519 = x - 21.3

x = 6.519 + 21.3

x = 27.8 to the nearest whole number

Final answer:

The minimum ACT Mathematics score required to be in the top 11% with a mean of 21.3 and a standard deviation of 5.3 is approximately 27.85, which is usually rounded to 28.

Explanation:

Top 11% for ACT Mathematics Score Requirement

If ACT Mathematics scores are normally distributed with a mean of 21.3 and a standard deviation of 5.3, the score corresponding to the top 11% can be found by determining the z-score that corresponds to the 89th percentile (100% - 11% = 89%). To find this z-score, one would typically use a z-score table or a statistical software. Once the z-score for the 89th percentile is found, it can be converted to an ACT score using the formula:

Z = (X - μ) / σ

where Z is the z-score, X is the ACT score, μ (mu) is the mean, and σ (sigma) is the standard deviation. Solving for X:

X = Z×σ + μ

Assuming the z-score for the 89th percentile is approximately 1.23, the minimum required score for a letter of recognition would be:

X = 1.23×5.3 + 21.3

X ≈ 1.23×5.3 + 21.3

X ≈ 6.549 + 21.3

X ≈ 27.849

Therefore, the minimum score required for a letter of recognition would be approximately 27.85, which can be rounded as appropriate for the context (usually to the nearest whole number, giving a score of 28).

Answer:

The factored form of the polynomial is 11*(x+2)*(x-5/11). The root found was r = -2

Step-by-step explanation:

If you take a positive value of x, you will most likely obtain positive results, since 11x² + 17x ≥ 11 + 17 = 28 for x ≥1, which means that 11x²+17x-10 ≥ 28-10 = 18 > 0.

Therefore, we prove with negative values.

Therefore, -2 is a root. We can find the other knowing that

p(x) = 11*(x-r₁)*(x-r₂) = 11*(x-(-2)) * (x-r₂) = 11*(x+2)*(x-r₂)

The independent term is 11*2*(-r₂) = -22r₂ = -10

thus, r₂ = -10/-22 = 5/11.

Therefore, p(x) = 11*(x+2)*(x-5/11)

To write 11x2+17x−10 in factored form we find two numbers whose sum is 17 and product is -110. The correct pair is 2 and -55 which leads to the factored form (11x - 55)(x + 2).

The question involves factoring a quadratic expression, 11x2+17x−10. To re-write this expression in factored form, one needs to find two numbers, such that their sum equals to the coefficient of x, 17, and their product equals to the product of the coefficient of x² and the constant term (11*(-10)=-110). Diego started by listing all pairs of factors of the constant term, -10. The correct pair here, considering the product and the sum, are 2 and -55, because 2*(-55)=-110 and 2+(-55)=17. Therefore, our factored form will be: (11x - 55)(x + 2).

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Answer:

cx

Step-by-step explanation:

Answer:

the answer is C 282

Step-by-step explanation:

Answer:

1944 Inches Squared

Step-by-step explanation:

Surface area Formula for a Cube:

[tex]A = 6a^2[/tex]

The "edge", which is also the side, is 18 inches.

[tex]a = 18[/tex]

Solve the formula.

[tex]A= 6a^2 = 6(18)^2 = 6 * 18^2\\18^2 = 324\\324 * 6 = 1944\\A=1944[/tex]

The cube's surface area should be 1944 square inches.

Answer:

Step-by-step explanation:

1944 Inches Squared

Step-by-step explanation:

Surface area Formula for a Cube:

The "edge", which is also the side, is 18 inches.

Solve the formula.

Answer:

(3n + 4) (n-2)

Step-by-step explanation:

Are you asking to factor this 3n^2 - 2n -8 ?

If so the best way to do this problem  is with the X method.

                                     top:    3*(-8)

    left:  factor of 3*-8                             right:  factor of 3*-8

                                   bottom:  -2

try the factors  4 and -6  because   4*-6 =  3 *-8 = -24

Because   notice that  4 + -6 = -2

so:

    3n^2 -2n - 8  can be rewritten as    3n^2  -6n + 4n  - 8

We should first use Distributive property to factor:  3n^2  -6n + 4n  - 8

3n^2  -6n + 4n  - 8  =   3n (n - 2)  +  4(n - 2)

Now we factor by grouping here :   (3n + 4) (n-2)  

I factored out the group  (n-2)

Therefore:  (3n + 4) (n-2) = 3n^2 -2n - 8

The volume of the new building is 11,726,069,760 cubic inches, and its surface area is 51,555,840 square inches.

To find the volume and surface area of the new building, we first need to calculate the dimensions of the new building by scaling up the dimensions of the model by a factor of 144.

1. Dimensions of the new building:

  -[tex]Width: \(10 \times 144 = 1440\) inches[/tex]

  - [tex]Length: \(18 \times 144 = 2592\) inches[/tex]

  - [tex]Height: \(28 \times 144 = 4032\) inches[/tex]

2. Volume of the new building:

  The volume of a rectangular prism (building) is calculated by multiplying its length, width, and height.

[tex]\[Volume = \text{Length} \times \text{Width} \times \text{Height}\][/tex]

  Substituting the given dimensions:

 [tex]\[Volume = 2592 \times 1440 \times 4032\][/tex]

 [tex]\[Volume = 11,726,069,760 \text{ cubic inches}\][/tex]

3. Surface area of the new building:

  The surface area of a rectangular prism (building) is calculated by adding the areas of all six sides.

[tex]\[Surface\,Area = 2(\text{Length} \times \text{Width} + \text{Length} \times \text{Height} + \text{Width} \times \text{Height})\][/tex]

  Substituting the given dimensions:

[tex]\[Surface\,Area = 2(2592 \times 1440 + 2592 \times 4032 + 1440 \times 4032)\][/tex]

 [tex]\[Surface\,Area = 51,555,840 \text{ square inches}\][/tex]

So, when the new building is completed:

- The volume will be [tex]\(11,726,069,760 \text{ cubic inches}\).[/tex]

- The surface area will be [tex]\(51,555,840 \text{ square inches}\).[/tex]

Answer:

45.216‬

Step-by-step explanation:

2 x 3.14 x7.2

Answer:

Step-by-step explanation:

Volume of water bottle = 143 cubic cm

πr²h = 143

3.14*r²*7.2 = 143

[tex]r^{2}=\frac{143}{3.14*7.2}\\\\r^{2}=6.325\\[/tex]

r = 2.51

r = 2.5 cm

Answer:

Step-by-step explanation:

Given

Compare the given with the options to identify equivalents

A)

Not equivalent

B)

Not equivalent

C)

Not equivalent

D)

Equivalent

Answer:

a

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

taking the square root of both sides of the equation

Answer:

Dimensions of page should be width of 6 inches and height of 9 inches

Step-by-step explanation:

Let x be the width of the printed part in inches

Let y be height of the printed part in inches.

Thus, Area of printed part; A = xy

And area of printed part is given as 24.

Thus, xy = 24

Making y the subject, we have;

y = 24/x

Now, the question says the top and bottom margins are 1.5 inches.

Thus, width of page = x + 1 + 1 = x + 2

And also the margins on each side are both 1m in length, thus the height of page will be:

y + 1.5 + 1.5 = y + 3

So area of page will now be;

A = (x + 2)•(y+3)

From earlier, we got y = 24/x

Thus,plugging this into area of page, we have;

A = (x + 2)•((24/x)+3)

A = 24 + 3x + 48/x + 6

A = 30 + 3x + 48/x

For us to find the minimum dimensions, we have to find the derivative of A and equate to zero

Thus,

dA/dx = 3 - 48/x²

Thus, dA/dx = 0 will be

3 - 48/x² = 0

Multiply through by x²:

3x² - 48 = 0

Thus,

3x² = 48

x² = 48/3

x = √16

x = 4 inches

Plugging this into y = 24/x,we have;

y = 24/4 = 6 inches

We want dimensions of page at x = 4 and y = 6.

From earlier, width of page = x + 2.

Thus,width = 4 + 2 = 6 inches

Height = y + 3 = 6 + 3 = 9 inches

So dimensions of page should be width of 6 inches and height of 9 inches

To minimize paper usage, we need to find the dimensions of the rectangular page. By setting up an equation and solving it, we can find the width and length of the page that result in the least amount of paper used.

To minimize the amount of paper used, we need to find the dimensions of the page that will result in the smallest possible area. Let's assume the length of the page is 'L' inches and the width is 'W' inches. We can set up the equation:

Next, we can use the quadratic formula to solve for L:

To find the minimum value of L, we can consider the factors contributing to the uncertainty:

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Answer:

175 cents

Step-by-step explanation:

1 quarter is equal to 25 cents.

Since there are 7 of them,

7 times 25 cents = 175 cents

No squares should be cut. Maximum volume is zero. Dimensions remain 15cm by 40cm by 0cm.

To find the size of the square that should be cut out from each corner to maximize the volume of the bin, we need to follow these steps:

1. Understand the problem : We have a rectangular piece of plastic with dimensions 15 cm by 40 cm. By removing squares from each corner and folding up the flaps, we can form an open-top bin. We want to find the size of the squares to be cut out to maximize the volume of the bin.

2. Define variables : Let's denote the side length of the square to be cut out from each corner as [tex]\( x \)[/tex] cm.

3. Express the volume of the bin : After cutting out squares and folding up the flaps, the dimensions of the resulting bin will be [tex]\( (15 - 2x) \)[/tex] cm by [tex]\( (40 - 2x) \)[/tex] cm by [tex]\( x \)[/tex] cm. So, the volume of the bin can be expressed as:  [tex]\[ V = x(15 - 2x)(40 - 2x) \][/tex]

4. Maximize the volume: To find the maximum volume, we need to find the critical points of the function [tex]\( V \)[/tex]. We'll take the derivative of [tex]\( V \)[/tex] with respect to [tex]\( x \)[/tex], set it equal to zero, and solve for [tex]\( x \)[/tex].

  [tex]\[ \frac{dV}{dx} = (15 - 2x)(40 - 2x) + x(-4)(40 - 2x) + x(15 - 2x)(-4) \][/tex]

  [tex]\[ 0 = (15 - 2x)(40 - 2x) - 8x(40 - 2x) - 4x(15 - 2x) \][/tex]

5. Solve for [tex]\( x \)[/tex] : Solve the equation for [tex]\( x \)[/tex] to find the critical points.

 [tex]\[ 0 = 600 - 70x + 4x^2 \][/tex]

 [tex]\[ 0 = 4x^2 - 70x + 600 \][/tex]

  Solve for [tex]\( x \)[/tex] using the quadratic formula:

  [tex]\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \][/tex]

  where [tex]\( a = 4 \)[/tex], [tex]\( b = -70 \)[/tex], and [tex]\( c = 600 \)[/tex].

  [tex]\[ x = \frac{-(-70) \pm \sqrt{(-70)^2 - 4(4)(600)}}{2(4)} \][/tex]

  [tex]\[ x = \frac{70 \pm \sqrt{4900 - 9600}}{8} \][/tex]

  [tex]\[ x = \frac{70 \pm \sqrt{-4700}}{8} \][/tex]

  Since the discriminant is negative, there are no real solutions for [tex]\( x \)[/tex] in this case. Therefore, we need to check the endpoints of our interval.

6. Check endpoints : Since [tex]\( x \)[/tex] must be non-negative and [tex]\( (15 - 2x) \)[/tex] and [tex]\( (40 - 2x) \)[/tex] must also be positive, the possible range for [tex]\( x \)[/tex] is [tex]\( 0 \leq x \leq 7.5 \)[/tex] cm.

  When [tex]\( x = 0 \), \( V = 0 \)[/tex] (no bin is formed).

  When [tex]\( x = 7.5 \), \( V = 7.5(15 - 2(7.5))(40 - 2(7.5)) = 7.5(0)(25) = 0 \)[/tex] (no bin is formed).

7. Conclusion : The maximum volume of the bin is achieved when no squares are cut out from the corners. Therefore, to maximize the volume, no squares should be cut out from the corners of the plastic, resulting in a rectangular prism with dimensions [tex]\( 15 \times 40 \times 0 \)[/tex] cm³, which does not form a bin.

So, the maximum volume of the bin is [tex]1000cm^3[/tex]

To maximize the volume of the bin, we need to determine the dimensions of the squares that should be cut out from each corner to form the bin. Let's denote the side length of the square to be cut out as

x centimeters.

When the squares are cut out and the flaps are folded up, the dimensions of the resulting bin can be expressed as follows:

Length of the bin: 40−2x centimeters

Width of the bin: 15−2x centimeters

Height of the bin (equal to the side length of the square cut out): x centimeters

The volume V of the bin is given by the product of its length, width, and height:

V=(40−2x)(15−2x)x

To find the maximum volume, we need to find the value of

x that maximizes this function. We can do this by taking the derivative of

V with respect to x, setting it equal to zero, and solving for x.

Let's find the derivative of V with respect to x:

[tex]$\frac{d V}{d x}=15(40-2 x)-2(15-2 x)(40-2 x)$[/tex]

Now, let's set the derivative equal to zero and solve for x:

[tex]$15(40-2 x)-2(15-2 x)(40-2 x)=0$[/tex]

After solving for x, we can substitute the value of

x back into the expression for the volume

V to find the maximum volume of the bin. Let's do these calculations.

First, let's simplify the derivative[tex]\frac{dv}{dx}[/tex]

[tex]$\begin{aligned} & \frac{d V}{d x}=15(40-2 x)-2(15-2 x)(40-2 x) \\ & =600-30 x-\left(30 x-4 x^2\right) \\ & =600-30 x-30 x+4 x^2 \\ & =600-60 x+4 x^2\end{aligned}$[/tex]

Now, we set the derivative equal to zero and solve for x:

[tex]$600-60 x+4 x^2=0$[/tex]

Dividing both sides by 4:

[tex]$150-15 x+x^2=0$[/tex]

Rearranging and factoring:

[tex]$$\begin{aligned}& x^2-15 x+150=0 \\& (x-10)(x-15)=0\end{aligned}$$So, $x=10$ or $x=15$.[/tex]

Since x=15 would result in a negative side length for the bin, we discard it.

Thus, the optimal size square to be cut out from each corner is 10 centimeters.We can then find the maximum volume

V by substituting x=10 into the volume formula:

[tex]$V=(40-2 \times 10)(15-2 \times 10) \times 10=(20)(-5) \times 10=1000 \mathrm{~cm}^3$[/tex]

So, the maximum volume of the bin is [tex]1000cm^3[/tex]

x = dimes

y = quarters

We also know:

Dimes: 0.10

Quarters: 0.25

100 = x + y

So, 0.10x + 0.25y = 100

And, y = 100 - x

Let’s use substitution:

0.10x + 0.25( 100 - x ) = 100

= 0.10x + 25 - 0.25x = 100

= 25 - 100 = 0.25x - 0.10x

= (-75) = 0.15x

x = (-75) divide by 0.15

x = (-500)

Answer:

The bottom equation is infinite solutions ( please give branliest)

2x - 6y = 18

x - 3y = 9

Step-by-step explanation:

Using substitution,

x=3y + 9

6x - 6x + 18 = 18

0 = 18 - 18

0 = 0

Answer: Last one:)

Step-by-step explanation:

Just did it

Answer:

Step-by-step explanation:

9 + 3 = 12

[tex]Water=\frac{9}{12}*48\\\\=9*4[/tex]

Water = 36 liters

Pesticide = 48 - 36  = 12 liters

Answer:I can't really tell what B says could you do another pic

Step-by-step explanation:

Answer:

Across the x axis.

Step-by-step explanation:

Russia obtained [tex]\( 5\% \)[/tex]of the total gold medals for the top 8 countries.

Let's denote the total number of gold medals obtained by Russia as [tex]\( x \)[/tex]. Since we know Russia got 3 gold medals, we have [tex]\( x = 3 \)[/tex].

Now, let's denote the total number of gold medals obtained by the top 8 countries (including Russia) as T. We're told that the total number of gold medals obtained by all top 8 countries combined is 60. Since Russia got 3 gold medals, the gold medals obtained by the other top 7 countries is [tex]\( T - 3 \)[/tex].

So, the percentage of gold medals obtained by Russia can be calculated as:

Percentage of gold medals obtained by Russia = [tex]\frac{\text{Number of gold medals obtained by Russia}}{\text{Total number of gold medals obtained by the top 8 countries}} \times 100\%\][/tex]

Substituting the known values:

[tex]\[\text{Percentage of gold medals obtained by Russia} = \frac{3}{T} \times 100\%\][/tex]

We know that the total number of gold medals obtained by the top 8 countries is 60, so [tex]\( T = 60 \).[/tex] Substituting this into the equation:

[tex]\[\text{Percentage of gold medals obtained by Russia} = \frac{3}{60} \times 100\%\][/tex]

Solving this equation:

[tex]\[\text{Percentage of gold medals obtained by Russia} = \frac{1}{20} \times 100\% = 5\%\][/tex]

So, Russia obtained [tex]\( 5\% \)[/tex]of the total gold medals for the top 8 countries.

Answer

25 percent

Step-by-step explanation:

Answer:

The correct answer is 100%

Step-by-step explanation:

:>

Answer:

X= 1 + 7/12

x = 1 - 7/12

Step-by-step explanation:

Answer:

[tex]x=\frac{19}{12}\\ or\\x=\frac{5}{12}[/tex]

Step-by-step explanation:

[tex]6x^2-x-2=0[/tex]

a=6

b=-1

c=-2

[tex]x=-b\frac{+}{}\frac{\sqrt[]{b^2-4ac} }{2a}[/tex]

[tex]x=-(-1)\frac{+}{}\frac{\sqrt[]{(-1)^2-4(6)(-2)} }{2(6)}[/tex]

[tex]x=1\frac{+}{}\frac{\sqrt[]{1+48} }{12}[/tex]

[tex]x=1\frac{+}{}\frac{\sqrt[]{49} }{12}[/tex]

[tex]x=1\frac{+}{}\frac{7}{12}[/tex]

------------------------------

[tex]x=1+\frac{7}{12}[/tex]

[tex]x=1-\frac{7}{12}[/tex]

------------------------------

[tex]1+\frac{7}{12}=\frac{(1*12)+(7*1)}{12} =\frac{12+7}{12} =\frac{19}{12}[/tex]

------------------------------

[tex]1-\frac{7}{12}=\frac{(1*12)-(7*1)}{12} =\frac{12-7}{12} =\frac{5}{12}[/tex]

Using stratified sampling concepts, it is found that the correct options are:

Stratified sampling divides the population into groups, called stratas, and a few elements of each group are surveyed.

In this problem, the households are divided to represents various​ locations, ethnic​ groups, and income brackets, hence, those are the stratas.

Stratified sampling is used because ensures that all segments of the population are represented.

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Answer:

  a.  csc²θ

Step-by-step explanation:

You can use the identities ...

  1 +tan² = sec²

  cot = cos/sin

  sec = 1/cos

  csc = 1/sin

___

Then the expression becomes ...

  [tex]\cot^2{\theta}(1+\tan^2{\theta})=\cot^2{\theta}\sec^2{\theta}=\dfrac{\cos^2{\theta}}{\sin^2{\theta}\cos^2{\theta}}=\dfrac{1}{\sin^2{\theta}}\\\\=\boxed{\csc^2{\theta}}[/tex]

Answer:

532

Step-by-step explanation:

divide 5,320 by 10

Answer: D

Step-by-step explanation:

The correct answer is d) No because their product is not equal to the identity matrix.

The matrices are given in the question as follows:

[tex]A= \left[\begin{array}{ccc}4&2\\-11&-6\end{array}\right] \\B= \left[\begin{array}{ccc}-4&-2\\11&6\end{array}\right][/tex]

To determine if two matrices are inverses of each other, we need to check if their product is equal to the identity matrix.

Let's calculate the product of matrices A and B:

[tex]A{\times}B = \left[\begin{array}{ccc}4\times-42+2\times11&4\times-2+2\times6\\-11\times-4+(-6\times11)&-11\times-2-6\times6\end{array}\right][/tex]

Simplifying the calculations to get:

[tex]A{\times}B = \left[\begin{array}{ccc}6&4\\-22&-14\end{array}\right][/tex]

The resulting matrix is not equal to the identity matrix:

[tex]A{\times}B = \left[\begin{array}{ccc}1&0\\0&1\end{array}\right][/tex]

Therefore, matrices A and B are not inverses of each other.

The correct answer is d) No because their product is not equal to the identity matrix.

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Final answer:

Three segments with lengths 4 cm, 6 cm, and 11 cm cannot form a triangle because the sum of the lengths of the two shorter sides is not greater than the length of the longest side, violating the Triangle Inequality Theorem.

Explanation:

To determine whether three segments with lengths 4 cm, 6 cm, and 11 cm can form a triangle, we must consider the Triangle Inequality Theorem. This theorem states that for any triangle, the sum of the lengths of any two sides must be greater than the length of the third side. If we attempt to apply this to the given lengths:

4 cm + 6 cm > 11 cm (False)

4 cm + 11 cm > 6 cm (True)

6 cm + 11 cm > 4 cm (True)

Since the sum of the lengths of the two shorter sides (4 cm + 6 cm) is not greater than the length of the longest side (11 cm), these three segments cannot form a triangle, whether it is an acute triangle, right triangle, or obtuse triangle.

If they were able to form a triangle, to classify the type of triangle, we would use the Converse of the Pythagorean Theorem. This theorem helps us understand if a triangle is acute, right, or obtuse:

In a right triangle, the square of the length of the longest side (hypotenuse) is equal to the sum of the squares of the lengths of the other two sides.

If the square of the longest side is greater than the sum of the squares of the other two sides, the triangle is obtuse.

If the square of the longest side is less than the sum of the squares of the other two sides, the triangle is acute.

However, since a triangle cannot be formed with these segments, we do not need to apply these rules here

Answer:

The answer is 126!!! Hope I helped!!!

Step-by-step explanation:

1. 6 x 3 = 18

2. 18 x 7 = 126

Answer:

126

Step-by-step explanation:

Multiply 7 x 6 x 3 which is equal to 126.

Have a great day!  Your amazing. I do a lot of answers on edg 6th grade.

Feel free to ask questions

Answer:

  45

Step-by-step explanation:

The average of the three numbers is the middle one: 138/3 = 46. Then the smallest of the three consecutive numbers is 45.

Final answer:

The smallest of the three consecutive numbers that add up to 138 is 45.

Explanation:

To find the smallest of the three consecutive numbers that add up to one hundred thirty-eight, we first need to represent the numbers algebraically.

Let x be the smallest number, x+1 is the next number, and x+2 is the largest number.

The equation that represents their sum is:

x + (x + 1) + (x + 2) = 138

To solve for x, we combine like terms:

3x + 3 = 138

Then we subtract 3 from both sides:

3x = 135

And divide both sides by 3 to find x:

x = 135 / 3

x = 45

Therefore, the smallest number is 45.