Just the distributive property to write an expression that is equivalent to 10 + 15x

Answer:

95% confidence interval for the difference in the proportion is [-0.017 , 0.697].

Step-by-step explanation:

We are given that a simple random sample of 12 small cars were subjected to a head-on collision at 40 miles per hour. Of them 8 were "totaled," meaning that the cost of repairs is greater than the value of the car.

Another sample of 15 large cars were subjected to the same test, and 5 of them were totaled.

Firstly, the pivotal quantity for 95% confidence interval for the difference between population proportion is given by;

                             P.Q. = [tex]\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }[/tex]  ~ N(0,1)

where, [tex]\hat p_1[/tex] = sample proportion of small cars that were totaled = [tex]\frac{8}{12}[/tex] = 0.67

[tex]\hat p_2[/tex] = sample proportion of large cars that were totaled = [tex]\frac{5}{15}[/tex] = 0.33

[tex]n_1[/tex] = sample of small cars = 12

[tex]n_2[/tex] = sample of large cars = 15

[tex]p_1[/tex] = population proportion of small cars that are totaled

[tex]p_2[/tex] = population proportion of large cars that were totaled

Here for constructing 95% confidence interval we have used Two-sample z proportion statistics.

So, 95% confidence interval for the difference between population population, ([tex]p_1-p_2[/tex]) is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                    of significance are -1.96 & 1.96}  

P(-1.96 < [tex]\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }[/tex] < 1.96) = 0.95

P( [tex]-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }[/tex] < [tex]{(\hat p_1-\hat p_2)-(p_1-p_2)}[/tex] < [tex]1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }[/tex] ) = 0.95

P( [tex](\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }[/tex] < [tex]p_1-p_2[/tex] < [tex](\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }[/tex] ) = 0.95

95% confidence interval for [tex]p_1-p_2[/tex] = [[tex](\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }[/tex] , [tex](\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }[/tex]]

= [[tex](0.67-0.33)-1.96 \times {\sqrt{\frac{0.67(1-0.67)}{12}+\frac{0.33(1-0.33)}{15} } }[/tex] , [tex](0.67-0.33)+1.96 \times {\sqrt{\frac{0.67(1-0.67)}{12}+\frac{0.33(1-0.33)}{15} } }[/tex]]

= [-0.017 , 0.697]

Therefore, 95% confidence interval for the difference between proportions l and 2 is [-0.017 , 0.697].

Answer:

a) [tex]L(t) = 3 + 2\cdot t[/tex], b) [tex]S (t) = 3\cdot t[/tex], c) Third day.

Step-by-step explanation:

a) The equation to represent Layla's fees is:

[tex]L(t) = 3 + 2\cdot t[/tex]

b) The equation to represent Sam's fees is:

[tex]S (t) = 3\cdot t[/tex]

c) Both earn the same amount for dog sitting at the third day.

Answer:

168

Step-by-step explanation:

GIVEN: Nadia is making a rectangular moisac out of [tex]\frac{1}{2}[/tex] inch by [tex]\frac{1}{2}[/tex] inch tiles. The rectangle is [tex]12[/tex] inches long and [tex]3\frac{1}{2}[/tex] inches wide.

TO FIND: How many tiles will Nadia use to cover the rectangle completely.

SOLUTION:

Area of rectangular moisac[tex]=\text{length}\times\text{width}[/tex]

                                            [tex]=12\times3\frac{1}{2}=\frac{12\times7}{2}[/tex]

                                            [tex]=42 \text{ inch}^2[/tex]

Area of one   tile [tex]=\text{side}^2[/tex]

                           [tex]=\frac{1}{2}\times\frac{1}{2}=\frac{1}{4}\text{ inch}^2[/tex]

According to question

Total tiles required [tex]=\frac{\text{Area of rectangular moisac}}{\text{Area of one tile}}[/tex]

                                [tex]=\frac{42}{\frac{1}{4}}=42\times4[/tex]

                                [tex]=168[/tex] tiles

Hence, 168 tiles are required to completely cover the rectangular moisac.

Answer:

w = [tex]-\frac{7}{6}u[/tex]

Step-by-step explanation:

If u will be the independent variable, then w will have to be made the subject of the equation so that w will depend on the changes in u

4u + 8w = −3u + 2w

First collect all like terms

8w − 2w = −3u − 4u

6w = −7u

divide both sides by 6

∴ w = [tex]-\frac{7}{6}u[/tex]

In the equation w = [tex]-\frac{7}{6}u[/tex] , U is independent variable.

Answer:

The answer is there is a difference in the mean production rate by shift

Step-by-step explanation:

The level of significance is actually very low since the same production level is maintained for each of the 5 workers at the same time in the afternoon.

As for the other shifts, that is, the day shift and the night shift, the level of significance varies according to the production established by each worker.h

Answer:

$220?

Step-by-step explanation:

Answer$220

Step-by-step explanation:

77/7=$11 so $11x20=220

In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are [tex]\binom44\binom{48}1=48[/tex] possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by [tex]\binom{13}1=13[/tex]. So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability

[tex]\dfrac{\binom{13}1\binom44\binom{48}1}{\binom{52}5}=\dfrac{624}{2,598,960}\approx0.00024[/tex]

There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing [tex]\binom41\binom{48}4=778,320[/tex] possible hands. Exactly 2 aces are drawn in [tex]\binom42\binom{48}3=103,776[/tex] hands. And so on. This gives a total of

[tex]\displaystyle\sum_{a=1}^4\binom4a\binom{48}{5-a}=886,656[/tex]

possible hands containing at least 1 ace, and hence B occurs with probability

[tex]\dfrac{\sum\limits_{a=1}^4\binom4a\binom{48}{5-a}}{\binom{52}5}=\dfrac{18,472}{54,145}\approx0.3412[/tex]

The product of these probability is approximately 0.000082.

A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e. [tex]P(A\cap B)=P(A)P(B)[/tex]. This happens if

The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So [tex]A\cap B[/tex] consists of 96 possible hands, which occurs with probability

[tex]\dfrac{96}{\binom{52}5}\approx0.0000369[/tex]

and so the events A and B are NOT independent.

The events A and B in the given scenario are not independent. This determination is based on the principle of sampling without replacement, where drawing a four of a kind is likely to influence the probability of drawing an ace.

Two events A: the hand is a four of a kind, and B: at least one of the cards in the hand is an ace, are defined in a situation where a 5-card hand is dealt from a perfectly shuffled 52-card deck. To determine if these events are independent, we need to check if the occurrence of event A affects the occurrence of event B.

In sampling with replacement, each member of a population is replaced after it is picked. However, dealing a 5-card hand from a deck of cards is an example of sampling without replacement, meaning that each card may only be chosen once, causing the events to be considered as not independent.

It is highly probable that drawing a four of a kind will influence the likelihood of drawing an ace. Hence, the events A and B are not independent.

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Final answer:

Upon calculating the mean, range, mode, and median for both groups of house cats, we found that none of the statistics have greater values for Group 1 than for Group 2.

Explanation:

To determine which statistic has a greater value for Group 1 than Group 2 in a dataset containing the weights of house cats, we first need to calculate the mean, range, mode, and median for both groups.

Calculations for Group 1:

Calculations for Group 2:

When comparing the statistics, we can see that the range of Group 1 is smaller than that of Group 2, and the mean and median for Group 1 are also smaller than those for Group 2. The mode for both groups is the same with two values that repeat the most. Therefore, none of the statistics have greater values for Group 1 than for Group 2.

Missing part of the question

b)What is the value of R?

Answer:

a. X = 155.2

b. R = 4.4

Step-by-step explanation:

a. Calculating the value of x.

The value of x is the mean of the mean observation; i.e. the mean column

Mean is calculated as: the summation of all observation divided by the number of observations.

Summation of Observation = 158.9 + 151.2 + 155.6 + 155.5 + 154.6

Summation of Observation = 775.8

Number of Observations = 5

X = Mean = 775.8/5

X = 155.16

X = 155.2 ----- Approximated to 1 decimal place

b. Calculating the value of R.

The value of R is the mean/average of the Range

Mean is calculated as: the summation of all observation divided by the number of observations.

Summation of Observation = 4.0 + 4.6 + 4.3 + 5.0 + 4.3

Summation of Observation = 22.2

Number of Observations = 5

R = Mean = 22.2/5

R = 4.44

R = 4.4 ----- Approximated to 1 decimal place

The average diameter [tex](\( \overline{x} \))[/tex] of the pistons from the provided data is 155.16 mm, calculated by summing the daily means and dividing by the number of days.

In the context provided, [tex]\( \overline{x} \)[/tex] refers to the average of the piston diameters measured across different days at Wemming Chung's plant.

To find this value, we need to calculate the mean of the daily means [tex](\( \overline{x} \))[/tex] which are 158.9, 151.2, 155.6, 155.5, and 154.6 mm. This is done by summing these values and dividing by the number of days (5 in this case).

[tex]\[ \overline{x} = \frac{158.9 + 151.2 + 155.6 + 155.5 + 154.6}{5} \][/tex]

[tex]\[ \overline{x} = \frac{775.8}{5} \][/tex]

[tex]\[ \overline{x} = 155.16 \text{ mm} \][/tex]

Hence, the value of  [tex]\( \overline{x} \)[/tex] is 155.16 mm.

Answer:

-5(3x^3-1)

Step-by-step explanation:

-15x^3+5

Factor out -5

-5(3x^3-1)

Final answer:

To find the probability that the mean of a sample of 44 cars would differ from the population mean by less than 51 miles, use the Central Limit Theorem to approximate the distribution of sample means. Calculate the standard error using the formula: standard error = population standard deviation / sqrt(sample size). Then, standardize the sample mean using the z-score formula. Finally, find the probability using a standard normal distribution table or a calculator.Therefore, the probability that the mean of a sample of 44 cars would differ from the population mean by less than 51 miles is approximately 0.3595, or 35.95%.

Explanation:

To find the probability that the mean of a sample of 44 cars would differ from the population mean by less than 51 miles, we can use the Central Limit Theorem. According to the Central Limit Theorem, the distribution of sample means approximates a normal distribution, regardless of the shape of the population distribution, as long as the sample size is large enough (typically n ≥ 30).

First, we need to calculate the standard error, which is the standard deviation of the sampling distribution of the sample mean. The standard error is given by the formula: standard error = population standard deviation / sqrt(sample size). In this case, the population standard deviation is 368 miles, and the sample size is 44. Therefore, the standard error = 368 / sqrt(44) = 55.354 miles.

Next, we use the z-score formula to standardize the sample mean. The z-score = (sample mean - population mean) / standard error. Plugging in the given values, we get: z-score = (51 - 2643) / 55.354 = -0.3668.

Finally, we need to find the probability that the standardized sample mean (z-score) is less than -0.3668. We can use a standard normal distribution table or a calculator to find the corresponding probability. From the standard normal distribution table, we find that the probability corresponding to a z-score of -0.3668 is approximately 0.3595. Therefore, the probability that the mean of a sample of 44 cars would differ from the population mean by less than 51 miles is approximately 0.3595, or 35.95%.

Answer:

Slope (m)= -12.5/5= -2.5

-12.5/5 in fraction form

or

-2.5 in decimal form

Step-by-step explanation:

slope (m)= -12.5/5= -2.5

the points belong as a decreasing linear function

equation: y= -2.5x-5

Answer:

The actual Answer is 10x5=50

Answer: 50

Step-by-step explanation: it’s like when you get 10 and add it up 5 times you get 50

Answer:

.55M + 75 = the total cost

.55(300) + 75 = $240

Step-by-step explanation:

Answer:

C. 31

Step-by-step explanation:

(570.7 - n) ÷ 16

(570.7 - 74.7) ÷ 16

496 ÷ 16

31

Answer:

The zeros for this function are x = -1 and x = 1.67

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

[tex]ax^{2} + bx + c, a\neq0[/tex].

This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = (x - x_{1})*(x - x_{2})[/tex], given by the following formulas:

[tex]x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}[/tex]

[tex]x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}[/tex]

[tex]\bigtriangleup = b^{2} - 4ac[/tex]

In this question:

[tex]f(x) = 3x^{2} - 2x - 5[/tex]

The zeros of the function are the values of x for which

[tex]f(x) = 0[/tex]

Then

[tex]3x^{2} - 2x - 5 = 0[/tex]

This means that [tex]a = 3, b = -2, c = -5[/tex]

Then

[tex]\bigtriangleup = (-2)^{2} - 4*3*(-5) = 64[/tex]

[tex]x_{1} = \frac{-(-2) + \sqrt{64}}{2*3} = 1.67[/tex]

[tex]x_{2} = \frac{-(-2) - \sqrt{64}}{2*3} = -1[/tex]

The zeros for this function are x = -1 and x = 1.67

Answer:

x ≥ -53

Step-by-step explanation:

There is a closed circle at -53 which means equal to

The line goes to the right which means greater than

x ≥ -53

Answer:

D) x>=-53

Step-by-step explanation:

A closed dot means -53 is included in the inequality as a solution, and since it's going right, it's greater than or equal to -53.

Answer:

[tex]\displaystyle \int\limits^8_4 {\frac{10}{x^2}} \, dx = \frac{5}{4}[/tex]

General Formulas and Concepts:

Calculus

Integration

Integration Rule [Reverse Power Rule]:                                                               [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:                                     [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

Integration Property [Multiplied Constant]:                                                         [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Area of a Region Formula:                                                                                     [tex]\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle f(x) = \frac{10}{x^2} \\\left[ 4 ,\ 8 \right][/tex]

Step 2: Find Area

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Final answer:

To solve 3km 6hm 7dam 5m ÷ 15, first convert the distance to meters (3675 m) and then divide by 15 to get 245 meters.

Explanation:

The question given by the student involves performing a division operation with a composite distance measurement in different units. First, we need to convert the entire distance into a single unit (meters) before we divide it by the given number (15).

To convert the given distance to meters, we use the metric system unit conversion:
1 kilometer (km) = 1000 meters (m), 1 hectometer (hm) = 100 meters (m), and 1 decameter (dam) = 10 meters (m). Therefore, 3 km is 3000 m, 6 hm is 600 m, 7 dam is 70 m, and adding the given 5 m to these conversions, we get a total distance of 3675 meters (3000 m + 600 m + 70 m + 5 m = 3675 m).

To find the final answer, divide 3675 meters by 15: which yields 245 meters. Thus, 3km 6hm 7dam 5m divided by 15 equals 245 meters.

Answer:

6(1-r)

Step-by-step explanation:

8-6r+2

=6-6r

=6(1-r)

Answer:

p(x) = x^4  - x^3  - 9x^2  - 11x  - 4

Step-by-step explanation:

You are saying there are  3 roots of  x = -1   and one  x = 4 root

so...

p(x)  =  [(x + 1)^3 ] * (x - 4)

p(x) =  (xxx  + 3xx  + 3x + 1 )*(x- 4)

p(x) = x^4  + 3 x^3  + 3x^2  + x  -  4x^3 - 12xx  - 12x  - 4

p(x) = x^4  - x^3  - 9x^2  - 11x  - 4

Answer: yes

Step-by-step explanation:

do u by chance still have access to those units on odyssey would love to get the answers lol.

Answer:

the 90% of confidence intervals for the average salary of a CFA charter holder

 (1,63,775 , 1,80,000)

Step-by-step explanation:

Explanation:-

random sample of n = 49 recent charter holders

mean of sample (x⁻) =  $172,000

standard deviation of sample( S) = $35,000

Level of significance α= 1.645

90% confidence interval

[tex](x^{-} - Z_{\alpha } \frac{s}{\sqrt{n} } , x^{-} + Z_{\alpha } \frac{s}{\sqrt{n} })[/tex]

[tex](172000 - 1.645 \frac{35000}{\sqrt{49} } , 172000 +1.645 \frac{35000}{\sqrt{49} })[/tex]

on calculation , we get

(1,63,775 , 1,80,000)

The mean value lies between the 90% of confidence intervals

(1,63,775 , 1,80,000)

Answer:

The answer is option A.

Step-by-step explanation:

Subjective probability is defined as a probability which is derived from a person's own experience or belief without relying on any data or scientific calculation.

In the question, the situation given in option A is an example of subjective probability because the analyst is giving a probability based on his or her own belief without using any data at all.

The other options clearly state the probability is being calculated by relying on observations and data.

I hope this answer helps.

A subjective probability example is the belief of a sports analyst in the probability of one college team beating another, without prior data. This contrasts with objective probabilities based on statistical analysis or historical evidence.

The example of a subjective probability among the options given is when a sports analyst believes there is a 0.8 probability that College A will beat College B in their upcoming basketball game, despite there being no previous encounters between the two teams to base this on. This type of probability, which includes personal belief or judgment rather than empirical evidence and statistical analysis, contrasts with objective probabilities that rely on historical data, such as the probability of a 20-year old driver having an accident or the probability of drawing a specific card from a standard deck.

Subjective probability is used in situations where there is a lack of historical data or when assessing future events, making it a personal estimation. This approach is different from calculating probabilities based on observed outcomes and statistical independence, where the probability of events is determined through analysis and empirical evidence.

Answer:

[tex](D)E[ X ] =np.[/tex]

Step-by-step explanation:

Given a binomial experiment with n trials and probability of success​ p,

[tex]f(x)=\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}, 0\leq x\leq n[/tex]

[tex]E(X)=\sum_{x=0}^{n}xf(x)= \sum_{x=0}^{n}x\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}[/tex]

Since each term of the summation is multiplied by x, the value of the term corresponding to x = 0 will be 0. Therefore the expected value becomes:

[tex]E(X)=\sum_{x=1}^{n}x\left(\begin{array}{c}n\\x\end{array}\right)p^x(1-p)^{n-x}[/tex]

Now,

[tex]x\left(\begin{array}{c}n\\x\end{array}\right)= \frac{xn!}{x!(n-x)!}=\frac{n!}{(x-)!(n-x)!}=\frac{n(n-1)!}{(x-1)!((n-1)-(x-1))!}=n\left(\begin{array}{c}n-1\\x-1\end{array}\right)[/tex]

Substituting,

[tex]E(X)=\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^x(1-p)^{n-x}[/tex]

Factoring out the n and one p from the above expression:

[tex]E(X)=np\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^{x-1}(1-p)^{(n-1)-(x-1)}[/tex]

Representing k=x-1 in the above gives us:

[tex]E(X)=np\sum_{k=0}^{n}n\left(\begin{array}{c}n-1\\k\end{array}\right)p^{k}(1-p)^{(n-1)-k}[/tex]

This can then be written by the Binomial Formula as:

[tex]E[ X ] = (np) (p +(1 - p))^{n -1 }= np.[/tex]

The correct formula for the expected number of successes in a binomial experiment with n trials and probability of success p is μ = np (Option D), which means that the expected number of successes is calculated by multiplying the total number of trials by the probability of success.

The formula for the expected number of successes in a binomial experiment with n trials and probability of success p is given by μ = np. In this formula, 'n' represents the number of trials, and 'p' is the probability of success on each trial. Therefore, the correct option, in this case, is D. Upper E (Upper X ) equals np.

This essentially means that the expected number of successes is obtained by multiplying the total number of trials by the probability of success. For instance, if you were to flip a coin (where the probability of getting heads is 0.5) 10 times, the expected number of times you'd get heads would be 0.5 * 10 = 5.

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Yes, the equation specifies a function with independent variable​ x.

Equation: 6x + 19y = 7

This can be put in y = mx + b form,

6x + 19y = 7

19y = -6x + 7

y = -[tex]\frac{6}{19}[/tex]x + [tex]\frac{7}{19}[/tex]

Since the equation can be put in the form of a linear function, the domain is all read numbers (-∞,∞) or -∞ < x < ∞ .

The equation 6x + 19y = 7 does not specify a function in terms of x because for each value of x, there exist multiple possible values of y. A specific example is shown when x = 1.

The equation "6x + 19y = 7" does not specify a function with the independent variable x. In a function, each input (x) corresponds to exactly one output (y). However, in this equation, each value of x corresponds to multiple values of y, thus it does not represent a function.

In order to find a value of x for which there are multiple corresponding values of y, we can set x to any arbitrary value. For example, if we set x = 1, we get "6(1) + 19y = 7", which simplifies to "19y = 1". This implies that there are infinite solutions for y when x = 1, confirming that the equation does not represent a function.

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Answer:

4/5

Step-by-step explanation:

We can find the slope when given two points by using

m= (y2-y1)/(x2-x1)

  = (8-0)/(10-0)

  =8/10

  = 4/5

Answer:

4/5

Step-by-step explanation:

Answer:

use [tex]a = 1/4\pi d^2\\[/tex]

all you have to do is plug 4 into d and then square it, and multiply everything together.

Step-by-step explanation:

Answer:

False

Step-by-step explanation:

Because with the lines on the outside automatically changes the number to a positive number so, therefor the numbers are equal hope this help.

Rate brainlest plz

Michaela's statement that |3| is bigger than |-3| is true.

Michaela's assertion that |3| is greater than |-3| is accurate. The absolute value of a number represents its distance from zero on the number line. In this case, |3| signifies a 3-unit distance from zero, and |-3| also corresponds to a 3-unit distance from zero. Since both values are equidistant from zero, their magnitudes are equal. Consequently, |3| and |-3| both have a value of 3, emphasizing that the absolute value of a number signifies its distance from zero, regardless of its sign, and in this case, both distances are identical at 3 units.

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Answer:

$70.77

Step-by-step explanation:

A=8.09s+3.79c

A=8.09(5)+3.79(8)

A=40.45+30.32

A=70.77

Answer:

$70.77

Step-by-step explanation:

5s+8c=?

5(8.09) + 8(3.79) = ?

40.45 + 30.32 = ?

$70.77

Answer:

the answer is 44

you don't have the answer choice