Answer:
Step-by-step explanation:
The given family of functions is the general solution of the differential equation on the indicated interval. find a member of the family that is a solution of the initial-value problem. y = c1e4x + c2e−x, (−∞, ∞); y'' − 3y' − 4y = 0, y(0) = 1, y'(0) = 2
Solution:
The given differential equation is,
[tex]y=C_{1}e^{4 x}+C_{2}e^{-x}[/tex]------(A)
Differentiating once,with respect to x,
[tex]y'=4C_{1}e^{4 x}-C_{2}e^{-x}[/tex]-------(1)
Differentiating again with respect to x,
[tex]y"=16C_{1}e^{4 x}+C_{2}e^{-x}[/tex]-------(2)
Equation (1) + Equation (2)
y' +y" [tex]=20 C_{1}e^{4 x}[/tex]
[tex]C_{1}=\frac{y'+y"}{20e^{4 x}}[/tex]
4 ×Equation (1) - Equation (2)
4 y'- y"[tex]=-5 C_{2}e^{-x}[/tex]
[tex]C_{2}=\frac{4y'-y"}{-5e^{-x}}[/tex]
Substituting the value of [tex]C_{1},C_{2}[/tex] in A,we get
[tex]y=\frac{y'+y"}{20}+\frac{4 y'-y"}{-5}\\\\ 20 y=y'+y"-16 y'+4 y"\\\\ 20 y=-15 y'+5y"\\\\ 4 y+3 y'-y"=0[/tex]
As, y(0)=1 , and y'(0)=2, gives
[tex]C_{1}+C_{2}=1\\\\ 4C_{1}-C_{2}=2[/tex]
gives , [tex]5C_{1}=3\\\\ C_{1}=\frac{3}{5}\\\\ 5 C_{2}=2\\\\ C_{2}=\frac{2}{5}[/tex]
So, member of the family that is a solution of the initial-value problem, [tex]y=C_{1}e^{4 x}+C_{2}e^{-x}[/tex] is
[tex]5 y=3 e^{4 x}+2 e^{-x}[/tex]
A stained glass window is shaped like a semicircle the bottom edge of the window is 36 inches long what is the area of the stained glass window
The low temperature in Leroy’s town one day was -4. The difference between the high temperature and the low temperature that day was 6. The equation h-(-4)=6 can be used to find h, the high temperature in the town that day in degrees Fahrenheit. What was the high temperature in the town that day, in degrees Fahrenheit?
Consider the quadratic equation x2=4x-5. How many solutions does the equation have
Solve and plot your answer on the number line below: 7.08 + 2x=15.96
Grace has 2 cups of strawberries and plans to divide this amount into equal parts to make 3 strawberry pies. What fraction of a cup of strawberries will be used for each pie?
Number of cups of Strawberries are there for 3 pies =2
Now we apply unitary method here to find how many strawberries are need for 1 pie.
Number of cups of Strawberries required for 1 pie = 2/3
Answer: So Grace would require 2/3 cups of Strawberries for making one pie.
By what percent will a fraction decrease if its numerator is decreased by 50% and its denominator is decreased by 25%?
Answer:
33.33% will work
Step-by-step explanation:
RSM BOI
Zakai cuts a piece of birthday cake as shown below.
What is the volume of the piece of cake?
Jorge is standing at a horizontal distance of 25 feet away from a building. his eye level is 5.5 feet above the ground and looking up he notices a window washer on the side of the building at an angle of elevation of 65, how high is the window washer above the ground
a puppy pen is 4 square feet wide and 5 feet long. is 21 square feet of fabric large enough to make a mat for the pen? Explain
You track fuel accounts for q shipping line. One vessel consumes 2 1/2 tons of fuel per day during transport. About how many fuel in tons should the vessel consume during 15-day transport?
A store charges 7% sales tax. Which expression can be used to find the total cost of an item with a price of p? 0.07p 0.93p 1.07p 7.00p
If you have an item that costs 10 dollars and a sales tax of 7% you could do it this way
10 * 7/100 = 0.70 dollars.
The total cost is 10.70 dollars. or 10 dollars and 70 cents.
The best way to do the total however is to multiply the cost by 1.07. You will get the number the customer has to pay.
10 * 1.07 = 10.70
So for any price (p) it would be 1.07*p
Answer:
1.07p
Step-by-step explanation:
The tax equals the price times the tax rate
We know the price p and the tax rate 7%
tax = p*7%
Changing this to decimal form
tax = .07p
The final price of the item is the sales tax plus the price
final price = tax + price
.07p +p
1.07p
Andy and alex both decided to order prints of their photos. Andy ordered 40 small 4x6 inch prints and 10 large 8x10 inch prints. He paid a total of $32.50 for his photos. Alex paid 20$ for 20 small 4x6 inch prints and 8 large 8x10 inch prints. How much do the small and large sized prints cost
Final answer:
To find the cost of small and large prints, we create two equations based on Andy's and Alex's orders and solve for the two variables. The small 4x6 inch prints cost $0.50 each, and the large 8x10 inch prints cost $1.25 each.
Explanation:
To solve how much small and large sized prints cost, we can set up a system of linear equations based on the information given:
Andy's order: 40 small prints and 10 large prints for $32.50Alex's order: 20 small prints and 8 large prints for $20.00Let s represent the cost of a small 4x6 inch print, and let l represent the cost of a large 8x10 inch print. We can then form the equations:
40s + 10l = 32.5020s + 8l = 20.00By dividing the first equation by 2, we get:
20s + 5l = 16.25Subtracting the second equation from this result gives:
(20s + 5l) - (20s + 8l) = (16.25 - 20)-3l = -3.75l = 1.25With the cost of a large print found, we can plug this back into the second equation to find the cost of a small print:
20s + 8(1.25) = 2020s + 10 = 2020s = 10s = 0.50Therefore, the cost of a small 4x6 inch print is $0.50 and a large 8x10 inch print is $1.25.
what is 0.080 as a fraction
Answer:
To write 0.080 as a fraction you have to write 0.080 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.
0.080 = 0.080/1 = 0.8/10 = 8/100
So your final answer is: 0.080 as a fraction equals 8/100
Step-by-step explanation:
The decimal number 0.080 as a fraction is A = 2/25
Given data:
The decimal number is represented as 0.080
Step 1: Count the number of decimal places in the given decimal. So, there are three decimal places.
Step 2: Write the decimal as the numerator of the fraction. The decimal 0.080 becomes the numerator 80.
Step 3: Determine the denominator of the fraction. Since there are three decimal places, the denominator should be 10 raised to the power of the number of decimal places. So, the denominator is 10³ = 1000.
Putting it all together, 0.080 as a fraction is 80/1000.
Dividing both the numerator and denominator by 40:
80 ÷ 40 / 1000 ÷ 40 = 2/25
Hence, 0.080 as a simplified fraction is 2/25.
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Christian got a haircut yesterday afternoon if the hair stylist charged $18 and christian gave 20% tip how much dod he pay for the haircut
Answer:
He paid $ 21.6 for the haircut.
Step-by-step explanation:
Given,
The amount charged by hair stylist = $ 18,
The percentage of tip = 20 %,
So, the amount of the tip = 20 % of 18
= 0.2 × 18
= $ 3.6,
Hence, the total amount paid by him for haircut = The amount charged by hair stylist + Tip
= $ 18 + $ 3.6
= $ 21.6
Determine the x-intercept of 5x -6y =10
find the surface area of the toolbox
Which number line represents the solution set for the inequality-4(x+3)<-2-2x
The inequality -4(x+3)<-2-2x simplifies to x > -5. Therefore, the number line representing this solution should shade the values greater than -5, thus, highlighting that x is any value greater than -5.
Explanation:Let's solve the inequality -4(x+3)<-2-2x step by step:
Distribute -4 through (x+3) to get -4x-12<-2-2x. Add 4x to both sides to isolate x, which leads to -12 < 2x - 2. Finally, add 2 to both sides to isolate x to get -10 < 2x or equivalently, x > -5.
As a result, the number line that represents this solution is one where the values greater than -5 are shaded. This means the value of x is anything greater than -5. Any number line visualization should start at -5 and include everything to the right of that point.
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How many outcomes are there in the sample space for rolling 1 die?
Answer:
6
Step-by-step explanation:
How many bits are required to represent the decimal numbers in the range from 0 to 999 in straight binary code?
Final answer:
To represent the decimal numbers from 0 to 999 in binary code, we require 10 bits. This is determined by finding the binary equivalent of the largest number, 999, which necessitates at least 10 powers of 2 (from [tex]2^0 \ to \ 2^9[/tex]).
Explanation:
To determine how many bits are required to represent the decimal numbers in the range from 0 to 999 in straight binary code, we need to find the binary equivalent of the largest number in that range, which is 999. In binary, this would require the highest power of 2 that is less than or equal to 999. The largest power of 2 less than 999 is 512 (29), and we continue to add powers of 2 to represent the number:
Adding these up, we see that we need at least 10 bits to represent the number 999 in binary, because adding powers of 2 from 20 to 29 will give us the required range. Therefore, we need 10 bits to represent any number from 0 to 999 in binary.
Suppose that the probabilities of a customer purchasing 0, 1, or 2 books at a book store are 0.20.2, 0.30.3, and 0.50.5, respectively. what is the standard deviation of this customer's book purchases?
The standard deviation of the customer's book purchases is 0.72.
The standard deviation of a discrete probability distribution can be calculated using the following formula:
σ = √(p[tex](x - \mu)^2[/tex])
where:
σ is the standard deviation
p(x) is the probability of the event x
μ is the mean of the distribution
In this case, the probabilities of the customer purchasing 0, 1, or 2 books are 0.2, 0.3, and 0.5, respectively. So, the mean of the distribution is:
μ = (0 * 0.2) + (1 * 0.3) + (2 * 0.5) = 1.2
The standard deviation is then:
σ = √([tex](0 - 1.2)^2 (0.3)^2[/tex] + [tex](1 - 1.2)^2 (0.3)^2[/tex] + [tex](2 - 1.2)^2 (0.5)^2)[/tex] = 0.72
So, the standard deviation of the customer's book purchases is 0.72.
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Hdc produces microcomputer hard drives at four different production facilities (f1, f2, f3, and f4) hard drive production at f1, f2, f3, and f4 is 20%, 25%, 15%, and 40%, respectively. quality control records indicate that 1.5%, 2%, 1%, and 3% of the hard drives are defective at f1, f2, f3, and f4, respectively.
a. if a defective hdc hard drive is picked at random, what is the probability that it was produced at f2?
b. if a defective hdc hard drive is picked at random, what is the probability that it was produced at f4?
c. if an hdc hard drive is picked at random, what is the probability that it is non-defective? g
a. Probability defective hard drive from F2 ≈ 0.3226.
b. Probability defective hard drive from F4 ≈ 0.7742.
c. Probability non-defective hard drive ≈ 0.9785.
To solve this problem, we can use Bayes' theorem, which states:
[tex]\[ P(A|B) = \frac{P(B|A) \times P(A)}{P(B)} \][/tex]
Where:
- [tex]\( P(A|B) \)[/tex] is the probability of event A happening given that event B has occurred.
- [tex]\( P(B|A) \)[/tex] is the probability of event B happening given that event A has occurred.
- [tex]\( P(A) \)[/tex] and [tex]\( P(B) \)[/tex] are the probabilities of events A and B, respectively.
Let's solve each part of the problem:
a. If a defective HDC hard drive is picked at random, what is the probability that it was produced at F2?
Let:
- A be the event that the hard drive is defective.
- B be the event that the hard drive was produced at F2.
We need to find [tex]\( P(B|A) \)[/tex], the probability that the hard drive was produced at F2 given that it is defective.
[tex]$\begin{aligned} & P(B \mid A)=\frac{P(A \cap B)}{P(A)} \\ & P(A \cap B)=P(A \mid B) \times P(B)=0.02 \times 0.25=0.005 \\ & P(A)=P(A \cap F 1)+P(A \cap F 2)+P(A \cap F 3)+P(A \cap F 4) \\ & P(A)=0.015 \times 0.20+0.02 \times 0.25+0.01 \times 0.15+0.03 \times 0.40=0.0155 \\ & P(B \mid A)=\frac{0.005}{0.0155} \approx 0.3226\end{aligned}$[/tex]
b. If a defective HDC hard drive is picked at random, what is the probability that it was produced at F4?
We need to find [tex]\( P(F4|A) \)[/tex], the probability that the hard drive was produced at F4 given that it is defective.
[tex]\[ P(F4|A) = \frac{P(A \cap F4)}{P(A)} \][/tex]
[tex]\[ P(A \cap F4) = P(A|F4) \times P(F4) = 0.03 \times 0.40 = 0.012 \][/tex]
[tex]\[ P(F4|A) = \frac{0.012}{0.0155} \approx 0.7742 \][/tex]
c. If an HDC hard drive is picked at random, what is the probability that it is non-defective?
Let P(non-defective) = P(non-defective at F1) + P(non-defective at F2) + P(non-defective at F3) + P(non-defective at F4)
P(non-defective) = [tex](1 - 0.015) \times 0.20 + (1 - 0.02) \times 0.25 + (1 - 0.01) \times 0.15 + (1 - 0.03) \times 0.40[/tex]
P(non-defective) = [tex]0.985 \times 0.20 + 0.98 \times 0.25 + 0.99 \times 0.15 + 0.97 \times 0.40[/tex]
P(non-defective) = 0.197 + 0.245 + 0.1485 + 0.388 = 0.9785
So, the probability that an HDC hard drive picked at random is non-defective is approximately [tex]\( 0.9785 \)[/tex].
What is the mean of the values in the stem-and-leaf plot? Enter your answer in the box.Key: 2|5 means 25
Enter your answer in the box.
Key: 2|5 means 25
A stem-and-leaf plot with a stem value of 1 with leaf values of 5 and 8, a stem value of 2, a stem value of 3, a stem value of 4 with a leaf value of 6, a stem value of 5 with leaf values of 0, 0, 0, 0, 7, a stem value of 6, a stem value of 7, a stem value of 8, and a stem value of 9.
The mean of the values in the stem-and-leaf plot is 42.
To find the mean of the values in the stem-and-leaf plot, we first need to interpret the plot correctly. Here's the stem-and-leaf plot description:
Stem | Leaves
1 | 5, 8
2 |
3 |
4 | 6
5 | 0, 0, 0, 0, 7
6 |
7 |
8 |
9 |
Let's list the individual values from the plot:
- From stem 1: Leaves are 5 and 8
- From stem 4: Leaf is 6
- From stem 5: Leaves are 0, 0, 0, 0, 7
Now, we calculate the mean (average) of these values.
Step-by-step calculation:
1. List of values:
- Values from stem 1: 15, 18
- Values from stem 4: 46
- Values from stem 5: 50, 50, 50, 57
2. Count the number of values:
- There are 2 values from stem 1, 1 value from stem 4, and 5 values from stem 5.
- Total count = 2 + 1 + 5 = 8
3. Calculate the sum of all values:
- Sum = 15 + 18 + 46 + 50 + 50 + 50 + 50 + 57
- Sum = 336
4. Calculate the mean:
- Mean = Sum / Count
- Mean = 336 / 8
- Mean = 42
Therefore, the mean of the values in the stem-and-leaf plot is [tex]{42} \).[/tex]
Michael will be travelling out of town for business. During his travel, he is scheduled to have 4 dinners, 5 lunches, and 3 breakfasts. His employer will pay him for these meals at the following rate: $ 22.65 for dinner, $ 10.95 for lunch, and $ 6.53 for breakfast.
what is the probabilaty getting a sum of 7 if you rolled a pair of dice?
A gardener plants a bed of flowers such that he plants twenty day lilies in the first row, twenty-six day lilies in the second row, and thirty-two day lilies in the third row. He continues to plant lilies in the bed with this pattern for a total of twelve rows. How many day lilies did he plant?
There are 86 lilies he did plant in 12th row of the garden.
What is Arithmetic Sequence?Arithmetic Progression (AP) is a sequence of numbers in order, in which the difference between any two consecutive numbers is a constant value. It is also called Arithmetic Sequence.
Here, The number of lilies plants in first, second third,..., and last row are respectively.
20,26,32,........
the number of rows of lilies plants is 12.
The sequence 20,26,32,........ is an A.P. with first term a =20, common difference d = 6 and n =12
formula for nth term.
∴aₙ = a+(n−1)d
aₙ=20+ (12-1).6
aₙ = 20 + 11 X 6
aₙ = 86
Thus, there are 86 lilies he did plant in 12th row of the garden.
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Please help me out with #8 surface area and please explain
Simplify 10/16 to lowest terms and find an equivalent fraction that has a denominator of 32?
Answer:
The lowest fraction for [tex]\frac{10}{16}[/tex] is [tex]\frac{5}{8}[/tex] and a equivalent fraction with denominator of 32 is [tex]\frac{20}{32}[/tex].
Step-by-step explanation:
First, to have the fraction to the lowest terms we will have to divide the numerator and denominator by 2, this is:
[tex]\frac{10/2}{16/2}=\frac{5}{8}[/tex]
As can be seen the expression couldn't be simplified more because there is no a common number that could divide the numerator and denominator.
Second, to have an equivalent fraction with 32 in the denominator we will have to multiply the denominator by 2 and of course the numerator, this is:
[tex]\frac{10*2}{16*2}=\frac{20}{32}[/tex]
The lowest fraction for [tex]\frac{10}{16}[/tex] is [tex]\frac{5}{8}[/tex] and a equivalent fraction with denominator of 32 is [tex]\frac{20}{32}[/tex].
To simplify 10/16 to lowest term, it becomes 5/8. An equivalent fraction of 5/8 with 32 as the denominator is 20/32.
Explanation:To simplify 10/16 to its lowest term, we have to find the greatest common divisor of 10 and 16, which is 2. Hence, when we divide both the numerator and the denominator by 2, we get 10/2 = 5 and 16/2 = 8. So, the fraction 10/16 simplified to its lowest term is 5/8.
Now, to find an equivalent fraction with 32 as the denominator, we need to multiply both the numerator and the denominator of 5/8 by the same number so as not to change the value of the fraction. Here, we multiply by 4 (since, 8*4 = 32) to get 5*4 = 20 on the numerator. Therefore, an equivalent fraction of 5/8 with 32 as the denominator is 20/32.
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ASAP Select the statement that correctly describes the expression below.
(2x+5)^2
a) the sum of the square of 2 times x and 5
b)the square of the sum of 2 times x and 5
c)the square of 2 times the addition of x and 5
d)the sum of 2 times x and the square of 5
Answer:
Option B
Step-by-step explanation:
The given expression is ( 2x + 5)²
We have to form a statement to describe the expression given.
(2x + 5)² square of sum of 2 times x and 5
Option B is the correct answer.
With a short time remaining in the day a delivery driver has to make deliveries at 5 locations among the 6 locations remaining. How many different routes are possible
To find the number of different routes the delivery driver can take to make the deliveries at 5 out of 6 locations, we can use the concept of permutations.
Explanation:To find the number of different routes the delivery driver can take, we can use the concept of permutations. Since the delivery driver has to make deliveries at 5 out of the remaining 6 locations, we need to calculate the number of ways to arrange these locations.
We can use the formula for permutations to find the number of different routes:
nPr = n! / (n - r)!
Using this formula, we can calculate the number of different routes as:
6P5 = 6! / (6 - 5)! = 6! / 1! = 6 × 5 × 4 × 3 × 2 × 1 / 1 = 720
Therefore, there are 720 different routes the delivery driver can take to make the deliveries.