Know how you would determine the percent yield of a reaction if you have the given amount of the reactants and the amount of the product actually collected in the lab.

Answers

Answer 1
First, use the given amount of reactants to calculate the theoretical amount of products that should be formed based on stoichiometry. Next, divide the actual amount of obtained product by that theoretical amount, and multiply by 100%. This gives the percent yield of the reaction.

Related Questions

What is the ionic form of this unbalanced equation? mno2 + hno2 → mn(no3)2 + h2o?

Answers

The  ionic  form  of  the unbalanced  equation

MnO2  +HNO2 =  Mn(NO3)2  +H2O  is  as   below

MnO2(s)   +  H^+(aq)  + NO2^-(aq) = Mn^2+(aq)  + No3^-(aq)  +  H20(l)

MnO2   does  not  dissociate  since it is  in solid state. In   addition H2O   is in liquid  state  thus  does  not  dissociate in to  ions

What is the mass of aluminum metal that releases 22.4 l of hydrogen gas at stp from hydrochloric acid? __al(s) + __hcl(aq) → __alcl3(aq) + __h2(g) 18.0 g 81.0 g 9.00 g 40.5 g 27.0 g?

Answers

The mass  of  Al  metal   that releases 2.4 L  of hydrogen gas at STP  is calculated as below

AT  STP  1 mole  =22.4 l
what about 22.4l =? moles
(22.4 L x 1  mole) /22.4 L= 2mole

write the reacing reaction

2Al+ 6 HCL = 2AlCl3 + 3H2
by use of  mole ratio between  Al to  H2  which is 2 : 3  the   mole Al = 1 x2/3 = 0.667 moles
mass =moles x molar mass
=0.667 mole  x27 g/mol= 18  grams
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