Latesha’s mother puts $85 in Latesha’s lunch account at school. Each day Latesha uses $3 from her account for lunch. The table below represents this situation. Latesha’s Lunch Account Day Amount Left in Account ($) 0 $85 1 2 3 4 5 How much is left in Latesha’s lunch account after she has had lunch for 5 days?

A.$15
B.$67
C.$70
D.82

Answer:

(a,b)

Step-by-step explanation:

simply we find the midpoint of AC and the midpoint of Bd by dividing over 2

Answer:

We choose D.

Step-by-step explanation:

Let the midpoint is O

We will use Angle-SIde-Angle principle to prove that the diagonals of a rectangle bisect each other.

Have a look at the two triangles: AOB and DOC, they are congruent because:

So we can conclude that: OB = OB  when two triangles: AOB and DOC are congruent.

Similar, apply for the two triangles: AOD and BOC are congruent so we have OA = OC .

=> It proves that the point O simultaneously is the midpoint and intersection point for the diagonals.

=> The midpoint of AC is ([tex]\frac{2a+ 0}{2}[/tex] , [tex]\frac{0 + 2b}{2}[/tex] ) = (a, b), we choose D.

Answer:

The length of each piece of cloth =1/12 yard

Step-by-step explanation:

Number of pieces = 5

Carlos cut 5/12 of a yard of cloth

Length of each piece = ?

To find the length of each piece simply divide 5/12 by 5.

Length of each piece of cloth = 5/12/5

Length of each piece of cloth =5/12 * 1/5

Length of each piece of cloth=1/12

Therefore the length of each piece of cloth =1/12 yard....

Answer:

the answer is a

Step-by-step explanation:

Answer:

=3/4

Step-by-step explanation:

A bus arrives at a bus stop every 40 minutes.

You arrive at a bus stop at a random time.

So, probability that you will wait at most 10 minutes = 10/40

So, The probability that you will wait at least 10 minutes= 1-10/40

=1- 10/40

By taking L.C.M we get;

=40-10/40

=30/40

=3/4

Thus the probability that you will have to wait at least 20 minutes for the bus is 3/4....

Answer:

3/4

Step-by-step explanation:

hahahaha to you asell

Answer:

The solution of kx-2=7 is x = 9/k

Step-by-step explanation:

Given:

kx-2 = 7

In order to get the solution of the given equation, we have to isolate x so that we can determine its value.

Adding 2 on both sides

kx-2+2 = 7+2

kx = 9

Dividing both sides by k

kx/k = 9/k

x = 9/k

Therefore, the solution of kx-2=7 is x = 9/k ..

Answer:

X=9/k

Step-by-step explanation:

^^^ person is right

Answer:

Step-by-step explanation:

[tex]\left\{\begin{array}{ccc}x+3y+2z=8&(1)\\3x+y+3z=-10&(2)\\-2x-2y-z=10&(3)\end{array}\right\qquad\text{subtract both sides of the equations (1) from (2)}\\\\\underline{-\left\{\begin{array}{ccc}3x+y+3z=-10\\x+3y+2z=8\end{array}\right }\\.\qquad2x-2y+z=-18\qquad(4)\qquad\text{add both sides of the equations (3) and (4)}\\\\\underline{+\left\{\begin{array}{ccc}-2x-2y-z=10\\2x-2y+z=-18\end{array}\right}\\.\qquad-4y=-8\qquad\text{divide both sides by (-4)}\\.\qquad\qquad y=2\qquad\text{put the value of y to (1) and (3)}[/tex]

[tex]\left\{\begin{array}{ccc}x+3(2)+2z=8\\-2x-2(2)-z=10\end{array}\right\\\left\{\begin{array}{ccc}x+6+2z=8&\text{subtract 6 from both sides}\\-2x-4-z=10&\text{add 4 to both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+2z=2&\text{multiply both sides by 2}\\-2x-z=14\end{array}\right\\\underline{+\left\{\begin{array}{ccc}2x+4z=4\\-2x-z=14\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad3z=18\qquad\text{divide both sides by 3}\\.\qquad\qquad z=6\qquad\text{put the value of z to the first equation}[/tex]

[tex]x+2(6)=2\\x+12=2\qquad\text{subtract 10 from both sides}\\x=-10[/tex]

Answer:

720

Step-by-step explanation:

permutation formula=

n!/(n-r)!

There are 720 different starting position configurations possible for the 6 starting players of a volleyball team that follows the rule.

We have

To determine the number of different starting position configurations for a volleyball team with 6 players, we can use the concept of permutations.

Since each player has a unique designated position on the court, we can think of this as arranging 6 distinct objects (the players) in 6 distinct positions (the court positions).

The number of possible arrangements can be calculated using the formula for permutations, denoted as "n P r," which represents the number of ways to select and arrange r objects from a set of n objects.

In this case, we want to arrange 6 players in 6 positions, so we can calculate 6 P 6:

6 P 6 = 6!

Using the formula for factorial:

6! = 6 * 5 * 4 * 3 * 2 * 1

= 720

Therefore,

There are 720 different starting position configurations possible for the 6 starting players of a volleyball team that follows the rule of having exactly 6 players on the court, each with a unique designated position.

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Hi !

625 - (625 ÷ 25) - 25 = 575

Answer:

575

Step-by-step explanation:

Following the order of operations, division is performed before subtraction

Given

625 - 625 ÷ 25 - 25 ← perform the division

= 625 - 25 - 25 ← now perform the subtraction

= 600 - 25

= 575

Step-by-step explanation:

Cavalieri's Principle. A method, with formula given below, of finding the volume of any solid for which cross-sections by parallel planes have equal areas. This includes, but is not limited to, cylinders and prisms.

Answer:

9÷2+4

Step-by-step explanation:

Answer:

[tex]h(x)=+-\sqrt{\frac{x+4}{9} }[/tex]

Step-by-step explanation:

Hello

I think  I can help you with this

Let

[tex]y = 9x^{2}-4\\h(x)=y^{-1}[/tex]

to find the inverse of y([tex]y^{-1}[/tex])

Step 1

switch x and y

[tex]y = 9x^{2}-4\\\\x= 9y^{2}-4[/tex]

Step 2

Now solve the equation for y (isolating y)

[tex]x= 9y^{2}-4\\Add\ 4\ to\ both\ sides\\x+4= 9y^{2}-4+4\\x+4=9y^{2}\\divide\ each\ side\ by\ 9\\\frac{x+4}{9} =\frac{9y^{2}}{9}\\\\x+4=y^{2} \\[/tex]

[tex]h(x)=+-\sqrt{\frac{x+4}{9} }[/tex]

Have a great day

[tex]\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-2}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-2-5}{4-(-3)}\implies \cfrac{-7}{4+3}\implies \cfrac{-7}{7}\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-5=1[x-(-3)]\implies y-5=1(x+3) \\\\\\ y-5=x + 3\implies y=x+8[/tex]

Answer:

option a

Step-by-step explanation:

To find the slope 'm' we use 2 points from the line, those are given in the statement:

[tex]x_{1} =3\\y_{1} =6\\\\x_{2} =5\\y_{2} =3\\m=\frac{y_{2} -y_{1} }{x_{2}-x_{1}}\\m=\frac{3 -6 }{5-3}}\\m=\frac{-3 }{2}}[/tex]

Answer:

it's A

Step-by-step explanation:

The domain is all the input values which is x|x=-5,-3,1,2,6

Answer:

the answer is B

Step-by-step explanation:

the sum of both angles is 90 degree.

By definition if the sum of two angles is 180 is supplementary

If the sum of two angles is 90 is complementary

Then, 70 + 20 =90 degree

So, They are complementary angles

Answer:

Option B.

Step-by-step explanation:

Measure of ∠ABC = 20°

and measure of ∠NML = 70°

Then ∠ABC + ∠NML = 20 + 70

                                  = 90°

Therefore, ∠ABC and ∠NML are complementary angles because sum of complementary angles is 90°.

Intersection of two sets E and F is set G which contains elements x that are common to set E and set F.

[tex]G=E\cap F=\{x; x\in E\wedge x\in F\}[/tex]

Here G is,

[tex]G=\{-2,6\}[/tex]

Union of two sets E and F is a set H which contains all elements x that occur in set E or set F.

[tex]H=E\cup F=\{x; x\in E\vee x\in F\}[/tex]

Hence,

[tex]H=\{-2,-1,2,3,5,6,7\}[/tex]

Hope this helps.

r3t40

The intersection of sets E and F: E ∩ F = {-2, 6}

The union of sets E and F: E U F = {-2, -1, 2, 3, 5, 6, 7}

Answer:

[tex]\large\boxed{(f+g)(x)=4^x+17x-1}[/tex]

Step-by-step explanation:

[tex](f+g)(x)=f(x)+g(x)\\\\f(x)=4^x+12x,\ g(x)=5x-1\\\\(f+g)(x)=(4^x+12x)+(5x-1)=4^x+17x-1[/tex]

The correct rule that describes the composition of transformations mapping AABC to AA"B"C" is:

- Ro. 900 ◦ T-6, -2(x, y)

Here's a step-by-step explanation:

1. "Ro. 900" stands for a 900 degrees counterclockwise rotation.

2. "T-6, -2" represents a translation of 6 units to the left and 2 units down.

3. When these transformations are applied in sequence to the original figure AABC, you first rotate it 900 degrees counterclockwise and then translate it 6 units to the left and 2 units down, resulting in the figure AA"B"C".

This rule combines rotation and translation to map AABC to AA"B"C". This composition of transformations is what leads to the desired outcome.

The complete question is : Which rule describes composition of transformations that maps ABC to A"B"C"?

Answer:

Step-by-step explanation:

[tex]\left\{\begin{array}{ccc}x-3y=6&\text{multiply both sides by (-2)}\\2x+2y=4\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-2x+6y=-12\\2x+2y=4\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad8y=-8\qquad\text{divide both sides by 8}\\.\qquad\qquad y=-1\\\\\text{Put the value of y to the first equation:}\\\\x-3(-1)=6\\x+3=6\qquad\text{subtract 3 from both sides}\\x=3[/tex]

Answer: y = -1 and x = 3

Step-by-step explanation:

x - 3y = 6 --------(1)

2x + 2y = 4 -------(2)

we multiply (1) by 2

2x - 6y = 12 --------(3)

(3) - (1)

-8y = 8

y = -1

Putting y = -1 into equation (1)

x - 3 (-1) = 6

x + 3 =6

collect the like term

x = 6 - 3

x = 3

Therefore x= 3 and y = -1

Answer:

[tex]\frac{\pi}{4}[/tex]

[tex]\frac{5\pi}{6}[/tex]

Step-by-step explanation:

The answer uses the unit circle and that sine and cosecant are reciprocals.

The first choice doesn't even fit the criteria that [tex]x[/tex] is between [tex]0[/tex] and [tex]2\pi[/tex] (inclusive of both endpoints) because of the [tex]x=\frac{-7\pi}{6}[/tex].

Let's check the second choice.

[tex]\csc(\frac{\pi}{4})=\frac{2}{\sqrt{2}} \text{ since } \sin(\frac{\pi}{4})=\frac{\sqrt{2}}{2}[/tex].

[tex]\csc(\frac{\pi}{4})>1 \text{ since } \frac{2}{\sqrt{2}}>1[/tex]

[tex]\csc(\frac{\pi}{2})=1 \text{ since } \sin(\frac{\pi}{2})=1[/tex] which means [tex]\csc(\frac{\pi}{2})=1[/tex] which is not greater than 1.

So we can eliminate second choice.

Let's look at the third.

[tex]\csc(\frac{5\pi}{6})=2 \text{ since } \sin(\frac{5\pi}{6})=\frac{1}{2}[/tex] which means [tex]\csc(\frac{5\pi}{6})>1[/tex].

[tex]\csc(\pi)[/tex]  isn't defined because [tex]\sin(\pi)=0[/tex].

So we are eliminating 3rd choice now.

Let's look at the fourth choice.

[tex]\csc(\frac{7\pi}{6})=-2 \text{ since } \sin(\frac{7\pi}{6})=\frac{-1}{2}[/tex] which means [tex]\csc(\frac{7\pi}{6})<1[/tex] and not greater than 1.

I was looking at the rows as if they were choices.

Let me break up my choices.

So we said [tex]x=-\frac{7\pi}{6}[/tex] doesn't work because it is not included in the inequality [tex]0\le x \le 2\pi[/tex].

How about [tex]x=0[/tex]?  This leads to [tex]\csc(0)[/tex] which doesn't exist because [tex]\sin(0)=0[/tex].

So neither of the first two choices on the first row.

Let's look at the second row again.

We said [tex]\frac{\pi}{4}[/tex] worked but not [tex]\frac{\pi}{2}[/tex]

Let's look at the choices on the third row.

We said [tex]\frac{5\pi}{6}[/tex] worked but not [tex]x=\pi[/tex]

Let's look at at the last choice.

We said it gave something less than 1 so this choice doesn't work.

Answer:x=pi/4 and x=5pi/6

Step-by-step explanation:

on edge just did it

Answer:

9

Step-by-step explanation:

To find the common difference, take the second term and subtract the first term

13-4 =9

Lets check:

Take the third term and subtract the second term

22-13 =9

The common difference is 9

Answer:

9

Step-by-step explanation:

9 is the common difference between the numbers in this sequence

4 +9 = 13

13 +9 = 22

22 +9 = 31

31 +9 = 40

Therefore the common difference is 9

PLEASE DO MARK ME AS BRAINLIEST IF MY ANSWER IS HELPFUL ;)

Answer:

The value is 14/9.

Step-by-step explanation:

xy/9

Put the value of x= -7 and y= -2 in the expression.

=(-7) (-2)/9

=14/9

Answer:

Option D. x=15°

Step-by-step explanation:

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

see the attached figure to better understand the problem

∠x=(1/2)[arc AB-arc CD]

arc AB=40°

Remember that the diameter divide the circle into two equal parts

arc CD=180°-(130+40)°=10°

substitute

∠x=(1/2)[40°-10°]=15°

Answer:

x = 15!

Step-by-step explanation:

I got it right on my in class exercise!

The answer is " D. Graph D"

Answer:

Assuming you have [tex]f(n)=0.4f(n-1)+12[/tex] with [tex]f(1)=4[/tex], the answer is f(2)=13.6.

Step-by-step explanation:

I think that says [tex]f(n)=0.4f(n-1)+12[/tex] with [tex]f(1)=4[/tex].

Now we want to find [tex]f(2)[/tex] so replace n with 2:

This gives you:

[tex]f(2)=0.4f(2-1)+12[/tex]

[tex]f(2)=0.4f(1)+12[/tex]

[tex]f(2)=0.4(4)+12[/tex]

[tex]f(2)=1.6+12[/tex]

[tex]f(2)=13.6[/tex]

Answer:

13.6 (Answer C)

Step-by-step explanation:

I think you meant  f(n) = 0.4 * f(n-1) + 12, where * represents multiplication.

Then f(2) = 0.4 * (4) + 12, or 1.6 + 12, or 13.6.

Answer:

B

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

[tex]\frac{f(b)-f(a)}{b-a}[/tex]

Here [ a, b ] = [ 3, 5 ]

From the table of values

f(b) = f(5) = 32

f(a) = f(3) = 8

Hence

average rate of change = [tex]\frac{32-8}{5-3}[/tex] = [tex]\frac{24}{2}[/tex] = 12

Answer:

The average rate of change is [tex]12[/tex]

Step-by-step explanation:

Given:

Interval; x = 3 to x = 5

We'll represent these by

x1 = 3

x2 = 5

The corresponding y values are:

When x = 3, y = 8

When x = 5, y = 32

This will also be represented

y1 = 8

y2 = 32

Average rate of change is then calculated as follows

[tex]m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}[/tex]

Where m represent average rate of change

By Substitution, we have

[tex]m = \frac{32 - 8}{5 - 3}[/tex]

[tex]m = \frac{24}{2}[/tex]

[tex]m = 12[/tex]

Hence, the average rate of change is [tex]12[/tex]

Answer:

[tex]\large\boxed{h(x)=x^3}[/tex]

Step-by-step explanation:

[tex]f(x)=(6x^3-7)^3\\\\(h\circ g)(x)=h\bigg(g(x)\bigg)\to\text{exchange x to}\ g(x)=6x^3-7\\\\f(x)=(\underbrace{6x^3-7}_{g(x)})^3=\bigg(g(x)\bigg)^3=h\bigg(g(x)\bigg)\\\\\text{Therefore}\ h(x)=x^3[/tex]

Answer:

B) 4

Step-by-step explanation:

Tan is opposite/adjacent. That means that 3 is the opposite side while 4 is the adjacent side.

Answer:

[tex]x=\frac{1+\sqrt{35}i}{-6}\,\, and\,\, x=\frac{1-\sqrt{35}i}{-6}\\[/tex]

Step-by-step explanation:

the quadratic formula is:

[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

a= -2, b = -1 and c =-3

Putting values in the formula

[tex]x=\frac{-(-1)\pm\sqrt{(-1)^2-4(-3)(-3)}}{2(-3)}\\x=\frac{1\pm\sqrt{-35}}{-6}\\x=\frac{1+\sqrt{-35}}{-6}\,\, and\,\, x=\frac{1-\sqrt{-35}}{-6}\\We\,\, know \,\,that \,\,\sqrt{-1} = i  \\x=\frac{1+\sqrt{35}i}{-6}\,\, and\,\, x=\frac{1-\sqrt{35}i}{-6}\\[/tex]

So, [tex]x=\frac{1+\sqrt{35}i}{-6}\,\, and\,\, x=\frac{1-\sqrt{35}i}{-6}\\[/tex]

Answer:

Using quadratic formula, the solution to this equation is  the roots of the equations given are ;   x = 1+√35i /  -6   or                x = 1-√35i /  -6

Step-by-step explanation:

-3x²  -  x   - 3=0

To solve this using quadratic formula, we will first of all write down the quadratic formula

x = -b ±√b²- 4ac   /   2a

From the above question;

a = -3    b = -1  and c=-3

So we can now proceed to plug-in our variable

x = -(-1) ± √(-1)² - 4(-3)(-3)    /      2(-3)

x=  1±√1-36   /   -6

x = 1 ±√-35    /  -6

x=1 ± √35  ·  √-1    /-6

x = 1±√35 i    /     -6

Note the square root of negative 1 is i

Either x = 1+√35i /  -6   or   x = 1-√35i /  -6

Therefore the roots of the equations given are ;   x = 1+√35i / -6   or   x = 1-√35i /  -6

Answer: A. M=2, y int=3

Step-by-step explanation:

In slope intercept form the equation is y=2x+3, in the formula y=mx+b m=slope and b=y intercept.

The slope and y-intercept of the equation 6x - 1 = 3y - 10 is Option(A) m=2, b = 3 .

The slope of a straight line is the measure of its inclination or tangent to the point of the straight line.

The y-intercept gives the value of the y-coordinate where the straight line intercepts with the y-axis.

For general representation of a straight line y = mx + c , the slope is the value of m and its y-intercept is c.

The given equation is 6x - 1 = 3y - 10 .

⇒ 3y = 6x + 10 - 1

⇒ 3y = 6x + 9

∴  y = 2x + 3

Comparing with the general equation of straight line, y = mx + c we get slope = 2 and y-intercept = 3.

Thus, the slope and y-intercept of the equation 6x - 1 = 3y - 10 is Option(A) m=2, b = 3 .

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Answer:

reciprocal

Step-by-step explanation:

Final answer:

To divide two fractions, rewrite the operation as the first fraction multiplied by the reciprocal of the second. Multiplication of fractions involves simply multiplying the numerators and denominators, then simplifying by any common factors.

Explanation:

To divide two fractions, first rewrite the problem as the dividend times the reciprocal of the divisor. When dividing by a fraction, it is equivalent to multiplying by the reciprocal of that fraction. For example, dividing by ⅓ is the same as multiplying by 3 (the reciprocal of ⅓). Similarly, multiplying by ½ is the same as dividing by 2 because ½ is the reciprocal of 2. To multiply fractions, simply multiply the numerators together and the denominators together, simplifying by any common factors as necessary.

Demonstrating this concept through an example, let’s consider the division of 4 by ⅓. First, we find the reciprocal of ⅓, which is 3, and then we multiply 4 by 3 to get 12. Through the multiplication of fractions, if we have ⅛ multiplied by ⅓, we would multiply the numerators (2 and 1) and the denominators (8 and 3), and then simplify the resulting fraction by canceling out any common factors.