Answer: i guess the problem is with P(x) => "x = [tex]x^{2}[/tex]", then P(x) is true if that equality is true, and is false if the equality is false.
so lets see case for case.
a) x = 0, and [tex]0^{2}[/tex] = 0. So p(0) is true.
b) x = 1 and [tex]1^{2}[/tex] = 1, so P(1) is true.
c) x = 2, and [tex]2^{2}[/tex] = 4, and 2 ≠ 4, then P(2) is false.
d) x= -1 and [tex]1^{2}[/tex] = 1, and 1 ≠ -1, so P(-1) is false.
The truth value of P(0) and P(1) is true while the truth value of P(2) and P(-1) is false
The statement is given as:
[tex]x = x^2[/tex]
For P(0), we have:
[tex]0 = 0^2[/tex]
[tex]0 = 0[/tex] --- this is true
For P(1), we have:
[tex]1 = 1^2[/tex]
[tex]1 = 1[/tex] --this is true
For P(2), we have:
[tex]2 = 2^2[/tex]
[tex]2= 4[/tex] -- this is false
For P(-1), we have:
[tex](-1) = (-1)^2[/tex]
[tex](-1) = 1[/tex] --- this is false
Hence, the truth value of P(0) and P(1) is true while the truth value of P(2) and P(-1) is false
Read more about truth values at:
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Show that 2 - sqrt(2) is irrational
Answer:
This proof can be done by contradiction.
Let us assume that 2 - √2 is rational number.
So, by the definition of rational number, we can write it as
[tex]2 -\sqrt{2} = \dfrac{a}{b}[/tex]
where a & b are any integer.
⇒ [tex]\sqrt{2} = 2 - \dfrac{a}{b}[/tex]
Since, a and b are integers [tex]2 - \dfrac{a}{b}[/tex] is also rational.
and therefore √2 is rational number.
This contradicts the fact that √2 is irrational number.
Hence our assumption that 2 - √2 is rational number is false.
Therefore, 2 - √2 is irrational number.
By assuming 2 - √2 is rational and showing this leads to a contradiction as both a and b would have to be even, which violates the initial condition that they have no common factors other than 1, it has been proven that 2 - √2 is irrational.
To show that 2 - √2 is irrational, we shall assume the opposite, that 2 - √2 is rational, and look for a contradiction. By definition, if 2 - √2 is rational, it can be expressed as a fraction of two integers, say √2 = a/b, where a and b are integers with no common factors other than 1, and b is not zero.
We can rearrange the equation to obtain √2 = 2 - a/b. Multiplying both sides by b gives us b√2 = 2b - a. Squaring both sides of this equation gives us 2b² = (2b - a)² = 4b² - 4ab + a².
Rearranging to solve for a² gives us a² = 2b², implying that a² is an even number, and hence a must be even. Let's say a = 2k for some integer k. Substituting this back into the equation gives us (2k)² = 2b², which simplifies to 4k² = 2b², and further to 2k² = b². This implies that b² is also even, which means b is even as well.
However, this is a contradiction because we assumed that a and b have no common factors other than 1; yet, we've just shown that both must be even, so they have at least a factor of 2 in common. This contradiction shows that the assumption that 2 - √2 is rational is false, and therefore 2 - √2 must be irrational.
What is the volume of the tank in #1 in ft) if the diameter is measured carefully to be 15.00 ft and the height 62.00 ft?
Answer:
The volume of this tank is [tex]V = 10956.30 ft^{3}[/tex], using [tex]\pi = 3.14[/tex]
Step-by-step explanation:
A tank has the format of a cylinder.
The volume of the cylinder is given by:
[tex]V = \pi r^{2}h[/tex]
In which r is the radius and h is the heigth.
The problem states that the diameter is measured carefully to be 15.00 ft. The radius is half the diameter. So, for this tank
[tex]r = \frac{15}{2} = 7.50[/tex] ft
The height of the tank is 62 ft, so [tex]h = 62[/tex].
The volume of this tank is:
[tex]V = \pi r^{2}h[/tex]
[tex]V = pi*(7.5)^2*62[/tex]
[tex]V = 10956.30 ft^{3}[/tex]
The volume of this tank is [tex]V = 10956.30 ft^{3}[/tex], using [tex]\pi = 3.14[/tex]
the simple interest on the loan. (Round your answer to the nearest cent.)
$875 at 6.85% for 5 years 6 months.
the total amount due for the simple interest loan. (Round your answer to the nearest cent.)
$6400 at 5.3% for 4 years 9 months.
the interest rate on a loan charging $960 simple interest on a principal of $3750 after 8 years.
the term of a loan of $350 at 4.5% if the simple interest is $63.
Answer:
1) $329.66
2) $8011.20
3) 3.2%
4) 4
Step-by-step explanation:
Simple interest formula: I = P*r*t
the simple interest on the loan: $875 at 6.85% for 5 years 6 months
5 years 6 months = 5,5 years
6.85% = 0.0685
I = 875*0.0685*5.5 = 329.66
the total amount due for the simple interest loan: $6400 at 5.3% for 4 years 9 months.
4 years 9 months = 4 + 9/12 = 4 + 0.75 = 4.75
5.3% = 0.053
I = 6400*0.053*4.75 = 1611.20
Total amount due: 6400+1611.20 = 8011.20
the interest rate on a loan charging $960 simple interest on a principal of $3750 after 8 years.
I = 960
P = 3750
t = 8
960 = 3750*r*8
960 = 30000*r
r = 0.032
r = 3.2%
the term of a loan of $350 at 4.5% if the simple interest is $63.
P = 350
r = 4.5% = 0.045
I = 63
t = ?
63 = 350*0.045*t
63 = 15.75*t
t = 4
The probability that a customer's order is not shipped on time is 0.06. A particular customer places three orders, and the orders are placed far enough apart in time that they can be considered to be independent events. Round your answers to four decimal places.
(a) What is the probability that all are shipped on time?
(b) What is the probability that exactly one is not shipped ontime?
(c) What is the probability that two or more orders are not shipped on time?
Answer:
a) There is a 83.06% probability that all orders are shipped on time.
b) There is a 15.90% probability that exactly one order is not shipped ontime.
c) The probability of at least two orders being late is 1.02% + 0.02% = 1.04%.
Step-by-step explanation:
Probability:
What you want to happen is the desired outcome.
Everything that can happen iis the total outcomes.
The probability is the division of the number of possible outcomes by the number of total outcomes.
In our problem, there is:
-A 6% probability that a customer's order is not shipped on time.
-A 94% probability that a customer's order is shipped on time.
We have these following orders:
O1 - O2 - O3.
(a) What is the probability that all are shipped on time?
The probabilities that each order is shipped on time are O1 = 0.94, O2 = 0.94 and O3 = 0.94. So:
[tex]P = (0.94)^{3}[/tex] = 0.8306
There is a 83.06% probability that all orders are shipped on time.
(b) What is the probability that exactly one is not shipped ontime?
The order's can be permutated. What this means? It means that we can have O1 late and O2,03 on time, O2 late and O1,O3 on time and O3 late and O1, O2 on time. We have a permutation of 3 elements(the orders) with 2 and 1 repetitions(2 on time and one late).
The probability that an order is late is:
[tex]P = (0.94)^{2}(0.06)[/tex] = 0.053 for each permutation
Considering the permutations:
[tex]P = 0.053*p^{3}_{2,1} = 0.053\frac{3!}{2!*1!} = 0.053*3 = 0.1590[/tex]
There is a 15.90% probability that exactly one order is not shipped ontime.
(c) What is the probability that two or more orders are not shipped on time?
P = P1 + P2, where P1 is the probability that two orders are late and P3 is the probability that all three orders are late.
P1
Considering the permutations, the probability that two orders are late is:
[tex]P_{1} = p^{3}_{2,1}*(0.94)*(0.06)^{2} = 3*(0.94)*(0.06)^{2} = 0.0102[/tex]
There is a 1.02% probability that two orders are late
P2
[tex]P_{2} = (0.06)^3 = 0.0002[/tex]
There is a 0.02% probability that all three orders are late.
The probability of at least two orders being late is 1.02% + 0.02% = 1.04%.
PLEASE HELP ASAP PLEASE
Choose the equation below that represents the line passing through the point (2, -4) with a slope of one half.
y = one half x + 5
y = one half x − 3
y = one half x − 5
y = one half x + 3
Answer:
The equation that represents the line passing through the point (2, -4) with a slope of one half is
[tex]f(x) = \frac{1}{2}x - 5[/tex]
Step-by-step explanation:
The equation of a line can be described by a first order equation in the following format:
[tex]f(x) = ax + b[/tex]
In which a is the slope of the line.
Solution:
The line slope is [tex]\frac{1}{2}[/tex], so [tex]a = \frac{1}{2}[/tex].
The equation of the line now is:
[tex]f(x) = \frac{1}{2}x + b[/tex]
The problem states that the line passes through the point(2,-4). This means that when x = 2, f(x) = -4
So:
[tex]f(x) = \frac{1}{2}x + b[/tex]
[tex]-4 = \frac{1}{2}*(2) + b[/tex]
[tex]-4 = 1 + b[/tex]
[tex]b = -5[/tex]
So, the equation that represents the line passing through the point (2, -4) with a slope of one half is
[tex]f(x) = \frac{1}{2}x - 5[/tex]
A box holding pennies, nickels and dimes contains thirteen coins with a total value of 83 cents. How many coins of each type are in the box? (These are US coins; a penny is 1 cent, a nickel is 5 cents, and a dime is 10 cents.)
Answer:
The number of pennies,nickels and dimes are (p,n,d)=(3,4,6).
Further explanation:
Given:
A box holding pennies, nickels and dimes contains thirteen coins in a box.
Total value is 83 cents.
Calculation:
Consider p,n and d be the number of pennies, nickel and dimes.
Now, total is 13 coins so [tex]p+n+d=13[/tex]
As we know that these following are US coin.
Penny=1 cent
Nickel=5 cents
Dime=10 cents
Step 1:
The value is already given as 83 cents that is 80+3 cents.
80 cents can be possible in many combinations as follows:
(N,D)=(0,8),(2,7),(4,6),(6,5),(8,4),(10,3),(12,2),(14,1),(16,0)
It is given that the total number of cents is 13 so we choose (4,6) as (n,d) .
So the value of nickel n=4
Dimes d=6
Step 2:
The value of p is calculated as follows:
Substitute 4 for n, 6 for d in equation [tex]p+n+d=13[/tex] as follows:
[tex]p+4+6=13[/tex]
[tex]p+10=13[/tex]
[tex]p=13-10[/tex]
p=3
Thus, the number of pennies,nickels and dimes are (p,n,d)=(3,4,6).
The problem can be represented by two equations based on the total coins and their total value. The number of pennies, nickels, and dimes cannot be precisely determined without extra constraints or assumptions.
Explanation:This problem is about the trio of pennies, nickels, and dimes, and their corresponding values; 1 cent, 5 cents, and 10 cents, respectively. Let's denote the number of pennies as P, nickels as N, and dimes as D.
From the problem, we know two key pieces of information:
There are 13 coins in total. Therefore: P + N + D = 13 The total value of all the coins is 83 cents. So: P(1 cent) + N(5 cents) + D(10 cents) = 83 cents
Mind this information, we'll try to solve it using the system of linear equations method. However, it's impossible to precisely calculate the number of each coin type without additional constraints or assumptions. This math problem is a common example of how real-life situations can pose complex mathematical challenges, requiring more information or advanced techniques of problem solving.
Learn more about Coin Counting here:https://brainly.com/question/12036455
4(8x + 7) = 17x - 8
help!!!
Answer:
x = 2.4 or 12/5 or 2 and 2/5
Step-by-step explanation:
4(8x + 7) = 17x - 8
4 * 8x = 32x
4 * 7 = 28
32x + 28 = 17x - 8
-28 - 28
32x = 17x - 36
-17x -17x
15x = -36
---- ----
15 15
x = 2.4 or 12/5 or 2 and 2/5
Hey!
---------------------------------------------------
Solution:
4(8x + 7) = 17x - 8
32x - 28 = 17x - 8
32x - 28 + 28 = 17x - 8 + 28
32x = 17x + (-36)
32x - 17x = 17x - (36) - 17x
15x = -36
15x/15 = -36/15
x = -36/15 or -12/5
---------------------------------------------------
Answer:
x = -12/5
---------------------------------------------------
Hope This Helped! Good Luck!
How much would you invest today to have $9500 in 8 years if the effective annual rate of interest is 4%?
Suppose that an investment of $5750 accumulates to $11533.20 at the end of 13 years, then the effective annual interest rate is i= ?
At an effective annual rate of interest of 5.3%, the present value of $7425.70 due in t years is $3250. Determine t
Answer:
a) You should invest $6941.90 today.
b) The effective annual interest rate is 11%.
c) t is approximately 6.
Step-by-step explanation:
These are compound interest problems. The compound interest formula is given by:
[tex]A = P(1 + \frac{r}{n})^{nt}[/tex]
Where A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.
a) How much would you invest today to have $9500 in 8 years if the effective annual rate of interest is 4%?
Here, we want to find the value of P when [tex]A = 9500, t = 8, n = 1, r = 0.04[/tex].
[tex]9500 = P(1 + \frac{0.04}{1})^{8}[/tex]
[tex]P = \frac{9500}{1.3685}[/tex]
[tex]P = 6941.90[/tex].
You should invest $6941.90 today.
b) Suppose that an investment of $5750 accumulates to $11533.20 at the end of 13 years, then the effective annual interest rate is i= ?
Here, we have that [tex]A = 11533.20, P = 5750, t = 13, n = 1[/tex], and we want to find the value of i, that is r on the formula above the solutions.
[tex]11533.20 = 5750(1 + r)^{13}[/tex]
[tex]\sqrt[13]{11533.20} = \sqrt[13]{5750(1 + r)^{13}}[/tex]
[tex]2.05 = 1.94(1 + r)[/tex]
[tex]r = 0.11[/tex]
The effective annual interest rate is 11%.
c) At an effective annual rate of interest of 5.3%, the present value of $7425.70 due in t years is $3250. Determine t.
Here, we have that [tex]A = 7425.70 + 3250 = 10675.7, P = 7425.7, r = 0.053, n = 1[/tex] and we have to find t. So
[tex]10675.7 = 7425.7(1 + \frac{0.053}{1})^{t}[/tex]
[tex](1 + 0.053)^{t} = \frac{10675.7}{7425.7}[/tex]
[tex](1.0553)^{t} = 1.4377[/tex]
We have that:
log_{a}a^{n} = n
So
[tex]log_{1.0553} (1.0553)^{t} = log_{1.0553} 1.4377[/tex]
[tex]t = 5.95[/tex]
t is approximately 6.
Mr. Chang wants to retire in 10 years. He deposits $650.00 every three months into his retirement investment account. If the account's interest rate is 7.8% compounded quarterly, how much will he have at the end of 5 years, when 20 quarterly deposits of $650.00 have been made?
Give answer in US dollars and cents rounded to the nearest cent (do NOT enter "$" sign)
Answer:
Mr. Chang will have 15714.90 dollars.
Step-by-step explanation:
p = 650
r = [tex]7.8/4/100=0.0195[/tex]
Number of periods or n = [tex]5\times4=20[/tex]
Future value formula is : [tex]p[\frac{(1+r)^{n}-1}{r} ][/tex]
Putting the values in formula we get;
[tex]650[\frac{(1+0.0195)^{20}-1}{0.0195} ][/tex]
= $15714.90
Hence, Mr. Chang will have 15714.90 dollars.
Evaluate the surface integral ∫∫ F.ds for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation.
F(x,y,z)=xi+yj+5k
S is the coundary of the region enclosed by the cylinder x^2+z^2=1 and the planes y=0 and x+y=2
Use the divergence theorem.
[tex]\vec F(x,y,z)=x\,\vec\imath+y\,\vec\jmath+5\,\vec k\implies\mathrm{div}\vec F(x,y,z)=2[/tex]
By the divergence theorem,
[tex]\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\iiint_R\mathrm{div}\vec F\,\mathrm dV[/tex]
where [tex]R[/tex] is the region with boundary [tex]S[/tex].
Compute the latter integral in cylindrical coordinates, taking
[tex]\begin{cases}x=r\cos\theta\\y=y\\z=r\sin\theta\end{cases}\implies\mathrm dV=r\,\mathrm dr\,\mathrm d\theta\,\mathrm dy[/tex]
[tex]\displaystyle\iint_R2\,\mathrm dV=2\int_0^{2\pi}\int_0^1\int_0^{2-r\cos\theta}r\,\mathrm dy\,\mathrm dr\,\mathrm d\theta=\boxed{4\pi}[/tex]
Show that the sum of two concave functions is concave. Is the product of two concave functions also concave?
Answer with explanation:
Let us assume that the 2 functions are:
1) f(x)
2) g(x)
Now by definition of concave function we have the first derivative of the function should be strictly decreasing thus for the above 2 function we conclude that
[tex]\frac{d}{dx}\cdot f(x)<0\\\\\frac{d}{dx}\cdot g(x)<0[/tex]
Now the sum of the 2 functions is shown below
[tex]y=f(x)+g(x)[/tex]
Diffrentiating both sides with respect to 'x' we get
[tex]\frac{dy}{dx}=\frac{d}{dx}\cdot f(x)+\frac{d}{dx}\cdot g(x)\\\\[/tex]
Since each term in the right of the above equation is negative thus we conclude that their sum is also negative thus
[tex]\frac{dy}{dx}<0[/tex]
Thus the sum of the 2 functions is also a concave function.
Part 2)
The product of the 2 functions is shown below
[tex]h=f(x)\cdot g(x)[/tex]
Diffrentiating both sides with respect to 'x' we get
[tex]h'=\frac{d}{dx}\cdot (f(x)\cdot g(x))\\\\h'=g(x)f'(x)+f(x)g'(x)[/tex]
Now we can see the sign of the terms on the right hand side depend on the signs of the function's themselves hence we remain inconclusive about the sign of the product as a whole. Thus the product can be concave or convex.
An oral liquid concentrate of sertraline hydrochloride (Zoloft) contains 20 mg/mL of the drug. How many grams of sertraline hydrochloride are in each 60-mL container of the concentrate?
Answer:
1.2 grams.
Step-by-step explanation:
We have been given that an oral concentrate of sertraline hydro-chloride (Zoloft) contains 20 mg/mL of the drug.
First of all, we will find number of mg in 60 mL container of the concentrate as:
[tex]\frac{\text{20 mg}}{\text{ml}}\times \text{60 ml}[/tex]
[tex]\text{20 mg}\times 60[/tex]
[tex]\text{1200 mg}[/tex]
We know 1 gram equals 1000 mg.
[tex]\text{1200 mg}\times \frac{\text{1 gram}}{\text{1000 mg}}[/tex]
[tex]1.2\times\text{1 gram}[/tex]
[tex]1.2\text{ grams}[/tex]
Therefore, 1.2 grams of sertraline hydrochloride are in each 60-mL container of the concentrate.
Adam and brianna each made a number pattern. Adam's pattern starts with number 3 and follows rule add 6. What are first four terms of Adam's pattern?
Answer:3 9 15 21
Step-by-step explanation:
3+6=9
9+6=15
15+6=21
or think of it as 3+3+3+3+3+3+3=21
Final answer:
Adam's number pattern starts with 3, and by adding 6 to each previous term, the first four terms are 3, 9, 15, and 21.
Explanation:
The student is asking about creating a number pattern based on a given rule. In this instance, the pattern begins with the number 3, and the rule is to add 6 to the previous term to get the next term. To determine the first four terms of Adam's pattern, we start with the number 3 and repeatedly add 6.
First term: 3 (starting number)
Second term: 3 + 6 = 9
Third term: 9 + 6 = 15
Fourth term: 15 + 6 = 21
Therefore, the first four terms of Adam's number sequence are 3, 9, 15, and 21.
Assume n and m are integers. Prove if m divides n, then m divides -n
Answer: So, if m divides n then n/m = x, and x is integer.
then -n/m = (-1*n)/m = -1*n/m = -1*x = -x.
So if x is integer, -x also is integer, then -n/m is integer and then m divides -n.
Where you used that in the integers set each number a has a opposite (also in the set ) such that a + b= 0, and b = -a = -1*a.
A bag contains three red marbles, three green ones, one lavender one, one How many sets of five marbles include at least two red ones?
Answer: There are 18 sets of five marbles including at least two red ones.
Step-by-step explanation:
Since we have given that
Number of red marbles = 3
Number of green marbles = 3
Number of lavender marbles = 1
total number of marbles = 3+3+1+1 = 8
We need to find the sets of five marbles including at least two red ones.
so, it becomes,
[tex]^3C_2\times ^4C_3+^3C_3\times ^4C_2\\\\=18[/tex]
hence, there are 18 sets of five marbles including at least two red ones.
To determine the total number of sets of five marbles that include at least two red ones, you need to figure out the total number of ways you can choose 5 marbles out of the 8 in the bag, and then calculate combinations for cases with at least 2 red ones and add them up.
Explanation:To determine the total number of sets of five marbles that include at least two red ones, you need to use combinatorics, which is a branch of Mathematics dealing with combinations of objects belonging to a finite set in accordance with certain constraints, such as those posed by questions concerning the possibility of constructing.
Firstly, you need to figure out the total number of ways you can choose 5 marbles out of the 8 in the bag. This is calculated using the combination formula: C(n, k) = n! / [k!(n-k)!]. Where n is the total number of items, and k is the number of items to choose. For this case, n is 8 (total marbles) and k is 5 (marbles we want to choose), so total possible combinations will be C(8, 5).
We want sets that include at least two red marbles, so the sets can have 2, 3 or all red marbles. So, calculate combinations for each case and add them up, like this:
2 Red and 3 Non-Red: C(3, 2) × C(5, 3)3 Red and 2 Non-Red: C(3, 3) × C(5, 2)All red: C(3, 3) × C(5, 0)Learn more about Combinations & Probability here:https://brainly.com/question/3901018
#SPJ3
1. Find the 16-bit computer representation of -2972.
Answer:
-B9C
Step-by-step explanation:
Hi!
Firstly,
1) Start dividing -2972 : 16 = -185 (quotient) *(16) -12 Remainder
2) Do it again! Divide -185 for 16 = -185 / 16 = -11 (quotient) *(16) - 9 Remainder
3) Divide = -11/16 there's no integer result (since it's 0.68) we put it 0*16 -11 (Remainder) = 11
(Since the result gave us a 0 as integer. We had to lower it one unit the Remainder to satisfy the division algorithm which says = a:b=q*b +r,
11 =0*16+11
4) Gathering all Remainders from bottom to top: 12912
Comparing with the Table (below), from the last remainder to the first, and checking it with the table:
Decimal = Hex (multiplying by minus 1 since it's negative):
-11912 =-B9C
A recipe for individual chocolate hazelnut tarts calls for ½ cup of hazelnuts per tart. If 1 cup of hazelnuts weighs 4 ounces, will a 5-kilogram bag of hazelnuts be sufficient to make 75 tarts? 9.
Answer:
The amount is sufficient to make 75 tarts.
Step-by-step explanation:
We have been given that a recipe for individual chocolate hazelnut tarts calls for ½ cup of hazelnuts per tart and 1 cup of hazelnuts weighs 4 ounces.
The half cup of hazelnuts will weigh 2 ounces [tex](\frac{4}{2}=2)[/tex].
1 kg equals 35.274 ounces.
[tex]\text{5 kg}=5\times 35.274\text{ ounces}[/tex]
[tex]\text{5 kg}=176.37\text{ ounces}[/tex]
Since each tart needs ½ cup of hazelnuts and half cup of hazelnuts will weigh 2 ounces, so we will divide 176.37 ounces by 2 to find number of tarts.
[tex]\frac{176.37}{2}=88.185\approx 88[/tex]
Since we can make 88 tarts from 5 kg hazelnuts, therefore, the 5-kilogram bag of hazelnuts be sufficient to make 75 tarts.
Determine whether the quantitative variable is discrete or continuous. Number of students in a class Is the variable discrete or continuous? A. The variable is continuous because it is not countable. B. The variable is discrete because it is not countable. C. The variable is continuous because it is countable. D. The variable is discrete because it is countable.
Answer:
D) The variable is discrete because it is countable.
Step-by-step explanation:
Both discrete and continuous falls under the numeric category.
Discrete variables are the variable that are countable and cannot be expressed in decimal form.
Example: Tosses of a coin, Number of rooms in an house.
Continuous variables on the other hand cannot be counted, they are countable and can be expressed in the form of decimals. Its value can be expressed in the form of interval.
Example: Time, Length.
Now, number of students in a class is a discrete variable since students are countable and they cannot be expressed in decimal form.
So the correct option is D) The variable is discrete because it is countable.
Final answer:
The number of students in a class is a quantitative discrete variable because student numbers are countable and would always be a whole number.
Explanation:
The number of students in a class is a quantitative discrete variable. This is because the number of students can be counted, and would always be a whole number. There is no situation in which you could have a fraction of a student. Discrete random variables like this are countable, as opposed to continuous random variables which result from measurements and can take on any value in a range, including decimals and fractions. For instance, if we were discussing the heights of students, which can vary in continuous increments, we would be talking about a continuous variable.
Therefore, the correct option for the provided question is: D. The variable is discrete because it is countable.
A heavy rainstorm dumps 1.0 cm of rain on a city 4 km wide and 8 km long in a 2-h period. Part A How many metric tons (1 metricton = 103 kg) of water fell on the city? (1 cm3 of water has a mass of 1 gram = 10-3 kg.) Express your answer using o
To find the mass of water that fell on the city, multiply the volume of the rainstorm by the density of water.
Explanation:To calculate the amount of water that fell on the city, we first calculate the volume of water by multiplying the width, length, and height of the rainstorm. Using the given values of 1.0 cm of rain, 4 km wide, and 8 km long, we find that the volume is 1.5 × 1018 m³. Since water has a density of 1 ton per cubic meter, we can calculate the mass by multiplying the volume by the density, which gives us 1.5 × 1018 metric tons.
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Digoxin (Lanoxin) is available for parenteral pediatric use in a concentration of 0.1 mg/mL. How many milliliters would provide a dose of 40 μg?
To give a dose of 40 μg of Digoxin using a solution with a concentration of 0.1 mg/mL, you should administer 0.4 mL of the solution. This is achieved by first converting the dose to the same units as the concentration, then applying the formula: Volume (mL) = Dose (mg) / Concentration (mg/mL).
Explanation:To determine how many milliliters would provide a dose of 40 μg of Digoxin, we first need to convert the dose from μg to mg because the concentration provided is in mg/mL. 1 mg is equivalent to 1000 μg. Hence, 40 μg would be the same as 0.04 mg.
Since the concentration of the Digoxin solution is 0.1 mg/mL, this means that every 1 mL of the solution contains 0.1 mg of Digoxin. Therefore, the volume in milliliters that would provide a dose of 0.04 mg (or 40 μg) can be calculated by the following equation: Volume (mL) = Dose (mg) / Concentration (mg/mL).
In this case, the calculation is: Volume = 0.04 mg / 0.1 mg/mL = 0.4 mL. Therefore, 0.4 mL of the solution will provide a dose of 40 μg of Digoxin.
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To provide a dose of 40 μg using a concentration of 0.1 mg/mL, 2.5 mL of the digoxin solution is needed.
Explanation:To find the volume of digoxin (Lanoxin) needed to provide a dose of 40 μg, we can use the formula:
C₁V₁ = C₂V₂
Given:
C₁ = 0.1 mg/mL (0.1 mg per 1 mL)
C₂ = 40 μg (0.04 mg)
V₂ = ? mL (unknown volume)
Rearranging the formula, we get:
V₂ = (C₁V₁) / C₂
Substituting in the given values:
V₂ = (0.1 mg/mL) / (0.04 mg) = 2.5 mL
Therefore, 2.5 milliliters of the digoxin solution would provide a dose of 40 μg.
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Convert the following pairs of decimal numbers to 5-bit 2's-complement numbers, then add them. State whether or not overflow occurs in each case. (a) 4 and 11 (b) 6 and 14 (c)-13 and 12 (d) -4 and 8 (e) -2 and -9 (f) -9 and -14
Step-by-step explanation:
(a) 4 and 11
binary equivalent of 4 in 5 bit = 00100
binary equivalent of 11 in 5 bit = 01011
decimal number 4 in 2's complement form = 11100
decimal number 11 in 2's complement form = 10101
now,
1 1 1 0 0
+ 1 01 0 1
1 1 000 1
Since, we are doing addition on 5 bit numbers but the result of addition came in 6 digit, so there will be overflow.
(b) 6 and 14
binary equivalent of 6 in 5 bit = 00110
binary equivalent of 14 in 5 bit = 01110
decimal number 6 in 2's complement form = 11010
decimal number 14 in 2's complement form = 10010
now,
1 1 0 1 0
+ 1 00 1 0
1 0 1 1 0 0
Since, we are doing addition on 5 bit numbers but the result of addition came in 6 digit, so there will be overflow.
(c) -13 and 12
binary equivalent of -13 in 5 bit = 10011
binary equivalent of 12 in 5 bit = 01100
decimal number -13 in 2's complement form = 01101
decimal number 12 in 2's complement form = 10100
now,
0 1 1 0 1
+ 1 0 1 0 0
1 0 0 0 0 1
Since, we are doing addition on 5 bit numbers but the result of addition came in 6 digit, so there will be overflow.
(d) -4 and 8
binary equivalent of -4 in 5 bit = 11100
binary equivalent of 8 in 5 bit = 01000
decimal number -4 in 2's complement form = 00100
decimal number 8 in 2's complement form = 11000
now,
0 0 1 0 0
+ 1 1 0 0 0
1 1 1 0 0
Since, we are doing addition on 5 bit numbers and the result of addition also came in 5 digit, so there will not be overflow.
(e) -2 and -9
binary equivalent of -2 in 5 bit = 11110
binary equivalent of -9 in 5 bit = 10111
decimal number -2 in 2's complement form = 00010
decimal number -9 in 2's complement form = 01001
now,
0 0 0 1 0
+ 0 1 0 0 1
0 1 0 1 1
Since, we are doing addition on 5 bit numbers and the result of addition also came in 5 digit, so there will not be overflow.
(f) -9 and -14
binary equivalent of -9 in 5 bit = 10111
binary equivalent of -14 in 5 bit = 10010
decimal number -9 in 2's complement form = 01001
decimal number -10 in 2's complement form = 01110
now,
0 1 0 0 1
+ 0 1 1 1 1
1 1 000
Since, we are doing addition on 5 bit numbers and the result of addition also came in 5 digit, so there will not be overflow.
To convert decimal numbers to 5-bit 2's-complement numbers, convert each number to binary and add them.
Explanation:Conversion to 5-bit 2's-complement numbers:
(a) For 4, convert to binary: 00100. For 11, convert to binary: 01011. Add the binary numbers: 00100 + 01011 = 01111. Since the sum is positive, there is no overflow.
(b) For 6, convert to binary: 00110. For 14, convert to binary: 01110. Add the binary numbers: 00110 + 01110 = 10100. Since the sum is negative, there is overflow.
(c) For -13, convert to binary: 10011. For 12, convert to binary: 01100. Add the binary numbers: 10011 + 01100 = 11111. Since the sum is negative, there is no overflow.
(d) For -4, convert to binary: 11100. For 8, convert to binary: 01000. Add the binary numbers: 11100 + 01000 = 00100. Since the sum is negative, there is overflow.
(e) For -2, convert to binary: 11110. For -9, convert to binary: 10111. Add the binary numbers: 11110 + 10111 = 101001. Since the sum is positive, there is overflow.
(f) For -9, convert to binary: 10111. For -14, convert to binary: 10010. Add the binary numbers: 10111 + 10010 = 110001. Since the sum is negative, there is overflow.
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how to solve this problem step by step (3×4)÷(7+9-10)
Answer:
2
Step-by-step explanation:
1. solve for the multiplication (3x4)= 12
2. solve for (7+9-10) take 7+9 which =16 and then subtract by 10. (16-10=6)
3. take the 12 and divide by 6
To solve the expression (3×4)÷(7+9-10), perform the operations inside the brackets first, then multiply and divide according to BODMAS/BIDMAS rules. The correct answer after simplifying is 2.
Explanation:To solve the problem (3×4)÷(7+9-10), you should follow the steps of BEDMAS/BIDMAS (Brackets, Exponents/Indices, Division and Multiplication, Addition and Subtraction), also known as the order of operations.
Firstly, address the operations within the parentheses. Calculate the sum and difference within the second set of brackets (7+9-10), which simplifies to 6.Next, perform the multiplication within the first set of brackets (3×4), which equals 12.Now you have simplified the original expression to 12÷6.Finally, divide 12 by 6 to get the answer, which is 2.Always remember to check the answer to see if it is reasonable by reviewing your calculation steps.
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The mean weight of an adult is 62 kilograms with a variance of 144.If 195 adults are randomly selected, what is the probability that the sample mean would differ from the population mean by greater than 2.2 kilograms? Round your answer to four decimal places.
Answer:
The probability that the sample mean would differ from the population mean by greater than 2.2 kilograms is 0.0104 .
Step-by-step explanation:
The mean weight of an adult is 62 kilograms with a variance of 144
i.e. [tex]\mu = 62 \\\sigma^2 = 144[/tex]
We are supposed to find probability that the sample mean would differ from the population mean by greater than 2.2 kilograms
i.e. [tex]P(\bar{x}<62-2.2) or P(\bar{x}>62+2.2)=1-P(59.8<\bar{x}<64.2)[/tex]
Using formula : [tex]\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]P(\bar{x}<62-2.2) or P(\bar{x}>62+2.2)=1-P(59.8<\bar{x}<64.2)[/tex]
[tex]P(\bar{x}<62-2.2) or P(\bar{x}>62+2.2)=1-P(\frac{59.8-62}{\frac{12}{\sqrt{195}}}<\frac{64.2-62}{\frac{12}{\sqrt{195}}})[/tex]
[tex]P(\bar{x}<62-2.2) or P(\bar{x}>62+2.2)=1-P(-2.56<z<2.56)[/tex]
[tex]P(\bar{x}<62-2.2) or P(\bar{x}>62+2.2)=1-{P(z<2.56)-P(z<-2.56)}[/tex]
Refer the z table
[tex]P(\bar{x}<62-2.2) or P(\bar{x}>62+2.2)=1-{0.9948-0.0052}[/tex]
[tex]P(\bar{x}<62-2.2) or P(\bar{x}>62+2.2)=0.0104[/tex]
Hence The probability that the sample mean would differ from the population mean by greater than 2.2 kilograms is 0.0104 .
0.0104 or 1.04% is the probability that the sample mean weight of 195 adults will differ from the population mean .
We have to use the central limit theorem.
Given the mean weight (62 kg) and variance (144 kg²) of the population, we first calculate the standard deviation:
Step 1: Calculate the population standard deviation.
Population standard deviation (σ) = √variance = √144 = 12 kg.Step 2: Calculate the standard error of the mean.
Standard error (SE) = σ / √n = 12 / √195 = 12 / 13.9642 ≈ 0.8594 kg.Step 3: Find the z-scores corresponding to ±2.2 kg difference from the mean.
Z = (X - µ) / SEFor X = 62 + 2.2 = 64.2 kg: Z = (64.2 - 62) / 0.8594 ≈ 2.56.For X = 62 - 2.2 = 59.8 kg: Z = (59.8 - 62) / 0.8594 ≈ -2.56.Step 4: Use the standard normal distribution to find the probabilities.
P(Z > 2.56) = 1 - P(Z ≤ 2.56) ≈ 1 - 0.9948 = 0.0052.Similarly, P(Z < -2.56) = 0.0052.Step 5: Calculate the total probability.
P(|X - µ| > 2.2) = P(Z > 2.56) + P(Z < -2.56) ≈ 0.0052 + 0.0052 = 0.0104.Therefore, the probability that the sample mean differs from the population mean by more than 2.2 kg is approximately 0.0104 or 1.04%.
If you roll one die two times, what is the probability of getting a 2 on the first roll and a 2 on the second roll? Show work or explain your reasoning. Copyright2016, The Charles A. Dana Center at the University of Texas at Austin
Answer: [tex]\dfrac{1}{36}[/tex]
Step-by-step explanation:
We know that when two events A and B are independent , then the probability of getting A and B will be :-
[tex]P(A\cap B)=P(A)\times P(B)[/tex]
In a fair dice,total outcomes =6
Number of 2's =1
Then, the probability of getting a 2 =[tex]\dfrac{1}{6}[/tex]
If you roll one die two times, then the probability of getting a 2 on the first roll and a 2 on the second roll will be:-
[tex]\dfrac{1}{6}\times\dfrac{1}{6}=\dfrac{1}{36}[/tex]
Hence, the probability of getting a 2 on the first roll and a 2 on the second roll=[tex]\dfrac{1}{36}[/tex]
Triangles are formed by the intersection of the lines y=x, y 2x, y=-2x, and y=-4. Solve for angles ABC and ABD A D B
Answer and Step-by-step explanation:
To find the angles between the lines, we can use the formula:
tanα = |ms - mr| / | 1 + ms.mr|
where ms and mr are the linear coefficients of the lines you want to find. It always finds the smaller angle formed.
Let's find all the angles from the triangles formed.
y=x ms = 1
y=2x mr = 2
tanα = |1 - 2| / | 1 + 1.2|
tanα = |-1| / | 1 + 2|
tanα = |-1/3|
tanα = 1/3
α = tan⁻¹1/3
α = 18.4°
y=x ms = 1
y=-4 mr = 0
tanα = |1 - 0| / | 1 + 1.0|
tanα = |1| / | 1 + 0|
tanα = |1/1|
tanα = 1
α = tan⁻¹1
α = 45°
y=2x ms = 2
y=-4 mr = 0
tanα = |2 - 0| / | 1 + 2.0|
tanα = |2| / | 1 + 0|
tanα = |2/1|
tanα = 2
α = tan⁻¹2
α = 63.4°
As these 2 lines are in both triangles, the suplement of this angle is also asked, so, 180° - 63.4° = 116.6°
For y=2x and y=-4, it's the same: α = 63.4°
y=2x ms = 2
y=-2x mr = -2
tanα = |2 - (-2)| / | 1 + 2.(-2)|
tanα = |4| / | 1 - 4|
tanα = |4/3|
tanα = 4/3
α = tan⁻¹ 4/3
α = 53.1°
Final answer:
To find angles ABC and ABD in the intersecting lines problem, analyze the slopes of the lines and their intersections.
Explanation:
Triangles can be formed by the intersection of lines with given equations. In this case, the lines are y=x, y= 2x, y=-2x, and y=-4. To find angles ABC and ABD, one must analyze the slopes of these lines and their intersections.
Angle ABC= arctan(∣ m2 −m 1 ∣)
Angle ABC = arctan(∣2−1∣)
Angle ABC = 45 degree
Angle ABD:
This angle is formed by the lines
Angle ABD= arctan (∣m 2 −m 1 ∣)
Angle ABD = arctan(∣−2−1∣)
Angle ABD ≈ 71.57 degree
Suppose that 25 days are chosen at random from a calendar. Explain why at least 3 of the 25 days must lie in the same month. Do some research to find the name of the principle you've used, and clearly describe it in your own words.
Answer:
Step-by-step explanation:
If you have to choose 25 days, you have to think how many months there are.
The year has 12 months, so, if you divide 25 days /12 months =2,08333. (more than 2--> 3)
So if you happen to choose 2 of every month you have 24 days chosen, you have to pick one extra day and will add 3 to the month it belongs.
In any way you choose, you an be sure there is at least one month with 3 or more days chosen.
What is the probability that Saturday is the day after Wednesday?
1
2
1/7
0
0 = 0% probability that Saturday is the day after Wednesday.
---------------------------------------------
A probability is the number of desired outcomes divided by the number of total outcomes.
In this question, we have to consider that:
There are events that are certain to happen, that is, Thursday being the day after Wednesday, which have 1 = 100% probability.There are events that are certain not to happen, that is, Saturday being the day after Wednesday, which have 0 = 0% probability.Thus, 0 = 0% probability that Saturday is the day after Wednesday.
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the correct answer is 1/7.
To determine the probability that Saturday is the day after Wednesday, let's consider the days of the week in order:
1. List the days of the week**: Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday.
2. Identify the position of Wednesday**: Wednesday is the 4th day of the week.
3. Determine the position of Saturday, the day after Wednesday: Saturday is the 6th day of the week.
4. Calculate the probability:
- There are 7 days in total.
- Wednesday is followed by Thursday, Friday, and then Saturday, making Saturday the 6th day after Wednesday.
5. Probability calculation:
- There is only one Saturday in the week.
- Therefore, the probability that Saturday is the day after Wednesday is [tex]\( \frac{1}{7} \).[/tex]
An automobile shop manager timed 27 employees and recorded the time, in minutes, it took them to change a water pump. Assuming normality, use Excel to find the 99% confidence interval for the true mean. Round your answers to three decimal places and use increasing order.
18.4 16.1 19.5 16.5 12.5 17.2 13.8 17.9 19.1 9.8 23.8 18.7 19.1 15.0 19.2 17.0 11.5 15.7 22.5 23.7 19.9 17.6 15.0 17.8 20.7 14.2 15.4
The 99% confidence interval for the true mean time to change a water pump is approximately (14.650, 20.850) minutes, based on the recorded times.
To find the 99% confidence interval for the true mean time it takes to change a water pump, follow these steps in Excel:
Compute the sample mean [tex](\(\bar{x}\))[/tex] using the AVERAGE function and the sample standard deviation (s) using the STDEV.S function for the recorded times.
Calculate the degrees of freedom (n - 1) using the COUNT function to count the number of samples and subtracting 1.
Use the T.INV.2T function to find the critical value for the 99% confidence level with the obtained degrees of freedom.
Compute the margin of error using the formula:
[tex]\(t_{\alpha/2} \times \frac{s}{\sqrt{n}}\)[/tex], where [tex]\(t_{\alpha/2}\)[/tex] is the critical value, s is the sample standard deviation, and n is the sample size.
Determine the confidence interval by subtracting and adding the margin of error to the sample mean.
Round the lower and upper bounds of the confidence interval to three decimal places.
Following these steps, the 99% confidence interval for the true mean time to change a water pump is approximately (14.650, 20.850) minutes based on the given recorded times.
A car is driven for 2 hours at 50 mph and gets 25 miles per gallon: how many miles are driven and how much gas is used?
Answer: 100 miles, 4 gallons used
Step-by-step explanation:
Dist = rate * time = 50 mi/hr * 2 hr = 100 mi
Miles = gallons * miles/gallon. 100 = gallons*25mpg. Gallons = 100/25 = 4
Are the irrational numbers closed under addition?
Answer:
Irrational numbers are not closed under addition.
Step-by-step explanation:
Irrational numbers are the numbers that cannot be expressed in the form of a fraction [tex]\frac{x}{y}[/tex]. In other words we can say that irrational number,s decimal expantion does not cease to end.
The closure property of addition in irrational numbers say that sum of two irrational number is always a rational number, But this is not true. It is not necessary that the sum is always irrational some time it may be rational.
This can be understood with the help of an example:
let (2+√2) and (-√2) be two irrational number. Their sum is (2+√2)+(-√2) = 2, which is clearly a rational number.
Hence, irrational numbers are not closed under addition.