Let x ∼ bin(9, 0.4). find
a. p(x > 6)
b. p(x ≥ 2)
c. p(2 ≤ x < 5)
d. p(2 < x ≤ 5)
e. p(x = 0) f. p(x = 7) g. μx h. σ2 x

Answers

Answer 1
a.
[tex]\mathbb P(X>6)=\mathbb P(X=7)+\mathbb P(X=8)+\mathbb P(X=9)[/tex]
[tex]=\dbinom97(0.4)^7(1-0.4)^{9-7}+\dbinom98(0.4)^8(1-0.4)^{9-8}+\dbinom99(0.4)^9(1-0.4)^{9-9}[/tex]
[tex]\approx0.025[/tex]

b.
[tex]\mathbb P(X\ge2)=1-\mathbb P(X<2)=1-\mathbb P(X=0)-\mathbb P(X=1)[/tex]
[tex]=1-\dbinom90(0.4)^0(1-0.4)^{9-0}-\dbinom91(0.4)^1(1-0.4)^{9-1}[/tex]
[tex]\approx0.929[/tex]

c.
[tex]\mathbb P(2\le X<5)=\mathbb P(X=2)+\mathbb P(X=3)+\mathbb P(X=4)[/tex]
[tex]=\dbinom92(0.4)^2(1-0.4)^{9-2}+\dbinom93(0.4)^3(1-0.4)^{9-3}+\dbinom94(0.4)^4(1-0.4)^{9-4}[/tex]
[tex]\approx0.663[/tex]

d.
[tex]\mathbb P(2<X\le5)=\mathbb P(X=3)+\mathbb P(X=4)+\mathbb P(X=5)[/tex]
[tex]=\dbinom93(0.4)^3(1-0.4)^{9-3}+\dbinom94(0.4)^4(1-0.4)^{9-4}+\dbinom95(0.4)^5(1-0.4)^{9-5}[/tex]
[tex]\approx0.669[/tex]

e.
[tex]\mathbb P(X=0)=\dbinom90(0.4)^0(1-0.4)^{9-0}\approx0.01[/tex]

f.
[tex]\mathbb P(X=7)=\dbinom97(0.4)^7(1-0.4)^{9-7}\approx0.021[/tex]

g, h.
For [tex]X\sim\mathcal B(n,p)[/tex], recall that [tex]\mathbb E[X]=\mu_X=np[/tex] and [tex]\mathbb V[X]={\sigma_X}^2=np(1-p)[/tex]. So

[tex]\mu_X=9(0.4)=3.6[/tex]
[tex]{\sigma_X}^2=9(0.4)(0.6)=2.16[/tex]
Answer 2
Final answer:

The question involves the properties of a binomial distribution with parameters 9 and 0.4. The properties asked can be calculated using binomial theory, allowing the probability of certain outcomes, the mean and variance of the distribution to be found.

Explanation:

The question involves a binomial distribution denoted as x ∼ bin(9, 0.4), where 9 is the total number of trials and 0.4 is the probability of success. The distribution properties desired are:

c. p(2 ≤ x < 5): The probability that x takes a value between 2 and 5, which is found by adding up the probabilities p(x = 2), p(x = 3) and p(x = 4) in the binomial distribution.e. p(x = 0): This is the probability that there are 0 successes, given by (0.6)^9 in this case.f. p(x = 7): The probability of having 7 successes which can be calculated using binomial formula.g. μx: This is the expected value or mean of the distribution, which in binomial distribution is np, so μx = 9 * 0.4 = 3.6.h. σ2 x: This is the variance, calculated as np(1-p), hence σ2x = 9 * 0.4 * (1 - 0.4) = 2.16.

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Related Questions

in fifteen minutes greg sailboat went 3/6 miles, gina sailboat went 6/6 miles, and stuart sailboat went 4/6 miles. whose sailboat went the longest distance in fifteen minutes?

Answers

Gina's did because 6 is bigger than 3 and 4.

A pendulum travels 30 inches on its first swing. During each of its subsequent swings, it travels 90 percent of the previous swing.

Answers

the 90 percent of 30 inches will be 27

Answer:

a1= 30 and r=0.9

Step-by-step explanation:

edge

find the domain of
[tex]f(x) = \frac{ \sqrt{x + 2} }{ {x}^{2} - 25 } [/tex]

Answers

See result as an attachment:

Cheryl paid $3.00 for a pair of socks and eight times as much for a pair of shoes. Her brother Kevin also bought socks and shoes but paid twice as much as Cheryl did for each. How much money did they spend together ?

Answers

They paid $111 all together.
Cheryl: 3 + 8(3) = 3 + 24 = 27

Kevin: 2(3) + 2(24) = 6 + 48 = 54

27 + 54 = 81

They spent $81.00 all together.

y = -16x2 + 32x - 10 This parabola has x-intercepts, representing the times when the dolphin's height above water is feet.

Answers

Answer:

2

0

two real solutions

Step-by-step explanation:

from edge!!

Final answer:

To find the x-intercepts of the quadratic equation representing the height of a dolphin's jump, we can use the quadratic formula by plugging in the coefficients from the equation y = -16x^2 + 32x - 10. The intercepts indicate the times when the dolphin's height above water is zero feet.

Explanation:

The question involves finding the x-intercepts of a quadratic equation, which represent the points where a parabola crosses the x-axis. In this context, the x-intercepts correspond to the times when the dolphin's height above water is 0 feet. To find the x-intercepts, we can use the quadratic formula:

x = −b ± √(b² − 4ac) / (2a)

For the equation y = −16x² + 32x − 10, the coefficients are a = −16, b = 32, and c = −10. By substituting these values into the quadratic formula, we can calculate the times when the dolphin is at the water level (y=0). Since this is a mathematical problem involving a real-world scenario, it is essential to check that the resulting times make sense within the context. Negative values for time, for example, would not be physically meaningful.

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In a line of students ,Jenna is number 8.The teacher says the rule for a number pattern is add4.The first term 7.What number should Jenna say?

Answers

1. You have that the rule for a number pattern is add 4 and the first term is 7.

 2. Let's call "n" to the number in the line where each student is. Then, you can express this as below:

 4n+7

 3. So, you have:

 Student N°1=4(1)+7=11
 Student N°2=4(2)+7=15
 Student N°3=4(3)+7=19
 Student N°4=4(4)+7=23
 Student N°5=4(5)+7=27
 Student N°6=4(6)+7=31
 Student N°7=4(7)+7=35
 Student N°8=4(8)+7=39

 What number should Jenna say?

 The answer is: 39

Cream filled chocolates are $3.59 a pound Billy bought 1/2 pound of vanilla creams what was the cost round your answer

Answers

$1.80, Divide 3.59 by two! There's your answer, your welcome!☺
$1.80, Divide 3.59 by two

This list shows the age at which 43 U.S. Presidents began their terms. 57 61 50 54 54 54 56 54 61 54 48 49 42 51 61 57 68 65 50 51 60 52 57 51 52 47 56 62 69 58 49 56 55 55 43 64 57 64 46 55 51 55 46 Before you can make a frequency table, you need to decide how to set up the age intervals. What is the BEST way to group these ages into six intervals?

Answers

The best way to group these ages into six intervals is from 40-44 to 65-69.

What is a Frequency Distribution Table ?

A frequency distribution table gives an idea about the data point or interval and its frequency.

The age of the Presidents given as

57 61 50 54 54 54 56 54 61 54 48 49 42 51 61 57 68 65 50 51 60 52 57 51 52 47 56 62 69 58 49 56 55 55 43 64 57 64 46 55 51 55 46

The smallest number ( age) is 42 and the largest number (age ) is 69

To make 6 intervals in this gap of 27 , each interval should be of length 5

Therefore the intervals will be

40-44

45-49

50-54

55-59

60-64

65-69

This is the best way to group into intervals.

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Final answer:

The best way to group the ages of U.S. Presidents into six intervals for a frequency table is by intervals of five years each, starting at age 42 and ending at age 71, to cover the entire range and maintain equal width for all intervals.

Explanation:

When grouping ages into intervals for a frequency table, it's best to have intervals that are of equal width and cover the entire range of data without overlap. For the ages of U.S. Presidents starting their terms, which range from 42 to 69, we could divide this range into six intervals in a way that makes sense for this data set.

First, find the range by subtracting the youngest age from the oldest: 69 - 42 = 27. Next, divide this range by the number of desired intervals (6), which gives us 4.5. We can round this to 5 to make the intervals more practical. Thus, each age interval will span 5 years. Starting at 42, the six intervals would be: 42-46, 47-51, 52-56, 57-61, 62-66, and 67-71.

This grouping covers all the ages and each interval is of equal width, making it easy to interpret the frequency table.

What is 30 divided by half plus 10

Answers

30 divided by 2 + 10
15 + 10
25 is your answer. Hope its helps! :)
30 divided by one half plus 10 can be written as 30 ÷ 1/2 + 10. The order of operation (GEMDAS) informs us that we simplify the division first. 30 ÷ 1/2 is the same as 30 times 2. That gives us 60. Then, we add 10 to get 70.

The value of the digit in the hundreds place in the number 653,841 is 1/10 the value of the digit in the thousands place in which number?

Answers

the correct question in the attached figure

we have that
the value of the digit in the hundreds place in the number 653,841 is------> 800

case  A) 748,917
the value of the digit in the thousands place------> 8000
1/10 the value of the digit is-------> (1/10)*8000=800
800=800---------------> is ok

case  B) 749,817
the value of the digit in the thousands place------> 9000
1/10 the value of the digit is-------> (1/10)*9000=900
900 is not 800

case  C) 784,817
the value of the digit in the thousands place------> 4000
1/10 the value of the digit is-------> (1/10)*4000=400
400 is not 800

case  D) 797,481
the value of the digit in the thousands place------> 7000
1/10 the value of the digit is-------> (1/10)*7000=700
700 is not 800

the answer is the option A) 748,917

The answer is 0.5.

To find the answer, understand the place value system in numbers.

The value of the digit in the hundreds place in the number 653,841 is 1/10 the value of the digit in the thousands place in which number.

To find the answer, we need to understand the place value system. In the number 653,841, the digit in the hundreds place is 8, and the digit in the thousands place is 5. Therefore, 1/10 of the digit in the thousands place is 0.5.

So, the answer is 0.5.

Use the diagram of the right triangle above and round your answer to the nearest hundredth. If m
Answer choices:

A) 17.32 m
B) 6.83 m
C) 14 m
D) 9.99 m

Answers

if you use the law of sins, the answer would be B) 6.928 (in the law of sines you round so it would be 6.93)

Answer:

b. 6.93 m.

Step-by-step explanation:

We have been given triangle ABC and we are asked to find the measure of a.

We will use law of sines to solve our given problem.

[tex]\frac{a}{\text{Sin}(A)}=\frac{b}{\text{Sin}(B)}=\frac{c}{\text{Sin}(C)}[/tex], where a, b and c are opposite sides of angle A, B and C respectively.

First of all, we will find the measure of angle B using angle sum property.

[tex]\angle A+\angle B+\angle C=180^{\circ}[/tex]

[tex]30^{\circ}+\angle B+90^{\circ}=180^{\circ}[/tex]

[tex]\angle B+120^{\circ}=180^{\circ}[/tex]

[tex]\angle B=180^{\circ}-120^{\circ}[/tex]

[tex]\angle B=60^{\circ}[/tex]

Upon substituting our given values in law of sines we will get,

[tex]\frac{a}{\text{Sin}(30^{\circ})}=\frac{12}{\text{Sin}(60^{\circ})}[/tex]

[tex]\frac{a}{0.5}=\frac{12}{\frac{\sqrt{3}}{2}}[/tex]

[tex]\frac{a}{0.5}=\frac{2*12}{\sqrt{3}}[/tex]

[tex]\frac{a}{0.5}*0.5=\frac{24}{\sqrt{3}}*0.5[/tex]

[tex]a=\frac{12}{\sqrt{3}}[/tex]

[tex]a=6.9282032302755\approx 6.93[/tex]

Therefore, the value of a is 6.93 meters and option 'b' is the correct choice.

Describe the test grades using the measures of center

Answers

which test grades are you talking about?

Jack purchased a box of 1,000 candy guitar lollipops to sell in the bakery for $20.00. How much did he pay for each lollipop?

Answers

20 divided by 1,000. 
0.02 is the right Anwar

Jeannie's restaurant served 58 customers on Monday. After the first day the amount of customers served decreases at a rate of 2.5% each day.

What is the explicit rule for this situation and approximately how many customers will be served on the 6th day?

Round to the nearest customer.

Drag and drop the answers into the boxes to match the situation.

Explicit rule

Number of customers on the 6th day.

A n = 58 x (0.975) n - 1, A n = 58 x (0.025) n - 1, A n = 58 (1.025) n - 1, 51, 49, 48, 46,

Answers

The rule is to find the percentage then divide

Answer:

51 customers

Step-by-step explanation:

Jeannie's restaurant served 58 customers on Monday.

Rate of decrement  r =2.5 % = 0.025

Formula : [tex]y=a(1-r)^{n-1}[/tex]

A is the initial amount

r is the rate

n is the no. of days

So, Substitute the values

[tex]y=58(1-0.025)^{n-1}[/tex]

[tex]y=58(0.975)^{n-1}[/tex]

So, explicit rule : [tex]A_n=58(0.975)^{n-1][/tex]

Now to find the no. of customers will be served on the 6th day

Substitute n = 6

[tex]A_6=58(0.975)^{6-1}[/tex]

[tex]A_6=51.1035[/tex]

So, 51 customers will be served on the 6th day

Two rectangular prisms have the same volume. The area of the base of the blue prism is 216 square units. The area of the base of the red prism is one third that of the blue prism. Which statement is true?

a) The height of the red prism is one-third the height of the blue prism.

b) The height of the red prism is the same as the height of the blue prism.


c) The height of the red prism is six times the height of the blue prism.


d) The height of the red prism is three times the height of the blue prism.

Answers

V = B*h

Let hb represent the height of the blue prism; let hr represent the height of the red prism.

216*hb = V = (1/3)*(216)*hr
3*hb = hr . . . . . . . . . . . . . . . divide by the coefficient of hr

The 4th selection is appropriate.

Answer:

D

Step-by-step explanation:

4x. (2x^3 — x^2–18x+15) Standard Form

Answers

4x. (2x^3 — x^2–18x+15)=
8x^4 - 4x^3 - 72x^2 + 60x
4x (2x ^ 3 - x ^ 2-18x + 15)
 For this case, the first thing to do is multiply the value of 4x for each of the terms within the parenthesis.
 You must take into account the following power properties:
 Same exponents are added.
 We have then:
 (8x ^ 4 - 4x ^ 3-72x ^ 2 + 60x)
 Answer:
 
The standard form is:
 (8x ^ 4 - 4x ^ 3-72x ^ 2 + 60x)


Choose the graph that represents the time for which the velocity of the ball will be between –90 and –58 ft/s.

Answers

The answer is c because t must be less than 2.5 and more than 1.5.


Find this by separating the inequality into:

-90 < -32t - 10

&

-32t - 10 < -58

Simplify and you get 2.5 and 1.5

Graph (C) represents the time for which the velocity of the ball will be between –90 and –58 ft/s option (C) is correct.

What is a number line?

It is defined as the representation of the numbers on a straight line that goes infinitely on both sides.

We have:

The velocity of the ball will be between –90 and –58 ft/s.

Let v be the velocity of the ball:

v lies between -90 and -58

-90 < v < -58

The above expression represents the inequality:

Or

-90 < -32t - 10

t < 2.5

And

-32t - 10 < -58

t > 1.5

The number line will be:

Open the circle on the number 1.5 and open circle at 2.5 and a line was drawn between this point.

Thus, graph (C) represents the time for which the velocity of the ball will be between –90 and –58 ft/s option (C) is correct.

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8pints compared to 15 cups

Answers

STEP 1:
First we need both in the same unit of measurement.

1 pint= 2 cups

Convert 15 cups to pints:
=15 cups ÷ 2 cups per pint
=7.5 pints

STEP 2:
Find percentage:
=8 pints ÷ 7.5 pints
=1.0666 decimal percent of 8 pints

STEP 3:
Convert to %:
=1.06666 x 100
=106.66% percent 8 is of 7.5 pints

*TIP: if you know you're changing to a percentage from a decimal, you will always move the decimal two places to the right.

ANSWER:
8 pints is 106.66% of 7.5 pints.

Hope this helps! :)

if c is the incenter of AMD, AMC=3x+6 AND dmc = 8X-49, FIND EACH MEASURE

Answers

3x+6=8x-49,
-6. -6
__________
3x=8x-55
-8x. -8x
________
-5x=-55
x=11,
3(11)+6=39
8(11)-49=39

Answer:

[tex]m\angle AMC = 39\°[/tex] and [tex]m\angle DMC = 39\°[/tex].

Step-by-step explanation:

As you can observe in the image attached, angles AMC and DMC are congruent, because if point C is the incenter of AMD, that means each line the forms such point is a bisector.

Remember that a bisector is a line that equally divides an angle.

So,

[tex]\angle AMC = \angle DMC\\3x+6=8x-49[/tex]

Solving for [tex]x[/tex], we have

[tex]6+49=8x-3x\\5x=55\\x=11[/tex]

Then, we substitute this value in each expression to find the angles.

[tex]\angle AMC = 3x+6 = 3(11)+6=33+6=39[/tex]

[tex]\angle DMC = 8(11)-49=88-49=39[/tex]

Therefore, the measures of those angles are [tex]m\angle AMC = 39\°[/tex] and [tex]m\angle DMC = 39\°[/tex].

Find the fifth term of A n = 2n

Answers

[tex] A_n = 2n [/tex]

Let n = 5.

[tex] A_5 = 2(5) = 10 [/tex]

Box i contains 4 red and 8 blue marbles while box ii contains 5 red and 3 blue marbles. an unfair coin is tossed –whose probability of turning up heads is 40%. if the coin comes up heads box i is chosen and a random marble is chosen, otherwise if it is tails the marble is chosen from box ii.(a)find the probability a red marble is chosen.(b)if a red marble is chosen, what is the probability it came from box i? (c)if a blue marble is chosen, what is the probability it came from box i?

Answers

Denote by [tex]B_1,B_2[/tex] the event that a marble is drawn from box 1 or 2, respectively, and by [tex]R[/tex] the event that a red marble is drawn. If a blue marble is drawn, we'll denote that by the complement of [tex]R[/tex], or [tex]R^C[/tex].

a. If a red marble is drawn, either it's drawn from box 1 or box 2. The events [tex]B_1[/tex] and [tex]B_2[/tex] are mutually exclusive, so we have

[tex]\mathbb P(R)=\mathbb P((R\cap B_1)\cup(R\cap B_2))=\mathbb P(R\cap B_1)+\mathbb P(R\cap B_2)[/tex]

Now invoke the definition of conditional probability:

[tex]\mathbb P(R)=\mathbb P(B_1)\mathbb P(R\mid B_1)+\mathbb P(B_2)\mathbb P(R\mid B_2)[/tex]

We're explicitly given the probability of drawing from either box. We also know the probabilities of drawing a red marble from box 1 or 2 are, respectively,

[tex]\mathbb P(R\mid B_1)=\dfrac{\dbinom41\dbinom80}{\dbinom{12}1}=\dfrac4{12}=\dfrac13[/tex]

and

[tex]\mathbb P(R\mid B_2)=\dfrac{\dbinom51\dbinom30}{\dbinom81}=\dfrac58[/tex]

So

[tex]\mathbb P(R)=\dfrac25\times\dfrac13+\dfrac35\times\dfrac58=\dfrac{61}{120}\approx0.508[/tex]

b. Given that we draw a red marble, we're looking for the probability that it was drawn from box 1, i.e. [tex]\mathbb P(B_1\mid R)[/tex]. We use Bayes' theorem:

[tex]\mathbb P(B_1\mid R)=\dfrac{\mathbb P(B_1\cap R)}{\mathbb P(R)}=\dfrac{\mathbb P(B_1)\mathbb P(R\mid B_1)}{\mathbb P(R)}[/tex]

which is really just a matter of using the definition of conditional probability to rewrite the numerator on the the right side, as

[tex]\mathbb P(R\cap B_1)=\mathbb P(R)\mathbb P(B_1\mid R)=\mathbb P(B_1)\mathbb P(R\mid B_1)[/tex]

We know [tex]\mathbb P(R)[/tex] from part (a), so we compute

[tex]\mathbb P(B_1\mid R)=\dfrac{\dfrac25\times\dfrac13}{\dfrac{61}{120}}=\dfrac{16}{61}\approx0.262[/tex]

c. Now we look for [tex]\mathbb P(B_1\mid R^C)[/tex], which can be computed similarly.

[tex]\mathbb P(B_1\mid R^C)=\dfrac{\mathbb P(B_1\cap R^C)}{\mathbb P(R^C)}=\dfrac{\mathbb P(B_1)\mathbb P(R^C\mid B_1)}{1-\mathbb P(R)}[/tex]
[tex]\mathbb P(B_1\mid R^C)=\dfrac{\dfrac25\times\dfrac23}{1-\dfrac{61}{120}}=\dfrac{32}{59}\approx0.542[/tex]

Write the epxressions for the equivalent capacitance of two capacitors write your answers in terms of c1 and c2

Answers

Connected in series:
.. Ceq = (C1*C2)/(C1 +C2)

Connected in parallel:
.. Ceq = C1 +C2

Brent was looking at his cell phone bill and saw that the total number of texts he has sent is tracked, as shown below:


Month
Texts
1
120
2
237
3
354
4
471


The function representing Brent's texting per month is f(m) = 117m + 3. What does the 117 represent?

Answers

It should be the additional texts per month or D

Answer:

The number of texts he sends per month

Step-by-step explanation:

The function f(m) = 117m + 3 is a linear function, which is in the form f(x) = mx+b.  In this form, m (the number beside our variable) is the slope, or rate of change, and b (the number added or subtracted) is the y-intercept.

In our function, 117 is the number beside the variable, which makes it the slope.  This is the rate of change of this function; it describes how the dependent variable (number of texts) changes for every change in the independent variable (months).  

In other words, it tells how many texts he sends per month.

Noah makes ceramic pots for the market. On the weekends he makes 11 more pots than he does during the week. Noah represented the number of pots he makes on weekends using the expression p + 11. Which expression represents the total mumber of pots Noah made one weekend if he made 14 more than his usual number?

Answers

Answer:
number of pots = p + 25

Explanation:
On weekends, Noah makes 11 pots more than the normal weekdays.
We are given that the equation representing the number of pots is:
number of pots = p + 11
Now, Noah made 14 pots more that his usual numbers, this means that we will add 14 to the usual number of pots that he makes.
Therefore, the equation will become:
number of pots = p + 14 + 11
number of pots = p + 25

Hope this helps :)

The range of F(x) = 6 * 3x is all positive real numbers.

Answers

yes it isssss !!!!!!!!!!!!!

John always wears a shirt, pants, socks, and shoes. He owns 12 pairs of socks, 3 pairs of shoes, 5 pairs of pants, and 5 shirts. How many different outfits can John make?

Answers

12 x 3 x 5 x 5 = 900 different outfits

Answer:

900

Step-by-step explanation:

Khan academy

Given a circle with a diameter of 4, which equation expresses π as the ratio of the circumference of a circle to its diameter?

Answers

4*pi=C
is the formula (d*pi=C)

C /4  = π


Took the test myself, this is the answer.

Tickets for the movies are $7 for adults and $4 for children. Fourteen people paid a total of $68 for tickets. How many were adults and how many were children?

Answers

so let a=adults tickdts and c=children tickets
7a+4c=68
sincr it was 14 ppl,
let a+c=14
so, system of equations.
multiply a+c= 14 all by 4 to get
4a+4c=56 subtract this from the other
7a+4c=68
-3a=-12
a=4
plug in to either. for a
4+c=14
c=10
plug into other equation to check.
7(4)+4(10)=68
28+40=68
28 plus 40=68 is how many adults and children

A fourth as much as the product of two thirds and 0.8

Answers

To answer this, you need to understand how to represent this using math symbols.

The product of is the answer to a multiplication problem, so it would be 2/3 x 0.8. One fourth of this means that we are finding that part of the answer. To show this we would multiply 1/4 by that answer. Please see the attached picture for the written out problem and the work. The answer is 2/15.

A fourth as much as the product of two thirds and 0.8 is ²/₁₅

Further explanation

Order of Operations in Mathematics follow this following rule :

ParenthesesExponentsMultiplication and DivisionAddition and Subtraction

This rule is known as the PEMDAS method.

In working on a mathematical problem, we first calculate operation that is in parentheses, follow by exponentiation, then multiplication or division, and finally addition or subtraction.

Let us tackle the problem !

First, we will translate this word problem into a mathematical equation.

The product of two thirds and 0.8

[tex]\frac{2}{3} \times 0.8[/tex]

A fourth as much as the product of two thirds and 0.8

[tex]\frac{1}{4} (\frac{2}{3} \times 0.8)[/tex]

[tex]= \frac{1}{4} (\frac{2}{3} \times \frac{4}{5})[/tex]

[tex]= \frac{1}{4} (\frac{2 \times 4}{3 \times 5})[/tex]

[tex]= \frac{1}{4} (\frac{8}{15})[/tex]

[tex]= \frac{1}{4} \times \frac{8}{15}[/tex]

[tex]= \frac{1 \times 8}{4 \times 15}[/tex]

[tex]= \frac{8}{60}[/tex]

[tex]= \frac{8 \div 4}{60 \div 4}[/tex]

[tex]= \boxed {\frac{2}{15}}[/tex]

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Answer details

Grade: Middle School

Subject: Mathematics

Chapter: Percentage

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point , Multiplication , Division , Exponent , PEMDAS , percentange , percent

Which multiplication expression that does not belong based on scaling. Explain.

Choose an expression


6 x 2 1/2

6 x 3 3/5

1/2 x 6

2 2/5 x 6


Answers

1/2 x 6 i believe because its the most shortest one in math

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