Answer:
x=200 Minutes
Step-by-step explanation:
Using the given information, we can set up slope equations for each set of numbers. Plan A has an equation of y=.05x+30. Plan B has an equation of y=.1x+20. These plans both equal y, so they can be made equal to each other. This looks like .05x+30=.1x+20. Subtract 20 from each side to aid in getting x by itself. This will look like .05x+10=.1x. Subtract .05x from each side to get all the x's to one side. This looks like .05x=10. Divide by .05 to get x. 10/.05=200. This shows how many minutes it takes for the plans to cost the same.
The equations 3x-4y=-2, 4x-y=4, 3x+4y=2, and 4x+y=-4 are shown on a graph.
Which is the approximate solution for the system of equations 3x+4y=2 and 4x+y=-4?
A. (–1.4, 1.5)
B. (1.4, 1.5)
C. (0.9, –0.2)
D. (–0.9, –0.2)
i cant download the graph picture but please help.
Answer:
A (-1,4,1.5)
Step-by-step explanation:
Solve by graphing, the lines intersect near this point.
Question 7 (5 points)
Find the first five terms of the sequence in which a1 =-10 and an = 4an - 1 + 7. if n
2.
Answer:
-10, -33, -125, -493, -1965
Step-by-step explanation:
a_1 = -10
a_n = 4a_(n - 1) + 7
The first five terms of the sequence are
a_1 = -10
a_2 = 4(-10) + 7 = -40 + 7 = -33
a_3 = 4(-33) + 7 = -132 + 7 = -125
a_4 = 4(-125) + 7 = -500 + 7 = -493
a_5 = 4(-473) + 7 = -1972 + 7 = -1965
write a point slope equation for the line that has slope 3 and passes through the point (5,21). do not use parenthesis on the y side
Answer:
y - 21 = 3(x - 5)
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
here m = 3 and (a, b) = (5, 21), hence
y - 21 = 3(x - 5) ← in point- slope form
The point slope form of an equation is y - y1 = m(x - x1). Substituting the given point (5,21) and slope 3 into the equation, we get y - 21 = 3(x - 5). To remove the parenthesis on the y side, we simplify the equation to be y = 3x + 6.
Explanation:The question asks for the writing of a point-slope equation of a line with a given slope of 3 that passes through a point (5,21). The point-slope form of an equation is generally denoted as:
y - y1 = m(x - x1)
Here, (x1, y1) = (5,21) and m (slope) = 3. Hence, substituting these values yields the equation:
y - 21 = 3(x - 5)
The asked equation without parenthesis on the y side would be:
y = 3x - 15 + 21
So, the final equation is:
y = 3x + 6
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What expression can be used to find 75% of 60%?
Answer:
The expression used to find of 75 and 60 is 45.
Step-by-step explanation:
To find expression of 75 and 60, multiply decimals from left to right.
0.75*0.60=0.45 =45%
.75*.60=.45=45
45=45
True
45, which is our answer.
Evaluate the function rule for the given value. y = 15 • 3^x for x = –3
Answer:
5/9
Step-by-step explanation:
y = 15 • 3^x
Let x = -3
y = 15 • 3^(-3)
The negative means the exponent goes to the denominator
y = 15 * 1/3^3
= 15 * 1/27
=15/27
Divide the top and bottom by 3
=5/9
what is the area of the sector shown
Answer:
[tex] D.~ 34.2~cm^2 [/tex]
Step-by-step explanation:
An arc measure of 20 degrees corresponds to a central angle of 20 degrees.
Area of sector of circle
[tex] area = \dfrac{n}{360^\circ}\pi r^2 [/tex]
where n = central angle of circle, and r = radius
[tex] area = \dfrac{20^\circ}{360^\circ}\pi (14~cm)^2 [/tex]
[tex] area = \dfrac{1}{18}(3.14159)(196~cm^2) [/tex]
[tex] area = 34.2~cm^2 [/tex]
How is the interquartile range calculated?
Minimum
Q1
Q1
Median
Median
Q3
Q3
Maximum
Maximum
Answer:
A
Step-by-step explanation:
The interquartile range is the difference between the upper quartile and the lower quartile, that is
interquartile range = [tex]Q_{3}[/tex] - [tex]Q_{1}[/tex]
The interquartile range (IQR) represents the spread of the middle 50 percent of a data set and is calculated by subtracting the first quartile (Q1) from the third quartile (Q3). It also helps in identifying potential outliers in the data.
Explanation:The interquartile range (IQR) is a measure of statistical dispersion, which is the spread of the middle 50 percent of a data set. It is calculated by subtracting the first quartile (Q1) from the third quartile (Q3). To elaborate:
If, for example, Q1 is 2 and Q3 is 9, the IQR is calculated as 9 minus 2, resulting in an IQR of 7.
In addition to providing insight into the spread of the central portion of the data set, the IQR can also be used to identify potential outliers. These are values that fall more than 1.5 times the IQR above Q3 or below Q1.
Consider the function represented by 9x+3y= 12 with x as the independent variable. How can this function be written using
function notation?
o AV=-=x+
o 0) = -3x+4
o Px) =-x+
o F) = - 3y+ 4
Answer:
f(x)=-3x+4
(can't see some of your choices)
Step-by-step explanation:
We want x to be independent means we want to write it so when we plug in numbers we can just choose what we want to plug in for x but y's value will depend on our choosing of x.
So we need to solve for y.
9x+3y=12
Subtract 9x on both sides
3y=-9x+12
Divide both sides by 3:
y=-3x+4
Replace y with f(x).
f(x)=-3x+4
Match the identities to their values taking these conditions into consideration sinx=sqrt2 /2 cosy=-1/2 angle x is in the first quadrant and angle y is in the second quadrant. Information provided in the picture. PLEASE HELP
Answer:
[tex]\boxed{\vphantom{\dfrac{\sqrt{2}}{2}}\quad \cos(x+y)\quad }\longleftrightarrow \boxed{\quad \dfrac{-(\sqrt{6}+\sqrt{2})}{4}\quad }[/tex]
[tex]\boxed{\vphantom{\dfrac{\sqrt{2}}{2}}\quad \sin(x+y)\quad }\longleftrightarrow \boxed{\quad\dfrac{\sqrt{6}-\sqrt{2}}{4}\quad }[/tex]
[tex]\boxed{\quad \tan(x+y)\quad }\longleftrightarrow \boxed{\quad\sqrt{3} -2\quad }[/tex]
[tex]\boxed{\vphantom{\sqrt{3}}\quad \tan(x-y)\quad }\longleftrightarrow \boxed{\quad-(2+\sqrt{3})\quad }[/tex]
Step-by-step explanation:
To find the values of the given trigonometric identities, we first need to find the values of cos x and sin y using the Pythagorean identity, sin²x + cos²x ≡ 1.
Given values:
[tex]\sin x = \dfrac{\sqrt{2}}{2}\qquad \textsf{Angle $x$ is in Quadrant I}\\\\\\\cos y=-\dfrac{1}{2}\qquad \textsf{Angle $y$ is in Quadrant II}[/tex]
Find cos(x):
[tex]\sin^2 x+\cos^2 x=1\\\\\\\left(\dfrac{\sqrt{2}}{2}\right)^2+\cos^2 x=1\\\\\\\dfrac{1}{2}+\cos^2 x=1\\\\\\\cos^2 x=1-\dfrac{1}{2}\\\\\\\cos^2 x=\dfrac{1}{2}\\\\\\\cos x=\pm \sqrt{\dfrac{1}{2}}\\\\\\\cos x=\pm \dfrac{\sqrt{2}}{2}[/tex]
As the cosine of an angle is positive in quadrant I, we take the positive square root:
[tex]\cos x=\dfrac{\sqrt{2}}{2}[/tex]
Find sin(y):
[tex]\sin^2 y + \cos^2 y = 1 \\\\\\ \sin^2 y + \left(-\dfrac{1}{2}\right)^2 = 1 \\\\\\ \sin^2 y + \dfrac{1}{4} = 1 \\\\\\ \sin^2 y = 1-\dfrac{1}{4} \\\\\\ \sin^2 y = \dfrac{3}{4} \\\\\\ \sin y =\pm \sqrt{ \dfrac{3}{4}} \\\\\\ \sin y = \pm \dfrac{\sqrt{3}}{2}[/tex]
As the sine of an angle is positive in quadrant II, we take the positive square root:
[tex]\sin y = \dfrac{\sqrt{3}}{2}[/tex]
The tangent of an angle is the ratio of the sine and cosine of that angle. Therefore:
[tex]\tan x=\dfrac{\sin x}{\cos x}=\dfrac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}}=1[/tex]
[tex]\tan y=\dfrac{\sin y}{\cos y}=\dfrac{\frac{\sqrt{3}}{2}}{-\frac{1}{2}}=-\sqrt{3}[/tex]
Now, we can use find the sum or difference of two angles by substituting the values of sin(x), cos(x), sin(y), cos(y), tan(x) and tan(y) into the corresponding formulas.
[tex]\dotfill[/tex]
cos(x + y)[tex]\cos(x+y)=\cos x \cos y - \sin x \sin y \\\\\\ \cos(x+y)=\left(\dfrac{\sqrt{2}}{2}\right) \left(-\dfrac{1}{2}\right) - \left(\dfrac{\sqrt{2}}{2}\right) \left(\dfrac{\sqrt{3}}{2}\right) \\\\\\ \cos(x+y)=-\dfrac{\sqrt{2}}{4} - \dfrac{\sqrt{6}}{4} \\\\\\ \cos(x+y)=\dfrac{-\sqrt{2}-\sqrt{6}}{4} \\\\\\ \cos(x+y)=\dfrac{-(\sqrt{2}+\sqrt{6})}{4} \\\\\\ \cos(x+y)=\dfrac{-(\sqrt{6}+\sqrt{2})}{4}[/tex]
[tex]\dotfill[/tex]
sin(x + y)[tex]\sin(x+y)=\sin x \cos y + \cos x \sin y \\\\\\\sin(x+y)=\left(\dfrac{\sqrt{2}}{2}\right) \left(-\dfrac{1}{2}\right) + \left(\dfrac{\sqrt{2}}{2}\right) \left(\dfrac{\sqrt{3}}{2}\right) \\\\\\\sin(x+y)=-\dfrac{\sqrt{2}}{4} + \dfrac{\sqrt{6}}{4} \\\\\\ \sin(x+y)=\dfrac{-\sqrt{2}+\sqrt{6}}{4} \\\\\\ \sin(x+y)=\dfrac{\sqrt{6}-\sqrt{2}}{4}[/tex]
[tex]\dotfill[/tex]
tan(x + y)[tex]\tan(x+y)=\dfrac{\tan x + \tan y}{1-\tan x \tan y} \\\\\\ \tan(x+y)=\dfrac{1 + (-\sqrt{3})}{1-(1) (-\sqrt{3})} \\\\\\ \tan(x+y)=\dfrac{1 -\sqrt{3}}{1+\sqrt{3}} \\\\\\ \tan(x+y)=\dfrac{(1 -\sqrt{3})(1 -\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})} \\\\\\ \tan(x+y)=\dfrac{1-2\sqrt{3}+3}{1-\sqrt{3}+\sqrt{3}-3} \\\\\\ \tan(x+y)=\dfrac{4-2\sqrt{3}}{-2} \\\\\\ \tan(x+y)=-2+\sqsrt{3} \\\\\\ \tan(x+y)=\sqrt{3} -2[/tex]
[tex]\dotfill[/tex]
tan(x - y)[tex]\tan(x-y)=\dfrac{\tan x - \tan y}{1+\tan x \tan y} \\\\\\\tan(x-y)=\dfrac{1 - (-\sqrt{3})}{1+(1) (-\sqrt{3})} \\\\\\\tan(x-y)=\dfrac{1 +\sqrt{3}}{1-\sqrt{3}} \\\\\\\tan(x-y)=\dfrac{(1 +\sqrt{3})(1 +\sqrt{3})}{(1-\sqrt{3})(1+\sqrt{3})} \\\\\\ \tan(x-y)=\dfrac{1+2\sqrt{3}+3}{1+\sqrt{3}-\sqrt{3}-3} \\\\\\ \tan(x-y)=\dfrac{4+2\sqrt{3}}{-2} \\\\\\ \tan(x-y)=-2-\sqrt{3}\\\\\\\tan(x-y)=-(2+\sqrt{3})[/tex]
If 47400 dollars is invested at an interest rate of 7 percent per year, find the value of the investment at the end of 5 years for the following compounding methods, to the nearest cent.
(a) Annual: $______
(b) Semiannual: $ _____
(c) Monthly: $______
(d) Daily: $_______
Answer:
Part A) Annual [tex]\$66,480.95[/tex]
Part B) Semiannual [tex]\$66,862.38[/tex]
Part C) Monthly [tex]\$67,195.44[/tex]
Part D) Daily [tex]\$67,261.54[/tex]
Step-by-step explanation:
we know that
The compound interest formula is equal to
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
Part A)
Annual
in this problem we have
[tex]t=5\ years\\ P=\$47,400\\ r=0.07\\n=1[/tex]
substitute in the formula above
[tex]A=47,400(1+\frac{0.07}{1})^{1*5}[/tex]
[tex]A=47,400(1.07)^{5}[/tex]
[tex]A=\$66,480.95[/tex]
Part B)
Semiannual
in this problem we have
[tex]t=5\ years\\ P=\$47,400\\ r=0.07\\n=2[/tex]
substitute in the formula above
[tex]A=47,400(1+\frac{0.07}{2})^{2*5}[/tex]
[tex]A=47,400(1.035)^{10}[/tex]
[tex]A=\$66,862.38[/tex]
Part C)
Monthly
in this problem we have
[tex]t=5\ years\\ P=\$47,400\\ r=0.07\\n=12[/tex]
substitute in the formula above
[tex]A=47,400(1+\frac{0.07}{12})^{12*5}[/tex]
[tex]A=47,400(1.0058)^{60}[/tex]
[tex]A=\$67,195.44[/tex]
Part D)
Daily
in this problem we have
[tex]t=5\ years\\ P=\$47,400\\ r=0.07\\n=365[/tex]
substitute in the formula above
[tex]A=47,400(1+\frac{0.07}{365})^{365*5}[/tex]
[tex]A=47,400(1.0002)^{1,825}[/tex]
[tex]A=\$67,261.54[/tex]
The value of an investment of $47,400 at an interest rate of 7% per year was calculated at the end of 5 years for different compounding methods, reaching slightly different amounts, with the highest value obtained through daily compounding.
The value of the investment at the end of 5 years for different compounding methods would be:
(a) Annual: $62,899.68(b) Semiannual: $63,286.83(c) Monthly: $63,590.92(d) Daily: $63,609.29Isabel is on a ride in an amusement park that Slidez the right or to the right and then it will rotate counterclockwise about its own center 60° every two seconds how many seconds pass before Isabel returns to her starting position
Final answer:
Isabel's ride rotates 60° every two seconds. It takes 6 intervals (360° divided by 60°) to make a full rotation. Multiplying 6 intervals by 2 seconds gives us 12 seconds for Isabel to return to the starting position.
Explanation:
To determine how many seconds will pass before Isabel returns to her starting position on the ride, we need to establish the total degrees of rotation that equate to a full circle, which is 360°. Since the ride rotates 60° every two seconds, we can calculate the number of two-second intervals required to complete a full 360° rotation.
Firstly, divide 360° by 60° to find the number of intervals:
360° / 60° = 6 intervals
Since each interval takes 2 seconds, multiply the number of intervals by 2 to find the total time:
6 intervals × 2 seconds/interval = 12 seconds.
Therefore, it will take Isabel 12 seconds to return to her starting position on the amusement park ride.
Write a function rule based on the table below.
x f(x)
1 5
2 10
3 15
f(x) = x + 4
f(x) = 5x + 2
f(x) = 5x
f(x) = 5
Answer:
[tex]\large\boxed{f(x)=5x}[/tex]
Step-by-step explanation:
[tex]\begin{array}{c|c}x&f(x)\\1&5\\2&10\\3&15\end{array}\\\\\\f(1)=5(1)=5\\f(2)=5(2)=10\\f(3)=5(3)=15\\\Downarrow\\f(x)=5x[/tex]
plz help meh wit dis question but I need to show work.....
Answer:
5
Step-by-step explanation:
16+24
--------------
30-22
Complete the items on the top of the fraction bar
40
----------
30-22
Then the items under the fraction bar
40
------------
8
Then divide
5
Step-by-step explanation:
First of all, solve the numerator.
16+24=40
Secondly, solve the denominator:
30-22 = 8
So now the fraction appear like this :
[tex] \frac{40}{8} [/tex]
40/8 = 5
a) 3(2x + 3) = -3 (-30 +4)
Answer:
3(2x+3)=-3(-30+4)
6x+9=90+12
6x+9=102
6x=93
x=15.5
-please mark as brainliest-
Answer:
11½ = x
Step-by-step explanation:
6x + 9 = 78
- 9 - 9
-------------
6x = 69 [Divide by 6]
x = 11½ [3⁄6 = ½]
I hope this helps you out, and as always, I am joyous to assist anyone at any time.
1. Factor each of the following completely. Look carefully at the structure of each quadratic function and consider the best way to factor. Is there a GCF? Is it an example of a special case? SHOW YOUR WORK
Answer: 1) (x - 7)(x - 8)
2) 2x(2x-7)(x + 2)
3) (4x + 7)²
4) (9ab² - c³)(9ab² + c³)
Step-by-step explanation:
1) x² - 15x + 56 → use standard form for factoring
∧
-7 + -8 = -15
(x - 7) (x - 8)
************************************
2) 4x³ - 6x² - 28x → factor out the GCF (2x)
2x(2x² - 3x - 14) → factor using grouping
2x[2x² + 4x - 7x - 14]
2x[ 2x(x + 2) -7(x + 2)]
2x(2x - 7)(x + 2)
*************************************
3) 16x² + 56x + 49 → this is the sum of squares
√(16x²) = 4x √(49) = 7
(4x + 7)²
******************************************************
4) 81a²b⁴ - c⁶ → this is the difference of squares
√(81a²b⁴) = 9ab² √(c⁶) = c³
(9ab² - c³)(9ab² + c³)
Which of the following is a geometric sequence? Help pleaseee!
Answer: B
Step-by-step explanation:
Division of components are consistent - the same
Answer:
B. -3, 3, -3, 3...
Step-by-step explanation:
There's two types of sequences, arithmetic and geometric.
Arithmetic equations are sequences that increase or decrease by adding or subtracting the previous number.
For example, take a look at the following sequence:
2, 4, 6, 8, 10, 12, 14, 16, 18, 20...
Here, the numbers are increasing by +2. [adding]
So, this the sequence is arithmetic, since its adding.
Geometric sequences are sequences that increase or decrease by multiplying or dividing the previous number.
For example, take a look at the following sequence:
2, 4, 16, 32, 64, 128, 256, 512...
Here, the numbers are icnreasing by x2. [multiplying]
So, the sequence is geometric since its multiplying.
Based on this information, the correct answer is "B. -3, 3, -3, 3..." since its being multiplyed by -1.
Helllllllppppp plzzzzzzzzz
Answer:
Hey, You have chosen the correct answer.
the correct answer is C.
Use the Quadratic Formula to solve the equation x2 - 4x = -7
The given quadratic equation x² - 4x = -7 is rearranged into standard form and then solved using the quadratic formula -b ± √(b² - 4ac) / (2a). The roots of the equation are realized from solving this formula.
Explanation:The subject of this problem is a quadratic equation in the form of ax²+bx+c = 0. The given equation is x² - 4x = -7, which can be rearranged into standard form as x² - 4x + 7 = 0. Thus, in this case, a=1, b=-4, and c=7.
The solutions or roots for this quadratic equation can be calculated using the quadratic formula, which is -b ± √(b² - 4ac) / (2a). Substituting the values of a, b, and c into the formula will give the roots of the given equation.
Doing that, we get: x = [4 ± √((-4)² - 4*1*7)] / (2*1)
The values that solve the equation are the roots of the quadratic equation.
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To solve the equation x^2 - 4x = -7 using the Quadratic Formula, we follow the steps of plugging the values of a, b, and c into the formula, evaluating the square root and simplifying to find the solutions.
Explanation:To solve the equation x2 - 4x = -7 using the Quadratic Formula, we first need to make sure the equation is in standard form, which is ax2 + bx + c = 0. In this case, a = 1, b = -4, and c = 7. Plugging these values into the Quadratic Formula, we get:
x = (-(-4) ± √((-4)2 - 4(1)(-7))) / (2(1))
x = (4 ± √(16 + 28))/2
x = (4 ± √44)/2
x = (4 ± 2√11)/2
x = 2 ± √11
So the solutions to the equation x2 - 4x = -7 are x = 2 + √11 and x = 2 - √11.
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What is the midpoint of a line segment with the endpoints (-6, -3) and (9,-7)?
Answer: (1.5, -5)
Step-by-step explanation: a p e x
Whats the quotient for this?
Answer:
Step-by-step explanation:
Divide 4378 by 15
From 4378 lets take the first two digits for division:
43/ 15
We know that 43 does not come in table of 15
So we will take 15 *2 = 30
43-30 = 13
The quotient is 3 and the remainder is 13
Now take one more number which is 7 with 13
137/15.
Now 137 does not come in table of 15
15*9 = 135
135-137 = 2
It means quotient is 9 and remainder is 2
Now take one more number which is 8 with 2
28/15
28 does not come in table of 15
15*1 = 15
28-15 = 13/15
Now the quotient is 1 and remainder is 13
Hence, the quotient of 4,378 is 291 and remainder is 13 ....
The diagram represents three statements: p, q, and r. For what value is both p ∧ r true and q false?
2
4
5
9
Answer:
9
Step-by-step explanation:
From the diagram:
only p true in 8 cases;only q true in 7 cases;only r true in 6 cases;both p and q true, r false in 5 cases;both p and r true, q false in 9 cases;both q and r true, p false in 4 cases;all three p, q and r true in 2 cases.So, correct option is 9 cases.
Answer:
The correct option is 4. For value 9 both p ∧ r true and q false.
Step-by-step explanation:
The diagram represents three statements: p, q, and r.
We need to find the value for which p ∧ r is true and q false.
p ∧ r true mean the intersection of statement p and r. It other words p ∧ r true means p is true and r is also true.
From the given venn diagram it is clear that the intersection of p and r is
[tex]p\cap r=9+2=11[/tex]
p ∧ r true and q false means intersection of p and r but q is not included.
From the given figure it is clear that for value 2 all three statements are true. So, the value for which both p ∧ r true and q false is
[tex]11-2=9[/tex]
Therefore the correct option is 4.
The perimeter of a bedroom is 88 feet. The ratio of the width to the length is 5:6. What are the dimensions of the bedroom?
Answer:
20 feet wide, 24 feet long
Step-by-step explanation:
Let x - width, y - length.
The perimeter is given by the formula:
P = 2*(width + length) or using x, y
P = 2*(x + y) = 88
x + y = 44
And we know that the ratio between the sides is 5/6:
x/y = 5/6. x is on top because the length is bigger than the width
x = 5y/6
Plug this in the first expression:
y + 5y/6 = 44. Muliply by 6
6y + 5y = 264
11y = 264
y = 264/11 = 24.
So x = 5(24)/6 = 20
What is the equation of the graph below
Answer:
y=-(x-3)^2+2
Step-by-step explanation:
since the curve is convex up so the coefficient of x^2 is negative
and by substituting by the point 3 so y = 2
Answer:
B
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
here (h, k) = (3, 2), hence
y = a(x - 3)² + 2
If a > 0 then vertex is a minimum
If a < 0 then vertex os a maximum
From the graph the vertex is a maximum hence a < 0
let a = - 1, then
y = - (x - 3)² + 2 → B
children play a form of hopscotch called jumby. the pattern for the game is as given below.
Find the area of the pattern in simplest form.
Answer:
7t^2 + 21t
Step-by-step explanation:
You have 7 tiles of each t by t+3.
One tile has an area of
t * (t+3) = t^2 + 3t
So in total the area is
7* (t^2 + 3t)
7t^2 + 21t
A parallelogram has coordinates A(1,1), B(5,4), C(7,1), and D(3,-2) what are the coordinates of parallelogram A’BCD after 180 degree rotation about the origin and a translation 5 units to the right and 1 unit down ?
Answer:
The coordinates are (4 , -2) , (0 , -5) , (-2 , -2) , (2 , 1)
Step-by-step explanation:
* Lets revise some transformation
- If point (x , y) rotated about the origin by angle 180°
∴ Its image is (-x , -y)
- If the point (x , y) translated horizontally to the right by h units
∴ Its image is (x + h , y)
- If the point (x , y) translated horizontally to the left by h units
∴ Its image is (x - h , y)
- If the point (x , y) translated vertically up by k units
∴ Its image is (x , y + k)
- If the point (x , y) translated vertically down by k units
∴ Its image is (x , y - k)
* Now lets solve the problem
∵ ABCD is a parallelogram
∵ Its vertices are A (1 , 1) , B (5 , 4) , C (7 , 1) , D (3 , -2)
∵ The parallelogram rotates about the origin by 180°
∵ The image of the point (x , y) after rotation 180° about the origin
is (-x , -y)
∴ The images of the vertices of the parallelograms are
(-1 , -1) , (-5 , -4) , (-7 , -1) , (-3 , 2)
∵ The parallelogram translate after the rotation 5 units to the right
and 1 unit down
∴ We will add each x-coordinates by 5 and subtract each
y-coordinates by 1
∴ A' = (-1 + 5 , -1 - 1) = (4 , -2)
∴ B' = (-5 + 5 , -4 - 1) = (0 , -5)
∴ C' = (-7 + 5 , -1 - 1) = (-2 , -2)
∴ D' = (-3 + 5 , 2 - 1) = (2 , 1)
* The coordinates of the parallelograms A'B'C'D' are:
(4 , -2) , (0 , -5) , (-2 , -2) , (2 , 1)
what is the value of x?
Answer:
x=35
Step-by-step explanation:
We have the two angles (6x -82) and (3x + 23) that are equal. To find 'x' we need to solve the system of equations:
6x -82 = 3x + 23
Solving for 'x':
3x = 105
x = 35
[tex]6x-82=3x+23\\3x=105\\x=35[/tex]
Which of the following numbers are less than 9/4?
Choose all that apply:
A= 11/4
B= 15/8
C= 2.201
Answer:
OPTION B.
OPTION C.
Step-by-step explanation:
In order to know which numbers are less than [tex]\frac{9}{4}[/tex], you can convert this fraction into a decimal number. To do this, you need to divide the numerator 9 by the denominator 4. Then:
[tex]\frac{9}{4}=2.25[/tex]
Now you need convert the fractions provided in the Options A and B into decimal numbers by applying the same procedure. This are:
Option A→ [tex]\frac{11}{4}=2.75[/tex] (It is not less than 2.25)
Option B→ [tex]\frac{15}{8}=1.875[/tex] (It is less than 2.25)
The number shown in Option C is already expressed in decimal form:
Option C→ [tex]2.201[/tex] (It is less than 2.25)
What is the volume of a sphere that has a radius of 9?
Answer:
V = 3053.63
Step-by-step explanation:
The volume of a sphere that has a radius of 9 is 3053.63.
V=4
3πr3=4
3·π·93≈3053.62806
Answer is provided in the image attached.
What is the sum of entries a32 and b32 in A and B? (matrices)
Answer:
The correct answer is option D. 13
Step-by-step explanation:
From the figure we can see two matrices A and B
To find the sum of a₃₂ and b₃₂
From the given attached figure we get
a₃₂ means that the third row second column element in the matrix A
b₃₂ means that the third row second column element in the matrix B
a₃₂ = 4 and b₃₂ = 9
a₃₂ + b₃₂ = 4 + 9
= 13
The correct answer is option D. 13
[tex]A={\begin{bmatrix}a_{11}&a_{12}&\cdots &a_{1n}\\a_{21}&a_{22}&\cdots &a_{2n}\\\vdots &\vdots &\ddots &\vdots \\a_{m1}&a_{m2}&\cdots &a_{mn}\end{bmatrix}}[/tex]
So
[tex]a_{32}=4\\b_{32}=9\\\\a_{32}+b_{32}=4+9=13[/tex]
A high school track is shaped as a rectangle with a half circle on either side . Jake plans on running four laps . How many meters will jake run ?
Answer:
[tex]1,207.6\ m[/tex]
Step-by-step explanation:
step 1
Find the perimeter of one lap
we know that
The perimeter of one lap is equal to the circumference of a complete circle (two half circles is equal to one circle) plus two times the length of 96 meters
so
[tex]P=\pi D+2(96)[/tex]
we have
[tex]D=35\ m[/tex]
[tex]\pi =3.14[/tex]
substitute
[tex]P=(3.14)(35)+2(96)[/tex]
[tex]P=301.9\ m[/tex]
step 2
Find the total meters of four laps
Multiply the perimeter of one lap by four
[tex]P=301.9(4)=1,207.6\ m[/tex]
Answer:
1207.6
Step-by-step explanation:
step 1
i got it right on the test
step 2
you get it right on the test