Linda bought circular table clothe that was a radius of 3 feet. What is the circmference to the nearest foot of linda's table cloth? (using Pie 3.14

Answer:

Option D [tex]\frac{b}{15}[/tex]

Step-by-step explanation:

Let

b-----> the number of bagels

we know that

To find the algebraic expression of "the bagels were divided equally into fifteen bags" , divided the number of bagels by fifteen

so

[tex]\frac{b}{15}[/tex]

The answer would be

B)

Answer:

[tex]15\cdot\sqrt[3]{x}\cdot \sqrt[5]{y}[/tex]

Step-by-step explanation:

We have been given an expression [tex]15x^{\frac{1}{3}}y^{\frac{1}{5}[/tex]. We are asked to express our given expression using a radical.

Using fractional exponent rule [tex]a^{\frac{m}{n}}=\sqrt[n]{a^m}[/tex], we can write terms of our given expression as:

[tex]15\cdot\sqrt[3]{x^1}\cdot \sqrt[5]{y^1}[/tex]

[tex]15\cdot\sqrt[3]{x}\cdot \sqrt[5]{y}[/tex]

Therefore, our required expression would be [tex]15\cdot\sqrt[3]{x}\cdot \sqrt[5]{y}[/tex].

In a calendrical system where leap years occur every four years without any exceptions, there would be 37 leap years in a 150-year period.

In a calendrical system where leap years occur every four years without exception, the number of leap years in a 150-year period can be calculated with a simple division operation. This is because every 4 years there is a leap year consistent with the rules of this calendar system.

To calculate the maximum number of leap years in a 150-year period, you would divide 150 by 4 as this represents the frequency of leap years. This results in a total of 37.5. Given that a half year cannot be a leap year, we eliminate the fraction and we have 37 leap years.

While the Gregorian calendar also has a leap year every four years, there are exceptions for century years not divisible by 400. But since the question specified a system without such rule, there would be more leap years in this system compared to the Gregorian calendar for the same period of time.

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The x and y intercepts of the equation 9/4x - 1/2y = -3 are -4/3 and 6 respectively. These were calculated by separately setting the x and y to zero and solving for the other variable.

To find the x and y intercepts of the equation 9/4x - 1/2y = -3, we need to set each of the variables x and y to zero separately and solve for the other variable.

Set y = 0 in the equation for the x-intercept. This gives us 9/4x = -3, and solving for x, we get x = -4*3/9 = -4/3.

For the b, set x = 0 in the equation. This gives us -1/2y = -3, and solving for y, we get y = 2*3 =6.

So the x-intercept and y-intercept of the equation are -4/3 and 6 respectively.

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We have been given that prices increase at a monthly rate of 0.5%.

Number of months in a year = 12

Let us suppose the item cost $1, then the percentage is given by

[tex]P=P_0(1+r)^n\\ \\ P=1(1+0.005)^{12}\\ \\ P=1.062[/tex]\\

Therefore, increase in a year is

[tex]1.062-1\\ =0.062[/tex]

Therefore, the required percentage in a year is 6.2%

Answer:

2/3

Step-by-step explanation:

Using the Normal distribution, the Empirical rule and the Central limit theorem, it is found that n is 36.

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

In this problem, since 68% of the students had sample means between 48.5 and 51.5 mm, we have that:

Using one of them, we can find the standard error. So:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]1 = \frac{51.5 - 50}{s}[/tex]

[tex]s = 1.5[/tex]

Then, since [tex]\sigma = 9[/tex], the sample size is found solving the following equation:

[tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

[tex]1.5 = \frac{9}{\sqrt{n}}[/tex]

[tex]1.5\sqrt{n} = 9[/tex]

[tex]\sqrt{n} = \frac{9}{1.5}[/tex]

[tex](\sqrt{n})^2 = (\frac{9}{1.5})^2[/tex]

[tex]n = 36[/tex]

n is 36.

A similar problem is given at https://brainly.com/question/13002303

Answer:

x = 9 ±√23

Step-by-step explanation:

The probability that worker 1 will outproduce worker 2 in a single day is approximately 0.352 or 35.2%.

To find the probability that worker 1 will outproduce worker 2 in a single day, we need to compare their production rates using their respective means and standard deviations.

Let X be the production of worker 1 and Y be the production of worker 2. We are interested in finding P(X > Y).

Given:

Worker 1: X ~ N(77, 22^2)

Worker 2: Y ~ N(66, 19^2)

First, we standardize the variables:

Z1 = (X - 77) / 22

Z2 = (Y - 66) / 19

Now, we find P(X > Y) = P(X - Y > 0):

= P((X - 77) - (Y - 66) > 0)

= P((X - Y) > (77 - 66))

Now, we find the mean and standard deviation of the difference:

Mean of (X - Y) = 77 - 66 = 11

Standard deviation of (X - Y) = sqrt(22^2 + 19^2) = sqrt(484 + 361) = sqrt(845) ≈ 29.07

Now we standardize the difference:

Z = (11 - 0) / 29.07 ≈ 0.378

Finally, we find the probability using the standardized normal distribution table:

P(Z > 0.378) ≈ 0.352

So, the probability that worker 1 will outproduce worker 2 in a single day is approximately 0.352 or 35.2%.

the probability that Worker 1 will outproduce Worker 2 in a single day is approximately 0.7202 or 72.02%.

To find the probability that Worker 1 will outproduce Worker 2 in a single day, we can use the z-score formula for normal distributions.

The z-score formula is given by:

[tex]\[ z = \frac{{X - \mu}}{{\sigma}} \][/tex]

Where:

- ( X ) is the value we want to find the z-score for (in this case, Worker 1's productivity).

- [tex]\( \mu \)[/tex]is the mean (average) productivity.

- [tex]\( \sigma \)[/tex] is the standard deviation.

For Worker 1:

- [tex]\( X_1 = 77 \)[/tex] units per day (average productivity)

- [tex]\( \mu_1 = 77 \)[/tex]units per day (average productivity)

- [tex]\( \sigma_1 = 22 \)[/tex] units per day (standard deviation)

For Worker 2:

-[tex]\( X_2 = 66 \)[/tex]units per day (average productivity)

- [tex]\( \mu_2 = 66 \)[/tex]units per day (average productivity)

- [tex]\( \sigma_2 = 19 \)[/tex] units per day (standard deviation)

First, we find the z-score for Worker 1's productivity relative to Worker 2's productivity:

[tex]\[ z = \frac{{X_1 - \mu_2}}{{\sigma_2}} = \frac{{77 - 66}}{{19}} = \frac{{11}}{{19}} \approx 0.579 \][/tex]

Next, we look up the z-score in the standard normal distribution table or use a calculator/tool that can calculate probabilities from the standard normal distribution. The z-score of 0.579 corresponds to a probability of approximately 0.7202.

Therefore, the probability that Worker 1 will outproduce Worker 2 in a single day is approximately 0.7202 or 72.02%.

The answer to the question is y=6x

Anjie's total cost for purchasing 600 shares of Tumblr stock at $38 per share plus a broker’s commission of $0.10 per share is $22,860. Hence, correct option is A $22,860.

To determine the total cost of Anjie’s purchase, follow these steps:

      600 shares* $38 per share = $22,800.

    2. Next, calculate the broker’s commission:

      600 shares* $0.10 per share = $60.

    3. Add the purchase cost and the broker’s commission to get the total cost:

     $22,800 + $60 = $22,860.

Thus, Anjie's total cost is $22,860 which corresponds to option A.

Answer:

B

Step-by-step explanation:

Answer:

The answer "attorney and notary fees" made me get the question wrong on brainly. The correct answer it showed me after I got it wrong was C. Credit check and administrative costs associated with loan processing

Step-by-step explanation: