Answer:
$91.76
Step-by-step explanation:
Interest the first month was ...
I = Prt
I = $15000(0.0387)(1/12) = $48.375 ≈ $48.38
Interest in the second month was ...
I = $15000(0.0347)(1/12) = $43.375 ≈ $43.38
So the total interest amount is ...
$48.38 +43.38 = $91.76
Marcella earned $91.76 in two months.
_____
Comment on rounding
We have assumed that Marcella's account statement will report the interest rounded to 2 decimal places (cents). Hence she obtains the benefit from rounding for both months.
If there is no statement, so that rounding is not required until the end of the second month, then she may not have that extra penny in her account.
Find a formula for the nth partial sum of the series and use it to find the series' sum if the series converges.
[5/1*2]+[5/2*3]+[5/3*4]+...+[5/n(n+1)]+...
Answer: [tex]S_n=5(1-\dfrac{1}{n+1})[/tex] ; 5
Step-by-step explanation:
Given series : [tex][\dfrac{5}{1\cdot2}]+[\dfrac{5}{2\cdot3}]+[\dfrac{5}{3\cdot4}]+....+[\dfrac{5}{n\cdot(n+1)}][/tex]
Sum of series = [tex]S_n=\sum^{\infty}_{1}\ [\dfrac{5}{n\cdot(n+1)}]=5[\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}][/tex]
Consider [tex]\dfrac{1}{n\cdot(n+1)}=\dfrac{n+1-n}{n(n+1)}[/tex]
[tex]=\dfrac{1}{n}-\dfrac{1}{n+1}[/tex]
⇒ [tex]S_n=5\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}=5\sum^{\infty}_{1}[\dfrac{1}{n}-\dfrac{1}{n+1}][/tex]
Put values of n= 1,2,3,4,5,.....n
⇒ [tex]S_n=5(\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+......-\dfrac{1}{n}+\dfrac{1}{n}-\dfrac{1}{n+1})[/tex]
All terms get cancel but First and last terms left behind.
⇒ [tex]S_n=5(1-\dfrac{1}{n+1})[/tex]
Formula for the nth partial sum of the series :
[tex]S_n=5(1-\dfrac{1}{n+1})[/tex]
Also, [tex]\lim_{n \to \infty} S_n = 5(1-\dfrac{1}{n+1})[/tex]
[tex]=5(1-\dfrac{1}{\infty})\\\\=5(1-0)=5[/tex]
Show that 6^3-1 is divisible by 5 using our identities
Answer:
Step-by-step explanation:
a³-b³=(a-b)(a²+ab+b²)
6³-1=6³-1³=(6-1)(6²+6*1+1²)=5×43
so 6³-1 is divisible by 5.
[tex]\displaystyle 6^3 - 1 = 216 - 1 = 215[/tex]
The number 215 is divisible by 5 because it ends in 5, according to the divisibility rules.
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Howard opens a savings account with a deposit of 800$. The bank will pay him 3% intrest per year. How much will Howard receive at the end of the year?
Answer:
$824
Step-by-step explanation:
3% (rate of interest) of 800= 24
800 + 24= 824
A paper airplane was thrown from the top of a tall building, The height of the paper airplane above the ground can be found using the function y= -1.5x+60, where x is the time in seconds the airplane has been in the air.
Answer:
How many seconds did it take the paper airplane to reach the ground?
40 Seconds.
Step-by-step explanation:
When the paper airplane touches the ground is equivalent to having a height equal to zero (y=0). So replacing in the equation:
[tex]y= -1.5x+60\\0= -1.5x+60\\1.5x=60\\x=\frac{60}{1.5} \\x=40[/tex]
The function y= -1.5x+60 describes the downward trajectory of a paper airplane. The '-1.5' represents the falling speed per second, and '+60' represents the initial height. To find the paper airplane's height at any time, substitute the time into the equation.
Explanation:The question deals with the concept of linear equations and gravity, a physics concept represented in mathematical terms. The function y= -1.5x+60 describes the trajectory of a paper airplane thrown from a building. This function means that the height y of the airplane above the ground, after x seconds, decreases by 1.5m each second, starting from an initial height of 60m.
The coefficient -1.5 represents the speed of the plane, which is downwards due to negative sign. After each second, the paper airplane will be 1.5 m lower than it was the previous second. The '+60' means the paper airplane was initially 60m off the ground.
To use this function for any given time (x), simply substitute the time into the equation. For example, for 5 seconds (x=5), the height y would be -1.5*5+60 = -7.5 + 60 = 52.5m
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A state department of public safety added 13x2 + 5x miles of highway to connect CoolTown and Bragville. It cost the department 3x2 – 9x thousand dollars to complete each mile of interstate. Which expression shows the total cost, in thousands of dollars, of creating this highway?
Answer:
x4 + 12x^3 – 45x^2
Step-by-step explanation:
Suppose that the sitting back-to-knee length for a group of adults has a normal distribution with a mean of mu equals 22.1 in. and a standard deviation of sigma equals 1.2 in. These data are often used in the design of different seats, including aircraft seats, train seats, theater seats, and classroom seats. Instead of using 0.05 for identifying significant values, use the criteria that a value x is significantly high if P(x or greater)less than or equals0.01 and a value is significantly low if P(x or less)less than or equals0.01. Find the back-to-knee lengths separating significant values from those that are not significant. Using these criteria, is a back-to-knee length of 24.2 in. significantly high?
In a normal distribution, the back-to-knee lengths that separate significant values from others are 24.896 inches (upper percentile) and 19.304 inches (lower percentile) respectively. Using these limits, a back-to-knee length of 24.2 inches is not considered significantly high.
Explanation:To find the back-to-knee lengths that separate significant values from those that are not, we need to find the values of x for which P(x ≥ some value) ≤ 0.01, and P(x ≤ some value) ≤ 0.01.
These values are known as the upper and lower percentiles, respectively, and can be obtained by transforming to a standard normal distribution (with a mean of 0 and a standard deviation of 1) using z-scores.
Let's use the standard normal table to find z-scores corresponding to 0.01 in the upper side and lower side of the distribution. You would find that the z-score which has an area of 0.01 in the upper tail is approximately 2.33, and in the lower tail it is -2.33.
Now, we can use these z-scores to calculate respective back-to-knee lengths. The formula for a z-score is z = (x - μ) / σ, where μ is the mean, σ is the standard deviation, and x is the observation. Solving for x gives us x = zσ + μ.
Upper percentile, x = (2.33*1.2) + 22.1 = 24.896 inches.
Lower percentile, x = (-2.33*1.2) + 22.1 = 19.304 inches.
So, any back-to-knee length above 24.896 inches or below 19.304 inches can be considered statistically significant. Therefore, a back-to-knee length of 24.2 inches would not be considered significantly high as it is less than 24.896 inches.
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In order to find the separating lengths for significant values in a normal distribution, we need to find the values corresponding to z-scores for probabilities 0.01 and 0.99. To know if a back-to-knee length of 24.2 in. is significantly high, compare the probability P(X>=24.2) with 0.01.
Explanation:In the problem presented, the information is about the normal distribution of the back-to-knee length of a group of adults. A normal distribution graph has its highest point at the mean, which in this case is 22.1 in., and it decrease on either side. The standard deviation, which measures the spread of the values, is given as 1.2 in.
For a value to be considered significantly high, the probability P(x or higher) should be less than or equal to 0.01. Similarly, for a value to be significantly low, P(x or lower) should also be less or equal to 0.01.
To find the back-to-knee lengths separating the significant values from non-significant, one can use the z-scores associated with the probabilities 0.01 and 0.99 (since the total probability of a normal distribution is 1). So, the lengths in question will be the ones that correspond to these z-scores.
Provided, a z-score is a value's number of standard deviations from the mean. If z is the z-score, μ is the mean, σ is the standard deviation, and x is the value, the formula is z=(x-μ)/σ.
Regarding the specific measurement of 24.2 in., we would need to calculate the probability P(X>=24.2) using the given mean and standard deviation in Z-score formula. If P(X>=24.2) is less than 0.01, then 24.2 in. can be considered as significantly high.
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Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonometric ratios sec thetaθ and sin thetaθ.
Answer:
[tex]\sin \theta = \dfrac{5}{13}[/tex] and [tex]\sec \theta = -\dfrac{13}{12}[/tex]
Step-by-step explanation:
Assume that the terminal side of thetaθ passes through the point (−12,5).
In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.
Using Pythagoras theorem:
[tex]hypotenuse^2=perpendicular^2+base^2[/tex]
[tex]hypotenuse^2=(5)^2+(12)^2[/tex]
[tex]hypotenuse^2=25+144[/tex]
[tex]hypotenuse^2=169[/tex]
Taking square root on both sides.
[tex]hypotenuse=13[/tex]
In a right angled triangle
[tex]\sin \theta = \dfrac{opposite}{hypotenuse}[/tex]
[tex]\sin \theta = \dfrac{5}{13}[/tex]
[tex]\sec \theta = \dfrac{hypotenuse}{adjacent}[/tex]
[tex]\sec \theta = \dfrac{13}{12}[/tex]
In second quadrant only sine and cosecant are positive.
[tex]\sin \theta = \dfrac{5}{13}[/tex] and [tex]\sec \theta = -\dfrac{13}{12}[/tex]
A recipe for brownies calls for 2/3 Cup of chocolate chips for a batch of two dozen brownies. How many chocolate chips will be needed to make 18 brownies.
Answer:
6 cups
Step-by-step explanation:
[tex](18 \times \frac{2}{3} ) \div 2 = [/tex]
[tex]12 \div 2 = [/tex]
[tex]6[/tex]
Police estimate that 84% of drivers wear their seatbelts. They set up a safety roadblock, stopping cars to check for seatbelt use. If they stop 140 cars,
what is the probability they find at least 27 drivers not wearing their seatbelts?
Use a Normal approximation.
Answer:
0.8802
Step-by-step explanation:
given that the Police estimate that 84% of drivers wear their seatbelts.
when they stop 140 cars, no of trials = no of cars checked = 140
Each car is independent of the other
Hence X no of cars with drivers wearing seat belts is binomial with p = 0.85
Required probability =
the probability they find at least 27 drivers not wearing their seatbelts
Since normal approximation is required we can approximate to
X is Normal with mean = np = [tex]140(0.84)\\=117.6[/tex]
std dev = [tex]\sqrt{npq} =4.338[/tex]
Required probability =atelast 27 drivers not wearing their seatbelts
= P(X>(140-27))
= P(X>113)
[tex]=P(X>112.5)\\=1- 0.1198\\=0.8802[/tex]
How can trigonometry be used to model the path of a baseball?
Trigonometry can be used to model projectile motion, such as the flight of a baseball. Given the angle at which the ball leaves the bat and the initial velocity, you can determine the distance the ball will travel.
Answer:
Trigonometry can be used to model projectile motion, such as the flight of a baseball. Given the angle at which the ball leaves the bat and the initial velocity, you can determine the distance the ball will travel.
Step-by-step explanation:
A tree is growing such that its trunk forms a 98 degree angle with the ground. At a point 27 meters from the tree, the angle of elevation to the top of the tree is 24 degrees. If a bug crawls from the base of the tree all the way to the top, how far has it gone? (i.e. how tall is the tree?)A. 46 metersB. 13 metersC. 54 metersD. 56 meters
Answer: option B is the correct answer
Step-by-step explanation:
The diagram of the tree is shown in the attached photo. The triangle ABC formed is not a right angle triangle. The last angle, angle C is gotten by subtracting the sum of angle A and angle B from 180(sum of angles) in a triangle is 180). It becomes
C = 180-(98+24)= 180 -122
C = 58 degrees
To find the height of the tree, we would apply the sine rule
a/sinA = b/sin B = c/ sinC
We would apply b/sin B = c/ sinC
b/sin24 = 27/sin58
b/0.4067 = 27/0.8480
Cross-multiplying,
27 ×0.4067 = b × 0.8480
10.9809 = 0.8480b
b = 10.9809/0.8480 = 12.949
Approximately 13 meters
The bug crawls 13 meters from the base to the top of the tree
A study of long-distance phone calls made from General Electric Corporate Headquarters in Fairfield, Connecticut, revealed the length of the calls, in minutes, follows the normal probability distribution. The mean length of time per call was 4.7 minutes and the standard deviation was 0.50 minutes.
(a) What fraction of the calls last between 4.7 and 5.5 minutes? (Round z-score computation to 2 decimal places and your final answer to 4 decimal places.)Fraction of calls (b) What fraction of the calls last more than 5.5 minutes? (Round z-score computation to 2 decimal places and your final answer to 4 decimal places.)Fraction of calls (c) What fraction of the calls last between 5.5 and 6 minutes? (Round z-score computation to 2 decimal places and final answer to 4 decimal places.)Fraction of calls
(d) What fraction of the calls last between 4 and 6 minutes? (Round z-score computation to 2 decimal places and your final answer to 4 decimal places.)Fraction of calls (e) As part of her report to the president, the director of communications would like to report the length of the longest (in duration) 3% of the calls. What is this time? (Round z-score computation to 2 decimal places and your final answer to 2 decimal places.)Duration
Answer:
a) 0.4452
b) 0.0548
c) 0.0501
d) 0.9145
e) 6.08 minutes or greater
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 4.7 minutes
Standard Deviation, σ = 0.50 minutes.
We are given that the distribution of length of the calls is a bell shaped distribution that is a normal distribution.
Formula:
[tex]z_{score} = \displaystyle\frac{x-\mu}{\sigma}[/tex]
a) P(calls last between 4.7 and 5.5 minutes)
[tex]P(4.7 \leq x \leq 5.5) = P(\displaystyle\frac{4.7 - 4.7}{0.50} \leq z \leq \displaystyle\frac{5.5-4.7}{0.50}) = P(0 \leq z \leq 1.6)\\\\= P(z \leq 1.6) - P(z <0)\\= 0.9452 - 0.5000 = 0.4452 = 44.52\%[/tex]
[tex]P(4.7 \leq x \leq 5.5) = 44.52\%[/tex]
b) P(calls last more than 5.5 minutes)
[tex]P(x > 5.5) = P(z > \displaystyle\frac{5.5-4.7}{0.50}) = P(z > 1.6)\\\\P( z > 1.6) = 1 - P(z \leq 1.6)[/tex]
Calculating the value from the standard normal table we have,
[tex]1 - 0.9452 = 0.0548 = 5.48\%\\P( x > 5.5) = 5.48\%[/tex]
c) P( calls last between 5.5 and 6 minutes)
[tex]P(4.7 \leq x \leq 5.5) = P(\displaystyle\frac{5.5 - 4.7}{0.50} \leq z \leq \displaystyle\frac{6-4.7}{0.50}) = P(1.6 \leq z \leq 2.6)\\\\= P(z \leq 2.6) - P(z <1.6)\\= 0.9953 - 0.9452 = 0.0501 = 5.01\%[/tex]
[tex]P(5.5 \leq x \leq 6) = 5.01\%[/tex]
d) P( calls last between 4 and 6 minutes)
[tex]P(4 \leq x \leq 6) = P(\displaystyle\frac{4 - 4.7}{0.50} \leq z \leq \displaystyle\frac{6-4.7}{0.50}) = P(-1.4 \leq z \leq 2.6)\\\\= P(z \leq 2.6) - P(z <-1.4)\\= 0.9953 - 0.0808 = 0.9145 = 91.45\%[/tex]
[tex]P(4 \leq x \leq 6) = 91.45\%[/tex]
e) We have to find the value of x such that the probability is 0.03.
P(X > x)
[tex]P( X > x) = P( z > \displaystyle\frac{x - 4.7}{0.50})=0.03[/tex]
[tex]= 1 -P( z \leq \displaystyle\frac{x - 4.7}{0.50})=0.03 [/tex]
[tex]=P( z \leq \displaystyle\frac{x - 4.7}{0.50})=0.997 [/tex]
Calculation the value from standard normal z table, we have,
P(z < 2.75) = 0.997
[tex]\displaystyle\frac{x - 4.7}{0.50} = 2.75\\x = 6.075 \approx 6.08[/tex]
Hence, the call lengths must be 6.08 minutes or greater for them to lie in the highest 3%.
The fraction of calls that last between 4.7 and 5.5 minutes is 0.4452, the fraction of calls that last more than 5.5 minutes is 0.0548, the fraction of calls that last between 5.5 and 6 minutes is 0.0501, the fraction of calls that last between 4 and 6 minutes is 0.9145, and the length of the longest 3% of the calls is 5.85 minutes.
Explanation:To solve this problem, we can use the standard normal distribution table by converting the given values into z-scores. The z-score formula is: z = (x - μ) / σ where x is the given value, μ is the mean, and σ is the standard deviation. Let's calculate the fractions for each part of the question:
(a) Between 4.7 and 5.5 minutes:
Calculate the z-score for 4.7 minutes: z = (4.7 - 4.7) / 0.5 = 0Calculate the z-score for 5.5 minutes: z = (5.5 - 4.7) / 0.5 = 1.6Use the z-score table to find the area to the left of 1.6: 0.9452Subtract the area to the left of 0 from the area to the left of 1.6: 0.9452 - 0.5 = 0.4452(b) More than 5.5 minutes:
Calculate the z-score for 5.5 minutes: z = (5.5 - 4.7) / 0.5 = 1.6Find the area to the left of 1.6 using the z-score table: 0.9452Subtract the area to the left of 1.6 from 1: 1 - 0.9452 = 0.0548(c) Between 5.5 and 6 minutes:
Calculate the z-score for 5.5 minutes: z = (5.5 - 4.7) / 0.5 = 1.6Calculate the z-score for 6 minutes: z = (6 - 4.7) / 0.5 = 2.6Find the area to the left of 1.6 using the z-score table: 0.9452Find the area to the left of 2.6 using the z-score table: 0.9953Subtract the area to the left of 1.6 from the area to the left of 2.6: 0.9953 - 0.9452 = 0.0501(d) Between 4 and 6 minutes:
Calculate the z-score for 4 minutes: z = (4 - 4.7) / 0.5 = -1.4Calculate the z-score for 6 minutes: z = (6 - 4.7) / 0.5 = 2.6Find the area to the left of -1.4 using the z-score table: 0.0808Find the area to the left of 2.6 using the z-score table: 0.9953Subtract the area to the left of -1.4 from the area to the left of 2.6: 0.9953 - 0.0808 = 0.9145(e) The longest 3% of the calls:
Find the z-score for an area of 0.97 using the z-score table: 1.88Use the z-score formula to find the time value: x = z * σ + μSubstitute z = 1.88, σ = 0.5, μ = 4.7 into the formula: x = 1.88 * 0.5 + 4.7 = 5.85So, the time for the longest 3% of the calls is 5.85 minutes.
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Find the area and perimeter of ABC at right. Give approximate (decimal) answers, not exact answers
Answer:
Area of Δ ABC = 21.86 units square
Perimeter of Δ ABC = 24.59 units
Step-by-step explanation:
Given:
In Δ ABC
∠A=45°
∠C=30°
Height of triangle = 4 units.
To find area and perimeter of triangle we need to find the sides of the triangle.
Naming the end point of altitude as 'D'
Given [tex]BD\perp AC[/tex]
For Δ ABD
Since its a right triangle with one angle 45°, it means it is a special 45-45-90 triangle.
The sides of 45-45-90 triangle is given as:
Leg1 [tex]=x[/tex]
Leg2 [tex]=x[/tex]
Hypotenuse [tex]=x\sqrt2[/tex]
where [tex]x[/tex] is any positive number
We are given BD(Leg 1)=4
∴ AD(Leg2)=4
∴ AB (hypotenuse) [tex]=4\sqrt2=5.66 [/tex]
For Δ CBD
Since its a right triangle with one angle 30°, it means it is a special 30-60-90 triangle.
The sides of 30-60-90 triangle is given as:
Leg1(side opposite 30° angle) [tex]=x[/tex]
Leg2(side opposite 60° angle) [tex]=x\sqrt3[/tex]
Hypotenuse [tex]=2x[/tex]
where [tex]x[/tex] is any positive number
We are given BD(Leg 1)=4
∴ CD(Leg2) [tex]=4\sqrt3=6.93[/tex]
∴ BC (hypotenuse) [tex]=2\times 4=8 [/tex]
Length of side AC is given as sum of segments AD and CD
[tex]AC=AD+CD=4+6.93=10.93[/tex]
Perimeter of Δ ABC= Sum of sides of triangle
⇒ AB+BC+AC
⇒ [tex]5.66+8+10.93[/tex]
⇒ [tex]24.59[/tex] units
Area of Δ ABC = [tex]\frac{1}{2}\times base\times height[/tex]
⇒ [tex]\frac{1}{2}\times 10.93\times 4[/tex]
⇒ [tex]21.86[/tex] units square
How many milligrams of zinc ions do the trout need to be exposed to in order for them to survive exactly one minute after exposure?
Answer:
1770
Step-by-step explanation:
No calculator is needed.
When you fill in the numbers, you get ...
1 = (x/1770)^(-0.8)
The only way the value will be 1 is if the fraction is 1:
x/1770 = 1
The only way the fraction will be 1 is x = 1770.
1770 mg Zn ions per liter will be lethal in 1 minute.
_____
Check
You know the answer will be slightly more than 1743 from your answer to the second part of the first question.
You spend 15 minutes reading email. You then spend 3 hours watching television. Write the ratio of the amount of time spent reading email to the amount of time spent watching television as a fraction in simplest form. The ratio in simplest form is nothing.
The amount of time spent reading email to the amount of time spent watching television is 1/12
Step-by-step explanation:
Given
Time to read email = 15 minutes
Time on television = 3 hours = 3*60 minutes = 180 minutes
Ration is the fraction between two things. In this case, the ration is from the amount of time spent reading email to the amount of time spent watching television
So,
Required ratio will be: 15/180
Simplifying => 1/12
So,
The amount of time spent reading email to the amount of time spent watching television is 1/12
Keywords: Ratio, fractions
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Consider a rectangle that is inscribed with its base on the x-axis and its upper corners on the parabola y=C−x2, with C>0. What are the width and height that maximize the area of this rectangle? What is that maximal area?
The maximum area of the given rectangle will be A = 4(C/3)√(C/3).
What is surface area?The quantity of space enclosing a three-dimensional shape's exterior is its surface area.
In other meaning, if we say side square then it is an area of the square but for a cuboid, there are 6 faces so the surface area will be external to all 6 surfaces area.
As per the given rectangle inscribed in the parabola has been drawn,
The area of rectangle A = (x + x)y
A = 2x(C - x²)
A = 2Cx - 2x³
To find the maximum area, take the first derivative with respect to x.
dA/dx = 2C - 6x² = 0
C - 3x² = 0
x = √(C/3)
Therefore, the area will be as,
A = 2C√(C/3) - 2(√(C/3))³
A = 2C√(C/3) - 2(C/3)√(C/3)
A = 2√(C/3) [C - C/3]
A = 2√(C/3)(2C/3)
A = 4(C/3)√(C/3)
Hence "The maximum area of the given rectangle will be A = 4(C/3)√(C/3)".
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Can someone answer this question?
The inequality is: 5>x≥0
Step-by-step explanation:
We have to write the inequality one by one
The inequality symbols are used to write inequalities.
So,
5 is greater than x will be written as:
5>x
And
0 is less than or equals to x:
0≤x or x≥0
We have to combine the both inequalities so that the variable is not repeated. The inequality symbols have to be written carefully while writing the compound inequalities.
5>x≥0
Keywords: Inequality, Relationships
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Is dollars 250 is to be divided among Neymar Rohit Sharma and Nadal so that Neymar gets two parts Rohit gets three parts and Nadal gets 5 parts how much money will we get? What will it be in percentage
Answer:
Step-by-step explanation:
Total amount of money to be shared among Neymar, Rohit Sharma and Nadal is $250
Neymar gets two parts. This means that Neymar gets 1/2 × total amount of money.
Neymar gets 1/2 × 250 = 125
The percentage will be amount that Neymar gets divided by the total amount and multiplied by 100. It becomes
125/250 × 100 = 50%
Rohit gets three parts. This means that Rohit gets 1/3 × total amount of money.
Rohit gets 1/3 × 250 = 83.33
The percentage will be amount that Rohit gets divided by the total amount and multiplied by 100. It becomes
83.33/250 × 100 = 33.33%
Nadal gets five parts. This means that Nadal gets 1/5 × total amount of money.
Nadal gets 1/5 × 250 = 50
The percentage will be amount that Nadal gets divided by the total amount and multiplied by 100. It becomes
50/250 × 100 = 20%
Answer:
Neymar: $50, 20%Rohit: $75, 30%Nadal: $125, 50%Step-by-step explanation:
A total of 10 parts are allocated to Neymar, Rohit, and Nadal, so each part represents 1/10 of the amount, or 10%.
Neymar gets 2 parts, or 20% of $250, so gets $50.
Rohit gets 3 parts, or 30% of $250, so gets $75.
Nadal gets 5 parts, or 50% of $250, so gets $125.
_____
Comment on the question
The question seems incomplete in that there are 4 names, but only 3 allocations.
A scientist begins with 250 grams of a radioactive substance. After 250 minutes, the sample has decayed to 36 grams. Write an exponential equation f(t) representing this situation. (Let f be the amount of radioactive substance in grams and t be the time in minutes.)
Answer:
f(t) = 250[tex]e^{-0.007752t}[/tex]
Step-by-step explanation:
Let f(t) = [tex]\alpha[/tex][tex]e^{\beta t }[/tex]
where f is the amount of radioactive substance in grams
and t is the time in minutes
initially (at t=0), f = 250 grams
⇒f(0) = 250 grams
⇒[tex]\alpha[/tex][tex]e^{0\beta}[/tex] = 250
⇒[tex]\alpha[/tex][tex]e^{0}[/tex] = 250
⇒[tex]\alpha[/tex] = 250 grams {∵[tex]e^{0} = 1[/tex]}
⇒f(t) = 250[tex]e^{\beta t }[/tex]
At t = 250 minutes, f = 36 grams
⇒f(250) = 36 grams
⇒250[tex]e^{250\beta}[/tex] = 36
⇒[tex]e^{250\beta}[/tex] = [tex]\frac{36}{250}[/tex] = 0.144
⇒250[tex]\beta[/tex] = ㏑ 0.144 = -1.938
⇒[tex]\beta[/tex] = -[tex]\frac{1.938}{250}[/tex] = -0.007752 [tex]min^{-1}[/tex]
∴f(t) = 250[tex]e^{-0.007752t}[/tex]
A new Firestone tire is guaranteed to last for 40,000 miles. The actual mean life of the tires is 47,000 miles with a standard deviation of 4,000 miles.
a) What percent of the tires will last for at least 40,000 miles?
b) What percent of the tires will not last for at least 40,000 miles?
c) What is the probability that a tire will last for more than 50,000 miles?
d) The Firestone Company wants to advertise how long some of their tires last. They decide to state how long the top 3% of their tires will last. How many miles will the top 3% of their tires last?
Answer:
a) 95.99%
b) 4.01%
c) 00.62%
Step-by-step explanation:
Explanation is given in the attachments.
Plz explain and prove the triangles congruence.
Answer:
[tex]\overline {JL} \cong \overline{MO}[/tex] is the only correct statement.
Step-by-step explanation:
When the two triangles are congruent then their Vertices are correspondence to each other. the correspondence of vertices are as
For, Δ JKL ≅ Δ MNO
J ↔ M
K ↔ N
L ↔ O
The true statement with respect to the correspondence are as
For, Δ JKL ≅ Δ MNO
∠JKL ≅ ∠MNO
∠JLK ≅ ∠MON
∠KJL ≅ ∠NMO
[tex]\overline {JL} \cong \overline{MO}[/tex]
[tex]\overline {KL} \cong \overline{NO}[/tex]
[tex]\overline {JK} \cong \overline{MN}[/tex]
These all are corresponding parts of congruent triangles (c.p.c.t).
What are the coordinates of the circumcenter of the triangle ?
Answer:
A=(-1,3)
B=(5,3)
C=(5,-5)
Step-by-step explanation:
Answer:
The answer to your question is (2, -1)
Step-by-step explanation:
1.- Find half points
AB
Between A and B there are 6 units, then the half point is three units from point A to the right
(2, 3)
BC
Between B and C there are 8 units, then the half point is four units below the point B.
(5, -1)
AC
Xm = -1 + 5 / 2 = 4 / 2 = 2
Ym = 3 - 5 / 2 = - 2 / 2 = - 1
(2, -1)
2.- Find the equations of the mediatrices
AB
x = 2 because the line must be perpendicuar to AB
BC
y = - 1 because the line must be perpendicular to BC
AC
slope m =[tex]\frac{-5 - 3}{5 + 1}[/tex]
m = [tex]\frac{-8}{6}[/tex]
m = [tex]\frac{-4}{3}[/tex]
mediatrix AC
y + 1 = -4/3 (x -2)
3y + 3 = -4x + 8
4x + 3y = 8 - 3
4x + 3y = 5
3.- Find the circumcenter
When x = 2
4(2) + 3y = 5
8 + 3y =5
3y = 5 - 8
3y = -3
y = -3/3
y = -1
When y = -1
4x + 3(-1) = 5
4x - 3 = 5
4x = 5 + 3
4x = 8
x = 8/4
x = 2
Circumcenter (2, -1)
In the July 2007 issue, Consumer Reports examined the calorie content of two kinds of hot dogs: meat (usually a mixture of pork, turkey, and chicken) and all beef. The researchers purchased samples of several different brands. The meat hot dogs averaged 111.7 calories, compared to 135.4 for the beef hot dogs. A test of the null hypothesis that there's no difference in mean calorie content yields a P-value of 0.124. Would a 95% confidence interval for μMeat −μBeef include 0? Explain.
Answer:
Since we FAIL to reject the null hypothesis, then if we construct an interval of 95% of confidence, the 0 should be included, because on the test hypothesis we conclude that there would be no significant difference between the means of the two groups analyzed, and the results obtained on the hypothesis test needs to be consistent with the confidence interval.
Step-by-step explanation:
A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".
The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".
The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".
[tex]\bar x_{meat}=111.7[/tex] represent the sample mean of calories for the meat hot dogs
[tex]\bar x_{beef}=135.4[/tex] represent the sample mean of calories for the beef hot dogs
The system of hypothesis on this case would be:
Null hypothesis: [tex]\mu_{meat}-\mu_{beef}=0[/tex]
Alternative hypothesis: [tex]\mu_{meat}-\mu_{beef}\neq 0[/tex]
On this case we have the p value obtained, after calculate the statistic and we got that [tex]p_v =0.124[/tex] if we select a 5% significance level [tex]\alpha=0.05[/tex] we see that [tex]p_v >\alpha[/tex] and on this case we can FAIL to rejec the null hypothesis, so there is not a significant difference between the mean of the two tpes of hot dogs analyzed at 5% of significance.
And since we FAIL to reject the null hypothesis, then if we construct an interval of 95% of confidence, the 0 should be included, because on the test hypothesis we conclude that there would be no significant difference between the means of the two groups analyzed, and the results obtained on the hypothesis test needs to be consistent with the confidence interval.
A 95% confidence interval for μMeat - μBeef including 0 indicates no significant difference in calorie content between meat and beef hot dogs.
Explanation:A 95% confidence interval for μMeat - μBeef that includes 0 suggests that there is no significant difference in the mean calorie content between meat and beef hot dogs. In this case, the difference in mean calorie content between the two types of hot dogs is not statistically significant, as the null hypothesis is not rejected. The P-value of 0.124 suggests that there is a 12.4% chance of observing a difference in mean calorie content as extreme as the one observed if the null hypothesis were true. Therefore, we cannot conclude that there is a significant difference in the mean calorie content between meat and beef hot dogs.
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A landscape architect wished to enclose a rectangular garden on one side by a brick wall costing $20/ft and on the other three sides by a metal fence costing $10/ft. If the area of the garden is 122 square feet, find the dimensions of the garden that minimize the cost.
Answer:
The dimensions of the garden that minimize the cost is 9.018 feet(length) and 13.528 feet(width)
Step-by-step explanation:
Let the length of garden be x
Let the breadth of garden be y
Area of Rectangular garden = [tex]Length \times Breadth = xy[/tex]
We are given that the area of the garden is 122 square feet
So, [tex]xy=122[/tex] ---A
A landscape architect wished to enclose a rectangular garden on one side by a brick wall costing $20/ft
So, cost of brick along length x = 20 x
On the other three sides by a metal fence costing $10/ft.
So, Other three side s = x+2y
So, cost of brick along the other three sides= 10(x+2y)
So, Total cost = 20x+10(x+2y)=20x+10x+20y=30x+20y
Total cost = 30x+20y
Substitute the value of y from A
Total cost = [tex]30x+20(\frac{122}{x})[/tex]
Total cost = [tex]\frac{2440}{x}+30x[/tex]
Now take the derivative to minimize the cost
[tex]f(x)=\frac{2440}{x}+30x[/tex]
[tex]f'(x)=-\frac{2440}{x^2}+30[/tex]
Equate it equal to 0
[tex]0=-\frac{2440}{x^2}+30[/tex]
[tex]\frac{2440}{x^2}=30[/tex]
[tex]\sqrt{\frac{2440}{30}}=x[/tex]
[tex]9.018 =x[/tex]
Now check whether it is minimum or not
take second derivative
[tex]f'(x)=-\frac{2440}{x^2}+30[/tex]
[tex]f''(x)=-(-2)\frac{2440}{x^3}[/tex]
Substitute the value of x
[tex]f''(x)=-(-2)\frac{2440}{(9.018)^3}[/tex]
[tex]f''(x)=6.6540[/tex]
Since it is positive ,So the x is minimum
Now find y
Substitute the value of x in A
[tex](9.018)y=122[/tex]
[tex]y=\frac{122}{9.018}[/tex]
[tex]y=13.528[/tex]
Hence the dimensions of the garden that minimize the cost is 9.018 feet(length) and 13.528 feet(width)
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The number of lattes sold daily by two coffee shops is shown in the table.
Shop A Shop B
55 36
52 40
50 34
47 39
51 44
48 41
53 40
53 38
Based on these data, is it better to describe the centers of distribution in terms of the mean or the median? Explain.
The answer is mean.
What are mean, median, and mode?Mean is the most commonly used measure of central tendency. It represents the average of the given collection of data. Median: Given that the data collection is arranged in ascending or descending order, the following method is applied:
• If number of values or observations in the given data is odd, then the median is given by [(n+1)/2]th observation.
• If in the given data set, the number of values or observations is even, then the median is given by the average of (n/2)th and [(n/2) +1]th observation.
Given here: Shop A Shop B
55 36
52 40
50 34
47 39
51 44
48 41
53 40
53 38
Total = 409 312
Since the data is not skewed mean will provide more accurate data then median.
Therefore the respective means are Shop A =51.125 Shop B=39
Hence, The answer is mean.
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Three pipes a and b and c can fill a swimming pool in 6 hours. After working on it together for 2 hours,C is closed and A and B finish the remaing work in 7 hours. Find the time taken by alone to fill the swimming pool.
Answer:
The pipe C alone can fill the tank in 14 hours .
Step-by-step explanation:
Given as :
The three pipes a , b , c can fill the pipes in 6 hours
They work for 2 hours
After that c pipe is close and a , b finish remaining work
Now, According to question
In 1 hour pipes ( a + b + c ) fill [tex]\frac{1}{6}[/tex] of the tank
∴ In 2 hour pipes ( a + b + c ) fill [tex]\frac{2}{6}[/tex] = [tex]\frac{1}{3}[/tex] of the tank
Remaining ( 1 - [tex]\frac{1}{3}[/tex] ) = [tex]\frac{2}{3}[/tex] part is filled by pipes a and b in 7 hours
∴ The whole tank is filled by a and b in 7 × [tex]\frac{3}{2}[/tex] = [tex]\frac{21}{2}[/tex] hours
∴ In 1 hour pipes A and b fill the tank in [tex]\frac{2}{21}[/tex] hours
∴ In 1 hour pipes C alone can fill the tank in[tex]\frac{1}{6}[/tex] - [tex]\frac{2}{21}[/tex] hours
Or, In 1 hour pipes C alone can fill the tank in [tex]\frac{9}{126}[/tex] = [tex]\frac{1}{14}[/tex]
Or, In 1 hour pipes C alone can fill the tank in 14 hours
Hence The pipe C alone can fill the tank in 14 hours . Answer
Carol has two cats rover and Bobo. Rover eat three fourths of a can of cat food each day and bobo eat a half of a can of cat food each day. Cat food cost five dollars for three cans. It's is only sold in three can packs. How much does it cost carol for a sixty day supply of cat food for her two cats.
Answer: A sixty day supply of cat food for her two cats will cost her $125
Step-by-step explanation:
Carol has two cats Rover and Bobo.
Let x = the quantity of a can of fast food.
Rover eats three fourths of a can of cat food each day. This means that Rover eats 3x/4 each day. Bobo eats a half of a can of cat food each day. This means that bobo eats x/2 each day.
Cat food costs five dollars for three cans. This means that 3x = 5
Total number of cans consumed by both dogs in a day is 3x/4 + x/2 =5x/4
That means the cost per day would be
(5x/4 × 5)/3x = 25x/4 ×1/3x
= 25/12
It costs her $25/12 per day
To determine the cost for 60 days, we would multiply the cost per day by 60. It becomes
25/12 × 60 = $125
A conical tank (with vertex down) is 10 feet across the top and 12 feet deep. If water is flowing into the tank at a rate of 10 cubic feet per minute, find the rate of change of the depth of the water when the water is 8 feet deep.
Answer:
[tex]\frac{dh}{dt}[/tex]≅[tex]0.286\frac{ft^{3} }{min}[/tex]
Step-by-step explanation:
[tex]V=\frac{\pi }{3}r^{2}h[/tex]; rate of change [tex]\frac{dV}{dt}=10\frac{ft^{3} }{min}[/tex], we must find the rate of change of the depth [tex]\frac{dh}{dt} =?;h=8ft[/tex]
5h=12r; [tex]V=\frac{\pi }{3}\({\((5h}/12} )} ^{2}h=\frac{\pi }{3}(\frac{25h^{2} }{144})h; V=\frac{25\pi h^{3}}{432}[/tex]; deriving [tex]\frac{dV}{dt} = \frac{25\pi }{432}(3h^{2})\frac{dh}{dt}[/tex] → [tex]10=\frac{25\pi h^{2}}{144} \frac{dh}{dt}[/tex] → h=8 then [tex]\frac{dh}{dt}=\frac{1440}{25\pi 64}=\frac{9}{10\pi}[/tex]≅ 0.286[tex]\frac{ft^{3} }{min}[/tex]
At the end of year X, automobile installment credit accounted for 36% of all outstanding consumer installment credit. At that time automobile finance companies extended $57 billion of credit, or 1/3 of the automobile installment credit. How many billion dollars of consumer installment credit was outstanding at that time?
A. 62
B. 171
C. 475
D. 513
E. 684
Answer:
475 billion dollars
Step-by-step explanation:
Let P be the customer credit
At the end of year X, 36% of P is gotten from automobile installment credit
57 billion credit is 1/3 of the automobile installment credit. This means that the total automobile installment credit 57*3 = 171 billion dollars
36% * P = 171
36/100 * P = 171
36P = 171 *100
P = 17100/36
P= 475 billion dollars
The pH of solution A is 2.4, while the pH of solution B is 9.4.
(a) What are their hydrogen-ion concentrations?
(b) How many times greater is the hydrogen-ion concentration of solution A than that of solution B?
(c) By how many orders of magnitude do the concentrations differ?
Answer:
The answer to your question is below
Step-by-step explanation:
pH definition
pH = - log [H⁺]
a) For pH = 2.4, solution A
2.4 = -log[H⁺]
[H⁺] = antilog⁻².⁴
[H⁺] = 0.00398
For pH = 9.4, solution B
[H⁺] = antilog⁻⁹.⁴
[H⁺] = 3.98 x 10⁻¹⁰
b) Divide hydrogen-ion concentration of solution A by hydrogen-ion concentration of solution B.
0.00398 / 3.98 x 10⁻¹⁰
10000000 times
c) By 7, because 7 is the number of zeros