Marisol and mimi walked the same distance from their school to a shopping mall. marisol walked 2 miles per hour, while mimi left 1 hour later and walked 3 miles per hour. if they reached the mall at the same time, how far from the mall is their school? answers

Answers

Answer 1

Marisol = 2 mph
Mimi = 3 mph and left 1 hour after Marisol had left

They arrived at the same time.
If Marisol took x hours to arrive, then Mimi took (x-1) hours. The distance was the same.

Distance, D = Speed*Time
Marisol: D = 2*x = 2x
Mimi: D = 3*(x-1) = 3x-3

then,
2x = 3x -3 => (2-3)x = -3 => -x = -3=> x = 3 hours

Therefore,
D =2x = 2*3 = 6 miles

Related Questions

A certain part of the electromagnetic spectrum ranges from 200 nm to 400 nm. what is the lowest frequency associated with this portion of the spectrum? (c 3.00 108 m/s)

Answers

The lowest and highest wavelengths of this part of the electromagnetic spectrum are:
[tex]\lambda_1 = 200 nm=200 \cdot 10^{-9} m[/tex]
[tex]\lambda_2 = 400 nm = 400 \cdot 10^{-9} m[/tex]

We can calculate the corresponding frequencies by using:
[tex]f= \frac{c}{\lambda} [/tex]
where c is the speed of light. If we use this equation, we find:
[tex]f_1 = \frac{c}{\lambda_1}= \frac{3 \cdot 10^8 m/s}{200 \cdot 10^9 m} =1.5 \cdot 10^{15}Hz[/tex]
[tex]f_2 = \frac{c}{\lambda_2}= \frac{3 \cdot 10^8 m/s}{400 \cdot 10^9 m} =7.5 \cdot 10^{14}Hz[/tex]
Therefore, the lowest frequency associated with this portion of the spectrum is
[tex]f_2 = 7.5 \cdot 10^{14} Hz[/tex]

with a bar magnet where are the lines of force closest together

Answers

At the tip of either of the magnets poles

Answer: at the tips of the magnet

Explanation: charges are more at the tip of a substance so likewise for a magnet

According to the Doppler affect what happens when a light surfaceMoves further away from an observer

Answers

The correct answer is The electromagnetic waves appear more in red color.
Since red is at the low-frequency end of the visible spectrum, we say that light from a receding star is shifted toward red, or redshifted.

Hello User

Answer: A

I hope I helped
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A 0.50-kg block attached to an ideal spring with a spring constant of 80 n/m oscillates on a horizontal frictionless surface. the total mechanical energy is 0.12 j. the greatest extension of the spring from its equilibrium length is:

Answers

Final answer:

The greatest extension of the spring from its equilibrium length is calculated through the formula for total energy in harmonic motion, given as 0.5 * k * x^2. When rearranged for displacement(x), and values substituted, the extension is found to be 0.155 meters or 15.5 cm.

Explanation:

In this problem, we are dealing with a block attached to an ideal spring and on a frictionless surface. The total mechanical energy, E, is given as 0.12 joules. We can use this information to find the peak displacement or the greatest extension, x, of the spring (amplitude) from its equilibrium length, using the formula E = 0.5*k*x^2.

The total energy of the system is the potential energy at the position of the greatest extension or amplitude, which means the block is momentarily at rest and has zero kinetic energy. Therefore, E = 0.5 * k * x^2, where E is the total energy, k is the spring constant, and x is the displacement.

Here, rearranging the formula to solve for the extension (x) we get x = sqrt((2*E)/k).

Substitute E = 0.12 joules and k = 80 N/m, into the equation. Therefore the greatest extension of the spring from its equilibrium length is x = sqrt((2*0.12 J)/80 N/m) = 0.155 meters or 15.5 cm.

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Final answer:

The greatest extension of the spring from its equilibrium length, which correlates to the amplitude A, is calculated from the given mechanical energy and spring constant. This can be determined by solving the equation for total mechanical energy, ETotal = (1/2)kA² for A. The calculation gives a maximum extension of approximately 15.5 cm.

Explanation:

The total mechanical energy of a block and spring system is equal to the potential energy stored in the spring at the maximum extension/compression because at these points all of the energy is potential and none is kinetic. The total mechanical energy is given by ETotal = (1/2)kA², where k is the spring constant and A is the amplitude, which is the maximum extension or compression of the spring from its equilibrium length.

In this circumstance, the total mechanical energy is 0.12 Joules, and the spring constant 'k' is 80 N/m. So we can solve the above equation for A, the maximum extension:

A = sqrt( (2 * ETotal) / k ) = sqrt( (2 * 0.12 J) / 80 N/m ) = 0.15494 meters,

which is about 15.5 cm (since 1 m = 100 cm).

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When light propagates from a material with a given index of refraction into a material with a smaller index of refraction, the speed of the light vie?

Answers

When light moves from a material with a higher index of refraction to one with a lower value, the speed of light increases, potentially causing the light to refract. The index of refraction ratio determines the extent of this change in speed.

When light travels from a material with a higher index of refraction to one with a lower index of refraction, the speed of light in the material increases. The index of refraction, denoted as n, is defined by the ratio n = c/v, where c is the speed of light in a vacuum (approximately 3.0 * 10⁻⁸ m/s), and v is the observed speed of light in the material.

Since the index of refraction for a vacuum is exactly 1 (because the speed of light in a vacuum is c), and since n is always greater than or equal to 1, when light enters a material with a smaller n, it means that v must increase."

For example, when light moves from water (where it travels slower due to a higher n) into air (with a smaller n), the light speeds up. This change in speed can cause the light to bend or refract. The extent to which this bending occurs depends on the difference in the indices of refraction between the two materials.

What form does the signal take while it is broadcast from a transmitting station to your radio or television, regardless of whether it is a digital or analog wave?

Answers

The answer is transverse waves.

What is the wavelength of a photon whose energy is twice that of a photon with a 622 nm wavelength?

Answers

The frequency of the [tex]\lambda_2 = 622 nm = 622 \cdot 10^{-9} m[/tex] wavelength photon is given by
[tex]f_2 = \frac{c}{\lambda_2}= \frac{3 \cdot 10^8 m/s}{622 \cdot 10^{-9} m}=4.82 \cdot 10^{14} Hz [/tex]
where c is the speed of light.

The energy of this photon is
[tex]E_2=hf_2 = (6.6 \cdot 10^{-34}Js)(4.82 \cdot 10^{14}Hz)=3.18 \cdot 10^{-19} J[/tex]
where h is the Planck constant.

The energy of the first photon is twice that of the second photon, so
[tex]E_1 = 2 E_2 = 2 \cdot 3.18 \cdot 10^{-19}J =6.36 \cdot 10^{-19} J[/tex]

And so now by using again the relationship betwen energy and frequency, we can find the frequency of the first photon:
[tex]f_1 = \frac{E_1}{h}= \frac{6.36 \cdot 10^{-19} J}{6.6 \cdot 10^{-34}Js}=9.64 \cdot 10^{14}Hz [/tex]

and its wavelength is
[tex]\lambda_1 = \frac{c}{f_1}= \frac{3 \cdot 10^8 m/s}{9.64 \cdot 10^{14}Hz} =3.11 \cdot 10^{-7}m = 311 nm [/tex]
So, we see that the wavelength of the first photon is exactly half of the wavelength of the second photon (622 nm).

What is the wavelength λ of light in glass, if its wavelength in air is λ0, its speed in air is c, and its speed in the glass is v? express your answer in terms of λ0, c, and v?

Answers

When an electromagnetic wave moves from a medium to another medium, its frequency remains constant. In this problem, we have light (which is an electromagnetic wave) moving from air to glass (or vice-versa), so we can write
[tex]f_0 = f[/tex] (1)
where [tex]f_0[/tex] is the frequency of the light in air, while f is the frequency in glass.

Using the relationship between frequency, wavelenght and speed of a wave, we have
[tex]f= \frac{v}{\lambda} [/tex]
where v is the speed of light in glass and [tex]\lambda[/tex] the wavelength in glass, and
[tex]f_0 = \frac{c}{\lambda_0} [/tex]
where c is the speed of light in air and [tex]\lambda_0[/tex] the wavelength in air. Using these two relationships, we can rewrite eq.(1) as
[tex] \frac{c}{\lambda_0}= \frac{v}{\lambda} [/tex]
and by re-arranging it, we find
[tex]\lambda= \frac{v}{c} \lambda_0 [/tex]

The wavelength λ of light in glass, if its wavelength in air is λ0, its speed in air is c, and its speed in the glass is v will be

[tex]\lambda=\dfrac{v}{c}\lambda_o[/tex]

What is wavelength?

The wavelength of any wave is defined as the distance between two max adjacent amplitudes, or the distance between two successive troughs or crest.

When an electromagnetic wave moves from a medium to another medium, its frequency remains constant. In this problem, we have light (which is an electromagnetic wave) moving from air to glass (or vice-versa), so we can write

[tex]f_o=f(1)[/tex] (1)

where is the frequency of the light in air, while f is the frequency in glass.

Using the relationship between frequency, wavelenght and speed of a wave, we have

[tex]f=\dfrac{v}{\lambda}[/tex]

where v is the speed of light in glass and the wavelength in glass, and

[tex]f_o=\dfrac{c}{\lambda_o}[/tex]

where c is the speed of light in air and the wavelength in air. Using these two relationships, we can rewrite eq.(1) as

[tex]\dfrac{c}{\lambda_o}=\dfrac{v}{\lambda}[/tex]

and by re-arranging it, we find

[tex]\lambda=\dfrac{v}{c} \lambda_o[/tex]

Hence the wavelength λ of light in glass, if its wavelength in air is λ0, its speed in air is c, and its speed in the glass is v will be

[tex]\lambda=\dfrac{v}{c}\lambda_o[/tex]

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Two astronauts are playing catch with a ball in space. The first astronaut throws the ball; and A) the ball moves, but the astronaut doesn’t. B) the ball moves, and so does the astronaut. C) the ball doesn’t move, but the astronaut does. D) the ball doesn’t move, and neither does the astronaut.

Answers

B) the ball moves, and so does the astronaut.

Two astronauts are playing catch with a ball in space. The first astronaut throws the ball, and the ball moves, and so does the astronaut because of the action-reaction law. When the ball goes forward, the astronaut goes backward.

plz give me the brainliest

Two astronauts are playing catch with a ball in the space. One astronaut throws the ball, then the ball moves, and so does the astronaut. Hence, option B is correct.

What is Newton's third law?

Newton's third law states that if two bodies meet, they exert forces on each other that are comparable in size and directed in the opposite direction.

Action and reaction law is another name for the third law. This law is critical in understanding issues involving static equilibrium, in which all the forces are in balance, but it also holds true for entities moving uniformly or quickly.

A game of catch is being played in space by two astronauts. A ball is thrown by the first astronaut, and thanks to the action-reaction rule, both the ball and the astronaut move. The astronaut is forced to move backwards as the ball advances.

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The potential energy due to the strong interaction, between two quarks or a quarkantiquark pair, goes something like v (r) = −α/r + βr, where α and β are positive constants. is there any point rv where the potential energy goes to zero? is there any point

Answers

Given that
V= x/r + Br.
If V=0 Then -x/r + Br = 0
→ -x + br²/r = 0
→Br² - x = 0
r² = x/B
r² = +₋ √x/B
Force = dv/dr = d/dr [ -x/r +Br]
F = -[ -x/-r² + B]
= [B +x/r²]
a,B are positive.
r² is constant and it can never be negative.
∴ [ B + x/r²] is a positive value.
V = 0 at r = ⁺₋√x/B for the value of r.

Find the ratio of the new/old periods of a pendulum if the pendulum were transported from earth to the moon, where the acceleration due to gravity is 1.63 m/s2 .

Answers

Final answer:

The period of a pendulum on the Moon is roughly 2.45 times longer than the period of a similar pendulum on Earth. This is due to the difference in gravitational forces on the two celestial bodies.

Explanation:

A pendulum's period is influenced by the acceleration due to gravity. On Earth, this is approximately 9.80 m/s². On the Moon, the gravitational pull is significantly weaker, approximating at about 1.63 m/s². Therefore, if a pendulum were taken from Earth to the Moon, its period would change due to the variance in gravitational forces.

The ratio of the new period (Tmoon) to the old period (Tearth) is determined by the square root of the ratio of the gravities: Tmoon/Tearth = sqrt(g earth / g moon)

Substituting values, we get Tmoon/Tearth = sqrt(9.80 / 1.63) = 2.45 (rounded).

So, the period of a pendulum on the Moon is about 2.45 times longer than that of the same pendulum on Earth.

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Calculate the absolute pressure at the bottom of a freshwater lake at a point whose depth is 27.8 m. assume the density of the water is 1.00 103 kg/m3 and the air above is at a pressure of 101.3 kpa.

Answers

The relative pressure at the bottom of the lake is given by
[tex]p_r = \rho g h[/tex]
where
[tex]\rho[/tex] is the water density
g is the gravitational acceleration
h is the depth at which the pressure is measured

At the bottom of the lake, h=27.8 m, so the relative pressure is
[tex]p_r = (1\cdot 10^3 kg/m^3)(9.81 m/s^2)(27.8 m)=2.72 \cdot 10^5 Pa[/tex]

To find the absolute pressure, we must add the atmospheric pressure, [tex]p_a[/tex], to this value:
[tex]p=p_r + p_a =2.72 \cdot 10^5 Pa + 1.013 \cdot 10^5 Pa =3.74 \cdot 10^5 Pa[/tex]

A magnetic field of 0.55 g is directed straight down, perpendicular to the plane of a circular coil of wire that is made up of 550 turns and has a radius of 20 cm. 1) if the coil is stretched, in a time of 35 ms, to a radius of 50 cm, calculate the emf induced in the coil during the process.

Answers

The emf induced in the coil is given by Faraday-Neumann-Lenz law:
[tex]\epsilon = - \frac{\Delta \Phi}{\Delta t} [/tex]
where
[tex]\Delta \Phi[/tex] is the variation of magnetic flux through the coil
[tex]\Delta t[/tex] is the time interval

The magnetic field intensity is
[tex]B=0.55 G \cdot (1 \cdot 10^{-4} T/G) = 0.55 \cdot 10^{-4} T[/tex]

Since the magnetic field strength is constant, the variation of flux through the coil is given by
[tex]\Delta \Phi = N B \Delta A[/tex] (1)
where N=550 is the number of turns, while [tex]\Delta A[/tex] is the variation of area of the coil. We can re-write (1) as
[tex]\Delta \Phi = NB (\pi r_1^2 - \pi r_2^2)=(550)(0.55 \cdot 10^{-4} T)(\pi (0.20m)^2-\pi (0.50m)^2) =[/tex]
[tex]=-0.020 Wb[/tex]

The time interval is [tex]\Delta t=35 ms=0.035 s[/tex], therefore the induced emf is
[tex]\epsilon = - \frac{\delta \Phi}{\Delta t}=- \frac{-0.020 Wb}{0.035 s}=0.57 V [/tex]

Allison wants to calculate the speed of a sound wave. Which formula should she use?
distance traveled / amplitude
number of wavelengths / amplitude
number of wavelengths / time
distance traveled / time

Answers

the true answer is distance traveled / time
because the speed of propagation of sound wave formula is the quotient of the distance traveled by a sound shaking by the time required on arrival. on edguinuity

Answer:

Option 4th is correct

distance traveled / time

Explanation:

Allison wants to calculate the speed of a sound wave.

The speed of the sound wave is the distance traveled divided by the time.

[tex]v = \dfrac{d}{t}[/tex]

Where, v = speed of sound

d = distance

t= time

Therefore, The formula should she use is, distance traveled / time

A parallel circuit has two 8.0-ohm resistors and a power source of 9.0 volts. If a 12.5-ohm resistor is added to the circuit in parallel, how will the current be affected and what value will it have?

Answers

The initial equivalent resistance of the circuit is
[tex] \frac{1}{R_{eq}}= \frac{1}{R_1}+ \frac{1}{R_2}= \frac{1}{8 \Omega}+ \frac{1}{8 \Omega} = \frac{1}{4 \Omega} [/tex]
which means
[tex]R_{eq}= 4 \Omega[/tex]
Therefore the initial current in the circuit is
[tex]I= \frac{V}{R}= \frac{9 V}{4 \Omega}=2.25 A [/tex]

When the new resistor of [tex]12.5 \Omega[/tex] is added to the circuit in parallel, the new equivalent resistance of the circuit is
[tex] \frac{1}{R_{eq}} = \frac{1}{8 \Omega} + \frac{1}{8 \Omega}+ \frac{1}{12.5 \Omega}= 0.33 \Omega^{-1}[/tex]
from which we find
[tex]R_{eq}=3 \Omega[/tex]
This means that the equivalent resistance of the circuit has decreased, and the new current is
[tex]I= \frac{V}{R_{eq}}= \frac{9 V}{3 \Omega}=3 A [/tex]
which means that the current in the circuit has increased.

Answer:

1/R1 + 1/R2 + ... = 1/Re

So...

1/17.2 + 1/22.4 = 1/Re

0.1021 = 1/Re

Re = 9.792 Ohms

Now use the Voltage equation V = IR

6 = I * 9.792

I = 6/9.792 = 0.613 Amps.Pato 0.61

Explanation:

Jupiter _____.

may have prevented asteroids from forming a planet
has a large gravitational field which can capture small comets
is responsible for creating most known meteors and meteoroids
releases radiation which warms comets and creates a comet tail

Answers

It's a because i chose this and got it right

Answer:

Jupiter may have prevented asteroids from forming a planet

Explanation:

A particle is attached to a spring and is pushed so that the spring is compressed more and more. As a result, the spring exerts a greater and greater force on the particle. Similarly, a charged particle experiences a greater and greater force when pushed closer and closer to another particle that is fixed in position and has a charge of the same polarity. In spite of the similarity, the charged particle will not exhibit simple harmonic motion on being released, as will the particle on the spring. Explain why not.

Answers

In order for particles to perform a simple harmonic motion, we must follow the law of force of the form F = -kx, where x is the displacement of the object from the equilibrium position and k is the spring constant. The force shown in F = -kx is always the restoring force in the sense that the particles are pulled towards the equilibrium position.

The repulsive force felt when the charge q1 is pushed into another charge q2 of the same polarity is given by Coulomb's law
F = k *q1* q2 / r^2.
It is clear that Coulomb's law is an inverse-square relationship. It does not have the same mathematical form as the equation F = -kx. Thus, charged particles pushed towards another fixed charged particle of the same fixed polarity do not show a simple harmonic motion when released. Coulomb's law does not describe restoring force. When q1 is released, it just fly away from q2 and never returns.

Physics 1315, what is faster speed; red light or gamma rays?

Answers

They travel at the same rate of speed

a 10.0 kg ball falling at 10.0 m/s hits a mattress and comes to a complete stop in 1 s. what force does the mattress exert to stop the ball

Answers

Using Newton's second law;

F = ma, where m = mass, a = acceleration or deceleration

a = Δv/t = (v-u)/t, but v= 0, u = 10 m/s, t = 1.
Then,
a = (0-10)1 = -10 m/s^2

Substituting;
F = ma = 10*-10 = -100 N

The mattress exerts 100 N to stop the ball.

What keeps an inflated balloon from falling down if you rub it against your hair and place it against a wall? 1. rubbing distorts the atoms inside the ballon and polarizes it. 2. rubbing leaves a balloon electrically charged; the charged balloon polarizes the wall. 3. when you rub the balloon against your hair, it will remove some m?

Answers

The answer is: rubbing leaves a balloon electrically charged; the charge polarizes the wall

there is no friction here

A balloon sticks to a wall after being rubbed on your hair because the friction causes electrons to move from your hair to the balloon, giving it a negative charge that attracts to the slightly positively charged surface.

When you rub a balloon against your hair, the balloon becomes electrically charged due to the transfer of electrons. This process is known as the triboelectric effect, where friction causes electrons to be transferred from your hair to the balloon. As a result, the balloon holds a negative charge while your hair holds a positive charge.

Due to this, the charged balloon can polarize the wall's molecules, causing the opposite charges to attract, which keeps the balloon stuck to the wall temporarily.

Which of these is a cultural service—a non material benefit people get from the environment

Answers

The answer is Providing national parks

Answer: providing national parks

Explanation:

Which of these statements would best explain the problem encountered with nuclear waste disposal?

Answers

A) The isotopes have a long half-life and only remain radioactive for a long time period.

Answer: A

Explanation:

A silver wire has a cross sectional area a = 2.0 mm2. a total of 9.4 × 1018 electrons pass through the wire in 3.0 s. the conduction electron density in silver is 5.8 × 1028 electrons/m3 and e = 1.60 × 10-19
c. what is the drift velocity of these electrons?

Answers

Final answer:

The drift velocity of electrons in a silver wire given an electron density of 5.8 x 10^28 electrons/m3, a cross-sectional area of 2.0 mm2, and a total of 9.4 x 10^18 electrons passing through in 3.0 s, is approximately 1.08 x 10^-4 m/s.

Explanation:

The drift velocity of electrons is a term used in physics to describe the average velocity that free charges such as electrons traverse in a material due to an externally applied electric field. Given the cross-sectional area (A), the number of electrons (Q), the time (t), the charge of an electron (e), and the electron density (n), you can determine the drift velocity (v) using the formula:

v = Q / (n * A * t)

Firstly, convert the cross-sectional area to m² since the electron density is given in 1/m³. So, the area would be 2.0 mm² = 2.0 x 10^-6 m².

To determine the number of electrons passing through during the given time period (3.0 s), we substitute what we know into the formula giving:

v = (9.4 x 10^18) / (5.8 x 10^28 x 2.0 x 10^-6 x 3.0)

This yields a drift velocity of 1.08 x 10^-4 m/s.

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To what potential should you charge a 3.0 μf capacitor to store 1.0 j of energy?

Answers

The energy stored in a capacitor is given by:
[tex]U= \frac{1}{2}CV^2 [/tex]
where
U is the energy
C is the capacitance
V is the potential difference

The capacitor in this problem has capacitance
[tex]C=3.0 \mu F = 3.0 \cdot 10^{-6} F[/tex]
So if we re-arrange the previous equation, we can calculate the potential V that should be applied to the capacitor to store U=1.0 J of energy on it:
[tex]V= \sqrt{ \frac{2U}{C} }= \sqrt{ \frac{2 \cdot 1.0 J}{3.0 \cdot 10^{-6}F} }=816 V [/tex]

To store 1.0 J of energy in a 3.0 μF capacitor, you should charge it to approximately 816.5 V.

To determine the potential (V) needed to charge a 3.0 μF capacitor to store 1.0 J of energy, we can use the formula for the energy stored in a capacitor:

Energy (E) = 0.5 × C × V²

Where:

E is the energy stored (1.0 J in this case)C is the capacitance (3.0 μF or 3.0 × 10⁻⁶F)V is the potential difference we need to find

Rearranging the formula to solve for V:

V² = (2E)/C

Substituting the given values:

V² = (2 × 1.0 J) / (3.0 × 10⁻⁶ F)

V² = 2.0 J / 3.0 × 10⁻⁶ F

V² = 666666.67 V²

Taking the square root of both sides:

V ≈ 816.5 V

Therefore, you should charge the 3.0 μF capacitor to approximately 816.5 V to store 1.0 J of energy.

Acceleration is best defined as the rate of change of ________ of an object.

Answers

Acceleration is best defined as the rate of change of ________ of an object. ANSWER: velocity!

Answer:

Velocity

Explanation:

Remember that acceleration is given by the next formula:

Acceleration: Vf-Vo/Time

Where Vf final velocity and Vo is initial velocity, so acceleration of an object is best defined as the change in velocity the an object experiences in a certain period of time, it is often described in M/s^2 and those are the units in the international system.

A calorie is the measurement of ____ required to raise a 1 gram of water 1 degree celsius.

Answers

Calorie is a unit of energy, it is used above all in the area of health to measure the energy content of food.

Therefore the statement must be completed in the following way:

A calorie is the measure of heat required to raise 1 gram of water 1 centigrade.

I need help finding the answer:
When a guitar string plays the note "A", the string vibrates at 440 Hz. What is the period of the vibration?

Answers

The formula applicable:

Period, T = 1/f --- Where T = period (s), and f = frequency (Hz).

Substituting by use of the values of frequency given in the current scenario,

T = 1/440 = 2.27*10^-3 seconds

Final answer:

The period of the guitar string's vibration when it plays the note 'A' is approximately 0.00227 seconds.

Explanation:

In physics, the period of vibration refers to the time it takes for a single complete cycle of vibration to occur. It is usually represented by the symbol T and is measured in seconds. To find the period of the guitar string's vibration, you can use the formula T = 1/f, where f is the frequency of the vibration.

In this case, the frequency of the guitar string playing the note 'A' is given as 440 Hz. So, the period can be calculated as T = 1/440 = 0.00227 seconds.

Therefore, the period of the guitar string's vibration when it plays the note 'A' is approximately 0.00227 seconds.

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What method of forecasting uses the effects of past weather conditions as part of its forecasting method

Answers

Analog method is the answer :)

the method is analog forecasting method

analog forecasting method uses the past weather data and compares it with the existing one to forecast. it is a complex method since it involves remembering previous data for whether that can be triggered by a specific event.

An electron in the n = 5 level of an h atom emits a photon of wavelength 1282.17 nm. to what energy level does the electron move?

Answers

The electron moves to energy level n = 3

[tex]\texttt{ }[/tex]

Further explanation

The term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is :

[tex]\large {\boxed {E = h \times f}}[/tex]

E = Energi of A Photon ( Joule )

h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )

f = Frequency of Eletromagnetic Wave ( Hz )

[tex]\texttt{ }[/tex]

The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.

[tex]\large {\boxed {E = \frac{1}{2}mv^2 + \Phi}}[/tex]

[tex]\large {\boxed {E = qV + \Phi}}[/tex]

E = Energi of A Photon ( Joule )

m = Mass of an Electron ( kg )

v = Electron Release Speed ( m/s )

Ф = Work Function of Metal ( Joule )

q = Charge of an Electron ( Coulomb )

V = Stopping Potential ( Volt )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

initial shell = n₁ = 5

wavelength = λ = 1282.17 nm = 1.28217 × 10⁻⁶ m

Unknown:

final shell = n₂ = ?

Solution:

We will use this following formula to solve this problem:

[tex]\Delta E = R (\frac{1}{(n_2)^2} - \frac{1}{(n_1)^2})[/tex]

[tex]h \frac{c}{\lambda} = R (\frac{1}{(n_2)^2} - \frac{1}{(n_1)^2})[/tex]

[tex]6.63 \times 10^{-34} \times \frac{3 \times 10^8}{1.28217 \times 10^{-6}} = 2.18 \times 10^{-18} \times ( \frac{1}{(n_2)^2} - \frac{1}{5^2})[/tex]

[tex]1.55128 \times 10^{-19} = 2.18 \times 10^{-18} \times ( \frac{1}{(n_2)^2} - \frac{1}{5^2})[/tex]

[tex]( \frac{1}{(n_2)^2} - \frac{1}{5^2}) = \frac{16}{225}[/tex]

[tex]\frac{1}{(n_2)^2} = \frac{1}{25} + \frac{16}{225}[/tex]

[tex]\frac{1}{(n_2)^2} = \frac{1}{9}[/tex]

[tex](n_2)^2 = 9[/tex]

[tex]n_2 = \sqrt{9}[/tex]

[tex]\boxed{n_2 = 3}[/tex]

[tex]\texttt{ }[/tex]

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[tex]\texttt{ }[/tex]

Answer details

Grade: College

Subject: Physics

Chapter: Quantum Physics

Final answer:

We can use the Rydberg formula to find out to which energy level an electron will move after emitting a certain wavelength of photon. Inserting the given values of photon wavelength and initial energy level will provide us the final energy level to which the electron moves. In this case, it moves to energy level n = 2.

Explanation:

The subject of this question involves examining the transition of an electron in a hydrogen atom after emitting a photon. Given we know the wavelength of the emitted photon, we can determine the initial and final energy levels, then calculate the transition the electron undergoes. We can use the Rydberg formula, R = 1.097373 x 107 m-1, which relates the wavelength of light emitted to the energy levels in an atom.

We find:

1/λ = R x (1/nf2 - 1/ni2)

Where:

λ = wavelength of lightR = Rydberg constantnf = final energy levelni = initial energy level

By inserting the given data, we see:

1/1282.17 x 10-9 m = R x (1/nf2 - 1/52)

Solving this equation gives nf = 2. Therefore, the electron moves to the energy level n = 2 after emitting the photon.

Learn more about Photon emission and electron transition here:

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Why are conductors and insulators both required to construct the electrical wiring in our home

Answers

Conductors are materials with many free electrons, so they allow electrical current to flow through them. Therefore, conductors are required in order to bring electricity to every room of the house.

Insulators, instead, are materials with few or no free electrons, so electrical currents do not flow through them. In the electrical wiring of the houses, they are used in order to isolate the conductive elements of the wire from other conductive materials (in fact, if the conductive elements touch other conductive elements of the house, part of the current would be dissipated)

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