Message are carried from the eye to the brain by

D

Nuclear reaction involves the nuclei of atoms. The nucleus can either split (as is the case with fission) of fuse as is the case with nuclear fusion. Remember the main particles in the nucleus are protons and neutrons.

Explanation:

In nuclear fission, atomic nuclei split into lighter atoms through loss of protons and neutrons (such as through loos of a beta particles - 2 protons and 2 neutrons). In the case of fusion, two atomic nuclei fuse under pressure (hence adding neutrons and protons) to create heavier atoms (2 hydrogens can fuse to form a helium). Electrons are not involved in nuclear reactions. Electrons are mainly involved in chemical reactions.

Learn More:

For more on nuclear fission and fusion check out;

https://brainly.com/question/913303

https://brainly.com/question/10245756

https://brainly.com/question/11354515

https://brainly.com/question/2005577

https://brainly.com/question/2005577

#LearnWithBrainly

Answer:

[tex]2Mg+O_{2} \rightarrow 2MgO[/tex]

Explanation:

Synthesis reaction:

In the synthesis reaction, two reactants combined to form a single product.

For example,

"A" and "B" are two reactants then combined to form a "AB" product.

The chemical reaction is as follows.

[tex]A+B \rightarrow AB[/tex]

The product "MgO" is formed by magnesium reacts with oxygen to form Magnesium oxide.

The chemical reaction is as follows.

[tex]2Mg+O_{2} \rightarrow 2MgO[/tex]

In a synthesis reaction to create MgO, magnesium and oxygen combine, each molecule of magnesium combining with half a molecule of oxygen to produce a molecule of magnesium oxide. The MgO product is a white crystalline solid at room temperature. This follows the general AB form synthesis reaction.

The synthesis reaction to create MgO from its elemental components is represented by the simple equation:

In this reaction, magnesium (Mg) combines with oxygen (O₂) to form magnesium oxide (MgO). To balance the equation, we use 0.5 moles of oxygen for every mole of magnesium. The principle of conservation of mass requires that the number of each type of atom is consistent on both sides of the equation.

The product, magnesium oxide, is a white crystalline solid at room temperature. When considering the general form of a synthesis reaction, AB, magnesium (A) and oxygen (B) come together to form magnesium oxide (AB).

https://brainly.com/question/25004705

#SPJ11

They are different subjects

In science we study physical , chemical and biological things

In maths we study about data handling, algorithms etc

In social we study about political economical and historical things

Answer:

hey are different subjects

In science we study physical , chemical and biological things

In maths we study about data handling, algorithms etc

In social we study about political economical and historical things

Explanation:

Answer:

element having 2+ valence electrons can transfer its more than one electron that is 2 electron completely.

Explanation:

Examples:

Cu²⁺, Mg²⁺, Sr²⁺ are examples having  2+ valance electron

one of the following is examples of element that have 2+ valence electrons

MgCl₂

Atomic number of Magnesium (Mg) is 12

Electronic Configuration of Mg:

1s², 2s², 2p⁶, 3s²

or

K =2

L = 8

M = 2

So, it have to give its 2 electrons to form a stable compound.

Similarly

Chlorine atomic number is 17

Electronic Configuration of Chlorine:

1s², 2s², 2p⁶, 3s², 3p⁵

or

K =2

L = 8

M = 7

So, it have to gain one electrons to form a stable compound and complete its octet.

So,

Two chlorine atom as a molecule gain 2 electrons from Mg²⁺ atom

So one Mg²⁺ and 2 Cl⁻ atoms form an ionic bond

where in this ionic bond Mg²⁺ transfer its 2 valence electron completely and chlorine molecule accept 2 electrons.

                 Cl-----Mg------Cl

So the Answer is

element having 2+ valence electrons can transfer its more than one electron that is 2 electron completely.

Answer:

The Awnser Is A. 0.325 Liters

Explanation:

Answer:

The density is : 0,75 g/cm3

Explanation:

We use the formula

density= mass/volume = 480 g/ 640cm3= 0, 75 g/cm3

Answer:

D. They tend to react in similar ways.

Explanation:

A is not correct, as there is only one gas in Group 16--that being oxygen

B is not correct, as these elements actually tend to react a lot with others elements

C is not correct, as there is only three nonmetals in Group 16--those being oxygen, sulfur, and selenium

Therefore, by process of elimination, answer D. is correct

Answer:

D) speed

Explanation:

Reaction rates can be affected by several factors, including concentration, temperature, surface area and presence of a catalyst. Increasing concentration increases the number of effective collisions. Increasing temperature increases the kinetic energy of the particles, leading to more effective collisions

Answer:

D

Explanation:

Speed

x = 20 long tables

y = 5 round table

Explanation:

We have the following system of equations:

x + y = 25

8x + 6y = 190

From the first equation we have:

x = 25 - y

And we replace x in the second equation:

8(25 - y) + 6y = 190

200 - 8y + 6y = 190

200 - 2y = 190

200 - 190 = 2y

10 = 2y

y = 5

Now we insert the value of y in the next equation:

x = 25 - y

x = 25 - 5

x = 20

Learn more about:

system of equations

https://brainly.com/question/1748197

https://brainly.com/question/1658819

#learnwithBrainly

Given the total number of tables and the number of seats they provide, we can derive a system of linear equations to solve for the number of each type of table.

This is a problem of linear algebra. Given that the total number of tables is 25 and each type of table seats a different number of people, we can set up the following system of equations:
 Equation 1): x + y = 25 (This equation comes from the fact that there are 25 tables total, a sum of long rectangular tables, x, and round tables, y.)
 Equation 2): 8x + 6y = 190 (This equation comes from the fact that all the seats at the tables are occupied and we know how many people each type of table can seat.) Solving these equations simultaneously will give us the values of x and y. This type of problem is common in Systems of Linear Equations in algebra.

https://brainly.com/question/34459204

#SPJ11

Answer:

A gas that exerts a pressure of 14 bar  in a container with a volume of 312 mL will exert a pressure of 6.7 bar when transferred to a container with a volume of 652 mL.

Explanation:

Given data;

Initial pressure = 14 bar

Initial volume  = 312 mL

Final pressure = ?

Final volume = 652 mL

Solution:

P₁V₁ = P₂V₂

P₂ = P₁V₁  / V₂

P₂ = 14 bar 312 mL / 652 mL

P₂ = 4368 bar. mL /652 mL

P₂ = 6.7 bar

A gas that exerts a pressure of 14 bar  in a container with a volume of 312 mL will exert a pressure of 6.7 bar when transferred to a container with a volume of 652 mL.

Answer:

P₁V₁ = P₂V₂

P₂ = P₁V₁  / V₂

P₂ = 14 bar 312 mL / 652 mL

P₂ = 4368 bar. mL /652 mL

P₂ = 6.7 bar

A gas that exerts a pressure of 14 bar  in a container with a volume of 312 mL will exert a pressure of 6.7 bar when transferred to a container with a volume of 652 mL.

Explanation:

Answer:

Empirical formula: CH₃O

Empirical formula mass = 31 g/mol

Explanation:

Data Given:

Molecular Formula = C₁₀H₃₀O₁₀

Empirical Formula = ?

Empirical Formula mass =

Solution

Empirical Formula:

Empirical formula is the simplest ration of atoms in the molecule but not all numbers of atoms in a compound.

So,

The ratio of the molecular formula should be divided by whole number to get the simplest ratio of molecule

As

C₁₀H₃₀O₁₀ Consist of  10 Carbon (C) atoms, 30 Hydrogen (H) atoms, and 10 Oxygen (O) atoms.

Now

Look at the ratio of these three atoms in the compound

                         C : H : O

                        10 : 30 : 10

Divide the ratio by two to get simplest ratio

                          C      :   H      :    O

                         10/10 : 30/10 : 10/10

                             1 : 3 : 1

So for the empirical formula the simplest ratio of carbon to hydrogen to oxygen is 1:3:1

So the empirical formula will be

                     Empirical formula of C₁₀H₃₀O₁₀ =  CH₃O

Now

To find the empirical formula mass in g/mol

Formula mass:

Formula mass is the total sum of the atomic masses of all the atoms present in a formula unit.

**Note:

if we represent the molar mass of the empirical formula for one mol in grams then it is written as g/mol

So,

As the empirical formula of C₁₀H₃₀O₁₀ is CH₃O

Then Its empirical formula mass will be

CH₃O

Atomic Mass of C = 12

Atomic Mass of H = 3

Atomic Mass of O = 16

Total Molar mass of CH₃O

CH₃O = 12 + 3(1) + 16

CH₃O = 12 + 3 + 16

CH₃O = 31 g/mol

The empirical formula for C10H30O10 is C5H15O5 with an empirical formula mass of 151.15 g/mol.

Empirical formula: The empirical formula for C10H30O10 is C5H15O5.

Empirical formula mass: The empirical formula mass can be calculated by summing the atomic masses of the elements in the empirical formula: C = 12.01 g/mol, H = 1.008 g/mol, O = 16.00 g/mol. Therefore, the empirical formula mass is (5*12.01) + (15*1.008) + (5*16.00) = 151.15 g/mol.

Answer:

N and P

Explanation:

Anion:

When an atom gain the electrons anion is formed. The negative sign shows that atom gain electron because number of electron are greater than protons or we can say that negative charge becomes greater than positive charge.

Cation:

When atom lose electron cation is formed. The atom thus have positive charge because number of positive charge i.e protons are increased are greater than negative charge or electron.

In given problem N and phosphorus both can gain three electrons which means negative charge becomes greater that's why the extra electron gained by atoms are written as -3 and both form anion with charge -3.

while Al form cation with charge +3 Mg form cation with charge +2 and iodine and bromine both form anion with charge of -1.

Answer:

[tex]\large \boxed{\text{1.38 g}}[/tex]

Explanation:

Two important formulas in radioactive decay are

[tex](1) \qquad t_{\frac{1}{2}} = \dfrac{\ln 2}{k}\\\\(2) \qquad \ln \left(\dfrac{N_{0}}{N}\right) = kt[/tex]

1. Calculate the decay constant k

[tex]\begin{array}{rcl}t_{\frac{1}{2}} &=& \dfrac{\ln 2}{k}\\\\\text{12.32 yr} &= &\dfrac{\ln 2}{k}\\\\k & = & \dfrac{\ln 2}{\text{12.32 yr}}\\\\& = & \text{0.056 26 yr}^{-1}\\\end{array}[/tex]

2. Calculate the mass remaining

[tex]\begin{array}{rcl}\ln \left(\dfrac{A_{0}}{A}\right) &= &kt \\\\\ln \left(\dfrac{\text{3.20 g}}{A}\right) &= &\text{0.056 26 yr}^{-1}\times \text{15 yr} \\\\\ln \left(\dfrac{\text{3.20 g}}{A}\right) &= &0.8439 \\\\\dfrac{\text{3.20 g}}{A} &= &e^{0.8439} \\\\\dfrac{\text{3.20 g}}{A}&= &2.325 \\\\A &= &\dfrac{\text{3.20 g}}{2.325}\\\\&= & \textbf{1.38 g}\\\end{array}\\\text{The final mass of the sample will be $\large \boxed{\textbf{1.38 g}}$}[/tex]

Answer: n = 1.30g

Explanation:

8.386 × 10^-23 moles

We are given;

We are required to determine the number of moles

In this case;

1 mole of Ba contains 6.022 × 10^23 atoms

Number of moles = 50.5 atoms ÷ 6.022 × 10^23 atoms

                             = 8.386 × 10^-23 moles

The number of moles in 50.5 atoms of Ba is 8.386 × 10^-23 moles

Answer:

The pOH of the solution is 13.176

Explanation:

The concentration of [tex]H_{3}PO_{4}[/tex] solution is 0.05 M

[tex]H_{3}PO_{4}[/tex] produces [tex]3\:H^{+}\:ions\:[/tex].

[tex]H_{3}PO_{4}\longrightarrow3H^{+}+PO_{4}^{3-}[/tex]

If the concentration of [tex]H_{3}PO_{4}[/tex] is 0.05 M, then the concentration of [tex]H^{+}\:ions\:[/tex] is three times that of [tex]H_{3}PO_{4}[/tex].

[tex][H^{+}]=3\times0.05=0.15M[/tex]

pH =-㏒([tex][H^{+}][/tex])= -㏒(0.15) =0.824

pOH = 14 - pH = 13.176

Answer:

Yes

Explanation:

Np²³⁷   →  He⁴ + Am²³³

The given nuclear equation is balanced. Np²³⁷ undergoes alpha decay and produce alpha particle and Am²³³.

Properties of alpha radiation:

Alpha radiations are emitted as a result of radioactive decay. The atom emit the alpha particles consist of two proton and two neutrons. Which is also called helium nuclei. When atom undergoes the alpha emission the original atom convert into the atom having mass number 4 less than and atomic number 2 less than the starting atom.

Alpha radiations can travel in a short distance.

These radiations can not penetrate into the skin or clothes.

These radiations can be harmful for the human if these are inhaled.

These radiations can be stopped by a piece of paper.

₉₂U²³⁸   →   ₉₀Th²³⁴  + ₂He⁴  + energy

Answer:

9.92 mol/L*s

Explanation:

Given data:

Rate of reaction = 0.62 mol/L*s

Temperature = 6°C

Rate of reaction at 46°C = ?

Solution:

There are 10 increase in four time of given temperature.

6+10 = 16

16+ 10 = 26

26+10 = 36

36=10 = 46

According to thumb rule,

By doubling the reaction four time the rate will be,

0.62 mol/L*s ×2⁴

0.62 mol/L*s × 16

9.92 mol/L*s

Answer:

1.1 x 10^4 J

Explanation:

Final answer:

The heat gained by the water when a metal sample is dropped into it can be determined using the formula q = mcΔT. For the given scenario, the water gains approximately 11000 J of heat.

Explanation:

To calculate the amount of heat gained by the water when a sample of metal is dropped into it, we can use the formula q = mcΔT, where q is the heat absorbed or released, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.

For water, the specific heat capacity (c) is typically 4.184 J/g°C.

In this case, the water's mass (m) is 400.0 g and the change in temperature (ΔT) is 28.0 °C - 21.4 °C = 6.6 °C.

Using the formula, we get q = 400.0 g × 4.184 J/g°C × 6.6 °C, which equals approximately 11016 J.

Since the question specifies to use the correct number of significant figures, we report the answer as 11000 J of heat gained by the water.

The question focuses on calculating the mass of water using its density and volume, requiring an understanding of physics concepts and the correct application of significant figures and units.

The question provided involves calculating the mass of water based on its density and volume, which is a fundamental concept in physics. To determine the mass of water, you use the formula mass = density × volume. The density of water is given as 1.000 ×10³ kg/m³, and various examples of volume calculations are provided, illustrating different contexts in which this calculation might be applied.

One specific calculation detailed is m = (1.000 × 10³ kg/m³) (2.00 × 10³ m³) = 1.00 × 10¸ kg, demonstrating how to apply the density-volume relationship. Another example provided is using a volume of 2.00 × 10¹ m³, resulting in a mass of 2.00 × 10±² kg. These calculations emphasize the importance of properly applying significant figures and units in physics problems.

Answer:

Explanation:

Pure Substance: are those having same type of atoms or molecules.

Compound: one or more atoms of the element combine to form a compound.

Mixture: is combination of one or more substances mix together.

Homogeneous Mixture: are those which are not distinguish by naked eye but can be separated into its components by physical means

Heterogeneous mixture: are those which can be distinguished by naked eye and can be separated into its components by physical means.

The complete detail of your answer in attachment

Answer:

D.

Explanation:

Energy is released after reaction, so this is exothermic reaction. D

Answer:

D

Explanation:

First of all, the reaction is exothermic. The equation is not normally written this way. The way it is written shows that energy is given off: the heat is a product. The only answer that is described is D

Exothermic (but oddly presented) and energy given off.

Answer:

P₂ = 0.7 atm.

Explanation:

Given data;

Initial Volume = 310 mL

Initial Pressure = 0.995 atm

Final volume = 440 mL

Final pressure = ?

Solution;

P₁V₁ = P₂V₂

P₂ = P₁V₁/V₂

P₂ =  0.995 atm . 310 mL / 440 mL

P₂ =  308.45 atm. mL /440 mL

P₂ = 0.7 atm.

Answer:

Substances generate a smell when their molecules land on so-called olfactory neurones in our noses (which, for some things, is a pretty unpleasant thought). ... But this fails to explain why some molecules with similar shapes can smell completely different, while others with quite different shapes can have a similar scent.

Explanation:

I took chemistry

Different substances have different odors because they release unique molecular compounds into the air that are detected by olfactory receptors in the nose. Humans can distinguish a vast number of scents due to the variety of olfactory receptors we possess. Our sense of smell, tightly linked to our sense of taste, is crucial for our interactions with the environment and can evoke strong emotional responses.

Why Do Different Substances Have Different Odors?

Different substances have different odors because each releases unique molecules into the air, which interact with the olfactory receptors in the nose. Humans have approximately 350 olfactory receptor subtypes that combine to distinguish roughly 10,000 different odors. In contrast, animals like mice have around 1,300 receptor types, indicating a possibly broader range of detectable scents. When odor molecules, also known as odorants, enter the nose, they dissolve in the olfactory epithelium, stimulating the receptors, and send signals directly to the olfactory bulb of the brain. The complexity of the sense of smell is sophisticated enough that humans can differentiate an estimated 1.72 trillion different detectible smells according to research by Bushdid et al. (Science, 343, 2014).

Our sense of taste is also closely connected to our olfactory sense. Taste buds and odor receptors collaborate to create the perception of flavor, and when our ability to smell is inhibited, such as with congested nasal passages, our perception of taste is similarly diminished. Substances with different molecular structures stimulate different receptors, accounting for the wide array of smells we can detect, ranging from pleasant scents to the objectionable odors of thiols, such as those found in skunk spray. Odorants can evoke powerful emotional responses and memories, making our sense of smell an important aspect of our daily experiences and interactions with the world around us.

https://brainly.com/question/34146658

#SPJ2

83.23 %

We are given;

We are required to get the mass percent of NH₄Cl in the original sample

Mass of NH₄Cl = Total mass of the mixture - remaining mass after sublimation

                         = 12.94 g - 2.17 g

                          = 10.77 g

% of NH₄Cl by mass =(Mass of NH₄Cl÷Total mass of original sample)×100

                                  = (10.77 g ÷ 12.94 g) × 100

                                  = 83.23 %

Therefore, the percent by mass of NH₄Cl in the original sample is 83.23%

Answer:

Osmosis

Explanation:

Particle in water move from low concentration to higher concentration in semi-permeable membrane. The particle of water would be less concentrated therefore the water would move into red blood cell therefore building in mass due to water and therefore swelling

Answer:

3.2043 x 10²³

Explanation:

No. of Mole of lead (Pb) = 0.532 mol

No. of atoms of lead = ?

Solution:

Formula Used to calculate

no. of moles = numbers of particles (ions, molecules, atoms) /Avogadro's number

Avogadro's no. = 6.023 x10²³

So,

The formula could be written as

no. of atoms of lead Pb = no. of moles x 6.023 x10²³

Put the values in above formula

no. of atoms of lead Pb = 0.532 mol x 6.023 x10²³

no. of atoms of lead Pb = 3.2043 x 10²³

so 3.2043 x 10²³ atoms of lead are contained in 0.532 mole.

Answer:

Add  limewater  

Explanation:

Ca(OH)₂ is about 1000 times more soluble than Mg(OH)₂

If you add limewater to the seawater, the magnesium ions will precipitate out as magnesium hydroxide.

Mg²⁺(aq) + 2OH⁻(aq) ⟶ Mg(OH)₂(s)

Answer:

P(total) = 94.4 kpa

Explanation:

Given data:

Pressure of hydrogen gas = 3.0 kpa

Pressure of water vapors = 91.4 kpa

Total pressure =?

Solution:

According to Dalton law of partial pressure,

The total pressure exerted by mixture of gases is equal to the sum of partial pressure of the individual gas.

This expression can be written as,

P(total) = P₁ + P₂ + P₃ + ...... Pₙ

Now we will put the values in formula:

P(total) = P₁ + P₂

P(total) = 3.0 kpa + 91.4 kpa

P(total) = 94.4 kpa