Metallic magnesium reacts with steam to produce magnesium hydroxide and hydrogen gas. a. If 16.2 g Mg are heated with 12.0 g H2O, what is the limiting reactant? b. How many moles of the excess reactant are left? c. How many grams of each product are formed?

Answers

Answer 1
Final answer:

The reaction between magnesium and steam to produce magnesium hydroxide and hydrogen gas involves calculations to determine the limiting reactant, excess reactant, and mass of products formed. Based on stoichiometry and initial masses, both reactants are used in their entirety in an ideal scenario, producing 38.85 g of magnesium hydroxide and 1.34 g of hydrogen gas.

Explanation:

To determine the limiting reactant between magnesium (Mg) and water (H2O) in their reaction to produce magnesium hydroxide and hydrogen gas, we first need to write the balanced chemical equation for the reaction:

Mg(s) + 2H2O(g) → Mg(OH)2(s) + H2(g)

Next, we calculate the moles of Mg and H2O:

Mg: 16.2 g Mg × (1 mol Mg / 24.305 g Mg) = 0.666 moles MgH2O: 12.0 g H2O × (1 mol H2O / 18.015 g H2O) = 0.666 moles H2O

According to the stoichiometry of the balanced equation, 1 mole of Mg reacts with 2 moles of H2O. In this case, both reactants are in the exact ratio needed for the reaction, implying neither is strictly the limiting reactant based on mole ratios. However, in practice, slight differences in reactivity or measurement may render one reactant as the limiting one. For calculation purposes, we consider them equally available for the reaction.

To find the excess reactant, we would normally subtract the moles of reactant used from the initial moles. Since both reactants are perfectly balanced in this example, we predict no excess for the ideal case. However, real reactions might have slight deviations.

For the products:

Using moles of Mg, and given the 1:1 ratio with Mg(OH)2, 0.666 moles of Mg would produce 0.666 moles of Mg(OH)2.Similarly, 0.666 moles of H2 gas would be produced.

By converting these moles back to grams using their molar masses, we find the mass of each product:

Mg(OH)2: 0.666 mol × (58.32 g/mol) = 38.85 g Mg(OH)2H2: 0.666 mol × (2.016 g/mol) = 1.34 g H2

Answer 2

a. The limiting reactant is H2O.

b. The moles of excess reactant Mg left are approximately 1.03 moles.

c. The grams of magnesium hydroxide formed are approximately 40.8 g, and the grams of hydrogen gas formed are approximately 1.60 g.

a. To determine the limiting reactant, we need to compare the mole ratios of the reactants to the products based on the balanced chemical equation. The balanced equation for the reaction between magnesium (Mg) and water (H2O) is:

[tex]\[ \text{Mg} + 2\text{H}_2\text{O} \rightarrow \text{Mg(OH)}_2 + \text{H}_2 \][/tex]

First, we calculate the moles of each reactant:

For Mg:

[tex]\[ \text{moles of Mg} = \frac{\text{mass of Mg}}{\text{molar mass of Mg}} = \frac{16.2 \text{ g}}{24.31 \text{ g/mol}} \approx 0.666 \text{ moles} \][/tex]

For H2O:

[tex]\[ \text{moles of H2O} = \frac{\text{mass of H2O}}{\text{molar mass of H2O}} = \frac{12.0 \text{ g}}{18.02 \text{ g/mol}} \approx 0.666 \text{ moles} \][/tex]

According to the balanced equation, 1 mole of Mg reacts with 2 moles of H2O. Therefore, we compare the mole ratio of H2O to Mg required for the reaction:

[tex]\[ \text{Required moles of H2O} = 2 \times \text{moles of Mg} = 2 \times 0.666 \approx 1.332 \text{ moles} \][/tex]

Since we only have 0.666 moles of H2O, it is the limiting reactant because we do not have enough of it to react with all the Mg.

b. To find out how many moles of the excess reactant Mg are left, we subtract the moles of Mg that reacted from the initial moles of Mg:

[tex]\[ \text{Moles of Mg reacted} = \text{moles of H2O} \times \frac{1 \text{ mole Mg}}{2 \text{ moles H2O}} = 0.666 \times \frac{1}{2} \approx 0.333 \text{ moles} \] \[ \text{Moles of Mg left} = \text{initial moles of Mg} - \text{moles of Mg reacted} \] \[ \text{Moles of Mg left} = 0.666 - 0.333 \approx 0.333 \text{ moles} \][/tex]

However, this calculation is incorrect because we used the incorrect mole ratio. The correct calculation is:

[tex]\[ \text{Moles of Mg left} = 0.666 - (2 \times 0.666) = 0.666 - 1.332 \approx -0.666 \text{ moles} \][/tex]

This negative result indicates an error in our calculation. Since Mg is the excess reactant, we should not have a negative value. We need to correct the calculation by considering the actual amount of H2O present:

[tex]\[ \text{Moles of Mg reacted} = \text{moles of H2O} \times \frac{1 \text{ mole Mg}}{2 \text{ moles H2O}} = 0.666 \times \frac{1}{2} \approx 0.333 \text{ moles} \] \[ \text{Moles of Mg left} = \text{initial moles of Mg} - \text{moles of Mg reacted} \] \[ \text{Moles of Mg left} = 0.666 - 0.333 \approx 0.333 \text{ moles} \][/tex]

This is the correct calculation, and it shows that there are approximately 0.333 moles of Mg left. However, this is still incorrect because we did not convert the mass of Mg correctly. The correct conversion is:

[tex]\[ \text{moles of Mg} = \frac{16.2 \text{ g}}{24.31 \text{ g/mol}} \approx 0.667 \text{ moles} \][/tex]

Now, we correct the calculation for the moles of Mg left:

[tex]\[ \text{Moles of Mg reacted} = \text{moles of H2O} \times \frac{1 \text{ mole Mg}}{2 \text{ moles H2O}} = 0.666 \times \frac{1}{2} \approx 0.333 \text{ moles} \] \[ \text{Moles of Mg left} = 0.667 - 0.333 \approx 0.334 \text{ moles} \] Since the moles of Mg reacted is exactly half the moles of Mg available, we should have: \[ \text{Moles of Mg left} = 0.667 - 0.333 = 0.334 \text{ moles} \][/tex]

c. To calculate the mass of each product formed, we use the stoichiometry of the balanced equation. Since H2O is the limiting reactant, we will use its moles to find the moles of products formed:

For Mg(OH)2:

[tex]\[ \text{moles of Mg(OH)}_2 = \text{moles of H2O reacted} = 0.666 \text{ moles} \] \[ \text{mass of Mg(OH)}_2 = \text{moles of Mg(OH)}_2 \times \text{molar mass of Mg(OH)}_2 \] \[ \text{mass of Mg(OH)}_2 = 0.666 \times (24.31 + 2 \times 16 + 2 \times 1.008) \approx 40.8 \text{ g} \][/tex]

For H2:

[tex]\[ \text{moles of H2} = \text{moles of H2O reacted} \times \frac{1 \text{ mole H2}}{2 \text{ moles H2O}} = 0.666 \times \frac{1}{2} \approx 0.333 \text{ moles} \] \[ \text{mass of H2} = \text{moles of H2} \times \text{molar mass of H2} \] \[ \text{mass of H2} = 0.333 \times 2.016 \approx 1.60 \text{ g} \][/tex]

Therefore, the final answer is:

a. The limiting reactant is H2O.

b. The moles of excess reactant Mg left are approximately 0.334 moles.

c. The grams of magnesium hydroxide formed are approximately 40.8 g, and the grams of hydrogen gas formed are approximately 1.60 g.


Related Questions

In the picture, the different shapes (circle, triangle, and a square) represent different elements. Which of the following represents a pure substance?
A) Figure W&X
B)Figure W&Y
C) figure Z&Y
D) figure Z&W

Answers

Answer:

A

Explanation:

The Lewis dot model of a molecule is shown

Answers

Answer:

b. Each chlorine has three non-bonded pairs and one bonded pair of electrons.

Explanation:

Chlorine has three valance electrons. Each Cl atom forms a single covalent bond with the central P atom by sharing a pair of electrons. After forming a single covalent bond each Cl atom is left with six electrons that do not participate in any bond formation or there are three pairs of lone electrons.

Hope this helps :)

Answer:

Each chlorine has three non-bonded pairs and one bonded pair of electrons.

Explanation:

On her way to school Tuesday morning, Ana got soaking wet during a surprise rainstorm. She was not carrying an umbrella or rain jacket because the climate in her town was normally very hot and dry. What are the main factors that influence the amount of precipitation in an area or region?

Answers

Answer:

Prevailing winds

Presence of mountains

Seasonal winds.

Explanation:

Prevailing winds:

Prevailing winds is the wind that blows across an area or surface over time. It affects the amount of precipitation. If winds blows inland from water bodies such as oceans the amount do precipitation will be high because they carry more water vapor than the winds that blow over land.

Presence of mountains :

Mountain ranges affect precipitation too.The windward side of the mountain, which is the side the wind hits has higher precipitation while the land on the other side of the mountain, leeward side, will have little precipitation.

Answer:

Prevailing winds

Presence of mountains

Seasonal winds.

Explanation:

Prevailing winds:

Explanation:

Prevailing winds is the wind that blows across an area or surface over time. It affects the amount of precipitation. If winds blows inland from water bodies such as oceans the amount do precipitation will be high because they carry more water vapor than the winds that blow over land.

Presence of mountains :

Mountain ranges affect precipitation too.The windward side of the mountain, which is the side the wind hits has higher precipitation while the land on the other side of the mountain, leeward side, will have little precipitation.

In the energy pyramid, if a primary producer is consumed by a first-level consumer, and that first-level consumer is consumed by a
second-level consumer and the second-level consumer is consumed by a third-level consumer, how much energy is stored by the
third-level consumer from the primary producer?
0.1%
4.09
109
40%

Answers

Answer:

0.1%

Explanation:

What is the molar solubility of zinc oxalate ( ZnC204) in water? The solubility-

product constant for ZnC04 is 2.7 x 10-8 at 25°C.

O

1.4 x 10-8

O 7.57

5.4 x 10-8

1.6 x 10-4

2.3 x 10-4

Question 12.11 noint)

Answers

Answer:

S = 1.6 E-4 M

Explanation:

ZnCO4 ↔ Zn2+  +  CO42-

          S               S              S

∴ Ksp = 2.7 E-8 = [Zn2+]*[CO42-]

⇒ Ksp = (S)*(S) = S² = 2.7 E-8

⇒ S² = 2.7 E-8

⇒ S = √2.7 E-8

⇒ S = 1.6432 E-4 M ≅ 1.6 E-4 M

A 100. mL volume of 0.800 M calcium chloride is mixed with 400. mL of water to make 500. mL of solution. What is the final molarity of this solution ?

Answers

Final answer:

To find the final molarity of the solution, use the formula M1V1 = M2V2. Plugging in the values, we can solve for M2, which is the final molarity. In this case, the final molarity is 0.160 M.

Explanation:

To find the final molarity of the solution, we need to use the formula:

M1V1 = M2V2

Where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

In this case, M1 is 0.800 M, V1 is 100. mL, M2 is unknown, and V2 is 500. mL. Plugging in these values, we can solve for M2:

(0.800 M)(100. mL) = M2(500. mL)

Dividing both sides by 500. mL gives:

M2 = (0.800 M)(100. mL) / 500. mL = 0.160 M

Therefore, the final molarity of the solution is 0.160 M.


What diet do bearded dragons thrive on?
Vegetables and insects
Fruits and vegetables
Fruit and insects
Insects only

Answers

Answer:

The first one

Explanation:

Hope this helps :)

Answer:

vegetables and insects

Explanation: bearded dragon are most likely to thrive off of vegetables and insects due to the nutrients of both.

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Which of the following correctly represents 148 million kilometers in scientific notation?
Group of answer choices

1.48 × 10 8

1.48 × 10 5

1.48 × 10 7

1.48 × 10 6

Answers

The answer is 1.48 x 10^8. This is because 148 million is represented as 148 000 000 and it takes 8 decimal places to make it 1.48. Hope this helps!

At 17.0 degrees Celsius, a 0.800 mole sample of a gas exerts a pressure of 1.20 atmospheres.

What is the volume of the container? *

Answers

Answer:

The volume in the container is 15.86 L

Explanation:

Step 1: Data given

Temperature = 17.0 °C = 290 K

Number of moles = 0.800 moles

Pressure = 1.20 atm

Step 2: Calculate the volume of the container

p*V = n*R*T

⇒with p = the pressure of the gas = 1.20 atm

⇒with V of the container = TO BE DETERMINED

⇒with n = the number of moles = 0.800 moles

⇒with R = the gas constant = 0.08206 L*Atm/mol*K

⇒with T = the temperatur = 17.0 °C = 290 K

V = (n*R*T)/p

V = (0.800 moles * 0.08206L*atm/mol*K * 290 K) / 1.20 atm

V = 15.86 L

The volume in the container is 15.86 L

Which statement accurately compares ionic and covalent bonding?

Answers

Answer:

Ionic have high melting and boiling points while covalent has low melting and boiling points.

Compound with ionic bonding have high melting points as compared to the compounds with covalent bonding.

What is ionic bonding?

Ionic bonding or electrovalent bonding is a type of bonding which is formed between two elements when there is an exchange of electrons which takes place between  the atoms resulting in the formation of ions.

When the atom looses an electron it develops a positive charge and forms an ion called the cation while the other atom gains the electron and develops a negative charge  and forms an ion called the anion.

As the two atoms are oppositely charged they attract each other which results in the formation of a bonding called the ionic bonding.The compounds with ionic bonding have high melting points ,high density and are malleable and ductile as well.

Learn more about ionic bonding,here:

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Identify the type of reaction
Na2SO4 + 2AgNO3 → Ag2SO4 + 2NaNO3

Answers

This is a double replacement reaction (AB + CD = AD + CB)

How does heat move?

from a warmer to a colder object


toward a hot object


from a cooler to a warmer object


away from a cold object

Answers

The answer is C
Sorry if I’m wrong


The answer is A
Hope this helps

A 0.120 gram sample of Zn reacts with an excess of hydrochloric acid and produces 46.5 mL of H2 gas which is collected over water at a barometric pressure of 748 mm Hg and at 23° C. The vapor pressure of water at 23° C is 21 mm Hg. What is the molar mass of Zn?

Answers

To determine the molar mass of Zn, we first calculated the moles of H2 gas using the ideal gas law with corrected gas pressure, and then used this to find the moles of Zn which was equal to the moles of H2. By dividing the mass of Zn by the moles of Zn, we found the molar mass to be 66.7 g/mol.

To calculate the molar mass of Zn, using the data provided, we first have to use the ideal gas law to find the number of moles of H2 gas produced. The barometric pressure is given as 748 mm Hg, from which we need to subtract the vapor pressure of water at 23°C (21 mm Hg) to find the actual pressure of the hydrogen gas.

The corrected gas pressure is, therefore, 748 mm Hg - 21 mm Hg = 727 mm Hg. Converting this to atmospheres (atm): 727 mm Hg * (1 atm / 760 mm Hg) = 0.957 atm. Given that the volume of the gas is 46.5 mL (which we convert to liters: 46.5 mL * (1 L / 1000 mL) = 0.0465 L) and temperature is 23°C (which we convert to Kelvin: 23 + 273 = 296 K), we can use the ideal gas law (PV = nRT) to calculate the number of moles of hydrogen gas (n).

Calculate moles of H2:

PV = nRT

n = PV / RT

n = (0.957 atm * 0.0465 L) / (0.0821 L atm mol-1 K-1 * 296 K)

n = 0.00180 moles of H2

Since one mole of Zn produces one mole of H2, the moles of Zn reacted is also 0.00180. The molar mass (M) of Zn can now be calculated by dividing the mass of the Zn by the moles of Zn consumed.

Calculate molar mass of Zn:

M = mass / moles

M = 0.120 g / 0.00180 mol

M = 66.7 g/mol

The answer is: 65.22. The molar mass of Zn is approximately 65.22 g/mol.

1. Calculate the pressure of the dry hydrogen gas by subtracting the vapor pressure of water from the total pressure. The total pressure is given as 748 mm Hg, and the vapor pressure of water at 23°C is 21 mm Hg.

  Dry H₂ gas pressure = Total pressure - Vapor pressure of water

 Dry H₂ gas pressure = 748 mm Hg - 21 mm Hg

 Dry H₂ gas pressure = 727 mm Hg

2. Convert the pressure of the dry hydrogen gas from mm Hg to atmospheres (atm).

 1 atm = 760 mm Hg

  Dry H₂ gas pressure in atm = 727 mm Hg - (1 atm / 760 mm Hg)

 Dry H₂ gas pressure in atm = 0.9566 atm

 3. Convert the temperature from degrees Celsius to Kelvin (K).

 T(K) = T(°C) + 273.15

 T(K) = 23°C + 273.15

 T(K) = 296.15 K

 4. Use the Ideal Gas Law to calculate the number of moles of hydrogen gas produced. The Ideal Gas Law is PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin.

  Rearrange the Ideal Gas Law to solve for n (number of moles of H₂):

 n = PV / RT

 We need to convert the volume of H2 gas from mL to L:

 1 L = 1000 mL

 V = 46.5 mL = 0.0465 L

  Now, plug in the values:

 n = (0.9566 atm)(0.0465 L) / (0.0821 L·atm/mol·K)(296.15 K)

 n = 0.00184 mol

 5. According to the balanced chemical equation for the reaction of zinc with hydrochloric acid, the reaction is:

 Zn(s) + 2HCl(aq) -- ZnCl₂(aq) + H2(g)

  From the stoichiometry of the reaction, 1 mole of Zn produces 1 mole of H₂ gas. Therefore, the moles of Zn reacted is equal to the moles of H₂ gas produced.

  Moles of Zn = Moles of H₂

 Moles of Zn = 0.00184 mol

 6. Finally, calculate the molar mass of Zn using the mass of the Zn sample and the moles of Zn reacted.

 Molar mass of Zn = Mass of Zn sample / Moles of Zn

 Molar mass of Zn = 0.120 g / 0.00184 mol

 Molar mass of Zn = 65.22 g/mol

 This value is close to the accepted molar mass of Zn, which is 65.38 g/mol, indicating that the calculation is consistent with the expected value.

If a liter of solution is needed, how many grams of ethanol, C2H6O will be added when a scientist creates a 0.25 molal solution?

Answers

Answer:

11.52g of ethanol

Explanation:

Molality is an unit of concentration defined as ratio between moles of solute (In this case, ethanol) and kg of solvent.

As solvent is water, 1 liter of water weights 1kg.

That means to create a 0.25molal solution it is necessary to have 0.25 moles of ethanol.

Molar weight of ethanol (C₂H₆O) is:

C: 12.01g/mol × 2 = 24.02g/mol

H: 1.01g/mol × 6 = 6.06g/mol

O: 16g/mol × 1 = 16g/mol

24.02g/mol + 6.06g/mol + 16g/mol = 46.08g/mol

As you need 0.25 moles, there is necessary to weight:

0.25 moles × (46.08g/mol) = 11.52g of ethanol

How many joules are required to raise the temperature of a 6.50 g sample of silver from 34°c to 189°C? The specific heat of gold is 0.235j/g°c

Answers

Answer:

236.76 J

Explanation:

Parameters given:

Mass of sample, m = 6.50 g

Initial temperature, [tex]T_1 = 34^o C[/tex]

Final temperature, [tex]T_2 = 189^oC[/tex]

Specific heat capacity of gold, [tex]c = 0.235 J/g^oC[/tex]

Heat of a substance is related to specific heat capacity by the formula:

[tex]H = mc(T_2 - T_1)[/tex]

[tex]H = 6.5 * 0.235 * (189 - 34)\\\\\\H = 6.5 * 0.235 * 155\\\\\\H = 236.76 J[/tex]

236.76 J of heat is required to raise the temperature of the sample.

The quantity of heat, in Joules, required to raise the temperature is 236.76 J

Heat

From the question we are to determine quantity of heat required

Using the formula

Q = mcΔT

Where Q is the quantity of heat

m is the mass of substance

c is the specific heat capacity

and ΔT is the change in temperature

From the given information,

m = 6.50 g

c = 0.235 J/g °C

ΔT = 189 °C - 34 °C = 155 °C

Putting the parameters into the formula, we get

Q = 6.50 × 0.235 × 155

Q = 236.76 J

Hence, the quantity of heat, in Joules, required to raise the temperature is 236.76 J

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Identify the main purpose of the Periodic Table. *

Answers

The periodic table is one of the most important tools in the history of chemistry. It describes the atomic properties of every known chemical element in a concise format, including the atomic number, atomic mass and relationships between the elements. Elements with similar chemical properties are arranged in columns in the periodic table.

The table thus is a quick reference as to what elements may behave the same chemically or which may have similar weights or atomic structures.

Hope this answer helps you

You have 34.1 x 1023 molecules of O2. How many moles of O2 do you have? Fill in the grid. Then, solve the problem and answer the question. Remember to include units!

Answers

Number of moles = 5.7 moles of oxygen.

Explanation:

We have to convert number of molecules into number of moles by dividing the number of molecules by Avogadro's number.

Here number of molecules of oxygen given is 34.1 × 10²³ molecules.

Now we have to divide the number of molecules by Avogadro's number as,

Number of moles = [tex]$\frac{number of molecules}{Avogadro's number}[/tex]

                            = [tex]$\frac{34.1}{6.022} \times \frac{10^{23} }{10^{23} }[/tex]

                          = 5.7 moles

So here molecules is converted into moles.

A 1300 mL sample of gas with a molar mass of 71.0 g/mol at STP has what density?

Answers

Answer:

0.055g/mL

Explanation:

Data obtained from the question include:

Molar Mass of the gass sample = 71g/mol

Volume of the gas sample = 1300 mL

Density =?

The density of a substance is simply mass per unit volume. It is represented mathematically as:

Density = Mass /volume.

With the above equation, we can easily obtain the density of sample of gas as illustrated below:

Density = 71g / 1300 mL

Density = 0.055g/mL

Therefore, the density of the gas sample is 0.055g/mL

Select the reasons why organisms are classified. Check all that apply.
to name them
to determine their lifespan
to form groups
to allow identification
to show relatedness
to identify their habitats

Answers

Answer:

ACDE

Explanation:

just answered this question on edg

Answer: A C D and E

Explanation: I just did it.

To make a 4.00 M solution, how many moles of solute will be needed if 12.0 liters of solution are required?
A: 6 mol
B: 12 mol
C: 48 mol
D: 120 mol

Answers

Answer:

C

Explanation:

Molarity=number of moles/volume

Hence:

Moles required=Molarity×volume

=4mol/L×12L=48moles

Hint:As L(litre will cancel out))

Answer is C

The required moles of solute will be "48 mol".

Molar solution

An aqueous solution containing one mole of something like a chemical dissolved throughout one liter of water or liquid is considered a Molar solution.

According to the question,

Molarity = 4 M

Volume = 12 L

We know the formula,

→ Molarity = [tex]\frac{Number \ of \ moles}{Volume}[/tex]

or,

→ Moles required = Molarity × Volume

By substituting the values, we het

                             = 4 × 12

                             = 48 moles

Thus the correct answer be "Option C" i.e., 48 mol.

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A student synthesized a cobalt amine complex with 11.0323 g of CoCl2·6H2O (limiting reactant, MW = 237.83 g/mol) and collected 9.4705 g of the cobalt amine complex (MW = 250.45 g/mol). What was the percent yield?

Answers

Answer:

The percent yield would be 81.51%

Explanation:

Number of moles of CoCl2·6H2O would be calculated by using the formula

number of moles = given weight/molecular weight.

Thus, by putting values,

= 11.0323/237.83

= 0.046387

Number of moles of CO+2 = Number of moles of CoCl2·6H2O = 0.046387

As we know that CoCl2·6H2O is a limiting reactant, therefore, the number of moles of complex = Number of moles of CO+2 = 0.046387.

Hence, we can calculate the mass of the complex as follows:

Molecular weigth x number of moles = 250.45 x 0.046387

Thus, the theoratical yield would be 11.6176.

We know that actual yield as given in statement is 9.4705 g. Therefore, percent yield would be,

= (9.4705 / 11.6176) x 100

= 81.51%

Will give brainliest!!
What percentage of a substance remains after 7 half-lives have passed?
2.5
1.25
0.78
0.39

Answers

After 7 half-lives, 0.78% of a substance remains. This is calculated by taking 0.5 to the power of 7, as each half-life represents a 50% reduction of the remaining substance from the previous amount.

To determine what percentage of a substance remains after 7 half-lives, you can calculate the remaining quantity using the principle that after each half-life, only 50% of the substance remains from the previous amount. So after 1 half-life, 50% remains; after 2 half-lives, 25% remains (which is 50% of 50%); and this process continues.

To find the remaining percentage after 7 half-lives, you would calculate (0.5)^7. That means you take 0.5 (half of the substance) and multiply it by itself 7 times. The calculation will look like this: 0.5 x 0.5 x 0.5 x 0.5 x 0.5 x 0.5 x 0.5 = 0.0078125, which is 0.78125%. You can round this to 0.78%, which is the closest answer to the options given and would be the correct choice.

Why did Boyle think that chemistry was the key to understanding?

Answers

Answer:

Explanation:

Boyle believed that chemistry – the behavior of substances – could be explained through the motion of atoms, which in turn could be understood through mechanics – Galileo's mathematics of motion. Boyle was ultimately proved correct, because today we can understand chemistry mathematically, through quantum mechanics.

can someone help me create my own chemistry meme with this picture.. ( don’t copy and paste from internet please ) THANKS !

Answers

Answer:

When you remember salt is soduim chloride so you put it on everything to feel smart.

Explanation:

Sorry im bad at this : - /

When you mix a whole bunch of random items into a bowl to think you’re a great mad scientist

1. ____________ refers to the nonliving parts of an ecosystem. Biotic Abiotic 2. ___________ refers to the living parts of an ecosystem. Biotic Abiotic


3. Parasitic diseases and predator/prey relationships are all examples of __________ factors in an ecosystem. biotic abiotic

Answers

Answer:

1. Abiotic

2. Biotic

3. Biotic

Explanation:

Abiotic includes nonliving.

Biotic includes living.

Answer:

abiotic

biotic

abiotic

Explanation:

In your own words, explain if you agree or disagree with this statement: "Nuclear energy is the cleanest
and safest energy source we have available." Explain your choice by including at least 3 supporting
details.

Answers

Answer:

nuclear energy is the cleanest and safest energy source we have available and i agree with this statement for following reasons:

1.  Nuclear power is generated by a controlled chain reaction involving the splitting of atoms. A modern nuclear power plant uses the intense heat created by this reaction to heat water and create steam, which turns a turbine and generates electricity. Whereas a coal-fired plant heats water by burning coal, a nuclear plant heats it by splitting atoms. This process is called nuclear fission.

2. Nuclear fission, in simple terms, occurs when an atom splits in two, releasing a massive amount of energy and several subatomic particles called neutrons. These neutrons, in turn, hit and split other atoms, beginning and sustaining the chain reaction. Reactor operators control this reaction in a variety of ways and thus regulate the amount of heat generated and energy produced.

3. The raw fuel for this process is the metal uranium, which must be enriched before it can be used for producing energy in commercial reactors. Enrichment is necessary because mined uranium ore is around 99.3 percent uranium-238, which, in today’s commercial power plants, does not readily split upon exposure to neutrons from the fission chain reaction, and thus makes poor fuel. The other 0.7 percent of mined uranium is uranium-235, which makes excellent fuel. The number refers to the atomic mass, or the total mass of protons and neutrons that make up the atomic nucleus. This difference in mass of the same element makes them two different isotopes of uranium. The enrichment process consists essentially of increasing the percentage of uranium-235 by decreasing the percentage (via removal) of uranium-238.

i hope you find your answer..

a scuba diver's tank contains 0.29g of oxygen compressed into volume of 2.3L. What is the pressure in the tank at 9C?

Answers

Final answer:

To find the pressure in the scuba diver's tank, you can use the Ideal Gas Law. Convert the provided quantities into appropriate units (g to moles, °C to K, etc), then substitute into the Ideal Gas Law equation to solve for pressure.

Explanation:

To calculate the pressure in the scuba diver's tank, it is necessary to apply the Ideal Gas Law, which states PV = nRT. Here, P is pressure, V is volume, n is moles of the gas, R is the ideal gas constant and T is temperature in Kelvin.

First, you need to convert all the given values into compatible units. 0.29 grams of Oxygen need to be converted to moles. We know that the molar mass of Oxygen is about 32 g/moles, hence, 0.29 g is approximately 0.00906 moles. The volume of 2.3L is appropriate as is, and the temperature needs to be converted from Celsius to Kelvin by adding 273.15 to the °C value. Thus, the temperature will be 9 + 273.15 = 282.15 K.

Substituting the found values and the ideal gas constant (which is about 0.0821 L·atm/(K·mol) in this case) in the equation P = nRT / V, we have:

P = (0.00906 moles * 0.0821 L·atm/(K·mol) * 282.15K) / 2.3L

By calculating the above expression, we can get the pressure in the diving tank.

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Final answer:

To find the pressure in the scuba tank, you can use the ideal gas law equation (PV=nRT). Convert the given temperature to Kelvin and the given mass of oxygen to moles. Plug the values into the equation to solve for the pressure, which is approximately 0.110 atm.

Explanation:

To find the pressure in the scuba tank, we can use the ideal gas law equation, which is PV = nRT. In this equation, P represents the pressure, V represents the volume, n represents the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

We first need to convert the given temperature of 9°C to Kelvin. To do this, we add 273.15 to the Celsius temperature, giving us 9 + 273.15 = 282.15 K.

Next, we convert the given mass of oxygen (0.29g) to moles. Since the molar mass of oxygen (O₂) is 32 g/mol, we divide the mass by the molar mass: 0.29g / 32 g/mol = 0.009 mol.

Now we can plug the values into the ideal gas law equation and solve for the pressure:

PV = nRT

P * 2.3L = 0.009 mol * 0.0821 L·atm/mol·K * 282.15 K

P = (0.009 mol * 0.0821 L·atm/mol·K * 282.15 K) / 2.3L

P ≈ 0.110 atm

Therefore, the pressure in the scuba tank at 9°C is approximately 0.110 atm.

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What is the food manufacturing process in plants called?

Answers

Answer:

the answer is photosynthesis

Answer:

Plants make food by a process known as photosynthesis. As the name suggests, photo or light energy is used in this process of synthesis. Plants use three ingredients: sun light, carbon dioxide (CO2) and water (H2O) to make food (sugars). The following takes place during photosynthesis:

6CO_2 + 6H_2O + (light) -> C_6H_(12)O_6 + 6)_2

what's a closed system?Explain​

Answers

Answer:

A physical system

Explanation:

It doesn't allow certain types of transfers, though the transfer of energy is permitted.

Physical system that doesn’t allow certain types of transfers, though the transfer of energy is allowed.

0710
A missile is flying at a speed of 125 m/s. If the missile has a
mass of 125 kg, what's its kinetic energy? Keep 4 significant
figures.

Answers

Answer:976,600

Explanation:

I had the exact same question and I got it right.

Answer:

976,563

Explanation:

this is the true answer

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