Answers
[tex]f= \frac{c}{\lambda} [/tex]
where c is the speed of light and [tex]\lambda[/tex] is the photon wavelength. For this radiation, photons have wavelength of
[tex]\lambda=13.0 cm=0.13 m[/tex]
Therefore their frequency is
[tex]f= \frac{c}{\lambda}= \frac{3 \cdot 10^8 m/s}{0.13 m}=2.3\cdot 10^9 Hz [/tex]
The energy of a photon with frequency f is given by
[tex]E=hf[/tex]
where h is the Planck constant. By using the frequency we found before, we find the energy of a single photon of this radiation:
[tex]E=hf=(6.6 \cdot 10^{-34} Js)(2.3 \cdot 10^9 Hz)=1.52 \cdot 10^{-24} J[/tex]
The energy of exactly one photon of this microwave radiation is 1.53 × 10⁻²⁴Joule
Further explanationThe term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is:
[tex]\large {\boxed {E = h \times f}}[/tex]
E = Energi of A Photon ( Joule )
h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )
f = Frequency of Eletromagnetic Wave ( Hz )
The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.
[tex]\large {\boxed {E = \frac{1}{2}mv^2 + \Phi}}[/tex]
[tex]\large {\boxed {E = qV + \Phi}}[/tex]
E = Energi of A Photon ( Joule )
m = Mass of an Electron ( kg )
v = Electron Release Speed ( m/s )
Ф = Work Function of Metal ( Joule )
q = Charge of an Electron ( Coulomb )
V = Stopping Potential ( Volt )
Let us now tackle the problem!
Given:
λ = 13.0 cm = 13.0 × 10⁻² m
Unknown:
E = ?
Solution:
[tex]E = h f[/tex]
[tex]E = h \frac{c}{\lambda}[/tex]
[tex]E = 6.63 \times 10^{-34} \frac{3 \times 10^8}{13.0 \times 10^{-2}}[/tex]
[tex]\large {\boxed {E = 1.53 \times 10^{-24} ~ Joule } }[/tex]
Learn morePhotoelectric Effect : https://brainly.com/question/1408276Statements about the Photoelectric Effect : https://brainly.com/question/9260704Rutherford model and Photoelecric Effect : https://brainly.com/question/1458544Photoelectric Threshold Wavelength : https://brainly.com/question/10015690Answer detailsGrade: High School
Subject: Physics
Chapter: Quantum Physics
Keywords: Quantum , Photoelectric , Effect , Threshold , Frequency , Electronvolt
Related Questions
The cars of a roller coaster ride have a speed of 30 km/hr as they pass over the top of the circular track. neglect any friction and calculate their speed v when they reach the horizontal bottom position
Answers
Since the friction is negligible, we can apply the law of conservation of energy. The total mechanical energy at the top and at the bottom must be the same:
[tex]E_t = E_b[/tex]
At the top, the mechanical energy is sum of kinetic energy and gravitational potential energy:
[tex]E_t = K_t + U_t = \frac{1}{2} mv_t^2 + mgh[/tex] (1)
where m is the mass of the cars, [tex]v_t[/tex] is the velocity of the cars at the top (30 km/h) and h is the height at the top (18 m).
At the bottom, the mechanical energy is just kinetic energy:
[tex]E_b = K_b = \frac{1}{2}mv_b^2 [/tex] (2)
where [tex]v_b[/tex] is the velocity of the cars at the bottom of the track. By putting together (1) and (2), we find
[tex] \frac{1}{2}mv_t^2 + mgh = \frac{1}{2}mv_b^2 [/tex]
from which we can isolate [tex]v_b[/tex], the velocity of the cars at the bottom of the track:
[tex]v_b = \sqrt{v_t^2 + 2gh} [/tex]
and since [tex]v_t = 30 km/h =8.33 m/s[/tex], we find
[tex]v_b = \sqrt{(8.33 m/s)^2 + 2(9.81 m/s^2)(18 m)}=20.56 m/s =74 km/h [/tex]
The speed of the roller coaster at the bottom of the track is v = sqrt((2gh + vtop2)).
To determine the speed of the roller coaster at the bottom of the track, we'll employ the conservation of mechanical energy principle, assuming no frictional losses. The total mechanical energy at the top will be equal to that at the bottom, meaning that the potential energy at the top will be fully converted into kinetic energy at the bottom.
The potential energy (PE) at the top of the circular track is given by PE = mgh, where m is the mass of the roller coaster, g is the acceleration due to gravity (9.8 m/s2), and h is the height of the top of the track above the bottom. The kinetic energy (KE) at the top is KE = (1/2)mv2, with v being the speed at the top (30 km/hr which needs to be converted to meters per second). At the bottom, the potential energy is zero, and all the energy is kinetic: KE = (1/2)mv2 (where v is the unknown speed we want to calculate).
Setting the total energy at the top equal to the total kinetic energy at the bottom and solving for v, we find that v = sqrt((2gh + vtop2)). Plugging in the values, with appropriate unit conversions, gives the speed v at the bottom of the track.
Scientists have documented that the current level of carbon dioxide in the atmosphere is _________
Answers
True or False: The tundra and taiga are known as cold biomes.
Answers
The quartz crystal in a digital watch has a frequency of 32.8 khz. what is its period of oscillation?
Answers
[tex]f=32.8 kHz = 3280 Hz[/tex]
The period of oscillation is equal to the reciprocal of the frequency; therefore, in this problem, the period of oscillation of the digital watch is:
[tex]T=\frac{1}{f}=\frac{1}{3280 Hz}=3.05 \cdot 10^{-4}s [/tex]
The quartz crystal in a digital watch with a frequency of 32.8 kHz has a period of oscillation of approximately 30.49 microseconds. This is obtained by using the formula T = 1/f, where T is the period and f is the frequency.
Explanation:The subject matter of this question is a physical concept pertaining to the characteristics of oscillations, specifically the relationship between frequency and the period of oscillation. In physics, the frequency of an oscillation is the number of oscillations per unit time, and is measured in hertz (Hz). The period of oscillation, on the other hand, is the time for one oscillation.
The quartz crystal in a digital watch vibrates or oscillates with a frequency of 32.8 kHz, or 32800 Hz. The relation between frequency and period is that they are inversely proportional, and this relationship can be represented by the formula T = 1/f, where T is the period and f is the frequency. Substituting the given frequency value into this formula, we would find that the period of oscillation is approximately 30.49 microseconds.
Thus, the period of oscillation for the quartz crystal in the watch is approximately 30.49 microseconds.
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Calculate kp at 298.15 k for the reactions (a), (b), and (c) using δg°f values.
Answers
To calculate Kp for a reaction at 298.15 K, you should use the ΔG° values for the reactants and products. Then, apply the relationship ΔG° = -RTlnKp to find Kp.
The calculation of Kp (equilibrium constant in terms of pressure) at a specific temperature for a chemical reaction can be done using the ΔG° (standard Gibbs free energy change) and the following relationship:
ΔG° = -RTlnKp
where R is the universal gas constant (8.314 J/mol·K), T is the temperature in Kelvin, and Kp is the equilibrium constant. You can rearrange the equation to solve for Kp:
Kp = e^(-ΔG°/RT)
To find ΔG° for the reaction, you can use the ΔG°f (standard Gibbs free energy of formation) values for the reactants and products:
ΔG° = Σ(ΔG°f products) - Σ(ΔG°f reactants)
Once you have ΔG°, you can calculate Kp using the rearranged equation. This method can be applied to any chemical reaction, including the examples provided, to determine if the equilibrium will favor the reactants or products at a specific temperature.
Several forces are applied to the pipe assembly shown. the inner and outer diameters of the pipe are equal to 1.50 and 1.75 inches, respectively. (a) determine the principal planes and principal stresses at pt. h located at the top of the outside surface of the pipe (b) determine the maximum shear stress at pt. h (c) provide a sketch (to-scale) of mohr's circle for the state of stress at pt. h
Answers
T= 8× 50 = 400lb.in
M = 16.30 = 480lb.in
F₂ = 50lb
To calculate the polar moment of inertia of shaft is
J = π/π²×(R⁴-r⁴)
= π²/2×(0.875⁴ - 0.750⁴)
= 0.423in.³
To calculate the moment of inertia
J= 1/2(J)
=1/2 (0.423)
=0.21188in.³
To calculate shear flow
Qy= 2/3(R³-r³)
= 2/3(0.875³- 0.750³)
= 0.16536in.³
To calculate the thickness of the shaft
t= R-r = 0.875 - 0.750 = 0.125 in.
The stress due to torsions is.
Tx = TR/J = 400 × 0.875/0.42376
=825. 9psi.
The stress due to bending
Qx =My/T = 480 × 0.875/0.2118
=1982.3psi
The stress due to transverse shear
Qx = VQ/I(2t)
=50 × 0.16536/0.2118× 0.250
=156.1psi
The answer involves determining normal and shear stresses at point H, computing principal stresses using the relevant formula and plotting these values on a Mohr's circle.
Explanation:To determine the principal planes and stresses, along with the maximum shear stress, we will need to work through a process of calculation and analysis. However, without numerical values for the forces applied to the pipe, we cannot perform accurate calculations. Theoretically, though, you would first find the normal and shear stresses on the element at point H. Subsequently, the formula for finding the principal stresses σ₁ and σ₂ would be σ₁/₂= (σx+σy) ÷ 2 ± sqrt ((σx-σy) ÷ 2)^2 + τxy^2. As for shear stress, τxy should be evaluated at the principal planes, where it reaches maximum and minimum. Lastly, to sketch Mohr's circle, you would plot the normal stress on the x-axis and shear stress on the y-axis.
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What is the highest point on this map?
A. 30 meters
B. 35 meters
C. 52 meters
D. 60 meters
Answers
Two power lines run parallel for a distance of 222 m and are separated by a distance of 40.0 cm. if the current in each of the two lines is 135 a and if they run in opposite directions, determine the magnitude and direction of the force each wire e
Answers
The magnetic field generated by a current-carrying wire is
[tex]B= \frac{\mu_0I}{2 \pi r} [/tex]
where
[tex]\mu_0[/tex] is the vacuum permeability
I is the current in the wire
r is the distance at which the field is calculated
Using I=135 A, the current flowing in each wire, we can calculate the magnetic field generated by each wire at distance
[tex]r=40.0 cm=0.40 m[/tex],
which is the distance at which the other wire is located:
[tex]B= \frac{\mu_0 I}{2 \pi r}= \frac{(4 \pi \cdot 10^{-7} N/A^2)(135 A) }{2 \pi (0.40 m)}=6.75 \cdot 10^{-5} T [/tex]
Then we can calculate the magnitude of the force exerted on each wire by this magnetic field, which is given by:
[tex]F=ILB=(135 A)(222 m)(6.75 \cdot 10^{-5}T)=2.03 N[/tex]
2) direction of the force:
The two currents run in opposite direction: this means that the force between them is repulsive. This can be determined by using the right hand rule. Let's apply it to one of the two wires, assuming they are in the horizontal plane, and assuming that the current in the wire on the right is directed northwards:
- the magnetic field produced by the wire on the left at the location of the wire on the right is directed upward (the thumb of the right hand is directed as the current, due south, and the other fingers give the direction of the magnetic field, upward)
Now let's apply the right-hand rule to the wire on the right:
- index finger: current --> northward
- middle finger: magnetic field --> upward
- thumb: force --> due east --> so the force is repulsive
A similar procedure can be used on the wire on the left, finding that the force exerted on it is directed westwards, so the force between the two wires is repulsive.
A stuffed toy with a mass of 0.900 kilograms sits on the edge of a bed at a height of 0.830 meters. If the toy falls off the bed, what will its kinetic energy be at a height of 0.500 meters? (Ignore frictional effects.)
0.0 J
2.9 J
4.4 J
7.3 J
Answers
The kinetic energy of the falling toy is 2.9 J when at a height of 0.500 m.
The kinetic energy of the toy falling from a height of 0.830 m to 0.500 m can be calculated using:
E = ∆PE = mg∆h
E = (0.900 kg)(9.81 m/s²)(0.830 m - 0.500 m)
E = 0.9 kg x 9.81 m/s² x 0.33 m = 2.89 J
Hence, the kinetic energy of the toy at a height of 0.500 m is 2.9 J.
what is the energy (in eV units) carried by one photon violet light that has a wavelength of 4.5e-7?
Answers
[tex]E=hf[/tex]
where h is the Planck constant and f is the photon frequency.
We can find the photon's frequency by using the following relationship:
[tex]f= \frac{c}{\lambda} [/tex]
where c is the speed of light and [tex]\lambda[/tex] is the photon's wavelength. By plugging numbers into the equation, we find
[tex]f= \frac{c}{\lambda}= \frac{3 \cdot 10^8 m/s}{4.5 \cdot 10^{-7} m}=6.67 \cdot 10^{14}Hz [/tex]
And so now we can find the photon energy
[tex]E=hf=(6.6 \cdot 10^{-34} Js)(6.67 \cdot 10^{14}Hz )=4.4 \cdot 10^{-19} J[/tex]
We know that 1 Joule corresponds to
[tex]1 J = 1.6 \cdot 10^{-19} eV[/tex]
So we can convert the photon's energy into electronvolts:
[tex]E= \frac{4.4 \cdot 10^{-19} J }{1.6 \cdot 10^{-19} J/eV}=2.75 eV [/tex]
A photon of violet light with a wavelength of 4.5×10⁻⁷ meters carries approximately 2.75 electron-volts (eV) of energy.
To find the energy of a photon of violet light with a wavelength of 4.5×10⁻⁷ meters, we can use the formula for energy in terms of wavelength:
Energy (E) = h * c / λ
Here,
h is Planck's constant (6.626 × 10⁻³⁴ J·s)c is the speed of light (3 × 10⁸ m/s)λ is the wavelength (4.5 × 10⁻⁷ meters)Substituting the values into the formula:
E = (6.626 × 10⁻³⁴ J·s) * (3 × 10⁸ m/s) / (4.5 × 10⁻⁷ m)
E = 4.414 × 10⁻¹⁹ J
Since we want the energy in electron-volts (eV), we convert from joules using the conversion factor 1 eV = 1.602 × 10⁻¹⁹ J:
E = (4.414 × 10⁻¹⁹ J) / (1.602 × 10⁻¹⁹ J/eV)
E ≈ 2.75 eV
Therefore, a photon of violet light with a wavelength of 4.5×10⁻⁷ meters carries approximately 2.75 eV of energy.
Why is it important to continuously monitor seismic data? A. to find out when earthquakes occurred in the past B. to map the location of all the largest earthquakes C. to know how strong future earthquakes will be D. to determine the location and magnitude of seismic activity
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It is important to continuously monitor seismic data in order to determine the location and magnitude of seismic activity. Thus, the correct option for this question is D.
What is Seismic data?Seismic data may be characterized as an exploration method of sending energy waves or sound waves into the earth and recording the wave reflections to indicate the type, size, shape, and depth of a subsurface rock formation.
The monitoring of seismic data is important for many purposes, like determining the frequency of occurrence of earthquake activity, evaluating earthquake risk, interpreting the geological and tectonic activity of the area, and providing an effective vehicle for public information and education. It also ensures the accessibility and integrity of earthquake data.
Therefore, it is important to continuously monitor seismic data in order to determine the location and magnitude of seismic activity. Thus, the correct option for this question is D.
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The distance between the first and fifth minima of a single-slit diffraction pattern is 0.500 mm with the screen 37.0 cm away from the slit, when light of wavelength 530 nm is used. find the slit width.
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[tex]y_n= \frac{n \lambda D}{a}[/tex] (1)
where
n is the order of the minimum
y is the displacement of the nth-minimum from the center of the diffraction pattern
[tex]\lambda[/tex] is the light's wavelength
D is the distance of the screen from the slit
a is the width of the slit
In our problem,
[tex]D=37.0 cm=0.37 m[/tex]
[tex]\lambda=530 nm=5.3 \cdot 10^{-7} m[/tex]
while the distance between the first and the fifth minima is
[tex]y_5-y_1 = 0.500 mm=0.5 \cdot 10^{-3} m[/tex] (2)
If we use the formula to rewrite [tex]y_5, y_1[/tex], eq.(2) becomes
[tex] \frac{5 \lambda D}{a} - \frac{1 \lambda D}{a} =\frac{4 \lambda D}{a}= 0.5 \cdot 10^{-3} m [/tex]
Which we can solve to find a, the width of the slit:
[tex]a= \frac{4 \lambda D}{0.5 \cdot 10^{-3} m}= \frac{4 (5.3 \cdot 10^{-7} m)(0.37 m)}{0.5 \cdot 10^{-3} m}= 1.57 \cdot 10^{-3} m=1.57 mm[/tex]
The surface water temperature on a large, deep lake is 3°c. a sensitive temperature probe is lowered several m into the lake. what temperature will the probe recor
Answers
Final answer:
The temperature recorded by the temperature probe will be colder than 3°C.
Explanation:
The temperature recorded by the sensitive temperature probe will depend on the depth it is lowered into the lake. As the depth increases, the temperature generally decreases. In this case, since the surface water temperature is 3°C, we can expect the temperature to be lower as the probe is lowered several meters into the lake.
The specific temperature at the depth of the probe cannot be determined without more information, such as the rate at which the temperature decreases with depth in the lake. However, it is reasonable to expect that the temperature will be colder than 3°C.
if an observer is hearing a rise in pitch that means the frequency of the waves in their position are falling
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Pitch refers to the highness or lowness of a sound. The pitch of a sound depends on the frequency of that pitch. The higher the frequency, the higher the pitch and the lower the frequency, the lower the pitch. Thus, if an observer is hearing a rise in pitch that means the frequency of the waves in that position are increasing.
Consider 3.5 kg of austenite containing 0.95 wt% c and cooled to below 727°c (1341°f). (a) what is the proeutectoid phase? (b) how many kilograms each of total ferrite and cementite form? (c) how many kilograms each of pearlite and the proeutectoid phase form?
Answers
The proeutectoid phase formed when austenite is cooled below 727°C is cementite. To calculate the masses of total ferrite and cementite formed, we use phase diagrams and the weight percentage of carbon. The masses of pearlite and the proeutectoid phase can be determined by subtracting the mass of pearlite from the initial mass of austenite.
Explanation:(a) Proeutectoid phase:
The proeutproeutectoidectoid phase that forms when austenite is cooled below 727°C is cementite (Fe3C).
(b) Formation of total ferrite and cementite:
To calculate the mass of each phase formed, we need to use phase diagrams. Given that the percentage of carbon in the austenite is 0.95 wt%, we can find the weight fractions of ferrite and cementite. Assuming the remaining weight percentage is Fe, we can then calculate the masses of ferrite and cementite.
(c) Formation of pearlite and the proeutectoid phase:
Pearlite consists of alternating layers of ferrite and cementite. The mass of pearlite formed can be determined using the mass of ferrite and cementite calculated in part (b). The mass of the proeutectoid phase can be obtained by subtracting the mass of pearlite from the initial mass of austenite.
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The proeutectoid phase is ferrite. The weight fractions of ferrite and cementite can be calculated from the composition of austenite. The amounts of pearlite and the proeutectoid phase cannot be determined without more information.
Explanation:(a) The proeutectoid phase is ferrite. Ferrite forms when austenite is cooled to below the eutectoid temperature.
(b) To determine the amount of ferrite and cementite that form, we need to calculate the weight fraction of each phase. Since the composition of austenite is given as 0.95 wt% C, the weight fraction of cementite is 0.95/100 = 0.0095. The weight fraction of ferrite is 1 - 0.0095 = 0.9905. Therefore, 3.5 kg * 0.0095 = 0.03325 kg of cementite forms and 3.5 kg * 0.9905 = 3.46675 kg of ferrite forms.
(c) To calculate the weight of pearlite and the proeutectoid phase, we need to know the eutectoid composition and the weight fraction of the proeutectoid phase. Without this information, it is not possible to determine the exact quantities of these phases.
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What are they wats to find the wavelength of a transverse wave
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In a nuclear power plant, _____.
energy is released from the nuclei of atoms
energy is released from the bonds of molecules
energy is released from the electrons of atoms
energy is stored in the nucleus of atoms
Answers
Answer:the answer is energy is released from the nuclei of atoms
Explanation:
If you weigh 670 n on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and a diameter of 25.0 km ? take the mass of the sun to be m s = 1.99×1030 kg , the gravitational constant to be g = 6.67×10−11 n⋅ m 2 /k g 2 , and the acceleration due to gravity at the earth's surface to be g = 9.810 m/ s 2 .
Answers
your weight on the surface of a neutron star with the same mass as the Sun and a diameter of 25.0 km would be approximately [tex]\( 2.8 \times 10^{12} \, \text{N} \).[/tex]
To calculate your weight on the surface of a neutron star with the given mass and diameter, we can use the formula for gravitational force ( F ) and the definition of weight ( W ).
The formula for gravitational force between two objects is given by:
[tex]\[ F = \frac{{G \cdot m_1 \cdot m_2}}{{r^2}} \][/tex]
Where:
- ( F ) is the gravitational force,
- ( G ) is the gravitational constant [tex](\( 6.67 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \))[/tex],
- [tex]\( m_1 \) and \( m_2 \)[/tex] are the masses of the objects,
- ( r ) is the distance between the centers of the objects.
On the Earth's surface, your weight ( W ) is calculated using your mass \( m \) and the acceleration due to gravity ( g ):
[tex]\[ W_{\text{Earth}} = m \cdot g_{\text{Earth}} \][/tex]
Given:
- Your weight on Earth[tex]\( W_{\text{Earth}} = 670 \, \text{N} \)[/tex],
- Mass of the Sun [tex]\( m_{\text{Sun}} = 1.99 \times 10^{30} \, \text{kg} \)[/tex],
- Diameter of the neutron star[tex]\( r = 25.0 \, \text{km} = 25,000 \, \text{m} \)[/tex].
First, let's calculate the gravitational force between you and the Earth using your weight:
[tex]\[ W_{\text{Earth}} = \frac{{G \cdot m \cdot m_{\text{Earth}}}}{{r_{\text{Earth}}^2}} \][/tex]
Solve for your mass \( m \):
[tex]\[ m = \frac{{W_{\text{Earth}} \cdot r_{\text{Earth}}^2}}{{G \cdot m_{\text{Earth}}}} \][/tex]
Substitute the given values:
[tex]\[ m = \frac{{670 \, \text{N} \cdot (6.371 \times 10^6 \, \text{m})^2}}{{6.67 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \cdot 5.97 \times 10^{24} \, \text{kg}}} \][/tex]
Calculate the mass ( m ) on Earth:
[tex]\[ m \approx 69 \, \text{kg} \][/tex]
Now, use this mass to calculate your weight[tex]\( W_{\text{Neutron Star}} \)[/tex] on the surface of the neutron star:
[tex]\[ W_{\text{Neutron Star}} = \frac{{G \cdot m \cdot m_{\text{Sun}}}}{{r_{\text{Neutron Star}}^2}} \][/tex]
Substitute the given values for the neutron star:
[tex]\[ W_{\text{Neutron Star}} = \frac{{6.67 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \cdot 69 \, \text{kg} \cdot 1.99 \times 10^{30} \, \text{kg}}}{{(25,000 \, \text{m})^2}} \][/tex]
Calculate[tex]\( W_{\text{Neutron Star}} \)[/tex]:
[tex]\[ W_{\text{Neutron Star}} \approx 2.8 \times 10^{12} \, \text{N} \][/tex]
So, your weight on the surface of a neutron star with the same mass as the Sun and a diameter of 25.0 km would be approximately [tex]\( 2.8 \times 10^{12} \, \text{N} \).[/tex]
Your weight on the neutron star would be approximately 1.45 × 10¹³ N due to the extremely high gravitational acceleration of 2.13 × 10¹¹ m/s².
To determine your weight on a neutron star, we first need to calculate the gravitational acceleration on its surface. Given:
The mass of the neutron star, M = 1.99 × 10³⁰ kgThe radius of the neutron star, R = 25.0 km = 2.5 × 10⁴ mThe gravitational constant, G = 6.67 × 10⁻¹¹ N⋅m²/kg²The formula for the gravitational acceleration gstar on the surface of a spherical object is:
gstar = G M / R²
Plugging in the values:
[tex]g^* = \frac{(6.67 \times 10^{-11} \, \text{N} \cdot \text{m}^2/\text{kg}^2) \times (1.99 \times 10^{30} \, \text{kg})}{(2.5 \times 10^4 \, \text{m})^2}[/tex]
gstar ≈ 2.13 × 10¹¹ m/s²
This is the gravitational acceleration on the neutron star. To find your weight, we use:
Weightstar = Mass * gstar
Your mass (from Earth weight):
Mass = WeightEarth / gEarth = 670 N / 9.81 m/s² ≈ 68.3 kg
Therefore, your weight on the neutron star:
Weightstar = 68.3 kg * 2.13 × 10¹¹ m/s² ≈ 1.45 × 10¹³ N
Therefore, your weight on the neutron star would be approximately 1.45 × 10¹³ N
A spring is stretched 175 mm by an 8-kg block. the block is displaced 100 mm downward from its equilibrium position and given a downward velocity of 1.50 m/s. assume that positive displacement y is downward.
Answers
The potential energy stored in a spring is given by the equation PE = 0.5kx². The speed of the block when it crosses the point where the spring is neither compressed nor stretched can be determined using the principle of conservation of energy. The speed of the block when it has traveled a distance of 20 cm from where it was released can be determined by considering the conservation of mechanical energy.
Explanation:The potential energy stored in a spring is given by the equation PE = 0.5kx², where k is the spring constant and x is the displacement from the equilibrium position. In this case, the spring is stretched by 175 mm (or 0.175 m) and the block is displaced 100 mm (or 0.1 m) downward.
Therefore, the potential energy stored in the block-spring system when the block was just released is:
PE = 0.5 * k * (0.175)²
Since the spring constant is not given in the question, we cannot calculate the exact potential energy. To determine the speed of the block when it crosses the point where the spring is neither compressed nor stretched, we need to use the principle of conservation of energy.
When the block is released, the potential energy stored in the spring is converted into kinetic energy:
PE = KE = 0.5mv²
Where m is the mass of the block and v is its velocity.
To determine the speed of the block when it has traveled a distance of 20 cm from where it was released, we need to consider the conservation of mechanical energy.
I will give u BRAINILIEST and 15 points
need the right answer
_______ is a technique that uses the images from several telescopes to produce a single image.
A. Radiation
B. Reflection
C. Refraction
D. Interferometry
Answers
It's a D. Interferometry I just took the test and I got it right
Select all that apply.
Which of the following are appropriate acceleration units?
-km/hr2
-m/s/s
-ft/s
-miles/hr/min
-sec/km/m
Answers
are perfectly good units of acceleration.
The only one that isn't is the one in the middle: ft/s
km/hr2 ,m/s/s and miles/hr/min are appropriate units of the acceleration from all the given options.
What is acceleration?The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².
Newton's three equations of motion are only applicable for the constant acceleration, the slope of the velocity time graph represents the acceleration of any object.
As we know the rate of change of velocity is known as acceleration
acceleration =change in velocity/change in time
In the acceleration unit, we divide the velocity and time components by the units of meters per second (m/s) and seconds (s) to compute acceleration. In addition, multiplying a distance by time twice equals multiplying a distance by time squared. The meter per second squared, or (m/s2), is the SI unit of acceleration as a result.
Thus, Out of all the alternatives provided, km/hr2, m/s/s, and miles/hr/min are valid units of acceleration.
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A mirrored-glass gazing globe in a garden is 28.0 cm in diameter. part a what is the focal length of the glob
Answers
[tex]R=2f[/tex] (1)
Since the diameter d is twice the radius R, we can rewrite (1) as
[tex] \frac{d}{2} = 2f [/tex]
From which we can calculate the focal length from the diameter:
[tex]f= \frac{d}{4}= \frac{28.0 cm}{4}=7.0 cm [/tex]
The mirrored-glass gazing globe acts as a concave mirror with a focal length that is half the radius of curvature, and since the globe's diameter is 28.0 cm, its focal length is 7.0 cm.
To find the focal length of a mirrored-glass gazing globe, which acts like a concave mirror, we'll use the relationship between the focal length (f) and the radius of curvature (R) of a spherical mirror. The form of this relationship is f = R/2. Given that the diameter of the globe is 28.0 cm, the radius of curvature R is half of that, which is 14.0 cm. Therefore, we can calculate the focal length by halving the radius of curvature.
Identify that image formation by a mirror is involved, which is a part of optics in physics.
The diameter of the gazing globe is given as 28.0 cm, so the radius R is 28.0 cm / 2 = 14.0 cm.
Use the relationship f = R/2 to find the focal length.
Calculate the focal length: f = 14.0 cm / 2 = 7.0 cm.
Thus, the focal length of the mirrored-glass gazing globe is 7.0 cm.
An ice skater starts a spin with her arms stretched out to the sides. she balances on the tip of one skate to turn without friction. she then pulls her arms in so that her moment of inertia decreases by a factor of 4. in the process of her doing so, what happens to her kinetic energy? (a) it increases by a factor of 4. (b) it increases by a factor of 16. (c) it remains constant. (d) it decreases by a factor of 4. (e) it increases by a factor of 16.
Answers
An ice skater pulling her arms in during a spin decreases her moment of inertia, increases her angular velocity, and consequently increases her rotational kinetic energy due to the conservation of angular momentum.
When an ice skater spins with her arms stretched out and then pulls them in, her moment of inertia decreases. Since angular momentum must be conserved in the absence of external torques, her angular velocity increases. According to the formula for rotational kinetic energy, K = (1/2)Iω², where K is the kinetic energy, I is the moment of inertia, and ω is the angular velocity, we can see that the kinetic energy depends on both the moment of inertia and the square of the angular velocity. When the skater pulls in her arms, and her moment of inertia decreases, her angular velocity increases sufficiently such that her rotational kinetic energy actually increases because it is proportionate to the square of the angular velocity. Hence, the work done by the skater to pull her arms in results in an increase in rotational kinetic energy, and the correct answer is that her kinetic energy increases, but the exact factor of increase would depend on the relationship between the new and original angular velocities.
Which statements accurately describe sound waves? Check all that apply.
Sound waves are transverse waves.
Sound waves require a medium to transfer energy.
Sound is heard when a vibration strikes the ear.
Sound waves can only travel through liquids and gases.
When particles of a medium interact, part of the wave’s energy is lost.
A wave’s energy can be distinguished from other movements of the medium.
Answers
Sound waves are longitudinal waves, which require a medium to travel. The statements that are true about sound waves are:
Sound waves require a medium to transfer energy. Sound is heard when a vibration strikes the ear. When particles of a medium interact, part of the wave's energy is lost.Sound waves are mechanical waves, which require a medium to travel. The medium can be solids, liquids, and gases. The statements correct about sound waves are:
Sound waves can only travel through mediums. Sound waves cannot be traveled through a vacuum. Sound waves are not transverse waves because their propagation is parallel to the direction of energy transport. The particles of sound waves when interacting, are some of the energy are lost as heat.Therefore, options, 2, 3, and 5 are correct.
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Answer:
B<C,,E
Explanation:
Two boxes need to be moved into storage Jamel and Jude each want to move a box. The force of gravity on both the boxes is 50 N. Jamal is lifting with a force of 60 N. And Jude is lifting with a force of 45 N. Which best describes the movement of the boxes
Answers
more upward force to it than the downward force of gravity,
so the NET force on the box is 10N upward.
Jude won't be able to lift his box. He's applying LESS upward
force to it than the downward force of gravity, so the NET force
on his box is 5N downward.
Which describes how a turbine works to produce energy for electricity? A. Energy from various energy sources, such as wind or from burning fossil fuels, is used to spin the blades of the turbine. The turbine then powers a generator, which produces electricity. B. Energy from various energy sources, such as wind or from burning fossil fuels, is used to spin the blades of the turbine, which produces electricity. C. The turbine produces energy from various energy sources like wind or burning fossil fuels to drive the generator to make electricity. D. The generator produces energy from various energy sources like wind or burning fossil fuels to drive the turbine to make electricity.
Answers
Works on simple principle of the turbine blades translation of energy sources causing the mechanical spin of the blades which is connected to a rotor which spins the main shaft of generator thus producing electricity.
Answer:
A. Energy from various energy sources, such as wind or from burning fossil fuels, is used to spin the blades of the turbine.
Explanation:
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I what is the resistance of
a. a 1.0-m-long copper wire that is 0.50 mm in diameter?
b. a i 0-cm-long piece of iron with a 1.0 mm x 1.0 mm square cross section?
Answers
[tex]R= \frac{\rho L}{A} [/tex]
where
[tex]\rho[/tex] is the resistivity of the material
L is the length of the conductor
A is its cross-sectional area
We can use this formula to solve both parts of the problem.
a) The length of the copper wire is L=1.0 m. Its diameter is d=0.50 mm, so its radius is
[tex]r= \frac{d}{2}=0.25 mm=0.25 \cdot 10^{-3} m [/tex]
And its cross-sectional area is
[tex]A=\pi r^2 = \pi (0.25 \cdot 10^{-3}m)^2 = 1.96 \cdot 10^{-7} m^2[/tex]
The copper resistivity is [tex]\rho=1.68 \cdot 10^{-8} \Omega m[/tex], therefore the resistance of this piece of wire is
[tex]R= \frac{\rho L}{A}= \frac{(1.68 \cdot 10^{-8} \Omega m)(1.0 m)}{1.96 \cdot 10^{-7} m^2}= 8.57 \cdot 10^{-2} \Omega[/tex]
b) The length of this piece of iron is L=10 cm=0.10 m. Its cross-sectional size is L=1.0 mm=0.001 m, so its cross-sectional area is
[tex]A=L^2 = (0.001 m)^2 =1 \cdot 10^{-6}m^2[/tex]
The iron resistivity is [tex]\rho = 9.71 \cdot 10^{-8} \Omega m[/tex], therefore the resistance of this piece of wire is
[tex]R= \frac{\rho L}{A}= \frac{(9.71 \cdot 10^{-8} \Omega m)(0.10 m)}{1.0 \cdot 10^{-6} m^2}=9.71 \cdot 10^{-3} \Omega [/tex]
Using Ohm's law, the resistance of a 1.0m copper wire with 0.50mm diameter is approximated to be 0.027 ohm and the resistance of a 10cm iron piece with a square cross-section of 1.0mm edge length is around 0.097 ohm.
Explanation:The resistance can be calculated using Ohm's law, with the resistance formula R = ρL/A where R is the resistance, ρ is the resistivity, L is the length, and A is the cross-sectional area. For copper, the resistivity is about 1.68 x 10^-8 ohm.meter. The diameter is 0.50mm, so the radius is 0.25mm and the cross-sectional area (A) of the wire is πr^2. Plugging these values into the formula, we find that the resistance of the copper wire is about roughly 0.027 ohm.
For the iron, using its resistivity value which is 9.71 x 10^-8 ohm.meter and the given cross-section of 1.0mm x 1.0mm, the resistance is found to be roughly around 0.097 ohm.
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A gas is compressed from 600 cm3 to 200cm3 at a constant pressure of 400 kpa. at the same time, 100 j of heat energy is transferred out of the gas. part a what is the change in thermal energy of the gas during this process?
Answers
The change in thermal energy of the gas during compression is 159900 J, calculated using the first law of thermodynamics. The work done on the gas by compression is greater than the heat removed, increasing the gas's internal energy.
The change in thermal energy of the gas during the compression process can be found using the first law of thermodynamics, which states that the change in internal energy (ΔU) of a system is equal to the heat added to the system (Q) minus the work done by the system (W).
First, we calculate the work done by the gas during compression. Work (W) can be calculated using the formula W = P ΔV, where P is the pressure and ΔV is the volume change. Since the gas is compressed at a constant pressure of 400 kPa, and the volume changes from 600 cm³ to 200 cm³, the volume change (ΔV) is -400 cm³ (it's negative because the volume decreases).
W = PΔV = 400 kPa (-400 cm³) = -160000 kPacm³
Since 1 kPacm³ is equivalent to 1 J, the work done by the system is -160000 J (negative sign indicates work is done by the gas).
Next, we know that 100 J of heat energy is transferred out of the gas, so Q = -100 J (negative sign indicates heat is lost).
Now, applying the first law of thermodynamics:
ΔU = Q - W
ΔU = (-100 J) - (-160000 J)
ΔU = 159900 J
The change in thermal energy of the gas is 159900 J. The gas's internal energy increases since the work done on the gas is greater than the heat energy removed from it.
An observer is moving in space toward a distant star at 200 km/s while the star is moving toward the observer at 400 km/s; the relative velocity being 600 km/s of approach. what relative change in frequency of the light from the star as seen by the observer? (the speed of light in space is 3.00 ´ 105 km/s).
Answers
Explanation:
The observed frequency can be found by using the following equation:
[tex]v = v_o ( \frac{1 + \frac{v_{observer}}{c}}{1- \frac{V}{c}} )[/tex] --- (1)
Where [tex] v_{observer} [/tex] = Speed of the observer = 200 *1000 m/s
V = speed of the star = 400 *1000 m/s
Plug in the values in (1):
(1) => [tex]v = v_o ( \frac{1 + \frac{200*10^3}{3*10^8}}{1- \frac{400*10^3}{3*10^8}} )[/tex]
[tex]v = v_o ( 1.002 )[/tex] --- (2)
Change in frequency is given as: [tex] \frac{v_o - v}{v_o} * 100[/tex]% --- (3)
Put (2) in (3):
[tex]\frac{v_o - 1.002*v_o}{v_o} * 100[/tex]%
=> -0.2%
Negative sign shows that it decreases!
Hence it is 0.2% (decrease).
A formatted printout (or screen display) of the contents of one or more tables or queries is a form. _________________________
a. True
b. False