Mr.Walden wrote the expression p^-5/q^0. He asked his students to write an equivalent expression of p^-5/q^0 simplified form. Four students wrote these expressions. Isaac q^0/p^-5 Rosa p^-5+p^0 Bruce p^5q^0 Brianna 1/p^5q^0 Which student is correct? Isaac Rosa Bruce Brianna

First : Distributive Property

(1/9∙x)+(1/9∙18)

1/9x+18/9

(1/3∙2x)+(1/3∙3)

1/9x+2+2/3x+1=x+3

Second : Rearrange

1/9x+2/3x-x+3-2-1

Third : Solve!                    :D

-7/9x=0

7/9x=0

x=0

When multiply two power expressions, that both have the same base, we can simply add the exponents.

For the first image that you provided:

y^(3/4) x y^(1/3) = y^(3/4 + 1/3) = y^(9/12 + 4/12) = y^(13/12)

Let me know if you have any further questions!

Plz mark as brainliest

The expression (y^2)^3 can be rewritten as y^6 using the rule of exponents that states when you raise a power to a power, you multiply the exponents.

The expression (y^2)^3 can be rewritten in the form of y^n using the rule of exponents which states that when you raise a power to a power, you multiply the exponents.

Here, we have y raised to the power 2, and that result is being raised to the power 3. We multiply these exponents together (2*3) to get 6. Thus, the rewritten expression is y^6.

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Here we are given the speed in meter per second as 8.8 m/s.

Now we have to convert this speed into kilometers per hour.

We are also given :

1 kilometer = 1000 meters and

1 hour = 60 minutes = 3,600 seconds

Now let us convert 8.8 m/s into km/h

1 m/ sec = (1/1000) km / (1/3600) hr

1 m/ sec = 18/5 km /hr

8.8 m/ sec = (18/5) * 8.8 km /hr

8.8 m/ sec = 31.68 km/h

Answer: So the speed in kilometers per hour is 31.68 km/hr. (option C)

Answer is provided in the image attached.

We have 8^(-4) over 8^(-10). The bases are both 8, so we subtract the exponents (numerator minus denominator).

[tex]\frac{8^{-4}}{8^{-10}} = 8^{-4-(-10)} = 8^{-4+10} = 8^{6}[/tex]

The final answer is choice C) 8^6

405,000,000 - 1.7×10^8

= 4.05 × 10^8  - 1.7 × 10^8

= (4.05 - 1.7) × 10^8

= 2.35 × 10^8

Hope it helps

x=Mike's age

y=Dan's age

It is given that,Mike is three years older than dan.

→ x=y+3

If you will draw the graph of the function, it will cut x axis at (3,0) and y axis at (0,-3).

⇒Graph-2

The graph that represents the relationship between Mike's age and Dan's age (y), is Option A with a positive slope of 1.

The relationship between Dan's age and Mike's age can be represented by a linear equation, where Mike's age (x) is three years older than Dan's age (y).

Therefore, the graph that represents this relationship would be a straight line with a positive slope of 1 and a y-intercept of -3.

The equation for this relationship would be:

x = y + 3

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The number 44 is 11 percentage of the number 400, and the correct option is B) 44 = 0.11 * x ; 400

Given data:

The first number is represented as p.

The value of p = 44

The second number is represented as q.

The value of q = q

So, the percentage of the number is A = 11 %, where A = ( p/q ) * 100

On simplifying the equation:

11 = ( 44/q) * 100

q = 4 * 100

q = 400

Hence, the number is 400.

To learn more about percentage, refer:

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the lenght of the picture is 14

6x³y + 6xy − 12x² − 12 = 6(xy-2) * (x²+1)

(x²+1) is a factor of 6x³y + 6xy − 12x² − 12

Answer:

y - 7 = -1/2(x + 15)

Step-by-step explanation:

m = (7 + 3)/(-15 - 5)

m = 10/-20

m = -1/2

y - y₁ = m(x - x₁)

y₁ = 7; x₁ = -15

y - (7) = (-1/2)(x - (-15))

y - 7 = -1/2(x + 15)

Hi,

You are absolutely correct.

You need to write it in decimal form.

Here are the answers

19) 5/11 = 0.4545 (Repeating decimal)

20) 6/10 = 0.6  (terminating decimal)

21) 4/11 = 0.3636363  (Repeating decimal)

22) 10/15 = 0.666667  (Repeating decimal)

Thank you :)

Answer:

Alecia drives at a slower rate than Trish, according to my math, too lazy to explain, please just believe me.

46 MPH for Trish.

Step-by-step explanation:

Please mark Brainliest!

Alecia drives at 43 mph and Trish drives at 46 mph. Alecia drives slower than Trish.

we have been given table containing 6 points.

let the numbers at question mark (?) are x and y respectivelly so we can rewrite the table as:

[tex]\left[\begin{array}{cccccc}a&5&6&7&8&9\\b&3.8&4.6&5.4&x&y\end{array}\right][/tex]

In the first row we see that numbers increase by 1 so that clearly means a=4.

Now we need to find the common difference in the outputs to help find the missing outputs in the table.

4.6-3.8=0.8

5.4-4.6=0.8

we are getting common difference of 0.8 so that means missing values can be found by adding or subtracting 0.8 as per their position.

b=3.8-0.8=3

x=5.4+0.8=6.2

y=6.2+0.8=7

Hence the final answer is given by table:

[tex]\left[\begin{array}{cccccc}4&5&6&7&8&9\\3&3.8&4.6&5.4&6.2&7\end{array}\right][/tex]

I am not sure what the answer is, so thanks for the free points?..

If the width is 3 less than the height, we can say that the width is x, and the height is x+3. As the tank is square based, we can say that the length is also x. If the tank has a capacity of 20, this is the volume of the tank. Using the formula for volume, we get (x)(x)(x+3)=20. We multiply this out to get x^3+3x^2=20. If we think this one through, we can realize that 2 works for x, as 8+12 = 20. This means that the dimensions are 2 by 2 by 2+3, or 5.

The standard form of an ellipse is

[tex] \dfrac{(x-x_0)^2}{a^2}+\dfrac{(y-y_0)^2}{b^2}=1 [/tex]

Let's try to complete some squares: if we focus on the part involing x, we have

[tex] 9x^2+54x = 9x^2+54x+81-81 = (3x+9)^2-81 = 9(x+3)^2-81 [/tex]

Similarly, for the part involving y, we have

[tex] 4y^2+8y = 4y^2+8y+4-4 = 4(y+1)^2-4 [/tex]

So, the equation becomes

[tex] 9(x+3)^2-81 + 4(y+1)^2-4 - 59=0 \iff 9(x+3)^2+ 4(y+1)^2-81-4-59=0 \iff 9(x+3)^2+ 4(y+1)^2 = 144 [/tex]

Divide both sides by 144 to get

[tex] \dfrac{(x+3)^2}{16}+ \dfrac{(y+1)^2}{36} = 1[/tex]

which is the standard form

Answer:

D

edge

Step-by-step explanation:

Based on the data set: 21, 23, 19, 25, 83, 23, 21...83 is clearly the outlier

To find the mean, all we have to do is add up all the remaining numbers (since we got rid of the 83) then divide them by how many numbers were added

21 + 23 + 19 + 25 + 23 + 21 = 132

Now we divide 132 by how many numbers were added (6)

132 ÷ 6 = 22

Therefore, the mean of the data set is 22

Hope this helps you

-AaronWiseIsBae

Function 1:

For the given table

[tex]\begin{array}{cc}x&f(x)\\-2&-2\\-1&1\\0&4\\1&7\end{array}[/tex]

you can plot the graph of the function (see first attached diagram). This function is linear and has equation f(x)=3x+4.

Function 2:

For the given function f(x)=-2x+3 you can create a table

[tex]\begin{array}{cc}x&f(x)\\-2&7\\-1&5\\0&3\\1&1\end{array}[/tex]

and plot the graph (see second attached diagram).

Function 3:

For the given graph of the function, you can find the function:

[tex]\dfrac{x-0}{6-0}=\dfrac{y-(-3)}{0-(-3)},\\ \\\dfrac{x}{6}=\dfrac{y+3}{3},\\ \\2(y+3)=x,\\ \\y=\dfrac{1}{2}x-3.[/tex]

Thus, the equation of the function 3 is [tex]f(x)=\dfrac{1}{2}x-3.[/tex]

The table will take a look

[tex]\begin{array}{cc}x&f(x)\\-2&-4\\-1&-3.5\\0&-3\\1&-2.5\end{array}[/tex]

The question deals with linear functions representation.For each given linear representation, create two additional: table values and a graph. Use the given information, like equation or table values or a graph, to calculate other forms.

This assignment deals with creating matching cards for linear functions. For each linear function, you'll need to obtain two additional representations. Firstly, you should find the table of values which means identifying various x and y values that satisfy the function. For instance, if your given function is y = 2x + 3, just substitute different values into x and find the corresponding y-values.

Second is to derive the graph. You can do this by plotting the points you obtained for your table of values on a graph. You'll notice that all these points will fall on a straight line as it is a linear function.

The provided representation will guide you while creating your table and graph. For instance, if you are given the equation, figure out the slope and y-intercept because they're crucial to draw the graph and construct the table.

If presented with the table values, find the rate of change, which will be the slope, and a point on the table which gives you the y-intercept and hence give you an equation. Finally, if given a graph, find two points on the line then apply the slope-intercept form to find your equation and table values.

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Solution

The general form of the n-th term = a + (n-1)d

Here we are given the 1st term (a) = 1

2nd term = 2

So the sequence is

1, 2, 3, 4, 5 , 6, 7, 8, ....................100, 101, 102....

The value of the first term in this sequence that is greater than 100 is 101.

Answer is a. 101

Scott starts with 25 plus the 100 from his grandfather making 125 then subtract 50 that he traded so you get 75

If you want an inequality, it would be 10m≤22 but the sign doesn't have a line under it

(couldn't find the one without the line)

If you want to solve then m≤2.2 and the line isn't under the sign

f(x)=3x+1, range x={4,5,6} --> domain is a set of values {13, 16, 19}

f(x)=x+10, for x={10,4,-6} domain is a set of {4, 14, 20}

The method that is used to solve systems of equations is D. All of the above.

Therefore, the correct option is all of the above.

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There is a lot to go over here. Unfortunately it looks like you got a lot incorrect. I'll focus on two problems. Hopefully these examples below will help correct the other mistakes.

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Problem 7)

We have the starting value be 20 and the ending value be 11. Subtract the values: (end)-(start) = 11 - 20 = -9. The negative indicates we have a drop or decrease.

We'll focus on the positive version of this number, so 9. Divide this value over the starting amount 20 to get 9/20 = 0.45 = 45%

So going from 20 miles to 11 miles is a decrease of 45%

Answer to problem 7 is: 45%

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Problem 13)

An increase of 300% means we added 3 times the original amount onto the original amount.

We take 300% of 25 to get 3*25 = 75

Which is then added onto 25 to get 25+75 = 100

Answer to problem 13 is: 100

answer: 20

work:

okay, so to solve this, set up as a system of equations and solve:

[tex]\frac{3}{5} = \frac{12}{x}[/tex]

this equation models our problem, because it shows the 3 to 5 ratio and out 12 to x, the number we're trying to find.

so, to solve, cross multiply

3(x) = 5(12)

3x = 20

x = 20

so, when there are 12 oranges, there are 20 pics total.

checking the answer:

the original equation states that "Three out of every five picks are orange" so, this means we can represent this as a fraction, 3/5.

to verify if our other fraction, which we can model as 12/20 is correct, we can simplify it, and if it's equivalent to 3/5 we know it's correct.

so, to simplify we need to find the greatest common factor between 12 and 20 so we can divide both numbers by this fraction.

well, the greatest common factor between these two numbers is 4, so divide both of them by 4.

[tex]\frac{12}{20}[/tex] ÷ [tex]\frac{4}{4} = \frac{3}{5}[/tex]

so, this verifies my answer is correct. hope this helps, and have an amazing day!