Ms. Hartman's class is going on a field trip to the planetarium. There are 25 students in the class, and each student needs to purchase a day pass to the planetarium and a lunch ticket. The day pass costs $10, and the lunch ticket costs t dollars.
Pick all the expressions that represent the total cost for the field trip.

250+10t

t(25+10)

250+25t

25(10+t)

f(18) = 39.50

This gives the monthly cost Kelsey will pay if she streams 18 movies in a month

Step-by-step explanation:

Given function is:

[tex]f(x) = 1.50x+12.50[/tex]

Here x is the number of movies

so for f(18), this means that the total number of movies will be 18

Solving

[tex]f(18) = 1.50(18)+12.50\\f(18) = 27+12.50\\f(18) = 39.50[/tex]

Hence,

f(18) = 39.50

This gives the monthly cost Kelsey will pay if she streams 18 movies in a month

Keywords: functions, Domain,range

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Answer:

[tex]a_{n} = a_{1} + (n-1)[/tex]this is the required representation for showing the position of a term in the sequence.

Step-by-step explanation:

Given:

The sequence is as follow:

0, 1, 2, 3, .......

To Find:

The expression while using 'n' to represent the position of a term in the sequence where n = 1 for the first term 0, 1, 2, 3, ....

Solution:

n = to represent the position of the term in the sequence.

[tex]a_{1} = \textrm{represent the first term in the sequence.} = 0[/tex]

d = Common difference.,i.e difference between the consecutive term.

d = second term - first term.

or

d = third term - second term.

Here we have d = 1 - 0 = 1

or                     d = 2 - 1 = 1

So, the required expression is

[tex]a_{n} = a_{1} + (n-1)\times d[/tex]

[tex]a_{n} = a_{1} + (n-1)[/tex]

If we require first term put n = 1

[tex]a_{1} = a_{1} + (1-1)[/tex]

[tex]a_{1} = 0[/tex]

If we require second term put n = 2

[tex]a_{2} = a_{1} + (2-1)[/tex]

[tex]a_{2} = 0 + 1[/tex]

[tex]a_{2} = 1[/tex]

If we require third term put n = 3

[tex]a_{3} = a_{1} + (3-1)[/tex]

[tex]a_{3} = 0 + 2[/tex]

[tex]a_{3} = 2[/tex]

and so on.......

Answer:

See explanation

Step-by-step explanation:

Let [tex]F(x)=\left(\dfrac{2}{3}\right)^x.[/tex] Plot the graph of this function. From the graph:

A. The domain of the function is [tex]x\in (-\infty,\infty).[/tex]

B. The range of the function is [tex]y\in (0,\infty).[/tex]

C. The y-intercept of the graph of F(x) is [tex](0,1).[/tex]

D. The horizontal asymptote is x-axis.

E. The graph of the function F(x) is decreasing from left to right.

F. The value [tex]\frac{2}{3}[/tex] determines that the graph of the function is decreasing from the left to the right.

Answer:

what he said above me

Step-by-step explanation:

The average rate of change of d(t) from t = 3 to t = 6 represent: A. The coin travels an average distance of 44.1 meters from 3 seconds to 6 seconds.

In Mathematics and Geometry, the average rate of change (ARoC) of a function f(x) on a closed interval [a, b] can be calculated by using this mathematical equation (formula):

Average rate of change (ARoC) = [tex]\frac{f(b) - f(a)}{(b - a)}[/tex]

Based on the given quadratic function, we can reasonably infer and logically deduce the following:

[tex]d(t)=4.9t^2\\\\d(3)=4.9(3)^2[/tex]

f(a) = d(3) = 44.1

[tex]d(t)=4.9t^2\\\\d(6)=4.9(6)^2[/tex]

f(a) = d(3) = 176.4

Next, we would determine the average rate of change (ARoC) of the function over the interval [3, 6]:

Average rate of change (ARoC) = [tex]\frac{176.4 - 44.1}{(6 - 3)}[/tex]

Average rate of change (ARoC) = 44.1 meters.

In this context, we can logically deduce that the coin travels an average distance of 44.1 meters from 3 seconds to 6 seconds.

Answer:

b. [tex]\frac{(10+x)}{(y-3)}[/tex]

Step-by-step explanation:

Question:

Look at each expression. Is it equivalent to "the quotient of 10 plus x and y minus 3"?

a. (10+x)/(y)

b. (10+x)/(y-3)

c. 10+(x)/(y)-3

d. (10+x-3)/(y)

Solution:

Given statement:

The quotient of 10 plus [tex]x[/tex] and [tex]y[/tex] minus 3

From the statement we can have the following:

Dividend =[tex]10+x[/tex]

Divisor [tex]=y-3[/tex]

The quotient is given by dividend divided by divisor.

The quotient thus can be expressed as:

[tex]\frac{(10+x)}{(y-3)}[/tex]

Answer: The answer will be C.

Answer:

the process of retting softens the tissue and helps to separate the fibres

Step-by-step explanation:

the process of retting softens the tissue and helps to separate the fibres

Thanks

Answer:

G: (-2, 0.5)

Step-by-step explanation:

the "X" is -2 and then the "Y" is 0.5 because it is between 0 and 1, so we could the that Y-axis is being added by 0.5 each time.

The class average on test 2 is 76 points

Given that, the class average on test 1 was 84.  

And the class average on test 2 was 8 points lower.  

We have to find what was the class average on test 2?  

Now, according to the given information.

Class average on test 2 is 8 points lower than class average on test 1.

So, class average on test 2 = class average on test 1 – 8 points

Class average = 84 – 8  

Class average = 76 points.

Hence, the class average on test 2 is 76 points

Answer:

x = ± 12

Step-by-step explanation:

Given

f(x) = x² - 144

To find the roots set f(x) = 0, that is

x² - 144 = 0 ( add 144 to both sides )

x² = 144 ( take the square root of both sides )

x = ± [tex]\sqrt{144}[/tex] = ± 12

Final answer:

The roots of the given quadratic function f(x) = x² - 144 are x = 12 and x = -12.

Explanation:

The roots of a quadratic function can be found by setting the function equal to zero and solving for x. In the case of f(x) = x² - 144, this is equivalent to solving the equation x² - 144 = 0. This equation is a difference of squares and can be factored as (x - 12)(x + 12) = 0. The roots of the equation are the values of x that make the equation true, which in this case are x = 12 and x = -12.

Answer:

5n+p>40

n+p<20

Step-by-step explanation:

Since pennies are worth 1 cent and nickels 5, using n as the number of nickels and p as the number of pennies, we can say that 5*n+1*p>40. Then, n+p is less than 20, so n+p<20. Our answer is then

5n+p>40

n+p<20

The currency called the dollar can be split into smaller forms called nickels, pennies, dimes, and quarters.

The system of inequalities that represents how many pennies and nickels that Jada could have is given as:

Let's represent the number of :

pennies = p

nickels = n

It is important to also note that:

1 penny = $0.01

1 nickel = $0.05

40 cents can also be written as: $0.40

Jada has p pennies and n nickels that add up to more than 40 cents.

The word more than means greater than and this can be represented by the inequality sign ">". Hence, our inequality equation is given as:

$0.01 x p + $0.05 x n > $0.40

0.01p + 0.05n > 0.40

She had fewer than 20 coins altogether.

The word fewer means less than and this can be represented by the inequality sign "<". Hence, our inequality equation is given as:

p + n < 20

Therefore, the system of inequalities that represents how many pennies and nickels that Jada could have is given as:

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Answer:

-x^2+12x-30

Step-by-step explanation:

Answer:

10

Step-by-step explanation:

3 + 7 = 10

Answer: 371697

Step-by-step explanation:

For continuously compounded values, we use the formula Pe^rt, or Pert. P is our principal/initial value, 230000. e is the constant e, r is our rate, 4% or .04, t is our time, 12. So, 230000*e^(.04*12)=371697.112504, rounding down, 371697.

Price of one ream of paper is $6.5

Step-by-step explanation:

Let,

x be the total cost.

Cost of one ream of paper = y

Cost of binder = $4.50

Cost of ink cartridge = $17.50

According to given statement;

x = 4.50 + 6y    Eqn 1

x = 17.50 + 4y   Eqn 2

As both spent the same amount, therefore,

Eqn 1 = Eqn 2

[tex]4.50+6y=17.50+4y\\6y-4y=17.50-4.50\\2y=13\\[/tex]

Dividing both sides by 2

[tex]\frac{2y}{2}=\frac{13}{2}\\y=6.5[/tex]

Price of one ream of paper is $6.5

Keywords: linear equation, division

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Answer:

3.09

Step-by-step explanation:

Answer:

3.09

The drawing will help

Answer:

798

Step-by-step explanation:

hsushshxhuxvshsjsvs

The area of a rectangle is given as:

Area = Length x width

Length = 38

Width = 21

The value of 38 x 21 as an area model is 798.

A rectangle is a two-dimensional shape where the length and width are different.

The area of a rectangle is given as:

Area = Length x width

We have,

38 x 21 as an area model.

This can be considered as,

Length = 38

Width = 21

Now,

The area of a rectangle.

= 38 x 21

= 798

Thus,

The value of 38 x 21 as an area model is 798.

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Answer:

3x^2 + 12x + 4y^2 - 8y = 32

Step-by-step explanation:

3(x^2+4x)+4(y^2-2y)=32

At first we have to break the parenthesis to get the variables in normal position. To break those, we have to multiply each with the help of algebraic expression:

or, (3*x^2) + (3 × 4x) + (4 × y^2) - (4 × 2y) = 32

or, 3x^2 + 12x + 4y^2 - 8y = 32

Since the equation does not have anything to add or deduct, therefore, it is the answer.

Answer:

m=-48.6

Step-by-step explanation:

-27.5-m=21.1

m=-27.5-21.1

m=-48.6

Answer:

48.6 Is your correct answer :)

Step-by-step explanation:Please mark brainlies :)

Answer:

x=5

Step-by-step explanation:

Since a Trapizode has 360 Degrees total and since the sides are equal we can say that

180=110+17x-15

70=17x-15

85=17x

x=5

The value of x in the trapezoid is 5

The sum of the sides on a trapezium is 180 ;

Using the expression :

17x + 95 = 180

17x = 180 - 95

17x = 85

x = 85/17

x = 5

Therefore, the value of x is 5.

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Answer:

Here we do not have the image, but i will try to give a explanation about this type of problem.

When we have the function f(x), the graph of the function h(x) = f(x - x0) means that the graph is displaced by x0 units to the right.

This is because the value of f(x = 0) is equivalent to h( x = x0), but the first one corresponds to the pair (0, f(0)) and the other corresponds to (x0, f(0))

This means that:

g(x) = 3√(x - 4) is displaced 4 units to the right.

g(x) = 3√(x + 4) = g(x) = 3√(x - (-4)) is diplaced 4 units to the left.

g(x) = 3√(x - 1.5) is displaced 1.5 units to the right.

g(x) = 3√(x + 1.5) is displaced 1.5 units to the left.

Answer:

e. It will take 11 seconds to reach the maximum height of 1,936 feet.

f. It will take 22 seconds to return to the earth.

Step-by-step explanation:

Given:

Initial velocity [tex]v_0[/tex] = 352 ft/sec

Solving for question e.

To find the time required to reach the maximum height we will use the formula,

[tex]h(t) = -16t^2+v_0t+h_0[/tex],

where [tex]v_0[/tex] is the starting velocity

[tex]h_0[/tex] is the initial height.

Using the velocity and starting height from our problem we have,

[tex]h(t) = -16t^2+352t+0[/tex],

The path of this rocket will be a downward facing parabola, so there will be a maximum.

This maximum will be at the vertex of the graph.

To find the vertex we start out with [tex]x= \frac{-b}{2a}[/tex] which in our case is,

[tex]x=\frac{-352}{2(-16)}=\frac{-352}{-32}= 11[/tex]

So, It will take 11 seconds for the rocket to reach its maximum height.

We will find maximum height using the formula by substituting value of t we get,

[tex]h(11)=-16(11^2)+352(11)+0\\h(11) = -16 \times121+ 352 \times 11 = -1936+3872= 1936 \ ft[/tex]

Hence the maximum height will be [tex] 1936 \ ft[/tex]

Now Solving for question f.

To find the time required for rocket to reach earth.

We will set our formula to 0 to find the time.

[tex]0= -16t^2+352t+0\\-16t(t-22)=0[/tex]

Using the zero product property, we know that either -16t = 0 or t - 22 = 0.  When -16t = 0 is at t = 0, when the rocket is launched. t - 22 = 0 gives us an answer of t = 22.

So the rocket reaches the Earth again at 22 seconds.

Answer:

-2x+3y=15

Step-by-step explanation:

y=2/3x+5

y-2/3x=5

-2/3x+y=5

3(-2/3x+y)=3(5)

-2x+3y=15

First add the two fractions inside parenthesis:

5/7 - 6/14

Rewrite 5/7 to have a common denominator:

5/7 = 10/14

Now you have 10/14 - 6/14

10-6 = 4

The answer is 4/14, which can be reduced to 2/7

Answer:

(a)

Step-by-step explanation:

2/7 hope it helps

Answer:

First box: 2

Second box: 30

Third box: 42

Step-by-step explanation:

5 sixes means 5 · 6, which equals 30. An unknown amount of sixes equals 12, which is 2 because 2 · 6 = 12.

30 + 12 = 42

7 · 6 = 42, so 42 is the answer.

I hope this helped! :)

They next ring together will be at 6:50 a.m.

Step-by-step explanation:

The given is:

We need to know at what time will they next ring together

To solve the problem lets find the lowest common multiple of 10 and 25

∵ The multiples of 10 are 10 , 20 , 30 , 40 , 50 , 60 , 70 , 80 , 90 , 100 , .....

∵ The multiples of 25 are 25 , 50 , 75 , 100 , ........

∵ The common multiples of 10 and 25 are 50 , 100 , ......

∴ The lowest common multiple of 10 and 25 is 50

∵ The two bells start ringing together at 6 a.m.

∵ The first bell rings every 10 minutes

∴ The first bell rings at 6:10 a.m. , 6:20 a.m. , 6:30 a.m. , 6:40 a.m. ,

   6:50 a.m. , .........

∵ The second bell rings every 25 minutes

∴ The second bell rings at 6:25 a.m. , 6:50 a.m. , ........

∴ They start ringing together at 6:50 a.m.

They next ring together will be at 6:50 a.m.

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Final answer:

To determine when two bells will next ring together, find the Least Common Multiple (LCM) of their ringing intervals. The LCM of 10 and 25 is 50, therefore the bells will next ring together at 6:50 a.m.

Explanation:

The question is about finding the next time two bells, ringing at different intervals, will ring together. To solve this, we need to find the Least Common Multiple (LCM) of the two bell ringing intervals: 10 minutes and 25 minutes. The LCM of 10 and 25 is 50 since 10 × 5 = 50 and 25 × 2 = 50. Since the bells start ringing together at 6 a.m., they will next ring together 50 minutes later.

Adding 50 minutes to 6 a.m., we get 6:50 a.m. Therefore, the two bells will next ring together at 6:50 a.m.

Answer:

9/2

Step-by-step explanation:

(3/4)/6=(3/4)(6/1)=18/4=9/2

Answer:

the line should have an open circle on 75.7 and point to the right