NEED HELP ASAP!!!! PLEASE?! An insecticide contains 75 centigrams of inherit ingredient for every 1 centigrade of active ingredient. If a quantity of the insecticide weighs 380, how much of each type ingredient does it contain?

Um, I'm not directly sure what you mean but if its 5-2 then it makes 3.

I don't get this question. But, if its 5 - 2 it is 3.

Hope this helps! :)

This is placed at the thousandth place

(i think that is what you wanted me to answer..?)

hope that helps :)

Add 16 to 1 9/16 that will then be 25/16 then you divide 5 from 25 that equals 5 so that is your answer

There are 259 kids on all 7 buses.

It will take 4 minutes to rotate 1º because 15 divided by 15 is one (to get 1º) and 60 (1 hour) divided by 15 is 4.

63 is your answer

Check:

Multiply: 3 x 2 = 6

Check that it is greater than 60, less than 70: 60 < 63 < 70

~Rise Above the Ordinary

77 - 3x = 5

subtract 77 from both sides : -3x = -72

divide by -3 on both sides to get x by itself : x = 24

The answer is that Mia has 24 friends (x = 24)

Answer:

open

Step-by-step explanation:

Inflation is the term used when an increase in the money supply reduces the purchasing power of money and causes prices to rise.

The length of ribbon needed to make 9 bows is 9 times the amount of ribbon needed for one bow, expressed mathematically as 9*x given 'x' is the length of ribbon for one bow.

Based on your query, there appears to be a detail missing, which is the length of the ribbon needed to make one bow. Suppose we denote that length as 'x' units. To find the total length necessary for making 9 bows, we would simply multiply that length by 9. In mathematical terms, this would be expressed as 9*x. So if it takes x units of ribbon to make one bow, it will take 9*x units of ribbon to make 9 bows.

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#SPJ2

Due to a typo, the exact length of ribbon per bow is unspecified. Assuming a length of [tex]\( x \)[/tex] per bow, for 9 bows the total needed would be [tex]\( 9x \)[/tex] This is akin to scaling up costs for making multiple items, similar to the production cost examples provided.

It seems there is a typo in the initial fraction of ribbon used per bow, as it is not provided in the question. Assuming the fraction provided is the one we would work with, let's say it takes [tex]\( x \)[/tex] of a ribbon to make one hair bow. To find out how much ribbon is needed to make 9 bows, we multiply [tex]\( x \)[/tex] by 9. Therefore, the total amount of ribbon required for 9 bows would be [tex]\( 9x \)[/tex].

Going by the example information given, if we compare it with the cost of manufacturing goods, we can draw on the parallel of calculating the cost to produce multiple items. For example, if pants finishing costs 49 cents for 7 pairs, and we want to calculate for 9 pairs, we would set up a proportion or use unit rate to find the answer. Though this example doesn't directly relate to the ribbon question, it illustrates the process of scaling up a unit quantity to a larger quantity, which is a common mathematical operation in both scenarios.

Answer:

Step-by-step explanation:

Solution in given attachment.

To round 12,387 with the thousands place underlined, we look at the digit to the right (3) and, since it is less than 5, we round down by keeping the 2 unchanged and turning all the digits to its right to zeros, which gives us 12,000.

Since the next digit (3) is less than 5, we do not increase the value of the underlined digit. Thus, we keep the 2 as it is and change all the digits to the right of it to zeros, resulting in the rounded number 12,000.

This concept is similar to the general principle applied when rounding numbers, which involves looking at the digit immediately to the right of the target place value. If it's 5 or greater, we round up. Otherwise, we round down. Examples of rounding numbers in different situations include:

Significant figures: Rounding an answer like 2,085.5688 to five significant figures would result in 2,085.6 because the first digit to be dropped is greater than 5.

Limiting the final answer to a certain place value: When adding 6527.23 and 2, the answer must be reported as 6528 because the digit 2 has no decimal places that would be significant, so we can only report to the ones place.

When working with calculations such as 119.902, if we need to limit our answer to tenths based on significant figures, we round down to 119.9.

if ur saying 1 13/15 divided by 1 2/5 then the answer is

The exact form : 4/3

Decimal form : 1.3

Mixed number form : 1 1/3

Answer:

it is right

Step-by-step explanation:

Yes, you are correct.  A negative number times a positive is a pos, and 4 times 12 is 48. Neg times a neg is a pos, and 48 times 3 is 144.

Swimmers: 50 children ÷ 12 = 4.2  (you can't have a decimal so you must round up)

5 adults are need.

Dancers: 32 children ÷ 15 = 2.1  (you can't have a decimal so you must round up)

3 adults are need.

Minimum number of adults needed is: 5 for swimmers + 3 for dancers = 8 adults

Answer:

f(-3) =  -9

Step-by-step explanation:

We usually express quadratic functions graphs in the form of f(x) = ax^n + bx + c

So f(-3) means that the value of this graph in the y-axis where x = -3 is -9

f(-3) = -9

I hope this helped.

The value of f(-3) is -9 for the quadratic function graphed.

It is defined as a special type of relationship and they have a predefined domain and range according to the function.

We know that if we plot a quadratic function on the coordinate plane we will get a parabola graph and the standard expression for the parabola:

[tex]\rm f(x)=ax^2+bx+c[/tex]

Where a, b, c are real numbers and a ≠ 0

The value of f(-3) means the value of y on the coordinate plane when [tex]\rm x = -3[/tex]

From the graph, we can see the value of y when x = -3

Therefore,

f(-3) = -9

Thus, the value of f(-3) is -9.

Learn more about the function here:

brainly.com/question/5245372

( - 6, 0).(2, 0 ) , vertex = ( - 2, - 16)

to find the x-intercepts set f(x) = 0

x² + 4x - 12 = 0

(x + 6)(x - 2) = 0 ( equate each factor to zero and solve for x )

x + 6 = 0 ⇒ x = - 6

x - 2 = 0 ⇒ x = 2

x- intercepts are ( - 6, 0),(2, 0)

given the quadratic in standard form : y = ax² + bx + c

the x-coordinate of the vertex = - [tex]\frac{b}{2a}[/tex]

here a = 1 , b = 4 and c = - 12

x- coordinate of vertex = - [tex]\frac{4}{2}[/tex] = - 2

substitute this value into the equation for y-coordinate

x = - 2 → y = 4 - 8 - 12 = - 16

vertex = ( - 2, - 16)

You find the highest number that can divide into all of them without leaving any with a remainder.

Hope this helps.

u have to multiply the three numbers till u get the GCF

correct me if im wrong

have a blessed day!

x + (x + 1) = 75

2x + 1 = 75

2x = 74

x = 37

75 - 37 = 38

You can check by substituting the product for the value of x.

37 + 37 + 1 = 75

The two consecutive integers whose sum is 75 are; 37 and 38.

If two consecutive integers sum up to become 75.

We can represent the first number as = x and

the second number as = (x + 1).

The sum of both of the numbers = 75.

therefore, x + (x + 1) = 75.

Dividing both sides of the equation by 2; we have;

x = 37

x + 1 = 38.

Ultimately, the two consecutive integers are; 37 and 38.

Read more:

https://brainly.com/question/18370359

Answer: 1)100ways and 2)90ways

Step-by-step explanation:

Given :-The 10 students who completed a special flying course are waiting to see if they will be awarded the one Distinction or the one Merit award for their efforts.

Ways can the two awards be given if the same student can receive both awards (i.e repetition is allowed)

=10×10=100ways

Ways can the two awards be given if the same student cannot receive both awards(i.e. repetition is not allowed)

=10×9=90ways

Final answer:

The number of ways two awards can be given out to 10 students is 100 when the same student can win both awards, and 90 when different students must win each award.

Explanation:

The student's question deals with the number of ways two awards can be given out to a group of 10 students under two different scenarios: one where the same student can receive both awards, and the other where the same student cannot receive both awards. This is a problem of permutations and combinations, a fundamental concept in probability and statistics.

Scenario 1: Same Student Can Receive Both Awards

In the first scenario, the same student can receive both the Distinction and the Merit award. Since there are 10 students and each student can potentially receive each of the two awards, we have 10 choices for the Distinction award and 10 choices for the Merit award. The total number of ways the two awards can be given out is simply the product of these two numbers:

10 (for Distinction) × 10 (for Merit) = 100 ways

Scenario 2: Different Students Receive Awards

In the second scenario, the same student cannot receive both awards. This means that once a student has been given one award, they cannot receive the other one. For the Distinction award, there are still 10 possible students. However, for the Merit award, there are only 9 remaining choices since the Distinction awardee cannot be considered:

10 (for Distinction) × 9 (for Merit) = 90 ways

Given that speed of the cyclist = 36 kilometers per hour.

Now question says to find the speed in meters per second.

We know that 1 kilometer = 1000 meter

and 1 hour = 3600 seconds

so to convert 36 kilometers per hour into meter per second, we will multiply 36 by 1000/3600

36*1000/3600

=36*10/36

=10

Hence final answer is speed = 10 meters per second.

That 10 meters per second means cyclist will travel 10 meters in 1 second.

Now to find distance travelled in 5 seconds, we just need to multiply 10 and 5

So the final answer will be 10*5 or 50 meters.

Answer:

Adult ticket = $8

Child ticket = $5.5

a = 8 and c = 5.5

Step-by-step explanation:

2a + 4c = 38

3a + 3c = 40.5

To solve for the value of a and c in these equations. We solve the simulatenous equation by substitution method.

2a + 4c = 38 ..........eqn1

3a + 3c = 40.5 ............eqn2

Step 1, Find the value of a in eqn1

2a + 4c = 38

2a = 38 - 4c

a = (38-4c)/2

a = 19 - 2c

Step 2, subtitle the value of a in eqn2 to get the value of c.

3a + 3c = 40.5

3(19-2c) + 3c = 40.5

57 - 6c +3c = 40.5

57-40.5 = 6c -3c

16.5 = 3c

c = 16.5/3

c = 5.5

Step 3, subtitle the value of c in eqn1 to get the value of a.

2a + 4c = 38

2a + 4(5.5) = 38

2a + 22 = 38

2a = 38-22

2a = 16

a = 16/2

a = 8

Therefore:

Adult ticket = $8

Child ticket = $5.5

a = 8 and c = 5.5

-1 1/8 because -9/8 is equal to [tex]-\frac{9}{8}[/tex] so just make it a improper fraction, pretend the negative is not there then add the negative at the end

-hope this helps :D

Answer: Our required decimal expansion would be[tex]1.\bar{240}[/tex]

Step-by-step explanation:

Since we have given that

[tex]1\dfrac{80}{333}[/tex]

We need to write in decimal form:

First we change the mixed fraction into improper fraction:

[tex]\dfrac{333\times 1+80}{333}=\dfrac{413}{333}\\\\=1.240240...............\\\\=1.\bar{240}[/tex]

Hence, our required decimal expansion would be[tex]1.\bar{240}[/tex]

680*.0013=.884 because 6.8*10^2=680 and 1.3*10^-3=.0013 when you multiply them it'll give you .884

always move the decimal point the number of times that 10 is to the power to.

for example if its a negative number you move the decimal back and add zeros

if its a positive number move forward and add zeros

Answer:

8.84x10^-1

Step-by-step explanation:

Thankyou

the original price of the sofa was 727.26

the product is always the same:

1440

The smallest possible product using the digits 2, 3, 5, 6, 8 is 1440.

To do this, we’ll arrange the digits in ascending order:

2 < 3 < 5 < 6 < 8

Hence, the smallest number formed using these digits is 23568.

Now let’s calculate the product:

2*3*5*6*8 = 1440

So, the product is always the same: 1440.

Whether you arrange the digits in ascending or descending order, the product remains unchanged because multiplication is commutative (i.e., the order of multiplication doesn’t matter)

Answer:

the answer is a c and d

Step-by-step explanation:

just think of it like this  6 x (30 - 3) so then it turns into 6 x 27 which is 162 :) I hope this helped :))