Need help with this im confused

In 12 days both geysers erupt on the same day again

The smallest number that is a multiple of each of two or more numbers.

Given:

A geyser Erupts every fourth day.

Another geyser erupts every sixth day.

so, to find how many days will both geysers erupt on the same day again

we have to find the LCM of 4 and 6

So, 4 = 2*2

6= 2*3

LCM (4, 6) =2*2*3 = 12

Hence,  12 days  both geysers erupt on the same day again.

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Answer:

The required probability is : [tex]\frac{1}{15}[/tex]

Step-by-step explanation:

Three married couples have purchased theater tickets and are seated in a row consisting of just six seats.

First we will check the total arrangements that is 6! ways.

6! = [tex]6\times5\times4\times3\times2\times1=720[/tex]

Jim and Paula can sit at far left in 2 ways and the remaining 4 in 4! ways,.

So, probability will be = [tex]2\times\frac{4!}{6!}[/tex]

= [tex]2\times\frac{24}{720}[/tex]

= [tex]\frac{48}{720}[/tex]

= [tex]\frac{1}{15}[/tex]

Answer:

Yes, SDS > SDT

Step-by-step explanation:

List S

25, 30, 40, 50, XS

Average list S = 40

So, we could write,

Average list S = 40 = (25 + 30 + 40 + 50 + XS) / 5

Solving for XS

XS = 40 x 5 – 25 – 30 – 40 – 50 = 200 – 145 = 55  

SDs = SD (25, 30, 40, 50, 55) = 12.74

List T

30, 40, 45, 50, XT

Average list T = 40

So, we could write,

Average list T = 40 = (30 + 40 + 45 + 50 + XT) / 5

Solving for XT

XT = 40 x 5 – 30 – 40 – 45 – 50 = 200 – 165 = 35  

SDT = SD (30, 35, 40, 45, 50) = 7.1

Even at first sight SDS > SDT  because 25 is out of the range 30-50, while 45 is within that range.

List S is more spread than list T.

A lower or higher number than the mean in a list can increase the standard deviation. In this case, the standard deviation of list S is greater than list T due to the presence of 25, which is farther from the mean of 40 than the numbers in list T.

The question asked relates to the standard deviation of two sets of positive integers, list S and list T. For each list, we calculate the standard deviation, which is a measure of how spread out the numbers are around the mean value. Based on the information provided:

The presence of a number lower or higher than the mean in list S or T respectively, will increase the standard deviation because the deviation or difference from the mean is greater. Remember, standard deviation measures the variation or dispersion from the average. Hence, if the integer 25 is in List S and the integer 45 is in list T, the standard deviation will be greater for list, S, considering these numbers are farther from the mean of 40 compared to the numbers in List T.

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Answer:

a. The dependent variable for this study is the "number of colds each individual experiences during the 3-month winter season" because it depends on the doses of vitamins and placebo.

b. The dependent variable is discrete because the number of colds is like 1,2,3,... so on.

c. The scale of measurement of the dependent variable is Ratio because the number of cold experiences can be 0.

Answer:

Step-by-step explanation:

1+|2+x|=9

1+|2+x| -1 =9-1

|2+x| = 8

2+x = 8 or 2+x = -8

x=6 or x= -10

Answer:

c

Step-by-step explanation:

i took the k12 test

Answer:

1. No

2.Yes

3.Yes

4.Yes

5.No

Step-by-step explanation:

Plug in the numbers

1. 3+3 = 9+9  /  6 = 18  /  NO

2. 20-0 = 20+0  /  20 = 20  /  Yes

3. 3+0/3-0  /  3/3 = 1  /  Yes

4. 4+3 = 16-9  /  7 = 7  / Yes

5. 0+1 = 1-0/0  /  1 = 1/0 / No

Rate as Brainliest plz

Answer: No Yes Yes Yes No

Step-by-step explanation: brain power

Answer: 90 Earth years.

Step-by-step explanation:

Analizing the information provided in the exercise, you need to find the Least Common Multiple (LCM) of the given numbers.

You can follow these steps:

1. You must descompose 6, 9, 15 and 18 into their prime factors:

[tex]6=2*3\\\\9=3*3=3^2\\\\15=3*5\\\\18=2*3*3=2*3^2[/tex]

2. Finally, you need to choose the commons and non commons with their greatest exponents and multiply them. Then you get:

[tex]L.C.M=2*3^2*5=2*9*5\\\\L.C.M=90[/tex]

Therefore, it will take 90 Earth years for them to all line up.

Answer:

  d.  (4,3,6,2)

Step-by-step explanation:

The list of second numbers of the ordered pairs is the range.

___

The second number of the first pair is 4; the second number of the second pair is 3. The only 4-number answer choice containing these two numbers is (d). You don't even have to work the whole problem to make the proper choice.

Answer:

  r = 29

Step-by-step explanation:

We assume your diagram is showing ...

To find r, use the relationship between the side lengths of the triangle.

__

In a 30°-60°-90° triangle, the ratio of shortest to longest sides is 1 : 2. Therefore, we have ...

 CD/CA = r/(r+29) = 1/2

  2r = r +29 . . . . . . multiply by 2(r+29)

  r = 29 . . . . . . . . . .subtract r

_____

The knowledge of 30°-60°-90° triangle relationships can come from any of several sources. One such source is consideration of what happens when you cut an equilateral triangle along its altitude. (The short side is half the long side of the resulting 30-60-90 triangle.)

Another source is the sine ratio of the 30° angle (trigonometry). Sin(30°) = CD/CA = 1/2.

Answer: [tex]\dfrac{2}{5}[/tex]

Step-by-step explanation:

Given : The proportion of students have a dog : [tex]P(D)=\dfrac{45}{100}[/tex]

The proportion of students have a cat  : [tex]P(C)=\dfrac{30}{100}[/tex]

The proportion of students have  both a dog and a cat  : [tex]P(C\cap D)=\dfrac{18}{100}[/tex]

Now, the conditional probability that a student who has a dog also has a cat will be :-

[tex]P(C|D)=\dfrac{P(C\cap D)}{P(D)}\\\\\\\Rightarrow\ P(C|D)=\dfrac{\dfrac{18}{100}}{\dfrac{45}{100}}\\\\\\\Rightarrow\ P(C|D)=\dfrac{18}{45}=\dfrac{2}{5}[/tex]

Hence, the probability that a student who has a dog also has a cat = [tex]\dfrac{2}{5}[/tex]

Answer:

3/5

Step-by-step explanation: I just did the test and got it right. This was after I tried 2/5 and got it wrong.

Answer:

[tex]x=18[/tex]

[tex]y=60[/tex]

[tex]z=40[/tex]

Step-by-step explanation:

From the relations stablished in the problem we have the following equation system:

[tex]y-z=20[/tex] (equation 1)

[tex]\frac{1}{2} xy+420=\frac{1}{2}z(x+30)[/tex] (equation 2)

[tex]\frac{y}{y+z} =\frac{x}{30}[/tex] (equation 3)

From equation 1 we can find an expression of [tex]y[/tex] in terms of [tex]z[/tex] which we're going to call equation 4

[tex]y-z=20[/tex]

[tex]y=z+20[/tex] (equation 4)

We can then replace the equation 4 in the equation 2 in order to find an expression of [tex]x[/tex] in terms of [tex]z[/tex]

[tex]\frac{1}{2} xy+420=\frac{1}{2}z(x+30)[/tex]

[tex]\frac{1}{2} (xy+840)=\frac{1}{2}z(x+30)[/tex]

[tex]xy+840=z(x+30)[/tex]

[tex]x(z+20)+840=z(x+30)[/tex] (here we replaced the eq.4)

[tex]xz+20x+840=xz+30x[/tex]

[tex]xz+20x-xz=30z-840[/tex]

[tex]20x=30z-840[/tex]

[tex]10(2x)=10(3z-84)[/tex]

[tex]x=\frac{1}{2} (3z-84)[/tex] (equation 5)

Now, we can replace equations 4 & 5 inside the equation 3 so we can find the value of [tex]z[/tex]

[tex]\frac{y}{y+z} =\frac{x}{30}[/tex]

[tex]\frac{z+20}{z+20+z} =\frac{1}{30}*\frac{1}{2} (3z-84)[/tex]

[tex]\frac{z+20}{2z+20} =\frac{1}{30}*\frac{1}{2} (3z-84)[/tex]

[tex]\frac{z+20}{2(z+10)} =\frac{1}{2}*\frac{1}{30} (3z-84)[/tex]

[tex]\frac{1}{2}*\frac{z+20}{z+10} =\frac{1}{2}*\frac{1}{30} (3z-84)[/tex]

[tex]\frac{z+20}{z+10} =\frac{1}{10} (\frac{3z}{3}-\frac{84}{3})[/tex]

[tex]\frac{z+20}{z+10} =\frac{1}{10} (z-28)[/tex]

[tex]z+20 =\frac{1}{10} (z-28)*(z+10)[/tex]

[tex]10(z+20) =z^{2}+10z-28z-280[/tex]

[tex]10z+200 =z^{2}-18z-280[/tex]

[tex]z^{2}-28z-480=0[/tex]

This is a quadratic equation which has the form [tex]a*z^{2} +b*z+c=0[/tex]

where

[tex]a=1[/tex]

[tex]b=-28[/tex]

[tex]c=-480[/tex]

Then, we can find the solutions to this quadratic equation using the well-know quadatric formula which says that

[tex]z=\frac{-b}{2a}[/tex]±[tex]\frac{\sqrt{b^{2}-4ac} }{2a}[/tex]

then, replacing the values of a, b and c we find the values of z

[tex]z_{1}=\frac{-(-28)+\sqrt{(-28)^{2}-4(1)(-480)} }{2(1)}[/tex]

[tex]z_{1}=40[/tex]

[tex]z_{2}=\frac{-(-28)-\sqrt{(-28)^{2}-4(1)(-480)} }{2(1)}[/tex]

[tex]z_{2}=-12[/tex]

We have two possible values of z, but because we're trying to find the measure of trapezoid's height the result shouldn't be negative, so we keep only the positive value of z, then

[tex]z=40[/tex]

Now we may replace this value of z in the equations 4 & 5 in order to find the values of x & y.

[tex]y=z+20[/tex] (equation 4)

[tex]y=40+20[/tex]

[tex]y=60[/tex]

[tex]x=\frac{1}{2} (3z-84)[/tex] (equation 5)

[tex]x=\frac{1}{2} (3(40)-84)[/tex]

[tex]x=18[/tex]

So we've found the values of x, y, and z.

[tex]x=18[/tex]

[tex]y=60[/tex]

[tex]z=40[/tex]

Answer:

a^4 - a^3 + a^2 - 2a - (2)/(a + 1)

The simplified form of (a⁷ - a⁴) ÷ (a³ + a²) is a³ - a⁴.

The given expression is: (a⁷ - a⁴) ÷ (a³ + a²)

To simplify it:

Factor out common terms: a⁴(a³ - 1) / a²(a + 1)

Cancel out common factors: a⁴(a³ - 1) / a²(a + 1) = a³ - a⁴

Therefore, the simplified form of (a⁷ - a⁴) ÷ (a³ + a²) is a³ - a⁴.

Answers and explanations:

87. The domain of added functions includes the restrictions of both. So the range of the added function in this question is [-4, 3]

88. When finding the domain of a divided function we do the same as adding, but with an extra rule: g can't equal zero. So for this question the domain is (-4, 3)

89. To graph f + g you add the y-values for each x-value. I added a picture to help explain this one!

Answer:

87. [-4, 3]

88. (-4, 3)

89. See Attachment

General Formulas and Concepts:

Algebra I

Step-by-step explanation:

*Notes:

Step 1: Define

Identify the domains of each function.

Domain of f(x): [-4, 3]

Domain of g(x): [-5, 5]

Step 2: Find 87.

Determine the x-values for each function that overlap/intersect.

f(x) and g(x) have intersect from -4 to 3.

Domain f + g: [-4, 3]

Step 3: Find 88.

Determine the x-values for which g(x) = 0.

The function g(x) equals 0 at x = -4 and x = 3. Therefore, these x-values are excluded in the domain.

Domain of f/g: (-4, 3)

Step 4: Find 89.

To draw a graph of the f + g, we must combine the y-values for each x-value domain in a t-chart and plot by hand.

x   |   f(x)          x   |  g(x)          x   |  f + g

-4     5             -4     0             -4      5

-3     4             -3      1             -3      5

-2     3             -2     2             -2      5

-1      3             -1      2             -1       5

0      2             0       1             0       3

1        1              1       1              1       2

2      -1             2       1              2      0

3      -3             3      0             3      -3

Answer:

See below.

Step-by-step explanation:

For the triangle to be a right triangle there must be a pair adjacent sides which are at right angles to each other - that is whose slope product = -1.

Slope of AB = (4-2)/(-6- -3) = -2/3.

Slope of BC = (8-4)/ (1 - - 6) =  2/7

Slope of AC =  (8-2) / (1 - -3) = 6/4 = 3/2.

Now 3/2 * -2/3 = -1 so sides AB and AC are at right angles and the 3 points are the vertices of a right triangle.

To confirm if the points A (-3, 2), B (-6, 4) and C (1, 8) are vertices of a right triangle, we use the Pythagorean theorem. After calculating the distances between each pair of points, we found that the square of the length of the longest side equals the sum of the squares of the lengths of the other two sides, proving that they form a right triangle.

To show that the points A (-3, 2), B (-6, 4), and C (1, 8) are vertices of a right triangle, we need to check if the square of the length of the longest side (hypotenuse) is equal to the sum of the squares of the lengths of the other two sides. This is known as the Pythagorean theorem. First, compute the distances between each pair of points using the distance formula:

AB = sqrt[(4-2)^2 + (-6-(-3))^2] = sqrt[2^2 + (-3)^2] = sqrt[4 + 9] = sqrt[13]

BC = sqrt[(8-4)^2 + (1-(-6))^2] = sqrt[4^2 + 7^2] = sqrt[16 + 49] = sqrt[65]

AC = sqrt[(8-2)^2 + (1-(-3))^2] = sqrt[6^2 + 4^2] = sqrt[36 + 16] = sqrt[52]

BC is the longest side, so we need to check if BC^2 = AB^2 + AC^2. Calculating, we find that 65 = 13 + 52, which is true. Therefore, points A, B, and C are vertices of a right triangle.

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Answer:

when x= -7

h(-7) = (-7)^2 -5

= (-1)^2*(7)^2-5

= 1*49-5

= 49-5

=44

Therefore , h(-7)=5

Answer:

h(- 7) = 44

Step-by-step explanation:

To evaluate h(- 7) substitute x = - 7 into h(x), that is

h(- 7) = (- 7)² - 5 = 49 - 5 = 44

The tension when the length is 0.3 meters and the number of vibrations is 12 is 40.96 Kg.

Given, that number of vibrations 'n' per second of a nylon guitar string varies directly with the square root of the tension 'T' and inversely with the length 'L' of the string.

Formulating the relation,

[tex]n \alpha \frac{\sqrt{T} }{L}[/tex]

[tex]n = K\frac{\sqrt{T} }{L}[/tex]

[tex]L \times n = K\sqrt{T}[/tex]

Substitute the values,

T = 256 Kg

n = 15

L = 0.6

[tex]0.6 \times 15 = K \times \sqrt{256}\\K = 9/16\\K = 0.5625\\[/tex]

Now when L = 0.3 and n = 12,

[tex]0.3 \times 12 = 0.5625 \times \sqrt{T}\\\sqrt{T} = 6.4\\ T = 40.96[/tex]

Therefore tension in the string is 40.96Kg .

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Answer:

[tex]2^{12}=4,096[/tex]

Step-by-step explanation:

You know that [tex]3x-y=12[/tex] and have to find

[tex]\dfrac{8^x}{2^y}[/tex]

Use the main properties of exponents:

1. [tex](a^m)^n=a^{m\cdot n}[/tex]

2. [tex]\dfrac{a^m}{a^n}=a^{m-n}[/tex]

Note that

[tex]8=2^3,[/tex]

then

[tex]7^x=(2^3)^x=2^{3\cdot x}=2^{3x}[/tex]

Now

[tex]\dfrac{8^x}{2^y}=\dfrac{2^{3x}}{2^y}=2^{3x-y}[/tex]

Since [tex]3x-y=12,[/tex] then [tex]2^{3x-y}=2^{12}=4,096[/tex]

Final answer:

The value of the expression [tex]\(\frac{8^x}{2^y}\)[/tex] given the equation 3x - y = 12 is 4096, since 8 can be expressed as 2^3 and the properties of exponents allow us to simplify the expression to 2^12.

Explanation:

The question involves determining the value of a mathematical expression given a specific equation.

Given the equation 3x - y = 12, we want to find the value of [tex]\(\frac{8^x}{2^y}\)[/tex].

This can be done by recognizing that 8 is a power of 2, specifically 8 = 2^3.

Thus, [tex]\(8^x = (2^3)^x = 2^{3x}\)[/tex]. Substituting back into the original expression, we get [tex]\(\frac{2^{3x}}{2^y}\)[/tex].

Using the properties of exponents, when dividing terms with the same base, we subtract the exponents: [tex]\(2^{3x - y}\)[/tex].

Since we know 3x - y = 12, we substitute 12 in place of 3x - y, giving us 2^12.

Therefore, the answer is 2^{12}, or 4096.

Answer:

1)3/4 cups of pasta

2)4

Step-by-step explanation:

1) as malik I use half the cups better divide the initial amount 3/4 by 2

C=[tex]\frac{3}{2} .\frac{1}{2} =3/4[/tex]

2)

As Malik use 6 cups, and each plate needs 3/2 cups, we divide 6 by 3/2

C=[tex]\frac{ \frac{6}{1} }{ \frac{3}{2} }=\frac{6.2}{3} =\frac{12}{3} =4[/tex]

Answer:

y = - 7.5

Step-by-step explanation:

Given

- 140 = 18 + 4(5y - 2) ← distribute and simolify right side

- 140 = 18 + 20y - 8

- 140 = 10 + 20y ( subtract 10 from both sides )

- 150 = 20y ( divide both sides by 20 )

- 7.5 = y

Answer:

Step-by-step explanation:

1 ) k²-8k = 0

k(k-8)=0

k = 0 or k=8

2) a²+5a=0

a(a+5) = 0

a=0 or a  = - 5

3 ) 6n²+5n-25=0

delta = b²-4ac      b =5 and a = 6   and   c= - 25

delta = 5²-4(6)(-25) = 625 = 25²

n 1 = (-5+25)/12 = 20/12 = 5/3

n 2 = (-5-25)/12 = -  30/12  = -5/2

same method for 4) and 5)

Answer:

Line 3

Step-by-step explanation:

we have

[tex]4(2x+3)=-20[/tex]

Verify each line

Line 1

[tex]4(2x+3)=-20[/tex] ----> the given equation

Line 1 is correct

Line 2

Distribute in the left side

[tex]8x+12=-20[/tex]

Line 2 is correct

Line 3

Subtract 12 both sides

[tex]8x=-20-12[/tex]

[tex]8x=-32[/tex]

The line 3 is not correct

Tessa made a mistake in Line 3 of the problem. The correct calculation should be -20 minus 12, which equals -32. The solution for x is -4.

The subject of this problem is Mathematics, specifically algebra. Looking at the lines of the problem you provided, we can see that Tessa's mistake lies in Line 3 when she subtracts 12 from -20 and gets -8. The correct subtraction should be -20 minus 12 = -32.

So, Line 3 would correctly be 8x = -32 . To solve for x, we would then divide -32 by 8 to get x = -4.

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Answer:

The X, should be 4

Step-by-step explanation:

7/2x - 5/2 = 23/2

7/2x = 23/2 + 5/2

7/2 = 14

x = 14 . 2/7

x= 4

The solution to the equation [tex]\frac{7}{2}x - \frac{5}{2} = \frac{23}{2}[/tex] is x = 4. By substituting x = 4 back into the equation, we confirm that it satisfies the original equation, proving that the solution is correct.

Let’s solve the equation [tex]\frac{7}{2}x - \frac{5}{2} = \frac{23}{2}[/tex] step-by-step as shown below-

Let's isolate the x-term by adding [tex]\frac{5}{2}[/tex] to both sides of the equation

This simplifies to:

Next, simplify the right-hand side:

Now, multiply both sides by [tex]\frac{7}{2}[/tex] to solve for x:

And the final solution is:

To check the solution, substitute x = 4 back into the original equation:

This becomes:

The left side simplifies to:

Which confirms:

Thus, the solution x = 4 is correct.

Answer:

  c.  7,999,999

Step-by-step explanation:

The number of possible phone numbers is the product of the number of possible digits in each position, less the excluded number:

  8·10·10 · 10·10·10·10 - 1 = 8,000,000 -1 = 7,999,999

Answer:

$58.26.

Step-by-step explanation:

Total cost without sales tax and tip =  3 * 6.25 + 3 * 7.50 + 6 *1.25

= $48.75

Plus Sales tax and tip:

= 48.75 + 0.045*48.74 + 0.15*48.75

= $58.26.

Answer:

58.25

Step-by-step explanation:

Answer:

As the x-values go to positive infinity, the function’s values go to positive infinity.

Step-by-step explanation:

With the information given you can plot a rough graph (see attachment)

As the x-values go to positive infinity, the function’s values go to positive infinity. -> True

As the x-values go to zero, the function’s values go to positive infinity. -> False, x = 0 is between a maximum and a minimum

As the x-values go to negative infinity, the function’s values are equal to zero. -> False x-values go to negative infinity, the function's values go to positive infinite

As the x-values go to negative infinity, the function’s values go to negative infinity. False x-values go to negative infinity, the function's values go to positive infinite

Answer: As the x-values go to positive infinity, the function’s values go to positive infinity.

Step-by-step explanation:

just did this

Answer:

  Multiply the number of cans by the volume of each: 12,000 oz.

Step-by-step explanation:

You find the total volume of more than one can by adding the volumes of the cans involved.

For 2 cans, the volume would be ...

  12 oz + 12 oz = 24 oz

__

When you consider adding numbers more than a couple of times, you start looking for ways to simplify the effort. Multiplication was invented for that purpose. Here, multiplying the volume of 1 can by 1000 is the same as adding the volumes of 1000 cans.

For 1000 cans with volume of 12 oz each, the volume of the total is ...

  1000 × 12 oz = 12,000 oz.

To calculate the total area of two rectangular rooms, we multiply the length by the width of each room separately and then add the two results together. The formula used is Total Area = (width1 × length1) + (width2 × length2). This demonstrates a practical application of geometry in everyday situations.

The student's question is about calculating the total area of two rectangular rooms given their lengths and widths. To find the area of a rectangle, we multiply its length by its width. Therefore, to find the total area of both rooms, we calculate the area of each room separately and then add the two areas together. The formula for the total area of the two rooms would be:

Total Area = (width1 × length1) + (width2 × length2)

By inserting the specific values for width1, length1, width2, and length2 into this formula, we can calculate the exact total area covered by both rooms.

This approach utilizes basic principles of geometry to combine the areas of the two spaces, providing a clear example of how mathematical concepts are applied in practical situations like room measurements.

Answer:

Joseph is not correct

Each digit from the leftmost digit is ten times the digit before it  

Step-by-step explanation:

* Lets explain how to solve the problem

- Any number formed from some digits, each digit has a place value

- Ex: 2,345 this number formed from 4 digits

 The place value of 5 is ones ⇒ 5

 The place value of 4 is tens ⇒ 40

 The place value of 3 is hundreds ⇒ 300

 The place value of 2 is thousands ⇒ 2,000

 2,345 = 2,000 + 300 + 40 + 5

* Lets check our problem

∵ The number is 9,999,999

- The number formed from 7 digits, the digits have different places value

∴ They couldn't have the same value

∴ Joseph is not correct

∵ The number formed from 7 digits

- The place value of the leftmost digit is millions

- The place value of the digit before the million is hundred thousands

- The place value of the digit before the hundred thousands is

 ten thousands

- The place value of the digit ten thousands is thousands

- The place value of the digit before thousands is hundreds

- The place value of the digit before hundreds is tens

- The place value of the digit before tens is ones

∴ 9,999,999 = 9,000,000 + 900,000 + 90,000 + 9,000 + 900

   + 90 + 9

∴ Each digit from the leftmost digit is ten times the digit before it  

Alisa's conjecture is true because the numbers in set A differ by two magnitudes, making the comparison easier. Alisa could have compared the leading digits in the ten thousand place to determine that the numbers in set B are relatively close in magnitude.

In order to construct an argument justifying whether Alisa's conjecture is true, we can compare the magnitude of the numbers in each set. Looking at set A, we have 45,000 and 1,025,680. The first number has four digits, while the second number has six digits, indicating a difference of two magnitudes.

Now let's look at set B, which consists of 492,111 and 409,867. Both numbers in set B have six digits, so they are of the same magnitude.

Based on this analysis, we can conclude that Alisa's conjecture is true. It is indeed easier to compare the numbers in set A because their magnitudes differ by two, making the comparison more straightforward.

When comparing set B using the ten thousand place, Alisa could have used the strategy of looking at the leading digit in the ten thousand place. In this case, the leading digits are 4 and 4, indicating that the numbers in set B are relatively close in magnitude.

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