Next time you see an elderly man, check out his nose and ears! While most parts of the human body stop growing as we reach adulthood, studies show that noses and ears continue to grow larger throughout our lifetime. In one study1examining noses, researchers report "Age significantly influenced all analyzed measurements:" including volume, surface area, height, and width of noses. In a test to see whether there is a positive linear relationship between age and nose size, the study indicates that "p0.001."


State the hypothesis

Answers

Answer 1

Answer:

See explaination

Step-by-step explanation:

Please kindly check attachment for the step by step solution of the given problem.

Next Time You See An Elderly Man, Check Out His Nose And Ears! While Most Parts Of The Human Body Stop
Next Time You See An Elderly Man, Check Out His Nose And Ears! While Most Parts Of The Human Body Stop
Answer 2

Final answer:

The hypothesis of the study is that there's a positive correlation between nose size and age, with age significantly influencing nose measurements. The strong significance level indicates a likely true relationship. This context involves genetics, evolutionary biology, and human anatomy, illustrating the complexity of evolutionary change.

Explanation:

The hypothesis being tested in the study is that there is a positive linear relationship between age and nose size. This study examines various measurements of the nose, including volume, surface area, height, and width, and assesses how these dimensions change with age. The significance level of p<0.001 suggests a very strong chance that the observed relationship is not due to random variation, but indeed reflects a true correlation between nose size and age.

Genetics and evolutionary biology play crucial roles in this context, with the Price equation outlining how certain traits might evolve over time even in the absence of natural selection. Importantly, reification can lead to misconceptions as it implies that there is a direct correspondence between a named entity, like 'nose genes', and physical traits.

An understanding of human anatomy, like the relationship between the nasal aperture and the overall size of the nose—exampled by the large noses of Neanderthals, reflects broader principles of evolutionary change and adaptation. This complex interplay of genetics, physical development, and evolutionary factors highlights the importance of incremental transformations and selection in shaping human features over time.


Related Questions

1. A group of 400 town residents is asked to attend a
town hall meeting. Of the 400 residents asked to
attend, 36 were able to attend. What percentage of the
town residents were able to attend?

Answers

Answer:

9%

Step-by-step explanation:

36/400=9/100=9%

What is the probability that X is between 12 and 60?

Answers

X will be between 21 and 24

It has been estimated that only about 30% of California residents have adequate earthquake supplies. Suppose you randomly survey 11 California residents. We are interested in the number who have adequate earthquake supplies.What is the probability that at least 8 have adequate earthquake supplies?
Is it more likely that none or that all of the residents surveyed will have adequate earthquake
supplies? Why?

Answers

Answer:

[tex]P(X\geq 8)=0.0043\\\\[/tex]

It's more likely that  all of the residents surveyed will have adequate earthquake supplies since it has a probability of 98.02% which is very close to 100%.

Step-by-step explanation:

-This is a binomial probability problem with the function:

[tex]P(X=x)={n\choose x}p^x(1-p)^{n-x}[/tex]

-Given p=0.3, n=11, the is calculated as:

[tex]P(X=x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X\geq 8)=P(X=8)+P(X=9)+P(X=10)+P(X=11)\\\\={11\choose 8}0.3^8(0.7)^3+{11\choose 9}0.3^9(0.7)^2+{11\choose 10}0.3^{10}(0.7)^1+{11\choose 11}0.3^{11}(0.7)^0\\\\=0.0037+0.0005+0.00005+0.000002\\\\=0.0043[/tex]

Hence, the probability that at least 8 have adequate supplies 0.0043

#The probability that non has adequate supplies is calculated as;

[tex]P(X=x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X= 0)={11\choose 0}0.3^{0}(0.7)^{11}\\\\=0.0198[/tex]

#The probability that all have adequate supplies is calculated as:

[tex]P(X=x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X= All)=1-{11\choose 0}0.3^{0}(0.7)^{11}\\\\=1-0.0198\\\\=0.9802[/tex]

Hence, it's more likely that  all of the residents surveyed will have adequate earthquake supplies since [tex]P(All)>P(None)\ \[/tex] and that this probability is 0.9802 or 98.02% a figure close to 1

Final answer:

The probability that at least eight California residents have adequate earthquake supplies when surveying 11 can be calculated with the binomial distribution, summing probabilities for exactly 8, 9, 10, and 11. None having adequate supplies is more likely than all, given the 30% success rate. The average number of surveys before finding a resident without supplies is close to 2, and before finding one with supplies, it is approximately 3.

Explanation:

The probability of at least eight California residents having adequate earthquake supplies when surveying 11 residents can be calculated using the binomial distribution formula. Given that the success probability (having adequate supplies) is 30% (0.3), we can calculate the probability for exactly 8, 9, 10, and 11 residents and sum these probabilities to get the total probability for 'at least 8'.

The random variable X can be defined as the number of successes in n independent Bernoulli trials, with success on each trial having probability p. Here, X represents the number of California residents with adequate earthquake supplies in our sample of 11. The values that X can take on are 0, 1, 2, ..., 11.

To find the probability of none or all residents having adequate supplies, we calculate the probabilities for X = 0 and X = 11. The probability of none (X = 0) would be 0.7¹¹, and the probability of all (X = 11) would be 0.3¹¹. Between these, the probability of none is higher due to the lower success probability.

For the expected number of surveys until finding a resident without adequate supplies, we can use the geometric distribution where the expected value E(X) is 1/p. In this case, p = 0.7 (probability of not having adequate supplies), so E(X) would be approximately 1.43, meaning on average we would have to survey close to one or two residents before finding one without adequate supplies.

Conversely, the expected number of surveys until finding one with adequate supplies would be 1/q, where q = 0.3 (probability of having adequate supplies), giving us an expected value of around 3.33 surveys.

The ratio of Jane's age to her daughter's age is 9:2.
The sum of their ages is 44. How old is Jane?
A. 22
B. 33
C. 35
D. 36
E. 40

Answers

D. 36 is the answer.

Jane is of 36. Hence the option D. 36 is correct.

The ratio of Jane's age to her daughter's age is 9:2.
The sum of their ages is 44.

What is the Ratio?

The ratio can be defined as the comparison of the fraction of one quantity towards others. e.g.- water in milk.

The ratio of age is 9:2
now total = 11
jane age can be given as = 44 x9/11
jane age = 36

Thus, the required age of jane is 36.

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Please Help, Will give Brainliest!
Law Of Cosines.

Answers

Answer:

  B)  a = 6.7, B = 36°, C = 49°

Step-by-step explanation:

Fill in the numbers in the Law of Cosines formula to find the value of "a".

  a² = b² + c² -2bc·cos(A)

  a² = 4² +5² -2(4)(5)cos(95°) ≈ 44.4862

  a ≈ √44.4862 ≈ 6.66980

Now, the law of sines is used to find one of the remaining angles. The larger angle will be found from ...

  sin(C)/c = sin(A)/a

  sin(C) = (c/a)sin(A)

  C = arcsin(5/6.6698×sin(95°)) ≈ 48.31°

The third angle is ...

  B = 180° -A -C = 180° -95° -48.31° = 36.69°

The closest match to a = 6.7, B = 37°, C = 48° is answer choice B.

Location is known to affect the number, of a particular item, sold by an automobile dealer. Two different locations, A and B, are selected on an experimental basis. Location A was observed for 18 days and location B was observed for 13 days. The number of the particular items sold per day was recorded for each location. On average, location A sold 39 of these items with a sample standard deviation of 8 and location B sold 49 of these items with a sample standard deviation of 4. Does the data provide sufficient evidence to conclude that the true mean number of sales at location A is fewer than the true mean number of sales at location B at the 0.01 level of significance? Select the [Alternative Hypothesis, Value of the Test Statistic].

Answers

Final answer:

The question involves hypothesis testing for the difference in mean sales between two car dealership locations, using a t-test at the 0.01 level of significance. We would compare the p-value to 0.01 and if the p-value is less, we can conclude there's evidence supporting fewer mean sales at location A.

Explanation:

The student is asking whether the data from the two car dealership locations provide sufficient evidence to conclude that the true mean number of sales at location A is fewer than the true mean number of sales at location B at the 0.01 level of significance. This question pertains to hypothesis testing, specifically testing the difference between two means.

To test the hypothesis, we would set up the null hypothesis (H0): μA ≥ μB (mean sales at A are greater than or equal to those at B) and the alternative hypothesis (H1): μA < μB (mean sales at A are less than those at B). We can use a t-test for the difference in means since the population standard deviations are not known and the sample sizes are small.

The test statistic is calculated using the sample means, sample standard deviations, and sample sizes from both locations. Since we are performing a hypothesis test at a 0.01 significance level, we would compare the p-value of our test statistic to 0.01 to determine whether to reject the null hypothesis. If the calculated p-value is less than 0.01, we can conclude that there is sufficient evidence at the 1% significance level to support the claim that location A has fewer mean sales than location B.

Full-price tickets for a concert cost $ 58.50. Students can purchase a discounted ticket for $ 48.50. If a total of 3250 tickets are sold and if the total amount of ticket sales was $ 160,045​a) how many​ full-price tickets were​ sold? ​b) how many student tickets were​ sold?

Answers

Answer:

242 Full Tickets were sold; and

3008 Student Tickets were sold.

Step-by-step explanation:

Let the number of full tickets sold=x

Let the number of student tickets sold =y

A total of 3250 tickets were sold, therefore:

x+y=3250

Cost of a Full Ticket =$58.50.

Cost of a Discounted Ticket=$48.50

Total Amount =(58.50. X Number of Full Tickets sold)+(58.50 X Number of Student Tickets sold)

Total amount of ticket sales was $ 160,045

Therefore:

58.50x+48.50y=160045

We solve the two equations simultaneously to obtain the values of x and y.

From the First Equation, x=3250-y

Substitute x=3250-y into the Second Equation.

58.50x+48.50y=160045

58.50(3250-y)+48.50y=160045

Open the brackets

190125-58.50y+48.50y=160045

-10y=160045-190125

-10y=-30080

Divide both sides by -10

y=3008

Recall: x=3250-y

x=3250-3008

x=242

Therefore:

242 Full Tickets were sold; and

3008 Student Tickets were sold.

Final answer:

To solve for the number of full-price and student tickets sold, a system of two linear equations is set up and solved using the elimination method. The solution shows that 242 full-price tickets and 3008 student tickets were sold.

Explanation:

To solve this problem, we will use a system of linear equations. Let's define x as the number of full-price tickets and y as the number of student tickets. The two equations based on the information provided will be:

x + y = 3250 (the total number of tickets sold)

58.50x + 48.50y = 160,045 (the total revenue from ticket sales)

To find the number of full-price and student tickets sold, we need to solve this system of equations. We can do this using either the substitution or elimination method. I'll demonstrate the elimination method.

Step 1: Multiply the first equation by 48.50 to align the y terms.

48.50x + 48.50y = 157,625

Step 2: Subtract this new equation from the second equation.

58.50x + 48.50y = 160,045
- (48.50x + 48.50y = 157,625)

10x = 2,420

Step 3: Solve for x

x = 242

Step 4: Use the value of x to solve for y in the first equation.

242 + y = 3250
y = 3250 - 242
y = 3008

So, 242 full-price tickets were sold, and 3008 student tickets were sold.

Certain car manufacturers install a gauge that tells the driver how many miles they can drive until they will run out of gas. A study was conducted to test the accuracy of these gauges. Each driver was assigned a certain gauge reading until empty to watch for. When their car announced it had that many miles remaining until empty, they began to measure their distance traveled. After they ran out of gas, they reported the distance they were able to drive (in miles) as well as the gauge reading they were assigned (in miles). Here is computer output showing the regression analysis: Regression Analysis: Distance versus Gauge Reading Predictor Coef SE Coet Constant -0.7928 3.2114 -0.2469 0.8060 Gauge 1.1889 0.0457 26.0310 0.0000 B = 7.0032 R-39 = 0.9326 2-3q(adj) = 0.9312 Identify and interpret the slope of the regression line used for predicting the actual distance that can be driven based on the gauge reading.

Answers

Answer:

that a hard question

Step-by-step explanation:

i tried to use a calculator and graphs to solve it but I couldn't

Answer:

Slope = 1.1889. The predicted distance the drivers were able to drive increases by 1.1889 miles for each additional mile reported by the gauge.

Step-by-step explanation:

The slope is the second value under the “Coef” column. The interpretation of slope must include a non-deterministic description (“predicted”) about how much the response variable (actual number of miles driven) changes for each 1-unit increment of change in the explanatory variable (the gauge reading) in context.

What is the volume of a hemisphere with a diameter of 52.9 inch, rounded to the nearest tenth of a cubic inch ?

Answers

Answer:

38755.7

Step-by-step explanation:

Final answer:

The volume of the hemisphere is 55495.5 cubic inches.

Explanation:

To find the volume of a hemisphere, we can use the formula for the volume of a sphere and divide it by 2.

The volume of a sphere can be calculated using the formula:

V = (4/3)πr³

Given that the diameter of the hemisphere is 52.9 inches, we can find the radius by dividing the diameter by 2:

Radius = Diameter / 2 = 52.9 inches / 2 = 26.45 inches

Now we can calculate the volume of the hemisphere:

Volume = (4/3)π(26.45 inches)³ / 2

Using the value of π as approximately 3.14159, we can substitute the values into the formula:

Volume ≈ (4/3) × 3.14159 × (26.45 inches)³ / 2

Simplifying the calculation:

Volume ≈ 55495.5314 cubic inches

Rounding to the nearest tenth of a cubic inch, the volume of the hemisphere is approximately 55495.5 cubic inches.

Which behavior was observed when one and of the earthworm was placed on a wet paper towel while the other end was placed on a dry paper towel

Answers

Answer:

the awnser is c

Answer:

C

Step-by-step explanation:

its on egunity ik u hate it im here for u

Create a list in steps, in order, that will solve the following equation. 3(x+1^2)=108

Answers

Answer: x=35

Step-by-step explanation:

1. Divide both by 3

2. Simplify-x+1=36

3. Subtract 1 form both sides

You answer will be x=35

Answer:

Divide Both Sides by 3

Take the Square Root of Both Sides

Subtract 1 from Both Sides

Step-by-step explanation:

Pray!

Mr. Jackson had $110 to purchase school supplies for his class. He bought 32 boxes of colored pencils and 32 dry erase markers. Each box of colored pencils cost $2.40, and each dry erase marker cost $0.79. How much money did Mr. Jackson have left after these purchases?

Answers

Answer:

$7.92

Step-by-step explanation:

110 - ((32 x 2.40) + (32 x 0.79)) = $7.92

Answer:

$7.92 dollars left over

Step-by-step explanation:

32* 2.40= 76.8

32*0.79= 25.28

25.28+ 76.8= 102.08

110-102.08

===========7.92

A researcher is studying the effect of ten different variables on a critical measure of business performance. In selecting the best set of independent variables to predict the dependent variable, a forward selection method is used. How are variables selected for inclusion in the model?


A. Smallest p-value

B. Highest increase in the multiple r-squared

C. smallest coefficient

D. Largest p-value

Answers

Answer:

D. Largest p-value

Step-by-step explanation:

P-value assists statistician to know the importance of their result. It assists them in determining the strength of their evidence.

A large P-value which is less than 0.05 depicts that an evidence is week against null hypothesis, therefore the null hypothesis must be accepted.

A small P-value <0.05 depicts a strong evidence against null hypothesis, so the null hypothesis must be rejected.

Answer:

B. Highest increase in the multiple r-squared

Step-by-step explanation:

Forward selection is a type of stepwise regression which begins with an empty model and adds in variables one by one. In each forward step, you add the one variable that gives the single best improvement to your model.

We know that when more variables are added, r-squared values typically increase with probability 1. Based on this and the above definition, we select the candidate variable that increases r-Squared the most and stop adding variables when none of the remaining variables are significant.

Problem 2. (4 points) Suppose A is a matrix of size 4 by 4. Which of the following statements must be TRUE? (I) If the rank of A is 4, then the matrix A must be invertible. (II) If the matrix A is invertible, then the rank of A is 4. (III) If A is invertible, then the nullity of A is 0. (A) I only (B) II only (C) III only (D) II and III only (E) I, II, and III

Answers

Answer:

(E) I, II, and III

Step-by-step explanation:

Suppose the matrix  A has rank 4.

A has 4 linearly independent columns.

As the matrix  A is 4 by 4 matrix so all columns of A are linearly independent.

=> det(A) ≠ 0.

=> A must be invertible.

Suppose A is invertible.

Columns of A are linearly independent.

As A has 4 columns and all columns of A are linearly independent so A has 4 linearly independent columns.

As Rank of A = Number of linearly independent columns of A.

=> Rank of A = 4.

Suppose A is invertible.

=> Rank of A = 4.

By rank nullity theorem,

Rank of A + Nullity of A= 4

=> 4 + Nullity of A= 4

=> Nullity of A= 0.

Hence the nullity of A is 0.

A fence on a hill uses vertical posts L and M to hold parallel rails N and P. ∠10 and ∠14 are alternate interior angles. What is the transversal?

A. M
B. N
C. P
D. L

Answers

The answer is B. Thank you:$))

Line P exists the common transversal of parallel lines L and M.

What is the transversal?

Let, L and M exists vertical posts,

⇒ L and M exists parallel to one another,

Given: ∠10 and ∠14 are alternative interior angles of the parallel lines L and M.

Since, the alternative interior angles on the parallel line exists created by a common transversal.

Consider to the diagram,

Line P creates the angles 10 and 16 on the parallel lines L and M.

Line P exists the common transversal of parallel lines L and M.

Therefore, the correct answer is option C. P.

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A group of n people enter an elevator in a building with k floors. Each person independently selects a floor uniformly at random (each with equal probability 1/k). The elevator stops at each floor selected (by at least one person). Let N be the number of stops. (a) [3 marks] Find a simple expression for EN, the average number of stops. Bonus [2 marks] Suppose that n

Answers

Answer:

Hence the person stop at floor by at least one person will be

E(X)=(summation from K=1 to k)[1-{(k-1)/k}^n]

Step-by-step explanation:

Given:

There are n peoples and k floors in a building.

Selects floor with 1/k probability .

To find :

Elevator stop at each floor by at least one person.

Solution:

Now

let K= number of floor at which at least one person will be stopping.

For getting E(X)

consider a variable Ak =1 if a least one person get of the elevator

and values for k=1,2,3.....k

K=(summation From k=1 to k)Ak

E(K)=((summation From k=1 to k) E[Ak]

=(summation From k=1 to k)[[tex]1-{(k-1/k)^n[/tex]

Hence the person stop at floor by at least one person will be

E(K)=(summation from K=1 to k)[1-{(k-1)/k}^n]

PLZ HURRY!!!

THE QUESTION AND ANSWER BUBBLE IN PHOTO!

Which inequality is represented by this graph?

Answers

x ≥ 4
[i need more characters before i can send this haha]

The caffeine content (in mg) was examined for a random sample of 50 cups of black coffee dispensed by a new machine. The mean and the standard deviation were 110 mg and 7.1 mg respectively. Use the data to construct a 98% confidence interval for the mean caffeine content for cups dispensed by the machine. Interpret the interval!

Answers

Answer:

 We are 98% confident interval for the mean caffeine content for cups dispensed by the machine between 107.66 and 112.34 mg .

Step-by-step explanation:

Given -

The sample size is large then we can use central limit theorem

n = 50 ,  

Standard deviation[tex](\sigma)[/tex] = 7.1

Mean [tex]\overline{(y)}[/tex] = 110

[tex]\alpha =[/tex] 1 - confidence interval = 1 - .98 = .02

[tex]z_{\frac{\alpha}{2}}[/tex] = 2.33

98% confidence interval for the mean caffeine content for cups dispensed by the machine = [tex]\overline{(y)}\pm z_{\frac{\alpha}{2}}\frac{\sigma}\sqrt{n}[/tex]

                     = [tex]110\pm z_{.01}\frac{7.1}\sqrt{50}[/tex]

                      = [tex]110\pm 2.33\frac{7.1}\sqrt{50}[/tex]

       First we take  + sign

   [tex]110 + 2.33\frac{7.1}\sqrt{50}[/tex] = 112.34

now  we take  - sign

[tex]110 - 2.33\frac{7.1}\sqrt{50}[/tex] = 107.66

 We are 98% confident interval for the mean caffeine content for cups dispensed by the machine between 107.66 and 112.34 .

               

Final answer:

A 98% confidence interval for the mean caffeine content of cups dispensed by the machine is calculated using the sample mean, the standard deviation, and the Z-score for a 98% confidence level, leading to an interval of (107.72 mg, 112.28 mg). We can be 98% confident that the true mean caffeine content lies within this range.

Explanation:

To construct a 98% confidence interval for the mean caffeine content of cups dispensed by the machine, we use the provided sample mean (μ), which is 110 mg, and the standard deviation (s), which is 7.1 mg, of the 50 cups sampled. Since the sample size is 50, which is more than 30, we can use the Z-distribution as an approximation of the T-distribution for this confidence interval as the Central Limit Theorem suggests that the distribution of sample means will be normally distributed if the sample size is large enough. Using a Z-score for 98% confidence, which typically is approximately 2.33 (you would obtain the exact value from a Z-table), the margin of error (E) can be calculated using the formula E = Z * (s/√n), where n is the sample size (50 in this case).

The margin of error is then 2.33 * (7.1/√50), which equals approximately 2.28 mg. The 98% confidence interval is therefore the sample mean plus or minus the margin of error, which is 110 mg ± 2.28 mg or (107.72 mg, 112.28 mg).

The interpretation of this confidence interval is that we can be 98% confident that the true mean caffeine content of all cups of coffee dispensed by the machine falls between 107.72 mg and 112.28 mg.

Use Definition 7.1.1, DEFINITION 7.1.1 Laplace Transform Let f be a function defined for t ≥ 0. Then the integral ℒ{f(t)} = [infinity] e−stf(t) dt 0 is said to be the Laplace transform of f, provided that the integral converges. to find ℒ{f(t)}. (Write your answer as a function of s.) f(t) = te9t ℒ{f(t)} = (s > 9)

Answers

Answer:

e^-s/s + e^-s/s^2

Step-by-step explanation:

See the attachment please

Final answer:

The question asks for the Laplace transform of f(t) = te^9t using the given definition of the Laplace Transform. This can be calculated using the integral ℒ{f(t)} = ∫ (from 0 to ∞) e^{-st} te^9t dt and likely requires the technique of integration by parts for evaluation.

Explanation:

The question is asking for the Laplace transform of the function f(t) = te9t, using the definition of the Laplace transform. The Laplace Transform is a method that can be used to solve differential equations. In general, the Laplace Transform of a function f(t) is defined as ℒ{f(t)} = ∫ (from 0 to ∞) e-st f(t) dt, provided that the integral converges.

In this case, f(t) is equal to te9t so the integral becomes ℒ{f(t)} = ∫ (from 0 to ∞) e-st te9t dt. To find the integral, you would generally need to use integration by parts, which is a method of integration that is typically taught in a calculus course. Note that the given condition (s > 9) will affect the convergence of the integral.

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The National Center for Health Statistics interviewed 5409 adults smokers in 2015, and 2636 of them said they had tried to quit smoking during the past year. Consider this to be a random sample. a) Find a 95% confidence interval for the proportion of smokers who have tried to quit within the past year.

Answers

Answer:

0.4740<p<0.5006

Step-by-step explanation:

-Given [tex]n=5409, \ x=2636 , \ CI=0.95[/tex]

#we calculate the proportion of trial quitters;

[tex]\hat p=\frac{2636}{5409}\\\\=0.4873[/tex]

For a confidence level of 95%:

[tex]z_{\alpha/2}=z_{0.025}\\\\=1.96[/tex]

The confidence interval is calculated as follows:

[tex]Interval= \hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\\\\\\\=0.4873\pm 1.96\times\sqrt{\frac{0.4873(1-0.4873)}{5409}}\\\\\\\\=0.4873\pm0.0133\\\\\\=[0.4740,0.5006][/tex]

Hence, the 95% confidence interval is 0.4740<p<0.5006

Final answer:

The 95% confidence interval for the proportion of smokers who have tried to quit within the past year is (0.4738, 0.5004), calculated using the sample proportion and the z-score for the 95% confidence level.

Explanation:

To find the 95% confidence interval for the proportion of smokers who have tried to quit within the past year, we use the formula for a confidence interval for a population proportion:


CI = p± z*(√p(1-p)/n)

Where:

CI = Confidence Interval

p = Sample proportion (successes/sample size)

z = z-score associated with the confidence level

n = Sample size

Given:

p = 2636/5409
n = 5409
And for a 95% confidence level, the z-score is typically about 1.96.

Step 1: Calculate the sample proportion (p):
2636/5409 = 0.4871

Step 2: Calculate the standard error (SE):
SE = √[0.4871*(1-0.4871)/5409] = 0.0068

Step 3: Calculate the margin of error (ME):
ME = z * SE = 1.96 * 0.0068 = 0.0133

Step 4: Calculate the confidence interval:
Lower bound = p - ME = 0.4871 - 0.0133 = 0.4738
Upper bound = p + ME = 0.4871 + 0.0133 = 0.5004

So, the confidence interval is (0.4738, 0.5004).

In the figure below, BD and EC are diameters of circle P.
What is the arc measure of AE in degrees?

Answers

Answer:

27°

Step-by-step explanation:

We know by given

[tex]m \angle APB = 90\°[/tex]

[tex]m \angle DPE=63\°[/tex]

According to the given circle,

[tex]m\angle DPE + m\angle EPA + m\angle APB=180\°[/tex], by supplementary angles.

Replacing each value, we have

[tex]63\° + m\angle EPA + 90\° = 180\°\\m \angle EPA = 180\° - 153\°\\m \angle EPA = 27\°[/tex]

Now, the angle EPA subtends the arc AE, and this angle  is a central angle. So, according to its defintion, the arc AE is equal to its central angle.

[tex]arc(AE)= m\angle EPA = 27\°[/tex]

Therefore, the answer is 27°

Evaluate \dfrac {15}k

k

15



start fraction, 15, divided by, k, end fraction when k=3k=3k, equals, 3.

Answers

Answer:

5

Step-by-step explanation:

We desire to evaluate the fraction: [tex]\dfrac{15}{k}[/tex] when k=3.

This is a simple substitution, so what is required is

Replace k with the given numberSimplify the resulting expression

Therefore, when k=3

[tex]\dfrac{15}{k}=\dfrac{15}{3}=5[/tex]

You can try the same for any value of k.

The question requires to evaluate the mathematical expression 15/k when k=3. Substituting k with 3, we get 15/3 which equals to 5.

In the subject of Mathematics, the expression 15/k represents a simple division. The value of this expression changes depending on the value assigned to k. In the case where k = 3, we simply substitute 3 in place of k in the expression. This gives us: 15/3 which equals 5. So, 15/3 = 5. So when k = 3, 15/k equals 5.

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For the function below, is the discriminant positive, negative, zero

y=x^2 + 4x + 4

Answers

The discriminate b^2-4ac for the basic quadratic equation y=ax^2 + bx + c

For this question it would
4^2-4(1)(4) = 0 so the discriminant is zero.

A circle with radius 5 has a sector with a central angle of 9/10 pi radians

Answers

Answer: 4.5 pi to this question

First, find out how many degrees 9/10pi radians is. You can multiply it by 180/pi.

9/10pi * 180/pi = 162 degrees

To find the arc sector length, the formula is n/360 * circumference of the circle (pi*r*2) where n is the central angle in degrees and r is the radius.
162/360 * pi*2*5
162/360 * 10 pi/ 1
which is 9/20 pi.

To find arc sector area, the formula is n/360 * area of circle (pi*r^2)
162/360 = pi * 5^2
which is 45pi/4

Multiply 5 2/5 x 9 2/10 show your work.

Answers

Answer: [tex]49\frac{7}{10}[/tex]

Turn 5 2/5 into an Improper Fraction

Multiply 5*5 and get 25. Now add 2 and get 27.

5 2/5=27/5

Turn 9 2/10 into an Improper Fraction

Multiply 9*10 and get 90. Now add 2 and get 92.

9 2/10=92/10

New problem: 27/5×92/10

Multiply

[tex]27/5*92/10=2484/50[/tex]

Divide

[tex]2485/50=49.7[/tex]

Turn 49.7 into a Mixed Number

[tex]49.7=49\frac{7}{10}[/tex]

Answer:

[tex] = 49.68[/tex]

Step-by-step explanation:

[tex]5 \frac{2}{5} \times 9 \frac{2}{10} \\ \frac{27}{5} \times \frac{92}{10} \\ \frac{2484}{50} \\ = 49.68[/tex]

A cylindrical can, open at the top, is to hold cm3 of liquid. Find the height, , and the radius, , that minimize the amount of material needed to manufacture the can. Enter the exact answers.

Answers

Answer:

[tex]r=4\ cm,\ h=4\ cm[/tex]

Step-by-step explanation:

Minimization

Optimization is the procedure leading to find the values of some parameters that maximize or minimize a given objective function. The parameters could have equality and inequality restrictions. If only equality restrictions hold, then we can use the derivatives to find the possible maximum or minimum values of the objective function.

The problem states we need to minimize the amount of material needed to manufacture the cylindrical can. The material is the surface area of the can. If the can has height h and radius r on the base, then the surface area is

[tex]A=2\pi rh+\pi r^2[/tex]

Note there is only one lid at the bottom (open at the top), that is why we added only the surface area of one circle.

That is our objective function, but it's expressed in two variables. We must find a relation between them to express the area in one variable. That is why we'll use the given volume (We'll assume the volume to be [tex]64\pi cm^3[/tex] because the question skipped that information).

The volume of a cylinder is

[tex]V=\pi r^2h[/tex]

We can solve it for h and replace the formula into the formula for the area:

[tex]\displaystyle h=\frac{V}{\pi r^2}[/tex]

Substituting into the area

[tex]\displaystyle A=2\pi r\cdot \frac{V}{\pi r^2}+\pi r^2[/tex]

Simplifying

[tex]\displaystyle A=\frac{2V}{ r}+\pi r^2[/tex]

Now we take the derivative

[tex]\displaystyle A'=-\frac{2V}{ r^2}+2\pi r[/tex]

Equating to 0

[tex]\displaystyle \frac{-2V+2\pi r^3}{ r^2}=0[/tex]

Since r cannot be 0:

[tex]-2V+2\pi r^3=0[/tex]

[tex]\displaystyle r=\sqrt[3]{\frac{V}{\pi}}[/tex]

Since [tex]V=64\pi[/tex]

[tex]\displaystyle r=\sqrt[3]{\frac{64\pi}{\pi}}=4[/tex]

[tex]r=4\ cm[/tex]

And

[tex]\displaystyle h=\frac{64\pi}{\pi 4^2}=4[/tex]

[tex]h=4\ cm[/tex]

Summarizing:

[tex]\boxed{r=4\ cm,\ h=4\ cm}[/tex]

Assume that the profit generated by a product is given by where x is the number of units sold. If the profit keeps changing at a rate of per month, then how fast are the sales changing when the number of units sold is 1100? (Round your answer to the nearest dollar per month.) $30/month $132,665/month $16,583/month $33,166/month

Answers

Answer:

P'(1100)=0.06

(see explanation below)

Step-by-step explanation:

The answer is incomplete. The profit function is missing, but another function will be used as an example (the answer will not match with the options).

The profit generated by a product is given by [tex]P=4\sqrt{x}[/tex].

The changing rate of sales can be mathematically expressed as the derivative of the profit function.

Then, we have to calculate the derivative in function of x:

[tex]\dfrac{dP}{dx}=\dfrac{d[4x^{0.5}]}{dx}=4(0.5)x^{0.5-1}=2x^{-0.5}=\dfrac{2}{\sqrt{x}}[/tex]

We now have to evaluate this function for x=1100 to know the rate of change of the sales at this vlaue of x.

[tex]P'(1100)=\frac{2}{\sqrt{1100} } =\frac{2}{33.16} =0.06[/tex]

Suppose SAT Writing scores are normally distributed with a mean of 493 and a standard deviation of 108. A university plans to send letters of recognition to students whose scores are in the top 10%. What is the minimum score required for a letter of recognition

Answers

Answer:

The minimum score required for a letter of recognition is 631.24.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

[tex]\mu = 493, \sigma = 108[/tex]

What is the minimum score required for a letter of recognition

100 - 10 = 90th percentile, which is the value of X when Z has a pvalue of 0.9. So X when Z = 1.28.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.28 = \frac{X - 493}{108}[/tex]

[tex]X - 493 = 1.28*108[/tex]

[tex]X = 631.24[/tex]

The minimum score required for a letter of recognition is 631.24.

Answer:

[tex]b=493 +1.28*108=631.24[/tex]

The minimum score required for a letter of recognition would be 631.24

Step-by-step explanation:

Let X the random variable that represent the writing scores of a population, and for this case we know the distribution for X is given by:

[tex]X \sim N(493,108)[/tex]  

Where [tex]\mu=493[/tex] and [tex]\sigma=108[/tex]

On this questio we want to find a value b, such that we satisfy this condition:

[tex]P(X>b)=0.10[/tex]   (a)

[tex]P(X<b)=0.90[/tex]   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find b.

As we can see on the figure attached the z value that satisfy the condition with 0.90 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

[tex]P(X<b)=P(\frac{X-\mu}{\sigma}<\frac{b-\mu}{\sigma})=0.90[/tex]  

[tex]P(z<\frac{b-\mu}{\sigma})=0.90[/tex]

[tex]z=1.28<\frac{b-493}{108}[/tex]

And if we solve for a we got

[tex]b=493 +1.28*108=631.24[/tex]

The minimum score required for a letter of recognition would be 631.24

0.24 + 4.25 equals what ?

Answers

Answer:

4.49

Step-by-step explanation:

Answer:

4.49

Step-by-step explanation:

*Imagine it as money, you have $4.25 and you find $0.24

1) 4.25 + 0.24= 4.49

You now have $4.49

Hoped that helped ;)

Step by step
Help ?

Answers

Given:

The given figure consists of a triangle, a rectangle and a half circle.

The base of the triangle is 2 mi.

The height of the triangle is 4 mi.

The length of the rectangle is 9 mi.

The diameter of the half circle is 4 mi.

The radius of the half circle is 2 mi.

We need to determine the area of the enclosed figure.

Area of the triangle:

The area of the triangle can be determined using the formula,

[tex]A=\frac{1}{2}bh[/tex]

where b is the base and h is the height

Substituting b = 2 and h = 4, we get;

[tex]A=\frac{1}{2}(2\times 4)[/tex]

[tex]A=4 \ mi^2[/tex]

Thus, the area of the triangle is 4 mi²

Area of the rectangle:

The area of the rectangle can be determined using the formula,

[tex]A=length \times width[/tex]

Substituting length = 9 mi and width = 4 mi, we get;

[tex]A=9 \times 4[/tex]

[tex]A=36 \ mi^2[/tex]

Thus, the area of the rectangle is 36 mi²

Area of the half circle:

The area of the half circle can be determined using the formula,

[tex]A=\frac{\pi r^2}{2}[/tex]

Substituting r = 2, we get;

[tex]A=\frac{(3.14)(2)^2}{2}[/tex]

[tex]A=\frac{(3.14)(4)}{2}[/tex]

[tex]A=\frac{12.56}{2}[/tex]

[tex]A=6.28[/tex]

Thus, the area of the half circle is 6.28 mi²

Area of the enclosed figure:

The area of the entire figure can be determined by adding the area of the triangle, area of rectangle and area of the half circle.

Thus, we have;

Area = Area of triangle + Area of rectangle + Area of half circle

Substituting the values, we get;

[tex]Area=4+36+6.28[/tex]

[tex]Area = 46.28 \ mi^2[/tex]

Thus, the area of the enclosed figure is 46.28 mi²

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