uh......huh?? I will look this thingie up for you, I have no clue, but I will. Have a PHENOMANAL night!
Answer:
ninety-nine quinsexagintillion nine hundred ninety-nine quattuorsexagintillion nine hundred ninety-nine tresexagintillion nine hundred ninety-nine duosexagintillion nine hundred ninety-nine unsexagintillion nine hundred ninety-nine sexagintillion nine hundred ninety-nine novemquinquagintillion nine hundred ninety-nine octoquinquagintillion nine hundred ninety-nine septenquinquagintillion nine hundred ninety-nine sexquinquagintillion nine hundred ninety-nine quinquinquagintillion nine hundred ninety-nine quattuorquinquagintillion nine hundred ninety-nine trequinquagintillion nine hundred ninety-nine duoquinquagintillion nine hundred ninety-nine unquinquagintillion nine hundred ninety-nine quinquagintillion nine hundred ninety-nine novemquadragintillion nine hundred ninety-nine octoquadragintillion nine hundred ninety-nine septenquadragintillion nine hundred ninety-nine sexquadragintillion nine hundred ninety-nine quinquadragintillion nine hundred ninety-nine quattuorquadragintillion nine hundred ninety-nine trequadragintillion nine hundred ninety-nine duoquadragintillion nine hundred ninety-nine unquadragintillion nine hundred ninety-nine quadragintillion nine hundred ninety-nine novemtrigintillion nine hundred ninety-nine octotrigintillion nine hundred ninety-nine septentrigintillion nine hundred ninety-nine sextrigintillion nine hundred ninety-nine quintrigintillion nine hundred ninety-nine quattuortrigintillion nine hundred ninety-nine trestrigintillion nine hundred ninety-nine duotrigintillion nine hundred ninety-nine untrigintillion nine hundred ninety-nine trigintillion nine hundred ninety-nine novemvigintillion nine hundred ninety-nine octovigintillion nine hundred ninety-nine septenvigintillion nine hundred ninety-nine sexvigintillion nine hundred ninety-nine quinvigintillion nine hundred ninety-nine quattuorvigintillion nine hundred ninety-nine trevigintillion nine hundred ninety-nine duovigintillion nine hundred ninety-nine unvigintillion nine hundred ninety-nine vigintillion nine hundred ninety-nine novemdecillion nine hundred ninety-nine octodecillion nine hundred ninety-nine septendecillion nine hundred ninety-nine sexdecillion nine hundred ninety-nine quindecillion nine hundred ninety-nine quattuordecillion nine hundred ninety-nine tredecillion nine hundred ninety-nine duodecillion nine hundred ninety-nine undecillion nine hundred ninety-nine decillion nine hundred ninety-nine nonillion nine hundred ninety-nine octillion nine hundred ninety-nine septillion nine hundred ninety-nine sextillion nine hundred ninety-nine quintillion nine hundred ninety-nine quadrillion nine hundred ninety-nine trillion nine hundred ninety-nine billion nine hundred ninety-nine million nine hundred ninety-nine thousand nine hundred ninety-nine
Train a And train b leave Central Station at the same time they travel the same speed but in opposite direction with a train a heading towards Station a and train b heading towards station b train a Reaches station after 2 1/2 hours train b reaching station be after four hours you station A and b Station are 585 miles apart what is the rate of the trains
Answer:
Both trains are traveling at 90 miles per hour.
Step-by-step explanation:
We are told that the rate is the same for both trains, and we know that the distance traveled by train a plus the distance traveled by train b equals 585 miles.
We will use [tex]Distance=Rate* Time[/tex] formula to solve this problem.
Train A: [tex]D_a=R*2.5[/tex] (Using 2.5 instead of 2 and 1/2)
Train B: [tex]D_b=R*4[/tex]
We can set an equation to solve for rate R of trains as:
[tex]D_a+D_b=585[/tex]
[tex]2.5R+4R=585[/tex]
[tex]6.5 R=585[/tex]
[tex]R=\frac{585}{6.5}[/tex]
[tex]R=90[/tex]
Therefore, rate of both train a and train b is 90 miles per hour.
The total distance between the two stations is
[tex]585 miles[/tex]
Let the distance between the Central Station and station b be x
This implies that the distance between the Central Station and station a is
[tex](585 - x) \: miles[/tex]
[tex]speed=\frac{distance}{time}[/tex]
so, let us write equations in terms of speed for the two trains and solve
For train a,
[tex]speed=\frac{585 - x}{4 } ....eqn \: 1[/tex]
For train b,
[tex]speed=\frac{x}{2 \frac{1}{2} } .....eqn \: 2[/tex]
We were told that both trains traveled with the same speed
This means that eqn 1 = eqn 2
[tex]\frac{585 - x}{4 }=\frac{x}{2.5} [/tex]
Cross multiplying
[tex]2.5(585 - x)=4(x) [/tex]
Expanding the brackets
[tex]1462.5 - 2.5x =4x[/tex]
Grouping like terms
[tex]1462.5= 4x + 2.5x[/tex]
[tex]6.5x = 1462.5 \\ x = \frac{1462.5}{6.5 } =225 \: miles[/tex]
The speed at which the trains were travelling is
[tex] \frac{225}{2.5}= 90 \: miles /hour[/tex]
Hence the rate of the trains is
[tex]=90\: miles /hour[/tex]
is 106.06 bigger than 106.60? I really hate math and i got normal schoolwork to do as well
106.60 is bigger round up on it and you get 107
Which equation has the following characteristics?
#1.-7/9 x 3/5 a.-27/45 b.-7/15c.7/15 d.27/45
Answer: B
Step-by-step explanation:
[tex]\frac{-7}{9} * \frac{3}{5} = \frac{-7(3)}{9(5)} = \frac{-7(3)}{3 * 3(5)} = \frac{-7}{3(5)} = \frac{-7}{15}[/tex]
Mrhopkins was making groups for the school field trip
HELP ASAP PLEASE!!!
How many seconds are there in 782 minutes?
Use the factor: 1 min= 60 sec
A. 782 sec
B. 13 sec
C. 46,920 sec
D. 0.077 sec
C. 46,920 seconds is your answer
Answer:
Step-by-step explanation:
C. 46,920 sec
What value of k makes the equation true?
k – 26.7 = 12.8
A.
13.9
B.
38.5
C.
39.5
D.
39.9
All you have to do is just add 26.7 with 12.8, with the result being 39.5
A school year has 4 quarters. What percent of a school year is 7 quaters
Final answer:
7 quarters represent 175 percent of a school year since 7 divided by 4, then multiplied by 100 equals 175%. This means 7 quarters is more than the duration of one standard school year.
Explanation:
To calculate what percent of a school year 7 quarters represent, we need to compare 7 quarters to the total number of quarters in a standard school year. Since we know that a school year consists of 4 quarters, we can set up a proportion to determine the percentage.
Step 1: Identify the total number of quarters in a school year, which is 4.
Step 2: Identify the number of quarters we're focusing on, which is 7.
Step 3: Set up a fraction to represent the portion, which is 7 divided by 4 (7/4).
Step 4: Convert this fraction to a percentage by multiplying by 100. So, (7/4) × 100 = 175%.
Therefore, 7 quarters represent 175 percent of a school year, which implies more than one full school year.
solve
(b-2ya^2)(3b-3ya^2)
Here we are given the expression:
[tex](b-2ya^{2})(3b-3ya^{2})[/tex]
We will use foil method to solve this expression.
The word FOIL is an acronym for the four terms of the product:
First ("first" terms of each binomial are multiplied together)
Outer ("outside" terms are multiplied—that is, the first term of the first binomial and the second term of the second)
Inner ("inside" terms are multiplied—second term of the first binomial and first term of the second)
Last ("last" terms of each binomial are multiplied)
Using this method let us simplify our expression.
[tex](b-2ya^{2})(3b-3ya^{2})[/tex]
=[tex]3b^{2}-3bya^{2}-6bya^{2}+6y^{2}a^{4}[/tex]
Now combining like terms we have:
=[tex]3b^{2}-9bya^{2}+6y^{2}a^{4}[/tex]
Answer: [tex](b-2ya^{2})(3b-3ya^{2})[/tex] simplifies to [tex]3b^{2}-9bya^{2}+6y^{2}a^{4}[/tex]
Answer:
The answer is 3b² - 9bya² - 6y²a².
Explanation:
(b - 2ya²)(3b-3ya²)
3b² - 3bya²-6bya²-6ya²
3b² - 9bya² - 6y²a².
Answer would be 3b² - 9bya² - 6y²a².
math help what is x? please keep
Apples = X
Pears = Y
3x+2y = 0.60
pears cost 2X-0.05 replace Y with this:
3X +2(2x-0.05) = 0.60
Simplify:
3X + 4X-0.10 = 0.60
Simplify:
7X -0.10 = 0.60
Add 0.70 to each side:
7X = 0.70
Divide both sides by 7:
X = 0.70 / 7
X = 0.10
Apples cost 0.10 each.
Pears cost 2x-0.05 = 2(0.10) - 0.05 = 0.20 - 0.05 = 0.15 each
A yogurt costs 45p hair many can be bought with £5
11
5 pound = 500 pence
500 pence/ 45 pence= 11.1111111
The 1906 earthquake in San Francisco had a magnitude of 8.3 on the richter scale. At the same time in Japan an earthquake with magnitude of 4.9 caused minor damage. How many times more was the San Francisco earthquake that the Japan earthquake?
In 1906 in San Francisco the magnitude of earthquake on richter scale was 8.3.
In the same year the magnitude of earthquake on richter scale in Japan was 4.9.
Now we have to find how many times more was the San Francisco earthquake that the Japan earthquake.
The amount of energy released in an earthquake is very large, so a logarithmic scale avoids the use of large numbers.
The formula used for these calculations is:
[tex]M=log_{10}(\frac{I}{I_{0}})[/tex]
Where M is the magnitude on the richter scale, I is the intensity of the earthquake being measured and I₀ is the intensity of a reference earthquake.
So because the magnitude is a base 10 log, the Richter number is actually the exponent that 10 is raised to in order to calculate the intensity of the earthquake.
So the difference in magnitudes of the earthquakes can be calculated as follows:
[tex]M=log_{10}(\frac{10^{8.3}}{10^{4.9})}[/tex]
M=3.4
Answer: The San Francisco earthquake was 3.4 times more than Japan earthquake.
Final answer:
The San Francisco earthquake released approximately 2510 times more energy than the earthquake in Japan, calculated using the Richter scale.
Explanation:
To determine how many times stronger the San Francisco earthquake was compared to the earthquake in Japan, we refer to the Richter scale, which is a logarithmic scale. A one-unit increase on this scale represents a ten-fold increase in amplitude of the seismic waves and roughly a thirty-fold increase in energy released. Therefore, to calculate the difference between a magnitude 8.3 earthquake and a magnitude 4.9 earthquake, we subtract the smaller magnitude from the larger one (8.3 - 4.9 = 3.4) and then calculate 10 raised to the power of this difference.
[tex]10^(3.4)[/tex] = 10 x 10 x 10 x 2.51 (approximately), which simplifies to about 2510 times more energy released by the San Francisco earthquake compared to the earthquake in Japan.
Write a quadratic equation with the given roots. Write the equation in the form of ax^2+bx+c=0 where a b and c are integers
You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.
If the [tex] x^2 [/tex] coefficient is 1, i.e. the equation is written like [tex] x^2+bx+c=0 [/tex], then you can say the following about the coefficients b and c:
[tex] b [/tex] is the opposite of the sum of the roots[tex] c [/tex] is the multiplication of the roots.So, for example, if we want an equation whose roots are 4 and -2, we have:
[tex] 4+(-2) = 4-2 = 2 \implies b = -2 [/tex][tex] 4 \cdot (-2) = -8 \implies c = -8 [/tex]So, the equation is [tex] x^2-2x-8=0 [/tex]
If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:
[tex] \dfrac{3}{4}+\dfrac{1}{2} = \dfrac{3}{4}+\dfrac{2}{4} = \dfrac{5}{4} \implies b = -\dfrac{5}{4} [/tex][tex] \dfrac{3}{4} \cdot \dfrac{1}{2} = \dfrac{3}{8} \implies c = \dfrac{3}{8} [/tex]And so the equation is
[tex] x^2 - \dfrac{5}{4} + \dfrac{3}{8} = 0 [/tex]
In order to have integer coefficients, you can multiply both sides of the equation by 8:
[tex] 8x^2 - 10 + 3 = 0 [/tex]
If x > 0 and y < 0, where is the point (x, y) located?
If x > 0 and y < 0 then the point (x, y) is located in Quadrant IV.
Look at the picture.
Answer:
II
Step-by-step explanation:
For every ten sheets of stickers you buy at a craft store, the total cost increases 20.50.
Answer:
cost of one sheet of sticker = 2.05
Step-by-step explanation:
given that for every 10 sheets of stickers total c0st increases 20.50
i.e. cost of 10 sheets of stickers = 20.50
When we purchase 1 sheet the price would be reduced.
In other words, direct variation is there for sheets of papers and costs
Hence for 1 sheet of stickers cost would be less than 10 sheets.
So divide by 10
Cost of 1 sheet of sticker = 20.50/10 = 2.05
The zoo closes at 5:00 p.M. It takes 3 1/2 hours to feed all the animals after closing. At what time do the zookeepers finishing feeding?
The zookeepers finish feeding the animals at 8:30 PM
An albatross can fly 400 kilometers in 8 hours at a constant speed using d as distance and t as number of hours. An equation that represents this situation is d=50t what are two contants of proportionality for the relationship between distance in kilometers and number of hours? What is the relaionship between the two values?
Answer:
Constant of Proportionality is 50.
Step-by-step explanation:
Albatross can fly 400 kilometers in 8 hours.
'd' represents the distance and 't' represents the number of hours.
The equation [tex]d=50t[/tex] represents the relationship between the distance and time.
Now, in the equation shown above 50 is the constant of proportionality, and 50 represents the rate of change of distance with time.
The constant of proportionality tells us the rate of change between two variables.
So for every 1 hour of time the distance covered is 50 kilometers.
Jerry walked a dog from 6:40 am to 7:30am . If he was paid $6 per hour how much did he earn
Answer:
Amount Jerry earned is $5
Step-by-step explanation:
Jerry is paid $6 per hour.
First we need to find the number of hours he walked the dog.
From 6.40 am to 7.30 am we have 50 minutes. Jerry walked the dog for 50 minutes.
An hour has 60 minutes.
We need to find how much Jerry gets paid for a minute.
Amount paid for a minute = [tex]\frac{$6}{60}[/tex]
=$[tex]0.1[/tex]
Therefore,
Amount paid for 50 minutes = $[tex]0.1[/tex] * [tex]50[/tex] minutes
=$[tex]5[/tex]
Determine the graph behavior at the zero(s) of the polynomial function f(x)=x^2 - 6x+9
[tex]f(x)=x^2-6x+9=(x-3)^2[/tex]
This a perfect square so the x-axis is a tangent at x=3
The correct answer is C
See graph
Given function is f(x) = x² -6x +9.
It is a quadratic function whose graph is an upward open parabola.
The zero(s) of the given function would be at x-intercepts of the graph i.e. y = 0.
It means 0 = x² -6x +9
We can solve this quadratic equation using factorization as follows:-
0 = x² -6x +9
0 = x² -3x -3x +9
0 = x(x-3) -3(x-3)
0 = (x-3)(x-3)
Therefore, x = 3 with multiplicity two.
Hence, option C is correct, i.e. The graph of the function touches the x-axis at x = 3.
Writing Polynomial Function Given a y-Intercept
We already got
f(x)= a(x-2)(x-3)(x-5)
We got [tex]a=\frac{1}{6}[/tex]
first we multiply the parenthesis in f(x)
f(x)= a(x-2)(x-3)(x-5)
[tex]f(x)= a(x^2-5x+6)(x-5)[/tex]
[tex]f(x) = a(x^3 - 10 x^2 + 31 x - 30)[/tex]
Replace the value of 'a'
[tex]f(x) = \frac{1}{6}(x^3 - 10 x^2 + 31 x - 30)[/tex]
Multiply 1/16 inside the parenthesis
[tex]f(x) = \frac{1}{6}x^3 - \frac{5}{3} x^2 + \frac{31}{6} x - 5[/tex]
7.67,7,7.72,7.38 least to greatest
Last year a business had profits of 8,000 this year it profit are five time as great what are this year profits
If 6 times a number is added to -4, the result is 10 times the number. Find the number.
the number is - 1
let the number be n then 6 times the number is 6n and added to -4 is
- 4 + 6n = 10n ( equal to 10 times the number )
subtract 6n from both sides
- 4 = 4n ( divide both sides by 4 )
[tex]\frac{-4}{4}[/tex] = n , hence n = - 1
A 20-foot length of wire is to be cut into 2 pieces, so that the longer piece is two feet longer than two times the shorter piece. Find the length of each piece.
2x+2=20-x
3x=18
x=6
2nd=14
Select all that apply.
To solve an equation with a variable, which of the follow are done?
Inverse operations are used
Addition is always used
The variable needs to be isolated
The value of the variable should be guessed first
answer is inverse operations are used
Answer:
The variable needs to be isolated and inverse operations are used.
Find the distance between -3 and 4. A) -12 eliminate b) -7 c) -1 d) 7
The formula of a distance between A and B = |B - A|.
We have -3 and 4. Substitute:
|4 - (-3)| = |4 + 3| = |7| = 7
Answer: d) 7What can be concluded about the sequence? The common ratio of the sequence is 2. The common difference of the sequence is 2. The next term of the sequence is represented by the point (5, 64). The next term of the sequence is represented by the point (5, –64).
The given information suggests that the sequence is a geometric sequence. The common ratio is 2, and the common difference is 2. The next term of the sequence can be found using the coordinates (5, 64) and (5, -64).
Explanation:The given information about the sequence suggests that it is a geometric sequence.
If the common ratio is 2, it means that each term is obtained by multiplying the previous term by 2.
If the next term is represented by the point (5, 64), it means that the 5th term of the sequence is 64. Using the formula for a geometric sequence, we can find the first term: a * (2^(5-1)) = 64, where a is the first term of the sequence.
Similarly, if the next term is represented by the point (5, -64), it means that the 5th term of the sequence is -64. Using the formula for a geometric sequence, the first term is -8.
Which linear inequality is represented by the graph? y ≤ 1/2x + 2
y ≥ 1/2x + 2
y ≤ 1/3x + 2
y ≥ 1/3x + 2
Answer:
I can confirm that the answer is in fact A
Step-by-step explanation:
I took the test and got it right ( edge 2021 )
The linear inequality represented by the graph is y ≤ 1/2x + 2. The correct option is A.
What is inequality?The relation between two expressions that are not equal, employing a sign such as ≠ ‘not equal to, > ‘greater than, or < ‘less than.
A graph is the representation of the data on the vertical and horizontal coordinates so we can see the trend of the data.
The given inequality y ≤ 1/2x + 2 is represented on the graph attached with the answer below.
In the graph, the linear line cut x-axis at ( -4, 0 ) and y-axis at ( 0, 2 ). And inequality covers the whole space below the line y = 1/2x + 2.
The linear inequality represented by the graph is y ≤ 1/2x + 2. The correct option is A.
To know more about inequality follow
https://brainly.com/question/24372553
#SPJ5
Matter is anything that
A. has mass and takes up space.
B. has only one physical state.
C. is important to human society.
D. contains two elements combined chemically.
The answer is A. Matter is anything that has mass and takes up space
21) on the first day of his cross-country trip, mike drove 100 miles in 2 hours before stopping for lunch. After lunch, he drove 420 miles in 6 hours. What was average speed in miles per hour for his 8 hours of driving?
Answer:
Average speed = 65 miles per hour
Step-by-step explanation:
Mike drove 100 miles in 2hrs
He stopped to take lunch then;
drove 420 miles in 6hrs
Total distance covered = 100 + 420 miles = 520 miles
Total time taken = 2 + 6 hrs = 8hrs
Average speed = Total distance ÷ total time = 520/8 = 65 miles per hour