Noble gas notation write the electron configuration for the manganese atom

Answers

Answer 1
 the electron configuration for the manganese atom [Ne]3s²

Related Questions

the closer an object is to the center of earth the ------------------ the gravitational force on that object

A greater

B less

these science

Answers

Answer:

Greater

Explanation:

According to the law of universal gravitation, the force of gravitation is directly proportional to the product of the masses of the two objects and INDIRECTLY proportional to the square of the distance. In short, the bigger the masses, the stronger the gravitational force, the lesser the distance between the two objects, the greater the gravitational force.

The atomic number of gold (Au) is 79, and it has a mass number of 197. How many electrons are present in each atom of gold?

Answers

There would be 79 electrons present in each atom of gold. I hope this helps :)

why might polar bears might become extinct A. they may drown when the glaciers melt B. too many people hunt them C. they do not have any predators D. their thick fur is not suited for a warming climate

Answers

They may drown when the glaciers melt is the cause of extinction of polar bears.

Reasons for extinction of polar bears

The climate change is the main factor for extinction of polar bear. This climate change is responsible for melting and fragmention of sea ice across the Arctic, forcing more pregnant females to migrate to land. This fragmentation also causes the drowning of polar bears.

So we can conclude that They may drown when the glaciers melt is the cause of extinction of polar bears.

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Answer:

Explanation:

A) Their thick fur is not suited for a warming climate.

Calculate the density of SO3 gas at STP. Show all work.

Answers

When the density formula at STP is:
density = molar mass / molar volume

So we can get the molar mass of SO3 from the periodic table = 32 + (16x3) = 80g

and at STP each 1 mole of gas occupy 22.4 L so we have the molar volume at STP = 22.4.
So by substitution in the density formula:
∴ density of SO3 = 80 g / 22.4 L = 3.571 g /L

Which of the following atoms would have the greatest velocity if each atom had the same kinetic energy?

Answers

the answer is hydrogen 

An atom would have the greatest velocity if each atom had the same kinetic energy is hydrogen. Therefore, option A is correct.

What do you mean by the kinetic energy ?

The energy an item has as a result of motion is known as kinetic energy. A force must be applied to an item in order to accelerate it. We must put forth effort in order to apply a force. Once the job is finished, energy is transferred to the item, which then moves at a new, constant speed.

The reason molecules in gases have the largest kinetic energy is because they have greater space between one another, experience less intermolecular force, and travel at a faster rate, which results in higher energy.

The most kinetic energy is found in gases, whereas solids have the lowest. So, of the examples above, hydrogen has the largest kinetic energy.

Thus, option A is correct.

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Your question is incomplete, most probably your question was

Which of the following atoms would have the greatest velocity if each atom had the same kinetic energy?

A. Hydrogen

B. Oxygen

C. Carbon

D. Sulfur

A 595 mL sample of chlorine gas at 24.7°C is held at constant pressure while it is heated and the volume of the gas expands to 876mL. What is the new temperature in Kelvin?
A) 83.7 K
B) 202 K
C) 365 K
D) 438 K

Answers

Charles law gives the relationship between temperature of gas and volume. This states that the volume of gas is directly proportional to the temperature at a constant pressure.
[tex] \frac{V1}{T1} = \frac{V2}{T2} [/tex]
Parameters for the first instance is given on the left side and parameters for the second instance are given on the right side of the equation.
temperature should be given in K.
temperature in Kelvin = temperature in celcius + 273
24.7 °C + 273 = 297.7 K
595 mL / 297.7 K = 876 mL / T
T = 438.2 K rounded off is 438 K
Answer is D

What location around the world are volcanoes consistently found? Along plate boundaries National parks Continent-ocean boundaries Along the equator

Answers

The location that volcanoes are consistently found in the World is near the Ring of Fire so the answer would be Continent-Ocean Boundaries. Hope this helped give brainiest, please!

The answer is continent ocean boundaries.

Potassium-40 can decay into either calcium-40 or argon-40. All three of these atoms have essentially the same weight. Ninety percent of the potassium-40 will decay into calcium-40, and only ten percent will decay into argon-40. When argon-40 is produced by the radioactive decay of potassium-40 inside a rock, the argon-40 produced by the decay is a gas and is trapped inside the rock. The amount argon-40 trapped in a rock can be measured by grinding up the rock and capturing the liberated argon-40 gas.

Suppose the amount of potassium-40 inside a rock is measured to be 0.81 milligrams, and the amount of argon-40 gas trapped in the rock is measured to be 0.377 milligrams.


1. How much of the potassium-40 that was originally present inside the rock has undergone radioactive decay to produce argon-40?

Answers

Answser:

3.77 mg of K-40 decayed into Ar-40.

Data:

1) K-40, Ca-40, Ar-40: all three have the same atomic mass
2) 90% of the potassium-40 will decay into calcium-40
3) 10% of the potassium-40 will decay into argon-40.
4) K-40 inside the rock = 0.81 mg
5) Ar-40 trapped = 0.377 mg

Soltuion:

1) 0.377 mg of Ar-40 is the 10% of the mass of the K-40 that decayed

=> x * 10% = 0.377 mg => x * 0.1 = 0.377mg

=> x = 0.377 mg / 0.1 = 3.77 mg

That means that 3.77 mg of K-40 decayed into Ar-40. And this is the answer to the question.

Additionaly, you can analyze the content of all K-40 and Ca-40, to understand better the case.

2) The mass of the K-40 that decayed into Ca-40 is 9 times (ratio 9:1) the amount that decayed into Ar-40 =>

mass of K-40 that decayed into Ca-40 = 9 * 0.377 = 3.393 mg

3) Total amount of K-40 that decayed = amount that decayed into Ar-40 + amount that decayed into Ca-40 = 0.377mg + 3.393mg = 3.77 mg

4) Original amount of K-40 = amount of K-40 that decayed + amount of K-40 present in the rock = 3.77mg + 0.81 mg = 4.58 mg

5) amount of K-40 that decayed into Ar-40 as percent

% = [3.77 mg / 4.58mg] * 100 = 82.31 %.



C2H4(g) + H2(g) mc009-1.jpg C2H6(g) + 137 kJ What happens to the amount of ethane (C2H6) when the temperature of the system is increased? The amount of ethane decreases. The amount of ethane increases initially and then decreases. The amount of ethane increases. The amount of ethane decreases initially and then increases.

Answers

Answer is: the amount of ethane decreases.
This reaction is exothermic, which means that heat is released. According to Le Chatelier's principle when the reaction is exothermic heat is included as a product and when the temperature increased, the heat of the system increase, so the system consume some of that heat by shifting the equilibrium to the left,  producing less ethane.

Answer:

A) The amount of ethane decreases.

Explanation:

Is more chemical weathering likely to occur in New York location or in the Illinois location? Explain your answer. HELP NEEDED (Science)

Answers

The pH of pure water is 7.0, which is neutral.

For a pH below this, the water is acidic. Substances that are acidic are often corrosive and thus could cause weather damaging. The pH of the precipitation in NY is below that of the precipitation in IL, and NY receives more precipitation, so for both of those reasons, it is likely to have more chemical weathering.

How many moles of CaCl2 have you delivered to the flask if you add 20.53mL of 0.511 M CaCl2 from the buret

Answers

Answer is: 0,0105 moles of calcium chloride have delivered to the flask.
V(CaCl₂) = 20,53 mL ÷ 1000 mL/L = 0,02053 L.
c(CaCl₂) = 0,511 M = 0,511 mol/L.
n(CaCl₂) = c(CaCl₂) · V(CaCl₂).
n(CaCl₂) = 0,511 mol/L · 0,02053 L.
n(CaCl₂) = 0,0105 mol.

We have that for the Question "How many moles of CaCl2 have you delivered to the flask if you add 20.53mL of 0.511 M CaCl2 from the buret" it can be said that no of moles of solute is

[tex]no of moles of solute=0.011[/tex]

From the question we are told

How many moles of CaCl2 have you delivered to the flask if you add 20.53mL of 0.511 M CaCl2 from the buret

Generally the equation for the morality  is mathematically given as

[tex]M=\frac{no of moles of solute}{volume of solution litre}[/tex]

Therefore

[tex]The volume of CaCl_2 =\frac{20.53}{1000}[/tex]

Hence

no of moles of solute=molality*volume*solution

[tex]no\ of\ moles\ of\ solute=0.511*\frac{20.53}{1000}[/tex]

[tex]no of moles of solute=0.011[/tex]

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A certain material has a mass of 12.48 g while occupying 12.48 cm3 of space. What is this material?

Answers

This material has a density of 1 g/cm3.
(since 12.48 g/ 12.48 cm3 = 1 g/cm3)

Therefore, this material is water.

Answer: The material is water as it has density of [tex]1g/cm^3[/tex]  

Explanation:

Density is defined as the mass contained per unit volume.  It is characteristic of a material.

[tex]Density=\frac{mass}{Volume}[/tex]

Given : Mass of object =12.48 grams

Volume of the object = [tex]12.48cm^3[/tex]

Putting in the values we get:

[tex]Density=\frac{12.48g}{12.48cm^3}[/tex]

[tex]Density=1g/cm^3[/tex]

Thus the density of the material is [tex]1g/cm^3[/tex] and material is water which has density of  [tex]1g/cm^3[/tex].

For a certain gas-phase reaction, the fraction of products in an equilibrium mixture is increased by either increasing the temperature or increasing the volume of the reaction vessel. complete the sentences to determine if the reaction is endothermic or exothermic and to determine which side of the equation has more molecules.

Answers

Hello!

First, we can model the chemical reaction in the following way:

nA(g) ⇄ mB(g)

Now, we can start answering the two questions:

 1) Determine if the reaction is endothermic or exothermic:

The reaction is endothermic. We know that because the fraction of products is increased when the temperature is increased. According to Le Chatelier's principle, the system will move in the opposing direction of the changes to establish a new equilibrium. We can model an endothermic reaction in the following way, knowing that it needs heat to be completed

nA(g) + Δ ⇄ mB(g)

So, adding heat in the left side of the reaction will displace the equilibrium in the opposing direction (the right side) increasing the fraction of products.

2) Determine which side of the equation has more molecules:

The right side of the equation has more molecules than the left side. According to Le Chatelier's Principle, in a gas phase reaction, increasing the volume results in a decrease in the internal pressure of the system, so the reaction shifts to the side with more molecules to restore the pressure of the system. As the fraction of products increases with the increase in volume, the right side will have more molecules. We can then express this reaction in the following way:

nA(g) ⇄ mB(g)  n<m

Have a nice day!

Final answer:

The reaction is endothermic because increasing the temperature increases the fraction of products, as energy acts as a reactant. Moreover, since the product fraction increases with volume, the products' side has more molecules, showing that the reaction has a larger number of gaseous products.

Explanation:

For a gas-phase reaction, the fraction of products in an equilibrium mixture is increased by either increasing the temperature or increasing the volume of the reaction vessel. To determine if the reaction is endothermic or exothermic, we can use the behavior of the system in response to these changes. When temperature is increased for an endothermic reaction, energy can be considered as a reactant, therefore, the equilibrium shifts towards the products. Conversely, for an exothermic reaction, which releases energy, an increase in temperature would shift the equilibrium towards reactants. Since increasing the temperature increases the fraction of products, the reaction is endothermic.

Regarding the change in volume, an increase in volume results in a decrease in pressure and favors the side of the reaction with more gas molecules. If the fraction of products increases with increased volume, this indicates that the side with the products has more gas molecules. Therefore, the reaction equation has more molecules on the products' side.

Which element is most metallic in character? EXPLAIN YOUR REASONING

Answers

You can tell the metallic property based on the first ionization of an element. The lower the first-ionization energy the more metallic the atom. So based on your table Element 2  is the most metallic. 

The more metallic an atom is the less amount of energy is needed to remove an electron. 

What happens when naoh is added to a buffer composed of ch3cooh and ch3coo−?

Answers

Hello!

When NaOH is added to a buffer composed of CH₃COOH and CH₃COO⁻, the following reactions happen:

-First, the NaOH is neutralized by CH₃COOH:

NaOH + CH₃COOH → H₂O + CH₃COONa

-Second, the CH₃COONa dissociates in its ions:

CH₃COONa  → CH₃COO⁻ + Na⁺

-Finally, CH₃COO⁻ (a weak base) reacts with water to form OH⁻ ions and regenerate CH₃COOH

CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻

By this sequence of reactions, the buffer can mitigate the effect of the strong base added.

Have a nice day!

pH of buffer solution containing [tex]{\mathbf{C}}{{\mathbf{H}}_{\mathbf{3}}}{\mathbf{COOH}}[/tex] and [tex]{\mathbf{C}}{{\mathbf{H}}_{\mathbf{3}}}{\mathbf{COOH}}[/tex] does not change on addition of NaOH to the buffer.

Further explanation:

Buffer solution:

The aqueous solution that consists of weak acid and its conjugate base is known as buffer solution. Such solutions resist any change in their pH on addition of strong base or acid.

pH is used to determine acidity or basicity of solutions. Solutions with pH less than 7 are acidic in nature, those with pH 7 are neutral and those with pH more than 7 are basic.

Classification of buffers:

Acidic buffer:

Solutions of weak acid and its conjugate base with pH less than 7 are acidic. Mixture of acetic acid and sodium acetate is an example of acidic buffer.

Basic buffer:

Solutions of weak base and its conjugate acid with pH more than 7 are basic in nature. Mixture of ammonium chloride and ammonium hydroxide is an example of basic or alkaline buffer.

[tex]{\text{C}}{{\text{H}}_{\text{3}}}{\text{COOH}}[/tex] is a weak acid while NaOH is a strong base so these react with each other to form respective salt and water. Reaction between these two occurs as follows:

 [tex]{\text{C}}{{\text{H}}_{\text{3}}}{\text{COOH}} + {\text{NaOH}} \to {\text{C}}{{\text{H}}_{\text{3}}}{\text{COONa}} + {{\text{H}}_{\text{2}}}{\text{O}}[/tex]

The salt formed by reaction of [tex]{\text{C}}{{\text{H}}_{\text{3}}}{\text{COOH}}[/tex] with NaOHis then dissociated to form its ions as follows:

[tex]{\text{C}}{{\text{H}}_{\text{3}}}{\text{COONa}} \rightleftharpoons {\text{C}}{{\text{H}}_{\text{3}}}{\text{CO}}{{\text{O}}^ - } + {\text{N}}{{\text{a}}^ + }[/tex]  

Ionic identity [tex]{\text{C}}{{\text{H}}_{\text{3}}}{\text{CO}}{{\text{O}}^ - }[/tex] reacts with water to form uncharged [tex]{\text{C}}{{\text{H}}_{\text{3}}}{\text{COOH}}[/tex] again. Reaction for this is as follows:

[tex]{\text{CHCO}}{{\text{O}}^ - } + {{\text{H}}_{\text{2}}}{\text{O}} \rightleftharpoons {\text{C}}{{\text{H}}_{\text{3}}}{\text{COOH}} + {\text{O}}{{\text{H}}^ - }[/tex]  

By going through above series of reactions, effect of addition of NaOH is neutralized by buffer containing [tex]{\text{C}}{{\text{H}}_{\text{3}}}{\text{COOH}}[/tex] and [tex]{\text{C}}{{\text{H}}_{\text{3}}}{\text{CO}}{{\text{O}}^ - }[/tex]. Hence pH of buffer solution does not undergo any change in it.

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Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Buffer solutions

Keywords: buffer solution, pH, CH3COOH, NaOH, CH3COO-, weak acid, strong base, acidic buffer, basic buffer, less than 7, more than 7, H2O, OH-, CH3COONa, reaction, conjugate base.

Predict whether the compounds are soluble or insoluble in water.
Soluble
Insoluble


Answers

Final answer:

Generally, polar and ionic compounds are soluble in water, while non-polar compounds are insoluble. However, conclusively predicting a compound's solubility requires additional information about the compound.

Explanation:

The solubility of compounds in water depends on the chemical nature of the compound. Generally, polar and ionic compounds are soluble in water due to its polar nature. This is because 'like dissolves like'. So, compounds such as sodium chloride, sugar, etc., are soluble in water.

On the other hand, non-polar compounds are usually insoluble in water. This includes many organic compounds like oils and fats.

However, the solubility of a compound can't be predicted with absolute certainty without additional information about the compounds' molecular structure, polarity, or the presence of functional groups.

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Calculate the mass of nitrogen dissolved at room temperature in a 80.0 l home aquarium. assume a total pressure of 1.0 atm and the mole fraction for nitrogen of 0.78. (the kh value for nitrogen in water is 6.1 x 10-4 m/atm.)

Answers

Final answer:

To calculate the mass of nitrogen dissolved in an 80.0 L aquarium, apply Henry's Law using the mole fraction and total pressure alongside the molar mass of N2, resulting in approximately 1.066 grams of dissolved nitrogen.

Explanation:

To calculate the mass of nitrogen dissolved in an 80.0 L home aquarium at room temperature, we consider the given total pressure of 1.0 atm and the mole fraction for nitrogen of 0.78. With the Henry's law constant (Kh) for nitrogen in water being 6.1 x 10-4 M/atm, we can determine the concentration of dissolved nitrogen first.

First, calculate the partial pressure of nitrogen (PN2) using the mole fraction and total pressure:

PN2 = mole fraction of N2 * total pressure = 0.78 * 1.0 atm = 0.78 atm

Next, apply Henry's Law to find the concentration of N2 in moles per liter (M):

Concentration of N2 = Kh * PN2 = 6.1 x 10-4 M/atm * 0.78 atm = 4.758 x 10-4 M

To find the total moles of N2 dissolved, multiply this concentration by the volume of the aquarium in liters:

Total moles of N2 = 4.758 x 10-4 M * 80.0 L = 0.038064 mol

Finally, to calculate the mass, we multiply the total moles by the molar mass of N2 (28.01 g/mol):

Mass of N2 = 0.038064 mol * 28.01 g/mol = 1.066 g

The rate of disappearance of hbr in the gas phase reaction 2hbr(g)→h2(g)+br2(g) is 0.140 m s-1 at 150°c. the rate of appearance of h2 is ________ m s-1.

Answers

Answer: 0.070 m/s

Explanation:

1) balanced chemical equation:

given: 2HBr(g) → H2 (g)+Br2(g)

2) Mole ratios:

2 mol HBr : 1 mol H2

3) That means that every time  2 moles of HBr disappear 1 mol of H2 appears.

That is, the H2 appears at half rate than the HBr disappears.

∴ rate of appearance of H2 = rate of disappearance of HBr / 2 = 0.140 m/s / 2 =  0.070 m/s, which is the answer.

The reaction rate is the rate at which reactants convert to the product. The rate of appearance of hydrogen is [tex]\bold{ 0.070 ms^-^1}[/tex]

The given reaction,

[tex]\bold { 2HBr(g) \rightarrow H_2 (g)+Br_2(g)}[/tex]

2 moles of HBr degrade to form 1 mole of Hydrogen and 1 mole of bromine.

The rate of disappearance of HBr = 0.140 m [tex]\bold {s^-^1}[/tex]

Since the molar ratio between HBr and Hydrogen is  2:1.

So,

[tex]\bold{Ra(H_2) = \dfrac {Rd(HBr)} {2}}[/tex]

Where,

[tex]\bold{Ra(H_2)}[/tex] - Rate of appearance of Hydrogen

[tex]\bold{ Rd(HBr)}[/tex]- Rate of disappearance of HBr

Put the value,

[tex]\bold{Ra(H_2) = \dfrac {Rd(HBr)} {2}}\\\\\bold {Ra(H_2) = \dfrac {0.140 m/s} {2}}\\\\\bold { Ra(H_2) = 0.070 ms^-^1}[/tex]

Therefore, the rate of appearance of hydrogen is [tex]\bold{ 0.070 ms^-^1}[/tex].

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Determine how many grams of co2 are produced by burning 4.37 g of c4h10.

Answers

combustion of hydrocarbons is when  C and H containing compounds are burnt in O₂
the balanced chemical reaction for combustion of C₄H₁₀ (butane) is as follows;
2C₄H₁₀ + 13O₂ ---> 8CO₂ + 10H₂O
the stoichiometry of C₄H₁₀ to CO₂ is 2;4, simplified ratio is 1:2
this means that for every 1 mole of butane used up,4 moles of CO₂ are formed
molar mass of butane - (12 g/mol *4) + (1 g/mol * 10) = 58 g/mol
58 g of butane      -  1 mol 
Therefore 4.37 g of butane - 1/58 g/mol * 4.37g = 0.075 mol
1 mol of butane forms --> 4 mol of CO₂
Therefore 0.075 mol of butane forms = 4 x 0.075 mol = 0.3 mol of CO₂
molar mass of CO₂ = 44 g/mol
mass of CO₂ formed = 0.3 mol * 44 g/mol = 13.2 g of CO₂ is formed 
Final answer:

To determine how many grams of CO2 are produced by burning 4.37 g of C4H10, we can use stoichiometry. The balanced equation shows that 1 mole of C4H10 produces 4 moles of CO2. By converting the mass of C4H10 to moles and then using the stoichiometric ratio, we can calculate the mass of CO2 produced.

Explanation:

To determine how many grams of CO2 are produced by burning 4.37 g of C4H10, we can use stoichiometry. The balanced equation shows that 1 mole of C4H10 produces 4 moles of CO2. First, we need to convert the mass of C4H10 to moles by dividing it by the molar mass of C4H10. Then, we can use the stoichiometric ratio to calculate the number of moles of CO2 produced. Finally, we can convert the moles of CO2 to grams by multiplying it by the molar mass of CO2

Given:

Mass of C4H10 = 4.37 gMolar mass of C4H10 = 58.12 g/molMolar mass of CO2 = 44.01 g/mol

Using the equation:

Mass of C4H10 (g) → Moles of C4H10 → Moles of CO2 → Mass of CO2 (g)

we can calculate:

4.37 g C4H10 * (1 mol C4H10 / 58.12 g C4H10) * (4 mol CO2 / 1 mol C4H10) * (44.01 g CO2 / 1 mol CO2) = 17.80 g CO2

Therefore, burning 4.37 g of C4H10 produces approximately 17.80 g of CO2.

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A 0.210 mol sample of pcl5(g) is injected into an empty 2.45 l reaction vessel held at 250 °c. calculate the concentrations of pcl5(g) and pcl3(g) at equilibrium.

Answers

when the balanced equation for this reaction is:
                        PCl5(g)       ↔    PCl3(g) + Cl2(g)
initial  C           (0.21/2.45)              0                 0
change                -X                      +X              +X
equilibruimC  (0.21/2.45)-X           X                 X

So by substitution in Ka formula: when we have Ka at 250°C = 1.8 (must be given- missing in your question)
Ka = [PCl3][Cl2]/[PCl5]
1.8 = (X)(X) / (0.21/2.45)-X
1.8*0.086- 1.8X = X^2
X^2 + 1.8X - 0.1548 = 0 by solving this equation
X= 0.082 mol
∴[PCl5] = (0.21/2.45) - X
             = 0.0857 - 0.082 = 0.0037 mol
∴[PCl3] = X = 0.082 mol

The average atomic mass of oxygen is 15.9994 amu. The atomic masses of its three isotopes are as follows: O-16: 15.995 amu; O-17: 16.999 amu; O-18: 17.999 amu Which isotope is most likely to have the greatest abundance in nature? O–16 O–17 O–18 all three isotopes may be equally abundant

Answers

the average atomic mass of oxygen is the atomic mass with respect to 1/12th the mass of a C-12 atom, related to natural abundance. 
amu - atomic mass units 
O-16 - 15.995 amu
O-17 - 16.999 amu
O-18 - 17.999 amu
the average atomic mass is 15.9994 amu
average atomic mass = ∑atomic mass of each isotope * relative abundance percentage
in other words the average atomic mass is closer to the atomic mass of the most abundant isotope. In this case 15.9994 is closest to 15.995 amu which is the atomic mass of O-16.
This means that O-16 is the most abundant isotope.

Answer: O-16

Explanation: To keep it short and sweet the answer is O-16

Treatment of an alpha,beta-unsaturated ketone with basic aqueous hydrogen peroxide yields an epoxy ketone. the reaction is specific to unsaturated ketones; isolated alkene double bonds do not react. on a sheet of paper, write a mechanism for the alkene to epoxide reaction. then, in the window below, draw the first intermediate in your mechanism.

Answers

The reaction mechanism for an alpha,beta-unsaturated ketone to react with basic peroxide to form an epoxide is shown below with a general ketone. The basic hydroxide is used to deprotonate the peroxide molecule to create a strong HOO- nucleophile. The peroxide then attacks the beta-carbon of the alkene and this pushes the electrons up to the oxygen of the carbonyl. This is the first intermediate that is formed during this reaction.

After the intermediate is formed, the lone pair from the oxygen pushes back down to form the carbonyl once more and this breaks a carbon-carbon bond which attacks the oxygen of the peroxy group, ultimately substituting an -OH group and forming the final epoxide ketone product.

If 17.4 mL of 0.800 M HCl solution are needed to neutralize 5.00 mL of a household ammonia solution, what is the molar concentration of the ammonia?

Answers

Answer: The concentration of ammonia is 2.784 M

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

[tex]n_1M_1V_1=n_2M_2V_2[/tex]

where,

[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is [tex]HCl[/tex]

[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is ammonia

We are given:

[tex]n_1=1\\M_1=0.800M\\V_1=17.4mL\\n_2=1\\M_2=?M\\V_2=5.00mL[/tex]

Putting values in above equation, we get:

[tex]1\times 0.800\times 17.4=1\times M_2\times 5.00\\\\M_2=2.784M[/tex]

Hence, the concentration of ammonia is 2.784 M

The molar concentration of the household ammonia solution is 2.78 M.

Let's start by writing the neutralization reaction:

HCl (aq) + NH₃ (aq) → NH₄Cl (aq)

The number of moles of HCl required to neutralize the ammonia solution can be calculated from the volume and molarity of the HCl solution:

moles HCl = Molarity x Volume (in liters) = 0.800 M x 17.4 mL x (1 L / 1000 mL) = 0.01392 mol

Since the reaction is 1:1, the number of moles of NH₃ required to neutralize the HCl is also 0.01392 mol.

The molar concentration of the ammonia solution can be calculated from the number of moles and the volume of the solution:

Molarity = moles / volume (in liters) = 0.01392 mol / 5.00 mL x (1 L / 1000 mL) = 2.78 M

Therefore, the molar concentration of the household ammonia solution is 2.78 M.

An aqueous solution has an h3o+ concentration of 4.4×10-2 m. calculate [oh–] for this solution.

Answers

first   calculate  Ph
Ph=  -log (H3O+)
Ph=-log( 4.4  x10^-2)=  1.4

Ph  +Poh=14
Poh  is  therefore= 14  - 1.4=12.6

Oh-   concentration  is  calculated   as  follows
1 x10^  -POh
that  is  1  x10^-12.6   which  is=  2.5  x10^-13

Hannah just finished building a house of cards that stands four stories high. She is worried that it will fall down. Which of the following statements must be true? A. A house of cards is too fragile and must fall down eventually due to gravity. B. If Hannah adds another card to the house of cards, then it will fall down. C. As long as nobody touches the house of cards, it will remain standing. D. If no unbalanced force acts upon the house of cards, then it will remain standing forever.

Answers

I think it's A, a house of cards is too fragile and must fall down eventually due to gravity.



Comment the correct answer. 

the answer is if no unbalanced force acts upon the house of cards then it will remain standing forever.

explanation:Newton's first law of motion states that an object at rest will remain at rest unless acted upon by an unbalanced force.  

Even if nobody touches the house of cards, another type of unbalanced force (like wind) could knock the cards down, or if Hannah adds another card to the house of cards, it may or may not fall down.

However, if no unbalanced force acts upon the house of cards, then it will remain standing forever.

when sodium hydroxide is dissolved in water, energy is released as heat to the surroundings l, causing an increase in the solutions temperature. which of the following best describes this type of reaction?
a.- exothermic
b.- exothermic
c.- decomposition
d.- synthesis

Answers

Final answer:

The process of sodium hydroxide dissolving in water and releasing heat is best described as an exothermic reaction, as it involves the release of energy to the surroundings.

Explanation:

When sodium hydroxide (NaOH) is dissolved in water, it disassociates into sodium (Na+) and hydroxide (OH-) ions, releasing energy in the form of heat to the surroundings, and causing an increase in the temperature of the solution. This type of reaction, where energy is released, is best described as an exothermic reaction. These reactions are characterized by the release of heat and a rise in the temperature of the surroundings. Care must be taken when dissolving sodium hydroxide in water due to the significant amount of heat produced.

It is important to note that this is different from an endothermic reaction, where energy is absorbed from the surroundings, causing a decrease in temperature. The process of sodium hydroxide dissolving in water is not a decomposition reaction, as that involves a single compound breaking down into two or more simpler substances. It also does not fit the definition of a synthesis reaction, which involves combining simpler substances to form a more complex product.

Final answer:

The dissolution of sodium hydroxide in water, which releases heat and increases the solution's temperature, is an exothermic reaction.

Explanation:

When sodium hydroxide is dissolved in water and energy is released as heat, increasing the solution's temperature, this type of reaction is best described as exothermic. An exothermic reaction is characterized by the release of energy to the surroundings, often in the form of heat. As the sodium hydroxide (NaOH) dissolves, it disassociates into sodium (Na+) and hydroxide (OH-) ions, and the process releases a significant amount of heat, indicating that the solution becomes very basic and the temperature rises.

How many grams of sodium iodide Nai must be used to produce 51.9 G of iodine I2

Answers

Hello!

61,30 grams of Sodium Iodide NaI must be used to produce 51,9 g of Iodine I₂

The reaction for the production of Iodine from NaI is the following:

2NaI(aq) + Cl₂ → I₂ + 2 NaCl

To calculate how many grams of NaI are needed to produce 51,9 g of Iodine, we use a conversion factor to go backward from grams of iodine to grams of sodium iodide. The coefficients of the reaction will help us, as well as the molar masses of each compound.

 [tex]51,9gI_2* \frac{1 mol I_2}{253,809 g I_2}* \frac{2 mol NaI}{1 mol I_2} * \frac{149,89 g NaI}{1 mol NaI}=61,30 g NaI [/tex]

Have a nice day!

Final answer:

To produce 51.9 grams of iodine (I2), approximately 61.2 grams of sodium iodide (NaI) must be used. This calculation is based on stoichiometry and the molar masses of NaI and I₂.

Explanation:

To calculate the amount of sodium iodide (NaI) needed to produce a given amount of iodine (I₂), we will use stoichiometry based on the balanced chemical equation of the reaction. The molecular weight of I₂ (iodine) is approximately 253.8 g/mol (126.9 g/mol for each iodine atom). Let's calculate how many moles of I₂ are in 51.9 grams.

Step 1. Convert from grams to moles of I₂ using the molar mass of I₂ in the unit conversion factor.

51.9 g I₂ × (1 mol I₂ / 253.8 g I₂) = 0.204 moles of I₂.

The balanced chemical equation for the production of iodine from sodium iodide may look like this, depending on the reacting substances involved:

2 NaI + Cl₂ → 2 NaCl + I₂

From the balanced equation, we see that the molar ratio between NaI and I₂ is 2:1. This means it takes 2 moles of NaI to produce 1 mole of I₂.

Step 2. Use the stoichiometry to find the moles of NaI needed.

0.204 moles I₂ × (2 moles NaI / 1 mole I₂) = 0.408 moles of NaI needed.

Step 3. Convert moles of NaI to grams.

The molar mass of NaI (22.99 g/mol for Na + 126.9 g/mol for I) is approximately 149.89 g/mol.0.408 moles NaI × (149.89 g NaI / 1 mole NaI) = 61.2 grams of NaI.

Therefore, to produce 51.9 grams of iodine (I₂), approximately 61.2 grams of sodium iodide (NaI) must be used.

A certain reaction has an activation energy of 69.0 kj/mol and a frequency factor of a1 = 3.40×1012 m−1s−1 . what is the rate constant, k, of this reaction at 22.0 ∘c ? express your answer with the appropriate units. indicate the multiplication of units explicitly either with a multiplication dot (asterisk) or a dash.

Answers

I'm not really sure.........

What is the oxidation state of each element in k2cr2o7?

Answers

To begin this, you'll first note down the valencies of atoms you're sure about.

K is always 1+
And O is always 2-, except for in peroxide where it is 1-.

So now you must remember that a compound is always neutral. Your net charge has to be 0.

K2Cr2O7.

K2 (1+ x 2) = 2+
Cr (2x) = 2x
O7 (2- ×7) = 14-

+2 +2x + (-14) = 0
•Simple algebra.
2x -12 = 0
2x = 12
x = +6.

Each Cr atom has an oxidation number of +6.

The oxidation number is the charge when the bonds are ionic in the atom. The oxidation state of potassium is +1, oxygen is -2 and chromium is +6.

What is the oxidation state?

The oxidation state or the number is the total of the electron gained or lost by the atom to form the chemical bond.

Potassium is always +1, and oxygen is -2 except in some cases.

The state can be shown as:

[tex]\rm K_{2} (+1 \times 2) = +2[/tex]

Cr (2x) = 2x

[tex]\rm O_{7} (-2 \times 7) = -14[/tex]

When the compound is neutral and the net charge is 0 then,

[tex]\begin{aligned} \rm +2 +2x + (-14) &= 0\\\\\rm 2x -12& = 0\\\\\rm x &= +6\end{aligned}[/tex]

Therefore, the oxidation number of chromium is +6.

Learn more about oxidation numbers here:

https://brainly.com/question/861708

The molar volume of a gas at STP, in liters, is ___ .
You can use the molar volume to convert 2 mol of any gas to ___ L.
You can also use the molar volume to convert 11.2 L of any gas to ____ mol. Avogadro’s law tells you that 1.2 L of O2(g) and 1.2 L of NO2(g) are ______-numbers of moles of gas.

Answers

Let us consider the following points

a) The volume of one mole of an ideal gas at STP (273.15 K and 1 atm) is 22.4 L.

b) the number of moles of in any given volume of gas can be calculated as:

[tex]Moles=\frac{22.4L}{Volumegiven}[/tex]

Solutions:

1) The molar volume of a gas at STP, in liters, is 22.4 L.

2) You can use the molar volume to convert 2 mol of any gas to 44.8 L

Volume = moles X 22.4L

Volume = 2 X 22.4 = 44.8L

3) You can also use the molar volume to convert 11.2 L of any gas to 0.5 mol.

As mentioned above

[tex]mole=\frac{volume}{22.4}=\frac{11.2}{22.4}=0.5mol[/tex]

4)  Avogadro’s law tells you that 1.2 L of O2(g) and 1.2 L of NO2(g) are ______-numbers of moles of gas.

The moles of oxygen will be:

[tex]mole=\frac{volume}{22.4}=\frac{1.2}{22.4}=0.0536mol[/tex]

The moles of nitrogen dioxide will be:

[tex]mole=\frac{volume}{22.4}=\frac{1.2}{22.4}=0.0536mol[/tex]

Total moles = 0.0536+0.0536 = 0.1072 moles


Final answer:

The molar volume of a gas at STP is 22.4 L. Therefore, 2 moles of any gas equals 44.8 L and 11.2 L of any gas equals 0.5 moles. Avogadro's law states that 1.2 L of O2(g) and 1.2 L of NO2(g) have the same number of moles.

Explanation:

The molar volume of a gas at Standard Temperature and Pressure (STP) is approximately 22.4 liters. Therefore, if you have 2 moles of any gas at STP, this would occupy a volume of 2 x 22.4 = 44.8 liters. Conversely, if you have 11.2 liters of any gas at STP, this equates to 11.2 / 22.4 = 0.5 moles of gas. According to Avogadro's law, equal volumes of gases, at the same temperature and pressure, contain equal numbers of molecules. So, 1.2 liters of O2(g) and 1.2 liters of NO2(g) contain the same number of moles of gas.

Learn more about Molar Volume and Avogadro's Law here:

https://brainly.com/question/32790562

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