Answer:
Nuclear plants are plants that involve the fission of relatively large atoms to produce electricity as its final product.
In nuclear power plants, the nuclear energy is converted to heat energy, after which the heat energy is converted to mechanical( rotational energy) which helps in the spinning of the turbines. The mechanical energy is then converted to electrical energy.
slader A baseball player slides to a stop on level ground. Using energy consideration, calculate the distance the 65 kg baseball player slides, given his initial speed is 6 m/s and the force of friction against him is a constant 450N.
Final answer:
The 65 kg baseball player slides a distance of 5.2 meters before coming to a stop, calculated using kinetic energy and the work done by friction.
Explanation:
To calculate the distance the 65 kg baseball player slides using energy considerations, we start by noting that the work done by friction is equal to the loss in kinetic energy as the player comes to a stop. The kinetic energy (KE) of the player can be calculated using the formula KE = (1/2)mv², where m is mass and v is velocity. Since the force of friction (f) is constant, the work (W) done by friction is W = fd, with d being the distance over which the friction acts.
Setting the initial kinetic energy equal to the work done by friction, we get:
(1/2)mv² = fd
Inserting the given values, we have:
(1/2)(65 kg)(6 m/s)² = (450 N)d
Upon calculating, we find:
d = (1/2)(65 kg)(6 m/s)² / (450 N)
d = 5.2 meters
Therefore, the baseball player slides a distance of 5.2 meters before coming to a stop.
A spaceship negotiates a circular turn of radius 2925 km at a speed of 29960 km/h. (a) What is the magnitude of the angular speed? 0.0028 Correct: Your answer is correct. rad/s (b) What is the magnitude of the radial acceleration? 23.68 Correct: Your answer is correct. m/s2 (c) What is the magnitude of the tangential acceleration? m/s2
a) 0.0028 rad/s
b) [tex]23.68 m/s^2[/tex]
c) [tex]0 m/s^2[/tex]
Explanation:
a)
When an object is in circular motion, the angular speed of the object is the rate of change of its angular position. In formula, it is given by
[tex]\omega = \frac{\theta}{t}[/tex]
where
[tex]\theta[/tex] is the angular displacement
t is the time interval
The angular speed of an object in circular motion can also be written as
[tex]\omega = \frac{v}{r}[/tex] (1)
where
v is the linear speed of the object
r is the radius of the orbit
For the spaceship in this problem we have:
[tex]v=29,960 km/h[/tex] is the linear speed, converted into m/s,
[tex]v=8322 m/s[/tex]
[tex]r=2925 km = 2.925\cdot 10^6 m[/tex] is the radius of the orbit
Subsituting into eq(1), we find the angular speed of the spaceship:
[tex]\omega=\frac{8322}{2.925\cdot 10^6}=0.0028 rad/s[/tex]
b)
When an object is in circular motion, its direction is constantly changing, therefore the object is accelerating; in particular, there is a component of the acceleration acting towards the centre of the orbit: this is called centripetal acceleration, or radial acceleration.
The magnitude of the radial acceleration is given by
[tex]a_r=\omega^2 r[/tex]
where
[tex]\omega[/tex] is the angular speed
[tex]r[/tex] is the radius of the orbit
For the spaceship in the problem, we have
[tex]\omega=0.0028 rad/s[/tex] is the angular speed
[tex]r=2925 km = 2.925\cdot 10^6 m[/tex] is the radius of the orbit
Substittuing into the equation above, we find the radial acceleration:
[tex]a_r=(0.0028)^2(2.925\cdot 10^6)=23.68 m/s^2[/tex]
c)
When an object is in circular motion, it can also have a component of the acceleration in the direction tangential to its motion: this component is called tangential acceleration.
The tangential acceleration is given by
[tex]a_t=\frac{\Delta v}{\Delta t}[/tex]
where
[tex]\Delta v[/tex] is the change in the linear speed
[tex]\Delta t[/tex] is the time interval
In this problem, the spaceship is moving with constant linear speed equal to
[tex]v=8322 m/s[/tex]
Therefore, its linear speed is not changing, so the change in linear speed is zero:
[tex]\Delta v=0[/tex]
And therefore, the tangential acceleration is zero as well:
[tex]a_t=\frac{0}{\Delta t}=0 m/s^2[/tex]
Sound moves at a speed of 343 meters per second through air, a gas.
Which pairing is most accurate for how sound will travel through
liquid and solid?
Answer:
need more info
Explanation:
A new roller coaster contains a loop-the-loop in which the car and rider are completely upside down. If the radius of the loop is 17.6 m, with what minimum speed must the car traverse the loop so that the rider does not fall out while upside down at the top? Assume the rider is not strapped to the car.
Answer:
The minimum speed must the car must be 13.13 m/s.
Explanation:
The radius of the loop is 17.6 m. We need to find the minimum speed must the car traverse the loop so that the rider does not fall out while upside down at the top.
We know that, mg be the weight of car and rider, which is equal to the centripetal force.
[tex]mg = \dfrac{mv^2}{r}\\v = \sqrt{rg}\\v = \sqrt{17.6\times 9.8}\\v = 13.13\ m/s\\[/tex]
So, the minimum speed must the car must be 13.13 m/s.
A 0.200 kg air-track glider moving at 1.20 m/s bumps into a 0.600 kg glider at rest.
a.) Find the total kinetic energy after collision if the collision is elastic.
b.) Find the total kinetic energy after collision if the collision is completely inelastic.
Answer:
a) 0.144J
b) 0.12J
Explanation:
A 0.200 kg air-track glider moving at 1.20 m/s bumps into a 0.600 kg glider at rest. a.) Find the total kinetic energy after collision if the collision is elastic. b.) Find the total kinetic energy after collision if the collision is completely inelastic.
Given that
M1 = 0.2kg
M2 = 0.6kg
U1 = 1.2 m/s
Since both momentum and energy are conserved in elastic collisions, the total kinetic energy after collision will be
1/2M1U^2 + 1/2M2U^2
1/2 × 0.2 × 1.2^2 + 0
K.E = 0.144J
B) In elastic collision, only momentum is conserved
M1U1 + M2U2 = (M1 + M2)V
U2 = 0 since the object is at rest
0.2×1.2 + 0 = (0.2 + 0.6)V
0.24 = 0.8V
V = 0.24/0.8
V = 0.3 m/s
K.E = 1/2(M1+M2)V
K.E = 1/2 (0.2 + 0.6) × 0.3
K.E = 0.4 × 0.3
K.E = 0.12J
Answer:
The other person is almost right, but I see where the numbers got fudged
Explanation:
Answer:a) 0.144Jb) 0.036J
Explanation: A 0.200 kg air-track glider moving at 1.20 m/s bumps into a 0.600 kg glider at rest. a.) Find the total kinetic energy after collision if the collision is elastic. b.) Find the total kinetic energy after collision if the collision is completely inelastic. Given that M1 = 0.2kgM2 = 0.6kgU1 = 1.2 m/s Since both momentum and energy are conserved in elastic collisions, the total kinetic energy after collision will be1/2M1U^2 + 1/2M2U^21/2 × 0.2 × 1.2^2 + 0K.E = 0.144J
B) This is where the other person's wrong:
m1u1+m2u2=(m1+m2)V
V=(0.200kg*1.20m/s)/(0.200kg+0.600kg)=0.3m/s
KE=1/2m*v^2
KE=1/2(0.200kg+0.600kg)*(0.3m/s)^2=1/2(0.8x0.3)^2=0.036 J
The diagram shows a person using a piece of gym equipment to lift weights.
A man sits on a chair with pulleys and a line attached to the side. His leg has the line attached to it and is shown in solid lines with his foot on the floor. His leg is also shown raised with a dotted extension of the line attached to it.
Which best describes the body in terms of simple machines?
The knees are inclined planes, and the lower legs hold the loads. The ankles are the fulcrums.
The lower legs are inclined planes, and the knees hold the loads. The ankles are the fulcrums.
The lower legs are levers, and the knees are fulcrums. The ankles hold the loads.
The knees are levers, and the lower legs are fulcrums. The ankles hold the loads.
Final answer:
In the provided scenario, the correct description of the body in terms of simple machines is that the lower legs are levers and the knees serve as fulcrums.
Explanation:
When we analyze the biomechanics of the body using the piece of gym equipment in the provided scenario, particularly during a leg workout, we can compare the body to a set of simple machines. In this context, the lower legs act as levers.
The knees operate as fulcrums, which are the points about which the levers rotate. The ankles do not carry or hold the load in this action; rather they act as the point of application for the effort when extending the foot in movements like calf raises.
The configuration described is analogous to a first-class lever, where the fulcrum (knee) is situated between the effort (muscles applying force near the ankle) and the load (the resistance on the leg extension machine). Hence, the correct description of the body in terms of simple machines is: "The lower legs are levers, and the knees are fulcrums."
To address the components from the question:
The knees are the fulcrums since they are the pivot point for the motion of the lower leg.
The lower legs are levers because they move around the fulcrum to lift the load on the gym equipment.
The ankles are where the calf muscles apply the effort but are not where the load is held.
Therefore, third option is correct: The lower legs are levers, and the knees are fulcrums. The ankles hold the loads.
Does a volcanic eruption cause a warming or cooling effect?
Answer:
they have a cooling effect! :)
Explanation:
Answer:
A cooling effect
Explanation:
As strange as it seems, volcanoes cool during eruption. All of the magma pent up in the core gets released into lava, which drastically changes the internal temperatures. This is kind of like how for some people, yelling/beating on inanimate objects helps them to "cool off".
what game most represents a wave
Answer:
tipping over dominoes
Explanation:
?
One game that represents the concept of a wave is the puzzle game "Wave Wave."
In "Wave Wave," players control a small triangle as it navigates through a series of challenging and rhythmic levels filled with obstacles. The gameplay involves moving the triangle in sync with the pulsating waves that define the level's layout.
The game's visuals and mechanics are designed to mimic the appearance and behavior of a wave, with the obstacles and patterns resembling the peaks and troughs of waves. The player's goal is to maintain control and timing, moving the triangle smoothly through the undulating paths while avoiding collisions.
"Wave Wave" is a creative interpretation of the wave concept in a gaming context, with its gameplay mechanics directly tied to the idea of navigating through waves. Keep in mind that there might be other games that also incorporate wave-like mechanics, so this is just one example.
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What is the measure of how difficult it is for current to flow in a circult?
O A
voltage
B.
resistance
C.
power
D.
energy
Answer:
Resistance
Explanation:
Resistance "resists" the flow of electricity and makes it more difficult to travel. The higher the resistance the less current there is in a circuit. Example being, open circuit (infinity ohms) means there is no current flowing with ohms law.
Which type of field is present near a moving electric charge
Answer:
magnetic field is the correct answer.
Explanation:
The magnetic field is produced by the movement of a charge or by current flow and through a magnetized material.magnetic fields are the areas where the objects display a magnetic force and the magnetic fields also affect the neighboring objects.The magnetic field is used as a tool to explain how the magnetic force is distributed inside thing magnetic.Our local piano tuner is making a house call to tune our piano (... yes, she's maintaining social distance!) She strikes a middle C tuning fork (about 262 Hz frequency), and strikes that key on your piano. You both hear a beat frequency of about 4 Hz. What is the actual frequency of your middle C piano string
Answer:
258 Hz or 266 Hz
Explanation:
When two sounds of similar frequency occur at the same time, a phenomenon called "beat" occurs. The beat is an interference patter between the two sounds; the frequency of this beats (called beat frequency) is given by the difference between the frequencies of the two sounds:
[tex]f_B = |f_1 -f_2|[/tex]
where
[tex]f_B[/tex] is the beat frequency
[tex]f_1[/tex] is the frequency of the 1st sound
[tex]f_2[/tex] is the frequency of the 2nd sound
In this problem,
[tex]f_B=4 Hz[/tex] is the beat frequency
[tex]f_1=262 Hz[/tex] is the frequency of the middle C tuning fork
[tex]f_2[/tex] is the frequency of the middle C piano string
Solving for f2, we find two solutions:
[tex]f_2=f_1-f_B = 262-4 = 258 Hz\\f_2 = f_1+f_B = 262+4=266 Hz[/tex]
Explain why sound energy is not a type of potential energy
Final answer:
Sound energy is a form of kinetic energy, not potential energy, because it arises from the motion and vibration of particles within a medium as the sound wave propagates.
Explanation:
Sound energy is not considered a type of potential energy because it is inherently associated with the motion of particles; therefore, it is a form of kinetic energy. Sound is a mechanical wave that results from the vibration of particles within a medium. As these particles oscillate, they transfer energy through the medium, resulting in what we perceive as sound. While a sound wave indeed combines kinetic and potential energy due to the motion of particles and the elasticity of the medium, the propagation of the wave itself and the sound energy we detect are manifestations of kinetic energy. In the case of potential energy, this form of energy is related to an object's position or state; for instance, a rock atop a hill has gravitational potential energy due to its elevated position in a gravitational field. Similarly, the chemical energy in a battery is potential energy based on the chemical composition and potential for a chemical reaction.
To help visualize the concept, consider water behind a dam. The water has potential energy because of its elevated position. As it moves and flows through turbines, it converts this potential energy into kinetic energy, which then can be harnessed to produce electricity. In contrast, when a guitar string is plucked, the energy initially stored in the deformed string is potential energy, but as the string returns to its normal state and vibrates, it generates sound—which is an expression of kinetic energy. Thus, when sound is produced, it is the motion and transfer of energy through a medium, reflecting kinetic, not potential, energy characteristics.
After a fall, a 75 kg rock climber finds himself dangling from the end of a rope that had been 18 m long and 11 mm in diameter but has stretched by 2.1 cm. For the rope, calculate (a) the strain, (b) the stress, and (c) the Young's modulus.
Answer:
(A) Strain = 0.0012
(b) Stress [tex]=77.44\times 10^5N/m^2[/tex]
(c) Young's modulus [tex]=6.45\times 10^9N/m^2[/tex]
Explanation:
Mass of the rock m = 75 kg
So weight of the rock [tex]F=mg=75\times 9.8=735N[/tex]
Length of the rope l = 18 m
Diameter of the rope d = 11 mm
Change in length of rope [tex]\Delta l=2.1cm =0.021m[/tex]
So radius r = 5.5 mm = 0.0055 m
Cross sectional area [tex]A=\pi r^2[/tex]
[tex]A=3.14\times 0.0055^2=9.49\times 10^{-5}m^2[/tex]
(a) Strain is equal to ratio change in length to original length
So strain [tex]=\frac{\Delta l}{l}=\frac{0.021}{18}=0.0012[/tex]
(b) Stress [tex]=\frac{Weight}{area}[/tex]
[tex]=\frac{735}{9.49\times 10^{-5}}=77.44\times 10^5N/m^2[/tex]
(c) Young's modulus is equal to ratio of stress and strain
So young's modulus [tex]=\frac{77.44\times 10^5}{0.0012}=6.45\times 10^9N/m^2[/tex]
According to the graph, what is the factorization of x2 - 6x + 5?
A. (X - 5)(x - 1)
B. (x + 5)(x - 1)
C. (X - 5)(x + 1)
D. (x + 5)(x + 1)
Answer:
the answer is A (×-5)(×-1)
Answer:
A. (x - 5)(x - 1)
Explanation:
x² - 6x + 5
ax² + by + c
What 2 numbers give a product of 5 (a * c) and a sum of -6 (b)?
-5, -1 ---> -5 + -1 = -6, (-5) * (-1) = 5
x² - 6x + 5 = (x - 5)(x - 1)
Does that help?
oung's experiment is performed with light of wavelength 502 nm from excited helium atoms. Fringes are measured carefully on a screen 1.50 m away from the double slit, and the center of the 20th fringe (not counting the central bright fringe) is found to be 9.60 mm from the center of the central bright fringe. What is the separation of the two slits?
Answer:
0.00156875 m
Explanation:
y = Distance from the 20th fringe = 9.6 mm
l = Distance to screen = 1.5 m
[tex]\lambda[/tex] = Wavelength = [tex]502\ nm[/tex]
m = Number of fringe = 20
We have the relation
[tex]\dfrac{y}{l}=\dfrac{m\lambda}{d}\\\Rightarrow d=\dfrac{m\lambda l}{y}\\\Rightarrow d=\dfrac{20\times 502\times 10^{-9}\times 1.5}{9.6\times 10^{-3}}\\\Rightarrow d=0.00156875\ m[/tex]
The seperation of the two slits is 0.00156875 m
What is the surface temperature of a distant star having a peak wavelength of 475 nm?
Answer:
Explanation:
Given that,
The peak wavelength is
λp = 475nm
Then, we want to find the temperature,
From Wein's displacement law,
When the maximum is evaluated from the Planck radiation formula, the product of the peak wavelength and the temperature is found to be a constant (k = 2.898 ×10^-3 mK)
So, applying this we have
λp•T = 2.898 ×10^-3
T = 2.898 × 10^-3 / λp
T = 2.898 × 10^-3 / 475 × 10^-9
T = 6101.05 K
The surface temperature of the distant star having the given peak wavelength is 6.1 × 10³K.
Given the data in the question;'
Peak wavelength; [tex]\lambda _p = 475nm = 4.75 *10^{-7}m[/tex]
To determine the surface temperature the star, we use the expression for peak wavelength by Wien's Displacement Law:
[tex]\lambda _p = \frac{0.2898 * 10^{-2}m.K}{T}[/tex]
Where T is the surface temperature
We substitute our value into the formula and solve for for "T"
[tex]4.75*10^{-7}m = \frac{0.2898 * 10^{-2}m.K}{T}\\\\T = \frac{0.2898 * 10^{-2}m.K}{4.75*10^{-7}m}\\\\T = 6. 1 * 10^3K[/tex]
Therefore, the surface temperature of the distant star having the given peak wavelength is 6.1 × 10³K.
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A ball rolls from x=-5 to x=32.4 m in 8.9 seconds. What was it’s average velocity
Answer:
4.157 m/s
Explanation:
Average velocity: This can be defined as the ratio change in position to time interval. The S.I unit of average velocity is m/s
The expression for average velocity is given as,
V = Δx/t.............. Equation 1
Where V = average velocity, Δx = change in position on the x- axis, t = time.
But,
Δx = x₂-x₁........... Equation 2
Substitute equation 2 into equation 1
V = (x₂-x₁)/t................ Equation 3
Given: x₂ = 32.4 m, x₁ = -5 m, t = 8.9 s
Substitute into equation 3
V = [32.4-(-5)]/8.9
V = (32.4+5)/8.9
V = 37.4/8.9
V = 4.157 m/s
Hence the average velocity = 4.157 m/s
Answer:
v = 4.20m/s
Average velocity is 4.20m/s
Explanation:
Average velocity is the change in displacement per unit time;
v = ∆x/t
Given;
∆x = 32.4 - (-5) = 37.4 m
t = 8.9 seconds
Substituting the values;
v = 37.4m/8.9s
v = 4.20m/s
Average velocity is 4.20m/s
What is the angular acceleration if the weight is 24.0 cm from the elbow joint, her forearm has a moment of inertia of 0.240 kg⋅m2, and the net force she exerts is 759 N at an effective perpendicular lever arm of 2.00 cm?
The complete question is;
To develop muscle tone, a woman lifts a 2.00-kg weight held in her hand. She uses her biceps muscle to flex the lower arm through an angle of 60.0º . What is the angular acceleration if the weight is 24.0 cm from the elbow joint, her forearm has a moment of inertia of 0.240 kg.m², and the net force she exerts is 759 N at an effective perpendicular lever arm of 2.00 cm?
Answer:
α = 42.76 rad/s²
Explanation:
We are given;
Mass; m = 2 kg
Distance; r = 24cm = 0.24m
Moment of inertia of the forearm; I = 0.24 kg.m²
Muscle Force; F = 759N
Perpendicular distance to lever arm; r' = 2cm = 0.02m
Angle at which she flexes arm; θ =60°
Let's assume that the arm starts extended vertically downwards. and we take the elbow joint as the point about which we calculate the torque.
Thus, we know that torque is given by the formula ;
τ = Force x Perpendicular distance
Thus, the toque exerted by force in the muscle is;
τ_muscle = 759 x 0.02 = 15.18 N.m
Also, torque exerted by the lifted weight is given as 0 because perpendicular distance is zero.
Thus, the net torque on the lower arm is;
τ_net = τ_muscle - τ_weight
τ_net = 15.18 - 0 = 15.18 N.m
Now, let's calculate moment of inertia of lifted weight.
The moment of inertia is given by;
I = mr²
Thus, moment of Inertia of lifted weight is; I_weight = 2 x 0.24² = 0.115 kg.m²
Thus,total moment of inertia is;
I_total = I_arm + I_weight
Thus, I_total = 0.24 + 0.115 = 0.355 kg.m²
Now, we can calculate the angular acceleration.
It's gotten from the equation;
τ_net = I_total•α
Where α is angular acceleration.
Thus making α the subject, we have ; α = τ_net/I_total
α = 15.18/0.355 = 42.76 rad/s²
Where would you expect to have more touch receptors: on the palm of your hand or on the back of your hand? Explain your reasoning
Explanation:
this is because if your going to touch something dangerouse your hand normally feels it first and its the front not the back so when you pick things up you can tell if its dangerouse hope that helped
The palm of the hand has more touch receptors than the back, due to its glabrous skin type which is thicker and more sensitive. These receptors allow for detection of fine touch and pressure, critical for manual tasks.
Explanation:Considering the density of touch receptors in different parts of our body, you could expect to have more touch receptors on the palm of your hand than on the back of your hand. This is due to the specific type of skin found on the palm, referred to as glabrous skin. This type of skin is typically thicker and more sensitive as compared to hairy skin, hence it contains more touch receptors.
The importance of the high density of touch receptors in areas such as palms and fingertips can be seen in the daily actions, such as the ability to sense fine touch and detailed information, which is necessary for fine motor tasks.
Furthermore, mechanoreceptors such as Merkel's disks, Meissner's corpuscles, Pacinian corpuscles, and Ruffini endings play a vital role in interpreting the touch-related sensory information of these regions. For instance, Merkel's disks and Meissner's corpuscles that are found deeper in the skin and in the upper parts of the skin respectively, detect fine touch. On the other hand, Pacinian corpuscles and Ruffini endings can sense deeper touch like pressure.
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The average intensity of light emerging from a polarizing sheet is 0.708 W/m2, and that of the horizontally polarized light incident on the sheet is 0.960 W/m2. Determine the angle that the transmission axis of the polarizing sheet makes with the horizontal.
Answer:
Angle θ = 30.82°
Explanation:
From Malus’s law, since the intensity of a wave is proportional to its amplitude squared, the intensity I of the transmitted wave is related to the incident wave by; I = I_o cos²θ
where;
I_o is the intensity of the polarized wave before passing through the filter.
In this question,
I is 0.708 W/m²
While I_o is 0.960 W/m²
Thus, plugging in these values into the equation, we have;
0.708 W/m² = 0.960 W/m² •cos²θ
Thus, cos²θ = 0.708 W/m²/0.960 W/m²
cos²θ = 0.7375
Cos θ = √0.7375
Cos θ = 0.8588
θ = Cos^(-1)0.8588
θ = 30.82°
Brainly i can you please help me
Answer:
bet
Explanation:
Two carts were initially at rest and side-by-side between two photogates. The mass of cart 1 was 0.505 kg. A spring was activated forcing the two carts away from one another, passing through the photogates and producing the readings as shown below. Determine the mass of cart 2.
Suppose an object is located in deep space, far away from any gravity. Would a force need to be applied in order to accelerate the object in space, or would there be no need for a force to make it accelerate?
Answer:
Force will be needed to make the object move
Explanation:
An object at rest will stay at rest and an object in motion will stay in motion unless acted on by an unbalaced object.
Is the magnetic field created by a current loop uniform?
The magnetic field produced by a current loop is not uniform. It is strongest at the center of the loop and decreases as you move away from the center. This change in strength across the space surrounding the loop makes it non-uniform.
Explanation:No, the magnetic field created by a current loop is not uniform. A current loop means a closed electrical circuit or a current flowing in a loop of conducting wire. When a current flows through the loop, a magnetic field is generated surrounding the loop. This magnetic field is strongest at the center of the loop and diminishes as you move away from the center. This variance in strength implies that the magnetic field is not uniform.
Example:
If you place a compass around a loop with flowing current, you'd notice that the compass needle's direction (which aligns with the magnetic field) changes as you move the compass around. This indicates that the magnetic field strength (and direction) changes across the space surrounding the current loop, which makes it non-uniform.
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The half-life of caffeine is 5 hours. If you ingested a 30 oz Big Gulp, after how much time will have to pass before you have under 1 oz of caffeine remaining?
Answer:
The time that will have to pass before one has under 1 oz of caffeine remaining is 24.53 hours
Explanation:
Here, we have the formula for half life as follows;
[tex]N(t) = N_0(\frac{1}{2})^{\frac{t}{t_{1/2}}[/tex]
Where:
N(t) = Remaining quantity of the substance = 1 oz
N₀ = Initial quantity of the substance = 30 oz
t = Time duration
[tex]t_{1/2}[/tex] = Half life of the substance = 5 hours
Therefore, plugging in the values, we have
[tex]1= 30(\frac{1}{2})^{\frac{t}{5}}[/tex]
[tex]\frac{1}{30} = (\frac{1}{2})^{\frac{t}{5}}\\ln(\frac{1}{30}) =\frac{t}{5} ln(\frac{1}{2})\\\frac{t}{5} = \frac{ln(\frac{1}{30}) }{ ln(\frac{1}{2})} = 4.91\\ t = 4.91 \times 5 = 24.53 \ hours[/tex]
The time that will have to pass before one has under 1 oz of caffeine remaining = 24.53 hours.
In a parallel circuit, each resistor has:
A: no connection to the voltage source
B: a shared connection to the voltage source
C: its own connection to the voltage source
Answer:
C
Explanation:
Answer:
In a parallel circuit, each resistor has: its own connection to the voltage source.
Explanation:
What is the magnitude of the acceleration a of the chair? What is the magnitude of the normal force fn acting on the chair?
The magnitude of the normal force and acceleration is calculated using Newton's second law and free body diagrams, considering all forces acting on the object.
Explanation:The question pertains to finding the magnitude of the acceleration and the normal force acting on a chair, block, or similar object using Newton's second law of motion. To determine these quantities, one must analyze the forces acting on the object in a free body diagram and apply the equations of motion. The normal force is the force exerted by a surface to support the weight of an object resting on it, and it acts perpendicular to the surface. To find the normal force (FN), we typically assume static equilibrium if the object is at rest, which implies that the net force in the vertical direction is zero; thus, FN equals the object's weight (mg), where m is the mass and g is the acceleration due to gravity. The magnitude of acceleration (a) can be calculated using the net force acting on the object (resultant force) divided by its mass, as stated by Newton's second law (F = ma).
For example, if a block is placed on a table, the normal force is equal to the gravitational force acting on it (FN = Fg). If the block is accelerating, you would calculate the net force by including all forces acting on the block, such as tension, friction, or applied forces, and then use F = ma to find the acceleration.
The 3 stages of the water cycle are
Answer:
Evaporation, condensation, precipitation
Explanation:
Answer:
Evaporation, condensation, precipitation & collection
Explanation:
A cross-country skier is skiing along at a zippy 8.0 mis. She stops pushing and simply glides along, slowing to a reduced speed of 6.0 mis after gliding for 5.0 m. What is the magnitude of her acceleration as she slows
Answer:
Acceleration, a = [tex]2.8\ m/s^2[/tex]
Explanation:
Given that,
Initial speed of the skier, u = 8 m/s
Final speed of the skier, v = 6 m/s
Distance, d = 5 m
We need to find the magnitude of her acceleration. It is equal to the rate of change of speed. It is given by :
[tex]v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2s}\\\\a=\dfrac{6^2-8^2}{2\times 5}\\\\a=-2.8\ m/s^2[/tex]
So, the magnitude of her acceleration is [tex]2.8\ m/s^2[/tex].
The magnitude of the skier's acceleration as she slows down is 0.4 m/s^2.
Explanation:To find the magnitude of the skier's acceleration, we can use the formula:
Acceleration = (Final Velocity - Initial Velocity) / Time
In this case, the initial velocity is 8.0 m/s, the final velocity is 6.0 m/s, and the time is 5.0 seconds.
Plugging these values into the formula, we get:
Acceleration = (6.0 m/s - 8.0 m/s) / 5.0 s = -0.4 m/s^2
So the magnitude of the skier's acceleration as she slows down is 0.4 m/s^2.
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A vertical wire carries a current straight down. What is the direction of magnetic field to the east of this wire?
Explanation:
The direction of magnetic field in a straight wire is given by Maxwell's right hand rule. It states that if the thumb of right hand points towards the direction of electric current, then the curled finger will give the direction of magnetic field.
In this case, a vertical wire carries a current straight down. It means that current will flow in the clockwise direction.
The magnetic field to the east of a vertical wire carrying a current straight down is directed into the page, which is determined by the right-hand rule.
To determine the direction of the magnetic field around a current-carrying wire, we can use the right-hand rule. For a wire that carries a current downward, you would point the thumb of your right hand in the direction of the current (downward), and then your fingers would naturally curl in the direction of the magnetic field. To the east of the wire, your fingers would point into the page, indicating that the magnetic field is directed into the page.