On a particle level, what happens when thermal conduction occurs within a solid?

Answers

Answer 1

Final answer:

Thermal conduction in solids occurs as atoms and molecules rapidly move or vibrate, transferring kinetic energy to neighboring particles, and through movement of electrons, facilitating heat transfer without the mass flow characteristic of convection.

Explanation:

On a particle level, when thermal conduction occurs within a solid, rapidly moving or vibrating atoms and molecules transfer some of their kinetic energy to adjacent particles. This is the principal means for heat transfer within a solid, with the close fixed spatial relationships between atoms in a solid facilitating this transfer by vibration. Heat is also transferred by the movement of electrons from one atom to another. Unlike convection which occurs in fluids, heat transfer by conduction in solids does not involve large-scale flow of matter.

For example, the heat from an electric burner transfers to the bottom of a pan via conduction. The hot surface causes the atoms in the pan to vibrate more energetically, which then collide with neighboring atoms, spreading the heat throughout the pan. Conductive heat transfer efficiency is affected by the temperature difference, size and thickness of the material, as well as its thermal properties.


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Jack (mass 52.0 kg ) is sliding due east with speed 8.00 m/s on the surface of a frozen pond. he collides with jill (mass 49.0 kg ), who is initially at rest. after the collision, jack is traveling at 5.00 m/s in a direction 34.0∘ north of east. ignore friction. part a what is the direction of the jill's velocity after the collision?

Answers

Final answer:

Using the law of conservation of momentum, it is determined that after her collision with Jack, Jill will move in a direction that is south of east.

Explanation:

This problem involves the principle of conservation of momentum. In this case, we have a two-body collision, where Mass1 (Jack, with mass 52kg and initial velocity 8m/s due east) collides with Mass2 (Jill, with mass 49.0kg and initially at rest). After the collision, Jack is traveling at a direction 34.0° north of east (let's call this direction east') with a speed of 5m/s. The initial momentum (Mass1 + Mass2) should be equal to the final momentum if we ignore the friction.

Before the collision, the total momentum was Momentum1 initial = Mass1 x Velocity1 initial = 52kg x 8m/s = 416 kg m/s, all in an eastward direction. Momentum2 initial = 0, as Jill was at rest.

After the collision, the final momentum of Jack becomes Momentum1 final = Mass1 x Velocity1 final = 52kg x 5m/s = 260 kg m/s, directed 34° north of east.

According to the law of conservation of momentum, the total initial momentum must equal the total final momentum. Hence, the final momentum of Jill will be Momentum2 final = Momentum1 initial - Momentum1 final = 156 kg m/s. This quantity only gives us the magnitude of the momentum, but we can calculate the direction based on Jack’s final direction. Given that momentum is a vector quantity, the principle of vector composition lets us infer that Jill’s final direction must be south of east to balance the north-of-east component of Jack's final momentum.


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What is the maximum velocity for the pacific plate?

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Calculating the Velocity of the Pacific Plate. Standard 3.5: 

"why might a good electrical conductor also be a good thermal conductor"

Answers

A good electrical conductor is a material that has a lot of free charges that can easily move across the material, and with a large mean free path.

Now let's assume that one side of the material is at higher temperature than the other side. The charges on the hotter side move faster than the charges on the cooler side, so the faster charges transfer part of their energy to the charges of the cooler side by collisions. The larger the number of free charges (and the larger their mean free path), the faster is this transmission of energy (which is basically transmission of heat), so the larger is the thermal conductivity of the material, so a good electrical conductor is generally also a good thermal conductor.

A block of mass m1 = 3.5 kg moves with velocity v1 = 6.3 m/s on a frictionless surface. it collides with block of mass m2 = 1.7 kg which is initially stationary. the blocks stick together and encounter a rough surface. the blocks eventually come to a stop after traveling a distance d = 1.85 m . what is the coefficient of kinetic friction on the rough surface? μk =

Answers

Final answer:

The calculation involves combining the masses after collision, calculating the final velocity using the law of conservation of momentum and then finding the frictional work done. Using the work-energy theorem, we can solve for the coefficient of kinetic friction.

Explanation:

The question is asking to find the coefficient of kinetic friction on the rough surface where two blocks m1 and m2 have collided and eventually come to a stop after traveling a certain distance. We first need to combine the mass of both blocks as they stick together and this results in a total mass (m1 + m2 = 3.5 kg + 1.7 kg = 5.2 kg). After collision, we can use the law of conservation of momentum to calculate the final velocity when both blocks stick together (m1*v1 + m2*v2 = (m1 + m2) * v_final).

Substituting known values (3.5 kg * 6.3 m/s + 1.7 kg * 0 m/s = 5.2 kg * v_final), we get v_final = 4.425 m/s.

Now, to find the coefficient of kinetic friction, we will use the equation of work-energy theorem where Workdone by friction = Change in kinetic energy. The work done by frictional force is equal to the force of friction multiplied by the distance, and force of friction equals the coefficient of kinetic friction times the normal force (which is mass times gravity in this case).

Thus, the equation would be: μk * m1 * g * d = ½ * m1 * v1^2 (since the final velocity is zero). Substituting the known values into this equation, we can solve to find the coefficient μk.

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If r1 < r2 < r3, and if these resistors are connected in series in a circuit, which one dissipates the most power

Answers

All three have the same current, so that is not a factor. Wattage (power) is E*I or i^2 R. The higher the resistance, the more power dissipated. The answer is R3 because it has the highest resistance.
R3 <<<< ===== answer.

One side of the moon always faces Earth because the time it takes the moon to spin on its axis is blank the time it takes the moon to travel around Earth.

Answers

The word to fill in the blank is "equal". Because the time taken to rotate (spin on its axis) is equal to the time of revolution (going around the earth), this means that both have the same rate of angular rotation. So for every bit that the moon goes around its orbit around earth, the moon itself rotates accordingly to present the exact same side to earth.

Answer: One side of the moon always faces Earth because the time it takes the moon to spin on its axis is "the same as" the time it takes the moon to travel around Earth.

In terms of the torque needed to rotate your leg as you run, would it be better to have a long calf and short thigh or vice versa? a) Long calf, short thigh b) Short calf, long thigh c) Does not matter

Answers

Final answer:

Having a short calf and long thigh would result in better torque for leg rotation during running, as a longer lever arm (thigh) from the pivot point (knee) allows for greater torque. However, proportions should be balanced for optimal running biomechanics.

Explanation:

In terms of the torque needed to rotate your leg as you run, it would be better to have a short calf and long thigh. This is because torque is the rotational equivalent of force and is calculated by multiplying the force by the distance from the pivot point. In this case, the pivot point is the knee.

Therefore, a longer thigh would result in a greater torque because the force (muscle contraction) is applied further from the pivot point (knee). Conversely, a short calf means less mass is being rotated around the pivot point, reducing the torque needed for movement.

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In terms of the torque needed to rotate your leg as you run, it be better to have b) Short calf, long thigh

In terms of the torque needed to rotate your leg as you run, it would be better to have a short calf and long thigh.

This is because torque is the rotational equivalent of force, and it depends on both the magnitude of the force and the distance from the pivot point where the force is applied. In running, the longer the distance from the pivot point (knee), the more torque is generated by the same muscle force. A long thigh and short calf combination helps in maximizing this distance, thereby reducing the effort required to achieve the same angular acceleration of the leg.

Let's break this down step-by-step:

Torque (τ) is defined as τ = r × F, where r is the distance from the pivot point (in this case, the knee) and F is the force applied by the muscles.For a given force, increasing the distance r will increase the torque, making it easier to rotate the leg.A long thigh means a greater r from the hip pivot point, increasing the torque generated for the same muscle effort.A short calf means less weight and less moment of inertia that needs to be rotated, making the rotation more efficient.

A proton beam in an accelerator carries a current of 106 μa. if the beam is incident on a target, how many protons strike the target in a period of 17.0 s?

Answers

The electric current is defined as the charge Q that passes a certain point in a time [tex]\Delta t[/tex]:
[tex]I= \frac{Q}{\Delta t} [/tex]
We know the current, [tex]I=106 \mu A=106 \cdot 10^{-6} A[/tex], and the time, [tex]\Delta t=17.0 s[/tex], so the total charge that strikes the target during this time is
[tex]Q=I \Delta t=(106 \cdot 10^{-6}A)(17.0s)=1.8 \cdot 10^{-3}C[/tex]

To find the number of proton, we must divide the total charge by the charge of a single proton, which is [tex]q=1.6 \cdot 10^{-19}C[/tex]:
[tex]N= \frac{Q}{q}= \frac{1.8 \cdot 10^{-3}C}{1.6 \cdot 10^{-19}C}=1.13 \cdot 10^{16} [/tex]
And this is the number of protons that strike the target in 17.0 s.

500 ml of four different liquids are heated to 50oC. According to the specific heat data, which liquid will cool to 35oC in the shortest amount of time?

Answers

That would be Gasoline.

Answer:C) gasoline

Explanation:

Specific heat is the measure of the heat energy required to increase or decrease the temperature of a substance by a certain temperature interval. Gasoline has the lowest specific heat; that means it takes less energy to lower or raise the temperature of gasoline compared to the other three liquids.

If it takes 6.02 kj of heat energy to melt a mole of ice, how much heat is absorbed when 6.30 g of water melts? 21.0 j 2.10 kj 21 kj 0.210 kj

Answers

First, let's see how many moles correspond to 6.30 g of water.
The molar weight of water is 18.01 g/mol, so
[tex]n= \frac{6.30 g}{18.01 g/mol}=0.35 mol [/tex]
Then we know it takes 6.02 kJ to melt 1 mole of ice, so if we have 0.35 mol, the amount of heat needed will be
[tex]Q=6.02 kJ \cdot 0.35 mol=2.10 kJ[/tex]

HELP PLEASE!! ASAP
Which accurately compares concave and convex lenses?
A. With both concave and convex lenses, the characteristics of the image do not depend on the placement of the object.
B. With both concave and convex lenses, the characteristics of the image depend on the placement of the object.
C. With concave lenses, the characteristics of the image do not depend on the placement of the object, but with convex lenses, they do.
D. With convex lenses, the characteristics of the image do not depend on the placement of the object, but with concave lenses, they do.

Answers

The correct answer is B) With both concave and convex lenses, the characteristics of the image depend on the placement of the object.
We can have a look at the lens equation:
[tex] \frac{1}{f} = \frac{1}{d_o}+ \frac{1}{d_i} [/tex]
where f is the focal length of the lens, [tex]d_o[/tex] the distance of the object from the lens and [tex]d_i[/tex] is the  distance of the image from the lens. As it can be seen from the formula, the distance of the image depends on [tex]d_o[/tex], the placement of the object.

The same is true for the magnification, i.e. the size of the image ([tex]h_i[/tex]) compared to the size of the object ([tex]h_o[/tex]), which is given by
[tex]M= \frac{h_i}{h_o} - \frac{d_i}{d_o} [/tex]
As it can be seen, this quantity depends on the placement of the object as well.

With concave lenses, the characteristics of the image do not depend on the placement of the object, but with convex lenses, they do.

Which of the following correctly describes the first animals that appeared?
A.) these were large creatures, similar to dinosaurs
B.) these were bony creatures that lived only in wet environments
C.) these were soft and boneless creatures
D.) these were large creatures that lived only in dry environments

Answers

A.) These were large creatures, similar to dinosaurs.

Using a crowbar, a person can remove a nail by exerting little force, whereas pulling directly on the nail requires a large force to remove it (you probably can't). why?

Answers

Here we deal with a lever law. It states that product of force and distance from a fixed point on a lever is equal on both sides.

F₁*d₁ = F₂*d₂

By analysing this formula we can see that applying small force on a great length equals great force on a small length.
To remove nail we need to apply certain force. If we use F₁ for this required force we can see that on other side we need to apply certain force. If we have greater arm length we need smaller force. In a crowbar arm length along which we apply force is greater than length of our arm. This leads to a conclusion that we need smaller force when using crowbar. Depending on the length of a nail it is possible that we need to apply force that is greater than force required to remove nail.

Final answer:

Using a crowbar to remove a nail requires less force because it uses leverage to amplify the input force and increase the mechanical advantage.

Explanation:

When using a crowbar to remove a nail, you are using a lever with a large mechanical advantage. The input force you apply to the crowbar is much smaller than the force exerted by the crowbar on the nail. This is because the length of the crowbar provides a greater lever arm, which increases the mechanical advantage.

On the other hand, when you try to pull directly on the nail, you don't have the same leverage as the crowbar, so you need to exert a larger force to overcome the resistance of the nail.

In summary, the crowbar allows you to remove a nail with less force because it uses leverage to amplify the input force and increase the mechanical advantage.

When a guitar string plays the note "a," the string vibrates at 440 hz ?

Answers

Answer:

440hz

Explanation: Guitars do in fact play at 440 herts for the note a

A piano tuner stretches a steel piano wire with a tension of 765 n. the steel wire has a length of 0.700 m and a mass of 5.25 g . part a what is the frequency f1 of the string's fundamental mode of vibration?

Answers

We will use Mersenne's law that states:
[tex]f=\frac{1}{2L}\sqrt{\frac{T}{\mu}[/tex]
Where f is fundamental frequency, T is the tension, [tex]\mu[/tex] is linear density(mass divided by length) and L is the length of the string. 
Let us find the linear density:
[tex]\mu=\frac{m}{L}=\frac{5.25}{0.7\cdot1000}=0.0075\frac{kg}{m}[/tex]
Now we just have to plug in all the number in the formula:
[tex]f=\frac{1}{2L}\sqrt{\frac{T}{\mu}}=\frac{1}{2\cdot 0.7}\sqrt{\frac{765}{0.0075}}=228.12$Hz[/tex]
Final answer:

The fundamental frequency of the steel piano wire, subjected to a tension of 765 N, with a length of 0.700 m, and a mass of 5.25 g, is approximately 424.6 Hz.

Explanation:

The frequency f1 of the string's fundamental mode of vibration can be calculated using the formula f = sqrt(T / μ) / 2L. Here:

T is the tension in the string, which is 765 Nμ is the linear density of the string, which is the mass of the string divided by its length. Therefore, μ = (5.25 g) / (0.700 m) = 0.0075 kg/mL is the length of the string, which is 0.700 m

Plugging these values into the formula, we get:
f1 = sqrt((765 N) / (0.0075 kg/m)) / (2 * 0.700 m) = 424.6 Hz

This means that the fundamental frequency of the string is roughly 424.6 Hz.

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Dr. Lao has discovered a substance that emits energy in the form of waves. If Dr. Lao observes that these waves can travel through a perfect vacuum, then

Answers

The waves are electromagnetic waves. 
That is the mostly likely answer.

Answer: The waves that travel through vacuum is electromagnetic waves.

Explanation:

There are two types of waves:

Mechanical waves: These are the waves that need a medium to travel so that they can transport their energy from one location to another. For Example:  Sound waves

Electromagnetic waves: These are waves which can travel through vacuum. These have electrical and magnetic component associated with them. They travel with the speed of light. They does not require a medium to travel. For Example: Infrared waves, Microwaves

Hence, the waves that travel through vacuum is electromagnetic waves.

A charge of 7.2 × 10-5 C is placed in an electric field with a strength of 4.8 × 105. If the electric potential energy of the charge is 75 J, what is the distance between the charge and the source of the electric field? Round your answer to the nearest tenth.

Answers

The answer is 2.2 meters.                          

The distance between the charge and the source of the electric field is 2.2 m.

The potential energy U of a charge q placed in an electric field created by a source charge Q, at a distance r from the source charge is given by,

[tex] U=\frac{kQq}{r} [/tex] ...... (1)

Here, k is the Coulomb constant.

The electric field E at a distance r from the source charge is given by,

[tex] E =\frac{kQ}{r^2} [/tex] ......(2)

From equations (1) and (2)

[tex] U=E*q*r [/tex]

Rewrite the expression for ri.

[tex] r=\frac{U}{Eq} [/tex]

Substitute 75 J for U, [tex] 4.5*10^5 V/m [/tex] for E and [tex] 7.5*10^{-5} C [/tex] for q.

[tex] r=\frac{U}{Eq} \\ =\frac{75 J}{(4.8*10^{5} V/m)(7.2*10^{-5}C)} \\ =2.17 m [/tex]

Rounding off to the nearest tenth, the the distance between the charge and the source charge is 2.2 m

why were you able to see the effects of the magnetic fields using iron filings

Answers

The iron filings aligned themselves in a pattern, along with the magnet connecting the north and south poles. This creates the “magnetic field”. Interacting with a metal object in between the magnetic properties of the metal interact with the magnet, expressing signs of magnetic force acting on it and the metal, pulled together letting you see the see the effects of the magnetic fields using iron filings. 
Iron filing are soft magnetic materials. The are highly attracted by magnets. 
They are used in the study of magnetic fields.
Another reason why they are used because they are light and and they can aline themselves in the paths of the magnetic fields. This way the fields patterns can be seen clearly.

Chanel has some cotton candy that came in a cloudy shape. She wants to make it more dense. Which describes the candy before and after Chanel manipulated it?
1)The candy before was a cube, and the candy after was a ball.
2)The candy before was compacted, and the candy after was fluffy.
3)The candy before was fluffy, and the candy after was compacted.
4)The candy before was a ball, and the candy after was a cube.

Answers

Answer: Option (C) is the correct answer.

Explanation:

As we known that density is the amount of mass divided by volume of the substance.

Mathematically,    Density = [tex]\frac{mass}{volume}[/tex]

So, when candy was present in the shape of a cloud then it means that it was fluffy as it has more volume.

Since, density is inversely proportional to volume therefore, with increase in volume there will occur a decrease in density.

But when the candy will become compact then there will occur a decrease in its volume. Hence, then there will occur an increase in the density of the candy.

Thus, we can conclude that the statement candy before was fluffy, and the candy after was compacted best describes the candy before and after Chanel manipulated it.

A mass of 15 kg of air in a piston-cylinder device is heated from 25 to 77°c by passing current through a resis tance heater inside the cylinder. the pressure inside the cylin der is held constant at 300 kpa during the process, and a heat loss of 60 kj occurs. determine the electric energy supplied, in kwh

Answers

A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
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How much work does an elevator motor do to lift a 1200-kg elevator car a height of 80 m at constant speed?

Answers

The increase in gravitational potential energy of the elevator car when is lifted to a height of 80 m is given by
[tex]\Delta U=mg \Delta h[/tex]
where m=1200 kg is the mass of the elevator car, [tex]g=9.81 m/s^2[/tex] is the gravitational acceleration, and [tex] \Delta h=80 m[/tex] is the variation of height of the elevator car. If we plug these numbers into the equation, we find:
[tex]\Delta U=(1200 kg)(9.81 m/s^2)(80 m)=9.42 \cdot 10^5 J[/tex]

For the work-energy theorem, the work done by the motor to lift the elevator must be equal to the energy acquired by the elevator car: but the energy acquired by the elevator car is [tex]9.42 \cdot 10^5 J[/tex], therefore the work done by the motor is exactly equal to this value:
[tex]W=\Delta U=9.42 \cdot 10^5 J[/tex]

Answer:

Work = 940800 J

Explanation:

As we know that work done is defined as

Work = (Force)(displacement in the direction of force)

here elevator motor lift a mass of 1200 kg

so in order to lift it up motor must have to apply the force same as the weight so that it will move up with constant speed.

so here we have

[tex]F = mg[/tex]

[tex]F = (1200 kg)(9.8 m/s^2)[/tex]

[tex]F = 11760 N[/tex]

now it is displaced upwards by distance d = 80 m

so here we have

[tex]W = (11760)\times (80)[/tex]

[tex]W = 940800 J[/tex]

so above is the work done by the elevator to lift it upwards

Two appliances are connected in parallel to a 120-v battery and draw currents i1 = 3.0 a and i2 = 3.1
a. if these appliances are instead connected in series to the same battery, what is the total current in the circuit?

Answers

Initially they are connected in parallel, so they have the same voltage V=120 V at their ends. Therefore we can use Ohm's law to calculate the resistance of each appliance:
[tex]R_1 = \frac{V}{I_1}= \frac{120 V}{3.0 A}=40 \Omega [/tex]
[tex]R_2 = \frac{V}{I_2}= \frac{120 V}{3.1 A}=38.7 \Omega [/tex]

When they are connected in series, they are crossed by the same current I. The equivalent resistance of the circuit in this case is [tex]R_{eq}=R_1+R_2 = 78.7 \Omega[/tex], so we can use Ohm's law for the entire circuit to find the current in the circuit:
[tex]I= \frac{V}{R_{eq}}= \frac{120 V}{78.7 \Omega}=1.52 A [/tex]

An experiment that produces waves on a string is analyzed, and the experimental value for the wave speed is found to be 66 m/s. If the accepted value for the wave speed is 63 m/s, what is the percent error? 0.045% 0.048% 4.5% 4.8%

Answers

4.8 is the correct answer

Answer:

4.8%

Explanation:

percentage error can be calculated as the difference between the theoretical and experimental value divided by the experimental value expressed in percentage.

The percentage error can be  computed mathematically as

(accepted value - experimental value)/accepted value × 100

accepted value = 63 m/s

experimental value = 66 m/s

difference = 63 - 66 = -3 m/s

use the absolute value = 3 m/s

percentage error = (accepted value - experimental value)/accepted value × 100

percentage error = 3/63 × 100

percentage error = 300/63

percentage error = 4.76%

percentage error = 4.8%

Brass is an alloy of copper and zinc the two metals are melted mixed and then solidified how would you best classify brass

Answers

Hello!

Brass is a Homogeneous mixture.

Homogeneous mixtures are those in which the components are in the same proportions in all the sample. In brass, as the two metals are fused together to form an alloy, the composition is the same in the entire piece. Brass is also called a Solid Solution. Brass is not a pure substance because it has two different elements in its composition.

Have a nice day!

Brass can be classified as  [tex]\boxed{{\text{a}}{\text{. homogenous mixture and a solid solution}}}[/tex].

Further explanation:

Alloy:

An alloy is defined as combination of metals or a combination of one or more metals with non-metals. Alloys have a large range of applications, ranging from surgical tools, aerospace industry to automobile construction. Steel, solder, brass, pewter, bronze, and amalgams are some examples of alloys. Alloys can be either solid solution or a mixture of metallic phases.

Mixture:

The material that is made up of two or more substances is called a mixture. It has no fixed formula, and its composition is also varied. All the individual constituents retain their properties after the formation of the mixture.

Types of mixtures:

1. Homogeneous mixtures

Homogeneous is a Latin word that means the same. These mixtures have a uniform composition throughout. Air, orange juice, and blood are the examples of a homogenous mixture.

2. Heterogeneous mixtures

Heterogeneous is a Latin word that means different. These mixtures that have non-uniform composition throughout. Concrete, soda, and chocolate chip cookies are the examples of a heterogeneous mixture.

Characteristics of mixtures:

1. It has a variable composition and has no formula.

2. Mixtures are not formed by any chemical reactions.

3. Mixtures can be either homogeneous or heterogeneous.

4. The constituents of the mixtures can be separated by physical methods such as filtration, heating, drying, distillation, crystallization.

5. The properties of the individual particles of the mixture are retained even after the formation of mixtures.

Copper and zinc are the two metals that are first melted, mixed and then solidified to form brass. Their composition is the same throughout the whole part of brass. So brass is an example of homogeneous mixture. It is also known as solid solution where zinc acts as solute and copper is a solvent.

Learn more:

1. The major contribution of Antoine Lavoisier to chemistry: https://brainly.com/question/2500879

2. Example of physical change: https://brainly.com/question/1119909

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Mixture

Keywords: mixture, characteristics, formula, composition, properties, chemical reactions, filtration, distillation, heating, crystallization, homogeneous, heterogeneous, brass, alloy, metals, non-metals, aerospace industry, automobile construction, surgical tools, solid solution, zinc and copper.

A cylinder with a moveable piston contains 219 ml of nitrogen gas at a pressure of 1.23 atm and a temperature of 295 k . part a what must the final volume be for the pressure of the gas to be 1.53 atm atm at a temperature of 337 k ?

Answers

Final answer:

The final volume needed for the pressure of the nitrogen gas to be 1.53 atm at a temperature of 337 K is approximately 190.8 ml. This is calculated using the combined gas law.

Explanation:

To find out what the final volume of nitrogen gas in the cylinder would be when the pressure is 1.53 atm and the temperature is 337 K, we can use the combined gas law, which is derived from the ideal gas law. The combined gas law states that the ratio of the product of pressure and volume to temperature remains constant for a fixed amount of gas when the temperature is measured in Kelvin. The formula for the combined gas law is (P1 * V1) / T1 = (P2 * V2) / T2, where P is pressure, V is volume, and T is temperature.

Given that:

Initial pressure (P1) = 1.23 atmInitial volume (V1) = 219 mlInitial temperature (T1) = 295 KFinal pressure (P2) = 1.53 atmFinal temperature (T2) = 337 K

We want to find the final volume (V2), so rearranging the equation to solve for V2 gives us:

V2 = (P1 * V1 * T2) / (P2 * T1)

Substituting the known values:

V2 = (1.23 atm * 219 ml * 337 K) / (1.53 atm * 295 K)

By performing the calculations:

V2 ≈ 190.8 ml

Therefore, the final volume needed for the pressure of the nitrogen gas to be 1.53 atm at 337 K is approximately 190.8 ml.

Suppose you charge a 1.0 f capacitor with two 1.5 volt batteries. how much charge was on each plate?

Answers

The charge on each plate of the capacitor is given by:
[tex]Q=C \Delta V[/tex]
where C is the capacitance of the capacitor, while [tex]\Delta V[/tex] is the potential difference applied on the two plates. Since we are using two batteries of 1.5 V, the total voltage applied is (assuming the two batteries are in series) 1.5 V+1.5 V= 3.0 V. Therefore, the charge on each plate is
[tex]Q=(1.0 F)(3.0 V)=3.0 C[/tex]

If you charge a 1.0 f capacitor with two 1.5 volt batteries, the amount of charge on each of the plates is 3colombs

The formula for calculating the charge on a capacitor is expressed as:

[tex]Q = C \triangle v[/tex]

C is the capacitance of the capacitor in farads

Δv is the change in the potential difference

Given the following parameters

C = 1.0F

For a two 1.5V batteries, v = 2(1.5) = 3V

Substitute the given parameters into the formula as shown:

[tex]Q = 1.0 \times 2(1.5)\\Q=1 \times 3.0\\Q =3Coulumbs[/tex]

Hence the amount of charge on each of the plates is 3colombs.

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What was the speed of the cannon ball if the spring compressed 58 cm when the cannon was fired?

Answers

I attached the full question.
We need to write down the law of conservation of momentum and energy.
The law of conservation of momentum:
[tex]m_cv_c=m_bv_b[/tex]
The law of conservation of energy:
[tex]\frac{1}{2}x^2=\frac{m_c v_c^2}{2}[/tex]
This tells us that potential energy of the compressed spring is used to stop the canon. In other words, the kinetic energy of the canon, after firing is used to do work again the force of the spring.
We can use this two equations to find the velocity of the cannonball:
[tex]\frac{1}{2}x^2=\frac{m_c v_c^2}{2}\\ v_c=\sqrt{\frac{1}{m_c}}}\cdot x[/tex]
We can now plug this in the first equation:
[tex]m_cv_c=m_bv_b\\ v_c=\sqrt{\frac{1}{m_c}}}\cdot x\\ m_c\cdot\sqrt{\frac{1}{m_c}}}\cdot x=m_bv_b\\ \sqrt{m_c}}}\cdot x=m_bv_b\\ v_b=\frac{\sqrt{m_c}x}{m_b}[/tex]
Please note that I found this question online with multiple diferent data( mass of the canon, ball etc)
You can use this formula, just plug in your numbers and you will get the correct answer.



To calculate the speed of a cannon ball using the distance the spring compressed, the spring constant is required to use energy conservation principles. Without this value, it is not possible to provide an exact answer.

To determine the speed of the cannon ball given that the spring compressed 58 cm when it was fired, we would use the conservation of energy principle where the potential energy stored in the spring is converted into the kinetic energy of the cannon ball. If we had the spring constant (k), we could use the formula for the potential energy stored in a spring, which is PE_spring = (1/2)kx² where x is the compression distance, and equate this to the kinetic energy formula KE = (1/2)mv², where m is the mass of the cannon ball, and v is the velocity we want to find. Without the specific spring constant, it is not possible to calculate the exact speed of the cannon ball.

Which stage of star development comes right after the long stable phase in the life cycle? A. Nova B. Red giant C. Red dwarf D. White dwarf

Answers

The answer is B. Red Giant. This comes after the main sequence phase which is stable phase where the star is at the point where continuous conversion of hydrogen to helium, once consumed it turns into red giant.

Which of the following occurs over a resistor in a circuit? Current is dissipated. Voltage is dropped. Charge is stored. Electrical energy is stored.

Answers

The correct answer is "Voltage is dropped".

In fact, when a current I flows through a resistor of resistance R, the voltage difference between the two ends of the resistor is (Ohm's law):
[tex]\Delta V = RI[/tex]
This product is different from zero, so there is a difference of voltage between the two ends of the resistor, and so there is a voltage drop across the resistor.

In a circuit, a voltage drop occurs over a resistor as the electric current flows through it, transforming electrical energy into heat due to resistance, not storing charge or electrical energy. the correct answer is voltage is dropped.

Among the choices provided for what occurs over a resistor in a circuit, the correct answer is voltage is dropped. When electric current flows through a resistor, it encounters resistance which impedes the flow of charge. This results in a voltage drop across the resistor. The energy that the charges lose as they pass through the resistor is dissipated mainly in the form of heat. This concept is reflected in the equation for electric power dissipation, P = IV, where P represents power, I is current, and V is voltage. This can also be expressed as P = I²R or P = V²/R using Ohm's law, where R is the resistance. Contrary to some of the other choices, resistors do not store charge or electrical energy; that function is typically carried out by capacitors in a circuit.

An unmanned spacecraft leaves for Venus. Which statements about the spacecrafts journey are true?

A)The weight of the spacecraft keeps changing.
B)The mass of the spacecraft keeps changing
C)The weight of the spacecraft remains the same
D) The mass of the spacecraft remains the same
E)The gravotational pull on the spacecraft remains the same
Hint: There is more than one answer

Answers

Answer:

A)The weight of the spacecraft keeps changing.

D) The mass of the spacecraft remains the same

Explanation:

As we know that the acceleration due to gravity depends on the height from the surface

As we know that the force due to gravity on objects near the surface is given as

[tex]F = \frac{Gm_1m_2}{(R+h)^2}[/tex]

here we know that

R = radius of planet

h = height from the surface of planet

So as we move away at more height the gravitational attraction force will keep on decreasing.

This gravitational attraction force of planet is also known as weight so we can say that the weight of the object will keep on changing while object move away.

Also we know that mass of object is quantity of the matter which always remains constant.

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