One angle is eight times it’s supplement increased by 45 degrees. What is the measures of the two supplementary angles?

Answers

Answer 1
Angle 1 = 8x + 45
Angle 2 = x

x + 8x  + 45 = 180
combine like terms

9x + 45 = 180
subtract 45 from both sides

9x = 135
divide both sides by 9 to isolate x

x = 15

Angle 1 = 8(15) + 45 = 165 degrees
Angle 2 = 15 degrees

Related Questions

Add the opposite number of 1 1/5 to the sum of the numbers (−8 3/4 ) and (−2 5/6 ).

Answers

(-8 3/4) +(-2 5/6) +(-1 1/5)
= -((8 +2 +1) +(45/60 +50/60 +12/60))
= -(11 +107/60)
= -(12 47/60)

= -12 47/60

PLEASE HELP IM SO CONFUSED BY THIS
If the measure of angle ACB = 30 and the measure of angle A = 80, find the measure of angle B
A: 60
B: 110
C: 180
D: 70

Answers

In a triangle, the three interior angles always add to 180°

m∠B = 180 - 30 - 80 = 70°

D: 70

If the measure of angle ACB = 30 and the measure of angle A = 80, the measure of angle B is 70 degrees.

What is the angle sum property?

The angle sum property of a triangle states that the sum of the interior angles of a triangle is 180 degrees.

If the measure of angle ACB = 30 and the measure of angle A = 80, To find the measure of angle B

We know that the angle sum property of a triangle states that the sum of the interior angles of a triangle is 180 degrees.

∠ACB + ∠A + ∠B = 180

30 + 80 + ∠B = 180

∠B = 180 - 110

∠B = 70

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Two forces with magnitudes of 25 and 30 pounds act on an object at angles of 10° and 100°, respectively. Find the direction and magnitude of the resultant force. Round to two decimal places in all intermediate steps and in your final answer.

Answers

The direction and magnitude can be found by summing the x- and y-components of each force.
It is best presented in the form of a table, where
x-component = Fcos(theta)
y-component = Fsin(theta)
For F=25 pounds, angle = 30
25cos(30)=21.65

Force  angle     x-component          y-component
25       30         25cos(30)=21.65    25sin(30)=12.5
30       100       30cos(100)=-5.21   30sin(100)=29.54
Total                Fx=16.44                 Fy=42.04
Therefore angle = tan^(-1)(Fy/Fx)=tan^(-1)(42.04/16.44) = 68.64 °
magnitude = sqrt(Fx^2+Fy^2)=sqrt(16.44^2+42.04^2)=45.15 pounds

Lita,Kala, and Rose entered a typing competition. Lita typed 2 times as fast as Kala. The ratio of the number of words Kala typed to the number of words Rose typed was 4:1. If Rose typed 48 words, how many words did Lita type?

Answers

If the ratio from Kala to Rose is 4:1, then for the 48 words Rose typed Kala typed 192 words. 48*4=192
Then Lita types twice as fast so 192*2=384.
It should be 384 words.

jeffery wei received a 6 year non subsidized student loan of 30000 at an annual interest rate of 5.2%. what are jeffery’s monthly loan payments for this loan after he graduates in 4 years

Answers

Final answer:

Jeffery's monthly loan payments for the loan will be $515.19.

Explanation:

To calculate the monthly loan payments for Jeffrey, we can use the formula for calculating the monthly payment of a loan. The formula is:

Monthly Payment = (Principal * Monthly Interest rate) / (1 - (1 + Monthly Interest rate) ^ (-n))

In this case, Jeffrey's principal is $30,000, the annual interest rate is 5.2%, and the loan term is 6 years. Since Jeffrey will graduate in 4 years, we need to adjust the loan term accordingly. The monthly interest rate can be calculated by dividing the annual interest rate by 12, and the number of monthly payments will be multiplied by 4.

Using these values in the formula, we can calculate the monthly loan payment for Jeffrey.

Monthly Payment = (30000 * 0.052/12) / (1 - (1 + 0.052/12) ^ (-24))

Monthly Payment = $515.19

The IRS has a group of 45 tax returns, 15 of which contain errors. An IRS auditor randomly selects 3 tax returns from this group. What is the probability the auditor selects none of those containing errors? Round to four decimal places.

Answers

Out of 45, there are 45-15=30 that do not contain errors.

If the auditor randomly selects 3 returns, without replacement, then
P(1)=30/45,
for the second one, there will be 29 correct returns out of 44, so
P(2)=29/44
Similarly,
P(3)=28/43
Therefore, by the multiplication rule, the probability of selecting 3 correct returns is the product
P(1)*P(2)*P(3)=30*29*28/(45*44*43)=406/1419

Answeeeeeerrrrr

0.2861

Sophia and Charlie brought potato salad to the company cookout. Sophia brought 2 quarts and Charlie brought 4 pints. How many TOTAL cups of potato salad did Sophia and Charlie bring together? (1 quart = 4 cups; 1 pint = 2 cups) A) 8 cups B) 10 cups C) 16 cups D) 20 cups

Answers

2 times 4 is 8, and 4 times 2 is 8. Add them together to get C)16 cups.
It is C. I hoped this helped:)

determine the area of a 21ft circle

Answers

A = (π/4)*d^2
.. = (π/4)*(21 ft)^2
.. = 110.25π ft^2
.. ≈ 346.36 ft^2

When 1 is added to the difference between seven times a number and 9, the result is greater than 10 added to 6 times the number. Find all such numbers.

Answers

10x6x9? Or simplify this question for me I'll figure out.

The region r is bounded by the parabola y = x2 and the line y = 4. set up definite integrals to find the moment mx of r about the x-axis and the area a of the region r. then find (x, y )

Answers

Consider this option:
Volume is 256π/5, area is 32/3.
Details are in the attachment.
P.S. intersection points are (-2;4) and (2;4).

At noon, ship a is 60 km west of ship
b. ship a is sailing south at 15 km/h and ship b is sailing north at 5 km/h. how fast is the distance between the ships changing at 4:00 pm?

Answers

dA/dt=15 km/h and dB/dt=5 km/h
base of our triangle if drawn is 60 km
to find dD/dt when t=4 hours we shall have:

(A+B)²+60²=D²
d/dt[(A+B)²+60²]=d/dt(D²)
[d(A+B)]/dt*2(A+B)(2)=dD/dt*2D
B=5km/h*4hr=20km
A=15km/hr*4=60km
20²+60²=D²
D=√4000

(15+5)*(2)*80*(2)=2*√4000*dD/dt
dD/dt=6400/√4000=101.192 km/hr

The two ships are sailing in opposite sides, Hence, the resultant speed is given by 15+5 = 20 km/hr.

Therefore, from the below triangle, we have

[tex]\frac{dx}{dt} = 20 \text{  km/hr}[/tex]

Let the distance between the ships is y. On applying Pythagorous theorem, we have

[tex]y^2=x^2+60^2\\ \text{On differentiating, we get}\\ 2y\frac{dy}{dt} =2x\frac{dx}{dt}\\\frac{dy}{dt}= \frac{x}{y} \frac{dx}{dt}[/tex]

On substituting the value of y as [tex]y=\sqrt{60^2+x^2}[/tex]

[tex]\frac{dy}{dt} =\frac{x}{\sqrt{60^2+x^2}} \frac{dx}{dt}[/tex]

Since, the at noon the ship is 60 km to each other. Hence, for 4 PM, i.e. t=4, we have

[tex]x=4 \times \frac{dx}{dt} \\ x= 4 \times 20 \\x=80[/tex]

On substituting the value in above, we get

[tex]\frac{dy}{dt} =\frac{80}{\sqrt{60^2+80^2}} (20[/tex]

[tex]\frac{dy}{dt} = 16.0 \text{ km/hr}[/tex]

Therefore,  the distance between the ships changing at a rate of 16 km/hr at 4:00 pm

53b−7b−6b+1 if b=25
Please help me with this problem! And what is the simplified expression?

Answers

Answer: 1001

B/c i said so

Paul needs 40 pounds of 48% silver alloy to finish a collection of jewelry. How many pounds each of 45% silver alloy and 60% silver alloy should he melt together to obtain the alloy he needs

Answers

Equation:
silver + silver = silver
0.45x + 0.60(40-x) = 0.48*40
----------------
45x + 60*40 - 60x = 48*40

--------
-15x = -12*40
x = (4/5)40
x = 32 lbs (amt of 45% slloy needed)
40-x = 8 lbs (amt of 60% alloy needed)

A prism with a base area of 3m^2 and a height of 4m^2 is dilated by a factor of 3/2 what is the volume of the dilated prism

Answers

72 because 12times 4 is 48  then 3/2 times 48 and that is 144/2 then divide it and 72

a parallelogram has an area of 108 square inches. The base of the parallelogram is 18 inches. Explain how you could find the height of the parallelogram, then find the height. Show your work.

Answers

Because the formula for finding the area of a parallelogram is base times height, you can divide the base of the parallelogram into the area to find the height.

A=bh

108=18h
divide both sides by 18 to find h

6=h

The height is 6 inches.

Answer:

Height=6in

Step-by-step explanation:

Took test and got it correct

One angle of a rhombus measures 108°, and the shorter diagonal is 9 inches long. Approximately how long is the side of the rhombus? (Hint: Diagonals of a rhombus bisect the angles.) 7 in. 8 in. 11 in.

Answers

The value of the length of the rhombus will be found as follows:
cos θ=adjacent /hypotenuse
θ=108/2=54°
adjacent = 9/2=4.5 inch
hypotenuse=length of the rhombus
thus
cos 54=9/x
x=4.5/cos 54
x=7.6558~8  inches
the answer is 8 inches

Answer:

8 in.

Step-by-step explanation:

Let's find the rhombus's length...

cosine =  [tex]\frac{adjacent}{hypotenuse}[/tex]

cosine = ° = 54°

adjacent =  = 4.5 in

Length of Rhombus = Hypotenuse

So...

cos54 = [tex]\frac{9}{x}[/tex]

x = [tex]\frac{4.5}{cos 54}[/tex]

x = 7.6558... about 8 inches

Using synthetic division, find the quotient Q(x) and the remainder R if the polynomial P(x) = x3 − 2x2 − 3x + 18 is divided by (x + 2).

Answers

Answer:

quotient: x^2 - 4x + 5
remainder: 8

Explanation:

1) Given

p(x) = x^3 - 2x^2 - 3x + 18
divisor: x + 2

2) Write the coefficients of p(x) in order:

1       -2        -3      18

3) dividing by x + 2 => run the division  for x = - 2

4) division

     | 1     -2     -3     +18
     |
 -2 |       -2     +8     - 10
-----------------------------------
      1     -4     +5      +8

The last digit is the remainder, the others are the coefficients of the quotient:

=>

quotient = x^2 - 4x + 5
remainder = 8

The quotient Q(x) is found to be x² - 4x - 11 and the remainder R is 4.

The question involves using synthetic division to find the quotient Q(x) and the remainder R when the polynomial P(x) = x³ − 2x² − 3x + 18 is divided by (x + 2).

To perform synthetic division, we first write down the coefficients of P(x): 1, -2, -3, and 18. The divisor is (x + 2), so we use -2 for the synthetic division.

Write the coefficients of P(x): 1, -2, -3, 18.

Write the root of the divisor (x + 2) = -2 on the left side of the synthetic division setup.

Bring down the first coefficient (1).

Multiply -2 by 1, place the result (-2) under the second coefficient (-2), and add the two numbers yielding -4.

Repeat the multiplication and addition process for the rest of the coefficients.

The results of the synthetic division process give us the coefficients of the quotient Q(x) and the remainder R.

In performing the synthetic division, we find that the quotient Q(x) is x² - 4x - 11 and the remainder is R = 4.

Please help me with this question

Answers

Try this option:
1. S=12²-10²=44 sq. ft.
2. S=10*12-6*8=120-48=72 sq. ft.

answers: 1-C; 2-C.

Hendrick makes birdhouses every weekend. it takes him 35 minutes to make a birdhouse. write and algebric expression that shows how long it takes him to make a birdhouse

Answers

y= 35x (x is the number of birdhouses Hendrick makes while 35 is the amount of time it takes him to make a birdhouse.)

One class of 75 students has an average midterm score of 67 and an sd of 12. another class of 325 students has an average of 72 and an sd of 15. find the average and the sd of the combined list of 400 students. hint: this uses the sd of a long list formula.one class of 75 students has an average midterm score of 67 and an sd of 12. another class of 325 students has an average of 72 and an sd of 15. find the average and the sd of the combined list of 400 students. hint: this uses the sd of a long list formula.

Answers

Answer:

- average: 71.0625
- standard deviation: 

Explanation:

Let 

a = average score of 325 students = 72
b = average score of 75 students = 67
S = total score of 325 students
T = total score of 75 students
u = standard deviation of the score of 325 students = 15
v = standard deviation of the score of 75 students = 12
C = average of the squares of the scores of 325 students 
D = average of the squares of the scores of 75 students 

The total score of 325 students is calculated as:

S = 325a
   = 325(72) 
S = 23,400

While the total score of 75 students is calculated in similar manner:

T = 75b
   = 75(67)
T = 5,025

To get the total score of 400 students, we just add the total score of 325 students and the total score of 75 students. So, the total score of 400 students is given by

S + T = 23,400 + 5,025
S + T = 28,425

To get the average score of  400 students, we just divide the total score of 400 students by the number of students, which is 400. In terms of equation,

[tex]\text{average score of 400 students} = \frac{S + T }{400} \\ = \frac{28,425}{400} \\ \boxed{\text{average score of 400 students} = 71.0625}[/tex]

To calculate the standard deviation of the scores of 400 students, we use the following formula:

[tex]\sigma_{400} = \sqrt{\left( C + D \right) - \left( \frac{S + T}{400} \right)^2}[/tex]

where

[tex]\sigma_{400}[/tex] = standard deviation of the scores of 400 students
[tex] C + D [/tex] = average of the squares of the scores of 400 students
[tex]\frac{S + T}{400}[/tex] = average of the scores of 400 students = 71.0625

Because

C = average of the squares of the scores of 325 students 
D = average of the squares of the scores of 75 students 
u = standard deviation of the score of 325 students = 15
v = standard deviation of the score of 75 students = 12
a = average score of 325 students = 72
b = average score of 75 students = 67

We have the following 

[tex]u^2 = C - a^2 \\ \Rightarrow \boxed{C = a^2 + u^2} [/tex]  (1)

[tex]v^2 = D - b^2 \\ \Rightarrow \boxed{D = v^2 + b^2}[/tex]   (2)

So, using equations (1) and (2),

[tex]C + D = (a^2 + u^2) + (v^2 + b^2) \\ = (72^2 + 15^2) + (12^2 + 67^2) \\ \boxed{C + D = 10,042}[/tex]

Hence, the standard deviation of the scores of 400 students is calculated as 

[tex]\sigma_{400} = \sqrt{\left( C + D \right) - \left( \frac{S + T}{400} \right)^2} \\ = \sqrt{\left( 10,042 \right) - \left(71.0625 \right)^2} \\ \boxed{\sigma_{400} \approx 70.65 }[/tex]
Final answer:

The average of the combined list of 400 students is 71.9 and the standard deviation is 13.1.

Explanation:

To find the average and standard deviation of the combined list of 400 students, you can use the following formulas:

Average of combined list = (Average of one class * Number of students in one class + Average of another class * Number of students in another class) / Total number of students

Standard deviation of combined list = sqrt(((SD of one class)^2 * (Number of students in one class - 1) + (SD of another class)^2 * (Number of students in another class - 1) + ((Average of one class - Average of another class)^2 * Number of students in one class * Number of students in another class)) / Total number of students)

Applying the values from the given information:

Average of combined list = (67 * 75 + 72 * 325) / 400 = 71.9

Standard deviation of combined list

= sqrt(((12^2 * 74) + (15^2 * 324) + ((67 - 72)^2 * 75 * 325)) / 400)

= 13.1

Why do clouds tend to form around 3:00 pm and 6:00 am

Answers

During daytime, the sun heats the land and warms the air that rises. That lowers the pressure, causing a gradient force to bring air from the colder sea. The wind is then onshore. Small cumulus clouds form over the land, often following the coastline very closely 

A cookie recipe states for every 3 cups of flour, 1 1/2 teaspoons of vanilla are needed. How many teaspoons are needed for 5 cups of flour?

Answers

3 / 1½ = 2 cups of flour per teaspoon

2x = 5
divide both sides by 2 to isolate x

x = 2.5

You need 2.5 teaspoons of vanilla for 5 cups of flour.

anaya drew a cylinder with a radius of 3 inches and a height of 5 inches. she also drew a cone with the same radius and height. which of the following is true?

Answers

I would say D, but i could be wrong.
The answer is B. The volume of the cylinder is three times the volume of the cone.

Alicia buys a 5 pound bag of rocks for fish tank. She uses 1 1/8 pounds for a small fish bowl. How much is left

Answers

Hello,

Here is your answer:

The proper answer to this question is "4".

Here is how:

First convert the mix number into a fraction:

1 1/8=9/8

5*8=40
1*8=8
-
9*1=9
8*1=8

40-8=32

32/8=4
8/8=1

Which means your answer is 4/1 or 4!

If you need anymore help feel free to ask me!

Hope this helps!

how much lower is Checkpoint 1 than Checkpoint 5?
checkpoint 1: -188
checkpoint 5: -57
the top of a hill rises 462 feet above Checkpoint 1. What is the altitude of the top of the hill?
checkpoint 1: -188
hill rises: 462ft

Answers

To find how much lower check. One is then check .5, you would subtract the absolute values of both negative integers. Think of it as finding the distance between -188 and -57 on a number line. Checkpoint one is 131 feet lower than checkpoint five. To find the altitude of the top Hill you need to think of where you are starting and how far you are moving. If you start at -188, it would take 188 feet to get back to zero. This would be the distance from zero to -188 or the absolute value of -188. From zero you then would go up to 274 more feet putting you at +274 feet for the altitude. I subtracted 462 minus the 188 it took to get back to zero to get the 274 feet.

The altitude of the top of the hill is 274 feet.

To find how much lower Checkpoint 1 is than Checkpoint 5, we subtract the elevation of Checkpoint 1 from the elevation of Checkpoint 5:

Difference = Elevation at Checkpoint 5 - Elevation at Checkpoint 1

Difference = (-57) - (-188)

Now, simplify the expression:

Difference = -57 + 188

Difference = 131 feet

So, Checkpoint 1 is 131 feet lower than Checkpoint 5.

Next, to find the altitude of the top of the hill, we add the rise of the hill to the elevation at Checkpoint 1:

Altitude of the top of the hill = Elevation at Checkpoint 1 + Hill rise

Altitude = (-188) + 462

Now, calculate the sum:

Altitude = 274 feet

The altitude of the top of the hill is 274 feet.

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Jacobs & Johnson, an accounting firm, employs 15 accountants, of whom 9 are CPAs. If a delegation of 4 accountants is randomly selected from the firm to attend a conference, what is the probability that 4 CPAs will be selected? (Round your answer to three decimal places.)

Answers

Using the hypergeometric distribution, it is found that there is a 0.0923 = 9.23% probability that 4 CPAs will be selected.

What is the hypergeometric distribution formula?

The formula is:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

x is the number of successes.N is the size of the population.n is the size of the sample.k is the total number of desired outcomes.

In this problem, there are 15 accountants, 9 are CPAs and 4 will be selected, hence N = 15, k = 9, n = 4.

The probability that 4 CPAs will be selected is P(X = 4), hence:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 4) = h(4,15,4,9) = \frac{C_{9,4}C_{6,0}}{C_{15,4}} = 0.0923[/tex]

0.0923 = 9.23% probability that 4 CPAs will be selected.

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Two squares are attached to the sides of a quarter circle as shown. What is the best approximation for the area of this figure? Use 3.14 to approximate pi. 178.5 mm² 215.7 mm² 231.8 mm² 278.5 mm² Two squares with sides measuring 10 mm. Both squares are connected by a quarter circle.

Answers

Answer:

the answer is D

Step-by-step explanation:


A geometric sequence is shown below : 2/3,2,6,18.. write the explicit formula

Answers

so we know this is a geometric sequence, meaning it has a multiplier, or a "common ratio".

now, we get the next term's value by simply multiplying the current term's value by the common ratio, so if we just divide any of the terms by the term before it, the quotient will just be the common ratio.

18/6 is just 3, so there you have it, and we know the first term is 2/3.

[tex]\bf n^{th}\textit{ term of a geometric sequence}\\\\ a_n=a_1\cdot r^{n-1}\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ r=\textit{common ratio}\\ ----------\\ r=3\\ a_1=\frac{2}{3} \end{cases}\implies a_n=\cfrac{2}{3}\cdot 3^{n-1}[/tex]

the digit in the __ place is the best stem value for the set of data shown above? please help

Answers

The digit in the tens place is the best stem value for the set of data. 

Using the mode concept, according to the stem-and-leaf plot, the missing value is of 71.

What is the mode of the data-set?

It is the value that appears the most times in the data-set. When it's unique, the mode is the value that appears the most often in a data set and it can be used as a measure of central tendency, like the median and mean.

Here, we have,

In this problem, following the key format of the stem-and-leaf plot, disconsidering the missing value, the values 71 and 64 each appear 3 times.

However, the mode is 71, meaning that is should appear more times than 64, which means that the missing value is of 71.

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complete question:

This Stem-and-Leaf Plot is missing one data item. If the mode of the data set is 71, what is the value of the unknown data item?

A slice is made perpendicular to the base of a right rectangular prism as shown.
What is the area of the resulting two-dimensional cross section?
Drag and drop the answer into the box.

mm²
48
28
84
144
16

Answers

Answer:

The correct option is 1. The area of cross section area is 48 mm².

Step-by-step explanation:

From the find it is noticed that the cross section is a rectangle with length 4 mm and width is 12 mm.

The area of a rectangle is the product of its dimensions.

[tex]A=l\times w[/tex]

Where, l is length of the rectangle and w is width of the rectangle.

The area of cross section is

[tex]A=4\times 12[/tex]

[tex]A=48[/tex]

Therefore the area of cross section area is 48 mm². Option 1 is correct.

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