One batch of 25 units requires the following processing times per unit: move time for raw materials to Cutting Department, 6 minutes; Cutting Department, 4 minutes; move time to Sewing Department, 3 minutes; Sewing Department, 10 minutes; move time to Packaging Department, 2 minutes; and Packaging Department, 4 minutes. a. How much of the time spent to produce the units is value-added time? b. Determine the total within-batch wait time. c. Calculate the total lead time for the batch.

Step-by-step explanation:

A direct proof is a method that takes an statement p, which we assume to be true, and use it to show directly that another statement q is true. So this method has the following steps:

Fact that we need to use:

Every odd integer can be written in the form 2m + 1 for some unique other integer m

Let p be the statement a and b be odd integers and q be the statement that the product of a and b is odd.

Proposition if a and b are odd, then the product of a and b is odd

Proof: Assume that a and b are odd integers, the by definition a = 2m + 1 and b = 2n + 1 for some integers m and n. we will now use this to show that the product of a and b is odd.

[tex]a\cdot b= (2m+1) \cdot (2n+1)\\a\cdot b = 2m\cdot 2n+2m+2n+1\\a\cdot b =4mn+2m+2n+1\\a\cdot b = 2(2mn+2m+2n) +1\\\:If  \:k=2mn+2m+2n\\a\cdot b = 2k+1[/tex]

Hence we have shown that the product of a and b is odd since 2k + 1 is and odd integer. Therefore we have shown that p ⇒ q and so we have completed our proof.

Answer:

Step-by-step explanation:

The proof by the direct method that the product of two odd numbers is odd integer number, is the following:

Let [tex]z_1[/tex] and [tex]z_2[/tex] be two odd integers, then [tex]z_1 = 2a+1[/tex] and [tex]z_2 = 2b +1[/tex], for some integers a and b.

[tex]z_1z_2 = (2a + 1) (2b + 1)\\\\z_1z_2 = 4ab + 2a + 2b + 1\\\\z_1z_2 = 2 (2ab + a + b) +1\\\\z_1z_2 = 2n + 1[/tex]

where [tex]n = 2ab + a + b[/tex], which guarantees that [tex]n[/tex] is an integer number. In this way, [tex]z_1z_2[/tex] is an odd integer.

Answer:

[tex]y(x)\ =\ \sqrt{x}[C_1cos\dfrac{\sqrt{3}}{2}logx+C_2sin\dfrac{\sqrt{3}}{2}logx][/tex]

Step-by-step explanation:

Given differential equation is

[tex]x^2y"-xy'+y=0[/tex]                     (1)

Let's assume that

[tex]x=e^t[/tex]

[tex]=>\ t\ =\ logx[/tex]

then,

[tex]\dfrac{dx}{dt}=e^t[/tex]

[tex]and\ \dfrac{d^2x}{dt^2}=e^t[/tex]

We can write,

[tex]\dfrac{dy}{dx}=\dfrac{dy}{dt}.\dfrac{dt}{dx}[/tex]

                      [tex]=e^{-t}\dfrac{dy}{dt}[/tex]

Similarly,

[tex]\dfrac{d^2y}{dt^2}=\dfrac{d^2y}{dt^2}.\dfrac{dt^2}{dx^2}[/tex]

                            [tex]=e^{-2t}.\dfrac{d^2y}{dt^2}[/tex]

Putting these values in equation (1), we will get

[tex]e^{2t}.e^{-2t}.\dfrac{d^y}{dt^2}-e^t.e^{-t}\dfrac{dy}{dt}+y=0[/tex]

[tex]=>\dfrac{d^2y}{dt^2}-\dfrac{dy}{dt}+y=0[/tex]

So, the characteristics equation can be given as

[tex]D^2-D+1=0[/tex]

[tex]=>D\ =\ \dfrac{1+\sqrt{1-4}}{2}\ or\ \dfrac{1-1\sqrt{1-4}}{2}[/tex]

[tex]=>D=\ \dfrac{1}{2}+i\dfrac{\sqrt{3}}{2}\ or\ \dfrac{1}{2}-i\dfrac{\sqrt{3}}{2}[/tex]

Hence, the general solution of the equation can be give by

[tex]y(t)\ =\ e^{\dfrac{t}{2}}[C_1cos\dfrac{\sqrt{3}}{2}t+C_2sin\dfrac{\sqrt{3}}{2}t][/tex]

Now, by putting the value of t in above solution, we will have

[tex]y(x)\ =\ e^{\dfrac{1}{2}logx}[C_1cos\dfrac{\sqrt{3}}{2}logx+C_2sin\dfrac{\sqrt{3}}{2}logx][/tex]

[tex]y(x)=\ \sqrt{x}[C_1cos\dfrac{\sqrt{3}}{2}logx+C_2sin\dfrac{\sqrt{3}}{2}logx][/tex]

Hence, the solution of above given differential equation can be given by

[tex]y(x)=\ \sqrt{x}[C_1cos\dfrac{\sqrt{3}}{2}logx+C_2sin\dfrac{\sqrt{3}}{2}logx][/tex]

Answer:

The area of the region between the curves y=6x^2 and y=4x is 8/27

Step-by-step explanation:

Use the diagram to visualize the problem, the area colored of blue is the one that needs to be found, let's do it in 3 parts:

Part 1: Find the intersection points of the curves

To do this we put both equations in one and solve it for x:

[tex]6x^2=4x[/tex]

[tex]6x^2-4x=0\\2x(3x-2)=0[/tex]

This equation has 2 possible solutions:

x=0 and x=2/3, so the interval for integration is 0 <= x <= 2/3

Part 2: Find the area below each curve

[tex]A_{blue}=\int\limits^0_{2/3} {6x^2} \, dx \\A_{blue}=2x^3[/tex], evaluate in 0 and 2/3

[tex]A_{blue}=\frac{16}{27}[/tex]

[tex]A_{red}=\int\limits^0_{2/3} {4x} \, dx \\A_{red}=2x^2[/tex], evaluate in 0 and 2/3

[tex]A_{red}=\frac{8}{9}[/tex]

Part 3: Substract the area of the blue curve (y=6x^2) to the area of the red curve (y=4x)

[tex]Area=\frac{8}{9}-\frac{16}{27}\\Area=\frac{8}{27}[/tex]

Answer:

Yes, a brain volume of [tex] 1392.7 cm^{3}[/tex] is significantly high.

Step-by-step explanation:

Given

The range rule of thumb indicates that the usual values are within 2 standard deviations from the mean:

minimum usual value = mean - 2 * standard deviation = [tex]1094.9 - 2*128.9=837.1 cm^{3}[/tex]

maximum usual value = mean + 2 * standard deviation = [tex]1094.9 + 2*128.9=1352.7 cm^{3}[/tex]

We can see that [tex] 1392.7 cm^{3}[/tex] is not between [tex] 837.1 cm^{3}[/tex] and [tex] 1352.7 cm^{3}[/tex], which indicates that this value is unusually high.

Using the range rule of thumb, it is found that:

----------------------------

The range rule of thumb states that:

----------------------------

----------------------------

[tex]1094.9 - 2(128.9) = 837.1[/tex]

----------------------------

[tex]1094.9 + 2(128.9) = 1352.7[/tex]

----------------------------

A similar problem is given at https://brainly.com/question/24126815

Answer:  [tex]30^{\circ},\ 60^{\circ},\ 90^{\circ}[/tex]

Step-by-step explanation:

We know that the sum of measure of all the angles of a triangle is 180°.

Given : The measure of the angles of a triangle are x, 2x, and 3x.

Then, the sum of all the angle will be given by :-

[tex]x+2x+3x=180^{\circ}\\\\\Rightarrow\ 6x=180^{\circ}\\\\\Rightarrow\ x=\dfrac{180^{\circ}}{6}=30^{\circ}[/tex]

Then, the measures of angles of the triangle will be : [tex]30^{\circ},\ 2(30^{\circ}),\ 3(30^{\circ})[/tex]

i.e. [tex]30^{\circ},\ 60^{\circ},\ 90^{\circ}[/tex]

Answer:

Step-by-step explanation:

Sin t . Sin 3t . Sin 5t = 1/4 [ - Sin t + Sin 3t + Sin 7t - Sin 9t ]

Take Right hand side and use the following formula

[tex]sin C - sin D = 2 Cos\left ( \frac{C+D}{2} \right )Sin\left ( \frac{C-D}{2} \right )[/tex]

[tex]Cos C - Cos D = 2 Sin\left ( \frac{C+D}{2} \right )Sin\left ( \frac{D-C}{2} \right )[/tex]

Take right hand side

[tex]\frac{1}{4}\left (Sin 3t - Sin t + Sin 7t - Sin 9t  \right )[/tex]

[tex]\frac{1}{4}\left (2 Cos 2t Sin t +2 Sin (-t)Cos 8t \right )[/tex]

[tex]\frac{1}{4}\times 2 Sin t\left (Cos 2t-Cos8t \right )[/tex]

[tex]\frac{1}{4}\times 2 Sin t\ \times 2 \times Sin 5t\times 3t[/tex]

Sin t . Sin 3t . Sin 5t

So, LHS = RHS

Answer:

a)

Reduced Row Echelon:

[tex]\left[\begin{array}{cccc}1&1/2&0&0\\0&1&7/4&0\\0&0&1&-4\end{array}\right][/tex]

Solution to the system:

[tex]x_3=-4\\x_2=-\frac{7}{4}x_3=7\\x_1=-\frac{1}{2}x_2=-\frac{7}{2}[/tex]

b)

Reduced Row Echelon:

[tex]\left[\begin{array}{cccc}4&3&0&7\\0&0&2&-17\\0&0&2&-17\end{array}\right][/tex]

Solution to the system:  

[tex]x_3=-\frac{17}{2}\\x_1=\frac{7-3x_2}{4}[/tex]

x_2 is a free variable, meaning that it has infinite possibilities and therefore the system has infinite number of solutions.

Step-by-step explanation:

To find the reduced row echelon form of the matrices, let's use the Gaussian-Jordan elimination process, which consists of taking the matrix and performing a series of row operations. For notation, R_i will be the transformed column, and r_i the unchanged one.

a) [tex]\left[\begin{array}{cccc}0&4&7&0\\2&1&0&0\\0&3&1&-4\end{array}\right][/tex]

Step by step operations:

1. Reorder the rows, interchange Row 1 with Row 2, then apply the next operations on the new rows:

[tex]R_1=\frac{1}{2}r_1\\R_2=\frac{1}{4}r_2[/tex]

Resulting matrix:

[tex]\left[\begin{array}{cccc}1&1/2&0&0\\0&1&7/4&0\\0&3&1&-4\end{array}\right][/tex]

2. Set the first row to 1

[tex]R_3=-3r_2+r_3[/tex]

Resulting matrix:

[tex]\left[\begin{array}{cccc}1&1/2&0&0\\0&1&7/4&0\\0&0&1&-4\end{array}\right][/tex]

3. Write the system of equations:

[tex]x_1+\frac{1}{2}x_2=0\\x_2+\frac{7}{4}x_3=0\\x_3=-4[/tex]

Now you have the  reduced row echelon matrix and can solve the equations, bottom to top, x_1 is column 1, x_2 column 2 and x_3 column 3:

[tex]x_3=-4\\x_2=-\frac{7}{4}x_3=7\\x_1=-\frac{1}{2}x_2=-\frac{7}{2}[/tex]

b)

[tex]\left[\begin{array}{cccc}4&3&0&7\\8&6&2&-3\\4&3&2&-10\end{array}\right][/tex]

1. [tex]R_2=-2r_1+r_2\\R_3=-r_1+r_3[/tex]

Resulting matrix:

[tex]\left[\begin{array}{cccc}4&3&0&7\\0&0&2&-17\\0&0&2&-17\end{array}\right][/tex]

2. Write the system of equations:

[tex]4x_1+3x_2=7\\2x_3=-17[/tex]

Now you have the reduced row echelon matrix and can solve the equations, bottom to top, x_1 is column 1, x_2 column 2 and x_3 column 3:

[tex]x_3=-\frac{17}{2}\\x_1=\frac{7-3x_2}{4}[/tex]

x_2 is a free variable, meaning that it has infinite possibilities and therefore the system has infinite number of solutions.

Answer:

The desviation is 8 4/7 or 8.571

Step-by-step explanation:

The conversion for any variable X to a standard z is

[tex]Z=\frac{X-\[Mu]}\\{\[Sigma]}[/tex]

where mu is the mean and sigma de desviation

You can find the value of Z whith the tables of the accumulated probability function. The accumulated probability for the mean is 0.5 .Remenber that the accumlated probability function represent the area at the left of an abscissa. Then

0.5+0.3531=0.8531

Acording to the accumulated probability function table, a Z=1.05 has an area of 0.8531 at its left.

Now it is only solving the equation

[tex]\[Sigma]=\frac{X-\[Mu]}{Z}[/tex]

σ=[tex]\frac{34-25}{1.05}[/tex]

σ=8.571

Answer: 43 cm

Step-by-step explanation:

The perimeter of rectangle is given by :-

[tex]P=2(l+w)[/tex], where l is length and w is width of the rectangle.

Given : The length of rectangle is 17.5 cm and the width is 40 mm in cm.

Since , 1 cm = 10 mm

Then, 40 mm= [tex]\dfrac{40}{10}\ cm=4\ cm[/tex]

Then, the  perimeter of rectangle will be :-

[tex]P=2(17.5+4)\\\\\Rightarrow\ P=2(21.5)\\\\\Rightarrow\ P=43\ cm[/tex]

Hence, the perimeter of rectangle = 43 cm

Answer:

y = 26

Step-by-step explanation:

9 + 22 = x + y

9 + 22 = 31

31 = x + y

x = 5

31 = 5 + y

31 - 5 = 26

y = 26

Hey!

-----------------------------------------------

Solution:

9 + 22 = 5 + y

31 = 5 + y

31 - y = 5 + y - y

31 - y = 5

31 - y - 31 = 31 - 5

y = 26

-----------------------------------------------

Answer:

y = 26

-----------------------------------------------

Hope This Helped! Good Luck!

Answer:

1. Group A and B agree with each other.

2. Group A and C do not agree with each other.

Step-by-step explanation:

When we are analizing this problem, we will see what are the ranges of this measured times. Since we are taking into account the error we can see that :

Question 1 is about the overlapping response in Group A and Group B. And yes, we have an overlap between 7.35 to 7.39. Among this times both group A and B are in agree with each other within the experimental uncertainty.

Question 2 is now referring to Group A and Group C. And no, there isn't any common time where both groups agree with each other.

Answer:

They are 11.7475km away from Vancouver when they meet.

Step-by-step explanation:

The first step to solve this problem is modeling the position of each ferry. The position can be modeled by a first order equation in the following format:

[tex]S(t) = S_{0} + vt[/tex], in which [tex]S_{0}[/tex] is the initial position of the ferry, t is the time in hours and v is the speed in km/h.

I am going to say that the positive direction is from Nanaimo to Vancouver, and that Nanaimo is the position 0 and Vancouver the position 22.

First ferry:

Leaves Nanaimo, so [tex]S_{0} = 0[/tex]. It is 2km/h faster than the second ferry, so i am going to say that [tex]v = v + 2[/tex]. It moves in the positive direction, so v is positive. The equation of the position of this train is modeled as:

[tex]S_{1}(t) = 0 + (v+2)t[/tex],

Second ferry:

Leaves Vancouver, so [tex]S_{0} = 22[/tex]. It has a speed of v, that is negative, since it moves in the negative direction. So

[tex]S_{2}(t) = 22 - vt[/tex]

The problem states that they meet in 45 minutes. Here we have to pay attention. Since the speed is in km/h, the time needs to be in h. So 45 minutes = 0.75h.

They meet in 0.75h. It means that

[tex]S_{1}(0.75) = S_{2}(0.75)[/tex]

With this we find the value o v, and replace in the equation of [tex]S_{2}[/tex] to see how far they are from Vancouver when they meet.

[tex]S_{1}(0.75) = S_{2}(0.75)[/tex]

[tex]0.75(v+2) = 22 - 0.75v[/tex]

[tex]0.75v + 1.50 = 22 - 0.75v[/tex]

[tex]1.50v = 20.50[/tex]

[tex]v = \frac{20.50}{1.50}[/tex]

[tex]v = 13.67[/tex]km/h.

[tex]S_{2}(t) = 22 - vt[/tex]

[tex]S_{2}(0.75) = 22 - 13.67*0.75 = 11.7475[/tex]

They are 11.7475km away from Vancouver when they meet.

The ferries are 10.25 km away from Vancouver when they meet after traveling for 45 minutes, with the ferry from Nanaimo moving at 15.67 km/h and the one from Vancouver at 13.67 km/h.

Distance Between Ferries

Let's denote the speed of the slower ferry as s km/h. Therefore, the speed of the faster ferry leaving Nanaimo will be s + 2 km/h. As they both start at the same time, we can express the distance they travel in terms of their speeds multiplied by the time, which is 45 minutes (or 0.75 hours when converted to hours).

Now, let's set up the equation for the distance each ferry has traveled when they meet: the distance traveled by the slower ferry plus the distance traveled by the faster ferry equals the total distance between Nanaimo and Vancouver, which is 22 km.

Distance of slower ferry: s (0.75) km

Distance of faster ferry: (s + 2)(0.75) km

The sum of both distances is 22 km, so we have:

s (0.75) + (s + 2)(0.75) = 22

Rearranging terms and solving for s gives us:

1.5s + 1.5 = 22

s = (22 - 1.5)/1.5

Calculating the value of s and consequently the distance each ferry traveled before meeting will give us the answer.

After solving, we can determine that the speed of the slower ferry is 13.67 km/h and the faster ferry is 15.67 km/h. To find the distance from Vancouver to the meeting point, we only need to calculate the distance traveled by the slower ferry:

Distance from Vancouver = (13.67 km/h) (0.75 h) = 10.25 km

Therefore, the ferries are 10.25 km away from Vancouver when they meet.

Answer:

First one: Its place value is 600,000.

Second one: Its place value is 600.

Step-by-step explanation:

Answer: a) FALSE b) FALSE

Step-by-step explanation:

a) For the given proposition p ∧ ¬(q ∨ s) you can solve first (q v s)

q v s is true if either q is true or s is true or both. It is only false if both q and s are false. So, the proposition (q v s) is true because q is true.

Now you can solve the negation: ¬(q ∨ s)

As we know, (q v s) is true then its negation ¬(q ∨ s) is false.

p ∧ ¬(q ∨ s) should be true when both p and ¬(q ∨ s) are true, and false otherwise. So, the proposition is false because p is true and ¬(q ∨ s) is false.

b) For the given proposition  ¬(q ∧ p ∧ ¬s)

You can rewrite the expression as: ¬[q ∧ (p ∧ ¬s) ]  to solve first each part of the propositions in parenthesis.

The negation of s: ¬s  is true because s is false

Now, you can solve (p ∧ ¬s) which is true because both p and ¬s are true.

To continue, you have to solve (q ∧ p ∧ ¬s) which is true because both q and (p ∧ ¬s) are true.

To finish, the negation: ¬(q ∧ p ∧ ¬s) is false.

Answer:

Option (c) is correct

Step-by-step explanation:

Case (a)

A = 3 + 5i = (3, 5)

B = 2 + 2i = (2, 2)

C = 5i = (0, 5)

Use the distance formula to find the distance between two points

[tex]AB = \sqrt{(2-3)^{2}+(2-5)^{2}}=\sqrt{10}[/tex]

[tex]BC = \sqrt{(0-2)^{2}+(5-2)^{2}}=\sqrt{13}[/tex]

[tex]CA = \sqrt{(0-3)^{2}+(5-5)^{2}}=\sqrt{9}[/tex]

For the triangle to be right angles triangle

[tex]BC^{2}=AB^{2}+CA^{2}[/tex]

Here, it is not valid, so these are not the points of a right angled triangle.

Case (b)

A = 2i = (0, 2)

B = 3 + 5i = (3, 5)

C = 4 + i = (4, 1)

Use the distance formula to find the distance between two points

[tex]AB = \sqrt{(3-0)^{2}+(5-2)^{2}}=\sqrt{18}[/tex]

[tex]BC = \sqrt{(4-3)^{2}+(1-5)^{2}}=\sqrt{17}[/tex]

[tex]CA = \sqrt{(4-0)^{2}+(1-2)^{2}}=\sqrt{17}[/tex]

For the triangle to be right angles triangle

[tex]AB^{2}=BC^{2}+CA^{2}[/tex]

Here, it is not valid, so these are not the points of a right angled triangle.

Case (c)

A = 6 + 4i = (6, 4)

B = 7 + 5i = (7, 5)

C = 8 + 4i = (8, 4)

Use the distance formula to find the distance between two points

[tex]AB = \sqrt{(7-6)^{2}+(5-4)^{2}}=\sqrt{2}[/tex]

[tex]BC = \sqrt{(8-7)^{2}+(4-5)^{2}}=\sqrt{2}[/tex]

[tex]CA = \sqrt{(8-6)^{2}+(4-4)^{2}}=\sqrt{4}[/tex]

For the triangle to be right angles triangle

[tex]CA^{2}=BC^{2}+AB^{2}[/tex]

Here, it is valid, so these are the points of a right angled triangle.

Answer:

a) 59.98

b) 2.99

c) 2.99

d) Significantly High

Step-by-step explanation:

Part a)

Highest speed measured = x = 75.6 Mbps

Average/Mean speed = [tex]\overline{x}[/tex] = 15.62 Mbps

Standard Deviation = s = 20.03 Mbps

We need to find the difference between carrier's highest data speed and the mean of all 50 data​ speeds i.e. x - [tex]\overline{x}[/tex]

x - [tex]\overline{x}[/tex] = 75.6 - 15.62 = 59.98 Mbps

Thus, the difference between​ carrier's highest data speed and the mean of all 50 data​ speeds is 59.98 Mbps

Part b)

In order to find how many standard deviations away is the difference found in previous part, we divide the difference by the value of standard deviation i.e.

[tex]\frac{59.98}{20.03}=2.99[/tex]

This means, the difference is 2.99 standard deviations or in other words we can say, the Carrier's highest data speed is 2.99 standard deviations above the mean data speed.

Part c)

A z score tells us that how many standard deviations away is a value from the mean. We calculated the same in the previous part. Performing the same calculation in one step:

The formula for the z score is:

[tex]z=\frac{x-\overline{x}}{s}[/tex]

Using the given values, we get:

[tex]z=\frac{75.6-15.62}{20.03}=2.99[/tex]

Thus, the Carriers highest data is equivalent to a z score of 2.99

Part d)

The range of z scores which are neither significantly low nor significantly​ high is -2 to + 2. The z scores outside this range will be significant.

Since, the z score for carrier's highest data speed is 2.99 which is well outside the given range, i.e. greater than 2, we can conclude that the  carrier's highest data speed​ is significantly higher.

Final answer:

The highest data speed recorded is 59.98 Mbps above the mean, and this difference equals approximately 2.996 standard deviations. This results in a z-score of 2.996, indicating that the carrier's highest data speed is significantly high.

Explanation:

a. The difference between the carrier's highest data speed and the mean of all 50 data speeds is found by subtracting the mean speed from the highest speed. This is calculated as 75.6 Mbps - 15.62 Mbps = 59.98 Mbps.

b. To find out how many standard deviations this difference is, we divide the difference by the standard deviation of the data speeds: 59.98 Mbps / 20.03 Mbps = 2.996 standard deviations.

c. The z-score for the carrier's highest data speed is calculated by subtracting the mean from the data speed and then dividing by the standard deviation: (75.6 Mbps - 15.62 Mbps) / 20.03 Mbps = 2.996.

d. Since the z-score of 2.996 is greater than 2, it suggests that the carrier's highest data speed is significantly higher than what is considered neither significantly low nor high. In other words, the carrier's highest data speed is significant.

Answer:

Case 1

None of the sides is yellow.

Probability of rolling a yellow on your next toss: zero %

Case 2

All the sides are yellow.

Probability of rolling a yellow on your next toss: 100 %

Case 3  

At least one of the sides is yellow.

[tex]\frac{q}{N}\times100\%[/tex]

where  

N = total number of tosses  in one hour.

q = number of tosses you rolled a yellow.

Step-by-step explanation:

Case 1

None of the sides is yellow.

Probability of rolling a yellow on your next toss: zero %

Case 2

All the sides are yellow.

Probability of rolling a yellow on your next toss: 100 %

Case 3  

At least one of the sides is yellow.

As you do not know if the die is fair or not, the only way to approximate a probability of rolling a yellow is by making a table of frequencies and record the times you have rolled yellow.

If the number of tosses made in an hour is big enough as to draw a conclusion, then according to the Law of Large Numbers, the probability of rolling a yellow in one toss of the die should be

[tex]\frac{q}{N}\times100\%[/tex]

where  

N = total number of tosses

q = number of tosses you rolled a yellow.

Now, suppose you want to roll the dice once more.  

As the event of rolling a die is independent of the previous tosses, this means that the probable outcome of the event does not depend on the previous results. So, the probability remains the same.  

Probability of tossing a yellow on your next toss of the die

[tex]\frac{q}{N}\times100\%[/tex]

where  

N = total number of previous tosses

q = number of tosses you rolled a yellow.

Answer:

46 minutes.

Step-by-step explanation:

You have a gift certificate worth $20 for one long-distance phone call.

The charge for the first minute = $1.10

Let the other additional minutes that you can talk = x

The charges for the x minutes = 0.42 per minute

the equation will be : 1.10 + 0.42x = 20

0.42x = 20 - 1.10

0.42x = 18.90

x = [tex]\frac{18.90}{0.42}[/tex]

x = 45

1 minute for $1.10 + 45 minutes for $0.42/min.

you can talk for 46 minutes.

The longest phone call you can make with a $20 gift certificate, given the cost structure of $1.10 for the first minute and $0.42 for each additional minute, is approximately 46 minutes.

The subject of this question is Mathematics, specifically related to linear equations and budget constraints in the context of phone call charges. To find the longest time you can talk on the phone using your gift certificate, you'll need to understand the cost structure. The charge is $1.10 for the first minute - that leaves you with $18.90 from the gift certificate for the remaining time ($20 - $1.10). Each additional minute costs $0.42. Now, divide the remaining amount in your gift certificate by the cost per additional minute: $18.90 ÷ $0.42 ≈ 45 minutes. Adding back the first minute, the longest call you can make with the gift certificate is approximately 46 minutes

.

Learn more about Linear Equations here:

https://brainly.com/question/32634451

#SPJ3

Answer:

(x,y) = ([tex]\frac{9}{2}[/tex],[tex]\frac{1}{2}[/tex])

Step-by-step explanation:

We have to find point of intersection of two lines.

the given equations of line are:

10x - 4y = 43 - (1)

-3x - 3y = -15 - (2)

Multiplying the first equation by 3 we have:

(10x - 4y = 43)×3 = 30x - 12 y = 129 - (3)

Multiplying second equation by 10 we have :

(-3x - 3y = -15)×10 = -30x -30y = -150 - (4)

Now, adding equation (3) and (4)  we have:

-42y = -21

⇒ y = [tex]\frac{1}{2}[/tex]

Now, putting this value of y in equation (1), we have

10x - 2 = 43

⇒ 10x = 45

⇒x = [tex]\frac{9}{2}[/tex]

Hence, the intersection of given two lines is (x,y) = ([tex]\frac{9}{2}[/tex],[tex]\frac{1}{2}[/tex])

Answer:

Described

Step-by-step explanation:

A solution becomes infeasible when no solution exit and which satisfies all the constraints. We will consider two basic types of infeasibility. The 1st we will call continuous infeasibility and the second one is discrete or integer infeasibility. Continuous infeasibility is the one where a non–MIP problem is infeasible. In this case the feasible region defined by the intersecting constraints is empty. Discrete or integer infeasibility is the one  where a MIP problem has a feasible relaxation (note that a relaxation of a MIP is the problem we get when we drop the discreteness required on the variables) but the feasible region of the relaxation contains no solution that satisfies the discreteness requirement.

Final answer:

An infeasible solution occurs when constraints of a problem conflict with each other, making it impossible to find a solution that satisfies all conditions. This is common in linear programming and can happen due to poor design decisions or unreasonable premises. Brainstorming alternative solutions is essential for finding feasible approaches.

Explanation:

An infeasible solution occurs in problem-solving when the constraints of a problem are such that no possible solution satisfies all the conditions. In mathematics and particularly in linear programming, this can happen when the set of constraints creates a situation where no intersection point exists between all the constraint equations - essentially, the requirements for a solution are mutually exclusive and cannot be met simultaneously.

For example, a situation may arise where a design problem contains a premise that produces an unreasonable result, highlighting that some design choices may not align with the physical reality, and thus are infeasible. An extremely large Coulomb force in a physics problem, due to the assumption of an excessively large separated charge, is an instance where the result is obviously incorrect and infeasible based on known physical principles.

When approaching such problems, a common strategy is to brainstorm alternative solutions and explore a wide variety of ideas that could potentially solve the problem within realistic constraints. Some ideas may be discarded as infeasible early on if they conflict with the basic laws of nature or if they stand little chance of practical application. This process is especially useful in engineering and design fields, where practicality and adherence to real-world principles are crucial.

Answer:

A. -0.87

Step-by-step explanation:

The correlation coefficient is a measure of the strength and nature of the linear relationship between two variables, one dependent and one independent. This coefficient takes values between -1 and 1, indicating with its sign whether the relationship is direct or inverse between the variables involved and with its absolute value indicates the strength of the linear relationship between them. A coefficient with absolute value close to 1 indicates great strength and better fit.

Conclusion: The best coefficient, of the propuetso in the problem, is that of -0.87, which indicates a strong relationship between the variables, a good fit and an inverse relationship between them.

Answer: -2.12°C

Step-by-step explanation:

Let x denotes the reading of the thermometers .

We assume that the readings on the thermometers are normally distributed.

Let a be the reading that separates the rejected thermometers from the others.

Given: Population mean : [tex]\mu=0[/tex]

Standard deviation: [tex]\sigma= 1[/tex]

Also, [tex]P(x<a)=0.017[/tex]

By using the z-table , the z-value corresponds to the p-value (one -tailed)0.017 is [tex]\pm2.12[/tex].

Now, [tex]z=\dfrac{a-\mu}{\sigma}[/tex]

i.e. [tex]\pm2.12=\dfrac{a-0}{1}[/tex]

i.e. [tex]\pm2.12=a[/tex]

For left tailed , [tex]a=-2.12[/tex]

It means the reading that separates the rejected thermometers from the others = -2.12°C.

Answer: The plot will be linear as described by the equation of the problem

Step-by-step explanation:

The first thing to do is to determine values of X and place them in one column. The following column should include all values solved by the equation in terms of y. Once you plot the graph, you should have something as the graph attached. To save it as a pdf, simply scan your graph paper to pdf and follow the instructions for assignment submission.

Answer:

The shop’s profit if it sold 150 units of sunscreen yesterday is $1000

Step-by-step explanation:

The total daily cost associated with the sale of this item yesterday was $200.

Cost of 1 unit = $8

So, Cost of 150 units = [tex]8 \times 150[/tex]

                                  = [tex]1200[/tex]  

So, revenue = $1200

Cost = $200

So Profit = Revenue - Cost

Profit = $1200-$200

Profit = $1000

Hence the shop’s profit if it sold 150 units of sunscreen yesterday is $1000

By DeMoivre's theorem,

[tex]\cos(4\theta)+i\sin(4\theta)=(\cos\theta+i\sin\theta)^4[/tex]

Expanding the right side gives

[tex]\cos^4\theta+4i\cos^3\theta\sin\theta-6\cos^2\theta\sin^2\theta-4i\cos\theta\sin^3\theta+\sin^4\theta[/tex]

Equating imaginary parts tells us

[tex]\sin(4\theta)=4\cos^3\theta\sin\theta-4\cos\theta\sin^3\theta[/tex]

(Not sure what you mean by sin(e) and cos(e)...)

Answer:

[tex]E(k)= \left[ \begin{array}{c} {6+0.10k\,\,if\,\,0\leq k \leq500} & 6+500\times0.10+0.11(k-500)\,\,if\,\,500<k\leq1000& 6+500\times0.10+500\times0.11+0.15(k-1000)\,\,if\,\,k>1000\end{array}[/tex]

Step-by-step explanation:

The cost function has 3 branches,

So the first branch the consumer pays 6 dollars plus .10cents for any additional kWh (k)

In the second, they pay the same as the first up to 500kWh, and after that they pay  0.11 for the additional kWh above 500: (k-500) but bellow 1000

In the third branch, for consumptions above 1000, they pay the fix amount, plus .10 for the first 500 ([tex]500\times0.10[/tex]) , .11 for the additional 500 ([tex]500\times0.11[/tex]) , and finally 0.15 for consumptions above 1000: [tex]0.15(k-1000)[/tex]

Final answer:

The monthly cost of electricity, E, as a function of the electricity used, x, is defined using a piecewise function with different rates for usage tiers, including a fixed base charge and variable rates for different consumption brackets.

Explanation:

To express the monthly cost E as a function of the amount x of electricity used by the customer, we consider the following rates:

Therefore, the function is a piecewise function defined as:

E(x) =

This function helps calculate the monthly electricity bill based on the usage levels. Remember that the first bracket is for the initial 500 kWh, the second bracket is for 501 to 1000 kWh, and the last bracket applies to usage above 1000 kWh.

Answer:

The solution of given equation are -1 and 5.

Step-by-step explanation:

The given equation is

[tex]|x-2|-3=0[/tex]

We need to solve the above equation by finding the zeros of

[tex]y=|x-2|-3[/tex]

The vertex form of an absolute function is

[tex]y=a|x-h|+k[/tex]

where, a is constant and (h,k) is vertex.

Here, h=2, k=-3. So vertex of the function is (2,-3).

The table of values is

   x           y

   0         -1

   2         -3

   4         -1

Plot these points on a coordinate plane and draw a V-shaped curve with vertex at (2,-3).

From the given graph it is clear that the graph intersect x-axis at -1 and 5. So, zeroes of the function y=|x-2|-3 are -1 and 5.

Therefore the solution of given equation are -1 and 5.

Now solve the given equation algebraically.

[tex]|x-2|-3=0[/tex]

Add 3 on both sides.

[tex]|x-2|=3[/tex]

[tex]x-2=\pm 3[/tex]

Add 2 on both sides.

[tex]x=\pm 3+2[/tex]

[tex]x=3+2[/tex] and [tex]x=-3+2[/tex]

[tex]x=5[/tex] and [tex]x=-1[/tex]

Therefore the solution of given equation are -1 and 5.

Answer:

(a) The confidence interval is: 0.0304 ≤ π ≤ 0.0830.

(b) Upper confidence bound = 0.0787

Step-by-step explanation:

(a) The confidence interval for p (proportion) can be calculated as

[tex]p \pm z*\sigma_{p}[/tex]

[tex]\sigma=\sqrt{\frac{\pi*(1-\pi)}{N} }\approx\sqrt{\frac{p(1-p)}{N} }[/tex]

NOTE: π is the proportion ot the population, but it is unknown. It can be estimated as p.

[tex]p=17/300=0.0567\\\\\sigma=\sqrt{\frac{p(1-p)}{N} }=\sqrt{\frac{0.0567(1-0.0567)}{300} }=0.0134[/tex]

For a 95% two-sided confidence interval, z=±1.96, so

[tex]\\LL = p-z*\sigma=0.0567 - (1.96)(0.0134) = 0.0304\\UL =p+z*\sigma= 0.0567 + (1.96)(0.0134) = 0.0830\\\\[/tex]

The confidence interval is: 0.0304 ≤ π ≤ 0.0830.

(b) The confidence interval now has only an upper limit, so z is now 1.64.

[tex]UL =p+z*\sigma= 0.0567 + (1.64)(0.0134) = 0.0787[/tex]

The confidence interval is: -∞ ≤ π ≤ 0.0787.

Final answer:

To calculate a confidence interval for the fraction of defective circuits, use the formula for the confidence interval of a proportion. The 95% two-sided confidence interval for the fraction of defective circuits is 0.0182 ≤ p ≤ 0.0951. The 95% upper confidence bound on the fraction of defective circuits is 0.0951.

Explanation:

To calculate a confidence interval for the fraction of defective circuits, we can use the formula for the confidence interval of a proportion. Let p-hat be the proportion of defectives in the sample, which is equal to 17/300 = 0.0567. We can calculate the standard error as [tex]\sqrt{((p-hat*(1-p-hat))/n)[/tex], where n is the sample size.

Using a 95% confidence level, we can find the critical value from the standard normal distribution, which is approximately 1.96. The lower bound of the confidence interval is given by p-hat - z*(standard error), and the upper bound is given by p-hat + z*(standard error).

Therefore, the 95% two-sided confidence interval for the fraction of defective circuits is 0.0182 ≤ p ≤ 0.0951. The 95% upper confidence bound on the fraction of defective circuits is 0.0951.

Answer: 0.7258

Step-by-step explanation:

Given : A telemarketer makes a sale on 25% of his calls.

i.e. p=0.25

He makes 300 calls in a night, i.e. n=300

Let x be a random variable that represents the number of calls make in night.

To convert the given binomial distribution to normal distribution we have :-

[tex]\mu=np=300(0.25)=75[/tex]

[tex]\sigma=\sqrt{p(1-p)n}=\sqrt{(0.25)(1-0.25)(300)}\\\\=\sqrt{56.25}=7.5[/tex]

Now, using [tex]z=\dfrac{x-\mu}{\sigma}[/tex], the z-value corresponds to x= 70 :-

[tex]z=\dfrac{70-75}{7.5}\approx-0.67[/tex]

The z-value corresponds to x= 90 :-

[tex]z=\dfrac{90-75}{7.5}\approx2[/tex]

By using the standard normal distribution table for z, the probability that he will make more than 70 sales but less than 90 sales:-

[tex]P(-0.67<z<2)=P(z<2)-P(z<-0.67)\\\\=P(z<2)-(1-P(z<0.67))\\\\=0.9772-(1-0.7486)\\\\=0.9772-0.2514=0.7258[/tex]

Hence, the probability that he will make more than 70 sales but less than 90 sales= 0.7258