One object has a charge of +5.0 · 10-6 c, and a second object has a charge of +2.0 · 10-6
c. the objects are 0.5 meters apart. what is the electrostatic force between them?

Answers

Answer 1
The electrostatic force between two charged objects is given by
[tex]F=k \frac{q_1 q_2}{r^2} [/tex]
where
k is the Coulomb's constant
q1 is the charge of the first object
q2 is the charge of the second object
r is the separation between the two objects

In our problem:
[tex]q_1=+5.0 \cdot 10^{-6} C[/tex]
[tex]q_2 = +2.0 \cdot 10^{-6} C[/tex]
[tex]r=0.5 m[/tex]
So if we plug these numbers into the equation, we can find the electrostatic force between the two objects:
[tex]F=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(5.0 \cdot 10^{-6} C)(2.0 \cdot 10^{-6}C)}{(0.5 m)^2}=0.36 N [/tex]
Answer 2

Final answer:

Using Coulomb's Law, the electrostatic force between two positive charges of +5.0 · 10^-6 C and +2.0 · 10^-6 C, 0.5 meters apart, is calculated to be approximately 0.0719 Newtons, indicating a repulsive force.

Explanation:

To calculate the electrostatic force between two charges, we use Coulomb's Law, which is expressed as F = k * |q1 * q2| / r2, where F is the force between the charges, k is the Coulomb's constant (approximately 8.987 x 109 N m2/C2), q1 and q2 are the magnitudes of the charges, and r is the distance between the centers of the two charges.

For the charges of +5.0 · 10-6 C and +2.0 · 10-6 C separated by 0.5 meters, we substitute these values into the formula to get the electrostatic force. Therefore, F = (8.987 x 109) * (5.0 x 10-6 * 2.0 x 10-6)/(0.5)2.

After calculating, F equals approximately 0.0719 Newtons. This force is repulsive since both charges are positive.


Related Questions

99 POINTS!!!
Why do people on Earth see only one side of the Moon when the Moon is visible in the sky?
A. The Moon does not rotate.
B. The Moon does not revolve.
C. The Moon and Earth rotate at the same rate.
D. The Moon rotates and revolves at the same rate.

Answers

I believe the answer is A) the moon does not rotate

Hello!

I believe the answer is C) The Moon and Earth rotate at the same rate. The moon and the earth rotate at the same rate. Meaning that the moon orbits the earth in 27.322 days. It also takes approximately 27 days for the moon to rotate once on its axis. So as a result, the moon does not seem to be spinning, but appears to observers from Earth to be keeping almost perfectly still.

I hope it helps!

The diagram shows the layers of the Sun. Which labels correctly identify the layers most closely associated with gamma rays and visible light?

Z: Gamma rays
X: Visible light

X: Gamma rays
Z: Visible light

Z: Gamma rays
Y: Visible light

Y: Gamma rays
Z: Visible light

Answers

Z - Gamma Rays
X - Visible Light

Gamma rays are heavily produced in the core of the sun but are diluted before they reach the surface (Z). And the surface is the only thing the human eye can see (X).

Answer:

Z: Gamma rays

X: Visible light

Explanation:

A close look at the diagram attach shows the core of the sun and then the external surface.

Gamma rays are intricately associated with the nuclear reactions that go on in the core of the sun that makes it to produce light. Hence Z must refer to gamma rays emitted in these nuclear processes at the core of the sun.

Visible light is given out by the sun and seen externally. Hence X is visible light.

What is the power generated by a 45 kg person who walks up a flight of 12 stairs, each 30 cm high, in 12 s?
A.13.5 W
B.132.3 W
C.1,350 W
D.13,230 W

Answers

The total distance covered by the person is 12 times the height of each stair:
[tex]\Delta h=12 \cdot 30 cm=360 cm=3.60 m[/tex]

The work done by the person to climb the stairs is equal to the increase in his gravitational potential energy:
[tex]W= \Delta U=mg \Delta h=(45 kg)(9.81 m/s^2)(3.60 m)=1589.2 J[/tex]

And therefore, the power generated by the person in 12 s is the work done divided by the time taken:
[tex]P= \frac{W}{t}= \frac{1589.2 J}{12 s}=132.3 W [/tex]

So, the correct answer is B.

True or false canvassing is an approach used to justify leads!!!hurry

Answers

Yes that is true
Good luck! :)

When you drive along the right-rear side of another vehicle, you are ______________?

Answers

When you drive along the right-rear side of another vehicle, you are in one of the driver's blind spots and in danger of a collision.


Hope this helps : )

When you drive along the right-rear side of another vehicle, you are in one of the driver's blind spots and in danger of a collision.

what is driving?

Driving is the controlled operation and movement of a vehicle, including cars, motorcycles, trucks, buses, and bicycles.

The most critical thing to do before you pass another vehicle is check to the right side.  It is also very important never to drive faster than the the speed limit, or at a speed that is unsafe for the current traffic,

weather or road condition in order to pass other vehicles. The law requires you to only pass other vehicles on the left (using the left lane). This is why you should check the right side.

Hence when you drive along the right-rear side of another vehicle, you are in one of the driver's blind spots and in danger of a collision.

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Practicing good human relations skills and having a positive attitude will

Answers

Have a positive effect on you as a human being. Your attitude will improve, your charisma will spread, and you will a better, more well rounded person.

If you practice good human relation skills then you will be more happy, be open, talk more, you will think more positive and a lot more. (these are just some examples)


Hope this will help someone! ;)

What happens to the efficiency of a ramp if friction is reduced?

Answers

it's efficiency will increase

What is not a similarity between symbolic and analogical representations

Answers

Answer:

(1) Physical characteristics different.

(2) Difference in direct relation of mental picture with the real object.

Explanation:

There are the points which describe the non similarities between symbolic and analogical representation:

Analogical representation is the representation that can share some of its physical characteristics with an object whereas symbolic representation is the representation which does not corresponds to physical characteristics of an object.In analogical representation, mental picture have direct relation to the actual object whereas in symbolic representation, mental picture does not have direct relation with an object.

Which statement best compares conduction, convection, and radiation?

Convection and radiation transfer thermal energy through matter only, and conduction transfers thermal energy through both matter and empty space.

Radiation and conduction transfer thermal energy through matter only, and convection transfers thermal energy through both matter and empty space.

Convection and conduction transfer thermal energy through matter only, and radiation transfers thermal energy through both matter and empty space.

Conduction, convection, and radiation transfer thermal energy through both matter and empty space.

Answers

In conduction mode of heat transfer energy is transferred through medium molecules by their vibration about their own position. SO here medium particles remain at their own position while energy is transferred from one point to other

In convection mode of heat transfer the heat is carried by the medium molecules from one place to other. So here medium moles itself transfer with the energy.

In radiation mode heat energy is transferred through electromagnetic waves so there is no medium required for this.

So correct answer is

Convection and conduction transfer thermal energy through matter only, and radiation transfers thermal energy through both matter and empty space.

Convection and conduction transfer thermal energy through matter only, and radiation transfers thermal energy through both matter and empty space.

An electron is projected vertically upward with a speed of 1.70 ✕ 106 m/s into a uniform magnetic field of 0.320 t that is directed horizontally away from the observer. describe the electron's path in this field when viewed from above.

Answers

The path of the electron is 30.2μm

Data;

speed = 1.70x10^6 m/smagnetic field = 0.320TCharge of an electron = 1.60x10^-19 Cmass of an electron = 9.1x10^-31 kg

The radius or path of the electron

The path of the electron is circular and the radius can be calculated with the help of centripetal force.

[tex]qvB = \frac{mv^2}{r} \\qB = \frac{mv}{r}\\ r = \frac{mv}{qB} \\[/tex]

Let's substitute the value and solve.

[tex]r = \frac{mv}{qB}\\r = \frac{9.10*10^-^3^ * 1.70* 10^6}{(1.60*10^-^1^9 * 0.320}\\r = 3.02*10^-5\\r = 30.2 \mu m[/tex]

The path of the electron is 30.2μm

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Final answer:

The path of an electron projected upward into a horizontal magnetic field, when viewed from above, forms a circular motion due to the magnetic force acting as a centripetal force. The electron will circulate clockwise because of its negative charge.

Explanation:

An electron is projected vertically upward with a speed of 1.70 × 106 m/s into a uniform magnetic field of 0.320 T that is directed horizontally away from the observer. When an electron moves through a magnetic field perpendicular to the direction of the field lines, it experiences a magnetic force perpendicular to both the field and its velocity. This force acts as a centripetal force and causes the electron to move in a circular path.

Since the magnetic field is horizontal and the electron is projected upward, the magnetic force will cause the electron to circulate in a plane perpendicular to the magnetic field. When viewed from above, the path of the electron will be a circle.

It's important to note that the direction of the force and thus the direction of the circular motion depends on the fact that the electron has a negative charge. According to the right-hand rule, as the electron is projected upward, the force will be directed to the observer's left, causing the electron to circulate clockwise when viewed from above.

A baseball has a mass of 145 g A bat exerts a force of 18400 N on the ball what is the acceleration of the ball

Answers

F=ma
18400=0,145*a
...................

Difference between duracell and interstate golf cart batteries

Answers

Duracell batteries are an example of an electrochemical cell that is powered between the reaction of Magnesium and Zinc, occurring in basic conditions (alkaline battery). This type of reaction has a precise output of 1.5 volts, and looks like this:

Zn + 2MnO2 ➡️ ZnO + Mn2O3

It’s not rechargeable.


Golf Cart Batteries are an example of an electrochemical cell that is powered by the reaction between Lead and Sulfuric Acid (Lead-Acid battery). This type of reaction occurs on larger scales than an alkaline battery, and thus can generate a variety of powers depending on how many instruments are present within the battery. The reaction looks like this:

PbO2 + Pb + 2H2SO4 ➡️ 2PbSO4 + H2O

This is a rechargeable cell, but is rather prone to discharging by the environment and surroundings of the battery.

Final answer:

The Duracell and Interstate brands offer golf cart batteries with differences in performance, battery life, and maintenance needs. While Duracell is known for reliable and long-lasting power, Interstate emphasizes build quality and has a strong support network. The choice depends on user preferences and cart compatibility.

Explanation:

The Duracell and Interstate brands offer golf cart batteries, with distinctions that can influence a consumer's choice. Duracell batteries are known for their long-standing reputation in battery reliability and performance. They typically provide a range of batteries for various applications, including golf carts, with attention to long-lasting power and durability. On the other hand, Interstate batteries boast top-quality construction and are also very reliable, with a strong presence in the automotive battery market. Consumers may find differences in the specifications such as battery life, maintenance requirements, performance under varying conditions, and price between the two brands.

When choosing between Duracell and Interstate golf cart batteries, one should consider factors such as the type of battery (flooded lead-acid vs. AGM), capacity, cycle life, maintenance needs, and warranty offered by the manufacturer. Duracell generally offers a reliable and consistent performance, while Interstate emphasizes build quality and has a strong distribution network for customer support. Ultimately, the decision should be based on the specific needs and preferences of the user, as well as the compatibility with their golf cart model.

Using what you know about newton's second law explain why a car with a lager mass use more fuel than a car with a smalle mass. assume both car dreive the same distance

Answers

The car with bigger Mass requires more fuel because More mass the heavier it gets. you can't grab the little car fuel tank and put it in the big car it will run out to fast.

overall answer : The bigger the mass = more weight which means it needs more fuel to run

What are the relative positions of the sun moon and earth during a full moon?

Answers

They are relatively straight or as straight as they are going to get during a given month that is when a full moon occurs.

If a cell phone is dropped from a very tall building, how far has the phone fallen after 2.7 seconds, neglecting air resistance?

Answers

The free fall of the phone is an uniformly accelerated motion toward the ground, with constant acceleration equal to
[tex]g=9.81 m/s^2[/tex]

So, assuming the downward direction as positive direction of the motion, since the phone starts from rest the distance covered by the phone after a time t is given by
[tex]y(t) = \frac{1}{2}gt^2 [/tex]
And if we substitute t=2.7 s, we find the distance covered:
[tex]y(t)= \frac{1}{2}(9.81 m/s^2)(2.7 s)^2=35.8 m [/tex]
Final answer:

The phone has fallen approximately 36.621 meters after 2.7 seconds.

Explanation:

In order to determine how far the phone has fallen after 2.7 seconds, we can use the equation of motion: s = ut + (1/2)at², where s is the distance, u is the initial velocity, t is the time, and a is the acceleration. Since the phone is dropped from rest, its initial velocity is 0 m/s. Neglecting air resistance, the only force acting on the phone is gravity, which accelerates it at a rate of 9.8 m/s². Plugging in the values, we get:

s = (0)(2.7) + (1/2)(9.8)(2.7)²

s = 36.621 m

Therefore, the phone has fallen approximately 36.621 meters after 2.7 seconds.

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If one light bulb burns out in a string of lights, and the rest stay lit, it is reasonable to assume that the lights are wired in

Answers

The lights are wired in PARALLEL.

In fact, when the lights are connected in parallel, they are connected on separate branches to the source of voltage, so if one light bulb burns out, the other lights continue to work because the current continues to flow in the other branches of the circuit.

Vice-versa, if the light bulbs are connected in series, they are on the same branch This means that if one of them burns out, the circuit is open in that point, so the current cannot flow anymore and the other light bulbs turn off as well.

Answer:

Series

Explanation:

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An object is attached to a vertical spring and bobs up and down between points a and
b. where is the object located when its kinetic energy is a minimum?

Answers

 it would be at either A or B. 

1) Back on the beach the following day, Clay notices that the waves propelling towards the beach have a period of 6 s. If the wave crests are 15 m apart what is the speed at which they are traveling?

2) Barry Manilow is playing a concert. Having purchased your ticket so late you are sitting in the back row 184 m from the stage. If Barry hits a note on his keyboard that has a frequency of 400 Hz, how many full sound wavelengths are there between you and Barry? How much is the time delay between the time the note is played and the time you hear the note?

3) find the frequency of the ultrasonic wave emitted by a bat if it has a wavelength of 0.0085 m

4) A "wave" in a football stadium has a period of 2 seconds. If the crests between these " waves" measure 20 m, what is the speed at which the "wave" is traveling?

Answers

1) The speed of a wave is given by
[tex]v=\lambda f[/tex]
where
[tex]\lambda[/tex] is the wavelength
f is the frequency of the wave

For the wave in this problem, the distance between two successive crests is 15 m, this means its wavelength is [tex]\lambda=15 m[/tex] (because the wavelength is the distance between two successive crests). The period of the wave is 6 s, and the frequency is the reciprocal of the period:
[tex]f= \frac{1}{T}= \frac{1}{6 s}=0.167 Hz [/tex]

Therefore, the speed of the waves is
[tex]v= \lambda f=(15 m)(0.167 Hz)=2.51 m/s[/tex]


2) The speed of sound in air is [tex]v=343 m/s[/tex]. The frequency of the note is f=400 Hz, so we can find its wavelength by using the same relationship we used at point 1)
[tex]\lambda = \frac{v}{f}= \frac{343 m/s}{400 Hz}=0.86 m [/tex]

Since you are sitting at a distance of d=184 m from the source of the sound wave, the number of wavelengths between you and Barry is
[tex]N= \frac{d}{\lambda}= \frac{184 m}{0.86 m}=213.9 \sim 214 [/tex]
So, there are approximately 214 fully wavelengths between you and Barry.

2b) The time delay between the time the note is played and the time you hear it corresponds to the time the sound takes to arrive to your ear, therefore the distance divided by the speed of sound:
[tex]t= \frac{d}{v}= \frac{184 m}{343 m/s}=0.54 s [/tex]


3) The wavelength of the ultrasound wave is [tex]\lambda=0.0085 m[/tex] while its speed is the speed of sound: [tex]v=343 m/s[/tex], therefore its frequency is
[tex]f= \frac{v}{\lambda}= \frac{343 m/s}{0.0085 m}= 4.04 \cdot 10^4 Hz=40.4 kHz[/tex]

4) The period of the wave is T=2 s, so the frequency is
[tex]f= \frac{1}{2 s}=0.5 Hz [/tex]
and the spacing between the crests, which corresponds to the wavelength, is
[tex]\lambda=20 m[/tex]
Therefore, the speed of the wave is
[tex]v=\lambda f=(20 m)(0.5 Hz)=10 m/s[/tex]

a cheetah can run from 0 to 70 mph in 2.2 seconds. what is the cheetah's acceleration in m/s?

Answers

Final answer:

The acceleration of a cheetah that can increase its speed from 0 to 70 mph in 2.2 seconds is 14.224 m/s² after converting the velocity into meters per second.

Explanation:

To calculate the acceleration of a cheetah that can go from 0 to 70 mph in 2.2 seconds, we first need to convert the speed from miles per hour (mph) to meters per second (m/s). The conversion factor is 1 mph = 0.44704 m/s. So, 70 mph is equivalent to 70 × 0.44704 m/s, which equals 31.2928 m/s. According to the formula for acceleration (a), which is the change in velocity (Δv) divided by the time (Δt), the cheetah's acceleration would be:

a = Δv / Δt = (31.2928 m/s - 0 m/s) / 2.2 s = 14.224 m/s²

Therefore, the cheetah's acceleration is 14.224 m/s².

You must raise the weight to a height of 10 meters. You cannot do it! Thinking back to what you have learned in science class, you set up the pulley you see here. How does using this pulley reduce the force needed to lift the weight 10 meters?

Answers

A single pulley has no advantage in reducing force. A single pulley only helps by changing direction of effort, pulling something from up to down feels easier then vice versa due to our muscles arrangement. However, the force needed is the same.
Meanwhile multiple pullies divide the tension. The lower pulley itself reduces the force into half so as to you feel a part of the tension while rest is suspended by the ceiling in the case in the diagram below.

Answer:

C.The amount of force stays the same; the direction changes. You pull down to move something up.

Explanation:

i got it right so trust me. if you dont ur loss

Building up electric charges on a Van de Graaff generator is an example of static

Answers

Static electricity is shown by building up electric charges on a Van de Graaff generator. Given statement is correct.

What is static electricity?

The imbalance of electric charges within or on the surface of a substance, or between materials, is known as static electricity.

Static electricity is generated by Van de Graaff generators. Static does not include acceleration, implying that it is stationary, which pertains to the formation of electric charges.

Static electricity is shown by building up electric charges on a Van de Graaff generator.

Hence,given statement is correct.

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When two pulses meet up with each other while moving through the same medium, they have a tendency to bounce off each other and return back to their origin?

Answers

The answer is False.  When two pulses meet up with each other while moving through the same medium, they do not have a tendency to bounce off each other and return back to their origin. The effect of one of the pulses on the displacement  is "destroyed" or canceled by the effect of the other pulse.

If the concentration of sn2+ in the cathode compartment is 1.50 m and the cell generates an emf of 0.24 v , what is the concentration of pb2+ in the anode compartment?

Answers

Answer:

4.8*10^-8M

Explanation:

Final answer:

To determine the concentration of Pb2+ in the anode compartment, we can use the Nernst equation. By rearranging the Nernst equation and plugging in the given values, we can calculate the concentration of Pb2+ in the anode compartment.

Explanation:

To determine the concentration of Pb2+ in the anode compartment, we need to use the Nernst equation. The Nernst equation relates the cell potential to the concentration of ions in each compartment of the cell. It is given by: Ecell = E°cell - (0.0592/n) × log([Pb2+]/[Sn2+]), where Ecell is the cell potential, E°cell is the standard cell potential, [Pb2+] is the concentration of Pb2+ in the anode compartment, [Sn2+] is the concentration of Sn2+ in the cathode compartment, and n is the number of electrons transferred in the balanced redox reaction.

In this case, the cell potential is 0.24 V, [Sn2+] is 1.50 M, and n is 2 (since it is a Sn2+/Pb2+ redox reaction). Therefore, the equation becomes: 0.24 = E°cell - (0.0592/2) × log([Pb2+]/1.50). We can rearrange this equation to solve for [Pb2+]: [Pb2+] = (10^((E°cell - 0.24) × 2 / 0.0592)) × 1.50.

In electromagnetic induction, does the direction of the magnet’s motion influence the direction of the induced current?

Answers

Yes, it does.

In fact, Faraday-Neumann-Lenz law can be written as
[tex]\epsilon = - \frac{\Delta \Phi}{\Delta t} [/tex]
where
[tex]\epsilon[/tex] is the induced emf
[tex]\Delta \Phi[/tex] is the magnetic flux variation
[tex]\Delta t[/tex] is the time interval

The negative sign in front of the formula gives the direction of the induced emf. In fact, the direction of the induced emf is such that it opposes to the change of magnetic flux. In other words, if the magnetic flux is increasing (for instance, when a magnet is moving toward a coil), the direction of the induced emf is such that it produces a magnetic field opposite to the original magnetic field; viceversa, when the magnetic flux is decreasing (for instance, when the magnet is moved away from the coil), the direction of the induced emf is such that it produces a magnetic field in the same direction of the original magnetic field.

What is the difference between AM radio waves and FM radio waves?

A-AM waves travel short distances along the Earth’s surface; FM waves travel farther.

B-An AM wave varies in amplitude; an FM wave varies in frequency.

C-FM waves are better reflected by particles in the Earth’s atmosphere.

D-An FM wave varies in amplitude; an AM wave varies in frequency.

Answers

The correct answer is B.
The answer is B. Hope it helped!

An experiment yielded the above temperature and time information. what is the freezing point of the material in this experiment if the material is a solid at time zero?

Answers

The answer is 0 degrees Celsius (0°C). It will be where the line flat lines the first time.  The second time would be the boiling point.  An experiment yielded the above temperature and time information. The freezing point of the material in this experiment if the material is a solid at time zero is 0 degrees Celsius (0°C) .

A person starts walking at a constant speed of 2.3 m/s in a straight line from point A to point B . At point B, she turns around and walks back to point A at a speed of 1.1 m/S. What was her average speed for the entire trip in m/s?

Answers

Final answer:

To calculate the average speed of the person's entire trip, you would use the formula of total distance divided by total time. In this scenario, the total distance is twice the distance from point A and B, and the total time is the sum of the times taken to walk from A to B and back.

Explanation:

The question is asking about the concept of average speed, which in physics is defined as the total distance travelled divided by the total time taken. In this case, the subject walks from point A to B and then retraces her steps back to A.

Since she's retracing her exact path, the total distance travelled is essentially twice the distance from A to B. The total time taken is the time taken to walk from A to B plus the time taken to walk back.

Firstly, we would determine the time taken for each leg of the journey by dividing the distance, say 'd', by her speed. However, since we don't have a specific distance given, we can use variables.

Let's say the time taken to travel from A to B is 't1' (d/2.3) and from B to A is 't2' (d/1.1).

Her total journey time 'T' is the sum of 't1' and 't2'. To get the average speed, we divide the total distance travelled (which is '2d') by 'T'. This would give us an equation that represents her average speed for the entire trip.

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A person starts walking at a constant speed of 2.3 m/s in a straight line from point A to point B. At point B she turns around and walks back to point A at a speed of 1.1 m/s

Let distance between A and B be s.

When she goes from A to B,

Time taken = Distance travelled/ Speed

= s/ 2.3

When she goes from B to A,

Time taken= Distance travelled/ Speed

= s/1.1

Total distance travelled= s+s= 2s

Total time taken:

= s/2.3+s/1.1

=1.1s+2.3s/1.1*2.3

=3.4s/2.53

Average speed= Total distance/ Total time

= 2s / (3.4s/2.53)

= 1.48 m/s

Therefore, the average speed of the whole journey is 1.48 m/s.

what can you tell about the hydrogen/hydroxide ion concentration of the unknown liquid

Answers

The answer is  H+ low and OH- high.  The hydrogen/hydroxide ion concentration of the unknown liquid becomes  H+ low and OH- high.  

What is planck's constant? choose 2 answers. a when the energy e of a photon is multiplied by its frequency f b 6.623 x 10-34 j.s c when the energy e of a photon is divided by its frequency f d 6.022 x 1023?

Answers

give me some answer choices and i will be happy to help

A beaker containing mercury is placed inside a vacuum chamber in a laboratory. the pressure at the bottom of the beaker is 26000 pa. what is the height of the mercury in the beaker? the acceleration of gravity is 9.81 m/s 2 .

Answers

The mercury density (at liquid state) is
[tex]\rho = 13.5 g/cm^3=13500 kg/m^3[/tex]

And we know that the pressure at the bottom of a column of fluid is given by (Stevin's law)
[tex]p=\rho g h[/tex]
where
[tex]\rho[/tex] is the liquid density
g is the gravitational acceleration
h is the height of the column of fluid

The pressure at the bottom of the beaker is [tex]p=26000 Pa[/tex], therefore we can re-arrange the previous equation to get the height of the column of mercury
[tex]h= \frac{p}{\rho g}= \frac{26000 Pa}{(13500 kg/m^3)(9.81 m/s^2)}=0.196m = 19.6 cm [/tex]
Other Questions
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