One serving of soybeans contains 14 grams of protein and 8 grams of fat. One serving of rice contains 4 grams of protein and 1/2 gram of fat. Calculate the number of servings of each that need to be combined, in order to end up with precisely 30 grams of protein and 15 grams of fat. How many servings of rice will be needed?

Answer:

A, B, and E

if I read your functions right.

Step-by-step explanation:

It's zeros are x=-6,-2, and 2.

This means we want the factors (x+6) and (x+2) and (x-2) in the numerator.

It has a y-intercept of 4.  This means we want to get 4 when we plug in 0 for x.

And it's long-run behavior is y approaches - infinity as x approaches either infinity.  This means the degree will be even and the coefficient of the leading term needs to be negative.

So let's see which functions qualify:

A) The degree is 4 because when you do x^2*x*x you get x^4.

The leading coefficient is -4/144 which is negative.

We do have the factors (x+6), (x+2), and (x-2).

What do we get when plug in 0 for x:

[tex]\frac{-4}{144}(0+6)^2(0+2)(0-2)[/tex]

Put into calculator:  4

A works!

B) The degree is 6 because when you do x*x^4*x=x^6.

The leading coefficient is -4/192 which is negative.

We do have factors (x+6), (x+2), and (x-2).

What do we get when we plug in 0 for x:

[tex]\frac{-4}{192}(0+6)(0+2)^4(x-2)[/tex]

Put into calculator: 4

B works!

C) The degree is 4 because when you do x*x*x*x=x^4.

The leading coefficient is -4 which is negative.

Oops! It has a zero at 0 because of that factor of (x) between -4 and (x+6).

So C doesn't work.

D) The degree is 3 because x*x*x=x^3.

We needed an even degree.

D doesn't work.

E) The degree is 4 because x*x^2*x=x^4.

The leading coefficient is -4/48 which is negative.

It does have the factors (x+6), (x+2), and (x-2).

What do we get when we plug in 0 for x:

[tex]\frac{-4}{48}(0+6)(0+2)^2(0-2)[/tex]

Put into calculator: 4

So E does work.

F) The degree is 4 because x*x*x^2=x^4.

The leading coefficient is -4/48.

It does have factors (x+6), (x+2), and (x-2).

What do we get when we plug in 0 for x:

[tex]\frac{-4}{48}(0+6)(0+2)(0-2)^2[/tex]

Put into calculator: -4

So F doesn't work.

G. I'm not going to go any further. The leading coefficient is 4/48 and that is not negative.

So G doesn't work.

Answer:

Step-by-step explanation:

Notice that we have 3 zeros, which means there are only 3 roots, which are -6, -2 and 2, this indicates that our expression must be cubic with the binomials (x+6), (x+2) and (x-2).

We this analysis, possible choices are C and D.

Now, according to the problem, it has y-intercept at y = 4, so let's evaluate each expression for x = 0.

[tex]y=-4x(x+6)(x+2)(x-2)\\y=-4(0)(0+6)(0+2)(0-2)\\y=0[/tex]

[tex]y=-\frac{4}{24} (x+6)(x+2)(x-2)\\y=-\frac{4}{24}(0+6)(0+2)(0-2)\\y=-\frac{4}{24}(-24)\\ y=4[/tex]

Therefore, choice D is the right expression because it has all given characteristics.

Answer:

The percentage of customer returns is 7%.

Step-by-step explanation:

Given,

Total gross sales = $ 7,500

Returns are,

$95 on Monday, $19 on Tuesday, $50 on Wednesday, $140 on Thursday, $160 on Friday, and $80 on Saturday,

So, the total returns = $ 95 + $ 50 + $ 140 + $ 160 + $ 80 = $ 525,

Hence, the percent of customer returns for the week = [tex]\frac{\text{Total returns}}{\text{Total gross sales}}\times 100[/tex]

[tex]=\frac{525}{7500}\times 100[/tex]

[tex]=\frac{52500}{7500}[/tex]

[tex]=7\%[/tex]

Answer: There would be 9 possibilities.

Step-by-step explanation:

Given : The number of regions in the spinner = 3

if we spin the spinner twice, then by using fundamental principal of counting , the number of possibilities is given by :-

[tex]3\times3=9[/tex]

Therefore, there would be 9 possibilities.

In a length-13 string of all uppercase letters, there are 26^13 possible strings. The number of strings that contain the word CHARITY is 26^6, and the number of strings that contain neither CHARITY nor HORSES is 26^13 - 26^6 - 26^7.

(a) To find the number of length-13 strings of all uppercase letters, we can use the formula: number of choices for each position (26) raised to the power of the number of positions (13). So, there are 26^13 possible strings.

(b) To find the number of strings that contain the word CHARITY, we can treat it as one block, which leaves us with 6 other available spaces. So, there are 26^6 strings that contain the word CHARITY.

(c) To find the number of strings that contain neither the word CHARITY nor the word HORSES, we can subtract the number of strings that contain CHARITY or HORSES from the total number of strings. So, the answer is 26^13 - 26^6 - 26^7.

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You correctly calculated the total number of strings in part (a), but part (b) requires multiplying by the number of possible positions for 'CHARITY'. For part (c), the initial calculation is correct after fixing part (b), as the words 'CHARITY' and 'HORSES' cannot both fit in a 13-letter string without overlapping.

The question involves calculating the number of possible strings using combinatorics and the rules of permutation.

For part (a), you correctly calculated the number of length-13 strings of uppercase letters as 26^13, since each position in the string can be occupied by any of the 26 letters of the alphabet.

In part (b), treating CHARITY as a single block and having 6 additional characters is almost correct, but you need to account for the positions where the block can start. There are 7 possible starting positions for 'CHARITY' in a 13-character string, so you need to multiply your answer by 7, giving 7 * 26^6.

For part (c), the calculation is more complex because you have to account for overlapping cases and ensure they are not subtracted twice. Subtracting 26^6 for 'CHARITY' strings and 26^7 for 'HORSES' strings from 26^13 doesn't account for the possibility of having both words in the string. However, since 'CHARITY' and 'HORSES' cannot both fit in a 13-letter string without overlap, your initial method would work here, but you still need to correct part (b) as explained. So the corrected calculation for (c) would remain at 26^13 - 7 * 26^6 - 26^7.

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Answer:

We have a normal distribution with a mean of 267 days and a standard deviation of 15 days. To solve this proble we're going to need the help of a calculator.

a. The probability of a pregnancy lasting 309 days or longer is:

P(z>309) = 0.0026 or 0.26%

b. The lowest 4% is separeted by the 240.74 days. The probability of pregnancy lasting 240.74 days is 4%.

Answer:

a) 0.26% probability of a pregnancy lasting 309 days or longer.

b) A pregnancy length of 241 days separates premature babies from those who are not premature.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

[tex]\mu = 267, \sigma = 15[/tex]

a. Find the probability of a pregnancy lasting 309 days or longer.

This is 1 subtracted by the pvalue of Z when X = 309. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{309 - 267}{15}[/tex]

[tex]Z = 2.8[/tex]

[tex]Z = 2.8[/tex] has a pvalue of 0.9974

So there is a 1-0.9974 = 0.0026 = 0.26% probability of a pregnancy lasting 309 days or longer.

b. If the length of pregnancy is in the lowest 4​%, then the baby is premature. Find the length that separates premature babies from those who are not premature.

This is the value of X when Z has a pvalue of 0.04. So X when Z = -1.75

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1.75 = \frac{X - 267}{15}[/tex]

[tex]X - 267 = -1.75*15[/tex]

[tex]X = 240.75[/tex]

A pregnancy length of 241 days separates premature babies from those who are not premature.

Answer:

Given inequality is,

-12 + 5(9p+3) - 36p < 6p - 12

By distributive property,

-12 + 45p + 15 - 36p < 6p - 12

Combine like terms,

3 + 9p < 6p - 12

Additive property of equality,

15 + 9p < 6p

Subtraction property of equality,

9p < 6p - 15

3p < -15

⇒ p < -5

That is, solution of the given inequality is (-∞, 5)

Answer:

[tex]x+\frac{-1}{3} \ln|x|+\frac{-8}{3}\ln|x+3|+C[/tex]

Step-by-step explanation:

To use partial fractions, I'm going to first do long division because the degree of the top is more than or equal to that of the bottom.

After I have that the degree of the bottom is more than the degree of the top, I will factor my bottom to figure out what kinds of partial fractions I'm going to have.

Let's begin with the long division:

The bottom goes outside.

The top goes inside.

                                      1

                                  -----------------

                    x^2+3x|    x^2          -1

                                  -(x^2+3x)

                              -----------------------------

                                          -3x       -1

We can not going any further since the divisor is more in degree than the left over part.

So we have so for that the integrand given equals:

[tex]\frac{x^2-1}{x^2+3x}=1+\frac{-3x-1}{x^2+3x}[/tex]

The 1 will of course not need partial fraction.

So we know our answer is x +  something   + C

Since the derivative of (x+c)=(1+0)=1.

Let's focus now on:

[tex]\frac{-3x-1}{x^2+3x}[/tex]

The bottom is not too bad too factor because it is binomial quadratic containing terms with a common factor of x:

[tex]x^2+3x=x(x+3)[/tex]

Since both factors our linear and there are two factors, then we will have two partial fractions where the numerators are both constants.

So we are looking to make this true:

[tex]\frac{-3x-1}{x^2+3x}=\frac{A}{x}+\frac{B}{x+3}[/tex]

Some people like to combine the fractions on the left and then regroup the terms and then compare coefficients.

Some people also prefer a method called heaviside method.

So I'm actually going to do this last way and I will explain it as I got.

We are going to clear the fractions by multiplying both sides by [tex]x(x+3)[/tex] giving me:

[tex]-3x-1=A(x+3)+Bx[/tex]

I know x+3 will be 0 when x=-3  so entering in -3 for x gives:

[tex]-3(-3)-1=A(-3+3)+B(-3)[/tex]

[tex]9-1=A(0)-3B[/tex]

[tex]8=-3B[/tex]

Divide both sides by -3:

[tex]\frac{8}{-3}=B[/tex]

[tex]B=\frac{-8}{3}[/tex]/

Now let's find A. If I replace x with 0 then Bx becomes 0 giving me:

[tex]-3(0)-1=A(0+3)+B(0)[/tex]

[tex]-1=A(3)+0[/tex]

[tex]-1=3A[/tex]

Divide both sides by 3:

[tex]\frac{1}{-3}=A[/tex]

[tex]\frac{-1}{3}=A[/tex]

Okay let me also who you other method of just comparing coefficients.

[tex]-3x-1=A(x+3)+Bx[/tex]

Distribute on the right:

[tex]-3x-1=Ax+3A+Bx[/tex]

Regroup terms on right so like terms are together:

[tex]-3x-1=(A+B)x+3A[/tex]

Now if this is to be true then we need:

-3=A+B        and         -1=3A

The second equation can be solved by dividing both sides by 3 giving us:

-3=A+B        and        -1/3=A

Now we are going to plug that second equation into the first:

-3=A+B  with A=-1/3

-3=(-1/3)+B

Add 1/3 on both sides:

-3+(-1/3)=B

-8/3=B

So either way you should get the same A and B if no mistake is made of course.

So this is the integral we are looking at now (I'm going to go ahead and include the 1 from earlier):

[tex]\int (1+\frac{\frac{-1}{3}}{x}+\frac{\frac{-8}{3}}{x+3})dx[/tex]

[tex]x+\frac{-1}{3} \ln|x|+\frac{-8}{3}\ln|x+3|+C[/tex]

Why I did choose natural log for both of those 2 terms' antiderivatives?

Because they are a constant over a linear expression. Luckily both of those linear expressions had a leading coefficient of 1.

Also recall the derivative of ln(x) is (x)'/x=1/x and

the derivative of ln(x+3) is (x+3)'/(x+3)=(1+0)/(x+3)=1/(x+3).

Let's check our answer:

To do that we need to differentiate what we have for the integral and see if we wind up with the integrand.

[tex]\frac{d}{dx}(x+\frac{-1}{3} \ln|x|+\frac{-8}{3}\ln|x+3|+C)[/tex]

[tex]1+\frac{-1}{3} \frac{1}{x}+\frac{-8}{3}\frac{1}{x+3}+0[/tex]

We are going to find a common denominator which would be the least common multiple of the denominators which is x(x+3):

[tex]\frac{x(x+3)+\frac{-1}{3}(x+3)+\frac{-8}{3}(x)}{x(x+3)}[/tex]

Now distribute property:

[tex]\frac{x^2+3x+\frac{-1}{3}x-1+\frac{-8}{3}x}{x^2+3x}[/tex]

Combine like terms:

[tex]\frac{x^2+3x+\frac{-9}{3}x-1}{x^2+3x}[/tex]

[tex]\frac{x^2+3x-3x-1}{x^2+3x}[/tex]

[tex]\frac{x^2-1}{x^2+3x}[/tex]

So that is the same integrand we started with so our answer has been confirmed.

[tex]A=\{a,b,c,d\}\\|A|=4\\\mathcal{P}(A)=2^4=16[/tex]

Answer:

B. f−1(x) = The quantity of 4x plus 3, divided by 5

Step-by-step explanation:

Given

[tex]f(x) = \frac{5x-3}{4}[/tex]

We have to find the inverse of the function

[tex]Let\\f(x) = y\\y=\frac{5x-3}{4}\\4y=5x-3\\4y+3=5x\\\frac{4y+3}{5} =y[/tex]

So, the inverse of f(x) is:

[tex]\frac{4y+3}{5}[/tex]

Hence,

The correct answer is:

B. f−1(x) = The quantity of 4x plus 3, divided by 5 ..

Final answer:

The statement 'The chair is broken or the stove is not hot' translates to 'p v ~q' in symbolic form, where 'p' represents 'The chair is broken,' and 'q' represents 'The stove is hot.' The 'v' symbolizes 'or,' and '~' indicates negation.

Explanation:

The question requests the compound statement 'The chair is broken or the stove is not hot' be written in symbolic form using propositional logic. Given the statements, p is 'The chair is broken,' and q is 'The stove is hot,' we can translate the request into symbolic form. The use of 'or' in propositional logic is represented by the symbol 'v' (wedge), and the negation of a statement is represented by the symbol '~' (tilde). Therefore, 'The stove is not hot' can be represented as '~q'.

To combine these statements into the requested compound statement, we use:
p v ~q
This reads as 'p or not q', which translates back into the original statement 'The chair is broken or the stove is not hot.' This allows us to see how logical operators like disjunction ('or') and negation ('not') work together to construct compound statements in propositional logic.

The work done by [tex]\vec F[/tex] is

[tex]\displaystyle\int_C\vec F\cdot\mathrm d\vec r[/tex]

where [tex]C[/tex] is the given curve and [tex]\vec r(t)[/tex] is the given parameterization of [tex]C[/tex]. We have

[tex]\mathrm d\vec r=\dfrac{\mathrm d\vec r}{\mathrm dt}\mathrm dt=k(1-2t)\,\vec\imath+\vec\jmath[/tex]

Then the work done by [tex]\vec F[/tex] is

[tex]\displaystyle\int_0^1((t-kt(1-t))\,\vec\imath+kt^2(1-t)\,\vec\jmath)\cdot(k(1-2t)\,\vec\imath+\vec\jmath)\,\mathrm dt[/tex]

[tex]=\displaystyle\int_0^1((k-k^2)t-(k-3k^2)t^2-(k+2k^2)t^3)\,\mathrm dt=-\frac k{12}[/tex]

In order for the work to be 1, we need to have [tex]\boxed{k=-12}[/tex].

Answer:

Option D. is the answer.

Step-by-step explanation:

The given statement is [tex]\frac{a}{b}+\frac{c}{d}=\frac{a+c}{b+d}[/tex]

Now we have to find a counter example from the given options that the statement is False.

A. a = 3, b = 5, c = -3, d = 5

[tex]\frac{a}{b}+\frac{c}{d}=\frac{a+c}{b+d}[/tex]=[tex]\frac{3}{5}+\frac{-3}{5}=\frac{3-3}{5+5}[/tex]

0 = 0

So the given statement is true.

B. a = 0, b = 4, c = 0, d= 9

[tex]\frac{a}{b}+\frac{c}{d}=\frac{a+c}{b+d}[/tex]

0 + 0 = 0

So for this example the given statement is true.

C. a = -2, b = 1, c = 2, d = 1

[tex]\frac{a}{b}+\frac{c}{d}=\frac{a+c}{b+d}[/tex]

[tex]\frac{-2}{1}+\frac{2}{1}=\frac{-2+2}{1+1}[/tex]

0 = 0

Statement is true for these values.

D. a = 1, b = 2, c = 1, d = 2

[tex]\frac{a}{b}+\frac{c}{d}=\frac{a+c}{b+d}[/tex]

[tex]\frac{1}{2}+\frac{1}{2}=\frac{1+1}{2+2}[/tex]

[tex]1=\frac{1}{2}[/tex]

Therefore, for these values of a, b, c and d, the given statement is False.

Option D. is the answer.

To find a counter example for the given statement, we need to test the options provided. However, all the options satisfy the equation, indicating that the statement holds true for all nonzero real numbers.

To find a counter example for the given statement, we need to find values for a, b, c, and d that make the equation a/b + c/d = a+c/b+d false. Let's consider the options given:

We can see that for all the options, the equation holds true. Therefore, there is no counter example and the statement is true for all nonzero real numbers.

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Answer:

d) stigma

Step-by-step explanation:

Secondary deviance marks the start of what Erving Goffman called a deviant career, which results in the acquisition of a stigma.

The correct answer is d) stigma.

According to Erving Goffman, secondary deviance is the process that occurs when an individual who has been labeled as deviant begins to accept the label and act in accordance with it. This acceptance and incorporation of the deviant label into one's self-concept can lead to a deviant career, which is a pattern of behavior that increasingly conforms to the label. The result of this process is the acquisition of a stigma, which is a powerful and discrediting social label that radically changes a person's self-concept and social identity.

To understand this concept, let's break it down:

- Primary deviance is the initial act of rule-breaking that may or may not be known to others. It does not necessarily lead to a deviant career.

- Secondary deviance occurs when others react to the primary deviance by labeling the individual as deviant. This labeling can lead to a self-fulfilling prophecy where the individual begins to adopt the identity of a deviant.

- The term ""stigma"" refers to a mark of disgrace associated with a particular circumstance, quality, or person. Goffman describes stigma as a discrepancy between virtual social identity and actual social identity.

- ""Anomie"" is a concept developed by Émile Durkheim, referring to a state of normlessness in society that can lead to deviant behavior, but it is not directly related to the concept of a deviant career as described by Goffman.

- ""Verstehen"" is a term used by Max Weber, referring to a deep form of understanding that is essential for social science, but it is not related to the acquisition of a label due to deviant behavior.

- A ""criminal record"" is a formal legal document that records a person's criminal history, but it is not the term Goffman used to describe the social label acquired as a result of secondary deviance.

Therefore, the correct term that fits Goffman's description of the result of a deviant career following secondary deviance is ""stigma.""

Answer:

Robin's gross pay=$50,400

Step-by-step explanation:

We are given that Robin has 15% of his gross pay directly into his mutual fund account each month.

If Robin  deposited each month =$630

We have to find the gross pay

Let Robin's gross pay =x

15 % of gross pay= 15% of x=[tex]\frac{15}{100}\times x=\frac{15}{100}x[/tex]

We know that 12 month in a year

[tex] \frac{15}{100}x=630\times 12[/tex]

[tex] 15x=630\times 100\times 12[/tex]

Using multiplication property of equality

[tex] x=\frac{756000}{15}[/tex]

Using division property of equality

[tex]x=50400[/tex]

Hence, Robin's gross pay=$50,400

Answer:

Step-by-step explanation:

Given that X is the height, in inches, of American men. The mean and standard deviation for American men's height are 69 inches and 3 inches, respectively.

X is N(69,3)

If a sample of 25 american men are selected the mean would remain the same.

But std dev becomes 3/sqrt 25=0.60

Hence sample height will follow

N(69, 0.60)

The value is 5 weeks

To find out how many weeks the oil will last with a specific usage per week, divide the total oil amount by the weekly usage, resulting in 5 weeks.

The oil barrel holds 53 3/4 gallons of oil, and 10 3/4 gallons are used every week.

To determine how many weeks the oil will last, you need to divide the total amount of oil by the weekly usage.

Answer:

There are 225 adult tickets.

Step-by-step explanation:

Let the number of adult tickets but represented by A while the number of student tickets be represented by S.

We are told the total is 391, so A+S=391.

There are 59 fewer student tickets (S) sold than adult tickets (T).

So there are 59 more adult tickets which means, A=59+S.

We are going to solve the system:

A+S=391

A=59+S

--------------------------------------------------

We are going to input the second equation into the first:

A+S=391 with A=59+S

(59+S)+S=391

59+S+S=391

59+2S=391

Subtract 59 on both sides:

2S=391-59

2S=332

Divide both sides by 2:

S=332/2

S=166

So A=59+S given S=166 means A=59+166=225.

There are 225 adult tickets while there is 166 student tickets.

Let's say the adult tickets would be X and the student tickets would be

X - 59.

Let's add them up. X + X - 59 = 391

2x = 450

x = 225

If there are 225 student tickets, we know that there are 63 fewer adult tickets so we take 225 and subtract 59 and we will get an answer of 166.

225 adult tickets were sold.

Answer:

6.67 ft

Step-by-step explanation:

   Let d = distance

 and w = weight

Then d = k/w

 or dw = k

 Let d1 and w1 represent Roger

and d2 and w2 represent Ellen. Then

d1w1 = d2w2

Data:

d1 = 6 ft; w1  = 120 lb

d2 = ?    ; w2 = 108 lb

Calculation:

6 × 120 = 108d2

       720 = 108d2

         d2 = 720/108 = 6.67 ft

Ellen must sit 6.67 ft from the fulcrum.

Ellen must sit approximately 6.67 feet from the fulcrum to balance the seesaw.

To solve this problem, we'll use the principle of inverse proportionality. The relationship between the distance from the fulcrum and the weight of the person can be expressed as:

[tex]\[ \text{Distance} \times \text{Weight} = \text{Constant} \][/tex]

Step 1:

Determine the constant of proportionality.

Since Roger weighs 120 pounds and sits 6 feet from the fulcrum, we can use his information to find the constant:

[tex]\[ 6 \times 120 = 720 \][/tex]

Step 2:

Use the constant to find Ellen's distance from the fulcrum.

Ellen weighs 108 pounds. We'll use the constant to find her distance:

[tex]\[ \text{Distance} \times 108 = 720 \][/tex]

[tex]\[ \text{Distance} = \frac{720}{108} \][/tex]

Step 3:

Calculate Ellen's distance from the fulcrum.

[tex]\[ \text{Distance} \approx 6.67 \text{ feet} \][/tex]

Therefore, Ellen must sit approximately 6.67 feet from the fulcrum to balance the seesaw.

Answer:

[tex]\frac{208}{1091}[/tex]

Step-by-step explanation:

To find probability of x, we need to find the number of x divided by total number.

Here,

Total = 208 + 552 + 331 = 1091

Number of help dash wanted ad = 208

Hence, the probability that the ad for a specific week is a help dash wanted ad = 208/1091

Answer: The value of cos theta is -0.352.

Step-by-step explanation:

Since we have given that

[tex]\vec{u}=1\hat{i}+2\hat{j}-2\hat{k}\and\\\\\vec{w}=\hat{j}+4\hat{k}[/tex]

We need to find the cos theta between u and w.

As we know the formula for angle between two vectors.

[tex]\cos\ \theta=\dfrac{\vec{u}.\vec{w}}{\mid u\mid \mid w\mid}[/tex]

So, it becomes,

[tex]\cos \theta=\dfrac{2-8}{\sqrt{1^2+2^2+(-2)^2}\sqrt{1^2+4^2}}\\\\\cos \theta=\dfrac{-6}{\sqrt{17}\sqrt{17}}=\dfrac{-6}{17}=-0.352\\\\\theta=\cos^{-1}(\dfrac{-6}{17})=110.66^\circ[/tex]

Hence, the value of cos theta is -0.352.

1197 hours, 48 minutes

is equal to

1197 + 48/60 hours

Dividing by 53 gives

1197/53 + 48/3180 hours

Since

1197 = 22*53 + 31

we get

22 + 31/53 + 48/3180 hours

22 + (1860 + 48)/3180 hours

22 + 3/5 hours

22 + 36/60 hours

22 hours, 36 minutes

Answer: 0.3413

Step-by-step explanation:

Given :Mean : [tex]\mu=60\text{ weeks}[/tex]

Standard deviation : [tex]\sigma = 5\text{ weeks}[/tex]

The formula for z -score :

[tex]z=\dfrac{x-\mu}{\sigma}[/tex]

For x= 60 ,

[tex]z=\dfrac{60-60}{5}=0[/tex]

For x= 65 ,

[tex]z=\dfrac{65-60}{5}=1[/tex]

The p-value = [tex]P(0<z<1)=P(z<1)-P(z<0)[/tex]

[tex]= 0.8413447-0.5= 0.3413447\approx0.3413[/tex]

Hence,  the probability that the project will take anywhere between 60 and 65 weeks to complete = 0.3413.

Final answer:

The probability that the project will take anywhere between 60 and 65 weeks to complete is 0.3413

Explanation:

To find the probability that the project will take anywhere between 60 and 65 weeks to complete, we need to calculate the z-scores for both 60 and 65 weeks using the given mean and standard deviation.

The formula to calculate the z-score is z = (x - mean) / standard deviation.

For 60 weeks, the z-score is (60 - 60) / 5 = 0, and for 65 weeks, the z-score is (65 - 60) / 5 = 1.

Next, we use the z-scores to find the corresponding probabilities using a standard normal distribution table or a calculator. The probability that the project will take anywhere between 60 and 65 weeks can be calculated as the difference between the two probabilities: P(60 ≤ x ≤ 65) = P(x ≤ 65) - P(x ≤ 60).

= 0.8413447 - 0.5

= 0.3413

Step-by-step explanation:

Given that

[tex]ax^2+bx+c=0[/tex]  

Where a,b,and c are odd integers.

We know that solution of quadratic equation given by following formula

[tex]z=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

Now we have to prove that above solution is a irrational number when a,b and c all are odd numbers.

Let's take a=3  ,b=9 ,c= -3   these are all odd numbers.

Now put the values

[tex]z=\dfrac{-9\pm \sqrt{9^2-4\times 3\times (-3)}}{2\times 3}[/tex]

So

[tex]z=\dfrac{-9\pm \sqrt{117}}{6}[/tex]

We know that square roots,cube roots etc are irrational number .So we can say that above value z is also a irrational number.

When we will put any values of a,b and c (they must be odd integers) oue solution will be always irrational.

Final answer:

The discriminator of the quadratic equation with odd a, b, and c is odd, making its square root and thus the solution z irrational.

Explanation:

Consider the quadratic equation ax2 + bx + c = 0, where a, b, and c are odd integers. To find the solution to this equation, we can use the quadratic formula.

The quadratic formula states that the solutions to the equation ax2 + bx + c = 0 are given by x = (-b ± sqrt(b2 - 4ac))/(2a). We need to consider the discriminant, b2 - 4ac, to prove whether the solution z is rational or irrational.

Since a, b, and c are odd integers, b2 is also an odd number (odd times odd is odd), and 4ac is an even number (even times odd is even). Therefore, b2 - 4ac is the difference between an odd and an even number, which is odd. An even number has a square root that is an integer or rational, but an odd number does not have an integer square root, making it an irrational number. Because the square root of an odd number is irrational, the solutions z must also be irrational.

Answer:

See below.

Step-by-step explanation:

I'll show you step by step how to do the synthetic division.

You are dividing polynomial -6x^4 + 22x^3 + 3x^2 + 15x + 20 by x - 4.

From the polynomial, you only need the coefficients in descending order of degree as they are written.

         -6    22    3    15    20

In synthetic division, you divide by x - b. You are dividing by x - 4, so b = 4.

The 4 is written to the left of the coefficients of the polynomial.

      ___________________

4   |       -6    22    3    15    20

      ___________________

This is what the setup looks like. You can see it in the problem you were given.

The first step is to just copy the leftmost coefficient straight down to below the line.

      ___________________

4   |       -6    22    3    15    20

      ___________________

             -6

Now multiply b, which is 4, by -6 and write it above and to the right.

     ___________________

4   |       -6    22    3    15    20

                    -24

      ___________________

            -6

Add 22 and -24 and write it next to -6.

     ___________________

4   |       -6    22    3    15    20

                    -24

      ___________________

             -6     -2

Multiply 4 by -2 and write it above and to the right. Add vertically.

     ___________________

4   |       -6    22     3    15    20

                    -24   -8

      ___________________

             -6     -2    -5

Multiply 4 by -5 and write it above and to the right. Add vertically.

     ___________________

4  |       -6    22     3    15    20

                    -24   -8   -10

      ___________________

             -6     -2    -5   -5

Multiply 4 by -5 and write it above and to the right. Add vertically.

     ___________________

4   |       -6    22     3    15    20

                    -24   -8   -10   -20

      ___________________

             -6     -2    -5   -5      0

The 4 numbers in the second line are the coefficients of the quotient.

The quotient is 1 degree less than the original polynomial.

The quotient is: -24x^3 - 8x^2 - 10x - 20

The last number on the third line is the remainder. Since here the reminder is zero, that means that this division has no remainder. The remainder is 0/(x - 4)

Fill in the boxes with:

-24, -8, -10, -20

-6, -2, -5, -5, 0

-24x^3 - 8x^2 - 10x - 20

0

The probability that a bottle of ketchup contains less than 17.5 oz, given a normal distribution with a mean of 17.6 oz and a standard deviation of 0.05 oz, is approximately 2.28%.

The question is asking for the probability that a bottle of ketchup contains less than 17.5 oz, given that the distribution of ketchup amounts in the bottle is normally distributed with a mean of 17.6 oz and a standard deviation of 0.05 oz. In terms of a normal distribution chart, we are looking for the area under the curve to the left of 17.5 oz.

To find this, we need to first convert our 17.5 oz to a standard score (or z-score). The z-score represents how many standard deviations away from the mean a data point is. It is calculated using the formula:

z = (X - μ) / σ

Where X is the data point (17.5 oz), μ is the mean (17.6 oz), and σ is the standard deviation (0.05 oz). Using this formula, we find z = -2.

Now, to find the probability, we can refer to a standard normal distribution table. The area under the curve to the left of z = -2 (which represents a data point of 17.5 oz) is approximately 0.0228, or 2.28%. Therefore, the probability that a bottle of ketchup contains less than 17.5 oz is about 2.28%.

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Answer:1.8701

Step-by-step explanation:

Area (A) of trapezium as marked is =[tex]\frac{1}{2}[/tex][tex]\left ( sum\ of\ parallel\ sides\right )\times height[/tex]

A=[tex]\frac{1}{2}[/tex][tex]\left ( 3+6\right )\times 4[/tex]

A=18[tex]in^2[/tex]

Now for Volume we have to multiply by length because area is same across the length.

volume(v)=[tex]A\times length[/tex]

Volume(v)=[tex]18\times 24[/tex]

Volume(v)=432 [tex]in^3[/tex]

Volume(v)=1.8701 gallon

I see 4 pairs of vertical angles and they are:

7/9

8/10

11/13

12/14

Answer:

4 pairs

Step-by-step explanation:

vertical angles are opposite angles formed by two intersecting lines.

please thank if you learned from this answer.

Answer:

13

Step-by-step explanation:

For m||n to be true, we would need to have those angles equal, or 7x-21 = 4x+18.

Solve this equation, and get 3x=39 or x=13.

value of  x = 13.

Equal angles are those that are vertically opposed, such as a = d and b = c. Adjacent angles add up to 180 degrees, as in the cases where a + b and a + c. Angles that correspond to one another are equal, such as a=e, b=f, c=g, and d=h. Interior angles combine to make 180 degrees, such as c plus e or d plus f. Equal alternate angles are c = f and d = e.

Given a figure, one line is intersecting the two parallel lines known as m and n. since both given angles are equal alternate angles hence both angles would be the same.

Hence,

4x + 18 = 7x - 21

x =13

Therefore, in the given drawing the value of x needs to be 13.

Learn more about angle here:

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912 cards in all

If there are 114 packs of cards and 8 in each you multiply 114 by 8 and get 912.

To find the total number of baseball cards, multiply the number of packs (144) by the number of cards in each pack (8), resulting in a total of 1,152 cards.

If a gross of baseball cards contains 144 packs of cards and each pack contains 8 baseball cards, the total number of cards would be calculated by multiplying the number of packs by the number of cards in each pack.

To get the total number of baseball cards.

144 packs x 8 cards/pack = 1,152 cards

Hence, a gross of baseball cards contains 1,152 cards in total.

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