Our goal here is to predict whether an accident just reported will involve an injury (MAX_SEV_IR = 1 or 2) or will not (MAX_SEV_IR = 0). For this purpose, create a dummy variable called INJURY that takes the value "yes" if MAX_SEV_IR = 1 or 2, and otherwise "no."

Answer:

See explaination for program code

Explanation:

%save as AdjustMinValue.m

%Matlab function that takes three arguments

%called number of samples count, user samples

%and min vlaue and then returns a data samples

%that contains values which are double of usersamples

%that less than min vlaue

%

function dataSamples=AdjustMinValue(numberSamples, userSamples, minValue)

dataSamples=userSamples;

%for loop

for i=1:numberSamples

%checking if dataSamples value at index,i

%is less than minValue

if dataSamples(i)<minValue

%set double of dataSamples value

dataSamples(i)= 2*dataSamples(i);

end

end

end

Sample output:

Note:

File name and calling method name must be same

--> AdjustMinValue(4, [2,12,9,20],10)

ans =

4 12 18 20

Final answer:

To determine the number of coins that player 2 will spend in a given round of the game, check the rules based on the value of the round: divisible by 3 = 3 coins, divisible by 2 but not by 3 = 2 coins, not divisible by 3 and not divisible by 2 = 1 coin.

Explanation:

To determine the number of coins that player 2 will spend in a given round of the game, we need to check the rules based on the value of the round:

If the round is divisible by 3, player 2 will spend 3 coins.

If the round is not divisible by 3 but is divisible by 2, player 2 will spend 2 coins.

If the round is not divisible by 3 and not divisible by 2, player 2 will spend 1 coin.

So, the method getPlayer2Move should be defined as follows:

public

int getPlayer2Move(int round)

{

if (

round % 3 == 0) { return 3;

}

else if

(

round % 2 == 0

) {

return 2;

} else {

return 1;

} }

Final answer:

The getPlayer2Move method returns 1, 2, or 3 based on the given rules.

Explanation:

The method getPlayer2Move returns 1, 2, or 3 based on the rules given in the question. If the round number is divisible by 3, the method returns 3. If the round number is not divisible by 3 but is divisible by 2, the method returns 2. If the round number is not divisible by 3 and not divisible by 2, the method returns 1. For example, if the round number is 4, which is divisible by 2 but not divisible by 3, the method would return 2.

Answer:

0 This is base class

Derived class: 9

16 Hello Base

Explanation:

The header files #include <iostream> #include <string> was wrongly included in the question this had to be edited.

After properly editing the programme to remove errors, the expected output when you run the code is:

0 This is base class

Derived class: 9

16 Hello Base

Final answer:

The C++ program demonstrates class inheritance and method overriding. The output for the baseClass object is "2 This is the base class", and for the derivedClass object is "Derived class: 7" followed by "10 Hello Base".

Explanation:

The provided C++ program defines two classes, baseClass and derivedClass, which demonstrate basic inheritance and method overriding. The main() function creates instances of these classes and calls their print() methods. The output of this program is determined by the details of the print methods.

When baseObject.print() is called, it triggers baseClass::print(), outputting the value of x and str for the base object, which are initialized in the baseClass constructor. The output would be "2 This is the base class".

Calling derivedObject.print() triggers derivedClass::print(), which first outputs the phrase "Derived class: " and the value of y from the derivedClass object, followed by the properties of the base class part of the same object, as per the constructor which passed "Hello Base", a (x in the base class), and the sum a + b. The resulting output would be "Derived class: 7" followed by "10 Hello Base" on a new line.

Final answer:

The lab involves analysis of financial ratios, banking operations evaluation using T-account balance sheets, and quantitative modeling in biology, highlighting the importance of data analysis across disciplines.

Explanation:

The request refers to a step-by-step completion of a lab that involves interpreting financial data, specifically using an income statement to calculate various ratios for company analysis. The lab directs students to use specific data analysis tools and apply concepts such as the money multiplier and T-account balance sheets to evaluate banking operations. One part of the lab requires creating a spreadsheet to analyze data in terms of mass fractions relative to sodium, underlining the importance of quantitative modeling skills, even in biology.

Moreover, statistics play a role in the exercise, as students must calculate measures such as mean, standard deviation, median, and interquartile range. The lab encompasses a cross-disciplinary approach, including data analysis in biology and economics, showcasing how quantitative skills are leveraged in diverse fields.

Lastly, the lab also involves learning how to collect and interpret data, which includes skills like observation, sketching, using geography tools, and graphical interpretation. These fundamental skills are critical for successful data analysis in various academic and professional contexts.

Answer:

See explaination

Explanation:

Merge sort working-

1.type of recursive sorting algorithm.

2.divides given array into halves.

3. Sort each halves. Merge this halves to give a sorted array.

4. Recursive call continues till array is divided and each piece has only one element.

5. Merge this small pieces to get a sorted array.

Binary search-

1. It is a search algorithm.

2. Requires a sorted array to work on.

3.Works repetively dividing a half portion of list that could contain item until it has narrowed down the possible location to just one.

Comparing Merge sort and Binary Search using Big O notation-

Merge Sort - O(n*log(n)) in all scenario whether best, average or worst case.

Binary Search- O(log(n)) in average and worst case. O(1) in best case.

So seeing the above comparison Binary search is faster.

Comparing Binary search and displaying the integers-

Binary Search- O(log(n)) in average and worst case. O(1) in best case.

Displaying the integer-O(1) if already initialized, O(n) in case of loop or function.

So seeing above one can conclude that binary search is fast. But in best case both works in a similar manner.

Final answer:

The pseudocode provided defines two functions, fahrenheitToCelsius and celsiusToFahrenheit, which perform temperature conversions between Fahrenheit and Celsius, and a main module for user interaction to perform and display the conversions.

Explanation:

Here is the pseudocode for two temperature conversion functions and a main module to interact with the user.

Function: fahrenheitToCelsius

Input: Real fahrenheitTemperature
Output: Real celsiusTemperature
Begin
   Set celsiusTemperature to (fahrenheitTemperature - 32) * (5.0 / 9.0)
   Return celsiusTemperature
End

Function: celsiusToFahrenheit

Input: Real celsiusTemperature
Output: Real fahrenheitTemperature
Begin
   Set fahrenheitTemperature to (celsiusTemperature * (9.0 / 5.0)) + 32
Return fahrenheitTemperature
End

Main Module

Begin
   Display "Enter a Fahrenheit temperature: "
   Input fahrenheitTemperature
   Set celsiusTemperature to fahrenheitToCelsius(fahrenheitTemperature)
   Display "The equivalent Celsius temperature is: " + celsiusTemperature
   Display "Enter a Celsius temperature: "
  Input celsiusTemperature
   Set fahrenheitTemperature to celsiusToFahrenheit(celsiusTemperature)
   Display "The equivalent Fahrenheit temperature is: " + fahrenheitTemperature
End

Answer:

The answer to this question can be defined as below:

Explanation:

The three uses of the spreadsheet can be described as follows:

In Business:

In Auditing:

In nursing:

Answer:

Explanation:

#include <iostream>

using namespace std;

int main()

{

   string cwords[8]={"ten", "fading", "post", "card", "thunder", "hinge", "trailing", "batting"};

   string temp="";

   for (int i=0; i<8; i++)

   {

       temp=cwords[i];

       int j=temp.length();

       if (temp[j-3]=='i' && temp[j-2]=='n' && temp[j-1]=='g')

       {

           cout<<temp<<endl;

       }

   }

   return 0;

}

The code segments must use an enhanced for loop given in the coding language.

A code segment is a chunk of an object file or the corresponding area of the program's source code that is used for programming. It is also referred to as a text segment or simply as text.

#include <iostream>

using namespace std;

int main()

{

  string cwords[8]={"ten", "fading", "post", "card", "thunder", "hin-ge", "trailing", "batting"};

  string temp="";

  for (int i=0; i<8; i++)

  {

      temp=cwords[i];

      int j=temp.length();

      if (temp[j-3]=='i' && temp[j-2]=='n' && temp[j-1]=='g')

      {

          cout<<temp<<endl;

      }

  }

return 0;

}

Therefore, the code segments are written above.

To learn more about code segments, refer to the link:

https://brainly.com/question/20063766

#SPJ2

Answer:

Prior Experience Working with Senior Officers versus Little or None.

Explanation:

Differences and disparities between the Services in career paths leading up to a joint assignment may surprise new staff officers in joint assignments.

For example, Army and Air Force officers will likely come to a joint assignment with prior junior officer experience as an administrative “exec” to a senior officer at the O-5 and above level.

In contrast, Navy, Marine Corps and Coast Guard officers will have had no such experience unless selected for one of the highly competitive Flag Aide or Aide-de-Camp billets to an O-7 or above who rates such an aide.

Having an experience working with senior officers and when a person has little or none shows the key element to remember when working with other services.

The act of working together in a joint project helps to provide some amount of guidance for the use of authority.

Note that having a previous experience in working with senior officers and when a person has little or none can be obviously shown when working with other services.

Learn more about Career from

https://brainly.com/question/9719007

Answer:

See explaination for the details of the answer.

Explanation:

#include <iostream>

#include <stack>

using namespace std;

int main(){

string str;

cout<<"Enter a String: ";

std::getline (std::cin,str);

bool flag=true;

stack<char> st;

for(int i=0;i<str.size();i++){

if( (str.at(i)>='0' && str.at(i)<='9') || str.at(i)=='+' || str.at(i)=='-' || str.at(i)=='/'|| str.at(i)=='*' || str.at(i)==' ' ){

// cout<<str.at(i) <<"came"<<endl;

continue;

}

if( str.at(i)=='{' || str.at(i)=='(' ){

st.push(str.at(i));

}

else if(!st.empty() &&((st.top() == '{' && str.at(i) == '}') || (st.top() == '(' && str.at(i) == ')')))

st.pop();

else{

flag=false;

break;

}

}

if(!st.empty()){

cout<<"Does not match"<<"\n";

}else{

if(flag)

cout<<"Match"<<"\n";

else

cout<<"Does not match"<<"\n";

}

return 0;

}

See attachment for the output.

Answer:

public class Main

{

public static void main(String[] args) {

 PrintFeetInchShort(5, 8);

}

public static void PrintFeetInchShort(int numFeet, int numInches) {

    System.out.println(numFeet + "'" + " " + numInches + "\"");

}

}

Explanation:

Create a function called PrintFeetInchShort that takes two parameters, numFeet, and numInches

Print the given values in required format. Use System.out.println to print the values, ends with a new line.

Inside the main, call the function with two integers as seen in the example

Answer:

enum Flower { ROSE, DAISY, PETUNIA }

Flower flora = Flower.ROSE

Explanation:

Flower is of Enumeration data type and it contains the constants ROSE, DAISY and PENTUA.

To write a statement that declares a variable of that type you use

Var_of_enum_type Var_name

And to initialize it with a constant of the enumeration data type you use the dot (.) operator.

Var_of_enum_type.CONSTANT

Answer:

#include <iostream>

#include <climits>

#include<fstream>

using namespace std;

int main ()

{

fstream filein;

ofstream fileout;

string inputfilename, outputfilename;

// ASk user to enter filenames of input and output file

cout<<"Enter file input name: ";

cin>>inputfilename;

cout<<"Enter file output name: ";

cin>>outputfilename;

// Open both file

filein.open(inputfilename);

fileout.open(outputfilename);

// Check if file exists [Output file will automatically be created if not exists]

if(!filein)

{

cout<<"File cannot be opened"<<endl;

return 0;

}

int min = INT_MAX;

int max = INT_MIN; //(Can't use 0 or any other value in case input file has negative numbers)

int count = 0; // To keep track of number of integers read from file

double average = 0;

int number;

// Read number from file

while(filein>>number)

{

// If min > number, set min = number

if (min>number)

{

min = number;

}

// If max < number. set max = number

if(max<number)

{

max = number;

}

// add number to average

average = average+number;

// add 1 to count

count+=1;

// If count reaches 10, break the loop

if(count==10)

{

break;

}

}

// Calculate average

average = average/count;

// Write result in output file

fileout<<"Max: "<<max<<"\nMin: "<<min<<"\nAverage: "<<average;

// Close both files

filein.close();

fileout.close();

return 0;

}

Final answer:

Daniel is employing Computer-Aided Design (CAD) software and 3D printing to create 3D models for his construction company. This allows for detailed, precise visualizations and virtual tours of home designs, aiding clients in understanding the end product before building commences.

Explanation:

Daniel is using Computer-Aided Design (CAD) software coupled with 3D printing technology to develop the 3D models. CAD software allows users to create detailed, precise representations of products, buildings, and other projects, which then can be used to create physical models through 3D printing. This method is widely utilized in various industries, including construction, architecture, and product design to facilitate visualization and prototyping. The realistic representations and simulations provided by today's CAD programs help professionals like Daniel to effectively communicate design concepts to clients without the need for traditional physical mock-ups, enhancing the design process significantly.

Through this technology, Daniel can construct virtual tours offering exact views of the architectural designs. These models not only help in visualizing the structures but also in making more informed decisions on the design before any actual construction begins. Daniel's utilization of technology for creating 3-dimensional paper models demonstrates how contemporary architectural practices leverage digital tools to bring concepts to life for both the design teams and their clients.

Answer:

see explaination

Explanation:

//selective dev elements by id name

var gradeA = document.querySelector("#GradeA");

var passing = document.querySelector("#Passing");

var learning = document.querySelector("#Learning");

//function showGrades

function showGrades() {

var arr = [];

//converting string to int and inserting into array

arr[0] = parseInt(gradeA.textContent);

arr[1] = parseInt(passing.textContent);

arr[2] = parseInt(learning.textContent);

//creating json blob

var blob = new Blob(new Array(arr), {type:"text/json"});

return blob;

}

Answer:

#include <stdio.h>

#include <string.h>

int main(void) {

  char simonPattern[50];

  char userPattern[50];

  int userScore;

  int i;

  userScore = 0;

  scanf("%s", simonPattern);

  scanf("%s", userPattern);

  for(i = 0;simonPattern[i]!='\0';i++){

         if(simonPattern[i]!=userPattern[i]){

            userScore=i;

            break;

     }

  }

  printf("userScore: %d\n", userScore);

  return 0;

}

Explanation:

Input the three numbers. A first method must be called and used to develop logic to find the smallest of the three numbers. A second method must be used to print out that smallest number found.

Explanation:

import java.util.Scanner;

public class Exercise1 {

public static void main(String[] args)

   {

       Scanner in = new Scanner(System.in);

       System.out.print("Input the first number: ");

       double x = in.nextDouble();

       System.out.print("Input the Second number: ");

       double y = in.nextDouble();

       System.out.print("Input the third number: ");

       double z = in.nextDouble();

       System.out.print("The smallest value is " + smallest(x, y, z)+"\n" );

   }

  public static double smallest(double x, double y, double z)

   {

       return Math.min(Math.min(x, y), z);

   }

}

Answer:

Explanation:

I don't know about the answer in java.

This is what I did in C#. Find attached the answer

public class JobApplication

   {

       private string name;

       public string Name

       {

           get { return name; }

           set { name = value; }

       }

       private string phoneNumber;

       public string PhoneNumber

       {

           get { return phoneNumber; }

           set { phoneNumber = value; }

       }

       private bool isSKilledInWordProcessing;

       public bool IsSkilledInWordProcessing

       {

           get { return isSKilledInWordProcessing; }

           set { isSKilledInWordProcessing = value; }

       }

       private bool isSkilledInSpreadsheets;

       public bool IsSkilledInSpreadsheets

       {

           get { return isSkilledInSpreadsheets; }

           set { isSkilledInSpreadsheets = value; }

       }

       private bool isSkilledInDatabases;

       public bool IsSkilledInDatabases

       {

           get { return isSkilledInDatabases; }

           set { isSkilledInDatabases = value; }

       }

       private bool isSkilledInGraphics;

       public bool IsSkilledInGraphics

       {

           get { return isSkilledInGraphics; }

           set { isSkilledInGraphics = value; }

       }

       public JobApplication(string name, string phoneNumber, bool isSKilledInWordProcessing,

           bool isSkilledInSpreadsheets, bool isSkilledInDatabases, bool IsSkilledInGraphics)

       {

           Name = name;

           PhoneNumber = phoneNumber;

           IsSkilledInDatabases = isSkilledInDatabases;

           IsSkilledInGraphics = isSkilledInGraphics;

           IsSkilledInWordProcessing = IsSkilledInWordProcessing;

           IsSkilledInSpreadsheets = isSkilledInSpreadsheets;

       }

   }

   class Program

   {

       static void Main(string[] args)

       {

           JobApplication jobApplication1 = new JobApplication("Emmanuel Man", "+39399399", false, true, true, true);

           CheckIfQualified(jobApplication1);

       }

       static void CheckIfQualified(JobApplication jobApplication)

       {

           if(jobApplication.IsSkilledInSpreadsheets && jobApplication.IsSkilledInGraphics  

               && jobApplication.IsSkilledInWordProcessing && jobApplication.IsSkilledInDatabases)

           {

               Console.WriteLine("The applicant, " + jobApplication.Name + " is qualified for the job");

           } else if (jobApplication.IsSkilledInSpreadsheets && jobApplication.IsSkilledInGraphics

               && jobApplication.IsSkilledInWordProcessing)

           {

               Console.WriteLine("The applicant, " + jobApplication.Name + " is qualified for the job");

           }

           else if (jobApplication.IsSkilledInSpreadsheets && jobApplication.IsSkilledInGraphics

               && jobApplication.IsSkilledInDatabases)

           {

               Console.WriteLine("The applicant, " + jobApplication.Name + " is qualified for the job");

           } else if (jobApplication.IsSkilledInWordProcessing && jobApplication.IsSkilledInGraphics

               && jobApplication.IsSkilledInDatabases)

           {

               Console.WriteLine("The applicant, " + jobApplication.Name + " is qualified for the job");

           }else if (jobApplication.IsSkilledInWordProcessing && jobApplication.IsSkilledInSpreadsheets

               && jobApplication.IsSkilledInDatabases)

           {

               Console.WriteLine("The applicant, " + jobApplication.Name + " is qualified for the job");

           }

           else

           {

               Console.WriteLine("The applicant, " + jobApplication.Name + " is not qualified for the job");

           }

       }

   }

Answer:

import java.util.Scanner;

public class TestJobApplicant{

public static void main(String[] args)

{

   JobApplicant applicant1 = new JobApplicant("Ted","555-1234", true, false, false, false);

   JobApplicant applicant2 = new JobApplicant("Lily", "655-1235", true, false, true, false);

   JobApplicant applicant3 = new JobApplicant("Marshall", "755-1236", false, false, false, false);

   JobApplicant applicant4 = new JobApplicant("Barney", "855-1237", true, true, true, false);

   JobApplicant applicant5 = new JobApplicant("Robin", "955-1238", true, true, true, true);

   String qualifiedMessage = "is qualified for an interview. ";

   String notQualifiedMessage = "is not qualified for an interview at this time. ";

   if (isQualified(applicant5))

       display(applicant5, qualifiedMessage);

   else

       display(applicant5, notQualifiedMessage);

}

   public static boolean isQualified(JobApplicant applicant) {

       int count = 0;

       boolean isQualified;

       final int MIN_SKILLS = 3;

       if(applicant.getWord())

           count += 1;

       if(applicant.getSpreadsheet())

           count += 1;

       if(applicant.getDatabase())

           count += 1;

       if(applicant.getGraphics())

           count += 1;

       if(count >= MIN_SKILLS)

           isQualified = true;

       else

           isQualified = false;

       return isQualified;

   }

   public static void display(JobApplicant applicant, String message) {

       System.out.println(applicant.getName() + " " + message +" Phone: " + applicant.getPhone());

   }

}

class JobApplicant {

   private String name, phone;

   private boolean word, spreadsheet, database, graphics;

   public JobApplicant(String name, String phone, boolean word, boolean spreadsheet, boolean database, boolean graphics){

       this.name = name;

       this.phone = phone;

       this.word = word;

       this.spreadsheet = spreadsheet;

       this.database = database;

       this.graphics = graphics;

   }

   public String getName() {return name;}

   public String getPhone() {return phone;}

   public boolean getWord() {return word;}

   public boolean getSpreadsheet() {return spreadsheet;}

   public boolean getDatabase() {return database;}

   public boolean getGraphics() {return graphics;}

}

Explanation:

Inside the JobApplicant class:

- Declare the variables

- Initialize the constructor

- Create the get methods for each variable

Inside the TestJobApplicant class:

- Create an isQualified method that checks if given applicant is qualified for the job.

- Create a display method that prints the name, message and phone number for the applicant

Inside the main:

- Initialize the applicant objects and messages

- Call the isQualified method with an applicant to see the result

Answer:

See explaination

Explanation:

import java.util.Scanner;

public class GtldValidation {

public static void main (String [ ] args) {

Scanner scnr = new Scanner(System.in);

// Define the list of valid core gTLDs

String [ ] validCoreGtld = { ".com", ".net", ".org", ".info" };

// FIXME: Define an array named validRestrictedGtld that has the names

// of the restricted domains, .biz, .name, and .pro

String [] validRestrictedGtld={".biz",".name",".pro"};

String inputName = "";

String searchName = "";

String theGtld = "";

boolean isValidDomainName = false;

boolean isCoreGtld = false;

boolean isRestrictedGtld = false;

int periodCounter = 0;

int periodPosition = 0;

int i = 0;

System.out.println("\nEnter the next domain name (<Enter> to exit): ");

inputName = scnr.nextLine();

while (inputName.length() > 0) {

searchName = inputName.toLowerCase();

isValidDomainName = false;

isCoreGtld = false;

isRestrictedGtld = false;

// Count the number of periods in the domain name

periodCounter = 0;

for (i = 0; i < searchName.length(); ++i) {

if (searchName.charAt(i) == '.') {

++periodCounter;

periodPosition = i;

}

}

// If there is exactly one period that is not at the start

// or end of searchName, check if the TLD is a core gTLD or a restricted gTLD

if ((periodCounter == 1) &&

(searchName.charAt(0) != '.') &&

(searchName.charAt(searchName.length() - 1) != '.')) {

isValidDomainName = true;

}

if (isValidDomainName) {

// Extract the Top-level Domain name starting at the period's position. Ex:

// If searchName = "example.com", the next statement extracts ".com"

theGtld = searchName.substring(periodPosition);

i = 0;

while ((i < validCoreGtld.length) && (!isCoreGtld)) {

if(theGtld.equals(validCoreGtld[i])) {

isCoreGtld = true;

}

else {

++i;

}

}

// FIXME: Check to see if the gTLD is not a core gTLD. If it is not,

// check to see whether the gTLD is a valid restricted gTLD.

// If it is, set isRestrictedGtld to true

}

System.out.print("\"" + inputName + "\" ");

if (isValidDomainName) {

System.out.print("is a valid domain name and ");

if (isCoreGtld) {

System.out.println("has a core gTLD of \"" + theGtld + "\".");

}

else if (isRestrictedGtld) {

System.out.println("has a restricted gTLD of \"" + theGtld + "\".");

}

else {

System.out.println("does not have a core gTLD."); // FIXME update message

}

}

else {

System.out.println("is not a valid domain name.");

}

System.out.println("\nEnter the next domain name (<Enter> to exit): ");

inputName = scnr.nextLine();

}

return;

}

}

Answer:

See explaination

Explanation:

#include <stdio.h>

#include <malloc.h>

typedef struct {

int eid;

char name[30];

char address[50];

float hourlyRate;

int totalHours;

float bonus;

float salary;

}employee;

void readEmployee(employee *employees, int size){

int i;

for(i = 0; i < size; ++i){

printf("Enter details of employee %d\n", i + 1);

printf("Enter eid: ");

scanf("%d", &employees[i].eid);

printf("Enter name: ");

scanf("%s", employees[i].name);

printf("Enter address: ");

scanf("%s", employees[i].address);

printf("Enter hourly rate: ");

scanf("%f", &employees[i].hourlyRate);

printf("Enter total hours: ");

scanf("%d", &employees[i].totalHours);

printf("Enter bonus percentage: ");

scanf("%f", &employees[i].bonus);

}

}

void ComputeSalary(employee *employees, int size){

int i;

for(i = 0; i < size; ++i){

employees[i].salary = (1 + (employees[i].bonus / 100.0)) * employees[i].hourlyRate * employees[i].totalHours;

}

}

void PrintEmployee(employee *employees, int size){

int i;

for(i = 0; i < size; ++i){

printf("Employee %d\n", i + 1);

printf("Eid: %d\n", employees[i].eid);

printf("Name: %s\n", employees[i].name);

printf("Address: %s\n", employees[i].address);

printf("Total hours: %d\n", employees[i].totalHours);

printf("Hourly rate: $%.2f\n", employees[i].hourlyRate);

printf("Bonus: %.2f%%\n", employees[i].bonus);

printf("Salary: $%.2f\n", employees[i].salary);

}

}

int main(){

int i, size;

employee *employees;

printf("Enter number of employees: ");

scanf("%d", &size);

employees = (employee *) malloc(sizeof(employee) * size);

readEmployee(employees, size);

ComputeSalary(employees, size);

PrintEmployee(employees, size);

return 0;

}

Answer:

file = open("numbers.txt")

numbers = []

for line in file:

   numbers.append(int(line))

print("The numbers in the file: " + str(numbers[0]) + " " + str(numbers[1]))

print("The sum of the numbers: " + str(numbers[0] + numbers[1]))

Explanation:

The code is in Python.

Open the file named numbers.txt

Create an empty list, numbers, to hold the numbers in the file

Create a for loop that iterates through file and adds the number inside the file to the list

Print numbers

Calculate and print the sum of the numbers

Final answer:

To read two integers from a file and print their sum, use a Python script to open the file, convert the strings to integers, calculate the sum, and print the results with the equation format.

Explanation:

To construct a program that reads the content from the file numbers.txt and prints out the two numbers along with their sum, you would need to use a programming language. Below is an example of how you might write such a program in Python:

with open('numbers.txt', 'r') as file:
   numbers = file.read().splitlines()

num1 = int(numbers[0])
num2 = int(numbers[1])
sum_of_numbers = num1 + num2

print(f"{num1} + {num2} = {sum_of_numbers}")

This program opens the file numbers.txt, reads its content line by line, converts the lines to integers, and then calculates their sum. Finally, it prints out the numbers and the sum in the format specified. It is assumed that numbers.txt contains one number per line and that these can be converted directly to integers.

Answer:

The condition evaluated to false!

Explanation:

lets attach line numbers to the given code snippet

Answer:

See explaination

Explanation:

Mutation Testing:

Mutation Testing is a type of software testing where we mutate (change) certain statements in the source code and check if the test cases are able to find the errors. It is a type of White Box Testing which is mainly used for Unit Testing. The changes in the mutant program are kept extremely small, so it does not affect the overall objective of the program.

We say a mutant is valid if it is syntactically correct. We say a mutant is useful if, in addition to being valid, its behavior differs from the behavior of the original program for no more than a small subset of program test cases.

VALID MUTANTS

1. if (x < 12 && (r – 3 > 12)) LOR

2. if (x < 12 || (r – 3 < 12)) ROR

3. if (x < 12 || (x – 3 < 12)) IVR

INVALID MUTANTS

1. if (x < 12 ||(r – 3 > 12) UPR

2. if (x < 12 (r – 3 < 12)) MLO

3. (x < 12 || (x – 3 < 12)) CSM

Note:

LOR: LOGICAL OPERATOR REPLACEMENT

ROR: RELATIONAL OPERATOR REPLACEMENT

IVR: INVALID VARIABLE REPLACEMENT

UPR: UNBALENCED PARANTHISIS REPLACEMENT

MLO: MISSING LOGICAL OPERATOR REPLACEMENT

CSM: CONTROL OPERATOR MISSING REPLACEMEN

Answer:

An Epic is a container for a Solution development initiative large enough to require analysis, the definition of a Minimum Viable Product (MVP), and financial approval prior to implementation. Implementation occurs over multiple Program Increments (PIs) and follows the Lean startup 'build-measure-learn' cycle.

Explanation:

Hope this is what your looking for

The purpose of a Program Epic is to represent business capabilities that address various user needs.

What is Program Epic ?

An Epic is a holder for a Solution improvement drive sufficiently enormous to require examination, the meaning of a Minimum Viable Product (MVP), and monetary endorsement preceding execution. Execution happens over numerous Program Increments (PIs) and follows the Lean startup 'assemble measure-learn' cycle.

A program epic obliged to a solitary delivery train, conveyed by different groups, and crossing numerous PI emphases. Program Epics can address business abilities that address different client needs. Include: Functionality that meets explicit partner needs.

Thus, the purpose is explained.

Learn more about Program Epic

https://brainly.com/question/15450565

#SPJ2

The program reads whitespace-delimited strings and an integer frequency, then outputs strings with the specified frequency in a case-insensitive manner using a frequency counting approach.

In this programming task, the goal is to create a program that reads whitespace-delimited strings and an integer frequency (freq). The program should then output the strings from the input that have a frequency equal to the specified freq in a case-insensitive manner.

To achieve this, the program needs to:

1. Read input: Use an input mechanism to read whitespace-delimited strings and the integer frequency.

2. Count frequency: Maintain a data structure, such as a dictionary or a hashmap, to store the frequency of each string. While reading the input strings, update the frequency count accordingly.

3. Filter strings: Iterate through the stored strings and output only those with a frequency equal to the specified freq. Ensure case-insensitivity by converting all strings to lowercase during comparison.

Here's a Python example:

```python

def find_strings_with_frequency(words, freq):

   word_count = {}    

   # Count the frequency of each word

   for word in words:

       word_lower = word.lower()

       word_count[word_lower] = word_count.get(word_lower, 0) + 1    

   # Output strings with the specified frequency

   result = [word for word, count in word_count.items() if count == freq]    

   return result

# Example usage

input_words = input("Enter whitespace-delimited strings: ").split()

input_freq = int(input("Enter frequency: "))

output_strings = find_strings_with_frequency(input_words, input_freq)

print("Strings with frequency {}: {}".format(input_freq, output_strings))

```

This program takes user input for whitespace-delimited strings and an integer frequency, processes the input, and outputs strings with the specified frequency in a case-insensitive manner.

Answer:

celsius = float(input("Enter the celcius value: "))

f = 1.8 * celsius + 32

print(str(celsius) + " C = "+ str(f) + " F")

Explanation:

The code is in Python.

Ask the user for the input, celsius value

Convert the celsius value to fahrenheit using the given formula

Print the result as in shown in the example output

Answer:

See explaination

Explanation:

#include<iostream>

#include<iomanip>

using namespace std;

int main(){

double tempF, tempC;

cout<<"Enter a degree in Celsius: ";

cin>>tempC;

tempF = tempC*(9/5.0)+32;

cout<<setprecision(1)<<fixed;

cout<<tempC<<" C = "<<tempF<<" F"<<endl;

return 0;

}

Answer:

See explaination

Explanation:

Kindly check the attachment for the details

Answer:

Changing the customer number on a record in the Orders table to a number that does not match a customer number in the customer table would violate referential integrity.

If deletes do not cascade, deleting a customer that has orders would violate referential integrity.

If deletes cascade, customer can be deleted and all orders for that customer will automatically be deleted.

Answer:

numBuckets = 47

def create():

global numBuckets

hSet = []

for i in range(numBuckets):

hSet.append([])

# print "[XYZ]: create() hSet: ", hSet, " type(hSet): ",type(hSet)

return hSet

def hashElem(e):

global numBuckets

return e % numBuckets

def insert(hSet,i):

hSet[hashElem(i)].append(i)

# print "[XYZ]: insert() hSet: ", hSet, " type(hSet): ",type(hSet)

def remove(hSet,i):

newBucket = []

for j in hSet[hashElem(i)]:

if j != i:

newBucket.append(j)

hSet[hashElem(i)] = newBucket

print "[XYZ]: remove() i: ", i," hashElem[i]: ", hashElem(i), " hSet[hashElem(i): ", hSet[hashElem(i)]

def member(hSet,i):

return i in hSet[hashElem(i)]

def testOne():

s = create()

for i in range(40):

insert(s,i)

print "[XYZ]: S: ", s

insert(s,325)

insert(s,325)

insert(s,9898900067)

print "[XYZ]: S: ", s

print "[XYZ]: ,member(s,325): ",member(s,325)

remove(s,325)

print "[XYZ]: After Remove, member(s,325): ",member(s,325)

print "[XYZ]: member(s,9898900067)",member(s,9898900067)

testOne()