Answer:
negative, positive, increase
Explanation:
From the given question,
During the formation of bond, between two atoms with difference between their electronegativity-
The more electronegative atom, will pull the electrons towards itself , and hence acquires a partial negative charge,And,
The less electronegative atom, will acquire a partial positive charge.The more the difference between the electronegativity of the atoms, the more would be the magnitude of partial charge.And, the less would be the difference between the electronegativity of the atoms, the lesser would be the magnitude of partial charge.Atoms with different electronegativities share electrons unequally, leading to partial charges. The more electronegative atom gains a partial negative charge, while the other has a partial positive charge. Larger electronegativity differences intensify these charges.
Explanation:When two atoms with different electronegativities form a covalent bond, the atom with higher electronegativity will attract shared electrons more and will have a partial negative charge. Conversely, the atom with lower electronegativity will have an equal and opposite partial positive charge. As the difference in electronegativity increases, the resulting magnitudes of the partial charges will also increase.
How much heat is required to vaporize a 3 g ice cube initially at 0◦C? The latent heat of fusion of ice is 80 cal/g and the latent heat of vaporization of water is 540 cal/g. The specific heat of water is 1 cal/(g · ◦ C). Answer in units of cal.
Answer : The amount of heat required is, 2160 cal.
Explanation :
The process involved in this problem are :
[tex](1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)\\\\(3):H_2O(l)(100^oC)\rightarrow H_2O(g)(100^oC)[/tex]
The expression used will be:
[tex]Q=[m\times \Delta H_{fusion}]+[m\times c_{p,l}\times (T_{final}-T_{initial})]+[m\times \Delta H_{vap}][/tex]
where,
[tex]Q[/tex] = heat required for the reaction = ?
m = mass of ice = 3 g
[tex]c_{p,l}[/tex] = specific heat of liquid water = [tex]1cal/g^oC[/tex]
[tex]\Delta H_{fusion}[/tex] = enthalpy change for fusion = [tex]80cal/g[/tex]
[tex]\Delta H_{vap}[/tex] = enthalpy change for vaporization = [tex]540cal/g[/tex]
Now put all the given values in the above expression, we get:
[tex]Q=[3g\times 80cal/g]+[3g\times 1cal/g^oC\times (100-0)^oC]+[3g\times 540cal/g][/tex]
[tex]Q=2160cal[/tex]
Therefore, the amount of heat required is, 2160 cal.
To vaporize a 3 g ice cube initially at 0°C, a total heat of 2160 cal is required. This includes the heat required to melt the ice, heat the melted ice to water's boiling point, and vaporize the water.
Explanation:The process to vaporize a 3 g ice cube at 0°C consists of three steps. First, the ice cube needs to melt. This requires an amount of heat given by Q = mass x latent heat of fusion. i.e., Q = 3 g x 80 cal/g = 240 cal.`
Then, the water obtained from melted ice at 0°C needs to be heated up to 100°C. The required heat is Q = mass x specific heat x ΔT, i.e., Q = 3 g x 1 cal/g°C x (100°C-0°C) = 300 cal.
Finally, the 100°C water needs to be vaporized. This requires an amount of heat given by Q = mass x latent heat of vaporization. i.e., Q = 3 g x 540 cal/g = 1620 cal.
So, the total heat required to vaporize a 3 g ice cube initially at 0°C is 240 cal + 300 cal + 1620 cal = 2160 cal.
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Complete the following two statements regarding quantum-mechanical concepts associated with the Bohr model of the atom and refinements that resulted from the wave-mechanical atomic model. " Two important quantum-mechanical concepts associated with the Bohr model of the atom are that electrons are particles moving in _______
Enter your answer for the missing word between words "moving in" and "orbitals" in accordance to the question statement discrete orbitals, and electron energy is quantized into
Enter your answer for the missing word after words "quantized in" in accordance to the question statement levels .
(b) Two important refinements resulting from the wave-mechanical atomic model are that the electron position is described in terms of a Enter your answer for the missing words after words "in terms of a" in accordance to the question statement electron cloud , and electron energy is quantized into both shells and subshells--each electron is characterized by Enter your answer for the missing word after words "is characterized by" in accordance to the question statement quantum numbers."
Answer:
Two important quantum-mechanical concepts associated with the Bohr model of the atom are (1) that electrons are particles moving in discrete orbitals, and (2) electron energy is quantized into shells. (b) Two important refinements resulting from the wave-mechanical atomic model are (1) that electron position is described in terms of a probability distribution, and (2) electron energy is quantized into both shells and subshells--each electron is characterized by four quantum numbers.
Explanation:
Part A:
The two important quantum-mechanical concepts associated with the Bohr model of the atom are:
(1) Electrons are particles moving in discrete orbitals.
(2) Electron energy is quantized into shells.
Part B:
The two important refinements resulting from the wave-mechanical atomic model are:
That electron position is described in terms of a probability distribution.The electron energy is quantized into both shells and subshells each electron is characterized by four quantum numbers.Learn more :
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An aqueous feed solution of 1000 kg/h containing 23.5 wt % acetone and 76.5 wt % water is being extracted in a countercurrent multistage extraction system using pure methylisobutyl ketone solvent at 298–299 k. the outlet water raffinate will contain 2.5 wt % acetone. use equilibrium data from
Question:
The question is incomplete. What is required to calculate was not added.The equilibrium data was not also added. Below is the additional questions and the answers.
1. Calculate the minimum solvent that can be used.
2.Using a solvent rate of 1.5 times the minimum, calculate the number of
theoretical stages.
Answer:
1. Minimum solvent = 411.047
2. N = 5
Explanation:
See the attached files for explanations.
An aqueous feed solution.
The aqua solution is a solvent on water that has a chemical equation of aq. The example includes the solution of the salt table and NaCl. Having positive and negative ions. The solution feed id of 1000 KG/hand consists of 23.5 wt% acetone and has a 76.5 wt% of water by volume which is being used.
Thus the answer is minimum solvent = 411.047 and the N equals 5.
The 76.5wt of water is extracted in a concurrent multistage of the extraction system and is used with the methyl isobutyl. With the ketone solvent at the temperature of 298-299K. The outer or output of 2.5 wt 5 acetone which is a colorless liquid gets dissolved.Hence the answer is a mini solvent of 411.0 and value of N as 5.Learn more about the aqueous feed solution.
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"11. Barium nitrate reacts with aqueous sodium sulfate to produce solid barium sulfate and aqueous sodium nitrate. Abigail places 20.00 mL of 0.500 M barium nitrate in a flask. She has a 0.225M sodium sulfate solution available. What volume of this solution must she add to her flask of barium nitrate so she has no excess reactant left over?"
Answer:
44 mL of Na2SO4
Explanation:
Step 1:
The balanced equation for the reaction. This is given below:
Ba(NO3)2 (aq) + Na2SO4 (aq) —> BaSO4 (s) + 2NaNO3 (aq)
Step 2:
Determination of the number of mole of Ba(NO3)2 in 20.00 mL of 0.500 M barium nitrate (Ba(NO3)2). This is illustrated below:
Molarity of Ba(NO3)2 = 0.5 M
Volume of solution = 20 mL = 20/1000 = 0.02 L
Mole of solute (Ba(NO3)2) =?
Molarity = mole /Volume
0.5 = Mole of Ba(NO3)2 / 0.02
Cross multiply to express in linear form
Mole of Ba(NO3)2 = 0.5 x 0.02
Mole of Ba(NO3)2 = 0.01 mole
Step 3:
Determination of the number of mole of Na2SO4 that reacted.
Ba(NO3)2 (aq) + Na2SO4 (aq) —> BaSO4 (s) + 2NaNO3 (aq)
From the balanced equation above,
1 mole of Ba(NO3)2 reacted with 1 mole of Na2SO4.
Therefore, 0.01 mole of Ba(NO3)2 will also react with 0.01 mole of Na2SO4.
Step 4:
Determination of the volume of Na2SO4 needed for the reaction. This is illustrated below:
Mole of Na2SO4 = 0.01 mole
Molarity of Na2SO4 = 0.225M
Volume =?
Molarity = mole /Volume
0.225 = 0.01 / volume
Cross multiply to express in linear form
0.225 x Volume = 0.01
Divide both side by 0.225
Volume = 0.01/0.225
Volume of Na2SO4 = 0.044 L
Converting 0.044 L to mL, we have
Volume of Na2SO4 = 0.044 x 1000
Volume of Na2SO4 = 44 mL
Therefore, 44 mL of Na2SO4 is needed for the reaction
Answer:
She has to add 44.44 mL of Na2SO4
Explanation:
Step 1: Data given
Volume of barium nitrate = 20.00 mL = 0.020 L
Molarity of barium nitrate = 0.500 M
Molarity of sodium sulfate = 0.225 M
Step 2: The balanced equation
Ba(NO3)2 (aq) + Na2SO4 (aq) → BaSO4 (s) + 2 NaNO3 (aq)
Step 3: Calculate volume of the sodium sulfate solution needed
For 1 mol Ba(NO3)2 we need 1 mol Na2SO4 to produce 1 mol basO4 and 2 moles NaNO3
C1*V1 = C2*V2
⇒with C1 = the molarity of Ba(NO3)2 = 0.500 M
⇒with V1 = the volume of Ba(NO3)2 = 0.020 L
⇒with C2 = the molarity of Na2SO4 =0.225 M
⇒with V2 = the volume of Na2SO4 = TO BE DETERMINED
0.500 M * 0.020 L = 0.225 M * V2
V2 = (0.500 M * 0.020 L) / 0.225 M
V2 = 0.04444 L = 44.44 mL
She has to add 44.44 mL of Na2SO4
A chemistry student needs 75 g of thiophene foran experiment. He has available 0.50 kg of a 29.3% w/w solution of thiophene in carbon tetrachloride.
Calculate the mass of solution the student should use. Ifthere's not enough solution, press the "No solution" button.
Answer: The mass of solution the student should use is 256 g
Explanation:
Given : 29.3 % w/w which means that 29.3 g of solute is present in 100 g of solution
Thus 100 g of solution contains = 29.3 g of solute
0.50 kg or 500 g of solution contains = [tex]\frac{29.3}{100}\times 500=146.5[/tex] g of solute (1kg=1000g)
146.5 g of solute is available in = 500 g of solution
Thus 75 g of solute is available in = [tex]\frac{500}{146.5}\times 75 g=256g[/tex] of solution
Thus the mass of solution the student should use is 256 g
A student went to the dentist and found out that he had a cavity. He always brushes his teeth twice a day, so he didn't understand how he got a cavity. The dentist told him that drinking things every day that are acidic, such as lemonade, can contribute to cavities. He didn't drink lemonade but does drink a variety of other drinks.
The next day he brought in a sample of each drink and asked his science teacher to borrow a pH probe to test each liquid. The pH of Drink A is 11.9, Drink B is 7.0, Drink C is 5.3, Drink D is 9.8, Drink E is 2.4. Explain which drink(s) the student should avoid if he wants to protect his teeth from further damage.
In your response, be sure to include:
1. an explanation of what pH measures
2. which drinks are acidic, basic, and neutral.
Answer:E is an acidic
Explanation:
Soo he should avoid the drink E and in pH measurement the more acidic is below 7 and the the more alkali is above 7 and the neutral drink is B and it may a water ...
Based on the enthalpy changes given for the reactions, which reactions are endothermic?
2H2O → 2H2 + O2, ΔH = 484 kJ
C + O2 → CO2, ΔH = -394 kJ
H2 + Br2 → 2HBr, ΔH = -73 kJ
2NH3 → N2 + 3H2, ΔH = 92 kJ
Answer:
the first and last
Explanation:
the enthalpy Change is positive.
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Answer:
One (2H2O → 2H2 + O2, ΔH = 484 kJ )
Four (2NH3 → N2 + 3H2, ΔH = 92 kJ)
Explanation:
An endothermic process is any process with an increase in the enthalpy H of the system. So if it has a positive result then the heat is going up which means it is endothermic .
A student dissolved 3.00 g of Co(NO 3) 2 in enough water to make 100. mL of stock solution. He took 4.00 mL of the solution then diluted it with water to give 275 mL of a final solution. How many grams of NO 3 - ion are there in the final solution?
Answer:
0.0812 grams of nitrate ions are there in the final solution.
Explanation:
Mass of cobalt (II) nitrate = 3.00 g
Moles of cobalt(II) nitrate = [tex]\frac{3.00 g}{183 g/mol}=0.0164 mol[/tex]
Volume of the solution = 100 mL = 0.100 L
1 mL = 0.001 L
[tex]Molarity=\frac{Moles}{Volume(L)}[/tex]
Molarity of the solution = [tex]\frac{0.0164 mol}{0.100 L}=0.164 M[/tex]
Cobalt (II) nitrate in its aqueous solution gives 1 mole of cobalt(II) ion and 2 moles of nitrate ions.
[tex][NO_3^{-}]=2\times [Co(NO_3)_2]=2\times 0.164 M=0.328 M[/tex]
Molarity of the nitrate ion before solution = [tex]M_1=0.328 M[/tex]
Volume of the nitrate ion before solution = [tex]V_1=4.00 mL[/tex]
Molarity of the nitrate ion after solution = [tex]M_2=?[/tex]
Volume of the nitrate ion after solution = [tex]V_2=275 mL[/tex]
[tex]M_1V_1=M_2V_2[/tex] ( Dilution)
[tex]M_2=\frac{0.328 M\times 4.00 mL}{275 mL}=0.00477 M[/tex]
Moles of nitrate ions in 275 ml = n
Molarity of the nitrate ion after solution =0.00477 M
volume of the final solution = 275 mL = 0.275 L
[tex]n=0.00477 M\times 0.275 L=0.00131 mol[/tex]
Mass of 0.00131 moles of nitrate ions:
0.00131 mol × 62 g/mol = 0.0812 g
0.0812 grams of nitrate ions are there in the final solution.
What is the main purpose of using NaOH in the saponification reaction . NaOH works as the catalyst b. NaOH solution is the solvent for the reaction c. NaOH acts as a reactant in the reaction d. NaOH facilitates the soap to salt out from the solution
Answer:
C. NaOH acts as a reactant in the reaction
Explanation:
Because during the saponification process, Na+ replaces the H+ in the fatty acid been used for the saponification process
Specific heat is used to explain why different substances
a) sink or float
b) change temp. at different rates
c) vaporize or condense at different temp.’s
d) melt and freeze at the same temp.
Answer:
change temperature at different rates
The specific heat is used to explain why different substances change the temperature at different rates.
Specific Heat:
It is the amount of heat that is required to increase the temperature of 1 kg of a substance by 1^oc. It is measured in the [tex]\bold {J/g/^oC }[/tex].
The specific heat capacity of water is [tex]\bold { 4.184 J/g/^oC.}[/tex]If the heat capacity is it takes more time to heat or cool it down. If specific heat capacity of a substance is low, then it takes less time to heat or cool it down.Therefore, the specific heat is used to explain why different substances change the temperature at different rates.
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A solution containing 1.0 M NiCl2 and 1.0 M SnBr2 undergoes electrolysis by passing a current between two platinum electrodes. What are the most likely first products to be formed? Cl2 (aq) + 2e- → 2Cl- (aq) ℰ°= 1.36 V Br2 (aq) + 2e- → 2Br- (aq) ℰ° =1.08 V Sn2+ (aq) + 2e- → Sn(s) ℰ° = -0.14 V Ni2+ (aq) + 2e- → Ni(s) ℰ°= -0.24 V
Answer:
Sn2+ (aq) + 2e- → Sn(s) ℰ° = -0.14 V
Explanation:
A close look at all the options shows that the most feasible first reaction is the reduction of tin II ion to ordinary metallic tin.
Given the two half cells, nickel is oxidized in one half cell to Ni II while in the second half cell, tin II ion is reduced to metallic tin. The platinum electrodes simply act as electron conduits in the cell.
__________ reactions are used to detect antibodies for relatively large pathogens
Answer:
The question is incomplete, no worries I got you.
Here is the complete question;
__________ reactions are used to detect antibodies for relatively large pathogens, such as bacteria. For these tests, the antigen is mixed with the test sample at various dilutions. Reaction mixes are then monitored for the formation of visible aggregates.
Explanation:
AGGLUTINATION is the reaction used.
Agglutination is the reaction in which there is the clumping of particles. A agglutination reaction is the visible clumping of the bacterial cells as an antigen reacts with its corresponding antibody. This type is often used as an initial confirmation of specific pathogens. Agglutination tests is is used to detect antibody or antigen and it involves the agglutination of bacteria, red cells, or antigen- or antibody-coated latex particles. It is therefor used for large pathogens like bacteria. In this reaction, antigens are introduced into various dilutions of antibodies in test tubes or surfaces of glass slides, visible clumping is observed which depends on the size of the antibodies, amount and acidity of the antibody molecule, time of incubation and as well as the environment of the reaction which includes optimum pH, protein concentration among others.
Of the reactions below, which one is not a combination reaction?Immersive Reader (2 Points) 2N2 + 3H2 → 2NH3 2Mg + O2 → 2MgO 2CH4 + 4O2 → 2CO2 + 4H2O C + O2 → CO2 CaO + H2O → Ca(OH)2
Answer: [tex]2CH_4+4H_2O\rightarrow 2CO_2+4H_2O[/tex] is not a combination reaction.
Explanation:
Synthesis reaction or combination reaction is defined as the reaction where two or more substances combine to form a single product.
[tex]2N_2+3H_2\rightarrow 2NH_3[/tex]
[tex]2Mg+O_2\rightarrow 2MgO[/tex]
[tex]CaO+H_2O\rightarrow Ca(OH)_2[/tex]
Combustion is a chemical reaction in which hydrocarbons are burnt in the presence of oxygen to give carbon dioxide and water.
[tex]2CH_4+4H_2O\rightarrow 2CO_2+4H_2O[/tex]
Among the provided reactions, the reaction 2CH4 + 4O2 → 2CO2 + 4H2O is not a combination reaction, but rather a combustion reaction.
Explanation:In the given reactions, the reaction 2CH4 + 4O2 → 2CO2 + 4H2O is not a combination reaction. In a combination reaction, two or more substances (either elements or compounds) combine to form a single compound. However, the mentioned reaction is actually an example of a combustion reaction where methane (CH4) undergoes combustion in the presence of oxygen (O2) to form carbon dioxide (CO2) and water (H2O).
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In photosynthesis, carbon dioxide and water are converted into glucose and oxygen in the presence of chlorophyll and light energy. If 1.0 mole of water is available with an excess of carbon dioxide, how many moles of glucose (C6H12O6) can be produced
Answer:
0.17 mole of glucose is formed.
Explanation:
Step 1:
The equation for the reaction. This is given below:
CO2 + H2O —> C6H12O6 + O2
Step 2:
Balancing the equation.
The equation can be balanced as follow:
CO2 + H2O —> C6H12O6 + O2
There are 6 atoms of C on the right side and 1 atom on the left side. It can be balance by putting 6 in front of CO2 as shown below:
6CO2 + H2O —> C6H12O6 + O2
Therefore are 12 atoms of H on the right side and 2 atoms on the left side. It can be balance by putting 6 in front of H2O as shown below:
6CO2 + 6H2O —> C6H12O6 + O2
There are a total of 8 atoms of O the right side and a total of 18 atoms on the left. It can be balance by putting 6 in front of O2 as shown below:
6CO2 + 6H2O —> C6H12O6 + 6O2
Now the equation is balanced.
Step 3:
Determination of the number of mole of glucose (C6H12O6) produced by 1 mole of water.
This is illustrated below:
6CO2 + 6H2O —> C6H12O6 + 6O2
From the balanced equation above,
6 moles of H2O produced 1 mole of C6H12O6.
Therefore, 1 mole of H2O will produce = 1/6 = 0.17 mole of C6H12O6.
Answer:
IF 1.0 mol of water is available, 0.167 moles of glucose (C6H12O6) will be produced
Explanation:
Step 1: Data given
Number of moles of water = 1.0 moles
Carbon dioxide is in excess
Step 2: The balanced equation
6CO2 + 6H2O → C6H12O6 + 6O2
Step 3: Calculate moles of glucose
For 6 moles CO2 we need 6 moles H2O to produce 1 mol glucose and 6 moles O2
For 1.0 moles of water we'll have 1.00 / 6 = 0.167 moles of glucose
IF 1.0 mol of water is available, 0.167 moles of glucose (C6H12O6) will be produced
what was the purpose of running a tlc of ferrocene, the acetylferrocene product mixture, and co-spot (an overlay of ferrocene and the product mixture) prior to conducting the column chromatography portion of the experiment?a. All of the belowb. To determine the elution in a chromatography column of the starting material and productsc. To determine if there was starting material still present in the reactiond. To identify the number of products of the reaction
Answer:
a. All of the below
Explanation:
Column chromatography in chemistry is a chromatography method used to isolate a single chemical compound from a mixture.
TLC can be used to analyze a chemical reaction to determine if the reactants have been consumed and a new product has formed. Running a tlc of ferrocene, the acetylferrocene product mixture, and co-spot, when you view the TLC plate under a UV light, you will notice that acetylferrocene product is on the right-most lane, this shows that the reaction appears to be a success: the higher spot of ferrocene has been consumed), and a new product spot is present. From these we can observe that the we can use this to identify the number of products of the reaction, determine if the starting material is still present in the reaction and the elution in a chromatography column of the starting material and products. Therefore, all the choices are correct.
Acetic acid has a Ka of 1.8 * 10-5. Three acetic acid/acetate buffer solutions, A, B, and C, were made using varying concentrations: acetic acid ten times greater than acetate, acetate ten times greater than acetic acid, and acetate=acetic acid.
Match each buffer to the expected pH. pH = 3.74 ; pH = 4.74 ; pH = 5.74
Part B: How many grams of dry NH4Cl need to be added to 2.30 L of a 0.600 M solution of ammonia, NH3, to prepare a buffer solution that has a pH of 8.71? Kb for ammonia is 1.8 * 10-5.
Express your answer with the appropriate units.
Answer:
A) acetic acid ten times greater than acetate pH = 3.74
B) acetate ten times greater than acetic acid pH = 5.74
C) For solution 3: acetate=acetic acid pH = 4.74
Mass NH4Cl = 40.30 grams
Explanation:
Step 1: Data given
Ka is: 1.8 * 10^-5
Solution 1: acetic acid ten times greater than acetate
Solution 2: acetate ten times greater than acetic acid
Solution 3: acetate=acetic acid
Step 2: The pH formula
pH = pKa + log[CH3COO-]/[CH3COOH]
For solution 1: acetic acid ten times greater than acetate this means ) [[CH3COO-]/[CH3COOH]) has a value of 1/10
pH = pKa + log[CH3COO-]/[CH3COOH]
pH = -log(1.8*10^-5) + log(1/10)
pH = 4.74 -1
pH = 3.74
For solution 2: acetate ten times greater than acetic acid
pH = pKa + log[CH3COO-]/[CH3COOH]
pH = -log(1.8*10^-5) + log(10)
pH = 4.74 + 1
pH = 5.74
For solution 3: acetate=acetic acid
pH = pKa + log[CH3COO-]/[CH3COOH]
pH = -log(1.8*10^-5) + log(1)
pH = 4.74 + 0
pH = 4.74
Part B: Calculate molarity
pOH = pKb + log [H
5.29= -log (1.8*10^-5) + log [BH+]/[0.600 M]
5.29 = 4.744 + log [BH+]/[0.600 M]
0.546 = [BH+]/0.600
[BH+] = 0.3276 M
Moles NH4+ = 0.3276 M * 2.30 L
Moles NH4+ = 0.75348 moles
Moles NH4Cl = 0.75348 moles
Mass NH4Cl = 0.75348 moles * 53.49 g/mol
Mass NH4Cl = 40.30 grams
Why is the use of pesticides on soils and
crops harmful for humans?
A. Pesticides are carried across the surface
in runoff which can contaminate aquifers.
B. Pesticides kill organisms that can harm
plants.
C. Pesticides pollute wells that people drink
from.
D. Pesticides are evaporated with water and
contaminate the atmosphere.
Answer:
A.
Once it rains the pesticide goes down the runoff and pollute the water
When the system is at equilibrium, it contains NO 2 at a pressure of 0.817 atm , and N 2 O 4 at a pressure of 0.0667 atm . The volume of the container is then reduced to half its original volume. What is the pressure of each gas after equilibrium is reestablished
Final answer:
When the system is at equilibrium with specific initial pressures and the volume of the container is reduced by half, the pressure of each gas changes accordingly.The pressure of NO₂ will be 1.634 atm, and the pressure of N₂O₄ will be 0.1334 atm.
Explanation:
When the system is at equilibrium, it contains NO₂at a pressure of 0.817 atm, and N₂O₄ at a pressure of 0.0667 atm. If the volume of the container is reduced to half its original volume, the pressure of each gas will change.
According to the ideal gas law, the pressure of each gas will double when the volume is reduced by half. So, after re-establishing equilibrium, the pressure of NO₂ will be 1.634 atm, and the pressure of N₂O₄ will be 0.1334 atm.
A shallow river dries up is an example of
Condensation
Evaporation
Precipitation
Runoff
Answer:
Evaporation
Explanation:
Evaporation is when liquid becomes a gas which is how the river dried up
If'substance X is a liquid, substance Y is a gas, and substance Z is a solid, and all are at the
same temperature and pressure, then the order of increasing strength of their intermolecular
forces would be
The answer is Y < X < Z
Final answer:
The order of increasing strength of intermolecular forces for substance X (liquid), Y (gas), and Z (solid) is: Y < X < Z, with the gas having the weakest and the solid having the strongest intermolecular forces.
Explanation:
If we consider substances X, Y, and Z, which are a liquid, a gas, and a solid respectively, and they are all at the same temperature and pressure, the order of increasing strength of their intermolecular forces can be determined based on their states of matter. Given that substances with stronger intermolecular forces are more likely to be a solid at room temperature and will have a higher boiling point, it follows that the solid will have the strongest forces, followed by the liquid, and then the gas. Consequently, substance Z (the solid) would have the strongest intermolecular forces, substance X (the liquid) would have intermediate forces, and substance Y (the gas) would have the weakest forces.
An equivalent is:___________
a) an equivalent is the amount of ion that has a 1+ charge.
b) 1 mole of an ionic compound.
c) 1 mole of any ion. the amount of ion that carries 1 mole of electrical charge.
d) the amount of ion that has a 1- charge.
Answer:
The amount of ion that carries 1 mole of electrical charge
Explanation:
One equivalent: In reaction stoichiometry, the amount of one substance that reacts with one mole of another substance. This will often (but not always) be a 1:1 mole ratio.
An equivalent is the amount of ion that carries 1 mole of electrical charge.
An equivalent is the amount of a substance that reacts with one mole of another substance in a given chemical reaction.
It is a unit of measurement in Stoichiometry that helps to describe the amount of ion that carries 1 mole of electrical charge.
Examples include:
1 mole of Na⁺ = 1 Eq1 mole of Cl⁻ = 1 Eq1 mole of Ca²⁺ = 2 EqThus, we can conclude that an equivalent is the amount of ion that carries 1 mole of electrical charge.
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How many dozens of doughnuts are in 48 doughnuts
Final answer:
There are 4 dozens in 48 doughnuts, as a dozen is a group of 12 objects. This quantity would require four boxes with a volume of 324 cubic inches each to hold all the doughnuts.
Explanation:
To find out how many dozens of doughnuts are in 48 doughnuts, we can simply divide the total number of doughnuts by the number in a dozen. Since a dozen refers to 12 objects, we divide 48 by 12.
48 ÷ 12 = 4
Therefore, there are 4 dozens in 48 doughnuts. When buying items like doughnuts, it is common to acquire them in groups, like a dozen, because it is more convenient and efficient.
Let's consider the dimensional aspect for a moment. If you have a 9x9x4 inch box for a dozen doughnuts, this box would have a volume of 324 cubic inches. For 48 doughnuts, which we have established are 4 dozens, we would need four of these boxes, equating to 4 × 324 in3 or 1296 in3 in total to hold all of them.
How many moles are contained in 2.0 L of N2 at standard temperature and pressure.
0.091 moles are contained in 2.0 L of N2 at standard temperature and pressure.
Explanation:
Data given:
volume of the nitrogen gas = 2 litres
Standard temperature = 273 K
Standard pressure = 1 atm
number of moles =?
R (gas constant) = 0.08201 L atm/mole K
Assuming nitrogen to be an ideal gas at STP, we will use Ideal Gas law
PV = nRT
rearranging the equation to calculate number of moles:
PV = nRT
n = [tex]\frac{PV}{RT}[/tex]
putting the values in the equation:
n = [tex]\frac{1X2}{0.08201 X 273}[/tex]
n = 0.091 moles
0.091 moles of nitrogen gas is contained in a container at STP.
Final answer:
To find how many moles are in 2.0 L of N2 at standard temperature and pressure, we use the fact that 1 mole of any gas occupies 22.4 L at STP. By dividing 2.0 L by 22.4 L, we find that there are approximately 0.089 moles of N2.
Explanation:
The question asks, How many moles are contained in 2.0 L of N2 at standard temperature and pressure? To answer this, it's essential to know that at standard temperature and pressure (STP), which is defined as 0°C (273K) and 1 atmosphere (atm) of pressure, 1 mole of any ideal gas occupies 22.4 liters of volume. This is a key concept in understanding gas laws and mol calculations in chemistry.
Given that we have 2.0 liters of N2 gas at STP, we can use the proportionality given by the molar volume at STP to find the number of moles. Since 22.4 liters is equivalent to 1 mole of a gas, we can set up a simple calculation to find the moles of N2 in 2.0 liters:
Moles of N2 = Volume of N2 (L) / Volume of 1 mole of gas at STP (L)
= 2.0 L / 22.4 L
= 0.089 moles of N2
This calculation demonstrates the direct application of molar volume at STP to determine the number of moles in a given volume of gas.
What type of reaction occurs between amines and carboxylic acids at room temperature?
Answer:
Acid-base equilibrium.
Explanation:
At low temperatures the amines react with carboxylic acids as bases and not as nucleophiles. This acid-base reaction is disadvantageous on heating, with the nucleophilic attack that will form the amide prevailing under these conditions.
Name this compound please
Answer:
The answer to your question is butanal
Explanation:
To name this compound we must consider:
1.- Identify the functional group. The functional group of this molecule is the first carbon to the right and its oxygen.
When carbon is attached to oxygen is a border, this functional group is called Aldehyde.
2.- Count the total number of carbons starting from the right. This molecule has 4 carbons.
3.- Name the compound
An organic molecule with 4 carbons is called butane but change the ending for al, then the name will be butanal
1. What is the kinetic energy of 44 kg cheetah running at 31m/s speed?
Explanation:
Given
mass (m) = 44 kg
velocity (v) = 31 m/s
Now
Kinetic energy
= 1/2 mv²
= 1/2 * 44 * 31²
= 0.5 * 44 * 961
= 21142 joule
Hope it will help you :)
What is the only force that acts between particles of helium gas?
Answer: The only force that acts between particles of helium gas is Vanderwaal forces.
Explanation:
When molecules are uncharged in nature but still combined together due to the dipole moment of elements then this force holding the molecules together is known as Vanderwaal forces.
This force is weak in nature.
For example, particles of helium gas has Vanderwaal force between its atoms.
Thus, we can conclude that the only force that acts between particles of helium gas is Vanderwaal forces.
Test your knowledge of water's ability to dissolve
substances by matching the following statements
with the correct answers.
when water breaks apart an ionic compound into
cations and anions.
when water surrounds substances that have been
"broken apart":
when water breaks down substances and
surrounds individual molecules or particles:
Answer: 1 dissociation. 2. Hydration. 3. Dissolving.
Explanation:
If I have 5.6 liters of gas in a piston at a pressure of 150 kPa and compress the gas until its volume is 4.8 L, what will the new pressure inside the piston be? round to 2 decimal places
Answer:
P1V1 = P2V2
(1.5 atm)(5.6 L) = (x)(4.8 L) x = 1.8 atm
If we have 5.6 liters of gas in a piston at a pressure of 150 kPa and compress the gas until its volume is 4.8 L, the new pressure inside the piston will be 175 kPa.
What is combined gas law?The combined gas law is the law of of gaseous state which is made by combination of Boyle's law, Charle's law, Avogadro's law and Gay Lussac's law.
It is a mathematical expression that relates Pressure, Volume and Temperature.
(P1 × V1)÷T1 = (P2 × V2)÷T2
Here temperature doesn't change, hence-
(P1 × V1) = (P2 × V2)
P1 = 150 kPa
V1 = 5.6 litres
P2 = ?
V2 = 4.8 litres
P2 = 175 kPa
Therefore, If we have 5.6 liters of gas in a piston at a pressure of 150 kPa and compress the gas until its volume is 4.8 L, the new pressure inside the piston will be 175 kPa.
To learn more about combined gas law click:
https://brainly.com/question/13154969
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A container holds 20.4 L of CO2 at 1.58 atm, what is the volume at STP?
Answer:
32.232 L
Explanation:
-Given the volume at 1.58atm is 20.4 L
-At standard pressure, the pressure is 1.00atm
-We apply Charle's Law to find the volume at STP:
[tex]P_1V_1=P_2V_2\\\\\\1.58\ atm\times 20.4\ L=1.00\ atm\times V_2\\\\V_2=\frac{1.58\times 20.4}{1.00}\\\\\\\\=32.232\ L[/tex]
Hence, the volume of the gas at STP is 32.232 L