Perfective maintenance usually is cost effective ____ the system

Answer: d)MTTD

Explanation: MTTD(Mean Time To Detect) is the time for the discovery of the  problem in a system.  It is basically the average time until the problem is noticed by someone. For e.g.- if there is a problem in a computer system at 9:00 am and the problem is noticed at 9:10 am by then user then the MTTD is  10 minutes . So, MTTD gives the mean time for which the system remains available for use.

Answer:

loop

Explanation:

Loop is the one which is used to execute the specific statement again and again until the condition is true.

In the programming, there are 3 basic loop used.

1. for loop

Syntax:

for(initialization, condition, increment/decrement)

{

  statement;

}

the above statement execute until the condition in the for loop true when it goes to false, the loop will terminate.

2. while loop

Syntax:

initialization;

while(condition)

{

  statement;

increment/decrement;

}

it is work same as for loop and the increment/decrement can be write after or before the statement.

3. do while

syntax:

initialization;

do

{

   statement;

   increment/decrement;

}while(condition);

here, the statement execute first then, it check the condition is true or not.

so, if the condition is false it execute the statement one time. this is different with other loops.

Final answer:

A loop is a structure that allows repeated execution of a block of statements in programming. It is controlled by a condition that, when false, will terminate the loop to prevent an infinite loop.

Explanation:

The correct answer to the question is b. loop. A loop is frequently used in programming to allow the repeated execution of a block of statements until a specified condition is met. Loops are a form of conditional control flow that can drastically alter the execution path of a program.

For instance, a while-loop will continue to execute so long as its condition remains True. If the condition evaluates to False, the loop terminates and control is passed to the statements that follow. During each iteration within the loop, it is essential to modify some variables, such as the iteration variable, to ensure the loop does not continue indefinitely, potentially leading to an infinite loop.

Answer:

3.WDM

Explanation:

WDM ( wavelength division multiplexing ) involves signals composed of light beams WDM is used in communication where fibers are used it is used for multiplexing of number of carrier signals  which are made of optical fibers by using different wavelength of laser light it has different wavelength so this WDM is used for signals composed of light beams it has property of multiplexing of signal

Answer: ORG $3000 tell us that we want to load the program from the address $3000.

LDAA #$C2 tell us to load the value contained in the address present in the register C2 into the accumulator.

Explanation:

ORG instruction in  microprocessor does not have a fixed address. It tell us where to begin the execution of the program by loading into a starting address space. It does not uses fixed addressing

LDAA instruction uses indirect addressing by placing the value from the address present in the register. Here  the address is contained in register C2.

Answer:

11.32milisec.

Explanation:

Average seek time = 8ms

transfer rate = 50MB/sec

disk rotate = 10000 rpm

controller overhead = 0.3 msec

Average time = ?

Average time is the addition of the seek time, transfer time, rotation time and ontroller overhead

[tex]Average\,time = Seek\,time+Rotation\,time+Transfer\,time+Controller\,overhead[/tex]

now, find the rotation time,

Rotation time is the time at which half rotation is made.

[tex]Rotation\,time=\frac{0.5}{rotation\,per\,second}[/tex]

convert rotation per minute to rotation per second.

[tex]rps=\frac{10000}{60}[/tex]

substitute in the above formula.

[tex]Rotation\,time=\frac{0.5}{\frac{10000}{60} }=0.003sec[/tex]

or 3milisec

now, find the transfer time by formula:

[tex]Transfer\,time=\frac{Number\,of \,read\,or\,write\,bytes}{transfer\,rate}[/tex]

so, read or write bytes is 1024

[tex][tex]Transfer\,time=\frac{1024}{50*10^{6} }=0.02milisec[/tex][/tex]

The average time is:

[tex][tex]Average\,time= 8+3+0.02+0.3=11.32milisec[/tex][/tex]

Answer:

return

Explanation:

return is the statement which is used to return the value from the function definition to the function calling.

it is also used as exit from the function.

for example:

int count()

{

     return 0;

     printf("hello");

}

In the above the function return 0 without print the message "hello". we can used return any where inside the function for immediately ending the execution of function.

Final answer:

The statement that causes a function to end immediately is the 'return' statement, which halts function execution and returns the flow of execution to where the function was called.

Explanation:

The statement that causes a function to end immediately in most programming languages is a return statement. When the return statement is executed, it ends the function execution and the flow of execution goes back to where the function was called, which can be likened to coming back from a 'detour'. It's important to realize that defining a function also creates a variable with the same name, which can be used to call the function later in the code.

A functional approach to programming includes various other concepts. For instance, to end the function, you have to enter an empty line in some interactive environments like REPLs (Read-Eval-Print Loop), although this is not necessary in a script. The last statement of a function plays a role similar to a 'Note of Finality' in a speech, indicating the end of the logic encapsulated by the function.

C++ program for Validating password

#include <iostream>

#include<cstring>

using namespace std;

int main()//driver function

{

char password[100];//declaring variables password

int lower=0,upper=0,flag=1;

cout<<"Enter the password\n";//taking input

cin>>password;

int length = strlen(password);//finding length

for(int i=0;i<length;i++)

{

if(password[i]>=65&&password[i]<=90)/*checking string must contain at least one uppercase letter */

{

upper=1;

}

if(password[i]>=97&&password[i]<=122)/*Checking string must contain at least one uppercase letter*/

{

lower=1;

}

}

if(length<10)//checking that string length should be less than 10

{

flag=0;

cout<<"Password must be at least ten characters long\n";

}

if(upper==0)

{

flag=0;

cout<<"Password have to be at least one uppercase letter\n";

}

if(lower==0)

{

flag=0;

cout<<"Password have to be at least one lowercase letter\n";    

}

if(flag==1)//if all condition turns out to true,printing Valid Password  

{

cout<<"Valid Password";

}

}

Output

Enter the password  

 Ayushyadav

  Valid Password

Enter the password  

  Ayush

Password must be at least ten characters long

 Enter the password

anmolyadav

Password have to be at least one uppercase letter

ANMOLVIJWANI

Password have to be at least one lowercase letter

Answer:

A. Foward

Explanation:

ebay employs the forward auction mechanism.

Answer Explanation:c

PCM( pulse code modulation) is a process for transmitting the analog data from one place to other place the signal which are used in pulse code modulation are binary that is only 0 and 1 using PCM all forms of analog data can be form including voice music etc.

to obtain pcm an analog signal is sampled at regular time interval the sampling rate is very high as compared to the frequency used by analog signal. the instant amplitude of analog signal at each sampling is being closer to the nearest several specific earlier levels.this process is called tantalization. in this the number of level is power of 2 so the sampling time is set as 125 microseconds.

Answer:

--a * (3 + b) / 2 - c++ * b = -13

Explanation:

First we have to evaluate (3+b) = 7

As a=3, so "--a" will be 2.

So we need to evaluate "--a * (3 + b) / 2" and as we know * and / has same precedence we have to follow left association.

So in "--a * (3 + b) / 2", "--a * (3 + b)" = 2*7 is evaluated first that is 14. then [tex]\frac{14}{2}[/tex] = 7.

Now in "c++*b" as c is post-incremented, so it will take 5 rather than 6.

So c++*b = 5 *4 = 20.

Now --a * (3 + b) / 2 - c++ * b = 7-20 = -13

Answer: Privilege

Explanation:

Privilege escalation is type of intrusion attack whereby the attacker gain access into the system with the privileges of that of an administrator. This may be due to programming errors or any type of bug in the system. This attack is extremely dangerous because the attack can change the environment of the system as it gets the administrator rights and access.

Answer

For First physical memory address,we add 00000 in segment values.

For Last physical memory address,we add 0FFFF in segment values.

NOTE-For addition of hexadecimal numbers ,you first have to convert it into binary then add them,after this convert back it in hexadecimal.

a)1000

For First physical memory address, we add 00000 in segment value

We add 0 at the least significant bit while calculating.

          10000 +00000 = 10000 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           10000 +0FFFF =1FFFF    (from note)

b)0FFF

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

     0FFF0 +00000=0FFF0 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           0FFF0 +0FFFF =1FFEF (from note)

c)0001

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

     00010 +00000=00010 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           00010 +0FFFF =1000F (from note)

d) E000

For First physical memory address,we add 00000 in segment value

 We add 0 at the least significant bit while calculating.

    E0000 +00000=E0000 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           E0000 +0FFFF =EFFFF (from note)

e) 1002

For First physical memory address,we add 00000 in segment value

 We add 0 at the least significant bit while calculating.

    10020 +00000=10020  (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           10020 +0FFFF =2001F (from note)

Answer:

#include <iostream>

#include <stdlib.h>

#include <time.h>

using namespace std;

int main()

{

   srand (time(NULL));  //initialize random seed

   int guess;

    int number = rand() % 2;  //generate random number 0 or 1

    cout<<"Enter the guess (0 or 1): ";

    cin>>guess;     //store in guess

    if(number == guess){     //check if number equal to guess

       cout<<"Guess is correct."<<endl;   //if true print correct message.

    }else{

        cout<<"Guess is incorrect."<<endl;  //otherwise print correct message.

    }

    return 0;

}

Explanation:

first include the three library iostream for input/output, stdlib,h for using the rand() function and time for using the time() function.

create the main function and initialize the random number generation seed, then generate the random number using the function rand() from 0 to 1.

after that, take input from user and then with the help of conditional statement if else check if random number is equal to guess number or not and print the appropriate message.

Answer:

Internet is a WAN (wide are network)

Explanation:

Great question, it is always good to ask away and get rid of any doubts that you may be having.

The Internet is a worldwide interconnected network with computers acting as nodes around the world. Communicating and sharing information between one another. LAN and WAN are connection types for the Internet.

LAN is a Local Area Network, which interconnects local computer nodes physically using Ethernet cables. Which are then connected to the internet itself.

WAN are wide area networks, which are usually interconnected through public communication services such as telephone cable.

Therefore the Internet is a WAN (wide are network)

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

Answer:

True

Explanation:

the while loop is used to execute the statement again and again unti the condition is true. Once the condition is False, the program control terminate the while loop and execute the next statement after the while loop.

for example:

int i=0;

while(i<5)

{

i++;

}

cout<<i<<endl;

one the code execute the while loop run 5 times and in the 6th times the condition become False then program control moves to print statement.

Answer:

Software testing is defined as, it the process of evaluation of the functionality of the system software application to check whether the software met the specified requirement or not and also used to identify defects which ensured that the product is free from all defects in order to produce the quality products.

Types of testing we may utilize for a component using CBSE approach are:

As, CBSE stands for the component based software engineering where  programmers should design and implemented software components in such a way that many different program can reuse them.

Answer: Extensibility

Explanation:

Extensibility is one of the features which can be easily enhanced over time. As the term extensibility refers to the addition of new features and adding more features to the present modules. This does not change the internal organisation of the earlier modules in fact they add new and more improved features to the present.

Answer:

Preemptive multitasking is the operating system that control the processor by not involving in task cooperation and preemptive is the process of controlling the task. On the other hand, preemptive multi threading is the parallel processing system in which the execution of the thread is preemptive.

Non-preemptive multitasking is the process in which the processor are never involves with the task and it is used for many window applications. Whereas, in non preemptive multi threading when a thread are given control then, it continues run until it can control the blocks.

Answer: False

Explanation:

Fixed length instructions are faster than variable length instruction because the fixed length instruction uses one clock cycle for their instruction whereas variable instruction takes more than one clock cycle. As RISC uses fixed length instruction and its CPI(cycles per instruction) is less compared to CISC which uses variable length instructions.

So fixed length instruction sets are faster than variable length instruction.

Answer:

#include <bits/stdc++.h>

using namespace std;

int main() {

  string email,username,host;//strings to store email,username,hostname..

  cout<<"Enter the email address "<<endl;

  cin>>email;//taking input of email address..

  bool flag=1;

  for(int i=0;i<email.length();i++)//iterating over the string email..

  {

      if(email[i]=='@')//if @ symbol is encountered make flag 0 skip this iteration.

      {

          flag=0;

          continue;

      }

      if(flag==1)//add to username if flag is 1.

      {

          username+=email[i];

      }

      else//add tom host..

      host+=email[i];

  }

  cout<<"The username is "<<username<<endl<<"The host name is "<<host;//printing the username and hostname..

return 0;

}

Explanation:

I have taken  three strings to store the email address entered by user ,username and host to store username and host name respectively.Then I am iterating over the string email if @ is encountered then skip that iteration before that keep adding characters to username string and after that keep adding characters to host.

Answer:

True

Explanation:

Algorithm for push function

The method of placing data on a stack is called a push operation.

It involves these steps −

Algorithm for Insertfirst function

As we can see that in both algorithms ,we are inserting data to a new nodes and incrementing/pointing to a new node for inserting data.Both algorithms uses the same approach.

Answer:

The term ‘Internal Recruitment’ refers to the process of identifying and attracting candidates from a certain organization to another position within the same organization.

Instead of opening the position to the public and attracting random candidates some companies may choose to advertise the vacancy internally and only allow members of the staff to apply.

Internal recruitment also refers to a strategy mostly big corporations use to advertise their jobs internally. Due to the size of these companies, these job openings would otherwise go unnoticed by employees in other departments.

Answer:

The answer is (C)

Let’s run the algorithm on a small input to see the working process.

Let say we have an array {3, 4, 1, 5, 2, 7, 6}. MAX = 7

Explanation:

So from the above execution, we got that the program reverses the numbers stored in the array.

Final answer:

The provided program reverses the numbers stored in the array by swapping elements from the start of the array with their corresponding elements at the end until it reaches the middle of the array. The correct answer is C. Reverses the numbers stored in the array.

Explanation:

The effect of the provided program is that it reverses the numbers stored in the array a. It uses a for-loop to swap elements symmetrically from the start and end of the array towards the middle. Specifically, for each iteration of the loop, it takes an element from the beginning part of the array (indexed by i) and swaps it with the corresponding element from the end of the array (indexed by MAX - i - 1).

The correct choice from the given options is:

This code does not arrange the elements in ascending order, count elements, or specifically move the largest value to the last position, so options A, B, and D are incorrect.

Explanation:

--!#&?&#&#(-$(-$)-"-)"(-'-)';'!'+%

Answer: Java exception inherits from exception class and  C++ exception is everywhere in the program.

Explanation: Java exception are the unwanted events that occur during the run time of a particular program and breaks the flow of it. Java exception are the subclass of the exception class that is it is derived from them.So, java exception inherits from exception class.

C++ exception are those circumstances which appear during a program which are unnecessary faults during the execution of a program. the exception allows to transfer the control  from one part to another part in a particular program. So, the C++ exception is anywhere in the  program.

Answer:

No Answer

Explanation:

LAN : Local Area Network

Used to connect all the computers with in a building or some limited distance

so that people can share data  and applications between different computers

useful for Intranet applications

WAN: Wide Area Network

used to cover large geographical area. it is network of networks. useful for computer networking.In short a WAN connects several LAN

Answer:

Vertical exchanges are typically used only to buy and sell materials required for an organization's support activities- False

This statement is false.

Answer:

If a returntype is added to a constructor method in Java, it ceases to be a constructor and behaves like an ordinary class method with the same name as class name.

Explanation:

If a returntype is added to a constructor method in Java, it ceases to be a constructor and behaves like an ordinary class method with the same name as class name.

Constructors are special methods which are used for initializing the object. Constructors do not have a return type. If we add a return type to the constructor method , it does not play any role during object initialization and can be involved like any other object method.

Answer:

T

Explanation:

an abstract class can be extended by another.the abstract class which is extending should be implemented by another class

Answer:

#include<bits/stdc++.h>

using namespace std;

int main()

{

   string st;

   getline(cin,st);

   int i=0;

   while(i<st.length())

   {

       if(isupper(st[i]))

       {

           st.erase(st.begin()+i);

           continue;

       }

       i++;

   }

   cout<<st<<endl;

   return 0;

}

Explanation:

I have included the file bits/stdc++.h which include almost most of the header files necessary.

For taking the input as a string line getline is used.

For checking the upper case isupper() function is used. cctype header file contains this function.

For deleting the character erase function is used.