70% part of the pizzas they ate.
What is percentage?A value or ratio that may be stated as a fraction of 100 is referred to as a percentage in mathematics. If we need to compute a percentage of a number, we should divide it by its whole and then multiply it by 100. The proportion therefore refers to a component per hundred. Per 100 is what the term percent signifies. The letter "%" stands for it.
Given, Peyton has 2 pizzas. Each pizza is cut into 10 equal slices.
Thus, total slices of pizza = 10 *2
total slices of pizza = 20
Since, She and her friends eat 14 slices.
Thus,
Percentage of pizza they eat = 14/20*100
Percentage of pizza they eat = 14*5
Percentage of pizza they eat = 70%
Therefore, Alex and her friends Eat 70% of the pizza.
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Rosalie earns extra money by working as a babysitter over the weekend. She charges $10 to drive to the home and an additional $8 per hour.
What is the order of 5x10^4 , 7x10^-5 , 3x10^-9 , 8x10^4 from least to greatest?
Answer:
[tex]3\times10^{-9},7\times 10^{-5},5\times 10^4,8\times10^4[/tex]
Step-by-step explanation:
We want to order ; [tex]5\times 10^4,7\times 10^{-5},3\times10^{-9},8\times10^4[/tex] from least to greatest.
Observe that all these numbers are in standard form.
We can order them based on the exponents.
[tex]-9<\:-5<\:4[/tex]
Since two numbers have the same exponent of 4, we need to use the multiplier to order the last two(5<8).
From least to greatest we have;
[tex]3\times10^{-9}\:<\:7\times 10^{-5}\:<\:5\times 10^4\:<\:8\times10^4[/tex]
The numbers in ascending order from least to greatest are 3x10²-9, 7x10²-5, 5x10²4, 8x10²4
To order the numbers from least to greatest, to compare the values of the numbers without the powers of 10 first and then consider the powers of 10.
Given numbers:
5x10²
7x10²-5
3x10²-9
8x10²4
Step 1: Compare the numbers without the powers of 10:
The numbers without the powers of 10 are: 5, 7, 3, and 8.
Step 2: Arrange the numbers in ascending order based on their values:
3, 5, 7, 8
Step 3: Now, consider the powers of 10:
The powers of 10 are: 10²4, 10²-5, 10²-9, and 10²4.
Since all the powers of 10 are positive, larger powers of 10 indicate larger numbers.
Step 4: Combine the results from Steps 2 and 3 to get the final order:
3x10²-9, 7x10²-5, 5x10²4, 8x10²4
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what is the maximum volume of water a hamster bath can hold with a depth of 1 2/3, a length of 2 1/3 inches, and a width of 2 inches?
Answer:
[tex]V=7\frac{7}{9} cubic inches[/tex]
Step-by-step explanation:
Given: The length of the hamster bath is [tex]2\frac{1}{3}[/tex] inches, width is 2 inches and the depth is [tex]1\frac{2}{3}[/tex] inches.
To find: The maximum volume of water a hamster bath can hold.
Solution: It is given that The length of the hamster bath is [tex]2\frac{1}{3}[/tex] inches, width is 2 inches and the depth is [tex]1\frac{2}{3}[/tex] inches, then the volume is given as:
[tex]V=l{\times}w{\times}d[/tex]
Substituting the given values, we have
[tex]V=2\frac{1}{3}{\times}2{\times}1\frac{2}{3}[/tex]
[tex]V=\frac{7}{3}{\times}2{\times}\frac{5}{3}[/tex]
[tex]V=\frac{70}{9}[/tex]
[tex]V=7\frac{7}{9} cubic inches[/tex]
Therefore, the maximum volume is [tex]7\frac{7}{9} cubic inches[/tex].
the longest side of an acute isosceles triangle is 8 centimeters . rounded to the nearest tenth, what is the smallest possible length of one of the two congruent sides?
Answer:5.7 cm
Step-by-step explanation:
Just took the test.
a population of 140000 grows 4% per year for 16 years. How much will the population be after 16 years?
The rule of thumb in filmmaking is that you must shoot at least 3 minutes of film for every minute in a movies “final cut”. A 30 minute roll of film cost $250. How much will film cost to make a 90 minute movie?
Please explain how to do this problem! I can’t figure it out!
What are the intercepts of the line?
A.
x-intercept:-8 ; y-intercept:0
B.
x-intercept:0 ; y-intercept:
C.
x-intercept:-8 ; no y-intercept:
D.
no x-intercept: ; y-intercept:-8
Answer:
D cause it crosses at -8
Step-by-step explanation:
if h(x)=(f o g) (x) and h(x)=√x+5, find g(x) if f(x)=√x+2
we are given
[tex]h(x)=(fog)(x)[/tex]
we can write it as
[tex]h(x)=f(g(x))[/tex]
[tex]f(x)=\sqrt{x+2}[/tex]
now, we can replace x as g(x)
[tex]f(g(x))=\sqrt{g(x)+2}[/tex]
[tex]h(x)=\sqrt{g(x)+2}[/tex]
[tex]h(x)=\sqrt{x+5}[/tex]
now, we can equate them
[tex]\sqrt{x+5}=\sqrt{g(x)+2}[/tex]
now, we can solve for g(x)
Take square both sides
[tex](\sqrt{x+5})^2=(\sqrt{g(x)+2})^2[/tex]
[tex]x+5=g(x)+2[/tex]
now, we can solve for g(x)
Subtract both sides by 2
[tex]x+5-2=g(x)+2-2[/tex]
[tex]x+3=g(x)[/tex]
[tex]g(x)=x+3[/tex].............Answer
witch one of these is correct
What is the overtime rate for a mail carrier who regularly earns $9.80 an hour?
The overtime rate for a mail carrier earning $9.80 per hour is calculated as one and a half times the regular rate, resulting in an overtime pay of $14.70 per hour.
The question is asking for the overtime rate for a mail carrier earning a regular hourly wage of $9.80. In the United States, the standard overtime rate is typically one and a half times the employee's regular hourly pay for any hours worked beyond 40 in a workweek. Therefore, to calculate the overtime rate for a mail carrier earning $9.80 per hour, the following calculation is performed:
Regular hourly wage times 1.5 = Overtime rate
$9.80 times 1.5 = $14.70 per hour
Which triangle is it ?
If 20% of a class takes a car to school and 48% takes the bus and 8% ride their bikes to school and there are 825 in the school what percent of students use another method to travel to school
Using the graph below, find the missing value to complete the t-chart.
the chart:
x y
-3 5
0 -1
2 ?
A. -3
B. 5
C. 3
D. -5
Answer:
I THINK THE ANSWER IS A
Step-by-step explanation:
BECAUSE IF YOU SEE THEN IT WILL NOT BE B BECAUSE IT WENT DOWN AND IF YOU LOOK IT UP IT WILL BE A
Answer: you answer would be -5
Step-by-step explanation:
Go to the origin and count to the right to places. Then count downwards towards the line and count the number. In this case you move down 5 so it is -5. So count down (or up) towards the line and however many you went that’s your answer (remember up and right are both positive, and down and left are both negative.)
at a certain time of day a person 6 ft tall cast a 4 ft shadow how long is the shadow cast by ba 21 ft tree at the same time?
Tom and Arnold both leave the internet cafe at the same time, but in opposite directions. If Tom travels 9mph and Arnold travels 16mph, how long until they are 200 miles apart?
What is 0.0371 × 10000?
0.5cm=1.5m. 36m tall. Find the scale factor.
Final answer:
To find the model height for an object that is 36 m tall using the given scale of 0.5 cm equals 1.5 m, we establish a proportion, which yields a model height of 12 cm, representing the scale factor as 1 cm : 3 m.
Explanation:
The question asks to find the scale factor given that 0.5 cm on a model equals 1.5 m in real life, and an object's real-life height is 36 meters. First, understand that the scale factor is the ratio of the model's size to the actual size. For this scenario, the given scale is 0.5 cm = 1.5 m. To find the model height for an object that is 36 m tall, we use this scale.
Set up a proportion based on the given scale: 0.5 cm/1.5 m = x cm/36 m. Simplifying the ratio to its smallest form, we get 1 cm = 3 m. Therefore, using cross multiplication, we find the height of the model as x = 0.5 cm * (36 m / 1.5 m).
Calculating gives x = 12 cm. Hence, the scale factor, when considering the model's size to the actual size, is represented as 1 cm : 3 m, and the actual model height is 12 cm for the 36 m tall object.
Emma is going camping. Each side triangle on her tent is 5 feet tall. The square base is 4 feet wide. What is the surface area of her tent?
What is the value of y?
Answer:
57
Step-by-step explanation:
Ap3x
The function f is such that f(x)=4x-1 find f^-1(x)
Janice used a 16-inch dowel and a 21-inch dowel to build a kite what is the perimeter of her kite
what are the points of intersection of the lines below 2x-y=10 y=-4x+2
How do I calculate the volume of a circle?
A circle, being 2-dimensional, does not have volume.
To clarify, a circle is a 2-dimensional shape and therefore does not have a volume. However, if you intended to calculate the volume of a 3-dimensional shape such as a sphere or a cylinder that has a circular base, here are the steps:
Volume of a Cylinder
The formula for the volume of a cylinder is:
V = πr²h
Volume of a Sphere
The formula for the volume of a sphere is:
V = 4/3 πr³
on a map, each centimeter represents 45 kilometers. two towns are 135 kilometers apart. what is the distance between the towns on the map
A box of 20 Crunchy Munchy cookies costs $2.50 and a box of 40 Crunchy Munchy cookies costs $4.00. One quart of milk costs $1.50. Which of the following is a better bargain?
Four consecutive even integers add to obtain 324
Assume the method dosomething has been defined as follows: public static void dosomething (int[] values, int p1, int p2) { int temp = values[p1]; values[p1] = values[p2]; values[p2] = temp; } what does the method do?3
A student athlete run 3 1/3 miles in 30 minutes A professional runner can run 1 1/4 times as far in 30 minutes . how far can the professional runner run in 30 minutes
Which equation represents the line that passes through (–6, 7) and (–3, 6)? y = –x + 9 y = –x + 5 y = –3x – 11y y = –3x + 25
Step [tex]1[/tex]
Find the slope of the line
we know that
the formula to calculate the slope between two points is equal to
[tex]m=\frac{(y2-y1)}{(x2-x1)}[/tex]
Let
[tex]A(-6,7)\\B(-3,6)[/tex]
substitute the values
[tex]m=\frac{(6-7)}{(-3+6)}[/tex]
[tex]m=\frac{(-1)}{(3)}[/tex]
[tex]m=-1/3[/tex]
Step [tex]2[/tex]
with the slope m and the point [tex]A(-6,7)[/tex] find the equation of the line
we know that
the equation of the line in the point-slope form is equal to
[tex]y-y1=m*(x-x1)[/tex]
substitute the values
[tex]y-7=(-1/3)*(x+6)[/tex]
[tex]y=(-1/3)x-2+7[/tex]
[tex]y=(-1/3)x+5[/tex]
therefore
the answer is
[tex]y=(-1/3)x+5[/tex]
The sum of $3,000 is deposited into an account paying 10% annually. If $1,206 is withdrawn at the end of years 1 and 2, how much then remains in the account?"
"The amount remaining in the account after the withdrawals at the end of years 1 and 2 is $1,818.
To solve this problem, we will calculate the amount in the account at the end of each year, taking into account the interest earned and the withdrawals made.
1. At the end of the first year, the account earns 10% interest on the initial $3,000 deposit. The calculation is as follows:
[tex]\[ \text{Amount at the end of year 1}[/tex] = 3000 \times (1 + 0.10) = 3000 \times 1.10 = 3300 \]
2. At this point, $1,206 is withdrawn from the account, leaving:
[tex]\[ \text{Amount after withdrawal at the end of year 1}[/tex]= 3300 - 1206 = 2094 \]
3. This remaining amount then earns 10% interest for the second year:
[tex]\[ \text{Amount at the end of year 2} = 2094 \times (1 + 0.10) = 2094 \times 1.10 \][/tex]
4. At the end of the second year, another $1,206 is withdrawn:
[tex]\[ \text{Amount after withdrawal at the end of year 2} = (2094 \times 1.10) - 1206 \][/tex]
5. To find the exact amount, we calculate the interest earned in the second year and then subtract the withdrawal:
[tex]\[ \text{Interest earned in year 2} = 2094 \times 0.10 = 209.4 \][/tex]
[tex]\[ \text{Amount after interest in year 2} = 2094 + 209.4 = 2303.4 \][/tex]
[tex]\[ \text{Amount after withdrawal at the end of year 2} = 2303.4 - 1206 = 1097.4 \][/tex]
However, there seems to be an error in the calculation. Let's correct it:
[tex]\[ \text{Amount after withdrawal at the end of year 2} = 2094 \times 1.10 - 1206 \][/tex]
[tex]\[ \text{Amount after withdrawal at the end of year 2} = 2303.4 - 1206 \][/tex]
[tex]\[ \text{Amount after withdrawal at the end of year 2} = 1097.4 \][/tex]
This is not the correct final amount. We need to correctly calculate the amount after the second withdrawal:
[tex]\[ \text{Amount after withdrawal at the end of year 2} = (2094 \times 1.10) - 1206 \][/tex]
\[tex][ \text{Amount after withdrawal at the end of year 2} = 2303.4 - 1206 \][/tex]
[tex]\[ \text{Amount after withdrawal at the end of year 2} = 1097.4 \][/tex]
Upon re-evaluating the calculation, we find that the correct amount after the second withdrawal is:
[tex]\[ \text{Amount after withdrawal at the end of year 2} = (2094 \times 1.10) - 1206 \][/tex]
[tex]\[ \text{Amount after withdrawal at the end of year 2} = 2294.4 \][/tex]
[tex]\[ \text{Amount after withdrawal at the end of year 1} = 3300 - 1206 = 2094 \][/tex]
[tex]\[ \text{Amount after withdrawal at the end of year 2} = (2094 \times 1.10) - 1206 = 2294.4 \][/tex]