Phillip flips a coin, rolls a standard number cube, and randomly chooses a shape from the list below. Find the probability that the coin will show tails, the cube will show an odd number, and a red shape will be chosen. 1/6 1/2 None of these 1/12 1/8 HELPPP PLZ TODAY!!!!

The probability Bill hits a higher percentage than Wilt in free throws is approximately 0.0085, or 0.85%.

To find the probability that Bill hits a higher percentage of his shots than Wilt, we can use the concept of binomial distributions.

Let's denote:

- [tex]\( W \)[/tex] as the number of successful shots Wilt makes out of 50,

- [tex]\( B \)[/tex] as the number of successful shots Bill makes out of 50.

Since Wilt makes 75% of his free throws and Bill makes 85% of his free throws, we can calculate the expected number of successful shots for each:

- For Wilt: [tex]\( E(W) = 50 \times 0.75 = 37.5 \)[/tex]

- For Bill: [tex]\( E(B) = 50 \times 0.85 = 42.5 \)[/tex]

Now, we can use the normal approximation to the binomial distribution to calculate the probability that Bill hits a higher percentage of his shots than Wilt. We'll assume that both distributions are approximately normal due to the central limit theorem.

The standard deviation for each player's distribution can be calculated as:

- For Wilt: [tex]\( \sigma_W = \sqrt{n \times p_W \times (1-p_W)} = \sqrt{50 \times 0.75 \times 0.25} \)[/tex]

- For Bill: [tex]\( \sigma_B = \sqrt{n \times p_B \times (1-p_B)} = \sqrt{50 \times 0.85 \times 0.15} \)[/tex]

Now, we can calculate the probability using a normal distribution:

[tex]\[ P(B > W) = P\left(Z > \frac{{E(B) - E(W)}}{{\sqrt{\sigma_B^2 + \sigma_W^2}}}\right) \][/tex]

Where [tex]\( Z \)[/tex] is a standard normal random variable.

Calculating:

[tex]\[ P(B > W) = P\left(Z > \frac{{42.5 - 37.5}}{{\sqrt{50 \times 0.85 \times 0.15 + 50 \times 0.75 \times 0.25}}}\right) \][/tex]

[tex]\[ P(B > W) = P(Z > 2.3717) \][/tex]

Using a standard normal distribution table or calculator, we find that  [tex]P(Z > 2.3717) \approx 0.0085 \).[/tex]

So, the probability that Bill hits a higher percentage of his shots than Wilt is approximately 0.0085, or 0.85%.

Answer: 2.32 seconds.

Step-by-step explanation:

Knowing that:

You can calculate how much longer it takes to her to swim the second half than the first half, by subtracting 30.12 seconds and 27.8 seconds.

Then:

[tex]30.12\ seconds-27.8\ seconds=2.32\ seconds[/tex]

Therefore, it took her 2.32 seconds longer to swim the second half on the race than the first half.

Answer:

2.32 seconds.

Step-by-step explanation:

We have been given that Lily swims a 100 meter race. She swims the first half 27.8 seconds and she swims the second half in 30.12 seconds.

To find how much longer it took Lily to swim the second half on the race than the first half, we need to subtract the time taken by Lily on first half from the time taken by Lily on second half.

[tex]\text{Difference of time}=30.12\text{ seconds}-\text{27.8 seconds}[/tex]

[tex]\text{Difference of time}=2.32\text{ seconds}[/tex]

Therefore, it took Lily 2.32 seconds more to swim the second half on the race than the first half.

Answer:

2

Step-by-step explanation:

The greatest common factor of whole numbers is the largest number that is a factor of all numbers. That is, it is the largest number that can divide all numbers.

In this case, the largest number that divide all the numbers is 2, who can divide 4, 18 and 12.

So:

[tex](4k, 18k^{4} ,12)= 2(2k,9k^{4} , 6)[/tex]

Let us say Amelia has y number of quarters and x number of nickel coins.

So total she has 15 coins.

[tex] x+y=15 [/tex]

[tex] x=15-y [/tex].................(1)

Now she has total amount = $2.15

1 dollar = 20 nickels and 1 dollar = 4 quarters

1 nickel = 0.05 dollar and 1 quarter = 0.25 dollar

so we can say that in terms of dollars,

[tex] 0.05x + 0.25y =2.15 [/tex].................. (2)

Plugging x from (1) in (2)

[tex] 0.05(15-y) + 0.25y =2.15 [/tex]

On solving we get ,

y=7

x=15-y =15-7 = 8

Answer: There are 8 nickels and 7 quarters.

Amelia has 7 quarters and 8 nickels, totaling $2.15 with 15 coins in total.

Let's solve it step by step.

Let's denote:

- [tex]\( Q \)[/tex] as the number of quarters.

- [tex]\( N \)[/tex] as the number of nickels.

Given that Amelia has a total of 15 coins, we can write the equation:

[tex]\[ Q + N = 15 \][/tex]

We're also given that the total value of her coins is $2.15. Since each quarter is worth $0.25 and each nickel is worth $0.05, we can write another equation for the total value:

[tex]\[ 0.25Q + 0.05N = 2.15 \][/tex]

Now, we can use these two equations to solve for [tex]\( Q \)[/tex] and [tex]\( N \)[/tex].

Step 1: Solve the first equation for [tex]\( Q \)[/tex]:

[tex]\[ Q = 15 - N \][/tex]

Step 2: Substitute this expression for [tex]\( Q \)[/tex] into the second equation:

[tex]\[ 0.25(15 - N) + 0.05N = 2.15 \][/tex]

Step 3: Distribute and solve for [tex]\( N \)[/tex]:

[tex]\[ 3.75 - 0.25N + 0.05N = 2.15 \][/tex]

[tex]\[ 3.75 - 0.20N = 2.15 \][/tex]

[tex]\[ -0.20N = 2.15 - 3.75 \][/tex]

[tex]\[ -0.20N = -1.60 \][/tex]

Step 4: Divide both sides by -0.20 to solve for [tex]\( N \)[/tex]:

[tex]\[ N = \frac{-1.60}{-0.20} \][/tex]

[tex]\[ N = 8 \][/tex]

Now that we know Amelia has 8 nickels, we can substitute this value back into one of the original equations to solve for [tex]\( Q \).[/tex]

Step 5: Use the first equation to solve for [tex]\( Q \)[/tex]:

[tex]\[ Q = 15 - 8 \][/tex]

[tex]\[ Q = 7 \][/tex]

So, Amelia has 7 quarters and 8 nickels.

Answer:

i will say bullet proof vest there are my reason

1. your teacher is suppose to keep you safe

2.bullet proof vest would keep you safe from gun shootings

3. school guards should check everyone's pockets before interning the school building

i hope this helps you -pandamathhelper  

The reconciled balance is calculated by starting with the checkbook balance, subtracting outstanding checks and any bank charges or errors. In Jim Lee's case, the reconciled balance is $4,320.

The reconciled balance for Jim Lee's bank account involves adjusting Jim's checkbook balance by accounting for any outstanding checks and any bank charges or errors. To calculate the reconciled balance, you follow these steps:

So, the reconciled balance would be: $6,800 (checkbook balance) - $1,330 (outstanding checks) - $120 (NSF check) - $30 (service charge) = $4,320.

Answer:

c = 23.3

Step-by-step explanation:

Answer:

[tex]23.3 \pi[/tex] cm

Step-by-step explanation:

Circumference of circle = [tex]2 \pi r[/tex]

The circumference of a circle is 60π cm.

So,  [tex]2 \pi r=60 \pi[/tex]

[tex]2r=60[/tex]

[tex]r=30[/tex]

Formula of length of arc = [tex]2 \pi r \times \frac{\theta}{360}[/tex]

Length of arc = [tex]2 \pi \times 30 \times \frac{140}{360}[/tex]

Length of arc = [tex]23.3 \pi[/tex]

So, Option C is true

Hence Length of arc is [tex]23.3 \pi[/tex] cm

The solution for the inequalities x² < 144 is the set of numbers that are greater than -12 and less than 12. Therefore, the solutions from the given options are 11, 7, -8, and -20.

The solution for the given inequality, x² < 144, is the set of all real numbers x for which x² is less than 144.

First, take the square root on both sides of the inequality to get -12 < x < 12.

This means x can be any number greater than -12 and less than 12.

The following numbers amongst the options given satisfy these conditions: -20, -8, 7, and 11.

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The expressions describing the area of the shaded region is 1/2 × 1/4

Expressions in math are mathematical statements that have a minimum of two terms containing numbers or variables, or both, connected by an operator in between.

Given that, a rectangle is divided into 12 columns and 6 rows, making 72 smaller rectangles.

We need to find the expressions for the area of the shaded region,

So, we have,

The height is 6 and the length is 12

The shaded part is 3 boxes by 3 boxes

Therefore, we can write =

3/6 × 3/12 = 1/2 × 1/4

Hence, the expressions describing the area of the shaded region is 1/2 × 1/4

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Answer: [tex][Q - R] + [S - T]=10m+7n-14[/tex]

Step-by-step explanation:

Given : [tex]Q = 7m + 3n[/tex],

[tex]R = 11 -2m[/tex],

[tex]S = n + 5[/tex], and

[tex]T = -m - 3n + 8[/tex]

Now  , [tex]Q-R= 7m + 3n-(11 - 2m)[/tex]

[tex]Q-R= 7m +3n-11+2m[/tex]    [ ∵ (-)(+)=(-) and (-)(-)=(+)]

[Note : when -1 is outside the parenthesis it indicates that -1 should be multiplied with each of the terms present inside the parenthesis .]

[tex]Q-R= 9m +3n-11[/tex]  [Combine like terms.]

[tex]S-T=n + 5-(-m - 3n + 8)[/tex]

[tex]S-T=n + 5+m+3n-8[/tex]    [ ∵ (-)(+)=(-) and (-)(-)=(+)]

[tex]S-T=4n +m-3[/tex]    [Combine like terms.]

Now, [tex][Q - R] + [S - T]=[9m +3n-11]+[4n +m-3][/tex]

[tex]=9m +3n-11+4n+m-3[/tex]

[tex]=10m+7n-14[/tex]  [combine like terms]

Hence, [tex][Q - R] + [S - T]=10m+7n-14[/tex]

Answer: 2,3,5

Step-by-step explanation:

To determine equations with no real solutions, assess for a negative discriminant or no x-intercepts in quadratic equations. Steps include identifying unknowns, choosing appropriate equations, simplifying terms, and checking for reasonableness.

To select each equation that has NO real solution, we must assess the equations provided, looking for specific characteristics that indicate the absence of real solutions. One of the hallmarks of such equations is when they represent a quadratic equation with no x-intercepts or the discriminant (b^2 - 4ac) in the quadratic formula is negative, which means the roots are complex numbers.

When working on problems like these, it's crucial to go through several steps: Identify the unknown, identify the knowns, choose an equation, eliminate terms to simplify the algebra, and then check the answer to see if it is reasonable.

Let's use an example equation: x^2 + 4 = 0. To determine if this has real solutions, we can identify the unknown (x), the knowns (coefficients of x), solve the equation or calculate the discriminant (4^2 - 4*1*-4 = 16 +16 = 32, which is positive), and confirm whether the solutions are real or not. In this case, because the discriminant is positive, this equation does have real solutions, and therefore would not be included in a list of equations with no real solutions.

The equations 2x² - 4x + 5 = -3, x² - 12x + 60 = 12, and x² + 3x + 6 = 0 have no real solutions, based on their negative discriminants.

We need to determine the discriminant (b² - 4ac) of each equation to check for real solutions. A negative discriminant indicates no real solutions.

Equations Analysis

Equations with No Real Solutions

Complete Question - Select each equation that has no real solution.

Final answer:

To calculate the number of times a hummingbird flaps its wings per minute, you multiply the number of flaps per second by 60. In this case, hummingbirds flap their wings approximately 4800 times per minute.

Explanation:

To calculate how many times a hummingbird flaps its wings per minute, you can start by determining how many times it flaps its wings per second. Given that some species of hummingbirds flap their wings 80 times per second, you can simply multiply this by 60 to find the number of times per minute:

80 flaps/second x 60 seconds/minute = 4800 flaps/minute

Therefore, hummingbirds flap their wings approximately 4800 times per minute.

The required graph of the quadratic function is the parabola shown in the attachment.

Given that,
To determine the graph to the best match of the graphed quadratic equation. F(x) = x² + 4x.

A parabola is a cross-section cut out of the cone and represented by an equation.

What is a graph?

The graph is a demonstration of curves that gives the relationship between the x and y-axis.

Here,
The given equation represents the parabola with vertex at (-2, - 5).
and a graph of the parabola is attached below.

Thus, the required graph of the quadratic function is the parabola shown in the attachment.

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Answer:

m=8

Step-by-step explanation:

on imagine 2021

Answer:

the x-intercepts are (-1,0) and (-11,0), the y-intercept is (0,11).

The answer is 140, you just add them up and it goes by 2.