Answers
You need a value at x = 2 that makes 4x = 8
2 equations, 2 unknowns. This think has to have an answer.
cx^2 + d = 2 when x = 1
c(1)^2 + d = 2
c + d = 2
cx^2 + d = 8 when x = 2
4c + d = 8
c + d = 2 Subtract
3c = 6
c = 2
Now go back and solve for d
c + d = 2
d = 0
==========
That should make it continuous at every point.
You should take note that h(x) has a problem at x = 2. The graph is well behaved at less than x =2 and it is well behaved at x > 2. It is just x = 2 that's the double ugly part of the problem. Check your givens above to make sure you understand what I'm saying. If you don't give me a shout.
Related Questions
Describe the graph of the function at its roots.
f(x) = (x − 2)3(x + 6)2(x + 12)
At x = 2, the graph the x–axis.
A) Crosses
B) Touches
Answers
answers:
Describe the graph of the function at its roots.
f(x) = (x − 2)3(x + 6)2(x + 12)
At x = 2, the graph crosses the x–axis.
At x = −6, the graph touches the x–axis.
At x = −12, the graph crosses the x–axis.
The required solution of the given function, at x = 2 the graph crosses the x-axis.
Given that,
The graph of the function at its roots. f(x) = (x − 2)³(x + 6)²(x + 12)
To discuss At x = 2, the graph is the x-axis.
Functions are the relationship between sets of values. e g y=f(x), for every value of x there is its exists in a set of y. x is the independent variable while Y is the dependent variable.
here,
The graph of the given function f(x) = (x − 2)³(x + 6)²(x + 12) is show,
From the graph, it is found that at x = 2, the graph passes through the x-axis.
Thus, the required solution of the given function, at x = 2 the graph crosses the x-axis.
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True or false All equilateral triangles are isosceles
Answers
Answer:
TRUE
Step-by-step explanation:
When all sides are the same length, at least one pair of sides is the same length.
Answer:
the answer is true
Step-by-step explanation:
Find the value of x. Round the answer to the nearest tenth, if needed.
A.
5.3
B.
15.9
C.
31.7
D.
48.1
Answers
How to tell if a scatter plot is positive or negative or no ttend?
Answers
What is the length of the base of a right triangle with an area of 20 m² and a height of 4 m? A.5 m B.10 m C.80 m D.160 m
Answers
l or b = length or base
w or h = width or height
a = area
b x h = a
b x (4) = 20
4b = 20
4b/.4 = 20/4
b = 20/4
b = 5
A. 5m is your answer
hope this helps
helppppppppppppppppppppppppppppppp
Answers
((2 ^ (1/2)) * (2 ^ (3/4))) ^ 2
We use for this case the properties of lso exponents:
((2 ^ (1/2)) * (2 ^ (3/4))) ^ 2
((2 ^ (2/2)) * (2 ^ (6/4)))
((2 ^ (1)) * (2 ^ (3/2)))
((2 ^ (1 + 3/2))
((2 ^ (5/2))
answer:
((2 ^ (5/2))
option 2
If f(x) = x2 + 1 and g(x) = x – 4, which value is equivalent to ? 37 97 126 606
Answers
Answer:
37
Step-by-step explanation:
its 37
The value of a composite function (f•g)(x) at x = 10 is 37 if the function f(x) = x² + 1 and g(x) =x - 4 option (A) 37 is correct.
What is a function?It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
The question is incomplete.
The complete question is:
If f(x) = x² + 1 and g(x) = x - 4, which value is equivalent to (f•g)(10)?
3797126606We have a function:
f(x) = x² + 1
g(x) =x - 4
Plug x = 10 in the function g(x)
g(10) = 10- 4
g(10) = 6
Plug the above value in the function f(x)
(f•g)(10) = f(g(10)) = (6)² + 1
(f•g)(10) = 36 + 1
(f•g)(10) = 37
Thus, the value of a composite function (f•g)(x) at x = 10 is 37 if the function f(x) = x² + 1 and g(x) =x - 4 option (A) 37 is correct.
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Why are epidemics and pandemics a relatively recent phenomenon in human history?
Answers
You are reducing a map of dimensions 2 ft by 3 ft to fit on a piece of paper 8 in. by 10 in. what are the dimensions of the largest possible map that can fit on the page?
Answers
Answer:
The dimensions of the largest possible map that can fit on the page are 10 inches by [tex]6\frac{2}{3}[/tex] inches.
Step-by-step explanation:
You are reducing a map of dimensions 2 ft by 3 ft
Lets change them to inches.
1 foot = 12 inches
So, 2 feet = [tex]2\times12=24[/tex] inches
3 feet = [tex]3\times12=36[/tex] inches
So, dimensions are : 24 inches x 36 inches
[tex]\frac{24}{36}=\frac{2}{3}[/tex]
Since 10 inch will be the longer side, we can find the shorter side by :
[tex]\frac{x}{10}=\frac{2}{3}[/tex]
[tex]3x=20[/tex]
[tex]x=\frac{20}{3}[/tex]
or [tex]x=6\frac{2}{3}[/tex] inches
So, the dimensions of the largest possible map that can fit on the page are 10 inches by [tex]6\frac{2}{3}[/tex] inches.
The dimension of the largest possible map which can fit on the paper can be used is [tex] 6\frac{2}{3} \: inches \: by \: 10 \: inches [/tex]
Map dimension = 2 feets by 3 feets Area of paper = 8in by 10inConverting the map dimension to inches :
1 feet = 12 inches2 feets = 2 × 12 = 24 inches
3 feets = 3 × 12 = 36 inches
Scale factor = 24 / 36 = 2/3
Longer side of the paper = 10 inches
Using the scale to obtain the length of the shorter side :
2/3 = x/10
Cross multiply
3x = 2 × 10
3x = 20
x = (20 ÷ 3)
x = 6 2/3 inches
The dimension of the largest possible map would be [tex] 6\frac{2}{3} \: inches \: by \: 10 \: inches [/tex]
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Use the clues to find the mystery number.
It is greater than 37,493.
It is less than 37,503.
It is an even number.
The value of the mystery number rounded to the nearest ten is less than the mystery number.
The value of the mystery number rounded to the nearest thousand is greater than the mystery number.
The mystery number is
Answers
El Generico public high school got a new flagpole. But they completely forgot to buy a cord and NO ONE knows how tall the flagpole is! To find out, they decided to use similar figures! As the sun was setting, Bob the janitor set up a 5-foot stick next to the flagpole and compared shadows. The 5-foot stick cast an 8-foot shadow. The shadow of the flagpole was 32-feet long.
Use rules of similar polygons to figure out how tall the flagpole is!
Answers
Length of Stick = 5 feet
Shadow of Stick = 8 feet
Shadow of flagpole = 32 feet
Length of flagpole = x = ?
Using rule of similar polygon we can write,
[tex] \frac{5}{8}= \frac{x}{32} \\ \\ \frac{5}{8}*32=x \\ \\ x=20 [/tex]
Therefore, the length of flagpole will be 20 feet.
A farmer has 300 ft of fencing with which to enclose a rectangular pen next to a barn. The barn itself will be used as one of the sides of the enclosed area.
What is the maximum area that can be enclosed by the fencing?
Enter your answer in the box.
ft²
Answers
y------> the length of the rectangle
x-----> the width of the rectangle
we know that
perimeter of the rectangle=2*[x+y]
Since the barn is used as one of the sides (let's say y) we can subtract y
we don't need fencing for this side
That makes the perimeter 2x + y
Since we have 300 feet of fencing
we set these equal:
2x + y = 300-------> y=(300-2x)------> equation 1
area of the rectangle=x*y
substitute the equation 1 in the area formula
Area=[(300-2x)]*x-----> Area=(-2x²)+300x
This is a quadratic equation
Since the leading coefficient is negative (-2) we know it opens downward
We are looking for the x-coordinate of the highest point called the vertex
using a graph tool
see the attached figure
the vertex is the point (75,11250)
that means for x=75 (width of the rectangle)
the area is 11250 ft²
the answer is
the maximum area that can be enclosed by the fencing is 11250 ft²
Answer:
The Answer is 11250 ft~
Step-by-step explanation:
I did the test and got it correct
Factor this expression completely and then place the factors in the proper location on the grid. Note:
Place factors alphabetically in the grid! mn - 4 m - 5 n + 20
Answers
[tex]mn-4m-5n+20[/tex]
[tex](mn-4m)-(5n+20)[/tex]
Notice that our the terms in our first parenthesis have a common factor [tex]m[/tex], and the terms in our second one have the common factor [tex]5[/tex]. Lets factor those out:
[tex]m(n-4)-5(n-4)[/tex]
Now we have a common factor [tex](n-4)[/tex] in both terms, so we can factor those out as well:
[tex](n-4)(m-5)[/tex]
We can conclude that the completely factored expression ordered alphabetically is [tex](m-5)(n-4)[/tex].
need answer plz smart people
Answers
13.
The radii are the lines that go from the exact center of the circle to anywhere on the circumference of the circle.
Here we can see that segments AB AD and AC go from the center to somewhere on the circumference, thus these segments are radii.
14.
Since the triangles are congruent, their corresponding angles are congruent. Given this, angle A is congruent to angle D and angle C is congruent to angle F.
A tip for future problems like this - you don't necessarily need to look at the diagram; the congruent statement gives you all the information you need about which angles correspond with each other and thus are congruent. Triangle ABC is congruent to triangle DEF: A corresponds to D, B corresponds to E, and C corresponds to F. This is useful because sometimes the triangles in the diagrams are not oriented the same way and its confusing to try to figure out which angles correspond.
15.
The diameter of a circle is the is a line that goes from a side through the center and to the other side of a circle.
The diameter is segment RS.
16.
Obtuse = greater than 90 degrees.
Acute = less than 90 degrees
Right = 90 degrees
Straight = 180 degrees (a straight line)
For this angle to be 90 degrees, it would have to be indicated by a little box in the corner; you must never assume an angle is 90 degrees, unless this information is explicitly stated in the question or shown in the diagram. This is not a right angle, nor is it a straight angle (it is not a straight line). That leaves obtuse and acute. Think: Is this greater than or less than 90 degrees? It is less than 90 degrees. The angle is acute.
.help thanks please :)
Answers
What’s the answer to this problem???
Answers
8y = -5x+16
divide everything by 8 to get just y
y = -5/8x+2
the slope = -5/8
You bought 8 gumdrops for 2¢ apiece. For the same amount of money, how many gumdrops can you buy at 8¢ apiece? gumdrops
Answers
You can buy 32 gumdrops at 8¢ apiece for the same amount of money as buying 8 gumdrops at 2¢ apiece.
Explanation:To find out how many gumdrops you can buy at 8¢ apiece for the same amount of money as buying 8 gumdrops at 2¢ apiece, you need to compare the prices and calculate the equivalent quantity. Since the prices are different, you can set up a proportion to solve the problem:
2¢ / 8 = 8¢ / x
By cross-multiplying, you get:
2 * x = 8 * 8
Now, solve for x to find the number of gumdrops you can buy at 8¢ apiece:
x = (8 * 8) / 2
x = 32
Therefore, you can buy 32 gumdrops at 8¢ apiece for the same amount of money as buying 8 gumdrops at 2¢ apiece.
To find out how many gumdrops you can buy at 8¢ apiece for the same amount of money you spent on 8 gumdrops at 2¢ apiece, divide the total amount of money by the new price.
Explanation:To find out how many gumdrops you can buy at 8¢ apiece for the same amount of money you spent on 8 gumdrops at 2¢ apiece, divide the total amount of money by the new price:
Total amount of money = 8 gumdrops x 2¢ apiece = 16¢
Number of gumdrops you can buy at 8¢ apiece = Total amount of money / 8¢
Number of gumdrops you can buy = 16¢ / 8¢ = 2 gumdrops
So, for the same amount of money, you can buy 2 gumdrops at 8¢ apiece.
Consuela and her three friends order 2 pizzas. Consuela cuts each pizza into 8 equal slices. She saves 2 slices of pizza for her older brother, Then she and her friends share the rest of the pizza, each eating the same number of slices. What fraction of the 2 pizzas is left over?
Answers
x--------------> the number of slices eating by Consuela and her three friends
we know that
[total slices]=8*2=16 slices
[slices of pizza for her older brother]=2
x=16-2=14 slides
Consuela and her friends share the rest of the pizza, each eating the same number of slices---------> 14/4= 3.5 slides of pizza each (this part is not necessary, but it is shown in a didactic way)
the question is
What fraction of the 2 pizzas is left over?
[slices of pizza for her older brother]/[total slices]=2/16=1/8
the answer is (1/8)
Final answer:
To find the fraction of the 2 pizzas left over, calculate the total slices consumed and subtract from the total. Consuela and her friends ate 14 slices out of 16, leaving 2/16 or 1/8 of the 2 pizzas left over.
Explanation:
Consuela and her friends ordered 2 pizzas, each cut into 8 slices. Consuela saved 2 slices, then shared the rest equally. Each person ate 2 slices.
To find out what fraction of the 2 pizzas is left over, calculate the total slices consumed and subtract from the total.
Each pizza had 8 slices, so 2 pizzas have 16 slices in total.Consuela saved 2 slices, so she and her friends ate 14 slices in total.Thus, the fraction of the 2 pizzas left over is 2/16 or 1/8.PLZ HELP ME!!A dilation has center (0, 0). Find the image of the point A (-4, 6) for the scale factor 4.5.
A' =
A- (‑18, 27)
B-(0.5, 10.5)
C-(10.5, 0.5)
D-(27, ‑18)
Answers
Selection A (-18, 27).
$394.63781 Round to the nearest dollar
Answers
Here is your answer:
The proper answer to your question is "$390.00
Here is how:
394.63781=$390
Your answer is $390!
If you need anymore help feel free to ask me!
Hope this helps!
.6 is higher than .4 so the dollar amount would go up one.
hope this helps
PLEASE help will mark brainliest algebra 2 . ... show your work
Answers
3x - 6= x + 4 .................distributive property
2x - 6 = 4 ......................addition property of equality
2x = 10 .........................addition property of equality
x = 5 ..............................division property of equality
Monica wants to measure the dimensions of her rectangular lawn. If the longer side of the lawn is (x + 3) feet and the diagonal length is (x + 4) feet, which function can be used to find the shorter side of her lawn?
a.] [tex]s(x)= \sqrt{2x+7} [/tex]
b.] [tex]s(x)= \sqrt{2 x^{2} +14x+25} [/tex]
c.] [tex]s(x)= \sqrt{x^{2} +7x+12} [/tex]
d.] [tex]s(x)= {x^{2} +7x+12} [/tex]
Answers
let
y--------------- > short side
applying the Pythagorean theorem
(x+4)²=y²+(x+3)²
y²=(x+4)²-(x+3)²-------> x²+8x+16-x²-6x-9=2x+7
y=√(2x+7)
which yields s^2=2x+7, hence a) is the correct answer.
Simplify the ratio 30 ml: 45 ml
Answers
In the ratio 30 ml :45 ml the GCF is 15
making the simplified ratio to be 2 ml:3 ml
Given: line segment AB is 10 inches long. Find the length of A'B' if AB is dilated to form A'B' with a scale factor of 1 2 . A) 1 2 inches B) 5 inches C) 10 inches D) 20 inches
Answers
[tex]|A'B'| = 5 \: units[/tex]
EXPLANATION
The formula for calculating the scale factor is
[tex]k = \frac{image \: length}{object \: length} [/tex]
Or
[tex]k = \frac{ |A'B'| }{ |AB|} [/tex]
Where k is the scale factor.
We were given
[tex] |A'B'|=10[/tex]
This is the image length.
We substitute the scale factor and the image length in to the formula to get,
[tex] \frac{1}{2} = \frac{ |A'B'| }{ 10} [/tex]
Multiply both sides by 10 to get,
[tex] \frac{1}{2}\times 10= |A'B'|[/tex]
[tex]|A'B'| = 5 \: units[/tex]
Answer:
Option (b) is correct.
The length of A'B' is 5 inches.
Step-by-step explanation:
Given : line segment AB is 10 inches long. AB is dilated to form A'B' with a scale factor of [tex]\frac{1}{2}[/tex]
we have to find the length of A'B'
Dilation of a figure is the increase or decrease in the length of the figure by a fixed scaling factor. if scaling factor is greater than 1 , then figure size increases, and if scaling factor is less than 1 , then figure size decreases.
Here, scaling factor is [tex]\frac{1}{2}[/tex] which less than 1 , so line segment A'B' decreases.
New image = scaling factor × original image
that is A'B' = [tex]\frac{1}{2}\times 10=5[/tex]
Thus, the length of A'B' is 5 inches.
Option (b) is correct.
PLEASE HELP
I WILL GIVE BRAINILEST
Daniel, a 37-year-old male, bought a $160,000, 10-year life insurance policy. What is Daniel’s annual premium? Use the table.
$611.20
$728.00
$1268.80
$1652.80
Answers
Male, 35-39, 10-year
The figure in this category shows $4.55, telling us that the annual premium per $1000 of coverage is $4.55.
Daniel bought $160,000 worth of life insurance, so that is 160 one-thousands.
So, we multiply the annual premium per $1000 ($4.55 as identified) by 160 to give us our answer:
4.55×160= $728
Therefore, the answer is $728
Answer:
the answer is b 728
Step-by-step explanation:
Energy resources that exist in limited amounts and, once used, cannot be replaced except over the course of millions of years are called_____energy resources
Answers
Answer: Non- renewable
The energy is derived from various sources on the basis of origin the energy can be derived from the renewable and non-renewable sources of energy. Renewable sources are those, which are abundantly available in nature and they can be replenished after a single use. For example, sunlight energy, wind energy, tidal energy, geothermal energy. But non- renewable sources are those which are available in limited amount hence, are expensive and cannot be replenished once they are used. For example fossil fuels such as coal, petroleum and natural gas. These are the resources which takes millions of years for their formation. Their genesis takes place inside the earth's geosphere under high heat and pressure conditions and by the action of the soil microbes acting upon the dead remains of plants and animals.
On the basis of the above description, energy resources that exist in limited amounts and, once used, cannot be replaced except over the course of millions of years are called non- renewable resources energy resources
Evaluate the expression Arcsec(sqrt 2). Do not use your calculator to answer this question. Do not express answer in decimals.
Answers
You're looking for the angle that has a secant of sqrt(2). And since the secant is simply the reciprocal of the cosine, let's take a look at that.
sqrt(2) = 1/x
x*sqrt(2) = 1
x = 1/sqrt(2)
Let's multiply both numerator and denominator by sqrt(2), so
x = sqrt(2)/2
And the value sqrt(2)/2 should be immediately obvious to you as a trig identity. Namely, that's the cosine of a 45 degree angle. Now for the issue of how to actually give you your answer. There's no need for decimals to express 45 degrees, so that caveat in the question doesn't make any sense unless you're measuring angles in radians. So let's convert 45 degrees to radians. A full circle has 360 degrees, or 2*pi radians. So:
45 * (2*pi)/360 = 90*pi/360 = pi/4
So your answer is pi/4 radians.
PLZZ HELP ME I WILL GIVE YOU THE BRAINLESS PERSON I GIVE YOU 12PTS
Please describe in detail using your vocabulary terms, directions, and the number of steps to explain how the pre-image became the image in this picture. Type your answer in a word document and upload it to this dropbox for me to grade. (5 pts)
Answers
A reflection across an axis is when the image is flipped over that axis that is mentioned. This is happening two times starting with the original. First it crosses the Y axis which will be flipping it to the left. The X values in the original ordered pair would all be the opposite of the original.
Then it is reflected across the X axis which would be flipping it down. This time the y values end of the ordered pair would all be the opposite from the previous figure.
The pre-image becomes the image in a picture through transformations such as translation, rotation, reflection, or dilation.
Explanation:The pre-image is the original figure before any transformations. The image is the new figure after a transformation has been applied to the pre-image. In this picture, the pre-image became the image through translation, rotation, reflection, or dilation.
Translation: The pre-image is moved in a specific direction without changing its shape or size.Rotation: The pre-image is turned around a fixed point by a certain angle.Reflection: The pre-image is flipped across a line to create the image.Dilation: The pre-image is either enlarged or reduced in size.By applying one or more of these transformations to the pre-image, it can become the image in the picture.
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Rowan raised $640 In a charity walk last year.this year he raised 15% more than he raised last year. How much money did Rowan raise this year?
Answers
1.15 × $640 = $736
PLEASE HURRY
Line segment CT contains the point C(−2, 5) and a midpoint at A(1, −3). What is the location of endpoint T? T(4, −11) T(3, −8) T(5, −1) T(−0.5, 1)
Answers
To find CT, you need to find the distance of CA then applies 2 times of the distance to the point C
Xca= Xa-Xc= 1- (-2)= 3
Yca= Ya- Yc= -3 -5= -8
Xt= Xc + 2* Xca= -2 + 2*3= 4
Yt= Yc + 2* Yca= 5 + 2*-8= -11
T(Xt, Yt)= T(4, -11)
The coordinate for point T would be (4, -11)