PLEASE HELP 98 POINTS!!!!!!
What is the reason for each step in the solution of the equation?

19=5x−1

Drag and drop the reasons into the boxes to correctly complete the table.



19=5x−1

20=5x

4=x

Combine Like Terms, Division Property of Equality, Addition Property of Equality, Commutative Property, Given

Answer:

D.) Neither A or B

Step-by-step explanation:

A.) Substituting X=2 and y=4 results to 9=10 which is a false statement

B.) Substituting X=3 and y=6 results to 16=18 Which is a false statement

C.) Look at A and B they lead to a false statement so It can't be both

The answer of the ordered pair is a solution of the equation 7x−5=4y−6 would be option D. neither A or B.

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Given equation;

7x - 5 = 4y -6 ...…...... (1)

Substitute x = 2 and y = 4 in equation (1)

7(2) -5 = 4(4) -6

9 ≠ 10

a) (2,4) is not satisfied

Now, Substitute x = 3 and y= 6 in equation (1)

7(3) -5 = 4(6) -6

 16 ≠ 18

b) Thus, (3,6) is not satisfied

c)  both A and B is also not satisfied

Hence, the answer would be option D. neither A or B.

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6(3x - 5) = 4(4x + 2)    Given

(6)(3x) + (6)(-5) = (4)(4x) + (4)(2)    Distributive property

18x - 30 = 16x + 8

18x - 16x - 30 = 16x - 16x + 8     Subtraction property of equality

2x - 30 = 8

2x - 30 + 30 = 8 + 30     Addition property of equality

2x = 38

2x : 2 = 38 : 2     Division property of equality

x = 19

Answer:

6

Step-by-step explanation:

The area of a polygon created with a scale factor of xxx is x^2x  

2

x, start superscript, 2, end superscript times larger than the original polygon:

\text{scale factor}^2=\text{how many times larger area of scale copy is}scale factor  

2

=how many times larger area of scale copy iss, c, a, l, e, space, f, a, c, t, o, r, start superscript, 2, end superscript, equals, h, o, w, space, m, a, n, y, space, t, i, m, e, s, space, l, a, r, g, e, r, space, a, r, e, a, space, o, f, space, s, c, a, l, e, space, c, o, p, y, space, i, s

The area of Rectangle RRR is 363636 times greater than the area of Rectangle QQQ. Let's substitute 363636 into the equation to find the scale factor.

?^2=36?  

2

=36question mark, start superscript, 2, end superscript, equals, 36

The scale factor is 666.

Hint #33 / 3

Thea used a scale factor of 666 to go from Rectangle QQQ to Rectangle RRR.

Answer:

6

Step-by-step explanation:

The area of a polygon created with a scale factor of xxx is x^2x  

2

x, start superscript, 2, end superscript times larger than the original polygon:

\text{scale factor}^2=\text{how many times larger area of scale copy is}scale factor  

2

The area of Rectangle RRR is 363636 times greater than the area of Rectangle QQQ. Let's substitute 363636 into the equation to find the scale factor.

?^2=36?  

2

=36question mark, start superscript, 2, end superscript, equals, 36

The scale factor is 666.

Hint #33 / 3

Thea used a scale factor of 6 to go from Rectangle Q to Rectangle R.

The answer is 293 meters because you multiply the 14650 books by how thick they are which is 0.02, and that should reveal your answer. Hope this helps!

A slope is also known as the gradient of a line. The slope of the line is positive and is equal to 0.2.

A slope also known as the gradient of a line is a number that helps to know both the direction and the steepness of the line.

Since the line is passing through the origin and (5,1). The slope of the line is,

m = (1-0)/(5-0) = 1/5 = 0.2

Hence, the slope of the line is positive and is equal to 0.2.

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Multiplying numerators and denominators to get the LCD in all fraction denominators

= 38−21×24×2

Then rewriting the equation with the equivalent fractions

= 38−428

With like denominators we can operate on just the numerators

= 3−4 2/8

=−39/ 8

Simplifying the answer

= − 39/8

= − 39/8

= − 4 7/8

I believe 0.75/ 8=0.09375 so 0.09375 is the answer i hope i helped

The percent increase to earned money will be 9.375%.

What is Percentage?

A relative value indicating hundredth part of any quantity is called percentage.

Given that;

An employee was hired at a wage of $8 per hour.

After a raise, the employee earned $8.75 per hour.

Now, The increase percent will be calculate as;

Increase percent in money = Increase money/Actual money x 100

                                          = (8.75 - 8.00) / 8 x 100

                                          = (0.75/8) x 100

                                          = 75/8

                                          = 9.375

Thus, The percent increase to earned money will be 9.375%.

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be smart be funny be kind smell good watch tv do homework

Solution :

Given a soda can has a diameter of 6 cm.

As we know,  the circumference of circle with radius r is , [tex]C=2\pi r[/tex].

And diameter of  the circle [tex]D = 2r[/tex]

So, the circumference of the circle with diameter D is ,  [tex]C=\pi D[/tex]

Put D= 6

[tex]\Rightarrow C=6 \pi\\\\Using\: \pi=3.14\\\Rightarrow C=6\times3.14\\\\\Rightarrow C=18.84[/tex]

Hence, the circumference of the can is 18.84 cm. (option C)

Here we have a problem with tax rates and percentages, we will find that the total price will be $48.66.

So we know that the price of the skirt is $45.99, this is our 100%.

So, when we know that a tax of 5.8% is applied, is over that 100%, meaning that the total price will be 105.8% of the original price.

Then we can write the equations.

105.8% = x

100% = $45.99

Taking the quotient of these two equations and solving for x we get:

(105.8%/100%)*$45.99 = x = $48.66

So the total price of the skirt is $48.66.

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Answer:

1. QS bisects ∠ PQR of Δ PQR.⇒[Given]

2. ∠PQS = 90° [Given]

3.∠PQS =∠RQS ⇒[QS bisects ∠ PQR]

4. .∠PQS +∠RQS =90°  [∴∠PQS = 90°⇒given]

    2∠PQS =90°⇒  [∠PQS =∠RQS ]

   ∠PQS=45°

So,∠PQS =∠RQS =45°

2.∠ 2= ∠ 4 [Given]

⇒∠ 2≅ ∠ 4[ congruency postulate]

∠2  and ∠ 3 are supplementary.⇒°[given]

⇒∠2 + ∠ 3=180° [ By the definition of supplementary].........(1)

∠1 and ∠4 are supplementary.⇒[∠1 and ∠4 form linear pair.]

⇒∠1 +∠4=180°[By the definition of supplementary]..............(2)

⇒∠2 + ∠ 3 =∠1 +∠4 [both of them are equal to 180, so they are equal to each other.⇒ Two things equal to same thing are equal to each other[Euclid postulate]]

⇒∠4 +∠3=∠1+∠4 [∠2=∠4⇒(given)]

⇒∠3=∠1   [law of cancellation]

⇒∠3≅∠1  [ Congruency property]

$504 + $580= $1084 is how much the bus company got in all.

Answer:

$1,084

Step-by-step explanation:

Multiply 36 by $14 and you get 504.

Then multiply 20 by $29 an you will get 580.

In order to figure out how much money they collected in total, you should add your two answers together, which will then be 1,084. The bus company collected $1,084

104 and 105 are consecutive numbers that add up to 209. Maybe this answers your question? Let me know otherwise.

I would say the answer would be B. or C.

not sure which but i hope i helped narrow it down..

Answer:

Its B

Step-by-step explanation:

Jonathan is 5 years older than his brother Chase.

Chase's Age = c

Jonathan's Age = c+5

Three times Jonathan's age would be 3(c+5).

The sum of Chase's age, c, and three times Jonathan's age, 3(c+5), is 55.

c+3(c+5)=55

The answer is B.

(7(5)+4)/(1/2)=39/.5=78

can you give more detail

a+b = 65

b - 2a = 5

Solve one variable in terms of another:

b = 5 + 2a

Substitute in this variable:

a + 5 + 2a = 65

3a = 70

a = 23.3

Use this to find the other variable:

23.3 + b = 65

b = 41.7

Check the answer:

23.3 + 41.7 = 65

65 = 65

ANSWERS:

a = 23.3

b = 41.7

Given : Invested amount = $5000.

Rate of interet = r% compunded monthly.

Number of years = 4 years.

Total interest received = $1866.

Therefore, total amount after 4 years = 5000+1866 = $6866.

We know, formula for compound interest :

[tex]A=P(1+\frac{r}{n})^{t\times n}[/tex], where P is the invested amount, n is the number of monthly installments in an year.

Number of months in an year are 12.

Plugging n=12, P=5000, t=4 in the formula now, we get

[tex]6866=5000{(1+\frac{r}{12})^{12\times 4}[/tex]

[tex]6866=5000{(1+\frac{r}{12})^{48}[/tex]

Dividing both sides by 5000, we get

[tex]\frac{6866}{5000} =\frac{5000}{5000} {(1+\frac{r}{12})^{48}[/tex]

[tex]\frac{6866}{5000} = {(1+\frac{r}{12})^{48}[/tex]

[tex]1.3732= {(1+\frac{r}{12})^{48}[/tex]

Taking 48th root on both sides, we get

[tex]\sqrt[48]{1.3732} = \sqrt[48]{(1+\frac{r}{12})^{48}}[/tex]

[tex]\sqrt[48]{1.3732}=\left(1+\frac{r}{12}\right)[/tex]

[tex]1.00662903758=1+\frac{r}{12}[/tex]

Subtracting 1 from both sides, we get

0.00662903758 = [tex]\frac{r}{12}[/tex]

Multiplying by 12 on both sides, we get

r=0.07954845101

r≈0.0795

Or 7.95%.

Now, we need to find the interest after four years if the rate of interest is 3.6% compounded quarterly.

There are 4 quarters in an year.

So, n=4 and r=3.6%= 0.036.

Plugging values in compound interest formula now, we get

[tex]A=5000{(1+\frac{0.036}{4})^{4\times 4}[/tex]

[tex]\mathrm{Divide\:the\:numbers:}\:\frac{0.036}{4}=0.009[/tex]

[tex]A=5000\times \:1.009^{16}[/tex]

[tex]A=5000\times \:1.15414\dots[/tex]

[tex]=5770.70222\dots[/tex]

A≈5770.70

Subtracting 5770.70 -5000.00 = 770.70.

(A)

We are given

Mr tan invested 5000 Swiss francs(CHf) bank

so,

[tex]P=5000[/tex]

nominal annual interest rate of r% compounded monthly

so, n=12

t=4

total interest he received was 1866 CHF

I=1866

we can use formula

[tex]I=P(1+\frac{r}{n} )^{nt}-P[/tex]

now, we can plug values

[tex]1866=5000(1+\frac{r}{12} )^{12*4}-5000[/tex]

now, we can solve for r

[tex]r=0.0795[/tex]

so, interest rate is 7.95%..........Answer

(B)

we are given

P=5000

r=0.036

n=4

t=4

so, we can use interest formula

[tex]I=P(1+\frac{r}{n} )^{nt}-P[/tex]

now, we can plug values

[tex]I=5000(1+\frac{0.036}{4} )^{4*4}-5000[/tex]

now, we can simplify it

and we get

[tex]I=770.702[/tex]

The total interest is 771 CHF...........Answer

By combining the like terms; the simplified answer in the correct way is 16x^2+6xy+6y^2

How to get answer:

- Find how many terms are in the algebraic equation. Counting I got 6 terms.

There are 2 xy's and 2 x's and 2y's

- Next combine all like terms

[tex]8x^{2} + 8x^{2} = 16x^{2}[/tex]

7xy+-xy=6xy

[tex]5y^{2} + y^{2}[/tex]=[tex]6y^{2}[/tex]

- Next Simplify

[tex]16x^{2}+6xy+6y^{2}[/tex]

Answer:

3 inches/hour

Step-by-step explanation:

During one winter snow storm in Denver Colorado Jesse noted that 16 inches of snow fell in [tex]5\frac{1}{3}[/tex] hours = [tex]\frac{16}{3}[/tex] hours

the snow fell in [tex]\frac{16}{3}[/tex] hours = 16 inches

snow fell in 1 hour = [tex]\frac{16}{\frac{16}{3}}[/tex]

                              = [tex]\frac{16\times 3}{16}[/tex]

                              = [tex]\frac{48}{16}[/tex]

                              = 3 inches

The rate of snowfall would be 3 inches/hour.

For this case we have:

Part A:

Point 1: [tex](x1, y1) = (6,10)\\[/tex]

Point 2:[tex](x2, y2) = (4, -2)\\[/tex]

We know that the slope m is given by:

[tex]m = \frac{(y2-y1)}{(x2-x1)}\\\\m = \frac{(- 2-10)}{(4-6)}\\\\m = \frac{(- 12)}{(- 2)}\\[/tex]

[tex]m = 6\\[/tex]

The slope is [tex]m = 6\\[/tex]

Part b:

The equation of the line in point-slope form is given by:

[tex](y-y1) = m (x-x1)\\[/tex]

Substituting the point 1 [tex](x1, y1) = (6,10)[/tex]we have:

[tex](y-10) = 6 (x-6)\\[/tex]

Thus, the point-slope equation is: [tex](y-10) = 6 (x-6)\\[/tex]

Part c:

The equation of the line in slope-intersection form is given by:

[tex]y = mx + b\\[/tex]

Rewriting the equation of part b we have:

[tex]y = 6 (x-6) +10\\\\y = 6x-36 + 10\\\\y = 6x-26\\[/tex]

Thus, the equation of the line in slope-intersection form is

[tex]y = 6x-26\\[/tex]

Answer:

[tex]m = 6\\\\(y-10) = 6 (x-6)\\\\y = 6x-26[/tex]

i think that it is 1/6

Answer:

But why is it 1/6? Why don't you divide?

Step-by-step explanation:

The domain is how far the graph stretches horizontally (on the x-axis).

Domain:  ( -∞ , ∞ )  or  -∞ < x < ∞

The range is how long the graph stretched vertically (on the y-axis).

Range:  ( -∞ , 2 ]  or  -∞ < y ≤ 2

The zeros are where the graph intersects with the x-axis. In other words, the x-values when y=0.

Zeros:  x = -1  and  x = 3