Answers
your answer is A
hope this helps :)
A = [tex]\frac{1}{2}[/tex]bh
[tex]\frac{1}{2}[/tex] × (bh) = A
[tex]\frac{bh}{2}[/tex] = A
bh = A × 2
bh = 2A
b = [tex]\frac{2A}{h}[/tex]
The answer is a: b= [tex]\frac{2A}{h}[/tex]
Related Questions
y=–3x + 6y=9 What is the solution to the system of equations? (–21, 9) (9, –21) (–1, 9) (9, –1)
Answers
ANSWER
The solution is [tex](-1,9)[/tex]
EXPLANATION
We want to solve the simultaneous equations
[tex]y=-3x+6---(1)[/tex]
and
[tex]y=9--(2)[/tex].
We substitute equation (2) in to equation (1), to obtain
[tex]9=-3x+6[/tex]
This has now become a linear equation in a single variable [tex]x[/tex].
We solve for x by grouping like terms.
[tex]9-6=-3x[/tex]
[tex]3=-3x[/tex]
We divide through by negative 3 to get;
[tex]-1=x[/tex].
Hence, the solution is [tex](-1,9)[/tex]
Contestants in a dance-a-thon rest for the same amount of time evey hoir. A couple rests for 25 minutew in 5 hours. How long did they rest in 8 hours?
Answers
If each couple rests for [tex] k [/tex] minutes every hour, the time spent resting, [tex] r [/tex], after [tex] h [/tex] hours is given by
[tex] r = kh [/tex]
We know that a couple spent 25 minutes resting in 5 hour. So, the rate is
[tex] 25 = 5k \iff k = \dfrac{25}{5}=5 [/tex]
So, every couple rests 5 minutes per hour.
This means that, after 8 hours, the couples rest
[tex] r = 5\cdot 8 = 40 [/tex]
minutes.
Verify the equation below with each of the values listed for x to find a solution.
5 = 3x + 4
Answers
Answer:
123123131231231312312
Step-by-step exp13123123123lanation:
jkbbhivbyuiiyu1312312
Carlos is using a number line to add another integer to –4. He begins by showing –4 on the number line, as shown below. Carlos adds the other integer on the number line and says that the sum is negative.Which is true of the number Carlos added to –4?
Answers
A scientist use 2 gallons of liquid for every 3 hours he works he uses blank of a gallon each hour he works
Answers
? gallons = 1 hour
3 / 2 = 0.66666667 gallons
Round the answer = 0.6 gallons
!!!!HELP ASAP WILL GIVE BRAINLIEST!!!!
What is the speed of a bobsled whose distance-time graph indicates that it traveled 124m in 29s?
Answers
Put 124m over 29s. Distance/Time = Speed. The answer is 4.27 mps.
Using the formula:
The speed would be the result of = distance divided by time
distance= 124m
time. =29 s
= 124 \div 29
= your speed
total speed = 4.27
Marta drew a scale drawing of her backyard. She used the scale 1/2 inch =4.5 feetif the actual length of her backyard is 54,what is her scale drawing in inches
Answers
1/2 inch…………4.5 feet
x inches……….54 feet
x=(54•1/2)/4.5
x=27/4.5
x=6 inches
A coral reef grows 0.12 m every week how much does it grow in 5 weeks
Answers
Final answer:
To calculate the growth of a coral reef over 5 weeks at a rate of 0.12 meters per week, you multiply the weekly growth by 5, resulting in a total growth of 0.6 meters.
Explanation:
If a coral reef grows 0.12 meters every week, we can calculate its growth over 5 weeks by multiplying the weekly growth rate by the number of weeks.
Perform the calculation: 0.12 m/week × 5 weeks = 0.6 meters.
Therefore, a coral reef grows 0.6 meters in 5 weeks.
A plane can fly 11 miles per minute the plane will fly 6 trips and eat shrimp is 500 miles how many hours will the plane fly
Answers
If i understand the question correctly the plane will fly 6 trips of 500 miles each trip.
Number of minutes it takes the plane to fly 500 miles
= 500 / 11
= 45.45 minutes
For 6 trips this = 45.45 * 6 = 272.73 minutes
= 4.55 hours to nearest hundredth.
Working alone it would take laura 45 minutes to mow the lawn kelly would take 1 hour 15 minutes if they work together the girls believe it will take 1 hour to mow the lawn which is the best described of the solution
Answers
Answer:
31.5 minutes only
Inverse proportion
Step-by-step explanation:
It takes 45 minutes for Laura to mow the lawn.
For Kelly it takes 1 hour 45 minutes or 60+45 = 105 minutes
In one minute Laura can mow 1/45 of the lawn.
Similarly in one minute Kelly can mow 1/105 of the lawn
Together in one minute they can mow the sum
= [tex]\frac{1}{45} +\frac{1}{105}[/tex]
Take lcd for 45 and 105 and make them equivalent fractions with same denominator
LCD of 45 and 105 is 15(3) (7) = 315
[tex]\frac{1}{45} +\frac{1}{105}=\frac{7+3}{315}=\frac{10}{315}\\=\frac{2}{63}[/tex]
In other words it would take 63/2 = 31.5 minutes only to lawn if they work together.
The situation here is the problem on inverse proportion. If no of people increase, work time would decrease.
Use the vertex (h, k) and a point on the graph (x, y) to find the general form of the equation of the quadratic function.
(h, k) = (−6, −1), (x, y) = (−9, 8)
Answers
To find the general form of the equation of the quadratic function given a vertex and a point, we can proceed as follows:
The vertex form of the equation for a quadratic function can be expressed as:
\[ f(x) = a(x - h)^2 + k \]
where
- \( a \) is a coefficient that affects the width and direction of the parabola,
- \( (h, k) \) is the vertex of the parabola.
We've been given the vertex \( (h, k) = (-6, -1) \) and a point on the graph \( (x, y) = (-9, 8) \).
Let's use the vertex form and plug in the values of the vertex and the given point to solve for \( a \).
\[ 8 = a(-9 + 6)^2 - 1 \]
\[ 8 + 1 = a(-3)^2 \]
\[ 9 = a(9) \]
\[ a = 9 / 9 \]
\[ a = 1 \]
Now we know that \( a \) equals 1, and our vertex form equation becomes:
\[ f(x) = 1(x + 6)^2 - 1 \]
To write the equation in general form \( f(x) = ax^2 + bx + c \), we need to expand the equation:
\[ f(x) = 1(x + 6)^2 - 1 \]
\[ f(x) = (x^2 + 12x + 36) - 1 \] (Expand the square)
\[ f(x) = x^2 + 12x + 36 - 1 \]
Finally, combine the constants:
\[ f(x) = x^2 + 12x + 35 \]
So the general form of the equation of the quadratic function given the vertex \( (-6, -1) \) and the point \( (-9, 8) \) is:
\[ y = x^2 + 12x + 35 \]
Here, \( a = 1 \), \( b = 12 \), and \( c = 35 \).
Two cars are driving towad each other along a straight road. Their separation distance is l - (r1 + r2)t, where l is their original separation distance and r1 and r2 are their speeds. Will the cars meet? When? What if they are going in the same direction and not driving toward one another? Will they meet then?
Answers
If they are going in the same direction, assuming they are both driving at a constant speed, they will never meet. One car will be constantly on the other’s tail, but since one car is constantly moving away from the other, they will never meet unless the first car (moving away from the other) stops or slows down enough so the other one catches up, or the car “chasing” the other speeds up enough to crash into the other.
find the product of 3 1/5 times 5/8 in simplest form
Answers
I added 3+1.5=4.5 then multiply 4.5×5.8=11.7.
I hope this helps.
Answer:
2
Step-by-step explanation:
What is the measure of
Answers
That would be (40 + 110) / 2
= 150 / 2
= 75 degrees answer
Helppppppppppppppppp
Answers
The definitions of the labels are:
acute - less than 90°right - exactly 90°obtuse - more than 90°straight - exactly 180°Since RQU is the sum of RQS, SQT and TQU, it measures 19+71+18 degrees, i.e. 108 degrees, and thus it's obtuse
Similarly, SQU is the sum of SQT and TQU, so it measures 71+18 = 89 degrees, so it's acute.
Finally, RQT is the sum of RQS and SQT, so it measures 19+71=90 degrees, and it's a right angle.
obtuse, acute and right
∠RQU = 19° + 71° +18° = 108° ⇒ obtuse angle
∠SQU = 71° + 18° = 89° ⇒ acute
∠RQT = 19° + 71° = 90° ⇒ right
Taylor has jar of 44 nickels and quarters. She has $4. 80. How many nickels does she have?
Answers
she has 40 nickels because: 80-40 = 40. this is equal to 40 nickels
Which function would you use to solve for the length b?
Answers
Let's assume
reference angle =B
so,
opposite =b
adjacent=a
now, we can use tan
[tex]tan(B)=\frac{b}{a}[/tex]
now, we can solve for b
Multiply both sides by a
[tex]a*tan(B)=a*\frac{b}{a}[/tex]
[tex]b=a*tan(B)[/tex]
so, option-A...............Answer
Alisha and brianna are working on more magic number puzzles. Again, the puzzles have the same steps,but alisha and brianna come up with different results. The girlswork for each puzzle is shown side-by-side. For each set of puzzles, tell whose result is correct and explain why that result is correct.
Answers
This question is about evaluating the solutions of two students, Alisha and Brianna, for a number puzzle involving sets and probabilities. Without specific puzzle instructions, it's hard to determine whose solution is correct. The correctness would depend on the puzzle's directions and the application of mathematical principles.
Explanation:The question is a mathematical one, involving the solving of number puzzles by two students, Alisha and Brianna. The requirements are to evaluate their solutions for correctness based on given parameters or steps. However, without the specific steps or guidelines of the puzzles presented, it's difficult to provide a definitive assessment or explanation of whose solution would be correct.
From the provided resources, we can infer that we're dealing with a problem-solving scenario involving sets, probabilities, problem analysis, and solution refinement. An example scenario might be: Alisha and Brianna are solving a magic number puzzle where they need to calculate the probability of specific outcomes from a set of numbers. Alisha identifies sets S and A and calculates P(A) as the number of outcomes in A divided by outcomes in S, while Brianna might approach the puzzle differently. The correctness of their results will depend on the puzzle's instructions and the maths principles applied.
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which equation is the quadratic regression equation for the data shown in the table?
x 3 6 5 10 5 4 7 2 9
y 7 2 4 5 3 5 1 12 2
y=3x∧2 + 6x+5
y=0.392x - 5.583x
y=0.392x∧2 - 5.583x + 21.167
y= -0.006x∧2 - 0.431x + 0.407
Answers
Answer-
Quadratic regression equation [tex]y=0.392x^2 - 5.583x + 21.167}[/tex]
Solution-
Quadratic Regression Equation,
[tex]ax^2+bx+c[/tex]
[tex]a=\frac{(\sum x^2y\sum xx)-(\sum xy\sum xx^2)}{(\sum xx\sum x^2x^2)-({\sum xx^2)}^2}[/tex]
[tex]b=\frac{(\sum xy\sum x^2x^2)-(\sum x^2y\sum xx^2)}{(\sum xx\sum x^2x^2)-({\sum xx^2)}^2}[/tex]
[tex]c=\frac{\sum y}{n}-b\frac{\sum x}{n}-a\frac{\sum x^2}{n}[/tex]
Where,
[tex]\sum xx=\sum x^2-\frac{(\sum x)^2}{n}[/tex]
[tex]\sum xy=\sum xy-\frac{\sum x\sum y}{n}[/tex]
[tex]\sum xx^2=\sum x^3-\frac{\sum x\sum x^2}{n}[/tex]
[tex]\sum x^2y=\sum x^2y-\frac{\sum x^2\sum y}{n}[/tex]
[tex]\sum x^2x^2=\sum x^4-\frac{(\sum x^2)^2}{n}[/tex]
Calculating the values from the table,
a= 0.392
b= -5.583
c= 21.167
∴ Quadratic regression equation,
[tex]y=0.392x^2 - 5.583x + 21.167[/tex]
The baseball stadium holds 23,564 people. 3/4 of the seats were sold. How many people were in the stadium
Answers
capacity of the stadium=23564
no.of seats occupied=3/4 of 23564
no.of people in the stadium=23564*3/4
=17673
Answer:
17673
Step-by-step explanation:
If a kennel has 50 dogs and some of them are puppies and some of them are adult dogs . The ratio of puppies to adult dogs in a kennel are 2:3 . How many puppies are there?
Answers
The ratio is 2:3 puppies to adult dogs, which means for every 2 puppies, there is 3 adult dogs.
Add the ratio together: 2+3 = 5
Divide total dogs by that total: 50 dogs / 5 = 10
Now multiply each number of the ratio by that to find the total number of each:
2 puppies x 10 = 20 total puppies.
3 adults x 10 = 30 total adult dogs.
What does the degree of a polynomial expression tell you about its related polynomial function? Explain your thinking. Give an example of a polynomial expression of degree three. Provide information regarding the graph and zeros of the related polynomial function.
Answers
The polynomial degree relates to the number of "zeros" or points of intersection of the polynomial function (curve in the (x,y) plane) with the x axis (that is, points where y=0). These zeros can sometimes be coinciding but that phenomenon aside, you will see N such intercepts with the x axis for a polynomial expression of N-th degree.
Example of a polynomial of 3rd degree is: x^3 + 2 x^2 - x - 2
You can factor it to (x-1)(x+1)(x+2) to see that the zeros are +1, -1, and -2. The plot is attached as an image - note the intercepts. Lmk if you have questions.
A degree in a polynomial function is the greatest exponent of that equation, which determines the most number of solutions that a function could have and the most number of times a function will cross the x-axis when graphed or we can also say that degree of polynomial determines the number of zeroes of that polynomial function.
Let us take an example of polynomial expression of degree three,
For e.g. [tex]x^{3}+2x^{2} -x-2=0[/tex] ...(1)
By hit and trial method we have to solve it .
Firstly, we put [tex]x = +1[/tex] in above equation ,
We get , [tex]1+2-1-2=0[/tex]
Thus, x = +1 is first zero of the equation.
Now ,we put [tex]x = -1[/tex] in equation...(1) ,
We get,
[tex]-1+2-(-1)-2=0[/tex]
i.e. x = -1 is also second zero of the equation.
Then, we put [tex]x = -2[/tex] in equation...(1) ,
We get ,
[tex]-8+8-(-2)-2=0[/tex]
Thus, the third zero of the equation is x = -2.
Therefore there are three zeroes of the polynomial function are x = -1, +1 and -2.
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There are about 25.4 millimeters in one inch. Write this number in scientific notation.
Answers
Answer:
I inch = 25.4mm
Step-by-step explanation:
i inch =25.4mm
= 2.54×10^1
25.4 millimeters in scientific notation can be written as [tex]2.54 \times 10^1 \text {milimeters}[/tex]
The value "25.4 millimeters" must be expressed as a decimal number between 1 and 10, multiplied by a power of 10, in order to be written in scientific notation.
We may write the given number, 25, as follows:
[tex]2.54 \times 10^1[/tex]
In scientific notation, the decimal point is placed after the first non-zero digit, and in this case it is 2. The exponent 1 indicates that we move the decimal point one place to the right to get the original value.
Therefore, 25.4 millimeters in scientific notation is [tex]2.54 \times 10^1\text{millimeters }[/tex]
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Suppose each square on the grids below is 1 cm by 1 cm. Estimate the area of the figure.
about 30 cm2
about 40 cm2
about 20 cm2
about 10 cm2
Answers
Answer:
About [tex]20cm^2[/tex]
Step-by-step explanation:
In the given image each of the square has side 1 cm by 1 cm.
If we could count the whole squares in the image we can see that there are about 14 whole squares, then there are 6 squares which are nearly half occupied so that makes about 3 whole squares. And then there are almost 12 squares whose quarter area is enclosed by the lines so that makes about 3 whole squares.
So the total area of the given figure is about [tex]20 cm^2[/tex].
Answer:
Option "C" would be the correct answer
The question is in the attached below , thank you for helping me .
Answers
JKLM is a parallelogram. - Given
JM is a parallel to KL. - Definition of bisect
Given - LN bisects <KLP.
<2 ~= <3 - Definition of bisect
<1 ~= <3 - Transitive Property of Congruence
An ice-hockey puck is slid along ice in a straight line. The puck travels at a steady speed of 20 ms^-1 and experiences no frictional force. How far does the puck travel in 2.5 s?
a. 5 m
b. 8 m
c. 25 m
d. 50 m
Answers
Answer:
d. 50 m
Step-by-step explanation:
1. You have the following information given in the problem above:
- The speed of the puck is 20 [tex]\frac{m}{s}[/tex] and experiences no frictional force.
- The time is 2.5 seconds.
2. Then, to calculate the distance, you must apply the following formula:
[tex]d=Vt[/tex]
Where [tex]d[/tex] is the distance, [tex]V[/tex] is the speed and [tex]t[/tex] is the time.
3. Now, you must substitute values into the formula, as below:
[tex]d=(20\frac{m}{s})(2.5s)[/tex]
4. Therefore, the result is:
[tex]d=50m[/tex]
Using the physics equation of distance = speed x time, it can be calculated that an ice-hockey puck moving at a constant speed of 20 ms^-1 for 2.5s would cover a distance of 50 m.
Explanation:In Physics, the equation for distance can be expressed as distance = speed x time. In this case, the speed of the ice-hockey puck is given as 20 ms^-1 and the time is 2.5 s. By plugging these values into the formula, we get:
Distance = 20 ms^-1 x 2.5 s = 50 m. As a result, the ice-hockey puck will travel a distance of 50 meters in 2.5 seconds if it continues at a steady speed of 20 ms^-1 without any interference from frictional forces. Therefore the correct answer to this question is option d) 50 m.
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A line segment has endpoints at (4, –6) and (0, 2). What is the slope of the given line segment? What is the midpoint of the given line segment? What is the slope of the perpendicular bisector of the given line segment? What is the equation, in slope-intercept form, of the perpendicular bisector?
Answers
slope = - 2, midpoint = (2, - 2 )
the slope m is calculated using the ' gradient formula '
m = ( y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (4, - 6 ) and (x₂, y₂ ) = (0, 2 )
m = [tex]\frac{2+6}{0-4}[/tex] = [tex]\frac{8}{-4}[/tex] = - 2
calculate midpoint using midpoint formula
{[tex]\frac{1}{2}[/tex] (4 + 0 ), [tex]\frac{1}{2}[/tex] (- 6 + 2 )] = (2, - 2 )
gradient of perpendicular bisector = - [tex]\frac{1}{-2}[/tex] = [tex]\frac{1}{2}[/tex]
equation in slope-intercept form is
y = mx + c ( m is slope and c the y-intercept )
partial equation is y = [tex]\frac{1}{2}[/tex] x + c
to find c substitute ( 2, - 2) into the partial equation
- 2 = 1 + c ⇒ c = - 3
y = [tex]\frac{1}{2}[/tex] x - 3 in slope-intercept form
Answer:
-2
(2,-2)
1/2
y=(1/2)x-3
Step-by-step explanation:
It’s correct on edge.
Given a line segment with end points A (0,0) and B (6,8), find point C (x,y) that the triangle vertices A, B and C has an area of 25 square units?
Answers
Answer:
C(6.25 , 0)
Step-by-step explanation:
Draw the diagram
A is at (0,0)
B is at (6,8)
Draw a line from A to B.
Put a large dot where (0,6) is. Call this D
Draw BD
Draw another line from (0,0) to just beyond (6,0) Call this C. Draw in BC
What You Have Drawn
The height of the triangle is BD and it is 8. That comes from B which is (6,8)
Solve
Formula
Area = 1/2 * B * H
Area = 25
H = 8
Area = 1/2 B * H
25 = 1/2 * B * 8 Switch sides
1/2 * B * 8 = 25 Combine factors on the left.
4 B = 25 Divide both sides by 4
4B/4 = 25/4
B = 6.25
What that means is that AC is 6.25 units long and is on the x axis
C is C(6.25,0)
A train leaves Roseville heading east at 6:00 am at 40 miles per hour. Another eastbound train leaves on a parallel track at 7:00 am at 50 miles per hour. What times will it be when the two trains are at the same distance away from Roseville?
Answers
Answer:
At 11:00 am the both trains will be at same distance away from Roseville
Step-by-step explanation:
The first train was 40 miles away from Roseville at 7:00 am
After some time t the both trains will be at the same distance away from Roseville.
We will make equation for that situation
d- distance v1= 40mph and v2= 50mph - velocity
d = v1*t + 40 = v2*t => v2*t - v1*t = 40 => t (v2-v1) = 40 -> t = 40/ (v2-v1)
t = 40/(50-40) = 40/10= 4h t = 4h
7:00 am * 4h = 11:00 am
Good luck!!!
Solve for x. −3(x−5)−2x=−10 Enter your answer in the box. x =
Answers
x= 5 that is what x =
First you had to expanded form.
[tex]-3(x-5)-2x=-5x+15[/tex]
[tex]=-5x+15=-10[/tex]
Then you subtract by fifteen from both sides of equation form.
[tex]-5x+15-15=-10-15[/tex]
Simplify.
[tex]-5x=-25[/tex]
Next, divide by negative five from both sides of equation form.
[tex]\frac{-5x}{-5}= \frac{-25}{-5}[/tex]
And finally simplify by equation.
[tex]x=5[/tex]
Final answer: [tex]\boxed{x=5}[/tex]
Hope this helps!
And thank you for posting your question at here on brainly, and have a great day.
-Charlie