please help asap!!! brainliest to best/right answer!!!!!!

Please Help Asap!!! Brainliest To Best/right Answer!!!!!!

Answers

Answer 1
The answer is C, I hope this helps!

Related Questions

If cos thetha =-0.96 and (sec thetha)(sin thetha)>0 find the value of tan thetha

Answers

cos(theta)=-0.96 <0
=>
theta is either in the 2nd or third quadrant.

cos(theta)=-0.96
=>
sec(theta)=1/cos(theta)=-1/0.96   <0

Given sec(theta)(sin(theta)>0
=> cos(theta)sin(theta)>0
=> cos(theta) and sin(theta) have the same sign, 
=> sin(theta)<0 
=>
theta is in the third quadrant. => tan(theta)>0

Given cos(theta)=-0.96
=>
|sin(theta)|=sqrt(1-(-0.96)^2)=sqrt(0.0784)=0.28 
=> sin(theta)=-0.28

Finally, 
tan(theta)=sin(theta)/cos(theta)=-0.28/-0.96
=7/24 
=0.29167 (to the fifth decimal place)

find the solution of this system of equations shown on the graph.

Answers

answer is (0,3)

hope it helps

A sequence is defined by the recursive function f(n + 1) = f(n) – 2. If f(1) = 10, what is f(3)? 1 6 8 30

Answers

The value of f(3) would be 6.

Using our formula, we know that f(1) = 10, and f(2) = f(1) - 2 = 10-2 = 8.  That means that f(3) = f(2) - 2 = 8 - 2 = 6.

Answer:

6

Step-by-step explanation:

what is the length of the 2nd base of a trapezoid if the length of one base is 27 and the length of the midsegment is 19

Answers

1. To solve this exercise you must apply the "Trapezoid midsegment theorem", which says that the length of the midsegment is equal to half the sum of the lengths of the bases of the trapezoid. Therefore, you have:
 
 x=(a+b)/2
 
 "x" is the midsegment (x=19).
 "a" and "b" are the bases (a=27).
 
 2. When you clear the second base "b" from the formula  x=(a+b)/2 and you substitute the values, you obtain: 
 
 x=(a+b)/2
 2x=a+b
 b=2x-a
 b=2(19)-27
 b=38-27
 b=11
 
 What is the length of the 2nd base of a trapezoid?
 
 The answer is: 11

Answer: 11


Step-by-step explanation:

X=(a+b)/2

2x=a+b

B=2+-a

B=2(19)-27

B=3-27

B=11


WILL MARK AS BRAINLIEST
Complete the general form of the equation of a sinusoidal function having an amplitude of 1, a period of [tex]\frac{ \pi }{2} [/tex], and a vertical shift up 3 units.
y=__________

Answers

The general form for a sine function is: y = a sin(b[x + c]) + d
The amplitude is given by a, so a = 1.
The period is given by 2*pi/b, so 2*pi/b = pi/2, and b = 4.
The variable c gives the horizontal shift, of which there is none, so c = 0.
Finally, the vertical shift of 3 units means that d = 3.
So the equation is:
y = sin(4x) + 3

Answer:

y = sin(4x) + 3

Step-by-step explanation:

Please answer this question!! Show your work

Answers

The answer is 6.4%

When converting a decimal to a percent two places to the right.


I hope this helps!

(Please help~! 20 Points~!)
The solution to 8x = 32 is x = ___.
3
4
5
6

Answers

8x=32
x=
[tex] \frac{32}{8} [/tex]

=4
8x = 8 x 4 because 8 x 3 = 24, 8 x 5 = 40, and 8 x 6 = 48, so the only reasonable answer would be b. 4.

Brainliest please? I am trying to move up a rank!

Solve the system of equations

1.8x-0.5y=-6.4
0.6x+2.1y=2.4

_______________________

x= ??

y= ??

Answers

Solve the following system:
{1.8 x - 0.5 y = -6.4
{0.6 x + 2.1 y = 2.4

In the first equation, look to solve for x:
{1.8 x - 0.5 y = -6.4
{0.6 x + 2.1 y = 2.4

1.8 x - 0.5 y = (9 x)/5 - y/2 and -6.4 = -32/5:
{(9 x)/5 - y/2 = -32/5


Add y/2 to both sides:
{(9 x)/5 = 1/10 (5 y - 64)
{0.6 x + 2.1 y = 2.4

Multiply both sides by 5/9:
{x = 1/18 (5 y - 64)
{0.6 x + 2.1 y = 2.4

Substitute x = 1/18 (5 y - 64) into the second equation:
{x = 1/18 (5 y - 64)
{2.1 y + 0.0333333 (5 y - 64) = 2.4

2.1 y + 0.0333333 (5 y - 64) = 2.1 y + (0.166667 y - 2.13333) = 2.26667 y - 2.13333:
{x = 1/18 (5 y - 64)
2.26667 y - 2.13333 = 2.4

In the second equation, look to solve for y:
{x = 1/18 (5 y - 64)
{2.26667 y - 2.13333 = 2.4

2.26667 y - 2.13333 = (34 y)/15 - 32/15 and 2.4 = 12/5:
(34 y)/15 - 32/15 = 12/5

Add 32/15 to both sides:
{x = 1/18 (5 y - 64)
{(34 y)/15 = 68/15

Multiply both sides by 15/34:
{x = 1/18 (5 y - 64)
y = 2


Substitute y = 2 into the first equation:

Answer: {x = -3, y = 2

Which term describes what a manufacturer spends for goods or services?

a)cost
b)price
c)markup

Pleas help. Willl fan and medal!!

Answers

The term describing what a manufacturer spends for goods or services is cost. Cost is the expenses incurred by the manufacturer as a result of his business or undertaking. There are two types of cost of a manufacturer. The cost of goods sold and the operating expenses. The cost of goods sold are those cost incurred directly as a result of manufacturing. The operating expenses are those other expenses not indirectly involved with the manufacture of goods or services.

Find the greatest common factor : 32a^3b^2, 44ab^3 and 40a^2b

Find the greatest common factor : 25^2q^3, 15p^2q^2 and 35pq^4

Answers

Answer
1) 4ab
2)  5pq²

Explanation
Greatest common factor is sometimes known as GCD (greatest common divisor). It means the greatest number that can divide a set of numbers.
For example, the GCD of 12 and 18 is 6.

Question 1
Find the GCF of 32a^3 b^3,44ab^3,and 40a^2 b. To do this you can factor out the common term.
32a^3 b^3,44ab^3,and 40a^2 b
Dividing every term by ab we shall have,
ab(32a^2 b^2,44b^2,and 40a)
Dividing again by 4,
4ab(8a^2 b^2,11b^2,and 10a)
Have no other common factor, the GCF = 4ab

Question 2
Find the GCF of 25p²q³,15p² q² and 35pq^4 . To do this you can factor out the common term.
25p²q³,15p² q² and 35pq^4
Dividing each term by 5,
5(5p²q^3, 3p²q² and 7pq^4)
Dividing again by pq2,
5pq² (5pq, 3p and 7q² )
There no been any other common divisor, the GCF = 5pq²

Answer:

Part A. 4ab

Part B. 5pq²

Step-by-step explanation:

Part A). In this part the given expressions are 32a³b², 44ab³, 40a²b

We have to find the greatest common factor of these expressions.

Factors of 32a³b² = 2×2×2×2×2×a×a×a×b×b

Factors of  44ab³ = 2×2×11×a×b×b×b

Factors of 40a²b = 2×2×2×5×a×a×b

So for the the greatest common factor we will choose the common factors (bold letters) of three expressions

GCF = 2×2×a×b = 4ab

Part B). The given expressions are 25p²q³, 15p²q² and [tex]35pq^{4}[/tex]

Factors of 25p²q³ = 5×5×p×p×q×q×q

Factors of 15p²q² = 3×5×p×p×q×q

Factors of [tex]35pq^{4}[/tex] = 5×7×p×q×q×q×q

Therefore greatest common factor will be = 5pq²

What are two solutions of 3 + 4 |x/2 + 3| = 11?

Answers

3 + 4abs(x/2 + 3) = 11 Subtract 3
4 abs(x/2 + 3) = 11 - 3
4 abs(x/2 + 3) = 8 Divide by 4
abs(x/2 + 3) = 8/4
abs(x/2 + 3) = 2

Solution 1
x/2 + 3 = 2 Subtract 3
x/2 = 2 - 3
x/2 = - 1 Multiply by 2
x/2 *2 = - 2
x = - 2

Solution 2
x/2 + 3 = - 2
x/2 = - 2 - 3
x/2 = - 5 Multiply by 2
x = -5 * 2
x = -10

Solutions
x = - 2 <<<< answer 1
x = -10 <<<< answer 2

If 8900 is invested at 3.8%

Answers

is this the question, i am assuming you are asking?            


If $8,900 is invested at 3.8% interest compounded quarterly, how much will the investment be worth in 13 yrs?
A.$14,551.87
B.$14,518.40
C.$14,452.92
D.$14,574.46


If it is, Here is your answer:

Just plug everything into the equation.

A(t) = P(1 + r/n)^(nt)

P is the principle (investment)
r is the interest rate expressed as a decimal
n is the number of times compounding occurs in a year
t is the number of years

A(13) = 8900(1 + 0.038/4)^(4+13) = 14551.87 

Answer is (A): 14, 551.87

5x - 20 = 2x + 10 How do you solve this problem?

Answers

5x - 2x = 10 + 20

3x = 30

x is 10
x=10
5x - 20 = 2x + 10
add 20 to both sides

5x= 2x + 30
subtract 2x from both sides

3x= 30
divide both sides by 3

x= 10

Hope this helps! :)

The range of typical total prices for an American tourist traveling on the European continent is $20.70 to $25.00. What is the average price?

Answers

For this case what we should do is find an average value of the total prices for a trip to europe
 We look for the average of the prices by means of the following expression:
 P = (20.70 + 25) / (2)
 P = 22.8 $
 Answer: 
 the average price is $ 22.8

Answer:

(The other answer has missing a number.)

The full answer is: $22.85

A platform has a volume of 135 cubic feet, but the concrete Joey wants to buy is sold by the cubic yard.

Answers

Not sure exactly what you're asking here, it probably cut you off and wouldn't let you type any more but I think the answer is that he needs to get a third of his original amount he was planning on buying, making it evened up to being 135 cubic feet.

The number of cubic yards of concrete does Joey need to buy is 5 cubic yards.

What is metric conversion?

Metric Conversion refers to the conversion of the given units to desired units for any quantity to be measured.

Given that, a platform has a volume of 135 cubic feet.

One cubic yard is equal to 27 cubic feet.

Now, number of cubic yards

= 135/27

= 5 cubic yards

Therefore, the number of cubic yards of concrete does Joey need to buy is 5 cubic yards.

To learn more about the metric conversion visit:

brainly.com/question/21244256.

#SPJ2

"Your question is incomplete, probably the complete question/missing part is:"

A platform has a volume of 135 cubic feet, but the concrete Joey wants to buy is sold by the cubic yard.

How many cubic yards of concrete does Joey need to buy?

Please help asap!!!! 53 points!

Answers

The easiest way is to graph it based upon the slope (m) and y-intercept (b), in the standard slope-intercept form: y = m (x) + b.
The line above intercepts the y-axis at y = -2, which is b. The slope (m) = rise/run = (y2-y1)/(x2-x1 ); so for the point (-4, 2) to (-6, 4) is:
(4-2)/(-6--4) = 2/(-6+4) = 2/-2 = -1.
So one form of the equation would be:
y = -1x - 2
Now the other form of an equation is point-slope: y-k = m (x-h), where the point is at (h, k)
and if we pick -5 for x (bc 5 it listed in 3 of the answers), the y at x=-5 looks like around +3
so we get: y-k = -1 (x--5)...
y-3 = -(x+5)... therefore D) is the correct answer:

Simplify these 12 radicals:
1) √80 2) √64
3) √45 4) √54
5) √32 6) √36
7) √150 8) √20
9) √180 10) √72
11) √8 12) √50

Answers

1)
[tex]4 \sqrt{5} [/tex]
2)
[tex]8[/tex]
3)
[tex]3 \sqrt{5} [/tex]
4)
[tex]3 \sqrt{6} [/tex]
5)
[tex]4 \sqrt{2} [/tex]
6)
[tex]6[/tex]
7)
[tex]5 \sqrt{6} [/tex]

8)
[tex]2 \sqrt{5} [/tex]
9)
[tex]6 \sqrt{5} [/tex]
10)
[tex]6 \sqrt{2} [/tex]
11)
[tex]2 \sqrt{2} [/tex]
12)
[tex]5 \sqrt{2} [/tex]

Evaluate 2x^2 − 5y / 3x − y when x = 2 and y = -4


Answers

If you substitute all the variables with the number assigned the answer would be 18.

If a force of 60 N is exerted on a 15 kg object, calculate the acceleration that the object undergoes. ________ m/s2 4 900 0.25 40

Answers

F=m•a
Then:
a=F/m
a=60/15=4 m/s²

Answer:  The correct option is

(A) 4 m/s.

Step-by-step explanation:  We are given that a force of 60 N is exerted on a 15 kg object.

We are to calculate the acceleration that the object undergoes.

From Newton's second law of motion, we have

[tex]F=ma,[/tex] where m is the mass of the object, a is the acceleration and F is the force exerted.

For the given object, we have

F = 60 N  and  m = 15 kg.

So, we get

[tex]F=ma\\\\\Rightarrow 60=15\times a\\\\\Rightarrow a=\dfrac{60}{15}\\\\\Rightarrow a=4.[/tex]

Thus, the required acceleration that the object undergoes is 4 m/sec.

Option (A) is CORRECT.

A job applicant estimates that his chance of passing a qualifying examination is 2/3, and his chance of being appointed if he does pass is 1/4. What is the probability that he will receive the job?

Answers

so, basically 2
2 * 1
- -
3 * 4
so 2 /12
1/6 when simplified
Answer:

Hence, the probability that he will receive job is:

                                   1/6

Step-by-step explanation:

It is given that:

chance of passing a qualifying examination is 2/3=P

and chance of being appointed if he does pass is 1/4=P'

Now, we are asked to find the probability that he will receive the job.

We are asked to find the probability that he will receive the job.

The probability is calculated as:

Probability that he qualify exam×Probability that he is being appointed.

=P×P'

=(2/3)×(1/4)

=1/6

Two parallel lines are _____ coplanar.


never


sometimes


always


Two lines that lie in parallel planes are _____ parallel.


sometimes


always


never



Please explain the answers, I want to understand this better.

Answers

Answer:

1. always

2. sometimes

Step-by-step explanation:

Two lines are coplanar if they lie in the same plane or in parallel planes. There is  ALWAYS a plane which contains two parallel lines (see first attached image for details).

Two lines that lie in parallel planes are sometimes parallel. For example, see at second image. Planes [tex]\alpha[/tex] and [tex]\beta[/tex] are parallel. Consider pair of lines [tex]a[/tex] and [tex]a_1[/tex] - they are parallel, but if you consider the pair of lines [tex]a[/tex] and [tex]b_1[/tex], you can see they are not parallel.

Answer:

always

sometimes

Step-by-step explanation:

By definition parallel lines are lines in a plane which do not meet, that means, they have to be coplanar. Coplanar means they are included in the same plane. Then, two parallel lines are always coplanar (imagine two parallel lines in a 3d space, there is always a plane that can contain them).

Two lines that lie in parallel planes are sometimes parallel. As stated before, if there is a third plane which contains the two lines, they can be parallel or cannot, but if there is no plane which contains them, they are not parallel.

Please help ASAP!!!! 52 points and will give brainliest for RIGHT answer!

Answers

i have made sure and the correct answer is d

Mara listens to audiobooks while she’s driving. She has 3 mystery, 4 fiction, and 2 humor audiobooks in her car. Summarize the data using the mode

Answers

The mode, or most commonly occurring number in this data set, would be 4. Mara, therefore, has mostly fiction titles in her car.

Answer:The mode, or most commonly occurring number in this data set, would be 4. Mara, therefore, has mostly fiction titles in her car.

Step-by-step explanation:

Jax solved an equation and justified his steps as shown below. What reason would justify step 2?

3x + 5 > 2 Step 1: Given

3x > -3 Step 2: ?

x> -1 Step 3: Division Property of Equality



a. Combine Like Terms


b. Division Property of Equality


c. Subtraction Property of Equality


d. Multiplication Property of Equality

Answers

Answer: The Subtraction Property of Equality

In the problem that Jax solved he subtract 5 from both sides of the equation. This is an example of the subtraction property of equality.

The property states that if you subtract the same amount from both sides of an equation the equation remains the same.
Final answer:

Step 2 can be justified using the Multiplication Property of Equality. This property states that if we multiply or divide both sides of an inequality by the same number, the inequality will still hold true.

Explanation:

Step 2 can be justified using the Multiplication Property of Equality. This property states that if we multiply or divide both sides of an inequality by the same number, the inequality will still hold true.

In this case, Jax divided both sides of the inequality by 3. This is a valid step because dividing both sides of the inequality by a positive number does not change the inequality. So, by dividing both sides by 3, Jax found that x > -1.

Make a the subject of the formula: v^2=u^2+2as. Please help & show working

Answers

It just means to isolate a. You can start like this::

V^2 = U^2 + 2AS
V^2 - U^2 = 2AS
(V^2 - U^2)/2S = A
A= (V^2 - U^2)/2S 

10 POINTS + BRAINLIEST ANSWER

A box contains 30 pieces of chocolate, distributed as shown in the table below. Each piece is made of either white chocolate or dark chocolate, and each piece contains either cream filling or no filling. If one piece is selected at random, what is the probability that the piece is either white chocolate with cream filling or dark chocolate with no filling? (10 POINTS + BRAINLIEST ANSWER)

A. 8/30

B. 12/30

C. 20/30

D. 22/30

Answers

It’s A 5+3= 8
8/30
I need 20 characters

The probability of selecting a chocolate at random that is either white chocolate with cream filling or dark chocolate with no filling is [tex]\frac{8}{30}[/tex].

What is probability?

Probability is the chance of happening an event or incident.

Given, the box contains 30 chocolates.

The number of chocolates that are white chocolate with cream filling is 5.

Therefore, the probability of selecting a chocolate at random that is white chocolate with cream filling is [tex]= \frac{5}{30}[/tex].

The number of chocolates that are dark chocolate with no filling is 3.

Therefore, the probability of selecting a chocolate at random that is dark chocolate with no filling is [tex]= \frac{3}{30}[/tex].

Now, the probability of selecting a chocolate at random that is either white chocolate with cream filling or dark chocolate with no filling is

[tex]= \frac{5}{30} + \frac{3}{30} \\= \frac{8}{30}[/tex]

Learn more about probability here: https://brainly.com/question/28001361

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What number is between 7/11 and 7/10

which one?
76/99
23/33
77/9
25/44

???? plz be sure its 56 points

Answers

23/33 is between 7/11 and 7/10 :)

PLEASE HELP QUICK!!!!

11PTS AND BRAINLIEST AVAILABLE TO CORRECT ANSWER

Answers

Your answer would be B

A machine packs at a constant rate of 2/3 of a box every 1/2 minuet. What’s is the number of boxes per minute that’s the machine packs?

Answers

For this case what we can do is the following rule of three:
 2/3 of a box ------> 1/2 minutes
 x of a box ---------> 1 minute
 Clearing x we have:
 x = (1 / (1/2)) * (2/3)
 Rewriting:
 x = 2 * (2/3)
 x = 4/3
 Answer:
 the number of boxes per minute that the machine packs is:
 x = 4/3

PLS HELP QUICKLY :V) Anna brings her granddaughter to a photo studio to take spring pictures. For the picture, they have a choice of a background scene, a toy prop, and an outfit. The studio has 12 different background scene, 36 toy props, and 15 outfits to choose from.

How many possible outcomes of a background scene, a toy prop, and an outfit does Anna have?

Answers

to figure out how many different possibilities there are in total, you need to multiply all the numbers together. 36*12*15=6840

so there are 6840 possibilities, and to get a single one of these, the probability is 1/6840

To calculate the total number of possible outcomes for the photo shoot, you multiply the number of background scenes (12), toy props (36), and outfits (15), which results in 6,480 possible combinations.

The question posed involves determining the number of possible combinations of a background scene, a toy prop, and an outfit in a photo studio with a set number of each option available. To find the total number of possible outcomes, one should multiply the number of choices for each category together. In this case, Anna has 12 different background scenes, 36 toy props, and 15 outfits to choose from.

Therefore, the calculation is as follows:

Number of background scenes: 12

Number of toy props: 36

Number of outfits: 15

By multiplying these numbers, we determine the total number of possible outcomes:

12 (backgrounds) times 36 (props) times 15 (outfits) = 6,480 possible outcomes.

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