Answer:
hydrogen
Explanation:
How many liters of o2 at 298 k and 1.00 bar are produced in 1.25 hr in an electrolytic cell operating at a current of 0.0500 a?
Answer:
0.0144 L
Explanation:
Step 1:
Data obtained from the question. This includes:
Temperature (T) = 298k
Pressure (P) = 1 bar
Time (t) = 1.25 hr
Current (I) = 0.0500 A
Step 2:
Determination of the quantity of electricity (Q) used. This is illustrated below:
Q = it
Time (t) = 1.25 hr = 1.25 x 3600 = 4500 secs
Current (I) = 0.0500 A
Quantity of electricity (Q) =?
Q = it
Q = 0.05 x 4500
Q = 225C
Step 3:
Determination of the number of mole of O2 liberated in the process.
In the electrolytic process, O2 will be liberated according to the equation:
2O^2- + 4e- —> O2
From the above illustration, 4 faraday are needed to liberate 1 mole of O2.
1 faraday = 96500C
Therefore of 4 faraday = 4x96500C = 386000C
From the above equation,
386000C of electricity liberated 1 mole of O2.
Therefore, 225C will liberate = 225/386000 = 5.83x10^-4 mole of O2.
Step 4:
Determination of the volume of the O2 liberated.
Number of mole (n) = 5.83x10^-4 mole
Temperature (T) = 298k
Pressure (P) = 1 bar = 0.987 atm
Gas constant (R) = 0.082atm.L/Kmol
Volume (V) =?
Applying the ideal gas equation:
PV = nRT
The volume of O2 can be obtained as follow:
PV = nRT
0.987 x V = 5.83x10^-4 x298x0.082
Divide both side by 0.987
V = (5.83x10^-4 x298x0.082)/0.987
V = 0.0144 L
The volume of [tex]\(O_2\)[/tex] produced is approximately [tex]0.0145 \ liters[/tex] at [tex]298 \ K[/tex] and [tex]1.00[/tex] bar.
To determine the volume of [tex]\(O_2\)[/tex] gas produced in an electrolytic cell, we can follow these steps:
Calculate the total charge
The total charge [tex]\(Q\)[/tex] passed through the cell is given by the product of current [tex]\(I\)[/tex] and time [tex]\(t\)[/tex]:
[tex]\[ Q = I \cdot t \][/tex]
Given:
[tex]Current, \(I = 0.0500 \, \text{A}\)[/tex]
[tex]Time, \(t = 1.25 \, \text{hr} = 1.25 \times 3600 \, \text{s} = 4500 \, \text{s}\)[/tex]
[tex]\[ Q = 0.0500 \, \text{A} \times 4500 \, \text{s} = 225 \, \text{C} \][/tex]
Determine the amount of [tex]\(O_2\)[/tex] produced
The half-reaction for the production of [tex]\(O_2\)[/tex] in water electrolysis is:
[tex]\[ 2 \, \text{H}_2\text{O} \rightarrow \text{O}_2 + 4 \, \text{H}^+ + 4 \, \text{e}^- \][/tex]
From this reaction, we see that [tex]4[/tex] moles of electrons produce [tex]1[/tex] mole of [tex]\(O_2\)[/tex]
The Faraday constant [tex](\(F\))[/tex] is [tex]\(96485 \, \text{C/mol}\)[/tex].
The moles of electrons [tex](\(n_{\text{e}^-}\))[/tex] can be calculated as:
[tex]\[ n_{\text{e}^-} = \frac{Q}{F} = \frac{225 \, \text{C}}{96485 \, \text{C/mol}} = 0.00233 \, \text{mol} \][/tex]
From the stoichiometry of the half-reaction, [tex]4[/tex] moles of electrons produce [tex]1[/tex] mole of [tex]\(O_2\)[/tex]:
[tex]\[ n_{\text{O}_2} = \frac{n_{\text{e}^-}}{4} = \frac{0.00233 \, \text{mol}}{4} = 0.000583 \, \text{mol} \][/tex]
Calculate the volume of [tex]\(O_2\)[/tex] gas
Use the ideal gas law to find the volume of [tex]\(O_2\)[/tex] gas at [tex]298\ K[/tex] and [tex]1.00[/tex] bar:
[tex]\[ PV = nRT \][/tex]
Given:
Pressure, \[tex](P = 1.00 \, \text{bar} = 1.00 \times 10^5 \, \text{Pa}\)[/tex]
Temperature, [tex]\(T = 298 \, \text{K}\)[/tex]
Gas constant, [tex]\(R = 8.314 \, \text{J/(mol K)}\)[/tex]
Moles of [tex]\(O_2\), \(n = 0.000583 \, \text{mol}\)[/tex]
[tex]\[ V = \frac{nRT}{P} = \frac{0.000583 \, \text{mol} \times 8.314 \, \text{J/(mol K)} \times 298 \, \text{K}}{1.00 \times 10^5 \, \text{Pa}} \][/tex]
[tex]\[ V = \frac{1.447 \, \text{J}}{1.00 \times 10^5 \, \text{Pa}} = 1.447 \times 10^{-5} \, \text{m}^3 \][/tex]
[tex]\[ V = 0.01447 \, \text{L} \][/tex]
What conditions are required for heat transfer between states of matter to occur? In what
direction will heat transfer occur?
We add 1.4 moles to 700 mL of water what is the molarity?
Answer: The molarity of solution is 2 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n = moles of solute = 1.4
[tex]V_s[/tex] = Volume of solution in ml = 700 ml
Now put all the given values in the formula of molality, we get
[tex]Molality=\frac{1.4\times 1000}{700}=2mole/L[/tex]
Therefore, the molarity of solution is 2 M
The pressure in a car tire is 198 kPa at 27°C. After a long drive, the pressure
is 225 kPa. What is the temperature of the air in the tire? Assume that the
volume is constant. Make sure your answer is rounded to nearest whole
number and your final answer has the units of K.*
Answer : The temperature of the air in the tire is, 341 K
Explanation :
Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.
[tex]P\propto T[/tex]
or,
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure = 198 kPa
[tex]P_2[/tex] = final pressure = 225 kPa
[tex]T_1[/tex] = initial temperature = [tex]27^oC=273+27=300K[/tex]
[tex]T_2[/tex] = final temperature = ?
Now put all the given values in the above equation, we get:
[tex]\frac{198kPa}{300K}=\frac{225kPa}{T_2}[/tex]
[tex]T_2=340.9K\approx 341K[/tex]
Therefore, the temperature of the air in the tire is, 341 K
Calculate the mass of KOH in a 35% solution that contains 58.5 g of water.
Answer:
Approximately [tex]\rm 31.5\; g[/tex].
Explanation:
The mass of a solution can be divided into two parts:
the solute (the material that was dissolved,) and the solvent.In this particular [tex]\rm KOH[/tex] solution in water,
[tex]\rm KOH[/tex] is the solute, whilewater is the solvent.The number [tex]35\%[/tex] here likely refers to the concentration of [tex]\rm KOH[/tex] in this solution. That's ratio between the mass of the solute ([tex]\rm KOH[/tex]) and the mass of the whole solution (mass of solute plus mass of solvent.) That is:
[tex]\displaystyle \frac{m(\text{KOH})}{m(\text{solution})} = 35\% = 0.35[/tex].
Hence, [tex]m(\mathrm{KOH}) = 0.35\, m(\text{solution})[/tex].
However, since the solution contains only the solute and the solvent, [tex]m(\text{solution}) = m(\text{solute}) + m(\text{solvent})[/tex].
For this solution in particular,
[tex]\begin{aligned}&m(\text{solution})\\&= m(\text{solute}) + m(\text{solvent}) \\ &= m(\text{KOH}) + m(\text{water})\end{aligned}[/tex].
As a result,
[tex]\begin{aligned}&m(\mathrm{KOH})\\ &= 0.35\, m(\text{solution}) \\&= 0.35\, (m(\mathrm{KOH}) + m(\text{water}))\\&= 0.35\, m(\mathrm{KOH}) + 0.35 \, m(\text{water})\end{aligned}[/tex].
Subtract [tex]0.35\, m(\mathrm{KOH})[/tex] from both sides of the equation:
[tex](1 - 0.35)\, m(\mathrm{KOH}) = 0.35\, m(\text{water})[/tex].
[tex]\begin{aligned} &m(\mathrm{KOH}) \\ &= \left(\frac{0.35}{1 - 0.35}\right)\cdot m(\text{water}) \\ &= \frac{0.35}{0.65} \times 58.5\; \text{g} = 31.5 \; \text{g}\end{aligned}[/tex].
Note, that for this calculation, there's nothing special about this [tex]35\%[/tex] solution of [tex]\mathrm{KOH}[/tex] in water. In general,
[tex]\displaystyle m(\text{solute}) = \left(\frac{\%\text{concentration}}{100\% - \%\text{concentration}}\right)\cdot m(\text{solvent})[/tex].
Why does phosphate act as an environmental contaminant?
Answer:
Too much phosphorus in the water causes algae to grow faster than ecosystems can handle. Large growths of algae are called algal blooms and they can severely reduce or eliminate oxygen in the water, leading to illnesses in fish and the death of large numbers of fish.
Explanation
Futhermore, with a loss of fish the whole ecosystem will be upset and will be in need of serious recovery.
Final answer:
Phosphate acts as an environmental contaminant by promoting eutrophication, excessive growth of algae in water. It is introduced through human activities and contributes to the overgrowth of algae, leading to negative effects on the aquatic ecosystem.
Explanation:
Phosphate acts as an environmental contaminant due to its role in promoting eutrophication. Eutrophication is the excessive growth of algae in a body of water, which leads to a decrease in dissolved oxygen levels that can harm aquatic organisms. Phosphates are introduced into the environment through human activities, such as the use of phosphate-containing detergents and the leaching of phosphate from rock by weathering. These phosphates contribute to the overgrowth of algae and the subsequent negative effects on the aquatic ecosystem.a
What is meant by enthalpy change?
Enthalpy change is a measurement of heat energy absorbed or released during a chemical reaction at constant pressure. It reflects the net energy required to break the chemical bonds of reactants versus the energy released when new bonds form in products, determining if the reaction is endothermic or exothermic.
It represents the difference between the enthalpy (heat content) of the reactants and the products. When chemical bonds are broken in reactants, energy is absorbed, and when new bonds form in products, energy is released. If the energy required to break bonds is greater than the energy released when new bonds are formed, the reaction is endothermic and the enthalpy change is positive; conversely, if more energy is released during bond formation than is absorbed during bond breaking, the reaction is exothermic and exhibits a negative enthalpy change.
The enthalpy change can be calculated using the formula ΔH = Σ (bond dissociation energies of reactants) minus Σ (bond dissociation energies of products), which simplifies the overall energy balance of bond breaking and bond formation processes. This understanding allows scientists to predict whether a reaction will absorb or release energy and is crucial in fields such as thermodynamics and chemical engineering.
When an irregular shaped object was put in a graduated cylinder with an initial volume of 25 mL of water, the water level rose to 54.0 mL of water after the object was submerged. If the mass of the object is 7.0 grams, what is the density of the object
Answer:
0.24 g/mL
Explanation:
The density of an object is given by the ratio between its mass and its volume:
[tex]\rho=\frac{m}{V}[/tex]
where
m is the mass of the object
V is its density
In this problem, we have:
m = 7.0 g is the mass of the object
The volume of an irregular shaped object can be measured by putting it into water, and by measuring the difference in water volume.
In this case,
[tex]V_1=25 mL[/tex] is the initial volume of water
[tex]V_2=54 mL[/tex] is the final volume of water
So the volume of the object is
[tex]V=V_2-V_1=54-25=29 mL[/tex]
Therefore, the density of the object is:
[tex]\rho = \frac{7.0 g}{29 mL}=0.24 g/mL[/tex]
Final answer:
To find the density of an irregular shaped object submerged in water, the volume displaced by the object is calculated first, and then the density is found by dividing the mass of the object by the displaced volume. In this case, the density is 0.241 g/mL.
Explanation:
When an irregular shaped object is placed in a graduated cylinder with a starting volume of 25 mL of water and causes the water level to rise to 54.0 mL upon submersion, the object displaces a volume of water equal to the difference in these measurements. To calculate the density of the object, you have to use the formula for density, which is mass divided by volume. Given that the mass of the object is 7.0 grams and the volume displacement is 54.0 mL - 25 mL = 29.0 mL, the density of the object can be found using these values.
The calculation would be as follows: Density = Mass / Volume = 7.0 grams / 29.0 mL = 0.241 g/mL.
Therefore, the density of the object is 0.241 g/mL, indicating how compact the object's mass is within its volume.
Name this compound please
Answer:
I don't understand
Explanation:
Sorry
Answer:
Butanol
Explanation:
By counting, we know this is C4H9OH
C4H9OH is Butanol
A solution of potassium cyanide, KCN, is made by dissolving 3.2 g of KCN in water. When this solution reacts with excess hydrochloric acid, HCl, it produces 0.30 g of poisonous hydrogen cyanide gas, HCN.
KCN + HCl --> KCl + HCN
(a) Calculate the theoretical yield of HCN.
(b) Calculate the percent yield of HCN.
Answer:
22.7%
Explanation:
We must first put down the equation of reaction to guide our work while solving the problem.
KCN(aq) + HCl (aq)--> KCl(aq) + HCN(aq)
The questions specifically state that HCl is in excess so KCN is the limiting reactant.
Number of moles of KCN reacted= mass of KCN reacted / molar mass of KCN
Mass of KCN reacted= 3.2 g
Molar mass of KCN= 65.12 g/mol
Number of moles of KCN= 3.2/65.12 g/mol= 0.049 moles
Theoretical yield of HCN is obtained thus;
From the reaction equation;
1 mol of KCN produced 1 mole of HCN thus 0.049 moles of KCN will produce 0.049 moles of HCN.
Mass of HCN = number of moles ×molar mass
Molar mass of HCN= 27.0253 g/mol
Hence mass of HCN produced= 0.049mol × 27.0253 g/mol= 1.32g of HCN
Actual yield of HCN= 0.30g
% yield= actual yield/ theoretical yield ×100
% yield= 0.30/1.32 ×100
%yield= 22.7%
Answer:
The theoretical yield HCN is 1.33 grams
The percent yield HCN is 22.56 %
Explanation:
Step 1: Data given
Mass of KCN = 3.2 grams
Molar mass KCN = 65.12 g/mol
Mass of HCN produced = 0.30 grams
Step 2: The balanced equation
KCN + HCl --> KCl + HCN
Step 3: Calculate moles KCN
Moles KCN = mass KCN / moalr mass KCN
Moles KCN = 3.2 grams / 65.12 g/mol
Moles KCN = 0.0491 moles
Step 4: Calculate moles HCN
For 1 mol KCN we need 1 mol HCl to produce 1 mol KCl and 1 mol HCN
For 0.0491 moles HCN we'll have 0.0491 moles HCN
Step 5: Calculate mass HCN
Mass HCN = moles HCN * molar mass HCN
Mass HCN = 0.0491 moles * 27.03 g/mol
Mass HCN = 1.33 grams = the theoretical yield
Step 6: Calculate the percent yield HCN
Percent yield = (actual yiel / theoretical yield) * 100 %
Percent yield = (0.30 grams / 1.33 grams)
Percent yield = 22.56 %
A metal tank contains three gases: oxygen, helium and nitrogen. If the partial pressures of the three gases in the tank are 25 atm of oxygen, 12 atm of nitrogen and 15 atm of helium, what is the total pressure inside the tank
Answer:
52 atm
Explanation:
25 + 12 + 15 = 52 atm
- Please let me know you agree with this or if it is right or wrong. If wrong, I will fix it.
How much energy is needed to vaporize 75.0 g of diethyl ether (c4h10o) at its boiling point (34.6°c), given that δhvap of diethyl ether = 26.5 kj/mol?
Answer: 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether
Explanation:
First we have to calculate the moles of diethyl ether
[tex]\text{Moles of diethyl ether}=\frac{\text{Mass of diethyl ether}}{\text{Molar mass of diethyl ether}}=\frac{75.0g}{74g/mole}=1.01moles[/tex]
As, 1 mole of diethyl ether require heat = 26.5 kJ
So, 1.01 moles of diethyl ether require heat = [tex]\frac{26.5}{1}\times 1.01=26.8kJ[/tex]
Thus 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether
The energy i.e. needed is 26.8 kJ of energy
The calculation is as follows:the moles of diethyl ether is
[tex]= 75.0 g \div 74\\\\[/tex]
= 1.01 moles
Since one mole of diethyl ether require heat = 26.8 kJ
Now the energy should be the same i.e. 26.8
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The molecular weight of calcium carbonate, \text{CaCO}_3CaCO 3 start text, C, a, C, O, end text, start subscript, 3, end subscript, is 100.09\,\dfrac{\text g}{\text{mol}}100.09 mol g 100, point, 09, start fraction, start text, g, end text, divided by, start text, m, o, l, end text, end fraction. How many moles of calcium carbonate are in 63.8\,\text g63.8g63, point, 8, start text, g, end text of calcium carbonate?
Answer: The number of moles of calcium carbonate is 0.637 moles
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
We are given:
Given mass of calcium carbonate = 63.8 g
Molar mass of calcium carbonate = 100.09 g/mol
Putting values in above equation, we get:
[tex]\text{Number of moles of calcium carbonate}=\frac{63.8g}{100.09g/mol}\\\\\text{Number of moles of calcium carbonate}=0.637mol[/tex]
Hence, the number of moles of calcium carbonate is 0.637 moles
What element is represented by [Rn]7s1?
Answer:
Radon
Explanation:
The element represented by [Rn]7s1 is francium (Fr), an alkali metal in Group 1 of the periodic table. Francium is highly reactive and extremely rare, with a short half-life.
Explanation:The element represented by [Rn]7s1 is francium (Fr).
Fr is an alkali metal in Group 1 of the periodic table and has the atomic number 87. It is highly reactive and can be found in very small amounts in minerals.
Fr is the second rarest naturally occurring element and is extremely unstable, with a very short half-life.
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Name and describe three measures of central tendency used to summarize data.
Answer:
There are three main measures of central tendency: the mode(the number that occurs most often) the median ( the middle value in the list of numbers) and the mean (the average number in the list of numbers)
Explanation:
I learned this
5C + 6O2 = ? What will be the product of molecules formed from this equation?
Answer:
5C + 6O₂ → 5CO + 7/2 O₂
Explanation:
According to the question the reaction is between carbon and oxygen molecule . The reactant side was given as 5 moles of carbon reacting with 6 moles of oxygen molecules. The chemical reaction between carbon and excess oxygen will form carbon dioxide but with limited oxygen it will form carbon monoxide.
Now let us write and balance the actual chemical equation as required from the question. In limited oxygen the reaction will be
The reactant said 5 moles of carbon which is 5 atoms of carbon reacting with 12 atoms of oxygen. The number of atoms of element on both sides of the chemical equation need to be balance . The balanced equation when oxygen is limited is written as
5C + 6O₂ → 5CO + 7/2 O₂
The product will be 5 moles of carbon monoxide and 3.5 moles of oxygen molecules(7 atoms) since the oxygen is limited . The carbon monoxide later reacts with more oxygen to form carbon dioxide.
Limiting reactant is the reactant that stops the reaction when it is completely consumed. The product of the given reaction is Carbon dioxide.
Balanced Reaction:
A reaction in which the number of moles of atoms in reactants is equal to the number of moles of the atoms in the product.
The given reaction,
[tex]\bold{5C + 6O_2 \rightarrow 5CO_2 \\\\}[/tex]
Carbon is a limiting reactant that reacts with 5 oxygen molecules. Oxygen is the excess reactant present in a large amount in the atmosphere. Hence only 5 molecules of Carbon dioxide will be produced.Therefore, the product of the given reaction is Carbon dioxide.
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15. Three gases are mixed in a cylinder. The total pressure in the cylinder is 456 mmHg. If
the hydrogen gas has a pressure of 230 mmHg, and the oxygen gas has a pressure of
148 mmHg, what is the pressure of the third gas, nitrogen?
Answer:
78 mmHg is the partial pressure of the nitrogen.
Explanation:
According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gasses.
[tex]P=p_{1}+p_{2}+p_{3}[/tex]
where,
[tex]P[/tex] = total pressure of the gas mixture = 456 mmHg
[tex]p_{1}[/tex] = partial pressure of hydrogen gas = 230 mmHg
[tex]p_{2}[/tex] = partial pressure of oxygen gas = 148 mmHg
[tex]p_{3}[/tex] = partial pressure of nitrogen gas = ?
Now put all the given values is expression, we get the partial pressure of the nitrogen gas i.e. [tex]p_3[/tex] .
[tex]456 mmHg=230 mmHg+148 mmHg+p_3[/tex]
[tex]p_3=456 mmHg-230 mmHg-148 mmHg=78 mmHg[/tex]
78 mmHg is the partial pressure of the nitrogen.
When 16 g of methane (CH4) and 32 g of oxygen (O2) reacted to produce carbon dioxide and water, 11 g of carbon dioxide was produced. Calculate the percent yield of carbon dioxide in this reaction. A) 5.0% B) 10% C) 25% D) 50%
Answer:
Percent yield = 50%
Explanation:
Given data:
Mass of CH₄ = 16 g
Mass of O₂ = 32 g
Mass of CO₂ = 11 g
Percent yield of CO₂ = ?
Solution:
Chemical equation:
CH₄ + 2O₂ → CO₂ + 2H₂O
Number of moles of CH₄:
Number of moles = mass/ molar mass
Number of moles = 16 g /16 g/mol
Number of moles = 1 mol
Number of moles of O₂:
Number of moles = mass/ molar mass
Number of moles = 32 g /32 g/mol
Number of moles = 1 mol
Now we will compare the moles of CO₂ with both reactant.
O₂ : CO₂
2 : 1
1 : 1/2×1= 0.5 mol
CH₄ : CO₂
1 : 1
Number of moles of CO₂ produced by oxygen are less so it will limiting reactant.
Theoretical yield:
Mass of CO₂:
Mass = number of moles × molar mass
Mass = 0.5 mol × 44 g/mol
Mass = 22 g
Percent yield:
Percent yield = actual yield / theoretical yield × 100
Percent yield = 11 g/ 22 g × 100
Percent yield = 50%
Consider the reaction below.
2 upper K plus upper B r subscript 2 right arrow 2 upper K superscript plus, plus 2 upper B r superscript minus.
What is being reduced?
only K
only Br2
both K and Br2
neither K nor Br2
Answer:
c
Explanation:
What volume will 454.5 grams of Hydrogen gas occupy at 1.050 atm and 25.00 ℃? (Don’t forget Hydrogen gas is diatomic - H2.
Answer:
5.24×10^3 L
Explanation:
Considering the volume occupied by 454.5g of H2 at 1.050 atm and 25°C.
Likewise, using ideal gas equation.
pV = nRT
Answer: The volume occupied by the gas is 5295.1 L
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Given mass of hydrogen gas = 454.5 g
Molar mass of hydrogen gas = 2 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of hydrogen gas}=\frac{454.5g}{2g/mol}=227.25mol[/tex]
To calculate the volume, we use the equation given by ideal gas equation:
PV=nRT
where,
P = pressure of the gas = 1.050 at m
V = Volume of gas = ?
n = number of moles of gas = 227.25 moles
R = Gas constant = [tex]0.0821\text{ L atm }mol^{-1}K^{-1}[/tex]
T = temperature of the gas = [tex]25^oC=[25+273]K=298K[/tex ]
Putting values in above equation, we get:
[tex]1.050atm\times V=227.25mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\\\V=\frac{227.25\times 0.0821\times 298}{1.050}=5295.1L[/tex]
Hence, the volume occupied by the gas is 5295.1 L
O3(g)+NO(g)<—>O2(g)+NO2(g) Write the equalibrium expression
Answer: [NO2][O2]/[NO] [O3]
Explanation: Kc = [NO2][O2]/[NO] [O3]
NaOH and bleach have several characteristics in common. They include all BUT one of the characteristics listed.
Answer:
Their pH is less than 7
Explanation:
Both of these compounds pHs are greater than 7.
Answer:
A) Their pH is less than 7
Explanation:
Their pH is less than 7 is not correct. Their pH is greater than seven, but not equal to seven.
Describe the sources of marine debris and explain why it is a problem with global origins.
Answer:
Explanation:
Marine debris consists of most anything used and discarded by humans. Winds, rivers and storms can carry this debris to the ocean from far inland, so it is not solely a case of pollution along shorelines. It is also true that oceangoing ships directly contribute to marine debris while they are at sea and not associated with any particular nation.
What do the COEFFICIENTS in a chemical reaction represent?
Answer:First: the coefficients give the number of molecules (or atoms) involved in the reaction. In the example reaction, two molecules of hydrogen react with one molecule of oxygen and produce two molecules of water. Second: the coefficients give the number of moles of each substance involved in the reaction.
Explanation: PLESE GIVE BRAINLIEST
The coefficients tells us about the number of atoms, molecules or compound present in a reaction. They are actually the numbers or terms which are used in a balanced chemical equation.
What is a balanced chemical equation?A chemical equation in which amount of reactants and products on both sides of the equation are equal is defined as the balanced chemical equation. The number of atoms of reactants and products on both sides will be equal.
The coefficients are the numbers which are added in front of the chemical formulae or symbol in order to balance the chemical equation. Only by adding the coefficients a balanced equation obeys the law of conservation of mass.
An equation is balanced with the help of coefficients.
For example, in the given reaction:
2H₂ + O₂ → 2H₂O
The coefficients of H₂,O₂ and H₂O are 2, 1 and 2.
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You started with only 6.750 g of sodium carbonate, but you ended up with more mass than that at the end of the reaction. According to the Law of Conservation of Mass, matter cannot be created or destroyed, so how is it possible for the product to weigh more than the starting material? (State your answer in 1-2 complete sentences.)
Answer:
It is not possible, since the total weight of all the reagents involved in the reaction is equal to the total weight of the product, since it is not possible to create or destroy atoms, thus, it is not possible to change the weight of the product. It is equal to the weight of the reagent.
Explanation:
What solute can be found in the greatest amount in urine?
Answer:
THE CORRECT ANSWER TO THE QUESTION ABOVE IS " UREA"
Explanation:
SOLUTE is defined as solid, liquid, or gas that is dissolved in a solution.
URINE is a by-product of metabolism that is produced by the kidneys in their process of blood purification. URINE contains of water, urea, chloride, sodium, potassium, dissolved ions, and inorganic and organic compounds.
Physical characteristics of URINE include color, smell, pH, density and turbidity.
UREA (also known as carbamide) is a non-toxic molecule, it is made up of ammonia and carbon and is the major organic component of human urine. UREA in urine is 9.3 g/L.
What is the hydrogen ion concentration of a substance with a hydroxide ion concentration of 1.07x10-10M?
(Be sure to give your answer in 3 sig figs and the unit. Also type the letter "e" for "X10" just like on webassign
with no spaces)
Answer:
Explanation:
[OH⁻] = 1.07 x 10⁻¹⁰
[H⁺] x [ OH⁻ ] = 10⁻¹⁴
[H⁺] x 1.07 x 10⁻¹⁰ = 10⁻¹⁴
[H⁺] = 10⁻¹⁴ / 1.07 x 10⁻¹⁰
= .93458 x 10⁻⁴
= 9.3458 x 10⁻⁵
= 9.35 x 10⁻⁵
= 9.35e-5. M.
A solution is made containing 22.8 g of magnesium nitrate per 325 g of water. What is the weight/ weight % or percent by mass of the solute?
Answer:
6.56%
Explanation:
mass of solute = 22.8 g
mass of solution = mass (solute) + mass (water) = 22.8 + 325 = 347.8 g
% by mass = [mass(solute)/ mass(solution)]*100% =(22.8/347.8)*100% = 6.56%
what kelvin temperature is equivalent to 35 degrees Celsius?
Answer:
308.15
Explanation:
To convert 35 degrees Celsius to Kelvin, you add 273.15, resulting in 308.15 Kelvin.
This conversion is straightforward because the size of one Kelvin is the same as one degree Celsius.
Hence, 35 degrees Celsius is equivalent to 308.15 Kelvin.To convert a temperature from degrees Celsius to Kelvin, you can use a simple formula: K = °C + 273.15. This formula takes advantage of the fact that the size of one Kelvin is identical to one degree Celsius; the only difference is their starting points.For instance, to find the Kelvin equivalent of 35 degrees Celsius, you would calculate as follows:
Add 273.15 to the Celsius temperature: 35°C + 273.15 = 308.15 K.Therefore, the temperature of 35 degrees Celsius is equivalent to 308.15 Kelvin.Jonathan is working in his basement on a science fair project when his little sister closes and locks the door. Jonathan wants to let his parents know that he is stuck down in the basement. He can either yell as loudly as he can, bang on the metal pipes, or bang on the concrete wall. Which should he do if he wants someone to hear him? Explain your answer, and explain why the other options would not be as effective.
Answer:
he can bang metal pipes but i would rather say that he has to yell for help
Explanation:
why because the basement is very loud and echo so when is parents hear him they can run to basement and get him out
hope this helped
The specific characteristic of the metal is to emit a resonant sound when banged. Metals are sonorous, so, banging on the metal pipes can help Jonathan to let his parents know his condition, i.e., option B.
What are the properties of metal?Metals are materials that are lustrous, ductile, good conductors of heat and electricity, and malleable.
Other properties include the state of metals which are solids at room temperature except mercury and gallium, which is liquid at room temperature.
The property of sonority of metals can help Jonathan to let his parents know his condition.
Thus, the correct answer is B.
For more details regarding metals, visit:
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