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Related Questions
Due tomorrow help please
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41 -39 = 2
43 -41 = 2
45 -43 = 2
These are all the same, so 2 is the common difference of the arithmetic sequence beginning with 39.
The Nth term is
[tex]a_{n}=a_{1}+(n-1)d\\a_{n}=39+2(n-1)\\a_{n}=37+2n[/tex]
The problem statement seems to ask for the 10th term and for a15. Here they are.
[tex]a_{10}=37+2\cdot 10=57\\a_{15}=37+2\cdot 15=67[/tex]
the solutions to a linear equation are the points in the plane that make the inequality true .
true or false ?
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The statement is false. An equation's solutions are points on a line; an inequality's solutions encompass a region on the plane.
Explanation:The statement is false. The solutions to a linear equation are the points (x, y) in the plane that make the equation true, not an inequality. An equation represents a line on the coordinate plane, and every point on that line is a solution to the equation. In contrast, an inequality describes a range or region of the coordinate plane, not just a single line, and the solutions are the coordinates within that range.
For instance, the solutions to the equation y = 2x + 3 are all the points on the line where this is true. On the other hand, solutions to the inequality y > 2x + 3 would be all the points in the region above the line y = 2x + 3.
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The assertion that solutions to a linear equation are the points that make an inequality true is incorrect. It is the solutions to a linear inequality that would make the inequality true.
Explanation:The statement provided in the question is false. Solutions to a linear equation are the points on the line that make the equation true, not an inequality. If we are dealing with a linear inequality, then its solutions are the points in the plane that satisfy the inequality, often forming a region, instead of just the points on a line.
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do 5, 4, 3 represent the side lengths of a triangle
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9 + 16 = 25
They are the side lengths of a triangle and they are the sides of a RIGHT triangle.
Given the following sets: A={ 2, 4, 6, 8, 10} B={ 3, 5, 7, 9} C={ 2, 3, 5, 7} N={ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10} Match the following Unions and intersections to the correct set.
a) {2, 3, 5, 7, 9}
b){3, 5, 7, 9}
ｃ）{2, 3, 4, 5, 6, 7, 8, 10}
ｄ）{ }
ｅ）{2, 4, 6, 8, 10}
1.
What is A U C?
2.
What is A ∩ B?
3.
What is A ∩ N?
4.
What is B ∩ N?
5.
What is B U C?
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2. d - only the numbers in both sets (there are none)
3. e - A is a proper subset of N, so their intersection is identical to A
4. b - B is a proper subset of N, so their intersection is identical to B
5. a - all the numbers in either of the sets
Find the volume of the given prism. round to the nearest tenth if necessary.
a. 2,511.5 yd to the power of 3b) 1,255.7 yd to the power of 3c) 1,025.3 yd to the power of 3d) 1,450.0 yd to the power of 3
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we know that
volume of the prism=area of the base*height
step 1
find the area of the base
the base is an equilateral triangle
calculate the area with the law of sines
Area=(1/2)*a²*sin C
where
a=10 yd
C=60° (three internal angles are equals)
Area=(1/2)*10²*sin 60°-----> 25√3 yd²
step 2
find the volume
volume of the prism=(25√3)*29-----> 1255.74 yd³ ------> 1255.7 yd³
the answer is the option
b) 1,255.7 yd to the power of 3
2) B $ 70.58
3) A 7 in
4) C 54 (pi)in^3
5) D 944 mm^3
~GENERAL OUT~
Please help me with a simple math problem.
What is M DFE?
A. 19
B. 42
C. 78
D. 119
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Betty makes pies. To make 6 pies, she uses 127 cups of flour. How many cups of flour are needed to make 1 pie?
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HELP ME PLEASE THIS IS IMPORTANT
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since the answer has 9 as the exponent c = 9-7 = 2
c=2
the answer is positive 36 so d would be 36 / -9 = -4
d = -4
ABC Bookstore sells new books, n, for $12, and used books, u, for $8. The store earned $112 revenue last month. The store sold 4 more used books than new books. Using the substitution method, how many new and old books did ABC bookstore sell?
A.n = 4; u = 8
B.n = 8; u = 4
C.n = 8; u = 12
D.n = 12; u = 8
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Revenue from new books = 12n
Revenue from old books = 8u
Last month, the store earned $112 as revenue, so we can write:
12n + 8u = 112
The store sold 4 more used books than new books, so we can write:
u = n + 4
Using the value of u, in above equation, we get:
12n + 8(n+4) = 112
12n +8n + 32 = 112
20n= 80
⇒
n=4
Since,
u = n + 4
u = 4 + 4 = 8
Thus, the store sold 4 new books and 8 old books last month. So the correct option is A
Divide. Give the quotient and remainder.
55 Divided by 8
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therefore, quotient=6
remainder =7
What are the inputs of the function below?
Please help
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Explanation:
The function declaration is f(x) where x represents the input. The input in the table given is the row labeled with x. Hence the inputs are -8 2 4 6 as shown in the table. So the correct option is Option (C) -8 2 4 6.
-i
Answer:
Input of the function are -8,2,4,6
Step-by-step explanation:
Input of a function are the domain .
Domain is the values of x. So inputs are the value of x in the table
Input of the table is x and output is f(x)
Input are the values that gives the output f(x)
From the table the x values are -8,2,4 and 6
Input of the function are -8,2,4,6
Compare the exponential and logarithmic models of population growth
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exponential is how much something increases by the way, tell me if this helps
How to find the sum of the squares of the lengths of the legs of a triangle of a=(-6,11) b=(2,8) c=(-1,0)?
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To find the sum of the squares of the lengths of the legs of a triangle, use the distance formula to calculate the length of each leg and then square these lengths, summing the squares of the two legs that do not form the hypotenuse.
Explanation:To find the sum of the squares of the lengths of the legs of a triangle with vertices A=(-6,11), B=(2,8), and C=(-1,0), we first calculate the length of each leg using the distance formula, which is √((x2-x1)² + (y2-y1)²). For AB, AC, and BC we find distances:
AB = √((-6-2)² + (11-8)²)AC = √((-6+1)² + (11-0)²)BC = √((2+1)² + (8-0)²)Then, we square each leg's length:
AB² = ((-6-2)² + (11-8)²)AC² = ((-6+1)² + (11-0)²)BC² = ((2+1)² + (8-0)²)Finally, we sum up the squares of AB and AC because they represent the legs of the triangle:
Σ(leg squares) = AB² + AC²The sum of the squares of the lengths of the legs has now been found.
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Jacob drove from town a to town b at an average rate of x miles per hour, then returned along the same route at y miles per hour. if he then drove back to town b at z miles per hour along the same route, what was jacob's average rate of speed for the entire trip, in miles per hour?
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= (total distance)/(time of 1st journey + time of 2nd journey + time of 3rd journey)
Let d = the distance between Town A and Town B
So, total distance traveled = 3d
Time = distance/speed
time of 1st journey = d/x
time of 2nd journey = d/y
time of 3rd journey = d/z
Total time = d/x + d/y + dz
To simplify, rewrite with common denominator: dyz/xyz + dxz/xyz + dxy/xyz
So, total time = (dyz + dxz + dxy)/xyz
Average speed = (total distance)/(total time)
= 3d/[(dyz + dxz + dxy)/xyz]
= (3dxyz)/(dyz + dxz + dxy)
Divide top and bottom by d to get: (3xyz)/(yz + xz + xy)
Tan α = - 4/3 lies in quad 2, and cos β = 2/3 lies in quad 1 find
a. cos(α + β)
b. sin( α+β)
c. t...
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[tex]\cos^2x+\sin^2x=1[/tex]
[tex]\tan^2x+1=\sec^2x=\dfrac1{\cos^2x}[/tex]
[tex]\cos(\alpha+\beta)=\cos\alpha\cos\beta-\sin\alpha\sin\beta[/tex]
[tex]\sin(\alpha+\beta)=\sin\alpha\cos\beta+\cos\alpha\sin\beta[/tex]
Not sure what part (c) is asking for, but I assume it's [tex]\tan(\alpha+\beta)[/tex], in which case
[tex]\tan(\alpha+\beta)=\dfrac{\sin(\alpha+\beta)}{\cos(\alpha+\beta)}[/tex]
If [tex]\tan\alpha=-\dfrac43[/tex], then
[tex]\dfrac1{\cos^2\alpha}=1+\left(-\dfrac43\right)^2=\dfrac{25}9[/tex]
[tex]\implies\cos\alpha=\pm\dfrac35[/tex]
We know that [tex]\alpha[/tex] lies in quadrant 2, i.e. [tex]\dfrac\pi2<\alpha<\pi[/tex], so we expect [tex]\cos\alpha<0[/tex]. So we take the negative root. We also find that
[tex]\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}\iff-\dfrac43=\dfrac{\sin\alpha}{-\frac35}\implies\sin\alpha=\dfrac45[/tex]
If [tex]\cos\beta=\dfrac23[/tex], then
[tex]\sin^2\beta=1-\left(\dfrac23\right)^2=\dfrac59\implies\sin\beta=\pm\dfrac{\sqrt5}3[/tex]
Since [tex]\beta[/tex] lies in quadrant 1, i.e. [tex]0<\beta<\dfrac\pi2[/tex], we know that [tex]\sin\beta>0[/tex], so we take the positive root.
Now,
[tex]\cos(\alpha+\beta)=-\dfrac35\cdot\dfrac23-\dfrac45\cdot\dfrac{\sqrt5}3=-\dfrac52-\dfrac4{3\sqrt5}[/tex]
[tex]\sin(\alpha+\beta)=\dfrac45\cdot\dfrac23+\left(-\dfrac35\right)\cdot\dfrac{\sqrt5}3=\dfrac8{15}-\dfrac1{\sqrt5}[/tex]
Then it follows that
[tex]\tan(\alpha+\beta)=\dfrac{\frac8{15}-\frac1{\sqrt5}}{-\frac52-\frac4{3\sqrt5}}=\dfrac{54-25\sqrt5}{22}[/tex]
The day started at 48 degrees. by 3:00 p.m., the temperature has increased by 17 degrees. by nightfall, the temperature fell 17 degrees. what was the net change in temperature
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Final answer:
The net change in temperature over the day is 0 degrees. After increasing by 17 degrees in the afternoon, the temperature fell by 17 degrees by nightfall, returning it to the starting temperature.
Explanation:
The student has asked about calculating the net change in temperature over the course of a day starting at 48 degrees. By 3:00 p.m., the temperature increased by 17 degrees, making it 65 degrees. But by nightfall, the temperature decreased by the same amount, falling back down to 48 degrees. The calculation of net change in this scenario is simple: subtract the starting temperature from the final temperature after all changes have occurred. In this case, the starting temperature was 48 degrees, it went up to 65 degrees, and then back to 48 degrees.
The net temperature change is therefore 48 degrees (final temperature) - 48 degrees (starting temperature), which equals 0 degrees. This means there was no net change in temperature over the course of the day. It is important to recognize that even though there was a temporary increase and subsequent decrease, the net effect cancels out, leaving the temperature the same as it started.
The length of a train is about 1,700 meters. If there are approximately 3.28 feet in one meter, what is the length of the train in feet?
0.002 feet
557,600 feet
5,576 feet
518 feet
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To convert 1,700 meters to feet, we multiply by the conversion factor of 3.28 feet per meter, resulting in a length of 5,576 feet for the train.
Explanation:To find the length of the train in feet, we need to convert meters to feet using the conversion factor provided. Given that 1 meter is approximately 3.28 feet, we can calculate the length of the train in feet by multiplying the length of the train in meters (1,700 meters) by the conversion factor (3.28 feet per meter).
The calculation would be as follows:
1,700 meters × 3.28 feet/meter = 5,576 feet
Therefore, the length of the train is 5,576 feet.
The cylinder below has a volume of 785 ft^3. and the cone has a volume of 314 ft^3.
(please see attached picture)
Which explains which figure has the greater height?
The cylinder has a greater height because the bases are the same, but the cylinder has a greater volume.
The cylinder has a greater height because the volume of the cylinder is greater than twice the volume of the cone.
The cone has a greater height because the bases are the same, but the volume of the cylinder is less than 3 times the volume of the cone.
The cone has a greater height because the bases are the same, but the volume of the cylinder is less than 4 times the volume of the cone.
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Answer:
The cone has a greater height because the bases are the same, but the volume of the cylinder is less than 3 times the volume of the cone.
Step-by-step explanation:
Just did the quiz
order them from least to greatest, with the least at the top.
6\pi -6
\pi 3
\sqrt{99}
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/sqrt{99} : 9.94
6/pi - 6 : 12.85
/pi 3 : 31
Sorry if it was incorrect, I am bored haha
Arranging the numbers in ascending order is: √99 < 6π - 6 < π³
How to arrange the numbers in ascending order?Arranging numbers in ascending order simply means arranging them from smallest to the biggest.
Now, the given numbers are:
6π - 6
π³
√99
Let us simplify the numbers to get:
6π - 6 = 6(3.14) - 6 = 12.85
π³ = 3.14³= 31
√99 = 9.95
Thus, arranging in ascending order is:
√99 < 6π - 6 < π³
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the function of y=log(x) is translated 1 unit right and 2 units down. which is the graph of the translated function
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The graph of the translated function is attached
To find the graph of the function, we apply the translations
Parent function: y = log(x)
1 unit right: y = log(x - 1)
2 units down: y = log(x - 1) - 2
The graph of the function: y = log(x - 1) - 2 is attached
In a class experiment, Sean finds that the probability that a student plays soccer is . If the school population is 300, how many students would we expect to play soccer, based on Sean's experiment?
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well I just got out of a test and the answer was 144.
Wha is the greatest common factor of 1 and 27
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BRAINLIEST PLUS 22 POINTS
- Angle LOM and angle MON are complementary angles. If m∠LOM = (x + 15)° and m∠MON = 48°, which equation could be used to solve forx?
A. (x + 15)° + 48° = 180°
B. (x + 15)° = 90°
C. (x + 15)° + 90° = 48°
D. (x + 15)° + 48° = 90°
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Angles that are complementary add up to 90. We know that in order to find the value of x, we'll need to create an equation. This equation would be (x + 15) + 48 = 90. This is because, together, the two angles must add up to 90.
ANSWER:
D - (x + 15) + 48 = 90
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
The correct equation to solve for x, given that angle LOM (measured as (x + 15)°) and angle MON (measured as 48°) are complementary, is (x + 15)° + 48° = 90°. Thus, the answer is option D.
Explanation:The subject of this question is Mathematics, specifically it refers to geometry, solving for a variable, and understanding the concept of complementary angles. Let's analyze the options provided.
Two angles are said to be complementary if the sum of their measure is 90 degrees. So, if angle LOM and angle MON are complementary, the sum of m∠LOM and m∠MON should be 90°. Since the measure of m∠LOM is given as (x + 15)° and the measure of m∠MON is given as 48°, the equation that represents this relationship is (x + 15)° + 48° = 90°.
Therefore, option D is the correct choice to solve for x.
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Find the Perimeter of the triangle. Round 2 decimal places.
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[tex]d= \sqrt{( x_{2}- x_{1}) ^{2}+(y_{2}-y_{1})^{2} } [/tex]
And as perimeter is just the sum of length of all side, we will calculate the length of each side and then sum them up.
1. Side AB:
[tex]d_{1}= \sqrt{( 3- (-2)) ^{2}+(0-3)^{2} }[/tex]
d₁= √34
2.Side AC
[tex]d_{2}= \sqrt{( (-4)- (-2)) ^{2}+((-3)-3)^{2} }[/tex]
d₂=2√10
3.Side BC
[tex]d_{3}= \sqrt{( (-4)- 3) ^{2}+((-3)-0)^{2} [/tex]
d₃=√58
Perimeter
[tex]P= \sqrt{34}+ 2\sqrt{10} + \sqrt{58} [/tex]
P=19.77
Write the equation of the parabola that has the vertex at point (2,7) and passes through the point (−1,3).
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The equation of the parabola with the vertex at (2,7) and passing through (-1,3) is y = -(4/9)(x - 2)^2 + 7, found by substituting the given points into the vertex form of a parabola's equation.
Explanation:To find the equation of a parabola given its vertex and a point it passes through, we use the vertex form of a parabola's equation, which is y = a(x - h)^2 + k, where (h, k) is the vertex of the parabola.
Given the vertex at (2,7) and a point (-1,3) through which the parabola passes, we substitute these values into the vertex form to find the value of 'a'.
Substituting the vertex, we have:
y = a(x - 2)^2 + 7
Then, substituting the point (-1,3) into the equation, we get:
3 = a(-1 - 2)^2 + 7
Solving for 'a', we get:
3 = a(3)^2 + 7 \n3 = 9a + 7 \n-4 = 9a \na = -4/9
Therefore, the equation of the parabola is:
y = -(4/9)(x - 2)^2 + 7
The equation of the parabola with the vertex at (2,7) and passing through (-1,3) is y = -(4/9)(x - 2)2 + 7, found by substituting the given points into the vertex form of a parabola's equation.
To find the equation of a parabola given its vertex and a point it passes through, we use the vertex form of a parabola's equation, which is y = a(x - h)2 + k, where (h, k) is the vertex of the parabola.
Given the vertex at (2,7) and a point (-1,3) through which the parabola passes, we substitute these values into the vertex form to find the value of 'a'.
Substituting the vertex, we have:
y = a(x - 2)2 + 7Then, substituting the point (-1,3) into the equation, we get:
3 = a(-1 - 2)2 + 7
Solving for 'a', we get:
3 = a(3)2 + 7n3 = 9a + 7n-4 = 9ana = -4/9
Therefore, the equation of the parabolais: y=-(4/9)(x-2)2+7
point E is the midpoint of ab and point f is the midpoint of CD
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AB is bisected by CD (TRUE). This is True because E is the midpoint between A and B and CD passes through E
CD is bisected by AB (FALSE) CD is bisected by point F and not AB
AE = 1/2 * AB (TRUE) since E is the midpoint of AB , E divides AB into two equal halves
EF = 1/2 * ED (FALSE) The true statement would have been CF = 1/2* CD
FD = EB (FALSE) sinc we do not know if CD and AB are of the same lengths
CE + EF = ED (TRUE) since F is the midpoint the sum of CE and EF is equal to ED
The statements for the line AB and CD for this condition that are true are given as:
Option A: [tex]\overline{AB}[/tex] is bisected by [tex]\overline{CD}[/tex]
Option C: [tex]AE = \dfrac{1}{2} \times AB[/tex]
Option F: CE + EF = FD
What is a bisector?A bisector of a line bisects that considered line. Bisect means to split in two equal parts.
For this case, we see that CD passes through mid point of AB, so CD is bisector of line AB or we say that line segment AB is bisected by line segment CD.
But AB does not passes through the center of AB, thus, AB is not a bisector of CD, or we say that line segment CD is not bisected by line segment AB
AE = EB
And AE + EB = AB
Thus, AE + AE + AB
or 2AE = AB
or AE = (AB)/2 = (1/2)AB
E is not necessary to be fixed on CD, it can move between C and F. Thus any statement about length of E to any point on CD is not necessary to be true.
FD is half of CD and EB is half of AB. It is not necessary that AB and CD are of same length, thus, it is not necessary that FD and EB are going to be of same length, thus, not congruent(two line segments are called congruent (denoted by ≅) if they are of same lengths).
CE + EF = CF, and CF = FD since F is midpoint.
Thus, CE + EF = FD
Thus, the statements for the line AB and CD for this condition that are true are given as:
Option A: [tex]\overline{AB}[/tex] is bisected by [tex]\overline{CD}[/tex]
Option C: [tex]AE = \dfrac{1}{2} \times AB[/tex]
Option F: CE + EF = FD
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What is the expected value of the game if 3 hits pay $6, 2 hits pays $4, 1 hit pays $2, and 0 hits pays costs $4?
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[tex]P\left(3\:hits\right)=0.7\times 0.5\times 0.3=0.105[/tex]
The probability of getting 2 hits is
[tex]P\left(2\:hits\right)=\left(0.7\times 0.5\times 0.7\right)+\left(0.7\times 0.5\times 0.3\right)+\left(0.3\times 0.5\times 0.3\right)=0.395[/tex]
The probability of getting 1 hit is
[tex]P\left(1\:hit\right)=\left(0.7\times 0.5\times 0.7\right)+\left(0.3\times 0.5\times 0.7\right)+\left(0.3\times 0.5\times 0.3\right)=0.395[/tex]
The probability of getting 0 hit is
[tex]P\left(0\:hit\right)=0.3\times 0.5\times 0.7=0.105[/tex]
The expected value is solved by adding the products of the probability by the given pay. That is
[tex]E=0.105\left(6\right)+0.395\left(4\right)+0.395\left(2\right)+0.105\left(4\right)=3.42[/tex]
The expected value is $3.42.
need help i havent done this since 2015 :// lolz
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m∠R = m∠P = 180° -m∠Q
m∠Q = 107°
m∠P = 73°
25. If you draw any diagonal, it divides the figure into two congruent triangles (by the SSS postulate). Corresponding angles are congruent, so the diagonal is a transversal between parallel lines. Thus opposite sides are parallel and the figure is a parallelogram.
27. Opposite sides are equal, and the diagonals bisect each other. Your four equations are
2w+4 = 5w-6 . . . . w = 10/3
12 = 3x-3 . . . . . . . x = 5
6y = 4y+6 . . . . . . . y = 3
27 = (5/4)z +2 . . . z = 20
Answer:
2w+4 = 5w-6 . . . . w = 10/3
12 = 3x-3 . . . . . . . x = 5
6y = 4y+6 . . . . . . . y = 3
27 = (5/4)z +2 . . . z = 20
107 and 73
Point X is the center of regular pentagon RSTUV. What is the measure of the angle of rotation that will map S onto U?
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Final answer:
The measure of the angle of rotation that will map vertex S onto vertex U in a regular pentagon is 72 degrees.
Explanation:
The student is asking about an angle of rotation in a geometric context, specifically concerning mapping one vertex of a regular pentagon onto another through rotation about the center of the shape. In a regular pentagon, the angles between adjacent vertices are all equal, as it is a symmetrical shape. Since there are five vertices in a pentagon, you can divide the full rotation of 360 degrees by the number of vertices to find the angle of rotation that will map one vertex onto the next.
To map vertex S onto vertex U in a regular pentagon, you will need to rotate the pentagon by 360 degrees divided by 5 vertices, which is 72 degrees. Therefore, a rotation of 72 degrees around the center point X of the pentagon will map S onto U.
If a cube with side length 6 inches has its dimensions divided in half, what will be the volume of the new cube?
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Given is the side length of a cube = 6 inches.
It says that the dimensions of this cube are divided into half, so the side length of new cube would be 3 inches.
We know the formula for volume of cube is given as follows :-
Volume of new cube = Side x Side x Side.
Volume of new cube = 3 inches x 3 inches x 3 inches.
Volume of new cube = 27 cubic inches.
Hence, 27 cubic inches is the answer.