Answers
You can put in numbers to find which is the graph
3/2(-2)^2 + 4(-2) - 2 = -4
Now you look for the graphs that have the point (-2, -4)
Only one graph has this which is graph 2
The answer is the second graph
Hope this helps!
Related Questions
Jorge owes his father $60. After raking the lawn for the month, he has paid him $12, $8, and $9. How much money does Jorge still has owes his father?
Answers
60 - 29= 31
Jorge owes his father $31
HELP PLEASE
Determine the missing statements and reasons for the following proof.
Answers
Reason 3: Congruent supplements theorem
Statements:
Statement 4: Angle 1 is congruent with angle 2
Answer: Option D:
Reason 3: Congruent supplements theorem.
Statement 4: Angle 1 is congruent with angle 2
In a mathematical proof, missing statements and reasons are usually concluded from the given statements and the relevant geometric postulates or theorems. They could include establishing the congruency of angles or declaring the parallelism of lines.
Explanation:Without the concrete steps of the proof or the reasoning proposed, it is difficult to provide the exact missing statements and reasons. However, in a general mathematical proof, common reasons used include 'definition of congruent angles', 'definition of parallel lines', 'alternate interior angles theorem', etc.
For instance, if we have a proof that involves stating two angles are congruent, the missing statement might be 'Angle A is congruent to Angle B', and the missing reason could be 'Definition of Congruent Angles' or 'Angle Bisector Theorem', if an angle bisector comes into the picture.
Another missing statement might be 'Segment AB is parallel to Segment CD', with the reason being 'Corresponding Angles Postulate', or 'Alternate Interior Angles Theorem', if the proof involves parallel lines.
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which number correctly completes this equation 3/4%x75= A. 0.255 B. 0.5625 C. 2.55. D. 5.626
Answers
3/4 of a percent is .0075.
0.0075 times 75 = 0.5625
The answer is B) 0.5625.
hat is the sum of the geometric series in which a1 = 3, r = 4, and an = 49,152?
Hint: an = a1(r)n − 1, where a1 is the first term and r is the common ratio.
Sn = −65,535
Sn = 16,383
Sn = 13,120
Sn = 65,535
Answers
To find the sum of the geometric series, we use the formula: Sn = a1 * (r^n - 1) / (r - 1). Substituting the given values and solving, we find that the sum is 16,383.
Explanation:To find the sum of a geometric series, we can use the formula Sn = a1 * (r^n - 1) / (r - 1), where Sn is the sum of the series, a1 is the first term, r is the common ratio, and n is the number of terms.
In this case, a1 = 3, r = 4, and an = 49,152. We can use the formula to find n, which is the exponent.
49,152 = 3 * (4^n - 1) / (4 - 1)
49,152 = 3 * (4^n - 1) / 3
16,384 = 4^n - 1
4^n = 16,385
n = log4(16,385)
n ≈ 7
Now, we can substitute the values into the formula for Sn.
Sn = 3 * (4^7 - 1) / (4 - 1)
Sn = 3 * (16,384 - 1) / 3
Sn = 3 * 16,383 / 3
Sn = 16,383
Therefore, the sum of the geometric series is 16,383. So the correct answer is Sn = 16,383.
The correct answer is [tex]\( S_n = 65,535 \)[/tex].
To find the sum of a geometric series, you can use the formula:
[tex]\[ S_n = a_1 \frac{(r^n - 1)}{r - 1} \][/tex]
Where:
- [tex]\( S_n \)[/tex] is the sum of the series,
- [tex]\( a_1 \)[/tex] is the first term,
- [tex]\( r \)[/tex] is the common ratio,
- [tex]\( n \)[/tex] is the number of terms.
Given [tex]\( a_1 = 3 \), \( r = 4 \), and \( a_n = 49,152 \)[/tex], we need to find [tex]\( n \)[/tex]. The formula for the [tex]\( n^{th} \)[/tex] term in a geometric series is [tex]\( a_n = a_1 \times r^{(n-1)} \)[/tex]. In this case, [tex]\( 49,152 = 3 \times 4^{(n-1)} \)[/tex]
Let's solve for n:
[tex]\[ 4^{(n-1)} = \frac{49,152}{3} \][/tex]
[tex]\[ 4^{(n-1)} = 16,384 \][/tex]
[tex]\[ n-1 = \log_4(16,384) \][/tex]
[tex]\[ n-1 = 7 \][/tex]
[tex]\[ n = 8 \][/tex]
Now that we have [tex]\( n = 8 \)[/tex], we can use it in the sum formula:
[tex]\[ S_n = 3 \frac{(4^8 - 1)}{4 - 1} \][/tex]
[tex]\[ S_n = 3 \frac{(65,536 - 1)}{3} \][/tex]
[tex]\[ S_n = 3 \frac{65,535}{3} \][/tex]
[tex]\[ S_n = 65,535 \][/tex]
Therefore, the correct answer is [tex]\( S_n = 65,535 \)[/tex].
7.
Find the amount of the payment for the sinking fund.
Amount Needed: $58,000
Years Until Needed: 2
Interest Rate: 6%
Interest Compounded: Semiannually
$13,863.74
$8,620.68
$28,155.52
$13,258.22
Answers
Substituting,
SFF = (0.06/2)/{(1+0.06/2)^2*2 -1} = 0.239
PMT = A*SFF = 58,000*0.239 = $13,863.57 ---- The closest answer is $13,863.74
Enrique earns 101010 points for each question that he answers correctly on a geography test. Write an equation for the number of points, yyy Enrique scores on the test when he answers xxx questions correctly.
Answers
[tex]y = 101010 \times x[/tex]
In the question it must be 10 instead of 101010, y instead of yyy and x instead of xxx.
Since, Enrique earns 10 points for each question that he answers correctly on a geography test.
We have to write an equation for the number of points, 'y' Enrique scores on the test when he answers 'x' questions correctly.
So, Number of points scored = Points scored for one question [tex] \times [/tex] Number of questions answered correctly.
So, Number of points scored = [tex] 10 \times x [/tex]
[tex] y=10 \times x [/tex]
y = 10x is the required equation.
A laterally loaded single pile is shown below. use the elastic pile solutions (based on the winkler's model) to calculate the displacement and rotation at pile head ????. assume free headed condition. pile length ???? = 30 ft; young's modulus ???????? = 3 × 10 6 psi; ????ℎ = 30 lb/in3 ; and the eccentricity ???? = 60 in.
Answers
while watching a football game, Lin Chow decided to list yardage agained as positive integers and yardage lost as negative integers. after this plays, Lin recorded 14, -7, and 9. what was the net gain or lost?
Answers
k+1=3k-1 please show me the correct steps to solve this problem
Answers
-2k + 1 = -1 |-1
-2k = -2 |:(-2)
k = 1
If i know a real root of f(x) = x3 -6x2 + 11x – 6 is neither 1, even, or negative, a good guess would be?
Answers
A good guess for the real root of the polynomial [tex]f(x) = x^3 - 6x^2 + 11x - 6[/tex] that is neither 1, even, nor negative, would be a positive odd integer such as 3 or 5, considering the constraints and the Rational Root Theorem.
The real root of the cubic equation [tex]f(x) = x^3 - 6x^2 + 11x - 6[/tex] that is neither 1, even, nor negative would most likely be a positive odd number (since all positive even numbers are, by default, also excluded). Considering the smallest odd numbers greater than 1 are 3 and 5, and given that we're working with integers, a good guess for the real root would be either 3 or 5. However, one can apply the Rational Root Theorem which states that any rational root, expressed in its lowest form p/q, must have p as a factor of the constant term and q as a factor of the leading coefficient. In this case, the possible rational roots could be
divisors of 6 (constant term) over divisors of 1 (leading coefficient), which gives us only divisors of 6 itself
since the leading coefficient is 1. Among those divisors, the ones that fit the criteria of being neither 1, even, nor negative, would be 3 or positive odd integers.
Q#2 Graph the relation in the table.Then use the vertical-line test.Is the relation a function
Answers
x y
-1 3
1 -1
2 2
1 3
We observe that the graph shown in the question shows a scattering of points that do not obey any behavior of known function.
Therefore, the table does not represent any function.
Answer:
The table does not represent a function.
By applying the vertical line test we find that the relation is not a function because there are two points which are (1,-1) , (1,3) have the same value of x with different values of y which contradicts with with the rule of function.
PLZ HELP ASAP WRITE STANDERED EQAUTION OF A CIRCLE
Answers
(x-xo) ^ 2 + (y-yo) ^ 2 = r ^ 2
Where,
(xo, yo): coordinate of the center of the circle
r: radius of the circle.
Substituting values we have:
(x-9.2) ^ 2 + (y + 7.4) ^ 2 = (5/3) ^ 2
Rewriting:
(x-9.2) ^ 2 + (y + 7.4) ^ 2 = 25/9
Answer:
The equation of the circle is:
(x-9.2) ^ 2 + (y + 7.4) ^ 2 = 25/9
C(9.2, -7.4)
r^2 = (x-h)^2 + (y-k)^2
(5/3)^2 = (x - 9.2)^2 + (y + 7.4)^2
The hypotenuse of an isosceles right triangle is 14 sqrt 2. How long is each leg of the triangle?
Answers
Hope this helps!
Answer:
14
Step-by-step explanation:
Let the legs of the triangle each have length $x$ (they are equal because it is an isosceles right triangle). Then
x^2 + x^2 = (14√2)^2 = 14^2 × (√2)^2 = 14^2 × 2, so x^2 = 14^2. Given that x must be positive, we have x = 14. So, the value of each leg is 14
(Hope this helped you!)
Each gallon of shingle stain covers 120 square feet. How many gallons should you buy to cover 658 square feet?
Answers
5.483 gallons bought to cover 658 square feet.
What is Unitary Method?The unitary technique involves first determining the value of a single unit, followed by the value of the necessary number of units.
For example, Let's say Ram spends 36 Rs. for a dozen (12) bananas.
12 bananas will set you back 36 Rs. 1 banana costs 36 x 12 = 3 Rupees.
As a result, one banana costs three rupees. Let's say we need to calculate the price of 15 bananas.
This may be done as follows: 15 bananas cost 3 rupees each; 15 units cost 45 rupees.
Given:
Each gallon of shingle stain covers 120 square feet.
We have to find gallons should be bought to cover 658 square feet.
We have to perform division
= 658/120
= 5.483 gallons
Hence, 5.483 gallons bought to cover 658 square feet.
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Hey can you please help me posted picture of question
Answers
A compound event is one in which there is more than one possible outcome. It is also defined as a probabilistic event with two or more favorable outcomes. For example, when you throw a die (singular for dice), it is called a simple event. On the other hand, when you throw a dice, it is known as a compound event.
K+1=3k-1 what us the answer
Answers
2k = 2
Divide by 2:
k = 1
If you want to check your work:
1 + 1 = 3 - 1
2 = 2
The probability that a student correctly answers on the first try (the event
a.is p(a) = 0.2. if the student answers incorrectly on the first try, the student is allowed a second try to correctly answer the question (the event b). the probability that the student answers correctly on the second try given that he answered incorrectly on the first try is 0.5. find the probability that the student answers the question on the first or second try.
a.0.90
b.0.40
c.0.10
d.0.70
e.0.60
Answers
We're given that [tex]P(A)=0.2[/tex] and [tex]P(B\mid A^C)=0.5[/tex]. From the first probability, we know that [tex]P(A^C)=1-0.2=0.8[/tex]. By definition of conditional probability,
[tex]\mathbb P(B\mid A^C)=\dfrac{\mathbb P(B\cap A^C)}{\mathbb P(A^C)}[/tex]
[tex]\implies\mathbb P(B\cap A^C)=0.5\cdot0.8=0.4[/tex]
We're interested in the probability of either [tex]A[/tex] or [tex]B[/tex] occurring, i.e. [tex]\mathbb P(A\cup B)[/tex]. Apply the inclusion-exclusion principle, which says
[tex]\mathbb P(A\cup B)=\mathbb P(A)+\mathbb P(B)-\mathbb P(A\cap B)[/tex]
We know the probability of intersection is 0, and we know [tex]\mathbb P(A)[/tex]. Meanwhile, by the law of total probability, we have
[tex]\mathbb P(B)=\mathbb P(B\cap A)+\mathbb P(B\cap A^C)=\mathbb P(B\cap A^C)[/tex]
so we end up with
[tex]\mathbb P(A\cup B)=0.2+0.4=0.6[/tex]
The probability that the student answers the question on the first or second try is 0.60.
Given
P(A) = 0.2
[tex]\rm P(B|A^c)=0.5[/tex].
What is conditional probability?The conditional probability of an event is when the probability of one event depends on the probability of occurrence of the other event.
When two events are mutually exclusive.
Then,
[tex]\rm P(A\cap B)=0[/tex]
The first probability is;
[tex]\rm P(A^C)=1-0.2=0.8[/tex]
Therefore,
The probability that the student answers the question on the first or second try is;
[tex]\rm P(A\cup B)= P(A) +P(B)-P(A \cap B)\\\\ P(A\cup B)= P(A) +P(B|A^C) \times P(A^C)-P(A \cap B)\\\\ P(A\cup B)= 0.2+0.5 \times 0.8 -0\\\\P(A\cup B)=0.2+0.40\\\\ P(A\cup B)=0.60[/tex]
Hence, the probability that the student answers the question on the first or second try is 0.60.
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A car rental costs $50 for the first day. Additional days cost $35 per day, unless the car is rented for 7 days or more, in which case there is a 10% discount on the daily rate. Identify the expression which represents the cost of renting a car if the car has been rented for more than a week.
A.) 45+35x
B.) 45+31.5x
C.) 50+35x
D.) 50+31.5x
Answers
Answer:
Option D [tex]\$50+\$31.5x[/tex]
Step-by-step explanation:
Let
x------> the number of days
y----> the cost of renting a car
we know that
For [tex]x<7\ days[/tex]
[tex]y=\$50+\$35x[/tex]
For [tex]x\geq 7\ days[/tex]
The rate is equal to
[tex]0.90*\$35=\$31.5[/tex]
so
[tex]y=\$50+\$31.5x[/tex]
In this problem. the car has been rented for more than a week
therefore
[tex]x> 7\ days[/tex]
The cost of renting a car is equal to
[tex]y=\$50+\$31.5x[/tex]
What is the domain of the function g(x) = 52x? x > 0 x < 0 all real numbers all positive real numbers
Answers
The domain: all real numbers.
Answer: all real numbers
Step-by-step explanation:
The given function is : [tex]g(x) = 52x[/tex], which is polynomial function with degree one.
The domain of a function is the set of all values for x for which the function must be defined.We know that the domain of a polynomial is the entire set of real numbers because for any real number r the polynomial function exists.
Therefore, the domain of the given function [tex]g(x) = 52x[/tex] is the set of real numbers.
A, B, C, and D have the coordinates (-8, 1), (-2, 4), (-3, -1), and (-6, 5), respectively. Which sentence about the points is true?
A, B, C, and D lie on the same line.
AB and CD are perpendicular lines.
AB and CD are parallel lines.
AB and CD are intersecting lines but are not perpendicular.
AC and BD are parallel lines.
Answers
We observe that the slopes of both lines are different (they are not reciprocal opposites).
Therefore, the lines are not perpendicular.
Answer:
AB and CD are intersecting lines but are not perpendicular.
See attached image.
Answer:
AB and CD are intersecting lines but are not perpendicular.
See attached image.
Step-by-step explanation:
What is the probability of rolling an even number or a prime number on a number cube? Write as a fraction in simplest form.
Answers
Final answer:
The probability of rolling an even number or a prime number on a six-sided die is 5/6, considering the unique favorable outcomes of 2, 3, 4, 5, and 6 against the total possible outcomes.
Explanation:
The question asks, "What is the probability of rolling an even number or a prime number on a number cube?" To answer this, first identify the outcomes on a six-sided die which are even and those that are prime.
Even numbers on a die: 2, 4, 6. Prime numbers on a die: 2, 3, 5. Notice that 2 is both even and prime, and it only needs to be counted once. Therefore, the unique favorable outcomes are 2, 3, 4, 5, 6.
The die has a total of 6 sides, making the total number of possible outcomes 6. The probability of rolling an even number or a prime number is therefore the number of favorable outcomes (5) divided by the total number of outcomes (6), which simplifies to 5/6.
Solve for y.
a.10
b.12
c.15
d.18
Answers
Angle ABD=90°
3x°=90°
3x=90
Solving for x:
3x/3=90/3
x=30
Angle CBD=90°
(2x+3y)°=90°
2x+3y=90
x=30
2(30)+3y=90
60+3y=90
Solving for y:
60+3y-60=90-60
3y=30
3y/3=30/3
y=10
Answer: Option a. 10
The sum of the squares of two numbers is 18. the product of the two numbers is 9. find the numbers.
Answers
Answer:
x=3 y=3
Step-by-step explanation:
The sum of the squares of two numbers is 18, and the product of those two numbers is 9, you just need to create an equation:
So the sum of the squares is 18, the first number will be represented as X and the second as Y:
[tex]x^{2}+ y^{2} =18[/tex]
And the other one is that the product of the two numbers is 9:
[tex]xy=9[/tex]
We have a system of equations here, we clear X from the first one:
[tex]x=\frac{9}{y}[/tex]
And instert that value of x in the first one:
[tex]x^{2}+ y^{2} =18\\(\frac{9}{y} )^{2}+ y^{2} =18\\81=y^2(18-y^2)\\y^4-18y^2+81=0\\(y^2-9)(y^2-9)=0\\Y^2-9=0\\y^2=9\\y=3[/tex]
By solving this equation we get that the first number is 3.
The second number is solved by inserting the value of Y into one of the equations, in this case we will use the second:
[tex]xy=9\\x=\frac{9}{y} \\x=\frac{9}{3} \\x=3[/tex]
So we get that x and y are both 3.
Hey can you please help me posted picture of question
Answers
Of the six faces numbered 1 to 6, there is only one five. The probability therefore of rolling a die and getting a five is equal to 1/6. This approach is the theoretical. Hence, the answer to this item is the first option, A Theoretical.
So basically if you think about it the answer is Empirical.
Conduct a chi-squared test of independence on the data presented in data set
d. assume equal probabilities of fe for each cell and make sure to report all relevant statistics, including the value of χ2 obtained, the critical value and your decision as to whether to reject the null hypothesis .
Answers
Ples help me find slant assemtotes
this one is different because it isn't a rational function
find the slant assemtotes of [tex](y+1)^2=4xy[/tex]
the equation can be rewritten using the quadratic formula as [tex]y=2x-1 \pm \sqrt{x^2-x}[/tex]
ples find slant assemtotes and show all work
thx
Answers
[tex]\displaystyle\lim_{x\to\pm\infty}(f(x)-p(x))=0[/tex]
[tex](y+1)^2=4xy\implies y(x)=2x-1\pm2\sqrt{x^2-x}[/tex]
Since this equation defines a hyperbola, we expect the asymptotes to be lines of the form [tex]p(x)=ax+b[/tex].
Ignore the negative root (we don't need it). If [tex]y=2x-1+2\sqrt{x^2-x}[/tex], then we want to find constants [tex]a,b[/tex] such that
[tex]\displaystyle\lim_{x\to\infty}(2x-1+2\sqrt{x^2-x}-ax-b)=0[/tex]
We have
[tex]\sqrt{x^2-x}=\sqrt{x^2}\sqrt{1-\dfrac1x}[/tex]
[tex]\sqrt{x^2-x}=|x|\sqrt{1-\dfrac1x}[/tex]
[tex]\sqrt{x^2-x}=x\sqrt{1-\dfrac1x}[/tex]
since [tex]x\to\infty[/tex] forces us to have [tex]x>0[/tex]. And as [tex]x\to\infty[/tex], the [tex]\dfrac1x[/tex] term is "negligible", so really [tex]\sqrt{x^2-x}\approx x[/tex]. We can then treat the limand like
[tex]2x-1+2x-ax-b=(4-a)x-(b+1)[/tex]
which tells us that we would choose [tex]a=4[/tex]. You might be tempted to think [tex]b=-1[/tex], but that won't be right, and that has to do with how we wrote off the "negligible" term. To find the actual value of [tex]b[/tex], we have to solve for it in the following limit.
[tex]\displaystyle\lim_{x\to\infty}(2x-1+2\sqrt{x^2-x}-4x-b)=0[/tex]
[tex]\displaystyle\lim_{x\to\infty}(\sqrt{x^2-x}-x)=\frac{b+1}2[/tex]
We write
[tex](\sqrt{x^2-x}-x)\cdot\dfrac{\sqrt{x^2-x}+x}{\sqrt{x^2-x}+x}=\dfrac{(x^2-x)-x^2}{\sqrt{x^2-x}+x}=-\dfrac x{x\sqrt{1-\frac1x}+x}=-\dfrac1{\sqrt{1-\frac1x}+1}[/tex]
Now as [tex]x\to\infty[/tex], we see this expression approaching [tex]-\dfrac12[/tex], so that
[tex]-\dfrac12=\dfrac{b+1}2\implies b=-2[/tex]
So one asymptote of the hyperbola is the line [tex]y=4x-2[/tex].
The other asymptote is obtained similarly by examining the limit as [tex]x\to-\infty[/tex].
[tex]\displaystyle\lim_{x\to-\infty}(2x-1+2\sqrt{x^2-x}-ax-b)=0[/tex]
[tex]\displaystyle\lim_{x\to-\infty}(2x-2x\sqrt{1-\frac1x}-ax-(b+1))=0[/tex]
Reduce the "negligible" term to get
[tex]\displaystyle\lim_{x\to-\infty}(-ax-(b+1))=0[/tex]
Now we take [tex]a=0[/tex], and again we're careful to not pick [tex]b=-1[/tex].
[tex]\displaystyle\lim_{x\to-\infty}(2x-1+2\sqrt{x^2-x}-b)=0[/tex]
[tex]\displaystyle\lim_{x\to-\infty}(x+\sqrt{x^2-x})=\frac{b+1}2[/tex]
[tex](x+\sqrt{x^2-x})\cdot\dfrac{x-\sqrt{x^2-x}}{x-\sqrt{x^2-x}}=\dfrac{x^2-(x^2-x)}{x-\sqrt{x^2-x}}=\dfrac x{x-(-x)\sqrt{1-\frac1x}}=\dfrac1{1+\sqrt{1-\frac1x}}[/tex]
This time the limit is [tex]\dfrac12[/tex], so
[tex]\dfrac12=\dfrac{b+1}2\implies b=0[/tex]
which means the other asymptote is the line [tex]y=0[/tex].
which means the other asymptote is the line .
a coin is tossed , then a number 1-10 is chosen at random.what is the probability of getting heads then a number less than 4?
Answers
The probability of tossing a coin and getting heads is 50%, or 0.5, and the probability of selecting a number less than four from 1-10 is 40%, or 0.4.
The overall probability can then be expressed as:
0.5 x 0.4 = 0.2 or 20%
There is a twenty percent chance that a heads would be tossed and a number less than four selected.
Together, two people earn $28,000. One earns $2,000 more than the other. How much is the smaller income?
$30k
$26k
$14k
$13k
Answers
2x+$2,000=$28,000
2x=$28,000-$2,000
2x=$26,000
x=26,000 divided by 2
x=$13,000
P1+2= P2 . -------Equation 2 . I abbreviate the thousands of $
Using substitution
P1+(P1+2)=28
2P1 +2=28
P1=13
then substitute into equation 2 we get
13+2=p2
P2=15
Therefore one is $15,000
and the other is 13,000
Smaller is 13,000!!!
If ∆XYZ = ∆KLM, then < Y = Please help due today
Answers
∠X = ∠K
∠Y = ∠L
∠Z = ∠M
So ∠Y = ∠L
I hope this helps!
Josiah has 3 packs of toy animals. Each pack has the same number of animals. Josiah gives 6 animals to his sister stephanie. Then josiah has 9 animals left.how many animals were in each pack?
Answers
Total number of animals will be 3x
after Josiah gave 6 animals to his sister the remaining animals were:
3x-6=9
thus sloving for x we have:
3x-6=9
add 6 on both sides
3x-6+6=9+6
3x=15
divide both sides by 3
(3x)/3=15/3
x=5
Answer:
There were 5 animals in each pack