They next ring together will be at 6:50 a.m.
Step-by-step explanation:
The given is:
Two bells ring every 10 and 25 minutes respectivelyThey start ringing together at 6 a.m.We need to know at what time will they next ring together
To solve the problem lets find the lowest common multiple of 10 and 25
∵ The multiples of 10 are 10 , 20 , 30 , 40 , 50 , 60 , 70 , 80 , 90 , 100 , .....
∵ The multiples of 25 are 25 , 50 , 75 , 100 , ........
∵ The common multiples of 10 and 25 are 50 , 100 , ......
∴ The lowest common multiple of 10 and 25 is 50
∵ The two bells start ringing together at 6 a.m.
∵ The first bell rings every 10 minutes
∴ The first bell rings at 6:10 a.m. , 6:20 a.m. , 6:30 a.m. , 6:40 a.m. ,
6:50 a.m. , .........
∵ The second bell rings every 25 minutes
∴ The second bell rings at 6:25 a.m. , 6:50 a.m. , ........
∴ They start ringing together at 6:50 a.m.
They next ring together will be at 6:50 a.m.
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Final answer:
To determine when two bells will next ring together, find the Least Common Multiple (LCM) of their ringing intervals. The LCM of 10 and 25 is 50, therefore the bells will next ring together at 6:50 a.m.
Explanation:
The question is about finding the next time two bells, ringing at different intervals, will ring together. To solve this, we need to find the Least Common Multiple (LCM) of the two bell ringing intervals: 10 minutes and 25 minutes. The LCM of 10 and 25 is 50 since 10 × 5 = 50 and 25 × 2 = 50. Since the bells start ringing together at 6 a.m., they will next ring together 50 minutes later.
Adding 50 minutes to 6 a.m., we get 6:50 a.m. Therefore, the two bells will next ring together at 6:50 a.m.
A section of the dining room has 3 tables with 6 chairs at each table determine which expressions represent the situation and which do not
(3)-(6)
3x6
(3)(6)
3/6
3+6
6+6+6
Represent the situation or do not represent the situation
Do:
3x6
(3)(6)
6+6+6
Do not:
(3)-(6)
3/6
3+6
When Maggie hooks her dog up to a rope that is staked in the yard, the dog can walk a distance of about 76 feet along the circumference. To the nearest tenth, what is the length of the rope?
C = 76 ft
Choices
12.1 ft
24.2 ft
12.7 ft
8.1 ft
Answer:
12.1
Step-by-step explanation:
76/2π
= 38/π
= 12
Answer: 12.1 ft
Step-by-step explanation:
Hi, to answer this we have to apply the circumference formula:
C= 2πr
Where:
C = circumference ( in this case is 76, since the dog can walk a distance of about 76 feet along the circumference.)
r = radius. (In this case the radius is the length of the rope, because the stake is in the center of the circumference)
Replacing with the values given and solving for "r":
76 = 2πr
76 /( 2π)= 12.0957= 12.1 ft
What's 4 3×7 + 2 1×3
Answer: 90
Step-by-step explanation: You equation is 4(3*7) + 2(1*3). To solve this, you first solve what is on the inside of the parenthesis. so 3 times 7 is 21. And 1 times 3 is 3. So now your equation looks like this 4(21) + 2(3). 4 times 21 is 84 and 2 times 3 is 6. So now your equation is 84 + 6 which equals 90.
Answer:
90
Step-by-step explanation:
4(3*7)+2(1*3)=4(21)+2(3)=84+6=90
Factor the expression completely: x^3−27y^3
The cost of 5 squash and 2 zucchini is $1.32. Three squash and 1 zucchini cost $0.75. Find the cost of each vegetable.
Final answer:
By solving a system of equations, we find that the cost of one squash is $0.18 and the cost of one zucchini is $0.21.
Explanation:
The question involves solving a system of linear equations to determine the cost of each vegetable. Let's define x as the cost of one squash and y as the cost of one zucchini. We have the two equations based on the information provided:
5x + 2y = $1.323x + y = $0.75We can solve this system using either substitution or elimination methods. For this example, I'll use the substitution method:
Solve the second equation for y: y = $0.75 - 3x.Substitute the expression for y in the first equation: 5x + 2($0.75 - 3x) = $1.32.Simplify and solve for x: 5x + $1.50 - 6x = $1.32, which simplifies to x = $1.50 - $1.32, so x = $0.18.Substitute x back into the equation for y: y = $0.75 - 3($0.18), so y = $0.75 - $0.54, thus y = $0.21.Therefore, the cost of one squash is $0.18 and the cost of one zucchini is $0.21.
Final answer:
To find the cost of each vegetable, a system of linear equations was set up and solved, revealing the cost of one squash to be $0.18 and the cost of one zucchini to be $0.21.
Explanation:
The cost of 5 squash and 2 zucchini is $1.32, and the cost of 3 squash and 1 zucchini is $0.75. To find the cost of each vegetable, we can set up a system of linear equations and solve for the unknowns.
Let 's' represent the cost of one squash and 'z' represent the cost of one zucchini. We can then create two equations based on the information given:
5s + 2z = $1.32
3s + 1z = $0.75
Now, we need to solve this system of equations. An effective way to do this would be using the substitution or elimination method. For simplicity, let's use the elimination method:
Multiply the second equation by 2 to align the coefficients of z:
6s + 2z = $1.50
Now subtract the modified second equation from the first:
(5s + 2z) - (6s + 2z) = $1.32 - $1.50
-s = -$0.18
s = $0.18
With the cost of one squash known, substitute 's' back into one of the original equations to find 'z':
3(0.18) + z = $0.75
0.54 + z = $0.75
z = $0.75 - $0.54
z = $0.21
So, one squash costs $0.18, and one zucchini costs $0.21.
In TVW if VW is three meters longer than TV, TW is 20 meters shorter than the sum of VW and TV, and the perimeter of TVW is 74 meters, find the length of VW.
PLEASE EXPLAIN STEPS!!!
Answer:
The length of VW is [tex]25\ m[/tex]
Step-by-step explanation:
we know that
The perimeter of triangle TVW is equal to
[tex]P=VW+TV+TW[/tex]
we have
[tex]P=74\ m[/tex]
so
[tex]74=VW+TV+TW[/tex] -----> equation A
[tex]VW=TV+3[/tex] ----> equation B
[tex]TW=(VW+TV)-20[/tex] ----> equation C
substitute equation B in equation C
[tex]TW=(TV+3+TV)-20[/tex]
[tex]TW=2TV-17[/tex] ----> equation D
substitute equation B and equation D in equation A
[tex]74=(TV+3)+TV+(2TV-17)[/tex]
solve for TV
[tex]74=4TV-14[/tex]
[tex]4TV=74+14[/tex]
[tex]4TV=88[/tex]
[tex]TV=22\ m[/tex]
Find the value of VW
[tex]VW=TV+3[/tex] -----> [tex]VW=22+3=25\ m[/tex]
Find the value of TW
[tex]TW=2TV-17[/tex] -----> [tex]TW=2(22)-17=27\ m[/tex]
Whose class would you rather be in, if each teacher has different grading schemes?
Mr. Winking’s Grade Weights
Homework Average
10%
Quiz Average
25%
Test Average
45%
Final Exam Grade
20%
Ms. Sand’s Grade Weights
Homework Average
15%
Quiz Average
20%
Test Average
40%
Final Exam Grade
25%
Your Grade Report:
Homework Average: 95%
Quiz Average: 85%
Test Average: 87%
Final Exam Grade: 90%
Step 1: Find your final average for Mr. Winking’s Class (10 points)
Step 2: Find your final average for Ms. Sand’s Class. (10 points)
Step 3: Determine which class you would rather be in. Write in complete sentences. Use your answers from steps 1 and step 2 to justify your answer. (10 points)
Answer:
Mr. Winking 87.9%
Ms. Sand 88.55%
Ms. Sand's class is better
Step-by-step explanation:
Step 1: Average in Mr. Winking's Class 87.9%
Convert each weight factor to a decimal.
Homework 10% = 0.1
Quiz 25% = 0.25
Test 45% = 0.45
Exam 20% = 0.2
Multiply your grades by the weight factors:
Homework 0.1 X 95% = 9.5%
Quiz 0.25 X 85% = 21.25%
Test 0.45 X 87% = 39.15%
Exam 0.2 X 90% = 18%
Add all of these values:
9.5% + 21.25% + 39.15% + 18%
= 87.9%
Step 2: Average in Ms. Sand’s Class 88.55%
Convert each weight factor to a decimal.
Homework 15% = 0.15
Quiz 20% = 0.2
Test 40% = 0.4
Exam 25% = 0.25
Multiply the weight factors by your grades:
Homework 0.15 X 95% = 14.25
Quiz 0.2 X 85% = 17
Test 0.4 X 87% = 34.8
Exam 0.25 X 90% = 22.5
All all these values:
14.25 + 17 + 34.8 + 22.5
= 88.55%
Step 3:
I would rather be in Ms. Sand's class. My average in her class would be 88.55%, whereas in Mr.Winking's Class, my average would be 87.9%. 88.55% is a higher mark than 87.9% and I want higher marks. Therefore, I would get higher marks in Ms. Sand's class.
-8(4+4n)=8(n+6)
what is the answer for this? please thank you :)
Answer:
n = -2
Step-by-step explanation:
Distribute first.
-32 - 32n = 8n + 48
Subtract 8n.
-32 - 40n = 48
Add 32
-40n = 80
n = -2
Answer: download Photomath is the best!! The answer is n=-2
Step-by-step explanation:
Put in simplest fraction form:
3,628,800/55
Section #1: Solvi
1) Find the solution to each equation.
A) 4(2x - 1) = -3x + 32
Section
1) Find the solution to each equation.
A) 4(2x - 1) = -3x + 32
Answer:The solution to the equation 4(2x - 1) = -3x + 32 is x = 3.273
Solution:Need to find the solution of following equation
4(2x - 1) = -3x + 32
Let use BODMAS rule to solve the expression
According to Bodmas rule, if an expression contains brackets ((), {}, []) we have to first solve or simplify the bracket followed by of (powers and roots etc.), then division, multiplication, addition and subtraction from left to right.
On opening the bracket of left hand side we get
[tex]4 \times 2x-4 \times 1=-3 x+32[/tex]
Now perform multiplication,
8x – 4 = -3x + 32
On bringing terms having variable x in left hand side and constant term on right hand side we get
8x + 3x = 32 + 4
=> 11x = 36
On dividing both sides by 11, we get
[tex]\begin{array}{l}{\Rightarrow \frac{11 x}{11}=\frac{36}{11}} \\\\ {\Rightarrow x=\frac{36}{11}=3.273}\end{array}[/tex]
Hence solution of equation 4(2x - 1) = -3x + 32 is 3.273
(-511) + (+709) = solve.
Answer:
198
Step-by-step explanation:
-511 + (+709) =
709 - 511 = 198
Answer:
-511 + 709 = 198
Step-by-step explanation:
-511+709 is the same as 709-511
Juan is a software salesman. His base salary is $2300, and he makes an additional $90 for every copy of Math is Fun he sells.
Let P represent his total pay (in dollars), and let N represent the number of coples of Math is Fun he sells. Write an equation relating P to N. Then use this
equation to find his total pay if he sells 21 coples of Math is Fun.
Equation:
8 O=D
xs ?
Total pay if Juan sells 21 coples: s]
How do I get the answer
The equation to represent Juan's pay is P = 2300 + 90N. If he sells 21 copies of the book, his total pay would be $4190.
Explanation:Pay Calculation
Given that Juan's base salary is $2300 and he makes an additional $90 for every copy of Math is Fun he sells, we can write an equation relating P (total pay) to N (number of sales) by adding together his base pay and his earnings from selling the books. This can be written as P = 2300 + 90N. We can then use this equation to calculate Juan's total pay if he sells 21 copies of the Math is Fun book. By substituting N = 21 into our equation, we get P = 2300 + 90*21, which simplifies to P = 2300 + 1890 = $4190. So, if Juan sells 21 copies of Math is Fun, his total pay would be $4190.
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Two pipes are connected to the same tank. When working together., they can fill the tank in 10hrs. The larger pipe, working alone, can fill the tank in 15 hrs less time than the smaller one. How long would the smaller one take, working alone, to fill the tank
Answer:
30 hours
Step-by-step explanation:
Let the small pipe take time "t" to fill up the tank alone
Since larger pipe takes 15 HOURS LESS, so it will take "t - 15" time to fill up the tank alone
Let the whole tank be equal to "1" and each pipe fills up a fraction of the tank.
Smaller Pipe fills up 10/t, and
Larger Pipe fills up 10/(t-15)
Totalling "1". So we can write:
[tex]\frac{10}{t}+\frac{10}{t-15}=1[/tex]
Now, we solve for t. First, we multiply whole equation by (t)(t-15), to get:
[tex]t(t-15)*[\frac{10}{t}+\frac{10}{t-15}=1]\\(t-15)(10)+10t=t(t-15)[/tex]
Now we multiply out and get a quadratic and solve by factoring. Shown below:
[tex](t-15)(10)+10t=t(t-15)\\10t-150+10t=t^2-15t\\20t-150=t^2-15t\\t^2-35t+150=0\\(t-30)(t-5)=0\\t=5,30[/tex]
Since, this time is for the smaller pipe (which takes longer than 15 hours), so we disregard t = 5 and take t = 30 as our solution. So,
Smaller pipe takes 30 hours to fill up the tank alone
The smaller pipe takes 30 hours to fill the tank on its own, determined by solving the equation derived from the combined and individual rates at which each pipe fills the tank.
Since they can jointly fill the tank in 10 hours, we can use the rates at which they fill the tank to set up the equation: 1/x + 1/(x - 15) = 1/10. To find the solution, we multiply each term by 10x(x - 15) to clear the denominators, which gives us 10(x - 15) + 10x = x(x - 15). This simplifies to 20x - 150 = x^2 - 15x. Rearranging the terms yields x^2 - 35x + 150 = 0, which can be factored into (x - 30)(x - 5) = 0. Thus, x could be either 30 hours or 5 hours. Since x - 15 must also be positive, x = 30 hours is the correct solution, meaning the smaller pipe takes 30 hours to fill the tank alone.
simplify 5(6x+9) using the distributive property
Answer:
30x+45
Step-by-step explanation:
5*6x=30x
5*9=45
Answer:
30x + 45
Step-by-step explanation:
We distribute the 5 to the variable 6x and the constant 9:
5(6x+9)
5 x 6x = 30x
5 x 9 = 45
The answer is 30x + 45
How do you solve : through: (1, -3) and (-5,0)?
Answer:
-1/2
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(0-(-3))/(-5-1)
m=(0+3)/(-6)
m=3/-6
simplify
m=-1/2
What’s the slope of (-2,1) and (3,-3)
Answer:
-4/5
Step-by-step explanation:
slope = m = (difference in y)/(difference in x) = (-3 - 1)/(3 - (-2)) =-4/5
Amy has 20 quarters.sodas cost $.75 write an expression for how many quarters Amy has left after buying D amount of sodas
The expression x=20-3D will present the amount Amy has left after buying D sodas.
Step-by-step explanation:
Given,
Total amount = 20 quarters
Cost of sodas = $0.75 = 0.75*100 = 75 cents
25 cents = 1 quarter
1 cent = [tex]\frac{1}{25}\ quarter[/tex]
75 cents = [tex]\frac{1}{25}*75[/tex] = 3 quarters
Amount of D sodas = 3D
Let x be the amount left with Amy.
Amount left = total amount - Amount of D sodas
[tex]x=20-3D[/tex]
The expression x=20-3D will present the amount Amy has left after buying D sodas.
Keywords: fractions, subtraction
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A boat goes 50 km downstream in the same time that it takes to go 30 km upstream. The speed of the stream is 3km/hour. Find the speed of the boat in still water.
Answer:
12 km/h
Step-by-step explanation:
Given: Distance covered by boat downstream = 50 km
Distance covered by boat upstream = 30 km
Time taken by boat in down stream and upstream are equal.
Speed of the stream = 3 km/h
Let x be the speed of boat in still water.
∴ Speed of boat in downstream [tex](s_1)[/tex] = [tex](x+3)\ km/h[/tex]
Speed of boat in upstream [tex](s_2)[/tex] = [tex](x-3)\ km/h[/tex]
As we know, [tex]Time = \frac{Distance}{speed}[/tex]
And time remain same for both upstream and downstream
∴ [tex]\frac{50}{(x+3)} = \frac{30}{(x-3)}[/tex]
Now, cross multiply both side
⇒ [tex]50\times (x-3) = 30\times (x+3)[/tex]
⇒ [tex]50x-30x = 150+90[/tex]
∴ [tex]x= 12\ km/h[/tex]
∴ Speed of boat in still water is 12 km/h
(2x^3+6x-1)+(3x^2-7x)
For this case we must simplify the following expression:
[tex](2x ^ 3 + 6x-1) + (3x ^ 2-7x)[/tex]
We eliminate the parentheses taking into account that:
[tex]+ * + = +\\+ * - = -[/tex]
So, we have:
[tex]2x ^ 3 + 6x-1 + 3x ^ 2-7x =[/tex]
We add similar terms taking into account that:
Different signs are subtracted and the sign of the major is placed:
[tex]2x ^ 3 + 3x^2-x-1[/tex]
Answer:
[tex]2x ^ 3 + 3x^2-x-1[/tex]
A graph with a line running through coordinates (0,0) and coordinates (30,24)
Item 3
Carl's new car gets 27 miles per gallon. What is the equation that represents y, the total miles driven on x gallons of gas?
a. x = 27y
b. y = 27x
c. y = 27 + x
d. x = 27 + y
Answer:
b. y = 27x
Step-by-step explanation:
When you talk about "per" it means multiplication, and 27 is being multiplied by (x) gallons of gas.
what does 500+38+2538+48 equal
please help before 2pm :/ THANKSSSS
Answer:
C = [tex]$ \frac{1}{10} $[/tex]
D = [tex]$ \frac{1}{10^2} $[/tex]
Step-by-step explanation:
78.09 = 7 [tex]$ \times A + 8 \times B + 0 \times C + 9 \times D $[/tex]
78.09 = 7 [tex]$ \times 10^1 + 8 \times 10^0 + 0 \times \frac{1}{10} + 9 \times \frac{1}{10^2}[/tex]
⇒ C = [tex]$ \frac{1}{10} $[/tex]
D = [tex]$ \frac{1}{10^2} $[/tex]
Hence, the answer.
to find the product 3 3/8 * 4 1/9.tara rewrote 3 3/8 as 17/8 amd 4 1/9 as 13/9. she multiplies the fractions to find the product 221/72. what error did she make
Answer:
The error Tara made is she rewrote incorrectly 3 3/8 as 17/8 and 4 1/9 as 13/9,
the corrected number can be rewrote as 3 3/8 as 27/8 and 4 1/9 as 37/9.
Step-by-step explanation:
To find the Product of:
[tex]3\frac{3}{8}\times 4\frac{1}{9}[/tex]
The Number can be rewrote as,
[tex]\frac{3\times8+3}{8}\times \frac{4\times9+1}{9}\\\\\frac{24+3}{8}\times \frac{36+1}{9}\\\\\frac{27}{8}\times \frac{37}{9}[/tex]
Tara made error here she rewrote the number incorrectly 3 3/8 as 17/8 amd 4 1/9 as 13/9.
Now multiplying the fraction we get
[tex]\frac{999}{72}[/tex]
Because she rewrote incorrectly which led her answer to multiplication of fraction, the product too was incorrect which she wrote as 221/72.
Write an expression for the area of a square with a side length of 4a squared. Simplify the expression.
Answer:
16a^4
Step-by-step explanation:
You do 4a^2*4a^2= 16a^4 because area of square is length times width and we know that that length and width in a square is equal.
4*4= 16
a^2*a^2= a^4 (because when you multiply powers with the same base like a in this case, you add the powers up. So in this example it would be 2+2= 4)
Put them together to give you 16a^4
Final answer:
The area of a square with a side length of 4a² is A = 16a⁴, showcasing the area's proportionality to the fourth power of side length a.
Explanation:
The expression for the area of a square with a side length of 4a squared is found by squaring the side length. Since the side of the square is 4a², the area A is given by:
A = (4a²) × (4a²) = 16a⁴
The simplified expression for the area is 16a to the fourth power, which indicates that the area is proportional to the fourth power of the side length a.
Help!!!! Plssss!!! ASAP
Answer:
The y-intercept is (0,-26)
Step-by-step explanation:
Given two points P(a,b) and Q(c,d), the line that passes for both points can be found with the expression
[tex]\displaystyle y-b=\frac{d-b}{c-a}(x-a)[/tex]
We'll take the first two points P(34,-52) and Q(51,-65) to find
[tex]y=-\frac{13}{17}(x-34)-52\\ \\y=-\frac{13}{17}x-26[/tex]
Let's verify if the third point is on the line:
[tex]y=-\frac{13}{17}68-26=-52-26=-78[/tex]
It belongs to the line. To find the y-intercept of the line, we set x to 0
[tex]y=-\frac{13}{17}(0)-26=-26[/tex]
The y-intercept is (0,-26)
What are the coordinates of 2x-4y=6 and 3x+y=-5 ?
Answer:
The coordinates are x = -1 and y = -2.
Step-by-step explanation:
Given:
Equations are 2x-4y=6 and 3x+y=-5.
Now, to find the coordinates.
[tex]2x-4y=6[/tex]...........(1)
[tex]3x+y=-5[/tex]...........(2)
So, first we solve the equation 1 to get the value of [tex]x[/tex].
[tex]2x-4y=6[/tex]
Subtracting both sides by [tex]-4y[/tex] we get:
[tex]2x=6+4y[/tex]
Dividing both sides by 2 we get:
[tex]x=3+2y[/tex]
Now, we put the value of [tex]x[/tex] in equation 2 to get [tex]y[/tex].
[tex]3x+y=-5[/tex]
[tex]3(3+2y)+y=-5[/tex]
[tex]9+6y+y=-5[/tex]
[tex]9+7y=-5[/tex]
On solving the whole equation we get :
[tex]y=-2[/tex]
And, now putting the value of [tex]y[/tex] in equation (1) we get [tex]x[/tex]:
[tex]2x-4y=6[/tex]
[tex]2x-4(-2)=6[/tex]
[tex]2x+8=6[/tex]
[tex]2x=6-8[/tex]
[tex]2x=-2[/tex]
on solving we get:
[tex]x=-1[/tex]
Therefore, the coordinates are x=-1 and y=-2.
Simplify this expression and write the result using positive exponents only
Answer:
[tex]\displaystyle 5b^{-4}[/tex]
Step-by-step explanation:
[tex]\displaystyle 5b^{-4} = (-5a^4b^{-7})(-a^{-4}b^3) \\ \\ \frac{5}{b^4} = 5b^{-4}[/tex]
According to the Negative Exponential Rule [part II], you bring the denominator to the numerator WHILE ALTERING THE INTEGER SYMBOL FROM POSITIVE TO NEGATIVE:
[tex]\displaystyle b^{-n} = \frac{1}{b^n}[/tex]
I am joyous to assist you anytime.
There are 1125 members in a mountaineering club. The club's secretary surveys 72 randomly selected members and finds that 63 members are in favor of holding a used-gear sale. About how many of the club members would be in favor of holding a used-gear sale?
63
72
984
1053
984 members of club would be in favor of used-gear sale based on results of survey.
Step-by-step explanation:
Number of people surveyed = 72
People in favor of sale = 63
Percentage of people in favor = [tex]\frac{People\ in\ favor\ of\ sale}{No.\ of\ people\ surveyed}*100[/tex]
Percentage of people in favor = [tex]\frac{63}{72}*100 = \frac{6300}{72}\\[/tex]
Percentage of people in favor = 87.5%
It means that 87.5% members of club will be in favor of sale.
Total members of club = 1125
Total members in favor = 87.5% of total members
[tex]Total\ members\ in\ favor=\frac{87.5}{100}*1125 = \frac{98437.5}{100}\\Total\ members\ in\ favor=984.3[/tex]
Rounding off to nearest whole number
Total members in favor = 984
984 members of club would be in favor of used-gear sale based on results of survey.
Keywords: percentage, division
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A manufacturing plant earned $80 per man-hour of labor when it opened. Each year, the plant earns an additional 5% per man-hour.Write a function that gives the amount A(t) that the plant earns per man-hour t years after it opens.
A function that gives the amount that the plant earns per man-hour t years after it opens is [tex]\mathrm{A}(\mathrm{t})=80 \times 1.05^{\mathrm{t}}[/tex]
Solution:Given that
A manufacturing plant earned $80 per man-hour of labor when it opened.
Each year, the plant earns an additional 5% per man-hour.
Need to write a function that gives the amount A(t) that the plant earns per man-hour t years after it opens.
Amount earned by plant when it is opened = $80 per man-hour
As it is given that each year, the plants earns an additional of 5% per man hour
So Amount earned by plant after one year = $80 + 5% of $80 = 80 ( 1 + 0.05) = (80 x 1.05)
Amount earned by plant after two years is given as:
[tex]=(80 \times 1.05)+5 \% \text { of }(80 \times 1.05)=(80 \times 1.05)(1.05)=80 \times 1.052[/tex]
Similarly Amount earned by plant after three years [tex]=80 \times 1.05^{t}[/tex]
[tex]\begin{array}{l}{\Rightarrow \text { Amount earned by plant after } t \text { years }=80 \times 1.05^{t}} \\\\ {\Rightarrow \text { Required function } \mathrm{A}(t)=80 \times 1.05^{t}}\end{array}[/tex]
Hence a function that gives the amount that the plant earns per man-hour t years after it opens is [tex]\mathrm{A}(t)=80 \times 1.05^{t}[/tex]
an elementary school teacher wants to know if the words in a book are too difficult for her students. She reads the first sentence on the first page in every chapter and finds three words her students would not know. what is the sample in this situation
A.the three words her students would not know
B. the words that she reads that her students would know
c. every word in the book
d.every word in the first sentence of the first page of every chapter<—my answer
Answer:
d.every word in the first sentence of the first page of every chapter.
Step-by-step explanation
the sample space means the set of total possible outcomes or ALL possible outcomes.so here, the situation is about the teacher reading a sentence.the favorable outcome is the set which has all the words that the students would not know from all the words read by the teacher or simply from the sample space.since the teacher reads the first sentence on the first page in every chapter , all the words in that sentence will be sample in this situation.