PLEASE HELP!!



Given the following balanced reaction between hydrochloric acid and oxygen gas to produce water and chlorine gas, how many grams of chlorine gas, Cl2, are produced from 27.8 g of hydrochloric acid and excess oxygen? (To find the molar mass in the problem, use the periodic table and round the mass to the hundreds place for calculation.)

4HCI(aq) +O2 ->2CI2 (g)+ 2H2O (I),

Answer:

Its mass is lowered, but it is still the same element.

Explanation:

It right

C. The reactions go to completion

The percent error for the 10 mL of water, given a measured mass of 9.925 g and a density of 0.9975 g/mL, is approximately 0.501%.

To calculate the percent error for the 10 mL of water given the measured mass and the density of water, we can use the formula for percent error:

Percent Error = | (Experimental Value - Theoretical Value) / Theoretical Value | × 100%

The theoretical mass of 10 mL of water using the density 0.9975 g/mL is calculated as follows:

Theoretical Mass = Volume × Density = 10 mL × 0.9975 g/mL = 9.975 g

The experimental mass measured is 9.925 g. Now, applying the percent error formula:

Percent Error = | (9.925 g - 9.975 g) / 9.975 g | × 100% = |(-0.05 g) / 9.975 g| × 100% ≈ 0.501%

Therefore, the percent error for the measurement of 10 mL of water is approximately 0.501%.

Answer : The correct option is, (a) 8.0 g

Solution : Given,

Percent of solute = 4 %

Mass of solution = 200 g

Mass by mass percent (m/m)% : It is defined as the mass of solute present in the mass of solution.

Formula used :

[tex](m/m)\%=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100[/tex]

Now put all the given values in this formula, we get the mass of solute.

[tex]4\%=\frac{\text{Mass of solute}}{200g}\times 100[/tex]

[tex]\text{Mass of solute}=8.0g[/tex]

Therefore, the mass of solute in solution is, 8.0 g

Final answer:

The strength of a weak acid is related to the strength of its conjugate base through an inverse relationship.

Explanation:

The strength of a weak acid is related to the strength of its conjugate base through an inverse relationship. According to the general rule, the stronger the acid, the weaker the conjugate base, and vice versa. This can be understood by considering the concept of acid-base equilibrium.

For example, if we have a strong acid and a weak base, the acid-base equilibrium will favor the side with the weaker acid and base. Conversely, if we have a weak acid and a strong base, the equilibrium will favor the side with the weaker acid and base.

Therefore, the strength of a weak acid and its conjugate base are inversely related, with the weaker acid having a stronger conjugate base.

Answer:

The answer is C) 6.63

Explanation:

When the coefficients in a balanced equation are multiplied by a factor, the resulting equilibrium constant is raised to this factor.

In this case, you have the following equilibrium:

N₂O₄(g) ⇌ 2 NO₂(g) Kc = 1.46

In which the coefficients are 1 (for N₂O₄) and 2 (for NO₂)

In the second equation, notice that you have the coefficients of the first equation multiplied by 5 (1 x 5= 5 for N₂O₄; 2 x 5= 10 for NO₂) :

5 N₂O₄(g) ⇌ 10 NO₂(g)

Thus, to obtain the equilibrium constant of the second equation (Kc'), you have to raise the first equilibrium constant (Kc) to 5:

K'c= (Kc)⁵= (1.46)⁵= 6.63

Answer:

The chemical name of carbon dioxide is [tex]CO_2[/tex].

Explanation:

[tex]C+2O\rightarrow CO_2[/tex]

In a model of carbon dioxide made by the student there are one carbon atom and two oxygen atoms which means that total atoms in the molecule of carbon-dioxide is three.

While writing the chemical name of the carbon dioxide we will first write the symbol of the electropositive atom and then electronegative atom:[tex]CO_2[/tex]

Final answer:

To rise the average kinetic energy of water molecules in a glass, you need to increase the water's temperature, which can be done by heating the water or increasing the room temperature. This is based on the principle that temperature is proportional to the average kinetic energy of the particles in a substance.

Explanation:

The average kinetic energy of water molecules in a glass can be raised by increasing the temperature of the water. This increase in temperature can be achieved in several ways, one of which is by increasing the temperature of the room, allowing heat energy to transfer from the environment to the water. It's important to note that replacing the water with a more dense fluid or adding more water will not increase the kinetic energy of the existing water molecules.

As detailed in the kinetic-molecular theory, temperature is directly proportional to the average kinetic energy of the particles in a substance. Thus, when water is heated, the molecules begin to move more rapidly, with more extensive vibrations and translations. This results in increased collisions between molecules and a higher average velocity and kinetic energy of the particles.

It's worth clarifying that kinetic energy is transferred from hot water molecules to colder substances like ice, but what we want in this scenario is to increase the kinetic energy of the water molecules themselves, which is done by applying heat to the water.

Answer:

I think planets....?

Explanation:

I'm not actually sure but my brother told me it's nebulae and I think he's lying... stars don't move and the moon wouldn't actually be a "point" even if it was it wouldn't be plural....

The  property of a wave is given as frequency

Generally, Frequency is simply defined as the number of waves that pass through a fixed point in a given amount of time

In conclusion, for a number  based on the number of waves or cycles that pass a fixed point in a specific unit of time, we refer to it as frequency

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Answer:

ALL are true

Explanation:

The partial pressure of Ne is [tex]\boxed{1.063{\text{ atm}}}[/tex].

Further Explanation:

Dalton’s law:

This law states that partial pressure of any gas is calculated by the multiplication of mole fraction and the total pressure of gas mixture.

The expression for partial pressure of a particular gas is,

[tex]{P_{{\text{gas}}}} = {X_{{\text{gas}}}} \cdot {P_{{\text{total}}}}[/tex]                                                                         …… (1)

Where,

[tex]{P_{\text{gas}[/tex] is the partial pressure of the gas.

[tex]{P_{{\text{total}}[/tex] is the total pressure of the mixture.

[tex]{X_{{\text{gas}}}[/tex] is the mole fraction of gas.

The formula to calculate moles of component is as follows:

[tex]{\text{Moles of component}} = \dfrac{{{\text{Mass of component}}}}{{{\text{Molar mass of component}}}}[/tex]                                   …… (2)

Substitute 10.0 g for mass of component and 20.179 g/mol for molar mass of component in equation (2) to calculate moles of Ne.

 [tex]\begin{aligned}{\text{Moles of Ne}} &= \frac{{{\text{10}}{\text{.0 g}}}}{{{\text{20}}{\text{.179 g/mol}}}} \\ &= 0.4956{\text{ mol}} \\\end{aligned}[/tex]

Substitute 10.0 g for mass of component and 39.948 g/mol for molar mass of component in equation (2) to calculate moles of Ar.

 [tex]\begin{aligned}{\text{Moles of Ar}} &= \frac{{{\text{10}}{\text{.0 g}}}}{{{\text{39}}{\text{.948 g/mol}}}} \\&= 0.2503{\text{ mol}} \\ \end{aligned}[/tex]

Total number of moles can be calculated as follows:

[tex]\begin{aligned}{\text{Total number of moles}} &= \left( {0.4956 + 0.2503} \right){\text{ mol}} \\ &= 0.7459{\text{ mol}} \\\end{aligned}[/tex]

The formula to calculate mole fraction of Ne is as follows:

[tex]{\text{Mole fraction of Ne}} = \dfrac{{{\text{Moles of Ne}}}}{{{\text{Total number of moles}}}}[/tex]                                    …… (3)

Substitute 0.4956 mol for moles of Ne and 0.7459 mol for total number of moles in equation (3).

[tex]\begin{aligned}{\text{Mole fraction of Ne}} &= \frac{{{\text{0}}{\text{.4956 mol}}}}{{{\text{0}}{\text{.7459 mol}}}} \\&= 0.6644 \\\end{aligned}[/tex]  

Substitute 0.6644 for [tex]{X_{{\text{gas}}}}[/tex] and 1.6 atm for [tex]{P_{{\text{total}}}}[/tex] in equation (1) to calculate partial pressure of Ne.

[tex]\begin{aligned}{P_{{\text{Ne}}}} &= \left( {0.6644} \right)\left( {1.6{\text{ atm}}} \right) \\&= 1.063{\text{ atm}} \\\end{aligned}[/tex]  

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Answer details:

Grade: Middle School

Subject: Chemistry

Chapter: Gases and the kinetic-molecular theory  

Keywords: partial pressure, mole fraction, Ne, Ar, moles, molar mass, mass, 1.063 atm, 1.6 atm, 0.6644, mole fraction of Ne.

The loss of static energy as electric charges move off an object is called electric discharge.

Electric discharge can be defined as release and transmission of electricity through a medium in an applied electric field.

It results from the conducting path between two points of different electrical potential in the medium where the points are immersed.

Answer:

3: Atoms X and Y will have a smaller atomic mass than atom Z

7: Fissile

8: It is used in nuclear power plants

Explanation:

3

The process of nuclear fission is where one unstable atom (in this case atom Z) splits into two smaller atoms (atoms X and Y) and releases energy in the form of radiation.

Hence, the combined atomic mass of X and Y cannot be grater than the mass of atom Z, fission does not need to be at high temperatures to take place, and the mass of element X will never equal the mass of element Z.

7

In nuclear fission, the energy is produced by the decay of radioactive elements, and that energy can not be obtained by combustion. Stable elements will not undergo fission, and low mass elements tend to be very stable too.

8

The energy produced from nuclear fission is not always controllable, that is why disasters such as nuclear meltdowns happen, because the energy output cannot be controlled. The atoms in the sun undergo fusion, and not fission. Once again, nuclear fission does not require high temperatures (nuclear fusion does, hence why the sun has such a high temperature).

B) atomic sodium has one more electron.

This can be easily seen if you compare the charges - ionic sodium carries one more positive charge than atomic sodium, so ionic sodium must have one fewer electron.

The percent ionization of the solution is 0.017%.

The steps involved are;

The equation of the reaction is;

            CH3CH2CH2COOH(aq)  ⇄ H^+(aq)  + CH3CH2CH2COO^-(aq)

I               0.0075                               0                0.085

C              -x                                        +x             + x

E          0.0075 - x                               x               0.085 + x

The Ka of the acid = 1.5 x 10^-5

Hence;

1.5 x 10^-5 = x(0.085 + x)/0.0075 - x

1.5 x 10^-5 (0.0075 - x ) =  x(0.085 + x)

1.1 x 10^-7 - 1.5 x 10^-5x = 0.085x + x^2

x^2 + 0.085x - 1.1 x 10^-7 = 0

x = 0.0000013 M

Percent ionization=  0.0000013 M/0.0075 × 100/1

= 0.017%

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Using the given free energy difference at 298 K and the equation ∆Gº = -RTlnK, we calculate the equilibrium constant (K) and determine that the most stable conformer of a substituted cyclohexane molecule comprises approximately 91.7% of the sample at equilibrium.

To determine what percent of the sample at equilibrium represents the most stable conformer of a substituted cyclohexane molecule, we use the free energy difference (
∆Gº) between the two chair conformations. Given that
∆Gº is 5.95 kJ/mol at 298 K, we first calculate the equilibrium constant (K) using the equation ∆Gº = -RTlnK, where R is the universal gas constant (8.314 J/mol•K) and T is the temperature in Kelvin. Substituting the known values, we have:

5.95 kJ/mol = - (8.314 J/mol•K)(298 K)lnK

Converting 5.95 kJ/mol to J/mol, we get 5950 J/mol. We then solve for K:

5950 J/mol = - (8.314 J/mol•K)(298 K)lnK

lnK = -5950 J/mol / (- (8.314 J/mol•K)(298 K))

lnK = 2.397

K = e^(2.397)

K ≈ 11.0

The ratio of the amounts of each conformer at equilibrium can be expressed as K = [Most Stable]/[Least Stable]. Hence, if the least stable conformer is taken as 1 part, the most stable will be 11 parts out of a total of 12 parts. The percent representation of the most stable conformer at equilibrium is then (11/12) * 100%, which approximates to 91.7%.

Therefore, the most stable conformer comprises approximately 91.7% of the sample at equilibrium.

a. The value of the rate constant (k) for this reaction at this temperature is 18.18 [tex]M^-1*s^-1.[/tex]

b. The rate law can be written as: ate = k[AB]

c. The half-life of the reaction when the initial concentration is 0.55 M is  0.038 seconds.

d. The concentrations of A and B after 75 seconds would be approximately 0.004 M each.

To answer the given questions, analyze the reaction kinetics based on the provided information:

a) The rate constant (k) can be determined from the slope of the plot 1/[AB] versus time. The slope is given as -0.055/M*s. The rate constant (k) can be calculated by taking the reciprocal of the slope:

k = -1/slope

k = -1/(-0.055/Ms)

k = 18.18 [tex]M^-1s^-1[/tex]

Therefore, the value of the rate constant (k) for this reaction at this temperature is 18.18 [tex]M^-1*s^-1[/tex].

b) The rate law can be determined using the given reaction:

AB --> A + B

Since the reaction is a first-order reaction, the rate law can be written as:

Rate = k[AB]

c) The half-life (t₁/₂) can be calculated using the first-order integrated rate law:

t₁/₂ = (0.693) / k

Given the initial concentration ([AB]₀) as 0.55 M and the rate constant (k) as 18.18 [tex]M^-1*s^-1[/tex],  calculate the half-life:

t₁/₂ = (0.693) / (18.18 [tex]M^-1*s^-1[/tex])

t₁/₂ ≈ 0.038 s

Therefore, the half-life of the reaction when the initial concentration is 0.55 M is approximately 0.038 seconds.

d) To determine the concentrations of A and B after 75 seconds, use the first-order integrated rate law:

[AB] = [AB]₀ * exp(-kt)

Given:

[AB]₀ = 0.250 M (initial concentration of AB)

t = 75 s (time)

Using the rate constant (k) calculated earlier (18.18 [tex]M^-1*s^-1[/tex]), calculate the concentrations of A and B:

[AB] = 0.250 * exp(-18.18 [tex]M^-1*s^-1[/tex] * 75 s)

[AB] ≈ 0.004 M

Since the reaction is stoichiometrically 1:1, the concentrations of A and B after 75 seconds would be:

[A] ≈ 0.004 M

[B] ≈ 0.004 M

Therefore, the concentrations of A and B after 75 seconds would be approximately 0.004 M each.

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The rate constant is 0.055/M*s. The rate law is rate = k[AB]. The half-life is 10.5 seconds and the concentrations of A and B after 75 seconds can be calculated using the integrated rate equation.

a) The slope of the line in the plot represents the rate constant (k) for this reaction. In this case, the slope is -0.055/M*s. So, the value of the rate constant is 0.055/M*s.

b) The rate law for the reaction can be determined by examining the stoichiometry of the reaction. The reaction is AB → A + B. Since the rate is expressed as 1/[AB], the rate law is rate = k[AB].

c) To find the half-life, we need to use the integrated rate equation ln([AB]₀/[AB]) = kt. Substituting the given values, we get ln(0.55/0.25) = (0.055/M*s)t. Solving for t, we find t = 10.5 seconds.

d) To find the concentrations of A and B after 75 seconds, we can use the integrated rate equation again. [A] = [AB]₀ - [AB]₀e^{-kt}. Plugging in the values, we get [A] = 0.250M - 0.250Me^{(-0.055/M*s)(75s)}. Similarly, we can find [B] = 0.250M - [A].

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Answer:

Scientists will be able to use relative dating and absolute dating to determine when the failure occurred.

Explanation:

Scientists will be able to use relative dating, because it is the method capable of determining an order of events that occurred in the past by relating the rock with that failure to a rock without failure or with different failures, without the need to determine an absolute age of when the failure happened, however revealing a relative, approximate date.

It will also be possible to use absolute dating, which will give a more precise age on the fault present in the rock, using a chronological age that will be determined by observing the physical and chemical properties of the rock. This technique shows the age of the event in numbers, as opposed to relative dating.