PLEASE HELP!!!!

I NEED HELP!!!
WILL GIVE BRAINLIEST!!!
Can someone also help me learn how to solve these problems??

Answer:

The fourth listed answer:

Domain: All Real numbers

Range : { f{x) | f(x) [tex]\leq[/tex] 0, f(x) = 1 }

Step-by-step explanation:

The domain consists of all Real numbers (notice that you have a well defined f(x) value for all possible x on the horizontal axis.

The Range is associated with the set of those f(x) values (on the vertical axis) that are connected via the functional relationship with a value  "x" of the domain. The line with positive slope extends to all f(x) values that are [tex]\leq[/tex] 0 (smaller than or equal to zero). While the flat horizontal line on the right of the plot corresponds to the line f(x) =1 (only one value of f(x) [1} connects with the x-values of the Domain that are larger than 3.

Answer:

12.5

Step-by-step explanation:

Vetrx is at: (0,-1) because other y values are repeated

y = a(x - 0)² - 1

y = ax² - 1

Using (1,0.5)

0.5 = a(1)² - 1

a = 1.5

f(x) = 1.5x² - 1

f(-3) = 1.5(-3)² - 1

f(-3) = 12.5

Answer:

D. 12.5

Step-by-step explanation:

Answer:

hope i helped

Step-by-step explanation:

Point D (3,1); Point B (-1,-2); Point C (4, -2)

Point D lies on the circle whose center is Point B and which contains the Point C if the distance:

BD = BC

BD^2 = BC^2

(- 1 - 3)^2 + (- 2 - 1)^2 = (4 - (-1))^2 + (-2 - (-2))^2

16 + 9 = 25

25 = 25

Follows, point D lies on the circle with radii 5.

To solve graphically we first need to write the equation of the circle whose center is Point B and which contains the Point C:

(x - (-1))^2 + (y - (-2))^2 = 5^2

(x + 1)^2 + (y + 2)^2 = 5^2

Answer:

8,15,17

Step-by-step explanation:

Answer:

I got 8,15, and 17 too just because of one side is short the other to should be longer.

Step-by-step explanation:

Answer:

8.37 minutes

Step-by-step explanation:

The key word times helps us know what operation we're doing, which is multiplication. Multiply 9.3 by 0.9 to get your answer.

Answer:

6 ^ 6x = 20

6x * log 6 = log (20)

6x * 0.77815125038 = 1.3010299957

6x = 1.6719500162

x = 0.278658336

Double check

6 ^ 6* 0.278658336 =

6 ^ 1.671950016  = 20

Step-by-step explanation:

Answer:

{1, 3, 5, 7, 9, 11}

The sample space of the odd number will be (1, 3, 5, 7, 9, 11).

Sample space simply means the possible outcomes that we can get when we make an experiment.

Odd numbers cannot be divided by 2. Examples include 1, 9, 11, 23, 45, 75 etc. In this case, the odd numbers that we can get from 1 to 11 will be 1, 3, 5, 7, 9 and 11 and this will be the sample space.

In conclusion, the sample space will be (1, 3, 5, 7, 9, 11)

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We can see that b1 = 18, b2 = 24, and h = 5

So, we can just substitute these in.

A = 1/2(18 + 24)5

A = 1/2 * 42 * 5

A = 21 * 5

A = 105

So, the answer is C. 105 sq cm

Answer:

105

Step-by-step explanation:

you just have to plug in your variables

Answer:

The length of the sides is 8[tex]\sqrt{2}[/tex]

Step-by-step explanation:

Since the diagonal divide a square into 2 45-45-90 triangles:

The diagonal is the hypotenuse of the triangle

Divide 16 by [tex]\sqrt{2}[/tex] and you will get 8[tex]\sqrt{2}[/tex].

If you like my answer please consider marking my answer as brainiest.

I don’t know bruv but I hope this somewhat helps. I used a websti called dezmos.

To determine the correct standard form of a quadratic equation from the given options, we expand (x-3)2 to get [tex]x^2 - 6x + 9 = 0,[/tex] which is the correct standard form [tex]ax^2 + bx + c = 0.[/tex]

To write the quadratic equation in standard form, you need to remember that the standard form is ax2 + bx + c = 0. The given equations will be compared to this standard form to find the correct answer.

Given Equations:

(x-3)2=0

0x2+9=0

0x2+6x+9=0

0x2 - 6x +9=0

Only the first equation, (x-3)2=0, can be simplified to the standard quadratic form if expanded. Let's expand it:

(x-3)2 = x2 - 6x + 9

So the correct standard form of the given equation is x2 - 6x + 9 = 0.

The other options, due to having a coefficient of 0 for x2, are not proper quadratic equations as they do not have the quadratic term.

Answer:

x = 1 and

Y = 2

Step-by-step explanation:

1. Y = x + 1

2. X + Y = 3

Substitute equation 1 into equation 2

X + Y = 3

X + X + 1 = 3

2x + 1 = 3

Subtract 1 from both sides to eliminate 1 on the left side

2x + 1 - 1 = 3 - 1

2x = 2

Divide both sides by 2 to isolate x

2x/2 = 2/2

x = 1

Substitute 1 for x in either equation to get Y

Using equation one, we have

Y = x + 1

= 1 + 1

= 2

x = 1

Y = 2

Check

X + Y = 3

1 + 2 = 3

3 = 3

Answer:

The second one!:

A number line going from 6 to 14. A closed circle is at 11. Everything to the right of the circle is shaded.

Step-by-step explanation:

The one that has a line going towards 14 from 11. The circle is closed (filled in.)

Please mark brainliest! Hope this helps!

Answer:

????????????????????

the seccond one

Answer:

119 student tickets and 95 non-student tickets

Step-by-step explanation:

I did a trial-and-error solution.

I started with 107 students and 107 non-students:

(107*$7)+(107*$12) = $2033

It was too high, which tells us that there should be more who paid for the cheaper price.

I ended up with 119 and 95:

(119*$7)+(95*$12) = $1973

Answer:

Sample Response: Partial and negative tickets cannot be sold, so the minimum number values of e and s are 0. If s = 0, then e = 16, and if e = 0, then s = 20. Therefore, the values of s are whole numbers from 0 to 20 and the values of e are whole numbers between 0 and 16. The greatest number of student tickets sold was 20 and the greatest number of nonstudent tickets sold was 16.

Step-by-step explanation:

Answer: The answer is c

Step-by-step explanation: Lets be freinds

Answer:

4 = b

5 = a

6 = a

Answer:

option D

Step-by-step explanation:

Given,

half life of silicon-32 = 710 years

Present silicon-32, N₀ = 90 gm

silicon-32 after 600 years,N = ?

[tex]k = \dfrac{-0.693}{t}[/tex]

[tex]k = \dfrac{-0.693}{710}[/tex]

k = -0.000976

Now,

[tex]N = N_0 e^{kt}[/tex]

[tex]N =90\times e^{-0.000976\times 600}[/tex]

[tex]N = 50.104\ g[/tex]

Hence, the correct answer is option D.

The amount of silicon-32 remaining after 600 years is 50.102 grams

Half life is the time taken for a substance to decay to half of its original amount. It is given by:

[tex]N=N_o(\frac{1}{2} )^\frac{t}{t_\frac{1}{2} } \\\\N\ is\ the\ value\ of\ the\ substance\ after\ t\ year, t_\frac{1}{2} \ is\ the\ half\ life\\and\ N_o\ is\ the \ original\ amount[/tex]

Given that half life = 710 years, original amount is 90 g, t = 600 years, hence:

[tex]N=90(\frac{1}{2} )^\frac{600}{710} \\\\N=50.102\ g[/tex]

The amount of silicon-32 remaining after 600 years is 50.102 grams

Find out more on half life at: https://brainly.com/question/25783920

Answer:

[tex]y=-150x+1600[/tex]

Step-by-step explanation:

Linear Equation:

[tex]$y=mx+b$[/tex]

[tex]f(x)=mx+b[/tex]

Consider:

The pool is full when the time is zero:

[tex]1600=m(0)+1600[/tex]

It is emptied (-) in the rate 150 gallons every hour.

[tex]f(x)=-150x+b[/tex]

[tex]f(x)=-150x+1600[/tex]

[tex]y=-150x+1600[/tex]

Answer:

4k=-2k+6-18

6k= -12

Step-by-step explanation:

Answer:

-      12

6     12

-2

Step-by-step explanation:

They add 6 to both sides so 4k=2-12

then add 2k to both side and get 6k=-12

divide by 6 and get k=-2

Answer:

14

Step-by-step explanation:

The diameter of a circle is twice the radius

d = 2*r

d = 2*7

d =14 m

Answer:

diameter = 14

Step-by-step explanation:

given that the radius of a circle = 7m

diameter = ?

recall that the formulae for finding the diamer = 2 x radius

diameter = 2 x 7

diameter = 14

Step-by-step explanation:

M is the mid point of AB

here given A ( - 7 , -7) and M ( -6 , -1) Let the coordinates of point B be ( x1, y1)

Now

( - 6 , -1 ) = {( x1 - 7)/ 2 , ( y1 - 7) / 2}

Equating

-6 = x1 -7 -1 = y1 - 7

2. 2

-12 = x1 - 7. -2 = y1 - 7

x1 = -12 +7. y1 = -2 +7

Therefore x1 = - 5. Therefore y1 = 5

Therefore the coordinates of B is ( -5 , 5)

Answer:

the coordinates of B is ( -5 , 5)

Step-by-step explanation:

m = the number of miles driven

Company A cost = 76    

[they charge $76 for unlimited mileage, so they don't charge by the miles driven]

Company B cost =  0.70m + 55  

[they charge an initial fee of $55 plus $0.70 per mile(m)]

For what mileages will Company A charge less than Company B?

Company A cost < Company B cost  ----->   76 < 0.70m + 55      

To solve for m, isolate/get the variable "m" by itself in the inequality:

76 < 0.70m + 55     Subtract 55 on both sides

76 - 55 < 0.70m + 55 - 55

21 < 0.70m     Divide 0.70 on both sides to get "m" by itself

[tex]\frac{21}{0.70} <\frac{0.70m}{0.70}[/tex]

30 < m      [m is any number greater than 30]

Company A will charge less than Company B for mileages over/greater than 30.

Final answer:

Company A will charge less than Company B when more than 30 miles are driven; the inequality used to determine this is 76 < 55 + 0.70m, and after solving, it shows that m > 30.

Explanation:

To find out for what mileages Company A will charge less than Company B, we need to set up an inequality based on the given price structures for both companies:

Company A charges a flat rate of $76 per day, regardless of mileage.

Company B charges an initial fee of $55 plus $0.70 per mile driven.

The inequality to represent this scenario is:

76 < 55 + 0.70m

To solve for m (the number of miles driven), we subtract 55 from both sides:

21 < 0.70m

Then, divide both sides by 0.70 to isolate m:

m > 30

So, Company A will charge less than Company B when Bob drives more than 30 miles.

Answer:

Approximately 53

Step-by-step explanation:

92% of 53 is 48.76, there is no way to use a whole number and get exactly 48, which is why it is approximately

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60.56 square feet, the area of the semicircles equates to 12.56 and the rectangle area is 48 so all you have to do is add them

Answer:

It is 60.56 ft2

Step-by-step explanation:

Hope this helps

Given:

θ = 54°

Radius = 10 in

To find:

The arc length of PQ

Solution:

Arc length formula:

[tex]$\text{Arc length}=2 \pi r\left(\frac{\theta}{360^\circ}\right)[/tex]

[tex]$\text{Arc length}=2 \times 3.14 \times 10\left(\frac{54^\circ}{360^\circ}\right)[/tex]

                 = 9.42 in

The arc length of PQ is 9.42 inches.

Answer:

J

Step-by-step explanation:

As you can see, the peak occurs at (2,6). That means that all values below 6 are in the range.

Answer:

1, 3, 4, and 7

Step-by-step explanation:

all of these are true

Answer:

d-(9,1)

Step-by-step explanation:

Answer:

(9,1)

Step-by-step explanation:

correct on edge

[tex]-15x^2y^2+25xy^2=5xy^2(-3x+5)\:or\:-5xy^2(3x-5)[/tex]

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