Chemistry High School

PLEASE HELP!Suppose you begin with 1.50~g of the hydrate copper(II)sulfate · x-hydrate (CuSO4· x H2O), where x is an integer. After dehydration you find that you are left with 0.96~g of the an-hydrate CuSO4. What is the unknown integer x. Round your answer to the nearest integer, enter only an integer.
Suppose you begin with of the hydrate KAl(SO4)2 · 12H2O. After dehydration you find that you are left with 3.0~g of the an-hydrate KAl(SO4)2. How many grams did you start with? Write the value to the correct number of significance figures.

Answers

Answer 1
For first problem:
mass of water = 1.5 g - 0.96 g = 0.54 g
mole of water = [tex] \frac{0.54 g}{18 g/mole} = 0.3 mol[/tex]
mole of CuSO₄ = [tex] \frac{0.96 g}{159.6 g/mole} = 6 x 10^{-3} mol [/tex]
mole of water / mole of anhydrate = [tex] \frac{0.03}{6 x 10^{-3}} = 5 [/tex] 
so x equal 5

For second problem:
After dehydration 12 H₂O evaporated decreasing mass by (12 x 18) = 216 g/mole
number of moles of KAl(SO₄)₂ = [tex] \frac{3}{258.2} = 0.0116 mol [/tex]
mass of evaporated water = 216 x 0.0116 = 2.5 g
Initial weight = 2.5 g + 3 g = 5.5 g

Related Questions

Would precipitation occur when 500 mL of a 0.02M solution of \(AgNO_3\) is mixed with 500 mL of a 0.001M solution of NaCl? Show your work.,

Answers

The balanced chemical reaction is
NaCl + AgNO3 --> AgCl + NaNO3 
To find out if precipitation will occur, we need to calculate the number of
moles acting in the chemical reaction 
But Molarity, M=nV, where n is the number of moles and V is the volume in
litres. So n = M/V
number of moles of AgNo3 = 0.02/500 * 10^(-3)
n= 0.04 
While n of Sodium chloride = 0.01/0.5 = 0.2. Since there is excess sodium chloride ( twice as much) precipitation will not occur. 2NaCl + 2AgNO3 -->
2AgCl + 2NaNO3. The reaction requires one and not two moles of AgNo3 as evident from the number of moles which is 0.04

How many electrons does ga lose to achive noble gas arrangement?

Answers

Gallium has 31 electrons (₃₁Ga 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p¹) and if loses 13 electrons, gallium would have configuration of noble gas argon with 18 electrons (₁₈Ar 1s² 2s² 2p⁶ 3s² 3p⁶), but that is not possible, so gallium only loses three electrons and has electron configuration:
₃₁Ga³⁺ 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰.

6.02 x 1022 molecules of HCl (molecular weight = 36.5 g/mole) in 2.0 liters of water

Answers

moles HCl = 6.02 x 10^22 / 6.02 x 10^23 = 0.100 
M = 0.100 / 2.00 L=0.0500

6.02 x 1022 molecules of HCl (molecular weight = 36.5 g/mole) in 2.0 liters of water. Therefore, M = 0.05

What is mole?

The SI unit for measuring the quantity of any substance would be the mole, abbreviated as mol.

Given data:

Number of molecule = 6.02 x [tex]10^{22}[/tex] molecules

Molecular weight = 36.5 g/mole

Moles = 6.02 x [tex]10^{22}[/tex]  / 6.02 x [tex]10^{23}[/tex] = 0.1mol

Hence, M = 0.1 /2 = 0.05

Therefore, M = 0.05

To know more about mole

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