Which of the following equations represents the line with a slope of negative 8/7 and a y-intercept of negative 3?
y = 8/7x - 3
y = 8/7x + 3
y = -8/7x - 3
y = -8/7x + 3
Find the volume of the tra ezoidal prism in the figure.
A. 72 m3
B. 252 m3
C. 432 m3
D. 216 m3
To solve this problem you must apply the proccedure shown below:
1. You can use the following formula for calculate the volume:
[tex]V=(\frac{a+b}{2})(h)(l)[/tex]
Where:
[tex]a=6m\\b=12m\\h=8m\\l=3m[/tex]
2. Now, you must substitute the values above into the formula:
[tex]V=(\frac{a+b}{2})(h)(l)\\V=(\frac{6m+12m}{2})(8m)(3m)\\V=216m^{3}[/tex]
Therefore, the answer is the last option: D. 216 m³.
Help with this geometry question, thank you . Only answer if your sure , thank you again
dude its b thats easy and yes im sure 4 units down and sense its not reflection then thats the answer
Please solve the inequality for p
4p + 2 < 2(p + 5)
P<1.5
Step-by-step explanation:
please help me on this one and tell me why ?
thank you
The domain is all of the x-values. The x-values are also considered the input values.
Side Note: the range is all of the y-values, which represent the output values.
Answer: A
Write an equation of the parabola in intercept form with x-intercepts of 12 and -6; and an axis of symmetry of (14, 4).
Please show work!
Intercept form is: y = a(x - p)(x - q)
It is given that: p = 14, q = -6, x = 14, y = 4
4 = a(14 - 12)(14 - (-6))
4 = a(2)(20)
4 = 40a
[tex]\frac{4}{40} = \frac{40a}{40}[/tex]
[tex]\frac{1}{10} = a[/tex]
Answer: y = [tex]\frac{1}{10}[/tex](x - 14)(x + 6)
Which formula can be used to describe the sequence?
The formula that can be used to describe the sequence is:
[tex]f(x)=-3\cdot (\dfrac{-1}{5})^{x-1}[/tex]
Step-by-step explanation:We are given a sequence of numbers as:
[tex]-3\ ,\ \dfrac{3}{5}\ ,\ \dfrac{-3}{25}\ ,\ \dfrac{3}{125}\ ,\ \dfrac{-3}{625}[/tex]
Hence, we could observe that the series is a series with alternating sign such that the power of 5 is increasing in the denominator and there is no change in the numerator i.e. the power of 3 remain unchanged.
Hence,third and last option are discarded.
Also, in first option each of the terms of the digit will be negative and not alternating and hence option (1) is also discarded.
Hence, the function that represent this sequence is:
[tex]f(x)=-3\cdot (\dfrac{-1}{5})^{x-1}[/tex]
An empty swimming pool needs to be filled to the top. The pool is shaped like a cylinder with a diameter of 6m and a depth of 1.7 m. Suppose water is pumped into the pool at a rate of 11 m3 per hour. How many hours will it take to fill the empty pool?
Use the value 3.14 for π, and round your answer to the nearest hour. Do not round any intermediate computations.
PLEASE SOMEONE HELP ME THANK YOU!!
Follow this as an example
An empty swimming pool needs to be filled to the top. The pool is shaped like a cylinder with a diameter of
10 m
and a depth of
1.4 m
. Suppose water is pumped into the pool at a rate of
11 m3
per hour. How many hours will it take to fill the empty pool?
Use the value
3.14
for
π
, and round your answer to the nearest hour. Do not round any intermediate computations.
The formula for the volume of a cylinder is ∏r2h. The problem gives d=10m, so r=5m.
The pool holds (3.14)*52*1.4 m3 = 109.9 m3 of water.
At a rate of 11 m3 per hour:
( 109.9 m3 ) / (11 m3/hr) = 9.990909 hr.
rounding to the nearest hour, this is 10 hours
The pool has a volume of approximately 47.97 cubic meters. The pump can fill 11 cubic meters per hour. Therefore, rounding up, it will take roughly 5 hours to fill the pool.
Explanation:The volume of the swimming pool shaped like a cylinder can be calculated using the formula for the volume of a cylinder which is V = πr2h, where r is the radius, h is the height (or depth in this case) and π is a constant whose value we'll take as 3.14. Therefore, the volume of the pool is V = 3.14 * (6/2)2 * 1.7.
Once we have the volume, we can divide this by the rate of water being pumped in, in terms of how many cubic meters it pumps per hour, to find out how many hours it would take. So the time taken to fill the pool, in hours, is Time = Volume / Rate.
By substituting the numbers we have into these formulas, we get V = 3.14 * 9 * 1.7 = 47.97 m3, and Time = 47.97 m3 / 11 m3/hour = approximately 4.36 hours. Since we need to round up to the nearest hour, the pool will take about 5 hours to fill.
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Juan ordered 20 pizzas for a party. 45% of the pizzas have 8 slices each. The remaining 55% of the pizzas have 12 slices each. Complete the model. Then complete the statements to find the total number of slices of pizza.
Total number of pizzas Juan ordered [tex]20[/tex]
Since, [tex]45\%[/tex] of pizzas have [tex]8[/tex] slices.
Therefore, number of pizzas with [tex]8[/tex] slices are: [tex]45\%\times(20)[/tex]
[tex]=\frac{45}{100} \times(20)[/tex]
[tex]=\frac{45}{10} \times(2)[/tex]
[tex]=\frac{90}{10}[/tex]
[tex]=9[/tex] pizzas
Also, since, [tex]55\%[/tex] of pizzas have [tex]12[/tex] slices.
Therefore, number of pizzas with [tex]12[/tex] slices are: [tex]55\%\times(20)[/tex]
[tex]=\frac{55}{100} \times(20)[/tex]
[tex]=\frac{55}{10} \times(2)[/tex]
[tex]=\frac{110}{10}[/tex]
[tex]=11[/tex] pizzas
Now, there are [tex]9[/tex] pizzas with [tex]8[/tex] slices and [tex]11[/tex] pizzas with [tex]12[/tex] slices.
Therefore, total number of slices of pizza are: [tex]=(9)(8)+(11)(12)[/tex]
[tex]=72+132[/tex]
[tex]=204[/tex] slices
Answer:
I hope this helped! <3
Step-by-step explanation:
Number of pizzas with 8 slices: 9
Number of pizzas with 12 slices: 11
45% of the pizzas have 8 slices each. In total, there are 72 slices in these pizzas.
55% of the pizzas have 12 slices each. In total, there are 132 slices in these pizzas.
Altogether, there is a total of 204 slices of pizza.
consider the equation 2x +4y =12. Solve for y
Hello!
Solve for y.
[tex]2x +4y =12[/tex]
Explanation:
↓↓↓↓↓↓↓↓↓↓↓↓↓
First you had to add by -2x from both sides of the equation.
[tex]2x+4y+-2x=12+-2x[/tex]
[tex]4y=-2x+12[/tex]
Then divide by 4 from both sides of the equation.
[tex]\frac{4y}{4}=\frac{-2x+12}{4}[/tex]
Simplify it should be the correct answer.
[tex]y=\frac{-1}{2}x+3[/tex]
Answer⇒⇒⇒⇒⇒⇒y=-1/2x+3
Hope this helps!
Thank you for posting your question at here on Brainly.
Have a great day!
-Charlie
Given: △ABC, m∠A=60°,
m∠C=45°, AB=9
Find: Perimeter of △ABC,
Area of △ABC
The perimeter of △ABC is approximately 25.93 units. The area of △ABC is approximately 28.62 square units.
Given that △ABC has m∠A=60°, m∠C=45°, and AB=9, we can use trigonometry to find the missing side lengths and then use them to calculate the perimeter and area of the triangle.
First, we can use the fact that the sum of the angles in a triangle is 180° to find m∠B:
m∠A + m∠B + m∠C = 180°
60° + m∠B + 45° = 180°
m∠B = 75°
Next, we can use the law of sines to find the length of side BC:
sin 60° / 9 = sin 75° / BC
BC = sin 75° * 9 / sin 60°
BC ≈ 8.14
Finally, we can use the fact that the sum of the side lengths of a triangle is its perimeter to find the perimeter of △ABC:
Perimeter = AB + BC + AC
Perimeter = 9 + 8.14 + AC
To find AC, we can use the fact that the angles in a triangle add up to 180°:
m∠A + m∠B + m∠C = 180°
60° + 75° + m∠C = 180°
m∠C = 45°
Now we can use the law of sines again to find AC:
sin 45° / AC = sin 60° / 9
AC = sin 45° * 9 / sin 60°
AC ≈ 7.79
Substituting this value into the equation for the perimeter, we get:
Perimeter = 9 + 8.14 + 7.79
Perimeter ≈ 25.93
Therefore, the perimeter of △ABC is approximately 25.93 units.
To find the area of △ABC, we can use the formula for the area of a triangle:
Area = 1/2 * base * height
We can use the fact that △ABC is a right triangle (since m∠C = 45°) to find the height:
sin 45° = height / 9
height = sin 45° * 9
height ≈ 6.36
Substituting the values for the base and height into the formula for the area, we get:
Area = 1/2 * 9 * 6.36
Area ≈ 28.62
Therefore, the area of △ABC is approximately 28.62 square units.
Perimeter of △ABC: 20.67 units,
Area of △ABC: 20.11 square units.
Explanation:In △ABC, we are given that ∠A = 60°, ∠C = 45°, and AB = 9 units. To find the perimeter, we need to calculate the length of side BC. Using the angles, we can determine that ∠B = 180° - ∠A - ∠C = 75°. Now, applying the Law of Sines, we find BC ≈ 8.21 units. The perimeter, therefore, is the sum of the three sides: 9 + 8.21 + BC ≈ 20.67 units.
For the area, we can use the formula A = 0.5 * AB * BC * sin(∠C). Substituting the known values, we get A ≈ 0.5 * 9 * 8.21 * sin(45°) ≈ 20.11 square units.
Explanation:
In the main answer, we first addressed the perimeter by finding the length of side BC through the Law of Sines. The perimeter is then calculated by summing the three sides.
Moving on to the area, we employed the formula for the area of a triangle involving two sides and the sine of the included angle. Substituting the given values, we obtained the area of △ABC as approximately 20.11 square units.
These calculations showcase the application of trigonometric principles in solving geometric problems involving angles and side lengths. The Law of Sines and the area formula for triangles provide a mathematical framework for determining these essential properties.
A salad dressing recipe requires at least 8 oz of oil to be combined with some combination of vinegar and lemon juice in a 16 oz container. What inequality models this situation? Let x represent the number of ounces of vinegar and let y represent the number of ounces of lemon juice. Enter your answer in the box.
Let x represent the number of ounces of vinegar
Let y represent the number of ounces of lemon juice
Oil required = 8 oz
Container can hold = 16 oz
So the inequality equation will be :
[tex]x+y+8\leq16[/tex]
PLEASE HELP ASAP
Prove that x+a is a factor of (x+a)^5 + (x+c)^5 + (a-c)^5
[tex]P(x)=(x+a)^5 + (x+c)^5 + (a-c)^5[/tex]
If [tex]x+a[/tex] is a factor of [tex]P(x)[/tex], then [tex]-a[/tex] is a root of [tex]P(x)[/tex].
Therefore
[tex](-a+a)^5+(-a+c)^5+(a-c)^5=0\\\\0^5+(-1(a-c))^5+(a-c)^5=0\\\\(-1)^5(a-c)^5+(a-c)^5=0\\\\-(a-c)^5+(a-c)^5=0\\\\0=0[/tex]
please help me on this question
it SHOULD be a function, it looks like it at least. All domains are not duplicated so its a function
Let a=3/4 and b=1/5. If a*x=b, then what is x?
In general, any equation like [tex] ax=b [/tex] (assuming [tex] a \neq 0[/tex]) is solved by
[tex] x= \dfrac{b}{a} [/tex]
So, in your case, the solution is
[tex] x = \dfrac{\frac{1}{5}}{\frac{3}{4}} [/tex]
Dividing by a fraction means to multiply by the inverse of that fraction:
[tex] \dfrac{\frac{1}{5}}{\frac{3}{4}} = \dfrac{1}{5} \cdot \dfrac{4}{3} = \dfrac{4}{15} [/tex]
Hey can you help with this please!?!?!
For this one, there are a few steps that will make it easier towards the end.
First lets solve for y
y+3x=8
subtract 3x from both sides
y=-3x+8
Now you are ready to plug in each of the x values and solve for y.
x vaues: -1, 0, 3
Here is what it would look like for each:
y=-3(-1)+8
y=3+8
y=11
y=-3(0)+8
y=8
y=-3(3)+8
y= -9+8
y=-1
So your final answer would be y= {-1, 8, 11}
~be careful putting it into the system, that one is sensitive~
Hope this helps!
A cable company had 260 subscibers.The ratio of regular subscribers to premium subscribers was 10:3.How many regular subscribers did they have
Final answer:
The cable company had approximately 866.67 regular subscribers.
Explanation:
To find the number of regular subscribers, we need to set up a proportion using the given ratio. The ratio of regular subscribers to premium subscribers is 10:3, which can be written as 10/3. Let x represent the number of regular subscribers.
We can set up the proportion:
10/3 = x/260
Cross-multiplying, we get:
3x = 260 * 10
3x = 2600
Dividing both sides by 3, we find:
x = 2600 / 3
Therefore, the cable company had approximately 866.67 regular subscribers.
A particular model rocket kit uses the scale 1 : 144. The actual rocket is 168ft tall. How tall will the model rocket be when completed
answer is equal to 168/144
7/6feet
A quarterback is sacked for a loss of 5 yard in Th e next play, his team loses 15yards then Th e team gain12yards on Th e third play
Find the percentage of each number 0.9percent of 1000
Answer:
9
Step-by-step explanation:
0.9 per cent of 1000 = 0.9(1000)/100 = 0.9(10) =9
Todd has 3/4 of an apple left from breakfast. His sister eight 1/8 of what is left. How much of the Apple is left?
5/8 is the answer. I just x the numerator and denominator by 2 to be 6/8-1/8=5/8
Which table represents the graph
I believe it is A. I did this awhile ago.
Need Help!
All of the following are equivalent fractions except
5/20
8/40
3/15
6/30
Which statement is true about the parts of this expression?
7.5y - z/9 + 50 +2ya) the constant is 7.5.B) the coefficients are 7.5 and -9.C) the variables are x and y.D) the like terms are 7.5y and 2y.
7.5y - z/9 + 50 + 2y
Okay, so it would be best to organize and simplify this expression: 9.5y -z/9 + 50
Alright, now let's eliminate some answers.
True or false: The constant is 7.5. This is false. 7.5 is a coefficient, 50 is a constant.
True or false: The coefficients are 7.5 and -9. This is false. Sure, 7.5 is a coefficient, but -9 is not. Actually, z/9 is also equal to (1/9)z, so technically 1/9 is the coefficient.
True or false: The variables are x and y. This is false. Where is x? Nonexistent.
True or false: The like terms are 7.5y and 2y. This is true. When we simplified the equation, we first combined like terms. 7.5y and 2y are like terms and therefore able to be combined. That's how we got 9.5y.
The answer, I believe, is D. Hope this helps!
Which is the intersection of the sets {2,3,5,7} and {2,5,11,13}?
A.null set
B.{2,3,5,7,11,13}
C.{2,5}
D.{3,7,11,13}
ANSWER
The set of the intersection of {[tex]2,3,5,7[/tex]} and {[tex]2,5,11,13[/tex]} is
{[tex]2,5[/tex]}
EXPLANATION
Let [tex]A=[/tex]{[tex]2,3,5,7[/tex]}
and
[tex]B=[/tex]{[tex]2,5,11,13[/tex]}.
The intersection of the two sets are the elements that are in both set A and set B.
The elements that are common to both sets are 2 and 5. So, we write;
[tex]A \cap B=[/tex]{[tex]2,5[/tex]}
Therefore the correct answer is C
The intersection of the sets {2,3,5,7} and {2,5,11,13} is the set {2,5}, which has the elements common to both sets. Therefore option c is correct
Explanation:The intersection of two sets is the set of elements common to both sets. In the provided sets {2,3,5,7} and {2,5,11,13}, the common elements are 2 and 5. Therefore, the intersection of these two sets is {2,5}. So, the correct answer is C. {2,5}.
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find the distance between (6,6) and(2,9)
The formula of a distance between two points A and B:
[tex]|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}[/tex]
We have A(6, 6) and B(2, 9).
Substitute:
[tex]|AB|=\sqrt{(2-6)^2+(9-6)^2}=\sqrt{(-4)^2+3^2}=\sqrt{16+9}=\sqrt{25}=5[/tex]
Answer: 5 units.Solve the equation.
x2 + 10x + 24 = 0
A) -12 and 2
B) 12 and -2
C) -4 and -6
D) 4 and 6
Answer:
Option C
Step-by-step explanation:
Given a quadratic equation
x^2+10x+24 =0
We can use either formula or factorization method to solve this equation.
The last term is 24, it is a product of 6 and 4. Sum =6+4 =10
Hence factoring can be done easier
Split the middle term as 6x +4x
x^2+6x+4x+24 =0
x(x+6)+4(x+6)=0
(x+4)(x+6)=0
Either x+4 =0 or x+6 =0
x=-6 or x =-4
Thus solution for this equation is option C
mattttttthhhhhhhhhhhhhh , i need help
Find the equation of a line that goes through the points (0,3), and (−10,4).
a.y=−110x+3
b.y=−10x
c.y=−110x
d.y=−13x
e.y=−10x+3
The slope-point formula:
[tex]y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have (0, 3) and (-10, 4)
Substitute:
[tex]m=\dfrac{4-3}{-10-0}=\dfrac{1}{-10}\\\\y-3=-\dfrac{1}{10}(x-0)\qquad|\text{add 3 to both sides}\\\\y=-\dfrac{1}{10}x+3\to\boxed{A.}[/tex]
A square technology chip has an area of 25 square centimeters how long is each side of the chip
ANSWER
Each side of the chip is 5 centimeters long.
EXPLANATION
The chip is in the form of a square.
The formula for finding the area of a square is
[tex]Area=l^2[/tex]
We were given in the question that, the area is 25 square centimeters. This means that,
[tex]25=l^2[/tex]
We take the square root of both sides to get,
[tex]\sqrt{25}=l[/tex]
[tex]\Rightarrow 5=l[/tex]
Hence the length of the square technology chip is 5 centimeters
How can you divide the pitchers into equal groups? Is there more than one way? Use your results to describe the entire collection of pitchers.